enVision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies

enVision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies

Go through the enVision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies regularly and improve your accuracy in solving questions.

enVision Math Common Core 2nd Grade Answers Key Topic 3 Add Within 100 Using Strategies

Essential Question:
What are strategies for adding numbers to 100?
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 1

enVision STEM Project: Earth Changes and Addition Strategies
Find Out Find and share books about how the Earth changes. Talk about changes that people can see, hear, and feel. Talk about changes that people cannot see happening.
Journal: Make a Book Show what you learn in a book. In your book, also:

  • Write new science words you learn. Draw pictures that help show what the words mean.
  • Write new math words you learn. Draw pictures that help show what the words mean.

Review What You Know

Vocabulary
Question 1.
Draw a circle around each even number. Use cubes to help.
15
7
14
2
19
18
Answer:

In the given numbers 14, 2 and 18 are the even numbers.know draw a circle around the 14, 2 and 18.

Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies img_1

Question 2.
Draw a square around each odd number. Use cubes to help.
12
3
6
17
11
4
Answer:

In the given numbers 3,17 and 11 are the odd numbers. Know draw the square around the 3, 17 and 11.

Question 3.
Complete the bar diagram to show the sum of 3 + 5.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 2
Answer:
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-2

In the above diagram they have given a 3 dots on the left side. Know we want to draw 5 dots on the right side. By adding both sides of the dots wet get 3 + 5 = 8

Arrays

Write an equation to show the number of circles in each array.
Question 4.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 3
By rows
_______ + _______ = _______
Answer:

Given,
Total number of rows = 2
Each row contains 4 circles.
4 + 4 = 8

Add Within 100 Using Strategies 1

Question 5.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 4
By columns
_______ + _______ = _______
Answer:
Given that,
Total number of columns = 3
Each column contains 3 circles.
3 + 3 + 3 = 9

Math Story
Question 6.
Joe has 5 apples. He picks 3 more apples. How many apples does Joe have now?
_______ apples
Does Joe have an even or an odd number of apples?
_________ number
Answer:
Given that
Total number of apples at Joe = 5
Joe picks more apples = 3
Total number of apples near Joe = 5 + 3 =8
Joe has an even number of apples.

Pick a Project

PROJECT ЗА
How far would you travel to cheer for your team?
Project: Make a Map to the Game
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 5

PROJECT ЗB
What are some important things to do at the airport?
Project: Write a List of Air Travel Tasks
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 6

PROJECT 3C
How many Olympic Games have there been?
Project: Create an Olympics Poster
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 7

3-ACT MATH PREVIEW

Math Modeling
Piled Up
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 8

Lesson 3.1 Add Tens and Ones on a Hundred Chart

Solve & Share
How can you use the hundred chart to help you find 32 + 43? Explain.
Write an equation to show the sum.

I can … add within 100 using place-value strategies and properties of operations.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 9
______ + _______ = ________

Visual Learning Bridge

Convince Me! Max says that to find 54 + 18 on a hundred chart, you can start at 54, move down 2 rows, and move back 2 spaces. Do you agree? Explain.

Guided Practice

Add using the hundred chart. Draw arrows on the chart if needed.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 11
Question 1.
17 + 32 = ________
Answer:
We are using the hundred chart to find the sum of 17 + 32
In the hundred charts we start at 17 moves down to 3 rows and move front to 2 spaces then we get 49
17 + 32 = 49
Question 2.
28 + 21 = ________
Answer:
We are using the hundred chart to find the sum of 28 + 21
In the hundred charts we start at 28 move down to 2 rows and move front to 1 space then we get 49.
28 + 21 = 49
Question 3.
________ = 19 + 20
Answer: we are using a hundred charts to find the sum of 19 + 20
In the hundred charts we start at 19 moves down to 2 rows then we get 39.
39 = 19 + 20
Question 4.
18 + 8 = ________
Answer:
We are using the hundred chart to find the sum of 18 + 8
In the hundred charts, we start at 18 moves down to 1 row and back to 2 space then we get 26
18 + 8 = 26

Independent Practice

Add using the hundred chart.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 12
Question 5.
33 + 9 = ________
Answer:
We are using the hundred chart to find the sum of 33 + 9
In the hundred charts we start at 33 down to 1 row and move back to 1 space then we get 42
33 + 9 = 42

Add Within 100 Using Strategies 2
Question 6.
________ = 12 + 73
Answer:
We are using the hundred chart to find the sum of 12 + 73
In the hundred charts we start at 12 down to 7 rows and move front to 3 Space we get 85
85 = 12 + 73
Question 7.
38 + 21 = ________
Answer:
We are using the hundred chart to find the sum of 38 + 21
In the hundred charts we start at 38 down to 2 rows and front to 1 space then we get 59
38 + 21 = 59
Question 8.
56 + 42 = ________
Answer:
We are using the hundred chart to find the sum of 56 + 42
In the hundred charts we start at 56 down to 4 rows and front to 2 spaces then we get 98
56 + 42 = 98
Question 9.
________ = 47 + 28
Answer:
We are using the hundred chart to find the sum of 47 + 28
In the hundred charts, we start at 47 down to 3 rows and back to  2 spaces then we get 75
75 = 47 + 28
Question 10.
39 + 17 = ________
Answer:
We are using the hundred chart to find the sum of 39 + 17
In the hundred charts, we start at 39 down to 2 rows and back to 3 spaces then we get 56
39 + 17 =56
Question 11.
________ = 61 + 19
Answer:
We are using the hundred chart to find the sum of 61 + 19
In the hundred charts, we start at 61 and down to 2 rows and back to 8 space then we get 89
89 = 61 + 19

Question 12.
Higher Order Thinking Write the digit that makes each equation true.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 13
Answer:
7 + 83 = 90
The number 7 makes the equation true.
34 + 25 = 57
The digit 5 makes the equation true.
16 + 52 = 67
The digit 1 makes the equation true.
62 + 21 = 83
The digit 2 makes the equation true.
Problem Solving

Use Tools Use the hundred chart to solve the problems.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 14
Question 13.
Sara has 48 buttons. Luis has 32 buttons. How many buttons do they have in all?
________ buttons
Answer:
Given that,
Total number of buttons at Sara = 48
Total number  buttons at Luis = 32
The total number of buttons at both of them have = 48 + 32
By using a hundred charts the sum of 48 + 32 is
In the hundred charts Start at 48 and down to 3 rows and front to 2 spaces then we get 80.
48 + 32 = 80
Question 14.
Mika had 70 buttons. Then she found 19 more buttons. How many buttons does Mika have now?
_______ buttons
Answer:
Given that,
Total number of buttons at Mika  = 70
She found more buttons = 19
Total number of buttons with Mike = 70 + 19
By using the hundred chart we find the sum of 70 + 19
In the hundred chart, we start at 70 then down to 2 rows and back to 1 space then we get
Question 15.
Higher Order Thinking Write the steps you take to add 43 and 39 on a hundred chart.
Answer:
We are using the hundred chart to find the sum of 43 and 39
In the hundred charts, we start at 43 and down to 4 rows and back to 1 space then we get 82
43 + 39 = 82
Question 16.
Assessment Practice which has a sum of 35? Choose all that apply.
☐ 15 + 20
☐ 16 + 19
☐ 20 + 15
☐ 30 + 15
Answer:
15 + 20 has a sum of 35.
16 + 19 has a sum of 35
20 + 15 has a sum 0f 35

Lesson 3.2 Add Tens and Ones on an Open Number Line

Solve & Share
How can you use the open number line to find 35 + 24?
Write an equation to show the sum. Explain your work.

I can … use an open number line to add tens and ones within 100.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 15

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 16

Convince Me! Explain how you can use an open number line to find 56 + 35.

Guided Practice

Use an open number line to find each sum.
Question 1.
59 + 24 = _________
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 17
Answer: 59 + 24 = 83
Question 2.
47 + 25 = _________
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
Answer:
First, draw a line.
Represent the numbers on the line.
The first number is 47 and counts by 20 then it gets 67 and hump 5 then we get 72.
Count the numbers and draw an arrow
47 + 25 = 72
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies img_2

Independent Practice

Use an open number line to find each sum.
Question 3.
34 + 15 = ________
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
Answer:
First, draw the line.
Represent the numbers on the line.
The first number is 34 and counts by 10 then it gets 44 and 5 then we get 49.
Count the numbers and draw an arrow.
34 + 15 = 49
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies img_3

Question 4.
34 + 46 = ________
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
Answer:
34 + 46 = 80
First, draw the Line.
Represent the number on the line.
The first number is 34 and counts by 20 then it gets 54 and counts again 20 then it gets 74 and jump to 6 then it gets 80.
Count the numbers and draw an arrow
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18
Question 5.
16 + 28 = _________
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
Answer:
16 + 28 =44
First, draw the Line.
Represent the number on the line.
The first number is 16and counts by 10 then it gets 26 and jumps to 2 then it gets 28.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (1)
Count the numbers and draw an arrow.
Question 6.
59 + 26 = ________
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
Answer: 59 + 26 = 85
First draw the Line.
Represent the number on the line.
The first number is 59 and counts by 20 then it gets 79 and jumps to 6 then it gets 85.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (1)
Question 7.
Number Sense Matt found 55 + 28 using the open number line below. Is his work correct? Explain.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 19
Answer: 55 + 28 = 83

Problem Solving

Use the open number line to solve each problem below.
Question 8.
Reason There are 24 apples in a basket. There are 19 apples on a tray. How many apples are there in all?
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
_________ apples
Answer: Apples in a basket = 24
Apples in a tray = 19
Total number of apples = 24 + 19 = 43
Using the number line.
First, draw the Line.
Represent the number on the line.
The first number is 24 and counts by 10 then it gets 34 and jumps to 9 then it gets 43.
Count the numbers and draw an arrow.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies img_18

Question 19.
Reason Jamie has 27 more berries than Lisa. Lisa has 37 berries. How many berries does Jamie have?
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
_________ berries
Answer:
Lisa has berries = 37
Jamie has berries = 27 berries more than Lisa
Jamie has berries = 37 + 27 =64
First draw the Line.
Represent the number on the line.
The first number is 37 and counts by 20 then it gets 54  and jumps to 9 then it gets 80.
Count the numbers and draw an arrow.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies img_19

Question 10.

Higher Order Thinking Use two different number lines to show that 34 + 23 has the same value as 23 + 34.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 18
Answer:
34 + 23 = 57
First, draw the Line.
Represent the number on the line.
The first number is 34 and counts by 20 then it gets 54 and jumps to 3 then it gets 57.
Count the numbers and draw an arrow.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies img_10 a
23 + 34 = 57
First, draw the Line.
Represent the number on the line.
The first number is 23 and counts by 30 then it gets 53 jumps to 3 then it gets 57.
Count the numbers and draw an arrow.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies img_10 b

Question 11.
Assessment Practice Use the numbers on the cards. Write the missing numbers under the number line to show how to find the sum.
Envision Math Common Core 2nd Grade Answer Key Topic 3 Add Within 100 Using Strategies 19
43 + 25 = _________
Answer:
43 + 25 = 68
Envision-Math-Common-Core-2nd-Grade-Answers-Topic-3-Add-Within-100-Using-Strategies-20

Lesson 3.3 Break Apart Numbers to Add

Solve & Share
Josh has 34 cans to recycle. Jill has 27 cans. How many cans do they have in all? Solve any way you choose. Use drawings and equations to explain your work.
I can … break apart numbers into tens and ones to find their sum.
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 21

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 22

Convince Me! Explain how you can break apart 28 to find 33 + 28.

Guided Practice

Break apart the second addend to find the sum. Show your work. Use an open number line to help.
Question 1.
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 23

Independent Practice

Break apart the second addend to find the sum. Show your work. Draw an open number line to help.
Question 2.
42 + 16 = ________
Answer:
42 + 16 =
42 + 10 + 6
52 + 6 = 58
First draw the Line.
Represent the number on the line.
The first number is 42 and counts by 10 then it gets 52 and jumps to 6 then it gets 58.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (2)
Question 3.
36 + 44 = ________
Answer:
36 + 44
36 + 40 + 4
76 + 4 = 80
First draw the Line.
Represent the number on the line.
The first number is 36 and counts by 20 then it gets 56 and counts again by 20 ten we get 76 and jump to 4 then it gets 80.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (1)
Question 4.
41 + 37 = ________
Answer:
41 + 37
41 + 30 + 7
71 + 7 = 78
First draw the Line.
Represent the number on the line.
The first number is 41 and counts by 30 then it gets 71 and jumps to 7 then it gets 78.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (1)
Question 5.
35 + 47 = ________
Answer:
35 + 47
35 + 40 + 7
75 + 7 = 82
First draw the Line.
Represent the number on the line.
The first number is 35 and counts by 40 then it gets 75 and jumps to 7 then it gets 82.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (1)
Question 6.
32 + 28 = ________
Answer:
32 + 28
32 + 20 + 8
52 + 8 = 60
First draw the Line.
Represent the number on the line.
The first number is 32 and counts by 20 then it gets 52 and jumps to 8 then it gets 60.
Count the numbers and draw an arrow.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies img_16a

Question 17.
48 + 27 = ________
Answer:
48 + 27
48 + 20 + 7
68 + 7 = 75
First draw the Line.
Represent the number on the line.
The first number is 48 and counts by 20 then it gets 68 and jumps to 7 then it gets 75.
Count the numbers and draw an arrow
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (1)
Question 8.
Number Sense Write the digit that makes each equation true.
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 24
Answer:
36 + 52 = 88
Here the digit 2 makes the equation true.
28 + 47 = 75
Here the digit 7 makes the equation true.
14 + 43 = 57
Here the digit 3 makes the equation true.
53 + 29 = 82
Here the digit 9 makes the equation true.
Problem Solving

Solve each problem. Show your work.
Question 9.
Amir planted 35 trees. Juan planted 27 trees. How many trees did they plant in all?
________ trees
Answer:
Given that,
Total number of trees planted by Amir  = 35
Total number of trees planted by Juan = 27
Total number of  plants planted by Amir and Juan = 35 + 27 = 62
Question 10.
Carmen has 18 pennies. Patrick has 12 more pennies than Carmen. How many pennies does Patrick have?
________ pennies
Answer:
Given that,
Total number of pennies at Carmen  = 18
Total number of pennies at Patrick  more than Carmen = 12
Total number of pennies at Patrick = 18 + 12 = 30
Question 11.
Higher Order Thinking Use the numbers on the cards. Use each number once to write a true equation.
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 25
Answer:
The numbers on the card are 3, 2, 8
First, write the 2 in the first empty box then we get 52, and write the 3 in the second empty box then we get 34
By adding 52 and 34 we get 86. Write the 8 in the third box.
The true equation is
52 + 34 = 86
Envision-Math-Common-Core-2nd-Grade-Answers-Topic-3-Add-Within-100-Using-Strategies-25
Question 12.
Assessment Practice which has a sum of 67? Choose all that apply.
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 26
Answer:
15 + 52 = 67

Lesson 3.4 Add Using Compensation

Solve & Share
27 + 16 = ________
Draw counters on the ten frames to show each addend. Then show how you can move some counters to make it easier to find the sum. Explain your work.
I can … break apart addends and combine them in different ways to make numbers that are easy to add mentally.
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 27

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 28

Convince Me! Solve.
19 + 26 = ☐
Explain how you can change the addends to make them easier to add.

Guided Practice

Use compensation to make numbers that are easier to add. Then solve. Show your work.
Question 1.
17 + 9 = ________
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 29

Question 2.
16 + 14 = __________
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 30
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Topic-3-Add-Within-100-Using-Strategies-30

Independent Practice

Use compensation to make numbers that are easier to add. Then solve. Show your work.
Question 3.
33 + 19 = __________
Answer:
33 + (10 + 9)
(33 + 10) + 9
43 + 9 = 52
Question 4.
28 + 8 = __________
Answer:
28 + (2 + 6)
(28 + 2) + 6
30 + 6 = 36
Question 5.
27 + 36 = __________
Answer:
27  + ( 30 + 6)
(27 + 30) + 6
57 + 6 = 63
Question 6.
Number Sense Explain how you can use compensation to make numbers that are easy to add. Solve. Show your work.
28 + 37 = Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 31
______ + ______ = Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 31
Answer:
28 + 37 =
28 + ( 30 + 7)
(28 + 30) + 7
58 + 7 = 65
Question 7.
Higher Order Thinking Show two different ways you could use compensation to make numbers that are easy to add. Solve. Show your work.
17 + 26 = Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 31
Answer:
17 + 26
17 + (20 + 6)
(17 + 20) + 6
37 + 6 = 43

Problem Solving

Use compensation to make numbers that are easier to add. Then solve. Show your work.
Question 8.
Explain Bella said there is only one way to rewrite this problem to make the numbers easier to add. Is she correct? Explain. Then solve.
42 + 29 = Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 31
Answer:
42 + 29
42 + (20 + 9)
(42 + 20) + 9
62 + 9 = 71
Question 9.
Vocabulary Show two different ways to use compensation to find the sum. Then solve.
58 + 35 = Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 31
What number is close to 58 or 35?
Answer:
58 + 35
58 + (30 + 5)
(58 + 30) + 5
88 + 5 = 92
Question 10.
Higher Order Thinking Show two different ways to use compensation to find the sum. Then solve.
37 + 16 + 5 = Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 31
Answer:
37 + (10 + 6) + 5
(37 + 10) + 6 + 5
47 + 6 + 5
47 + 11
47 +(10 + 1)
(47 + 10) + 1
57 + 1= 58
Question 11.
Assessment Practice which is equal to 42 + 18? Choose all that apply.
☐ 58
☐ 40 + 20
☐ 40 + 10 + 8
☐ 50 + 10
Answer:
The equation 40 + 20 and 50 + 10 are equal to 42 + 18

Lesson 3.5 Practice Adding Using Strategies

Solve & Share
Tameka has 39 blocks. Kim has 43 blocks. How many blocks do they have in all? Choose any strategy. Solve. Show and explain your work.

I can … choose a strategy to help me add two-digit numbers.
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 32
_________ bolcks

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 33

Convince Me! In 66 + 25 above, why was 4 added to 66 and then subtracted from 95?

Guided Practice

Find each sum. Use any strategy. Show your work.
Question 1.
Envision Math Common Core 2nd Grade Answers Topic 3 Add Within 100 Using Strategies 34

Question 2.
67 + 26 = ___________
Answer:
67 + 26 =
67 + 20 + 6
87 + 6 = 93

Independent Practice

Find each sum. Use any strategy. Show your work.
Question 3.
33 + 52 = ___________
Answer:
33 + 52 =
33 + 50 + 2
73 + 2 = 75
Question 4.
27 + 6 = ___________
Answer:
27 + 6 = 33
Question 5.
___________ = 49 + 45
Answer:
49 + 45
49 + 40 + 5
89 + 5 = 94
Question 6.
57 + 12 = ___________
Answer:
57 + 12
57 + 10 + 2
67 + 2 = 69
Question 7.
___________ = 63 + 20
Answer:
66 + 20 = 86
Question 18.
14 + 58 = ___________
Answer:
14 + 58
14 + 50 + 8
64 + 8 = 72
Question 9.
45 + 55 = ___________
Answer:
45 + 55
45 + 50 + 5
95 + 5 = 100
Question 10.
87 + 9 = ___________
Answer:
87 + 9 = 96
Question 11.
19 + 61 = ___________
Answer:
19 + 61
19 + 60 + 1
79 + 1 = 80

Number Sense Write the digit that makes each equation true.
Question 12.
45 + 1☐ = 61
Answer:
45 + 16 = 61
The digit 6 makes the equation true.
Question 13.
84 = ☐8 + 56
Answer:
84 = 28 + 56
The digit 2 makes the equation true.
Question 14.
3☐ + 19 + 56
Answer:
30 + 19 + 56 = 105
The digit 0 makes the equation true

Problem Solving

Use the hundred chart to solve each problem. Be prepared to explain your work.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 35

Question 15.
Reasoning Martin has 44 marbles. Carol has 39 marbles. Steve has 90 marbles. How many marbles do Martin and Carol have in all? Do they have more or fewer marbles than Steve?
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 36
_______ marbles
Circle:
more
fewer
Answer:
Given that,
Total number of marbles at Martin = 44
Total number of marbles at Carol = 39
Total number of marbles at Steve = 90
Total  number of marbles at Martin and Carol  = 44 + 39
Using a hundred charts find the sum of 44 + 39
In the hundred charts we start at 44 then down to 3 rows we get 74 and front to 4 space then we get 78
44 + 39 = 78
They both them have fewer marbles than Steve.
Question 16.
Higher Order Thinking José collected 32 leaves on Saturday. On Sunday, he collected 14 more leaves than he did on Saturday.
How many leaves did José collect in all?
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 37
________ leaves
Answer:
Given that
Total number of leaves Jose collected  on Saturday = 32
Total number of leaves Jose collected on Sunday = 14
Total number of leaves they collected = 32 + 14 = 46
Question 17.
Lucita wants to use an open number line to find 53 + 18. Show how Lucita can use an open number line to find 53 + 18.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 38
Answer:
53 + 18 = 71
First, draw the Line.
Represent the number on the line.
The first number is 53 and counts by 10 then it gets 63 and jumps to 8 then it gets 71.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (2)
Question 18.
Assessment Practice Maria used a hundred chart to find a sum. She started at 68. Then she moved down 3 rows and back I space. Which number did she land on?
A. 88
B. 97
C. 98
D. 99
Answer:
Maria started at 68
She moved down to three rows is 98
And she back to 1 space then his number is 97

Lesson 3.6 Solve One-Step and Two-Step Problems

Solve & Share
The red team has 15 more points than the blue team. The blue team has 36 points. How many points does the red team have?
Choose any strategy. Solve. Explain your work.

I can … use drawings and equations to solve one-step and two-step problems.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 39

Visual Learning Bridge
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 40

Convince Me! What steps did you take to find the number of tickets Amy sold? Explain.

Guided Practice

Solve the two-step problem. Show your work.
Question 1.
Steve read 15 books. Sam read 9 fewer books than Steve. Dixon read 8 more books than Sam. How many books did Sam read?
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 41
Sam read _______ books.
Envision-Math-Common-Core-Grade-2-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-41
sam read 6 books.

How many books did Dixon read?
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 42
Dixon read _______ books.
Envision-Math-Common-Core-Grade-2-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-42
Dixon read 14 books.

Independent Practice

Solve the problems below. Show your work.
Question 2.
Brian has 17 fewer marbles than Kyle. Brian has 21 marbles. How many marbles does Kyle have?
________ marbles
Answer:
Given that,
Total number of marbles at Brain = 21
The total number of marbles at Brain has  fewer than Kyle  = 17
Total number of marbles marbles at Kyle = 21 + 17 = 38
Question 3.
Clint catches 7 frogs. 3 frogs hop away. Then Clint catches 6 more frogs. How many frogs does Clint have now?
_________ frogs
Answer:
Given that,
Total number of frogs the Clint catches = 7
Total number of Frogs hop away = 3
Clint catches another more frogs = 6
Total number of frogs at Clint = 7 – 3 + 6 = 10
Question 4.
Erwin sees 23 birds in a tree. Then 18 more birds come. How many birds does Erwin see now?
_________ birds
Answer:
Given that,
Erwin sees the total number of birds in a tree = 23
More birds come on the tree = 18
Total number of birds that seen bye the Erwin  = 23 + 18 = 41
Question 5.
There are 31 bluefish in a pond. There are also 8 goldfish and 3 redfish in the pond. How many fish are in the pond?
________ fish
Answer:
Given that
Total number of Blue fishes in a pound = 31
Total number of Goldfishes in a pound = 8
Total number of Red fishes in a pound = 3
Total number of fishes in a pound = 31 + 8 + 3 = 42
Question 6.
Higher Order Thinking Mr. Leu buys 6 bananas. Then he buys 8 more bananas. He gives some bananas to Mr. Shen. Now Mr. Leu has 5 bananas. How many bananas did Mr. Leu give to Mr. Shen?
_________ bananas
Answer:
Given that,
Mr. Leu buys bananas = 6
He buys more bananas = 8
Total bananas at Mr. Leu = 6 + 8 = 14
Mr. Leu gave some bananas to the Mr. Shen
Mr. Leu left only 5 bananas
Mr. Leu gave to Mr. Shen = 14 – 5 = 9

Problem Solving

Solve the problems below. Show your work.
Question 7.
There are 21 more green crayons than blue crayons. There are 14 blue crayons. How many green crayons are there?
__________ green crayons
Answer:
Given that,
Total number of Blue crayons = 14
Green crayons are 21 more than blue crayons.
Total number of Green crayons = 14 + 21 = 35

Question 8.
Make Sense Dan swims 4 laps on Monday. He swims 5 laps on Tuesday. Then he swims 9 laps on Wednesday. How many laps does Dan swim in all?
_________ laps
Answer:
Given that,
Dan swims on Monday = 4 laps
Dan swims on Tuesday = 5 laps
Dan swims on Wednesday = 9 laps
Total number of laps that Don swim = 4 + 5 + 9 = 18

Question 9.
Higher Order Thinking Robert has 20 blueberries. He has 10 more blueberries than Janessa. He has 14 fewer blueberries than Amari. How many blueberries does Janessa have? How many blueberries does Amari have?
Janessa has ________ blueberries.
Amari has __________ blueberries.
Answer:
Given that,
A robot has 20 blueberries
He has 10 more blueberries than Janessa
Janessa has blueberries = 20 – 10 = 10
The robot has 14 blueberries fewer than Amari
Amari has total number of blueberries = 20 + 14 = 34

Question 10.
Assessment Practice Billy saw 19 animals at Grayson Zoo in the morning. He saw 17 more animals after lunch. How many animals did Billy see in all?
__________ animals
Answer:
Given that,
Billy saw animals at Grayson Zoo in the morning = 19
Billy saw animals at Grayson Zoo in the afternoon = 17
Total number of animals that Billy saw = 19 + 17

Lesson 3.7 Problem Solving

Construct Arguments
Solve & Share

Carrie has 16 more red apples than green apples. She has 24 green apples. How many red apples are there?
Use any strategy to solve. Use pictures, numbers, or words to explain your thinking and work.

I can … use pictures, numbers, and words to explain why my thinking and work are correct.

Thinking Habits
Construct Arguments
How can I use math to explain why my work is correct?
Am I using numbers and symbols correctly?
Is my explanation clear?

Visual Learning Bridge
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 43

Convince Me! Are both math arguments above clear and complete? Explain.

Guided Practice

Solve. Use pictures, words, or numbers to make a math argument. Show your work.
Question 1.
There are 16 chickens in the yard. There are 19 chickens in the barn. There are 30 nesting boxes. Will all of the chickens have a nest? Explain.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 44
Answer:
Given that,
Total number of Chickens in a yard = 16
Total number of Chickens in a barn = 19
Total number of Chickens in a nesting  = 30
Total number of chickens = 16 + 19 = 35
5 chickens have no nest

Independent Practice

Solve each problem. Use pictures, words, or numbers to make a math argument. Show your work.
Question 2.
Greg had 45 sports cards. Jamal gives him 26 more cards. How many sports cards does Greg have now?
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 45
_________ sports cards
Answer:
Given that,
Total number of sports cards at Grah  = 45
Jamal gives more cards to Grah = 26
Total number of sports cards at Grah = 45 + 26 = 71

Question 3.
Denise drew 8 stars with crayons. Then she drew 6 more stars. Trina drew 5 stars. How many fewer stars did Trina draw than Denise?
________ fewer stars
Answer:
Given that,
Denise draw stars with crayons = 8
She draws more stars = 6
Total number of stars drawn by Denise = 8 + 6 = 14
Trina draw a star = 5
14 – 5 = 9
Trina draw 9 fewer stars than Denise

Problem Solving

Performance Task
Bean Bag Toss Evan and Pam each throw two bean bags. Points are added for a score. Pam’s total score is 100. Which two numbers did Pam’s bean bags land on?
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 46
Question 4.
Make Sense What information is given? What do you need to find?
Answer:
In the above task, Pam and Evan play a bean bag toss game.
The score Pam’s is 100
The numbers that Pam’s bean bag lands on are 56 and 44.
By adding 56 and 44 we get 100.so, the beam bag lands on 56 and 44.
Question 5.
Explain Which numbers did Pam’s bags land on? Explain how you know.
Answer:
Given that,
Pam’s bags land on 56 and 44
The total score Pam’s is 100
By adding 56 and 44 we get 100
So, Pam’s bags are landed on 56 and 44.

Question 6.
Explain How could you use a hundred charts to solve the problem? Explain.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 47
Answer:
using a hundred charts for example you went to find the sum of 10  + 15.
first, mark the 10 in the hundred charts and down to 1 row and back to 5 places then we get 15 has the answer.
This is the way to solve the problem using a hundred charts.

Topic 3 Fluency Practice Activity

Find & Match
Find a partner. Point to a clue. Read the clue.
Look below the clues to find a match. Write the clue letter in the box next to the match.
Find a match for every clue.
I can … subtract within 20.

Clues
A. Every difference equals 3.
B. Every difference is less than 2.
C. Every difference equals 11 – 5.
D. Exactly two differences are equal.
E. Every difference is greater than 8.
F. Exactly three differences are odd.
G. Every difference equals 16 – 8.
H. Exactly three differences are even.

Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 48

Topic 3 Vocabulary Review

Understand Vocabulary
Word List

  • bar diagram
  • break apart
  • compensation
  • mental math
  • ones
  • open number line
  • tens

Question 1.
Circle the numbers that have a 3 in the one’s place.
33
45
13
38
Answer:
In the above-given numbers, 33 and 13 has 3 in the one’s place then circle the 33 and 13.
Question 2.
Cross out the numbers that do NOT have an 8 in the tens place.
80
18
78
89
Answer:
In the above-given numbers, 18 and 78 do not have 8 in the ten’s place. Then cross out the 18 and 78.
Envision-Math-Common-Core-2nd-Grade-Answers-Topic-3-Add-Within-100-Using-Strategies-20 a
Question 3.
Write an equation to show how to break apart 54 by place value.
Answer: 50 + 4
Question 4.
Use the open number line to find 38 + 23. Add the tens and then add the ones.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 49
Answer:
38 + 23
38 + (20 + 3)
58 + 3 = 61
First draw the Line.
Represent the number on the line.
The first number is 38 and counts by 20 then it gets 54 and jumps to 3 then it gets 61.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (1)

Use Vocabulary in Writing
Question 5.
Describe a way to find 47 + 18. Use terms from the Word List.
Answer:
47 + (10 + 8)
(47 + 10) + 8
57 + 8 = 65

Topic 3 Reteaching

Set A

You can use a hundred charts to help you add. Find 62 + 12.
Start at 62. Move down 1 row to add the 1 ten in 12.
Then move over 2 columns to add the 2 ones in 12.
Envision Math Common Core Grade 2 Answer Key Topic 3 Add Within 100 Using Strategies 50

Use a hundred charts to find each sum.
Question 1.
85 + 15 = _______
Answer:
Using the hundred chart the sum of 85 + 15 is
In the hundred charts, we start at the 85 then down to 1 row then we get 95, and move front to 5 space then we get 100.
85 + 15 = 100
Question 2.
60 + 23 = _________
Answer:
Using the hundred chart the sum of 60 + 23 is
In the hundred charts, we start at 60 and then move down to 2 rows then we get 80 and move front to 3 space then we get 83
60 + 23 = 83

Set B

You can use an open number line to find 49 + 32.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 51
Place 49 on the number line. There are 3 tens in 32. So, count on by 10 three times. There are 2 ones in 32. So, count on 2 from 79.
So, 49 + 32 = 81

Use an open number line to find each sum.
Question 3.
35 + 13 = ________
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 52
Answer:
35 + 13 = 48
First, draw the Line.
Represent the number on the line.
The first number is 35 and counts by 10 then it gets 45  and jumps to 3 then it gets 48.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-Grade-2-Answers-Topic-3-Add-Within-100-Using-Strategies-52 (1)

Question 4.
47 + 26 = _________
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 52
Answer:
47 + 26 = 73
First, draw the Line.
Represent the number on the line.
The first number is 47 and counts by 20 then it gets 67 and jumps to 6 then it gets 73.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-Grade-2-Answers-Topic-3-Add-Within-100-Using-Strategies-52 (1)

Set C

Find 55 + 17.
Break apart 17 into 10+ 7.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 53

Break apart the second addend to find the sum. Show your work.
Question 5.
53 + 28 = _________
Answer:
53 + 28
53 + 20 + 8
73 + 8 = 81Question 6.
78 + 19 = _________
Answer:
78 + 19
78 + 10 + 9
88 + 9 = 97

Set D

Find 48 + 27.
48 is close to 50. So, take 2 from 27 and give it to 48 to make 50.
48 + 27 = ?
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 54

Use compensation to make numbers that are easier to add. Then solve. Show your work.
Question 7.
17 + 46 = ________
Answer:
17 + 46
17 + 40 + 6
57 + 6 = 63

Question 8.
29 + 57 = ________
Answer:
29 + 57
29 + 50 + 7
79 + 7 = 86

Set E

You can use different strategies and tools to find a sum.
You can:

  • Use a hundred chart
  • Use an open number line
  • Break apart one addend
  • Use compensation

Solve. Show your work.
Question 9.
Ted’s puzzle has 37 more pieces than his brother’s puzzle. His brother’s puzzle has 48 pieces. How many pieces does Ted’s puzzle have?
________ pieces
Answer:

Given that,
Ted’s puzzle has more pieces than her brother = 37
His brother puzzle has pieces = 48
Total number of pieces does Ted’s have = 48 + 37 = 85

Set F

Marla walks 12 blocks on Monday. On Tuesday, she walks 4 fewer blocks. How many blocks does Marla walk in all?
Blocks Marla walks on Tuesday:
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 55

Solve the two-step problem.
Question 10.
Wyatt has 16 crayons. He buys 24 new crayons. Then he finds 7 more crayons. How many crayons does Wyatt have now?
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 56
________ crayons
Answer:
Envision-Math-Common-Core-Grade-2-Answers-Topic-3-Add-Within-100-Using-Strategies-56
Total number of crayon = 47

Set G

Thinking Habits
Construct Arguments
How can I use math to explain my work?
Am I using numbers and symbols correctly?
Is my explanation clear?
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 57

Solve the problem. Use words and numbers to make a math argument.
Question 11.
A second-grade class sets a goal to collect 70 cans. One week they collect 38 cans. The next week they collect 35 cans. Do they meet their goal?
Answer:
Given that,
A second-grade class set a goal to collect cans = 70
One week the second-grade class set collect cans = 38
Next week the second-grade class set collect cans = 35
Total number of cans they collected = 38 + 35 =73
Yes they meet their goal by collecting 73 cans out of 70

Topic 3 Assessment Practice

Question 1.
Which have a sum of 43? Choose all that apply.
☐ 33 + 10
☐ 28 + 13
☐ 10 + 33
☐ 19 + 24
☐ 10 + 21
Answer:
33 + 10 has a sum of 43
10 + 33 has a sum of 43
19 + 24 has a sum of 43
Question 2.
Terry has 63 crayons. She gets 25 more crayons. How many crayons does Terry have in all? Show your work.
________ crayons
Answer:
Given that,
Total number of crayons near Terry = 63
Tenny get more crayons = 25
Total number of crayons at Terry = 63 + 25 = 88
Question 3.
Which equation does this number line show?
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 58
A. 57 + 28 = 85
B. 57 + 38 = 95
C. 57 + 33 = 90
D. 57 + 39 = 96
Answer:
57 + 38 = 95
Question 4.
Use the numbers on the cards. Write the missing numbers under the number line to show how to find the sum of 40 + 35.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 59
Answer:
Question 5.
Colin has 54 pennies and 28 nickels. How many coins does Colin have?
Break apart the second addend to solve. Show your work.
________ coins
Answer:
Given that,
Total number of pennies near Colin = 54
Total number of nickels near Colin = 28
Total number of coins near colin = 54 + 28
54 + (20 + 8)
(54 + 20) + 8
74 + 8 = 82

Question 6.
Show how to add 68 + 16 using the open number line.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 60
68 + 16 = ___________
Answer:
68 + 16 = 84
First draw the Line.
Represent the number on the line.
The first number is 68 and counts by 10 then it gets 78 and jumps to 6 then it gets 84.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-Grade-2-Answers-Topic-3-Add-Within-100-Using-Strategies-52 (1)
Question 7.
Part A
Show how you can use an open number line to find 44 + 27.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 60
44 + 27 = _________
Answer:
44 + 27 = 71
First draw the Line.
Represent the number on the line.
The first number is 44 and counts by 20 then it gets 64 and jumps to 7 then it gets 71.
Count the numbers and draw an arrow.
Envision-Math-Common-Core-Grade-2-Answers-Topic-3-Add-Within-100-Using-Strategies-52 (1)

Part B
In words, tell how you used the open number line to find the sum.
Answer:
Suppose  we have a sum that is 14 + 13
Then draw a line and represent the numbers on a line and place a 14 on the line shift  10 from the 14 we get 24 then jump to 3 then we get 27.
The sum of 14 + 13 = 27.
Envision-Math-Common-Core-2nd-Grade-Answer-Key-Topic-3-Add-Within-100-Using-Strategies-18 (1)

Question 8.
Which have a sum of 70? Choose all that apply.
☐ 35 + 35
☐ 40 + 30
☐ 45 + 45
☐ 50 + 200
☐ 30 + 30
Answer:
35 + 35
40 + 30

Question 9.
Lisa has 18 markers. Adam has 22 markers. Will all of the markers fit in a box that can hold 38 markers?
Make a math argument. Explain.
Answer:
Given that,
Total number of markers near Lisa = 18
Total number of markers near Adam = 22
Total number of Markers fit in a box = 38
Total number of markers = 18 + 22 = 40
Total markers are not fit into a box.

Question 10.
Ted has 52 cards in a box. Tyrone has 48 more cards than Ted. How many cards does Tyrone have? Show your work to explain your thinking.
________ cards
Answer:
Given that
Ted has  cards in a box = 52
Tyrone has more card than Ted = 48
Total number of cards at Tyrone = 52 + 48 = 100
Question 11.
Which are equal to 47 + 25? Choose all that apply.
☐ 40 + 20 + 7 +5
☐ 40 + 20 + 12
☐ 50 + 12
☐ 50 + 22
Answer:
To find the sum of 47 + 25 we apply the 40 + 20 + 7 + 5

Question 12.
Emma has 46 rocks. She gets 25 more rocks from Gus. How many rocks does Emma have now?
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 61
________ rocks
Answer:
Given that,
Emma has rocks = 46
She get more rocks = 25
Total number of rocks at Emma = 46 + 25 = 71
Question 13.
Is each sum 64? Choose Yes or No.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 62
Answer:
Envision-Math-Common-Core-Grade-2-Answers-Topic-3-Add-Within-100-Using-Strategies-62

Question 14.
Break apart the second addend to find 56 + 38. Show your work.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 63
56 + 38 = ________
Answer:
56 + 38
56 + 30 + 8
86 + 8 = 94

Question 15.
Write an equation to solve each part of the two-step problem.
Ken has 45 stamps. He uses 20 stamps. Then he buys 7 more stamps. How many stamps does he have now?
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 64
Ken has ________ stamps.
Answer:
Given that,
Ken has total number of stamps = 45
He used total number of stamps = 20
He buy another stamps = 7
Total number of stamps Ken have = 45 – 20 + 7
25 + 7 = 32

Question 16.
Show two different ways to find 28 + 49 using compensation.
Way 1
Way 2
Answer:
Way 1: 28 + 49 = 77
Way 2:  28 + 49
28 + 40 + 9
68 + 9 = 77

Topic 3 Performance Task

Popcorn Sales
A second-grade class is selling popcorn to help pay for a field trip.
This table shows how many boxes some students have sold.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 65

Question 1.
How many boxes of popcorn did Ted and Mary sell in all? Use the open number line to solve. Show your work.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 66
_________ boxes
Answer:
Given that,
Number of popcorn did Ted sell = 21
Number of popcorn did Mary sell = 34
Total number of popcorn box sell = 21 + 34 = 55
First draw the Line.
Represent the number on the line.
The first number is 21and counts by 30 then it gets 51and jumps to 4 then it gets 80.
Count the numbers and draw an arrow.

Question 2.
James says that Mary and Nancy sold more boxes in all than Darnell and Ted sold in all. Do you agree with him?
Circle:
Yes
No
Explain your answer.
Answer:
Given that,
Total number of boxes sold by Mary = 34
Total number of boxes sold by Nancy = 19
Total number of boxes sold by Mary and Nancy = 34 + 19 = 43
Total number of boxes sold by Darnell = 28
Total number of boxes sold by Ted = 21
A total number of boxes sold by Darnell and Ted = 21 + 28 = 49
James said wrong that Mary and Nancy sold fewer boxes than Darnell and Ted.
Question 3.
Which two students sold a total of 55 boxes? Use any strategy to solve. Show your work.
Circle the names of the two students.
Envision Math Common Core Grade 2 Answers Topic 3 Add Within 100 Using Strategies 67

Question 4.
Nancy sold 18 fewer boxes than Lucas. How many boxes did Lucas sell?

Part A
Solve the problem. Show your work and explain your thinking.
________ boxes
Answer:
Given that,
Nancy sold fewer boxes than Lucas = 18
Total number of boxes that Nancy sold = 19
Total number of boxes that Lucas sold more than Nancy = 19 – 18 = 1

Part B
Look at the list of strategies on the left. To show that your answer in Part A is correct, use a different strategy to solve the problem.
Answer:

Envision Math Grade 5 Answer Key Topic 2.6 Subtracting Decimals

Envision Math 5th Grade Textbook Answer Key Topic 2.6 Subtracting Decimals

Subtracting Decimals

How can you subtract decimals?
What is the difference in the wingspans of the two butterflies?
Choose an Operation
Subtract to find the difference.
Find 5.92 – 4.37.
Estimate: 6 – 4 = 2
Envision Math Grade 5 Answers Topic 2.6 Subtracting Decimals 1

Other Examples

Using 0 as a placeholder
Find 49.59 – 7.9
Envision Math Grade 5 Answers Topic 2.6 Subtracting Decimals 3

Using 0 as a placeholder

Find 24.6 – 8.27.
Envision Math Grade 5 Answers Topic 2.6 Subtracting Decimals 4

Subtracting Money
Find $26.32 – $5.75.
Envision Math Grade 5 Answers Topic 2.6 Subtracting Decimals 5

Subtracting Decimals 1

Guided Practice*

In 1 through 8, subtract the decimals.

Do you know how?

Question 1.
Envision Math Grade 5 Answers Topic 2.6 Subtracting Decimals 6
Answer:

Question 2.
Envision Math Grade 5 Answers Topic 2.6 Subtracting Decimals 7
Answer:

Question 3.
Envision Math Grade 5 Answers Topic 2.6 Subtracting Decimals 8
Answer:

Question 4.
Envision Math Grade 5 Answers Topic 2.6 Subtracting Decimals 9
Answer:

Question 5.
56.8 – 2.765
Answer:

Question 6.
$43.80 – $16.00
Answer:

Question 7.
22.4 – 10.7 8.
Answer:

Question 8.
$36.40 – $21.16
Answer:

Do you understand?

Question 9.
Reasonableness Explain why 1.55 cm is a reasonable answer for the difference in the wingspans of the two butterflies.
Answer:

Subtracting Decimals 2

Question 10.
In the Other Examples above, is the value of 7.9 changed when you annex a zero after 7.9? Why or why not?
Answer:

Question 11.
Writing to Explain How is finding 9.12 – 4.8 similar to finding $9.12 – $4.80? How is it different?

Step 1

Write the numbers, lining up the decimal points.
Envision Math 5th Grade Answer Key Topic 2.6 Subtracting Decimals 40

Step 2

Subtract the hundredths. Regroup if needed.
Envision Math 5th Grade Answer Key Topic 2.6 Subtracting Decimals 40.1

Step 3

Subtract the tenths and ones.
Bring down the decimal point.
Envision Math 5th Grade Answer Key Topic 2.6 Subtracting Decimals 41
The difference is reasonable
since the estimate was 2.
The difference in the wingspans is 1.55 cm.

Independent Practice

In 12 through 23, subtract to find the difference.

Question 12.
Envision Math Grade 3 Answer Key Topic 2.6 Subtracting Decimals 40.3
Answer:

Question 13.
Envision Math Grade 3 Answer Key Topic 2.6 Subtracting Decimals 41.3
Answer:

Question 14.
Envision Math Grade 3 Answer Key Topic 2.6 Subtracting Decimals 42
Answer:

Question 15.
Envision Math Grade 3 Answer Key Topic 2.6 Subtracting Decimals 43
Answer:

Question 16.
15.03 – 4.121
Answer:

Question 17.
13.9 – 3.8
Answer:

Question 18.
65.18 – 12.005
Answer:

Question 19.
$52.02 – $0.83
Answer:

Question 20.
7.094 – 3.657
Answer:

Question 21.
34.49 – 12.619
Answer:

Question 22.
85.22 – 43.548
Answer:

Question 23.
$10.05 – $4.50
Answer:

Problem Solving

Question 24.
Writing to Explain Why is it necessary to line up decimal points when subtracting decimals?
Answer:

Question 25.
Reasonableness Sue subtracted 2.9 from 20.9 and got 1.8. Explain why this is not reasonable.
Answer:

Question 26.
The pyramid of Khafre measured 143.5 meters high. The pyramid of Menkaure measured 65.5 meters high. What was the difference in the heights of these two pyramids?
A. 68.8 meters
B. 69.3 meters
C. 78 meters
D. 212.3 meters
Envision Math 5th Grade Answer Key Topic 2.6 Subtracting Decimals 60

Question 27.
An average person’s upper leg measures 19.88 in. and the lower leg measure 16.94 in. How much longer is the upper leg than the lower leg?
Envision Math 5th Grade Answer Key Topic 2.6 Subtracting Decimals 61
Answer:

Envision Math Grade 5 Answer Key Topic 2.3 Estimating Sums and Differences

Envision Math 5th Grade Textbook Answer Key Topic 2.3 Estimating Sums and Differences

How can you estimate sums?
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 1
Students are collecting cans of dog food to give to an animal shelter. Estimate the sum of the cans collected in Weeks 3 and 4.

Another Example
How can you estimate differences?
Estimate 22.8 – 13.9.

One Way
Round each addend to the nearest whole number.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 3
22.8 – 13.9 is about 9.

Another Way
Substitute compatible numbers.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 4
22.8 – 13.9 is about 10.

Explain It

Question 1.
Which estimate is closer to the actual difference? How can you tell without subtracting?
Answer:

Question 2.
When is it appropriate to estimate an answer?
Answer:

Guided Practice*

Do you know HOW?

In 1 through 6, estimate the sums and differences.

Question 1.
49 + 22
Answer:

Question 2.
86 – 18
Answer:

Question 3.
179 + 277
Answer:

Question 4.
232 – 97
Answer:

Question 5.
23.8 – 4.7
Answer:

Question 6.
87.2 + 3.9
Answer:

Estimating Sums and Differences 1

Do you UNDERSTAND?

Question 7.
Give an example of when estimating is useful.
Answer:

Question 8.
The students in the example at the top collected more cans of dog food in week 4 than in week 3. Estimate about how many more.
Answer:

One Way
Round each addend to the nearest whole number.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 5
237 + 345 is about 500. The students collected about 500 cans of dog food in Weeks 3 and 4.

Another Way
Substitute compatible numbers.
Compatible numbers are easy to add.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 10
237 + 345 is about 600. The students collected about 600 cans of dog food in Weeks 3 and 4.

Independent Practice

In 9 through 24, estimate each sum or difference

Question 9.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 11
Answer:

Question 10.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 12
Answer:

Question 11.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 13
Answer:

Question 12.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 14
Answer:

Question 13.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 15
Answer:

Question 14.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 16
Answer:

Question 15.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 17
Answer:

Question 16.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 18
Answer:

Question 17.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 19
Answer:

Question 18.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 20
Answer:

Question 19.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 21
Answer:

Question 20.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 22
Answer:

Question 21.
3,205 – 2,812
Answer;

Question 22.
93 – 46
Answer;

Question 23.
1,052 + 963
Answer:

Question 24.
149 – 51
Answer:

In 25 through 39, estimate each sum or difference.

Question 25.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 23
Answer:

Question 26.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 24
Answer:

Question 27.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 25
Answer:

Estimating Sums and Differences 2

Question 28.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 26
Answer:

Question 29.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 27
Answer:

Question 30.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 28
Answer:

Question 31.
Envision Math Grade 5 Answers Topic 2.3 Estimating Sums and Differences 29
Answer:

Question 32.
Envision Math 5th Grade Answer Key Topic 2.3 Estimating Sums and Differences 30
Answer:

Question 33.
77.11 – 8.18
Answer:

Question 34.
35.4 – 7.8
Answer:

Question 36.
89.66 – 27.9
Answer:

Question 37.
22.8 + 49.2 + 1.7
Answer:

Question 38.
67.5 – 13.7
Answer:

Question 39.
$9.10 + $48.50 + $5.99
Answer:

Problem Solving

Question 40.
Writing to Explain The cost of one CD is $16.98, and the cost of another CD is $9.29. Brittany estimated the cost of these two CDs to be about $27. Did she overestimate or underestimate? Explain.
Answer:

Question 41.
Martha cycled 14 miles each day on Saturday and Monday, and 13 miles each day on Tuesday and Thursday. How many miles
did she cycle in all?
Answer:

Question 42.
One fifth-grade class has 11 boys and 11 girls. A second fifth-grade class has 10 boys and 12 girls. There are 6 math teachers. To find
the total number of fifth-grade students, what information is not needed?
A. The number of girls in the first class.
B. The number of boys in the first class.
C. The number of math teachers.
D. The number of boys in the second class.
Answer:

Question 43.
On vacation, Steven spent $13 each day on Monday and Tuesday. He spent $9 each day on Wednesday and Thursday. If Steven brought $56 to spend, how much did he have left to spend?
Answer:

Question 44.
Estimate 74.05 + 9.72 + 45.49 by rounding to the nearest whole number. What numbers did you add?
A. 75, 10, and 46
B. 74.1, 9.7, and 45.5
C. 74, 10, and 45
D. 75, 10, and 50
Answer:

Question 45.
Golden Gate Park is located in San Francisco, California. The park covers 1,017 acres and has been compared to the size and shape of Central Park in New York City. Central Park covers 843 acres. About how many more acres does Golden Gate Park cover than Central Park?
Envision Math 5th Grade Answer Key Topic 2.3 Estimating Sums and Differences 31

Number Patterns

Example:
What are the next two numbers in the pattern?
24, 29, 28, 33, 32, 37, 36, …
Think The first number is increased by 5. The next number is decreased by 1. I see that the pattern continues.
Envision Math 5th Grade Answer Key Topic 2.3 Estimating Sums and Differences 50
To find the next two numbers, add 5, and then subtract 1. The next two numbers are 41 and 40.

The following numbers form a pattern.
3, 7, 11, 15, 19, …
In this case the pattern is a simple one.
The pattern is add 4.
Some patterns are more complicated.
Look at the following pattern.
20, 24, 30, 34, 40, 44, 50, …
In this case, the pattern is add 4, add 6.
Look for a pattern. Find the next two numbers.

Question 1.
9, 18, 27, 36, 45, …
Answer:

Question 2.
90, 80, 70, 60, 50, …
Answer:

Question 3.
2, 102, 202, 302, …
Answer:

Question 4.
26, 46, 66 , 86, …
Answer:

Question 5.
20, 31, 42, 53, 64, …
Answer:

Question 6.
100, 92, 84, 76, 68, …
Answer:

Question 7.
1, 3, 9, 27, …
Answer:

Question 8.
800, 400, 200, 100, …
Answer:

Question 9.
20, 21, 19, 20, 18, 19, 17, …
Answer:

Question 10.
10, 11, 21, 22, 32, 33, …
Answer:

Question 11.
25, 32, 28, 35, 31, 38, …
Answer:

Question 12.
5, 15, 10, 20, 15, 25, 20, …
Answer:

Question 13.
The following numbers are called Fibonacci numbers.
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, …
Explain how you could find the next two numbers.
Answer:

Question 14.
Write a Problem Write a number pattern that involves two operations.
Answer:

enVision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length

enVision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length

Go through the enVision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length regularly and improve your accuracy in solving questions.

enVision Math Common Core 2nd Grade Answers Key Topic 14 More Addition, Subtraction, and Length

Essential Question:
How can you add and subtract lengths?

Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 1

enVision STEM Project: Modeling Land, Water, and Length
Find Out Find and share books and other sources that show the shapes and kinds of land and water in an area. Draw a picture or make a model to show the land or water in an area.
Journal: Make a Book Show what you learn in a book. In your book, also:

  • Draw a picture to show the shape of some land or water in your area.
  • Make up a math story about lengths. Draw a picture to show how to solve the problem in your story.

Review What You Know

Vocabulary
Question 1.
Circle the measuring unit that is better to estimate the length of a room.
meter
centimeter
Answer: centimeter

Question 2.
Circle the number of feet in 1 yard.
2 feet
3 feet
4 feet
12 feet
Answer: 3 feet

Question 3.
The clock shows the time a math class begins. Circle a.m. or p.m.
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 2
Answer: 10 a.m.

Estimate
Question 4.
Estimate the length of the eraser in centimeters.
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 3
About _______ centimeter
Answer: 4 centimeter

Compare
Question 5.
A sidewalk is 632 yards long. A jogging trail is 640 yards long.
Use <, >, or = to compare the lengths.
632 Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 4 640
Answer: 632 < 640

Rectangles
Question 6.
Label the 2 missing lengths of the sides of the rectangle.
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 5
Answer: The missing lengths are 3cm and 4 cm.
In the rectangle opposite sides are equal. So, the 2 missing lengths of the sides of a rectangle are 3cm and 4cm.

Pick a Project

PROJECT 14A
How tall are Ferris wheels?
Project: Write a Ferris Wheel Story
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 6

PROJECT 14B
How big are insects?
Project: Make Insect Drawings
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 7

PROJECT 14C
How can you measure if you do not have tools?
Project: Make a Measurement Poster
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 8

PROJECT 14D
How is some food grown?
Project: Draw a Garden Plan
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 9

Lesson 14.1 Add and Subtract with Measurements

Solve & Share
The ant crawled along the edge of this blue rectangle. Measure the total distance the ant crawled. Show your work and be ready to explain it.
I can … solve problems by adding or subtracting length measurements.
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 10

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 11

Convince Me! Explain how to find the distance around a square park that is 2 miles long on each side.

Guided Practice

Decide if you need to add or subtract. Then write an equation to help solve each problem.
Question 1.
What is the distance around the baseball card?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 12

Question 2.
What is the distance around the puzzle?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 13
Distance around: _________ in.
Answer:
The puzzle has four sides one side is 12in and 15in.
The opposite side of 12in is also 12in and the opposite side of 15in is also 15in.
The total distance around the puzzle is 15 + 15 + 12 + 12 = 54
The distance around the puzzle is 54in.
Independent Practice

Decide if you need to add or subtract. Then write an equation to help solve each problem.
Question 3.
What is the distance around the door?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 14
_________
Distance around: ________ ft
Answer:
The door has four sides one side is 3ft and 7ft.
The opposite side of 3ft is also 3ft and the opposite side of 7ft is also 7ft.
The total distance around the door is 3 + 3 + 7 + 7 = 20
The distance around the door is 20ft.

Question 4.
What is the distance around the cell phone?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 15
___________
Distance around: _________ in.
Answer:
The cell has four sides one side is 4in and 2in.
The opposite side of 2in is also 2in and the opposite side of 4in is also 4in.
The total distance around the cell is 2 + 2 + 4 + 4 = 12
The distance around the cell is 12in.

Question 5.
How much longer is the red scarf than the blue scarf?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 16
________ in. longer
Answer:
Given that,
The length of the red scarf is 60in.
The length of the blue scarf is 45in.
Red scarf – blue scarf = 60 – 45 = 15
The red scarf is 15in longer than a blue scarf.

Question 6.
Algebra What is the length of the shorter side of the rectangle?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 17
Complete the equation to solve.
20+ _______ + 20 + _______ = 60
The shorter side is ________ centimetres.
Answer:
The Given that,
The length of the longer side of the  rectangle is 20cm
The other side of the longer side is also 20cm
But the given equation is
20 + 20 = 60
40 = 60
60 – 40 = 20
20 can be divided into 2 shorter sides so, one shorter side is 10 and another shorter side is 10.
The shorter side is 20 centimetres.

Problem Solving

Decide if you need to add or subtract. Then write an equation to help solve each problem.
Question 7.
Model Ashley’s sunflower is 70 inches tall. Kwame’s sunflower is 60 inches tall. How much taller is Ashley’s sunflower than Kwame’s sunflower?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 18
_________ inches taller
Answer:
Given that,
The length of Ashley’s sunflower is 70 inches.
The length of Kwame’s sunflower is 60 inches.
70 – 60 = 10
Ashley’s sunflower is 10inches longer than Kwame’s sunflower.

Question 8.
Model Ben compares the length of a leaf and a plant. The leaf is 15 centimetres. The plant is 37 centimetres. How much shorter is the leaf than the plant?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 19
__________ centimeters shorter
Answer:
Given that,
The total length of the leaf is 15 centimeters.
The total length of the plant is 37 centimeters.
37 – 15 = 22
The length of the leaf is 22 centimeters shorter than the length of the plant.

Question 9.
Higher Order Thinking Tyler threw a ball 42 feet and then 44 feet. Sanjay threw a ball 38 feet and then 49 feet. Who threw the longer distance in all? Show you work.
Answer:
Given that,
Tyler threw a ball is 42 feet and then 44 feet.
Tyler threw a ball in total = 42 + 44 = 86
Sanjay threw a ball is 38 feet and then 49 feet.
Sanjay threw a ball in total = 38 + 49 = 87
Sanjay threw a ball longer distance than Tyler.

Question 10.
Assessment Practice What is the distance around the placemat?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 20
A. 28 in.
B. 39 in.
C. 56 in.
D. 66 in.
Answer:
The placemat has four sides one side is 121in and 17in.
The opposite side of 11in is also 11in and the opposite side of 17in is also 17in.
The total distance around the placemat is 11 + 11 + 17 + 17 = 56
The distance around the placemat is 56in.
C is the correct option.

Lesson 14.2 Find Unknown Measurements

Solve & Share
Julie and Steve each cut a piece of yarn. The total length of both pieces is 12 cm. Measure each piece of yarn. Circle Julie and Steve’s pieces. Then explain your thinking.
I can … add or subtract to solve problems about measurements.
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 21

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 22

Convince Me! How does drawing a yardstick help you solve the problem above?

Guided Practice

Write an equation using a ? for the unknown number. Solve with a picture or another way.
Question 1.
A square stamp measures 2 centimeters in length. How many centimeters long are two stamps?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 23

Anawer: 2+2 = 4

Question 2.
Stuart’s desk is 64 centimeters long. His dresser is 7 centimeters longer than his desk. How long is Stuart’s dresser?
________ cm
Answer:
Given that,
Stuart’s desk is 64 centimeters long. His dresser is 7 centimeters longer than his desk.
64 + 7 = 71 centimeters
Thus his dresser is 71 centimeter long.

Independent Practice

Write an equation using a ? for the unknown number. Solve with a picture or another way.
Question 3.
Filipe’s pencil box is 24 centimeters long. Joe’s pencil box is 3 centimeters shorter than Filipe’s. How long is Joe’s pencil box?
_________ cm
Answer:
Given that
Filipe’s pencil box is 24 centimeters long. Joe’s pencil box is 3 centimeters shorter than Filipe’s.
24 – 3 = 21 centimeters
Thus Joe’s pencil box is 21 centimeters.

Question 4.
Clark threw a red ball and a blue ball. He threw the red ball 17 feet. He threw the blue ball 7 feet farther. How far did Clark throw the blue ball?
__________ ft
Answer:
Given that,
Clark threw a red ball and a blue ball. He threw the red ball 17 feet.
He threw the blue ball 7 feet farther.
17 + 7 = 24 feet.Question 5.
en Vision® STEM Ashlie’s map shows where animals, land, and water are at a zoo. The distance around her map is 38 inches. What is the length of the missing side?
Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 24
____________ inches
Answer: The length of the missing side in the given map is 11 in.

Problem Solving

Solve each problem.
Question 6.
Make Sense A brown puppy is 43 centimeters tall. A spotted puppy is 7 centimeters shorter than the brown puppy. A white puppy is 14 centimeters taller than the brown puppy. How tall is the spotted puppy? Think about what you need to find.
_______ cm

Answer:
Given that,
the brown puppy is 43 centimeters tall.
A spotted puppy is 7 centimeters shorter than a brown puppy.
A white puppy is 14 centimeters taller than the brown puppy.
43 – 7 = 36 centimeters
Thus spotted puppy is 36 centimeters tall.

Question 7.
Vocabulary Complete the sentences using the terms below.
foot
yard
inch
A paper clip is about 1 _______ long.
My math book is about 1 ________ long.
A baseball bat is about 1 ________ long.
Answer:
A paper clip is about 1 inch long.
My math book is about 1 foot long.
A baseball bat is about 1 yard long

Question 8.
Higher Order Thinking Jack jumped 15 inches. Tyler jumped I inch less than Jack and 2 inches more than Randy. Who jumped the farthest? How far did each person jump?
Answer:
Given that,
Jack jumped = 15 inches
Tyler jumped 1 inch less than jack
Tyler jumped = 14 inches
Randy jumped = 14 + 2 = 16
Randy jumped farthest.

More Addition, Subtraction, and Length 1

Question 9.
Assessment Practice Kim was 48 inches tall in January. She grew 9 inches during the year. How tall is Kim at the end of the year? Write an equation with an unknown and then draw a picture to solve.
Answer:
Given that,
Kim was tall in January = 48 inches
Kim grew during the year = 9 inches
Total Kim tall at the end of the year = 48 + 9 = 57 inches

Lesson 14.3 Continue to Find Unknown Measurements

Solve & Share
Alex has a piece of ribbon that is 45 feet long. He cuts the ribbon. Now he has 39 feet of ribbon. How many feet of ribbon did Alex cut off? Draw a picture and write an equation to solve. Show your work.
I can … add and subtract to solve measurement problems by using drawings and equations.
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 25

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 26

Convince Me! How does writing an equation help you solve the problem above?

Guided Practice

Write an equation using a ? for the unknown number. Solve with a picture or another way.
Question 1.
A plant was 15 inches tall. It grew and is now 22 inches tall. How many inches did the plant grow?
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 27
Answer: 15 + 7 = 22

Question 2.
Each bus is 10 meters long. Each boat is 7 meters long. What is the total length of two buses and two boats?
Answer:
Given that,
Total number of buses = 2
Length of each bus = 10
Total length of two buses = 2 × 10 = 20
Total number of boats = 2
Length of each boats = 7
Total length of two boats = 7 × 2 = 14
Therefore, total length of two buses and two boats = 20 + 14 = 34

Independent Practice

Write an equation using a ? for the unknown number. Solve with a picture or another way.
Question 3.
Brent’s rope is 49 inches long. He cuts off some of the rope and now it is 37 inches long. How much rope did Brent cut off?
Answer:
Given that,
The total length of Brent’s rope = 49 inches
He cut off some of the rope and now it is = 37 inches
Brent cut off rope = 49 – 37 = 12inches
Question 4.
Sue ran for some meters and stopped. Then she ran another 22 meters for a total of 61 meters in all. How many meters did she run at first?
Answer:
Given that,
Sue ran total meters in all = 61 meters
Sue ran some meters from 61 meters = 22 meters
Sue rum at first time  = 61 – 22 = 39

Question 5.
Algebra Solve each equation. Use the chart.
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 28
Answer:
Problem Solving

Solve each problem.
Question 6.
Make Sense The yellow boat is 15 feet shorter than the green boat. The green boat is 53 feet long. How long is the yellow boat? Think about what you are trying to find. Write an equation to solve. Show your work.
________ ft
Answer:
Given that,
The total length of Green boat = 53 feets
Length of the yellow boat is 15 feet shorter than green boat = 53 – 15 = 38 feets
Length of the yellow boat is 38 feets

More Addition, Subtraction, and Length 3
Question 7.

Vocabulary Steve measured the length of his desk. It measured 2 units.
Circle the unit Steve used.
meter
foot
centimeter
inch
Lori measured the length of her cat. It measured 45 units.
Circle the unit Lori used.
centimeter
yard
inch
foot
Answer:
Steve used:
Meter
Lori used
Centimeter

Question 8.
Higher Order Thinking Lucy’s ribbon is I foot long. Kathleen’s ribbon is 15 inches long. Whose ribbon is longer and by how many inches? Explain your thinking.
Answer:
Given that,
Lucy’s ribbon = 1 foot long
1 foot = 12 inches
Kathleen’s ribbon = 15 inches
Kathleen’s ribbon is longer than Lucy’s ribbon.

Question 9.
Assessment Practice Mary’s water bottle is 25 cm long. Joey’s water bottle is 22 cm long. Ella’s water bottle is 17 cm long.
Which statements are correct? Choose all that apply.
☐ Mary’s bottle is 8 cm longer than Ella’s.
☐ Joey’s bottle is 6 cm longer than Ella’s.
☐ Joey’s bottle is 3 cm shorter than Mary’s.
☐ Ella’s bottle is 8 cm longer than Mary’s.
Answer: Mary’s bottle is 8 cm longer than Ella’s and Joey’s bottle is 3 cm shorter than Mary’s are correct.

Lesson 14.4 Add and Subtract on a Number Line

Solve & Share
Amelia walks 18 blocks on Monday and 5 blocks on Tuesday. How many blocks does she walk in all?
Use the number line to show how many blocks Amelia walks. Then write an equation to show your work.
I can … add and subtract on a number line.
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 29

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 30

Convince Me! Explain how to add 14 inches and 11 inches using a number line.

Guided Practice

Use the number lines to add or subtract.
Question 1.
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 31

Question 2.
28 – 14 = _______
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 32
Answer:
Subtraction of 28 and 14 is
28 – 14 = 14

Independent Practice

Use the number lines to add or subtract.
Question 3.
80 – 35 = ________
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 33
Answer:
Subtraction of 80 and 35 is
80 – 35 = 45

Question 4.
19+ 63 = ________
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 33
Answer:
Addition of 19 and 63
19 + 63 = 82

Question 5.
Higher Order Thinking Use the number line to show 15 inches plus O inches. Explain your thinking.
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 32
Answer:
15 inches + 0 inches = 15 inches

Question 6.
Number Sense Show each number below as a length from 0 on the number line. Draw four separate arrows.
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 34
Answer:

Problem Solving

Use the number line to solve each problem.
Question 7.
Use Tools A football team gains 15 yards 1 on its first play. The team gains 12 yards on its second play. How many yards does the team gain in two plays?
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 35
__________ yards
Answer:

Given that,
A football team gains on its first play = 15 yards.
A football team gains on its second play =12 yards.
Food ball team gains in two plays = 15 + 12 = 27 yards.

Question 8.
Use Tools Mia buys 25 feet of board. She uses 16 feet of board for a sandbox. How many feet of board does she have left?
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 36
_________ feet
Answer:
Given that,
Total length of board Mia buy = 25 feets
She uses a board for sand box = 16 feets
How many feets of board she left = 25 – 16 = 9

Question 9.
Higher Order Thinking The runners on the track team ran 12 miles on Monday. On Tuesday, they ran 6 more miles than they ran on Monday. How many miles did they run in all on both days?
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 35
_________ miles
Answer:
Given that,
The runners on the track team ran on Monday = 12 miles
The runners on the track team ran on Tuesday = 6 more miles than Monday = 6miles + 12miles = 18miles
They ran in all on both days = 12 miles+ 18 miles = 30 miles

Question 10.
Assessment Practice Deb has two pencils. One pencil is 9 cm long and the other pencil is 13 cm long. What is the total length of both pencils?
Use the number line to show your work.
Envision Math Common Core 2nd Grade Answers Topic 14 More Addition, Subtraction, and Length 35
___________ centimeters
Answer:
Given that,
Deb has two pencils
The total length of one pencil = 9 centimeters
The total length of other pencils = 13 centimeters
Total length of both the pencils = 9 centimetres + 13 centimetres = 22 centimetres

Lesson 14.5 Problem Solving

Use Appropriate Tools
Solve & Share

Choose a tool to solve each part of the problem. Be ready to explain which tools you used and why.
Which line is longer? How much longer? Draw a line that is that length.
I can … choose the best tool to use to solve problems.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 37

Thinking Habits Which of these tools can I use?
counters
paper and pencil cubes
place-value blocks
measuring tools
string
number line
technology
Am I using the tool correctly?
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 38

Visual Learning Bridge
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 39

Convince Me! Explain why counters are NOT the best tool to use to solve the problem above.

Guided Practice

Choose a tool to use to solve the problem. \ Show your work. Explain why you chose that tool and how you got your answer.
Question 1.
Sara cut 19 centimeters of ribbon into two pieces. One piece is 11 centimeters long. How long is the other piece?
Answer:
Given that,
Sara cut 19 centimeters of ribbon into two pieces.
The length of one piece = 11 centimetres
The length of other piece = 19 centimetres – 11 centimetres = 8 centimetres.
The length of other pieces = 8 centimeters.

Independent Practice

Solve each problem. Show your work.
Question 2.
Work with a partner. Measure each other’s arm from the shoulder to the tip of the index finger. Measure to the nearest inch. Whose arm is longer and by how much?
Choose a tool to use to solve the problem. Explain why you chose that tool and how you got your answer.
Answer:

Question 3.
Marcel jumped 39 centimeters high. Jamal jumped 48 centimeters high. How much higher did Jamal jump than Marcel?
Which tool would you NOT use to solve this problem? Explain.
Answer:
Given that,
Marcel jumped = 39 centimetres
Jamal jumped = 48 centimetres
Jamal jumped more than Marcel.

Place value box tool is not used for solving the problem.

Problem Solving

Performance Task
Sailboats Zak is measuring sailboats at the dock. Mr. Lee’s sailboat is 64 feet long. Ms. Flint’s sailboat is 25 feet shorter than Mr. Lee’s boat. Help Zak find the length of Ms. Flint’s boat.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 40

Question 4.
Use Tools Which tool would you NOT use to solve this problem? Explain.
Answer:

Question 5.
Be Precise Will you add or subtract to solve the problem?
______________
Write an equation. Use ? for the unknown.
______________
What unit of measure will you use?
______________
Answer:

Question 6.
Explain What is the length of Ms. Flint’s boat? Did you use a tool to solve the problem? Explain.
Answer:
Given that,
The length of Ms. Flint’s boat = 25 feet shorter than Mr. Lee’s boat.
Mr. Lee’s boat = 65 feets.
Length of the Ms. Flint’s boat = 65

Topic 14 Fluency Practice

Follow the path
Color a path from Start to Finish. Follow the sums and differences that are odd numbers. You can only move up, down, right, or left.
I can … add and subtract within 100.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 41

Topic 14 Vocabulary Review

Understand Vocabulary
Choose a term from the Word List to complete each sentence.
Word List
• centimeter (cm)
• foot (ft)
• height
• inch (in.)
• length
• mental math
• meter (m)
• yard (yd)

Question 1.
The length of your finger can best be measured in centimeters or ___________.
Answer:
The length of your finger can best be measured in centimetres or inches.

Question 2.
100 ________ equals 1 meter.
Answer:
100 centimetres equals to 1 meter.

Question 3.
__________ is how tall an object is from bottom to top.
Answer:
Height is how tall an object is from bottom to top.

Write T for true or F for false.
Question 4.
_______ 1 yard is 5 feet long.
Answer:
False

Question 5.
________ 12 inches is I foot long.
Answer:
True

Question 6.
________ A centimeter is longer than a meter.
Answer:
False

Question 7.
_________ You can do mental math in your head.
Answer:
False

Use Vocabulary in Writing
Question 8.
Tell how to find the total length of two pieces of string. One piece of string is 12 inches long. The other piece is 9 inches long. Use terms from the Word List.
Answer:
Given that,
The total length of one piece of string = 12 inches
The total length of other pieces of string = 9 inches
The total length of two pieces = 12 inches + 9 inches = 21 inches

Topic 14 Reteaching

Set A

What is the distance around the front of the bookcase?
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 42
Add the lengths. Write an equation.
4+ 3+ 4+ 3 = 14
Distance around: 14 feet

Write an equation to help solve.
Question 1.
What is the distance around the front of the crayon box?
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 43
Distance around: _________ cm
Answer:
Given that,
The crayon box has four sides
The length of the two sides is 12cm and 9cm.
The opposite side of 12 cm is also 12 cm.
The opposite side of 9cm is also 9 cm
Total distance around crayon box = 12 + 12 + 9 + 9 = 42 centimetres.

Set B

A kite string is 27 feet long. Some of the string is cut off. Now the kite string is 18 feet long. How many feet of kite string were cut off?
Write an equation and draw a picture.
27 – ? = 18 or 18+? = 27
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 44

Write an equation using a ? for the unknown number. Then draw a picture to solve.
Question 2.
A piece of yarn is 42 inches long. Mia cuts some of it off. It is now 26 inches long. How much yarn did Mia cut off?
Answer:
Given that,
A piece of yarn = 42 inches long
Mia cuts some of it and now it is = 26 inches
Mia cut off yarn = 42 – 26 = 16 inches

Set C

A book measures 10 inches long. Another book measures 13 inches long. What is the total length of both books?
You can show 10 + 13 on a number line.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 45

Solve the problem using the number line.
Question 3.
One room in Jackie’s house is 15 feet long. Another room is 9 feet long. What is the total length of both rooms?
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 46
Answer:
Given that,
The length of one room in Jackie’s house = 15 feets
The length of other room in Jackie’s house = 9 feets
Total length of two rooms in Jackie’s house = 15 + 9 = 24 feets

Set D

Thinking Habits
Use Tools
Which of these tools can I use?
counters
paper and pencil cubes
place-value blocks
measuring tools
string
number line
technology
Am I using the tool correctly?
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 47

Choose a tool to solve the problem.
Question 4.
Damon’s shoelace is 45 inches long. His shoelace breaks. One piece is 28 inches long. How long is the other piece?
Explain your solution and why you chose the tool you used.
Answer:
Given that,
The total length of Damon’s shoelace = 45 inches long.
His shoelace breaks into two pieces and one-piece length = 28 inches
The length of other piece = 45 inches – 28 inches = 17 inches

Topic 14 Assessment Practice

Question 1.
A notebook has a length of 7 in. and a width of 5 in. What is the total distance around the notebook? Use the image below for help.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 48
Distance around: _______ in.
Answer:
Given that,
The note book has a length of 7 inches and 5 inches
Total distance around the note book = 7 + + 7 + 5 + 5 = 24
Total distance around the note book = 24 inches.

Question 2.
Kate is 48 inches tall. Tom is 2 inches taller than Kate. James is 3 inches shorter than Tom.
How tall is James?
A. 45 inches
B. 47 inches
C. 50 inches
D. 53 inches
Answer:
Given that,
Kate is 48 inches tall.
Tom is 2 inches tall than Kate = 48 + 2 = 50 inches
James is 3 inches shorter than Tom = 50 – 3 = 47 inches
James has 47 inches tall.
Option B is correct.

Question 3.
Alexis has a rope that is 7 feet long. Mariah’s rope is 9 feet long. Sam’s rope is 3 feet longer than Mariah’s rope.
Use the measurements on the cards to complete each sentence.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 49
Sam’s rope is ________ long.
Alexis’s rope is ________ shorter than Mariah’s rope.
Sam’s rope is _________ longer than Alexis’s rope.
Answer:
Sam’s rope is 12 feet long.
Alexis’s rope is 2 feets shorter than Mariah’s rope.
Sam’s rope is 5 feet longer than Alexis’s rope.

Question 4.

Joe rides his bike 18 miles. Then he rides 7 more miles.
Use the number line to find how far Joe rides. Then explain your work.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 50
Answer:
Given that,
Joe rides his bike = 18 miles.
He rides 7 more miles = 18 + 7 = 25 miles
Joe rides in total = 25 inches.

Question 5.
Pat says that each unknown equals 25 cm. Do you agree? Choose Yes or No.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 51
Answer:

Question 6.
Grace got a plant that was 34 cm tall. The plant grew and now it is 42 cm tall. How many centimeters did the plant grow?
A. 8 cm
B. 12 cm
C. 42 cm
D. 76 cm
Answer:
Given that,
Grace got a plant that was 34 centimeters long.
The plant grows up to 42 centimeters tall.
How much the plant grow = 42 – 34 = 8 centimetres.
Option A is correct

Question 7.
Claire rides her bike 26 miles on Saturday and Sunday. She rides 8 miles on Sunday. How many miles does she ride on Saturday?
Write an equation to show the unknown. Then use the number line to solve the problem.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 52
Answer:
Given that,
Claire rides her bike on Saturday and Sunday = 26 miles
She rides on Sunday = 8 miles
She rides on Saturday = 26 – 8 = 18 miles

Question 8.
Chris had a string that is 18 cm long. He cut off 7 cm. How much string is left?
A. Which of these tools could you use to solve the problem? Choose all that apply.
☐ centimeter ruler
☐ paper and pencil
☐ measuring cup
☐ number line
☐ inch ruler
Answer:

B. Write an equation to show the unknown.
Then draw a number line to solve.
________ Envision Math Common Core 2nd Grade Answer Key Topic 14 More Addition, Subtraction, and Length 4 _______ = _________
________ cm
Answer:

Topic 14 Performance Task

Fishing Fun Jim and his family go on a fishing trip. They use a boat and fishing gear to help them catch fish.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 53

Question 1.
Jim takes this fishing box with him. What is the distance around the front of the fishing box? Write an equation to help solve the problem.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 54
Distance around: _________ centimeters
Answer:
Jim takes this fishing box with him.
The length of the fishing box = 31
The breath of the fishing box = 16
Distance around the front of the fishing box = 31 + 16 = 47 centimetres

Question 2.
Jim’s fishing pole is 38 inches long. Performance His dad’s fishing pole is 96 inches Task long. How much shorter is Jim’s pole than his dad’s pole? Part A
Write a subtraction equation that shows the problem.

Part B
Solve the problem.
__________ inches shorter
Answer:
Jim’s fishing pole = 38 inches
His dad’s fishing pole = 96 inches
96 – 38 = 58
Jim’s fishing pole is 58 inches shorter than his dad’s fishing pole.

Question 3.
Jim catches a fish 49 yards away from the shore. Later, he helps row the boat closer to the shore. Now he is 27 yards away from the shore. How many yards closer to shore is Jim now than when he caught the fish?
Part A
Write an addition equation that shows the problem.
Answer:

Part B
Solve the problem.
______ yards
Answer:

Question 4.
Jim catches a silver fish that is 12 inches long. His sister catches a green fish that is 27 inches long. What is the total length of both fish?
Use the number line to solve.
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 55
__________ inches
Answer:
Given that,
Jim catches a silver fish that is 12 inches long.
His sister catches a green fish that is 27 inches long.
The total length of two fishes = 12 + 27 = 39 inches.

Question 5.
Jim has 27 yards of fishing line. He gives 12 yards of line to a friend. How many yards of line does Jim have left?
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 56
Answer:
Given that,
Jim has 27 yards of fishing line.
He gives 12 yards of line to a friend.
Jim left the fishing line = 27 – 12 = 15 yards

Question 6.
Jim’s family meets a man with a big boat. A parking spot at the dock is 32 feet long. Will the man’s car and boat fit in the parking spot?
Envision Math Common Core Grade 2 Answer Key Topic 14 More Addition, Subtraction, and Length 57

Part A
What do you need to find?
Answer:
A parking spot at the dock is 32 feets
Length of the big boat = 27 feets.
Length of the car = 7 feets.
There is a space between car and boat = 2 feets.
Total length of car and boat = 34 feets
Yes the car and boat fit in the parking spot.

Part B
What is the total length? Write an equation to solve.
Will the car and boat fit in the parking spot? Explain.
_____________
What tool did you use? _______________
Answer:

Envision Math Grade 4 Answer Key Topic 2.9 Subtracting Across Zeros

Envision Math 4th Grade Textbook Answer Key Topic 2.9 Subtracting Across Zeros

Draw a Picture and Write an Equation

The mass of a human brain is how much greater than the mass of a chimpanzee brain?
Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 1

Guided Practice*

Do you know HOW?

Solve. Draw a picture to help you.

Question 1.
In one week, Sandy earned $36 from her babysitting job. She got $15 more for doing her chores. How much money did Sandy earn?
Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 1.1
Answer:

Question 2.
How can you show that 930 grams is a reasonable answer for the question asked above?
Answer:

Question 3.
Write a Problem Write a problem using the table at the top. Solve. Draw a picture to help you.
Answer:

Independent Practice

Solve. Draw a picture to help you.

Question 4.
Four cities are on the same road that runs east and west. Fleming is west of Bridgewater but east of Clinton. Union is between Fleming and
Bridgewater. It is 21 miles from Fleming to Union. It is 55 miles from Clinton to Union. How far is it from Clinton to Fleming?
Answer:

Question 5.
Scott and his friends walk to school together. Scott leaves his home at 7:00 A.M. He meets Johnny and Zach at the end of the block. Next, they meet Paul, Tim, and Pete. Dan and Torey join them one block before the school. How many friends walk to school altogether?
Answer:

Read and Understand

What do I know?
The average mass of a chimpanzee brain is 420 grams. The average mass of a human brain is 1,350 grams.

What am I asked to find?

The difference between the masses

Plan and Solve

Draw a picture.
Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 15
Write an equation. Use subtraction to solve.
1,350 – 420 = Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 16
The human brain has a mass that is 930 grams more than the chimpanzee brain.

Question 6.
The American Kennel Club recognizes 17 breeds of herding dogs and 26 breeds of terriers. Draw a picture that could help find the total number of herding dogs and terriers.
Answer:

Question 7.
Using the information in Exercise 6, write an equation to find how many more breeds of terriers than herding dogs there are.

For 8 through 10, use the table to the right.

Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 16.1

Question 8.
There are about 200 more animals in the Minnesota Zoo than in the Phoenix Zoo. About how many species of animals are in the Minnesota Zoo?
Answer:

Question 9.
About how many more species are in the Indianapolis Zoo than the Phoenix Zoo?
Answer:

Question 10.
How can you find the number of species of animals at the San Francisco Zoo?
Answer:

Question 11.
A parking lot had a total of 243 cars in one day. By 6:00 A.M., there were 67 cars in the lot. In the next hour, 13 more cars joined these. How many more cars would come to the lot by the end of the day?
Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 19
Answer:

Question 12.
A shoe store sold 162 pairs of shoes. The goal was to sell 345 pairs. How many pairs of shoes did they NOT sell?
Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 20
Answer:

Independent Practice

For 13 and 14, use the table at the right.

Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 21

Question 13.
What equation can you write to help find the cost of the shoes and socks together?
Answer:

Question 14.
What equation can you write to help find the difference between the cost of the shirt and the shorts?
Answer:

Question 15.
Byron spent $7.75 on popcorn and a drink at the movie theater. The popcorn was $4.25. How much was the cost of the drink?
Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 25
Answer:

Question 16.
Each school day, Mikaela sold the same number of tickets to the school play. On Monday she sold 4 tickets. How many tickets did she sell all together in 5 days?
Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 26
Answer:

Question 17.
Writing to Explain Ken makes 2 nametags in the time it takes Mary to make 5 nametags. When Mary has made 15 nametags, how many has Ken made?
Answer:

Question 18.
Mr. Lee had 62 pencils at the beginning of the school year. At the end of the school year he had 8 pencils left. How many pencils were given out during the year?
Envision Math 4th Grade Answer Key Topic 2.9 Subtracting Across Zeros 27
Answer:

Think About the Process

Question 19.
Carlene bought a book for $13.58. She paid with a $10 bill and a $5 bill. Which expression would find the amount of change Carlene would receive?
A. $15 – $13.58
B. $15 – $1.42
C. $10 + $5
D. $13.58 + $1.42
Answer:

Subtraction Across Zero 1

Question 20.
Terrence rode 15 rides before lunch at the county fair. He rode 13 rides after lunch. Each ride requires 3 tickets. Which expression
represents the number of rides he rode during the day?
A. 15 – 13
B. 15 + 13
C. 15 – 3
D. 13 – 3
Answer:

Stop and Practice

Find each sum. Estimate to check if the answer is reasonable.

Question 1.
Envision Math Grade 4 Answer Key Topic 2.9 Subtracting Across Zeros 40
Answer:

Question 2.
Envision Math Grade 4 Answer Key Topic 2.9 Subtracting Across Zeros 41
Answer:

Question 3.
Envision Math Grade 4 Answer Key Topic 2.9 Subtracting Across Zeros 42
Answer:

Question 4.
Envision Math Grade 4 Answer Key Topic 2.9 Subtracting Across Zeros 43
Answer:

Question 5.
5,474 + 723
Answer:

Question 6.
47,090 + 2,910
Answer:

Question 7.
6,685 + 37
Answer:

Find each difference. Estimate to check if the answer is reasonable.

Question 8.
Envision Math Grade 4 Answer Key Topic 2.9 Subtracting Across Zeros 45
Answer:

Question 9.
Envision Math Grade 4 Answer Key Topic 2.9 Subtracting Across Zeros 46
Answer:

Question 10.
Envision Math Grade 4 Answer Key Topic 2.9 Subtracting Across Zeros 47
Answer:

Question 11.
Envision Math 4th Grade Textbook Answers Topic 2.9 Subtracting Across Zeros 48
Answer:

Question 12.
Envision Math 4th Grade Textbook Answers Topic 2.9 Subtracting Across Zeros 540
Answer:

Question 13.
5,302 – 88
Answer:

Question 14.
2,249 – 51
Answer:

Question 15.
8,001 – 4,832
Answer:

Error Search Find each sum or difference that is not correct. Write it correctly and explain the error.

Question 16.
Envision Math 4th Grade Textbook Answers Topic 2.9 Subtracting Across Zeros 50
Answer:

Question 17.
Envision Math 4th Grade Textbook Answers Topic 2.9 Subtracting Across Zeros 51
Answer:

Question 18.
Envision Math 4th Grade Textbook Answers Topic 2.9 Subtracting Across Zeros 52
Answer:

Question 19.
Envision Math 4th Grade Textbook Answers Topic 2.9 Subtracting Across Zeros 53
Answer:

Question 20.
Envision Math 4th Grade Textbook Answers Topic 2.9 Subtracting Across Zeros 54
Answer:

Number Sense

Estimating and Reasoning Write whether each statement is true or false. Explain your answer.

Question 21.
The number 213,753 is ten thousand more than 223,753.
Answer:

Question 22.
The sum of 6,823 and 1,339 is greater than 7,000 but less than 9,000.
Answer:

Question 23.
The sum of 42,239 and 11,013 is less than 50,000.
Answer:

Question 24.
The difference of 7,748 – 989 is greater than 7,000.
Answer:

Question 25.
The sum of 596 + 325 is 4 less than 925.
Answer:

Question 26.
The difference of 12,023 and 2,856 is closer to 9,000 than 10,000.
Answer:

Envision Math Grade 4 Answer Key Topic 2.5 Problem Solving

Envision Math 4th Grade Textbook Answer Key Topic 2.5 Problem Solving

Missing or Extra Information

Kendra had $7. She bought a sandwich, a drink, and an apple at the cafeteria. She spent a total of $3 on the sandwich and the drink.
How much money did Kendra have left?
Envision Math Grade 4 Answer Key Topic 2.5 Problem Solving 0.1

Do You Know How?

Question 1.
At the zoo, Julie saw 18 penguins. She saw 8 Adelie penguins. The rest of the penguins she saw were Rockhopper penguins. She learned
that Rockhopper penguins grow to be about 5 to 8 pounds. How many Rockhopper penguins did Julie see?
Answer:

Question 2.
What information was not needed in Problem 1?
Answer:

Question 3.
Write a Problem Write a problem that contains too much or too little information.
Answer:

Independent Practice

Question 4.
Carmin spent 30 minutes completing his homework after school. Then he played soccer. What information do you need to find how many minutes Carmin spent completing his homework and playing soccer all together?
Answer:

Grade 4 Answer Key Topic 2.5 Problem Solving 1

Question 5.
June only has quarters and pennies in her coin collection. She has 85 coins in all. What would you need to know to find out how many quarters June has in her collection?
Answer:

Read & Understand

What do I know?
Kendra had $7. She bought a sandwich, a drink, and an apple. The sandwich and the drink was $3.

What am I asked to find?
The amount of money Kendra had left.

Plan

Draw a diagram to show what you know and want to find.
Envision Math 4th Grade Answer Key Topic 2.5 Problem Solving 20
Think Is there missing information needed to solve the problem?
Is there any extra information not needed to solve the problem?

Question 6.
Kayla ate two tacos and an apple for lunch. The tacos had 260 calories. How many calories did Kayla eat for lunch?
Answer:

Question 7.
There are 35 sopranos in the school choir. The 40 remaining choir members are altos. How many students are in the school choir?
Answer:

Question 8.
There are 328 places for activity photographs in the yearbook. The yearbook club has decided to make most of the photographs black and
white. How many color photographs will be in the yearbook?
Answer:

Question 9.
A notebook costs $2.68, and a pen costs $1.79. Does Jasmine have enough money to buy a notebook and two pens?
Answer:

Grade 4 Answer Key Topic 2.5 Problem Solving 2

Question 10.
The tallest steel roller coaster is in Jackson, New Jersey. It is 456 feet tall. The tallest wooden roller coaster is in Cincinnati, Ohio. The roller coaster is 7,032 feet long. How much taller is the steel roller coaster than the wooden roller coaster? Choose the letter that contains the information that is needed to solve the problem.
A. The tallest steel roller coaster travels at 128 miles per hour.
B. The tallest steel roller coaster is 3,118 feet long.
C. The tallest wooden roller coaster travels at 78.3 miles per hour.
D. The tallest wooden roller coaster is 218 feet tall.
Answer:

Question 11.
Mrs. Song bought school supplies for her two children, Jason and Kevin. Jason is two years older than Kevin and is in the fourth grade. She spent $38 for Kevin’s supplies and $46 for Jason’s supplies. If she paid with a $100 bill, how much change did she get back?
Envision Math Grade 4 Answer Key Topic 2.5 Problem Solving 50
Answer:

enVision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison

enVision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison

Go through the enVision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison regularly and improve your accuracy in solving questions.

enVision Math Common Core 3rd Grade Answers Key Topic 13 Fraction Equivalence and Comparison

Essential Question:
What are different ways to compare fractions?
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 1

enVision STEM Project: Life Cycles
Do Research A frog egg hatches into a tadpole that lives in water. The tadpole will change and eventually become an adult frog. Use the Internet or another source to gather information about the life cycle of a frog and other animals.

Journal: Write a Report Include what you found. Also in your report:

  • Tell about what is in a frog’s habitat to support changes the frog goes through in its life cycle.
  • Compare the life cycles of the different animals you studied.
  • For the animals you studied, make up and solve problems using fractions. Draw fraction strips to represent the fractions.

Review What You Know

Choose the best term from the box. Write it on the blank.

  • <
  • >
  • numerator
  • unit fraction

Vocabulary

Question 1.
The symbol ___________ means is greater than.

Answer:
The symbol > means greater than.

Explanation:
In the above-given question,
given that,
greater than symbol is used to compare numbers.
for example:
3 > 1.
so the symbol > is used for large numbers when compared with small numbers.

Fraction Equivalence and Comparison 2

Question 2.
The symbol _________ means is less than.

Answer:
The symbol < means less than.

Explanation:
In the above-given question,
given that,
less than a symbol is used to compare numbers.
for example:
1 < 3.
so the symbol < is used for small numbers when compared with large numbers.

Question 3.
A ________ represents one equal part of a whole.

Answer:
The fraction represents one equal part of a whole.

Explanation:
In the above-given question,
given that,
a fraction represents one equal part of a whole.
for example:
3/4.
the whole part is 4.
the 3/4 of the portion is filled.
so the fraction represents one equal part of a whole.

Comparing Whole Numbers

Compare. Write <, >, or =.
Question 4.
48 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 30

Answer:
48 > 30.

Explanation:
In the above-given question,
given that,
the two numbers are 48 and 30.
30 is less than 48.
48 is greater than 30.
48 > 30.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-1

Question 5.
6 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 6

Answer:
6 = 6.

Explanation:
In the above-given question,
given that,
the two numbers are 6 and 6.
6 is equal to 6.
6 = 6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-2

Question 6.
723 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 732

Answer:
723 < 732.

Explanation:
In the above-given question,
given that,
the two numbers are 723 and 732.
723 is less than 732.
732 is greater than 723.
723 < 732.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-3

Question 7.
152 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 183

Answer:
152 < 183.

Explanation:
In the above-given question,
given that,
the two numbers are 152 and 183.
152 is less than 183.
183 is greater than 152.
152 < 183.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-4

Question 8.
100 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 10

Answer:
100 > 10.

Fraction Equivalence and Comparison 1

Explanation:
In the above-given question,
given that,
the two numbers are 100 and 10.
100 is greater than 10.
10 is less than 100.
100 > 10.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-5

Question 9.
189 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 99

Answer:
189 > 99.

Explanation:
In the above-given question,
given that,
the two numbers are 189 and 99.
189 is greater than 99.
99 is less than 189.
189 > 99.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-6

Question 10.
456 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 456

Answer:
456 = 456.

Explanation:
In the above-given question,
given that,
the two numbers are 456 and 456.
456 is equal to 456.
456 = 456.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-7

Question 11.
123 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 223

Answer:
123 < 223.

Explanation:
In the above-given question,
given that,
the two numbers are 123 and 223.
123 is less than 223.
223 is greater than 123.
123 < 223.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-8

Question 12.
421 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 399

Answer:
421 > 399.

Explanation:
In the above-given question,
given that,
the two numbers are 421 and 399.
421 is greater than 399.
399 is less than 421.
421 > 399.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-9

Question 13.
158 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 185

Answer:
158 < 185.

Explanation:
In the above-given question,
given that,
the two numbers are 158 and 185.
158 is less than 185.
185 is greater than 158.
158 < 185.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-10

Question 14.
117 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 117

Answer:
117 = 117.

Explanation:
In the above-given question,
given that,
the two numbers are 117 and 117.
117 is equal to 117.
117 = 117.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-11

Question 15.
900 Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 893

Answer:
900 > 893.

Explanation:
In the above-given question,
given that,
the two numbers are 900 and 893.
900 is greater than 893.
893 is less than 900.
900 > 893.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-12

Identifying Fractions

For each shape, write the fraction that is shaded.
Question 16.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 3

Answer:
The fraction is 4/8.

Explanation:
In the above-given question,
given that,
the figure contains 8 boxes.
4 boxes are filled.
4/8 portion of the boxes are filled.
4/8 = 1/2.
so half portion of the boxes is filled.

Question 17.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 4

Answer:
The fraction is 1/6.

Explanation:
In the above-given question,
given that,
there are 6 boxes in the figure.
1 box is filled.
so 1/6 portion is filled.

Question 18.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 5

Answer:
The fraction is 2/4.

Explanation:
In the above-given question,
given that,
the figure contains 4 boxes.
2 boxes are filled.
2/4 portion of the boxes are filled.
2/4 = 1/2.
so half portion of the boxes is filled.

Division

Divide.
Question 19.
30 ÷ 5

Answer:
The answer is 6.

Explanation:
In the above-given question,
given that,
the two numbers are 30 and 5.
5 x 6 = 30.
30 / 5 = 6.

Question 20.
72 ÷ 8

Answer:
72 / 8 = 9.

Explanation:
In the above-given question,
given that,
the two numbers are 72 and 8.
8 x 9 = 72.
72 / 8 = 9.

Question 21.
28 ÷ 4

Answer:
28 / 4 = 7.

Explanation:
In the above-given question,
given that,
the two numbers are 28 and 4.
4 x 7 = 28.
28 / 4 = 7.

Question 22.
48 ÷ 6

Answer:
48 / 6 = 8.

Explanation:
In the above-given question,
given that,
the two numbers are 48 and 6.
6 x 8 = 48.
48 / 6 = 8.

Question 23.
81 ÷ 9

Answer:
81 / 9 = 9.

Explanation:
In the above-given question,
given that,
the two numbers are 81 and 9.
9 x 9 = 81.
81 / 9 = 9.

Question 24.
45 ÷ 5

Answer:
45 / 5 = 9.

Explanation:
In the above-given question,
given that,
the two numbers are 45 and 5.
5 x 9 = 45.
45 / 5 = 9.

Question 25.
32 ÷ 8

Answer:
32 / 8 = 4.

Explanation:
In the above-given question,
given that,
the two numbers are 32 and 8.
8 x 4 = 32.
32 / 8 = 4.

Question 26.
42 ÷ 6

Answer:
42 / 6 = 7.

Explanation:
In the above-given question,
given that,
the two numbers are 42 and 6.
6 x 7 = 42.
42 / 6 = 7.

Question 27.
49 ÷ 7

Answer:
49 / 7 = 7.

Explanation:
In the above-given question,
given that,
the two numbers are 49 and 7.
7 x 7 = 49.
49 / 7 = 7.

Question 28.
How can you check if the answer to 40 ÷ 5 is 8?

Answer:
40 / 5 = 8.

Explanation:
In the above-given question,
given that,
the two numbers are 40 and 5.
40 / 5 = 8.
8 x 5 = 40.

Pick a Project

PROJECT 13A
Do you want to ride a horse?
Project: Design a Racetrack for Horses
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 6

PROJECT 13B
How deep do you have to dig before you reach water?
Project: Create a Picture of a Well
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 7

PROJECT 13C
How many coffee beans does it take to fill up a container?
Project: Plot Fractions on a Number Line
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 8

3-ACT MATH PREVIEW

Math Modeling
What’s the Beef?
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 9

Lesson 13.1 Equivalent Fractions: Use Models

Solve & Share
Gregor threw a softball of the length of the yard in front of his house. Find as many fractions as you can that name the same part of the length of the yard that Gregor threw the ball. Explain how you decided
I can … find equivalent fractions that name the same part of a whole.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 10

Answer:
1/9, 2/9, 3/9, 4/9.

Explanation:
In the above-given question,
given that,
Gregor threw a softball off the length of the yard in front of his house.
Gregor threw the 1st ball at 1 yard.
1/9.
the length of the yard is 9.
Gregor threw the 2nd ball at 2 yards.
2/9.
Gregor threw the 3rd ball at 3 yards.
3/9.
Gregor threw the 4th ball at 4 yards.
4/9.
so the fractions are 1/9, 2/9, 3/9, and 4/9.

Look Back! How can fraction strips help you tell if a fraction with a denominator of 2, 3, or 6 would name the same part of a whole as \(\frac{3}{4}\)?

Answer:
2/4 and 6/4.

Explanation:
In the above-given question,
given that,
the denominators are 2, 3, and 6.
3/4 and 2/4 = 1/2.
6/4 = 3/2.

Essentials Question
How Can Different Fractions Name the Same Part of a Whole?

Visual Learning Bridge
The Chisholm Trail was used to drive cattle to market. Ross’s herd has walked \(\frac{1}{2}\) the distance to market. What is another way to name \(\frac{1}{2}\)?
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 11

\(\frac{1}{2}\) = \(\frac{}{}\) You can use fraction strips.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 12
The fractions \(\frac{1}{2}\) and \(\frac{2}{4}\) represent the same part of the whole.
Two \(\frac{1}{4}\) strips are equal to \(\frac{1}{2}\), so \(\frac{1}{2}\) = \(\frac{2}{4}\).
Another name for \(\frac{1}{2}\) is \(\frac{2}{4}\).

You can find other equivalent fractions. Think about fractions that name the same part of the whole.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 13
Four \(\frac{1}{8}\) strips are equal to \(\frac{1}{2}\), so \(\frac{1}{2}\) = \(\frac{4}{8}\).
Another name for \(\frac{1}{2}\) is \(\frac{4}{8}\)

Convince Me! Look for Relationships In the examples above, what pattern do you see in the fractions that are equivalent to \(\frac{1}{2}\)? What is another name for \(\frac{1}{2}\) that is not shown above?

Answer:
The other name is 4/8.

Explanation:
In the above-given question,
given that,
Four \(\frac{1}{8}\) strips are equal to \(\frac{1}{2}\).
\(\frac{1}{2}\) = \(\frac{4}{8}\).
\(\frac{1}{2}\) is \(\frac{4}{8}\).
so the other name is 4/8.

Another Example!
You can find an equivalent fraction for \(\frac{4}{6}\) using an area model.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 14
Both area models have the same-sized whole. One is divided into sixths. The other shows thirds. The shaded parts show the same part of a whole. Because \(\frac{4}{6}\) = \(\frac{2}{3}\), another name for \(\frac{4}{6}\) is \(\frac{2}{3}\).

Guided Practice

Do You Understand?
Question 1.
Divide the second area model into sixths. Shade it to show a fraction equivalent to \(\frac{1}{3}\):
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 15

Answer:
1/3 = 2/6.

Explanation:
In the above-given question,
given that,
divide the second area model into sixths.
\(\frac{1}{3}\) = \(\frac{2}{6}\).
\(\frac{1}{3}\) is \(\frac{2}{6}\).
2/6 = 1/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-13

Do You Know How?
Question 2.
Use the fraction strips to help find an equivalent fraction.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 16

Answer:
1/4 = 4/16.

Explanation:
In the above-given question,
given that,
\(\frac{1}{4}\) = \(\frac{4}{16}\).
\(\frac{4}{16}\) is \(\frac{1}{4}\).
1/4 = 4/16.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-14

Independent Practice

Question 3.
Use the fraction strips to help find an equivalent fraction.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 17
Answer:
1/2 = 4/8.

Explanation:
In the above-given question,
given that,
1/4 + 1/4 = 1/2.
1/2 + 1/2 = 1.
4/8 = 1/2.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-15

Question 4.
Divide the second area model into eighths. Shade it to show a fraction equivalent to \(\frac{1}{2}\).
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 18

Answer:
1/2 = 4/8.

Explanation:
In the above-given question,
given that,
divide the second area model into eights.
\(\frac{1}{2}\) = \(\frac{4}{8}\).
\(\frac{1}{2}\) is \(\frac{4}{8}\).
1/2 = 4/8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-16

In 5-8, find each equivalent fraction. Use fraction strips or draw area models to help.
Question 5.
\(\frac{3}{4}\) = \(\frac{}{8}\)

Answer:
\(\frac{3}{4}\) = \(\frac{6}{8}\).

Explanation:
In the above-given question,
given that,
divide the 1st area model into fourths.
divide the second area model into eights.
3/4 = 6/8.
6/8 = 3/4.

Question 6.
\(\frac{6}{6}\) = \(\frac{}{8}\)

Answer:
\(\frac{6}{6}\) = \(\frac{1}{8}\).

Explanation:
In the above-given question,
given that,
divide the 1st area model into sixths.
divide the second area model into eights.
6/6 = 1.
1/8 = 6/6.

Question 7.
\(\frac{2}{6}\) = \(\frac{}{3}\)

Answer:
\(\frac{2}{6}\) = \(\frac{1}{3}\).

Explanation:
In the above-given question,
given that,
divide the 1st area model into sixths.
divide the second area model into thirds.
2/6 = 1/3.
1/3 = 2/6.

Question 8.
\(\frac{4}{8}\) = \(\frac{}{2}\)

Answer:
\(\frac{4}{8}\) = \(\frac{1}{2}\).

Explanation:
In the above-given question,
given that,
divide the 1st area model into eigths.
divide the second area model into halfs.
4/8 = 1/2.
1/2 = 4/8.

Problem Solving

In 9 and 10, use the fraction strips at the right.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 19
Question 9.
Marcy used fraction strips to show equivalent fractions. Complete the equation.
\(\frac{}{4}\) = ________

Answer:
\(\frac{1}{4}\) = \(\frac{2}{8}\).

Explanation:
In the above-given question,
given that,
divide the 1st area model into fourths.
divide the second area model into eights.
1/4 = 2/8.
2/8 = 1/4.

Question 10.
Rita says the fraction strips show fractions that are equivalent to \(\frac{1}{2}\). Explain what you could do to the diagram to see if she is correct.

Answer:
\(\frac{2}{4}\) = \(\frac{1}{2}\).

Explanation:
In the above-given question,
given that,
divide the 1st area model into fourths.
divide the second area model into halves.
2/4 = 1/2.
1/2 = 2/4.

Question 11.
Reasoning A band learns 4 to 6 new songs every month. What is a good estimate for the number of songs the band will learn in 8 months? Explain.

Answer:
The number of songs the band will learn in 8 months = 80 songs.

Explanation:
In the above-given question,
given that,
A band learns 4 to 6 new songs every month.
4 + 6 = 10.
10 x 8 = 80.
so the number of songs the band will learn in 8 months = 80 songs.

Question 12.
Three-eighths of a playground is covered by grass. What fraction of the playground is NOT covered by grass?

Answer:
The fraction of the playground is not covered by grass = 5/8.

Explanation:
In the above-given question,
given that,
three-eights of a playground is covered by grass.
8 – 3 = 5.
so the fraction of the playground is not covered by grass = 5/8.

Question 13.
Higher Order Thinking Aiden folded 2 strips of paper into eighths. He shaded a fraction equal to \(\frac{1}{4}\) on the first strip and a fraction equal to \(\frac{3}{4}\) on the second strip. Use eighths to show the fractions Aiden shaded on the pictures to the right. Which fraction of each strip did he shade?

Answer:
The fraction he shaded = 6/8.

Explanation:
In the above-given question,
given that,
Aiden folded 2 strips of paper into eighths.
2/8.
He shaded a fraction equal to \(\frac{1}{4}\) on the first strip.
1/4.
fraction equal to \(\frac{3}{4}\) on the second strip.
3/4.
he shaded the 6/8 portion of each strip.
6/8 = 3/4.

Assessment Practice

Question 14.
Which fractions are equivalent? Select all that apply.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 20

Answer:
1/4 and 2/8.
3/4 and 6/8.
2/4 and 4/8.

Explanation:
In the above-given question,
given that,
there are three equivalent fractions.
the fractions are:
2/8 = 1/4.
6/8 = 3/4.
4/8 = 2/4.

Lesson 13.2 Equivalent Fractions: Use the Number Line

Solve & Share
The top number line shows a point at \(\frac{1}{4}\). Write the fraction for each of the points labeled A, B, C, D, E, and F. Which of these fractions show the same distance from 0 as \(\frac{1}{4}\)?
I can … use number lines to represent equivalent fractions.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 21

Look Back! How can number lines show that two fractions are equivalent?

Answer:
The fractions are 1/2, 2/4, 3/4, 2/8, 4/8, and 4/6.

Explanation:
In the above-given question,
given that,
The number line A shows the fraction 1/2.
B shows the fraction 2/4.
C shows the fraction 3/4.
D shows the fraction 2/8.
E shows the fraction 4/8.
F shows the fraction 4/6.
2/4 = 1/2.
2/8 = 1/4.
4/8 = 1/2.
4/6 = 2/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-17

Essential Question
How Can You Use Number Lines to Find Equivalent Fractions?

Visual Learning Bridge
The Circle W Ranch 1-mile trail has water for cattle at each \(\frac{1}{4}\) mile mark. The Big T Ranch 1-mile trail has water for cattle at the \(\frac{1}{2}\)-mile mark. What fractions name the points on the trails where there is water for cattle at the same distance from the start of each trail?
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 22

You can use number lines to find the fractions.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 23
The fractions \(\frac{2}{4}\) and \(\frac{1}{2}\) name the same points on the trails where there is water for cattle. They are at the same distance from the start of the trails.

Convince Me! Model with Math lan paints \(\frac{6}{8}\) of a fence. Anna paints \(\frac{3}{4}\) of another fence of equal size and length. How can you show that lan and Anna have painted the same amount of each fence?

Answer:
Yes, both Anna and Lan have painted the same amount of each fence.

Explanation:
In the above-given question,
given that,
Lan paints \(\frac{6}{8}\) of a fence.
Anna paints \(\frac{3}{4}\) of another fence of equal size and length.
3/4 = 6/8.
2 x 3 = 6.
4 x 2 = 8.
so both Anna and Lan have painted the same amount of each fence.

Guided Practice

Do You Understand?
Question 1.
Complete the number line to show that \(\frac{2}{6}\) and \(\frac{1}{3}\) are equivalent fractions.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 24

Answer:
2/6 = 1/3.

Explanation:
In the above-given question,
given that,
the fractions on the number line are:
1/6, 2/6, 3/6, 4/6, and 5/6.
2/6 = 1/3.
4/6 = 2/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-18

Question 2.
Sheila compares \(\frac{4}{6}\) and \(\frac{4}{8}\) she discovers that the fractions are NOT equivalent. How does Sheila know?
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 25

Answer:
Yes, both fractions are not equivalent.

Explanation:
In the above-given question,
given that,
Sheila compares \(\frac{4}{6}\) and \(\frac{4}{8}\).
4/6 = 2/3.
2 x 2 = 4.
2 x 3 = 6.
4/8 = 2/4.
2 x 2 = 4.
4 x 2 = 8.
so 4/6 is not equal to 4/8.

Do You Know How?
In 3 and 4, find the missing equivalent fractions on the number line. Then write the equivalent fractions below.
Question 3.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 26

Answer:
The missing equivalent fractions on the number line is 3/6.

Explanation:
In the above-given question,
given that,
the fractions on the number line are:
1/6, 2/6, 3/6, 4/6, 5/6, and 1.
3/6 = 1/2.
so the 3/6 and 1/2 are the equivalent fractions.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-19

Question 4.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 27

Answer:
6/8 = 3/4.

Explanation:
In the above-given question,
given that,
the fractions on the number line are:
1/8, 2/8, 3/8, 4/8, 5/8, 6/8, and 7/8.
2/8 = 1/4.
4/8 = 1/2.
6/8 = 3/4.
2 x 3 = 6.
2 x 4 = 8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-20

Independent Practice

In 5-8, find the missing equivalent fractions on the number line. Then write the equivalent fractions below.
Question 5.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 28

Answer:
The missing equivalent fractions on the number line are 2/8.

Explanation:
In the above-given question,
given that,
the fractions on the number line are 1/8, 2/8, 3/8, 4/8, 5/8, 6/8, and 7/8.
2/8 = 1/4.
1 x 2 = 2.
4 x 2 = 8.
so the missing equivalent fraction is 2/8 = 1/4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-21

Question 6.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 29

Answer:
The missing equivalent fractions on the number line are 4/6.

Explanation:
In the above-given question,
given that,
the fractions on the number line are 1/6, 2/6, 3/8, and 5/6.
2/6 = 1/3.
1 x 2 = 2.
3 x 2 = 6.
4/6 = 2/3.
2 x 2 = 4.
3 x 2 = 6.
so the missing equivalent fraction is 4/6 = 2/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-22

Question 7.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 30

Answer:
The missing equivalent fractions on the number line are 4/8.

Explanation:
In the above-given question,
given that,
the fractions on the number line are 1/8, 2/8, 3/8, 5/8, 6/8, and 7/8.
2/8 = 1/4.
1 x 2 = 2.
4 x 2 = 8.
4/8 = 2/4.
2 x 2 = 4.
4 x 2 = 8.
so the missing equivalent fraction is 4/8 = 2/4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-23

Question 8.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 31

Answer:
The missing equivalent fractions on the number line are 6/6.

Explanation:
In the above-given question,
given that,
the fractions on the number line are 1/6, 2/6, 3/6, 4/6, and 5/6.
2/6 = 1/3.
1 x 2 = 2.
3 x 2 = 6.
4/6 = 2/3.
2 x 2 = 4.
3 x 2 = 6.
6/6 = 1.
1 x 6 = 6.
so the missing equivalent fraction is 6/6 = 1.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-24

Problem Solving

Question 9.
Number Sense Bradley had 40 slices of pizza to share. How many pizzas did he have? Explain how you solved the problem.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 32

Answer:
The number of pizzas did he have = 5.

Explanation:
In the above-given question,
given that,
Bradley had 40 slices of pizza to share.
each pizza was cut into 8 slices.
40/8 = 5.
5 x 8 = 40.
so the number of pizzas did he have = 5.

Question 10.
Ms. Owen has 15 magazines to share among 5 students for an art project. How many magazines will each student get? Use the bar diagram to write an equation that helps solve the problem.
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 33

Answer:
The number of magazines will each student get = 3.

Explanation:
In the above-given question,
given that,
Ms. Owen has 15 magazines to share among 5 students for an art project.
15 / 5 = 3.
3 + 3 + 3 + 3 + 3 = 15.
3 x 5 = 15.
so the number of magazines will each student get = 3.

Question 11.
Yonita has 28 different apps on her computer. Casey has 14 music apps and 20 game apps on his computer. How many more apps does Casey have than Yonita? Explain.

Answer:
The number of apps does Casey has more than Yonita = 6.

Explanation:
In the above-given question,
given that,
Yonita has 28 different apps on her computer.
Casey has 14 music apps and 20 game apps on his computer.
14 + 20 = 34.
34 – 28 = 6.
so the number of apps does Casey has more than Yonita = 6.

Question 12.
Construct Arguments How can you tell, just by looking at the fractions, that \(\frac{2}{4}\) and \(\frac{3}{4}\) are NOT equivalent? Construct an argument to explain.

Answer:
Yes, 2/4 and 3/4 are not equivalent fractions.

Explanation:
In the above-given question,
given that,
the fraction 2/4 = 1/2.
1 x 2 = 2.
2 x 2 = 4.
the fraction 3/4 is not an equivalent fraction.
so both the fractions are not equal.

Question 13.
Higher Order Thinking Fiona and Gabe each had the same length of rope. Fiona used \(\frac{2}{3}\) of her rope. Using sixths, what fraction of the length of rope will Gabe need to use to match the amount Fiona used? Draw a number line as part of your answer.

Answer:
The fraction of the rope Gabe used is 4/6.

Explanation:
In the above-given question,
given that,
Fiona and Gabe each had the same length of rope.
Fiona used \(\frac{2}{3}\) of her rope.
4/6 = 2/3.
2 x 2 = 4.
3 x 2 = 6.
so the fraction of rope Gabe used is 4/6.

Assessment Practice

Question 14.
Use the number line to find which fraction is equivalent to \(\frac{3}{6}\).
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 34

Answer:
Option A is the correct answer.

Explanation:
In the above-given question,
given that,
3/6 = 1/2.
1 x 3 = 3.
3 x 2 = 6.
1/2 = 3/6.
so option A is correct.

Question 15.
Use the number line to find which fraction is equivalent to \(\frac{4}{8}\).
Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 35

Answer:
Option C is the correct answer.

Explanation:
In the above-given question,
given that,
4/8 = 2/4.
2 x 2 = 4.
4 x 2 = 8.
2/4 = 4/8.
so option C is correct.

Lesson 13.3 Use Models to Compare Fractions: Same Denominator

Solve & Share
Maria and Evan are both jogging a mile. Maria has jogged mile, and Evan has jogged mile. Show how far each has jogged. Use any model you choose. Who jogged farther? How do you know?
I can … compare fractions that refer to the same-sized whole and have the same denominator by comparing their numerators.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 36

Look Back! Suppose Evan had jogged \(\frac{5}{8}\) mile instead of \(\frac{3}{8}\) mile. Now, who has jogged farther? Explain.

Answer:
Evan jogged farther than Maria.

Explanation:
In the above-given question,
given that,
Evan had jogged \(\frac{5}{8}\) mile instead of \(\frac{3}{8}\).
5/8 – 3/8 = 2/8.
so I think maria jogged very little when compared to Evan.
so Evan jogged farther than Maria.

Essential Question
How Can You Compare Fractions with the Same Denominator?

Visual Learning Bridge
Two banners with positive messages are the same size. One banner is \(\frac{4}{6}\) yellow, and the other banner is \(\frac{2}{6}\) yellow. Which is greater, \(\frac{4}{6}\) or \(\frac{2}{6}\)?
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 37

\(\frac{4}{6}\) is 4 of the unit fraction is \(\frac{1}{6}\).
\(\frac{2}{6}\) of the unit fraction \(\frac{1}{6}\).
So, \(\frac{4}{6}\) is greater than \(\frac{2}{6}\).
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 38

Record the comparison using symbols or words.
\(\frac{4}{6}\) > \(\frac{2}{6}\)
Four sixths is greater than two sixths.
If two fractions have the same denominator, the fraction with the greater numerator is the greater fraction.

Convince Me! Reasoning Write a number for each numerator to make each comparison true. Use a picture and words to explain how you decided.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 39

Guided Practice

Do You Understand?
Question 1.
Explain how you can use fraction strips to show whether \(\frac{5}{6}\) or \(\frac{3}{6}\) of the same whole is greater.

Answer:
5/6 > 3/6.

Explanation:
In the above-given question,
given that,
the fractions are 5/6 and 3/6.
so 5/6 is greater than 3/6.
3/6 < 5/6.
5/6 > 3/6.

Question 2.
Which is greater, \(\frac{3}{4}\) or \(\frac{2}{4}\)? Draw \(\frac{1}{4}\)-strips to complete the diagram and answer the question.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 40

Answer:
3/4 is greater than 2/4.

Explanation:
In the above-given question,
given that,
3/4 is greater than 2/4.
the whole is 4.
but one time it is divided into 3 parts.
it is divided into 2 parts.
so 3/4 > 2/4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-25

Do You Know How?
In 3 and 4, compare. Write <, >, or =. Use the fraction strips to help.
Question 3.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 41

Answer:
2/8 > 1/8.

Explanation:
In the above-given question,
given that,
the fractions are 2/8 and 1/8.
1/8 + 1/8 = 2/8.
2/8 is greater than 1/8.
so 2/8 > 1/8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-26

Question 4.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 42

Answer:
3/6 < 5/6.

Explanation:
In the above-given question,
given that,
the fractions are 3/6 and 5/6.
5/6 is divided into 5 parts.
1/6 + 1/6 + 1/6 = 3/6.
so 3/6 < 5/6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-27

Independent Practice

Leveled Practice In 5-14, compare. Write <, >, or =. Use or draw fraction strips to help. The fractions refer to the same whole.
Question 5.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 43

Answer:
3/8 < 4/8.

Explanation:
In the above-given question,
given that,
the two fractions are 3/8 and 4/8.
1/8 + 1/8 + 1/8 = 3/8.
1/8 + 1/8 + 1/8 + 1/8 = 4/8.
so 3/8 < 4/8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-28

Question 6.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 44

Answer:
3/4 = 3/4.

Explanation:
In the above-given question,
given that,
the two fractions are 3/4 and 3/4.
1/4 + 1/4 + 1/4 = 3/4.
3/4 = 3/4.
so both of them are equal.

Question 7.
\(\frac{6}{8}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{3}{8}\)

Answer:
6/8 > 3/8.

Explanation:
In the above-given question,
given that,
the two fractions are 6/8 and 3/8.
6/8 = 3/4.
2 x 3 = 6.
4 x 2 = 8.
1/8 + 1/8 + 1/8 = 3/8.
6/8 > 3/8.

Question 8.
\(\frac{5}{8}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{7}{8}\)

Answer:
5/8 < 7/8.

Explanation:
In the above-given question,
given that,
the two fractions are 5/8 and 7/8.
1/8 + 1/8 + 1/8  + 1/8 + 1/8 = 5/8.
1/8 x 7 = 7/8.
5/8 < 7/8.

Question 9.
\(\frac{1}{2}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{1}{2}\)

Answer:
1/2 = 1/2.

Explanation:
In the above-given question,
given that,
the two fractions are 1/2 and 1/2.
1/2 x 1 = 1/2.
1/2 x 1 =1/2.
so both of them are equal.

Question 10.
\(\frac{1}{3}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{2}{3}\)
Answer:

1/3 < 2/3.

Explanation:
In the above-given question,
given that,
the two fractions are 1/3 and 2/3.
1/3 x 1 = 1/3.
1/3 + 1/3 = 2/3.
1/3 < 2/3.

Question 11.
\(\frac{6}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{3}{6}\)
Answer:

6/6 > 3/6.

Explanation:
In the above-given question,
given that,
the two fractions are 6/6 and 3/6.
1/6 + 1/6 + 1/6  + 1/6 + 1/6 + 1/6 = 6/6.
1/6 + 1/6 + 1/6 = 3/6.
6/6 > 3/6.

Question 12.
\(\frac{2}{8}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{3}{8}\)
Answer:

2/8 < 3/8.

Explanation:
In the above-given question,
given that,
the two fractions are 2/8 and 3/8.
1/8 + 1/8 = 2/8.
1/8 + 1/8 +1/8 = 3/8.
2/8 < 3/8.

Question 13.
\(\frac{3}{3}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{1}{3}\)
Answer:

3/3 > 1/3.

Explanation:
In the above-given question,
given that,
the two fractions are 3/3 and 1/3.
1/3 + 1/3 + 1/3  = 3/3.
1/3 x 1 = 1/3.
3/3 > 1/3.

Question 14.
\(\frac{1}{4}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{3}{4}\)
Answer:

1/4 < 3/4.

Explanation:
In the above-given question,
given that,
the two fractions are 1/4 and 3/4.
1/4 x 1 = 1/4.
1/4 +1/4 + 1/4  = 3/4.
1/4 < 3/4.

Problem Solving

In 15 and 16, use the pictures of the strips that have been partly shaded.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 45
Question 15.
Compare. Write <, >, or =
The green strips show \(\frac{1}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{2}{6}\)

Answer:
1/6 < 2/6.

Explanation:
In the above-given question,
given that,
the two fractions are 1/6 and 2/6.
1/6 x 1 = 1/6.
1/6 +1/6 = 2/6.
1/6 < 2/6.

Question 16.
Do the yellow strips show \(\frac{2}{4}\) > \(\frac{3}{4}\)? Explain.

Answer:
No, 2/4 < 3/4.

Explanation:
In the above-given question,
given that,
the two fractions are 2/4 and 3/4.
1/4 +1/4 = 2/4.
1/4 +1/4 + 1/4  = 3/4.
2/4 < 3/4.

Question 17.
Izzy and Henry have two different pizzas. Izzy ate \(\frac{3}{8}\) of her pizza. Henry ate \(\frac{3}{8}\) of his pizza. Izzy ate more pizza than Henry. How is this possible? Explain.

Answer:
No, it was not possible.

Explanation:
In the above-given question,
given that,
Izzy and Henry have two different pizzas.
Izzy ate \(\frac{3}{8}\) of her pizza.
Henry ate \(\frac{3}{8}\) of his pizza.
3/8 = 1/8 + 1/8 + 1/8.
3/8 x 1 = 3/8.
3/8 = 3/8.
so both of them ate the equal.

Question 18.
Generalize Two fractions are equal. They also have the same denominator. What must be true of the numerators of the fractions? Explain.

Answer:
Yes, the two fractions are equal.

Explanation:
In the above-given question,
given that,
Izzy and Henry have two different pizzas.
Izzy ate \(\frac{3}{8}\) of her pizza.
Henry ate \(\frac{3}{8}\) of his pizza.
3/8 = 1/8 + 1/8 + 1/8.
3/8 x 1 = 3/8.
3/8 = 3/8.
so both of them ate the equal.

Question 19.
Number Sense Mr. Domini had $814 in the bank on Wednesday. On Thursday, he withdrew $250, and on Friday, he withdrew $185. How much money did he have in the bank then?

Answer:
The money he has in the bank = $379.

Explanation:
In the above-given question,
given that,
Mr. Domini had $814 in the bank on Wednesday.
On Thursday, he withdrew $250.
On Friday, he withdrew $185.
250 + 185 = 435.
814 – 435 = 379.
so Mr. Domini had $814 in the bank on Wednesday.

Question 20.
Higher Order Thinking Tom’s parents let him choose whether to play his favorite board game for \(\frac{7}{8}\) hour or for \(\frac{8}{8}\) hour. Explain which amount of time you think Tom should choose and why.

Answer:
Tom should choose 8/8 hour.

Explanation:
In the above-given question,
given that,
Tom’s parents let him choose whether to play his favorite board game for 7/8 hours.
8/8 hour = 1.
7/8 x 1 = 7/8.
1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 8/8.
1 = 8/8.
so i think Tom should choose 1 hour.

Assessment Practice

Question 21.
Paul and Enrique each have equal-sized pizzas cut into 8 equal slices. Paul eats 3 slices. Enrique eats 2 slices. Select numbers and symbols from the box to write a comparison for the fraction of pizza Paul and Enrique have each eaten.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 46

Answer:
Paul eats more slices than Enriques.

Explanation:
In the above-given question,
given that,
Paul and Enrique each have equal-sized pizzas cut into 8 equal slices.
Paul eats 3 slices.
Enrique eats 2 slices.
1/8 + 1/8 + 1/8 = 3/8.
1/8 + 1/8 = 2/8.
so paul eats more slices than Enriques.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-30

Lesson 13.4 Use Models to Compare Fractions: Same Numerator

Solve & Share
Krista, Jamal, and Rafe each had 1 serving of vegetables. Krista ate \(\frac{2}{6}\), Jamal ate \(\frac{2}{3}\), and Rafe ate \(\frac{2}{8}\) of his serving. Arrange the fractions in order from least to greatest to show who ate the least and who ate the greatest amount of vegetables.
I can … compare fractions that refer to the same whole and have the same numerator by comparing their denominators.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 47

Answer:
Rafe, Krista, and Jamal.

Explanation:
In the above-given question,
given that,
Krista, Jamal, and Rafe each had 1 serving of vegetables.
Krista ate \(\frac{2}{6}\), Jamal ate \(\frac{2}{3}\).
Rafe ate \(\frac{2}{8}\) of his serving.
2/6 = 1/6 + 1/6.
2/3 = 1/3 + 1/3.
2/8 = 1/8 + 1/8.
so Rafe ate least when compared to Krista and Jamal.
so the order from least to highest.
Rafe, Krista, and Jamal.

Look Back! Tamika ate \(\frac{2}{2}\) of a serving of vegetables. In order from least to greatest, arrange the fractions of a serving Krista, Jamal, Rafe, and Tamika each ate. Explain your reasoning.

Answer:
Rafe, Krista, Jamal, and Tamika.

Explanation:
In the above-given question,
given that,
Tamika ate \(\frac{2}{2}\) of a serving of vegetables.
2/2 = 1.
so Tamika at more than Rafe, Krista, and Jamal.

Essential Question
How Can You Compare Fractions with the Same Numerator?

Visual Learning Bridge
Claire bought 2 scarves as souvenirs from her visit to a Florida university. The scarves are the same size. One scarf is \(\frac{5}{6}\) orange, and the other scarf is \(\frac{5}{8}\) orange. Which is greater, \(\frac{5}{6}\) or \(\frac{5}{8}\)?
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 48

What You Show
Use fraction strips to reason about the size of \(\frac{5}{6}\) a compared to the size of \(\frac{5}{8}\).
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 49
There are 5 sixths. There are 5 eighths. The parts are different sizes.
The greater the denominator, the smaller each part will be.

What You Write
Describe the comparison using symbols or words.
\(\frac{5}{6}\) > \(\frac{5}{8}\)
Five sixths is greater than five eighths.
If two fractions have the same numerator, the fraction with the lesser denominator is the greater fraction.

Convince Me! Critique Reasoning Julia says \(\frac{1}{8}\) is greater than \(\frac{1}{4}\) because 8 is greater than 4. Critique Julia’s reasoning. Is she correct? Explain.

Answer:
Yes, Julia’s reasoning was correct.

Explanation:
In the above-given question,
given that,
Julia says \(\frac{1}{8}\) is greater than \(\frac{1}{4}\).
1/8 = 1 x 1/8.
1/4 = 1 x 1/4.
so Julia’s reasoning was correct.

Guided Practice

Do You Understand?
Question 1.
How can fraction strips help you reason about whether \(\frac{4}{6}\) or \(\frac{4}{8}\) of the same whole is greater?

Answer:
4/6 > 4/8.

Explanation:
In the above-given question,
given that,
the two fractions are 4/6 and 4/8.
4/6 = 1/6 + 1/6 + 1/6 + 1/6.
4/8 = 1/8 + 1/8 + 1/8 + 1/8.
4/6 x 1 = 4/6.
4/8 x 1 = 4/8.
so 4/6 > 4/8.

Question 2.
Which is greater, \(\frac{1}{4}\) or \(\frac{1}{6}\)? Draw fraction strips to complete the diagram and answer the question.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 50

Answer:
1/4 > 1/6.

Explanation:
In the above-given question,
given that,
the two fractions are 1/4 and 1/6.
1/4 x 1 = 1/4.
1/6 x 1 = 1/6.
1 is divided into 1/4 and 1/6.
1/4 > 1/6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-31

Do You Know How?
In 3 and 4, compare. Write <, >, or =. Use fraction strips to help.
Question 3.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 51

Answer:
3/6 < 3/3.

Explanation:
In the above-given question,
given that,
the two fractions are 3/6 and 3/3.
3/6 = 1/6 + 1/6 + 1/6.
3/3 = 1.
so 3/6 < 3/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-32

Question 4.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 52

Answer:
4/6 < 4/8.

Explanation:
In the above-given question,
given that,
the two fractions are 4/6 and 4/8.
4/6 = 1/6 + 1/6 + 1/6 + 1/6.
4/8 = 1/8 + 1/8 + 1/8 + 1/8.
so 4/6 = 1 x 4/6.
so 4/6 < 4/8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-33

Independent Practice

Leveled Practice In 5-14, compare. Write <, >, or =. Use or draw fraction strips to help. The fractions refer to the same whole.
Question 5.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 53

Answer:
2/4 < 2/3.

Explanation:
In the above-given question,
given that,
the two fractions are 2/4 and 2/3.
2/4 = 1/4 + 1/4.
2/3 = 1/3 + 1/3.
so 2/4 < 2/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-34

Question 6.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 54

Answer:
4/4 > 4/6.

Explanation:
In the above-given question,
given that,
the two fractions are 4/4 and 4/6.
4/4 = 1.
1/6 + 1/6 + 1/6 + 1/6 = 4/6.
so 4/4 > 4/6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-35

Question 7.
\(\frac{2}{3}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{2}{2}\)

Answer:
2/3 > 2/2.

Explanation:
In the above-given question,
given that,
the two fractions are 2/3 and 2/2.
2/2 = 1.
1/3 + 1/3 = 2/3.
so 2/3 > 2/2.

Question 8.
\(\frac{4}{8}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{4}{8}\)

Answer:
4/8 = 4/8.

Explanation:
In the above-given question,
given that,
the two fractions are 4/8 and 4/8.
4/8 = 1/8 + 1/8 + 1/8 + 1/8.
4/8 x 1 = 4/8.
so 4/8 = 4/8.

Question 9.
\(\frac{5}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{5}{8}\)

Answer:
5/6 > 5/8.

Explanation:
In the above-given question,
given that,
the two fractions are 5/6 and 5/8.
5/6 = 1/6 + 1/6 + 1/6 + 1/6 + 1/6.
5/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
so 5/6 > 5/8.

Question 10.
\(\frac{1}{4}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{1}{3}\)

Answer:
1/4 > 1/3.

Explanation:
In the above-given question,
given that,
the two fractions are 1/4 and 1/3.
1/4 = 1/4 x 1.
1/3 x 1 = 2/3.
so 1/4 > 1/3.

Question 11.
\(\frac{1}{3}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{1}{6}\)

Answer:
1/3 > 1/6.

Explanation:
In the above-given question,
given that,
the two fractions are 1/3 and 1/2.
1/3 = 1 x 1/3.
1/2 x 1 = 1/3.
so 1/3 > 1/6.

Question 12.
\(\frac{4}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{4}{6}\)

Answer:
4/6 = 4/6.

Explanation:
In the above-given question,
given that,
the two fractions are 4/6 and 4/6.
4/6 = 1 x 4/6.
1/6 + 1/6 + 1/6 + 1/6 = 4/6.
so 4/6 = 4/6.

Question 13.
\(\frac{1}{8}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{1}{2}\)

Answer:
1/8 < 1/2.

Explanation:
In the above-given question,
given that,
the two fractions are 1/8 and 1/2.
1/8 = 1 x 1/8.
1/2 x 1 = 1/2.
so 1/8 < 1/2.

Question 14.
\(\frac{2}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{2}{3}\)

Answer:
2/6 < 2/3.

Explanation:
In the above-given question,
given that,
the two fractions are 2/6 and 2/3.
2/6 = 1/6 + 1/6.
1/3 + 1/3 = 2/3.
so 2/6 < 2/3.

Problem Solving

Question 15.
James uses blue and white tiles to make the two designs shown here. James says that the total blue area in the top design is the same as the total blue area in the bottom design. Is he correct? Explain.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 55

Answer:
Yes, James was correct.

Explanation:
In the above-given question,
given that,
James uses blue and white tiles to make the two designs.
James says that the total blue area in the top design is the same as the total blue area in the bottom design.
4/8 = 1/8 + 1/8 + 1/8 + 1/8.
1/8 x 4 = 4/8.
so James was correct.

Question 16.
Amy sold 8 large quilts and 1 baby quilt. How much money did she make from selling quilts?
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 56

Answer:
The money did she make from selling quilts = $520.

Explanation:
In the above-given question,
given that,
Amy sold 8 large quilts and 1 baby quilt.
60 x 8 = 480.
40 x 1 = 40.
480 + 40 = 520.
so the money did she make from selling quilts = $520.

Question 17.
Be Precise Write two comparison statements about the fractions shown below.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 57

Answer:
3/3 > 3/4.

Explanation:
In the above-given question,
given that,
the two fractions are 3/3 and 3/4.
3/3 = 1/3 + 1/3 + 1/3.
3/4 = 1/4 + 1/4 + 1/4.
so 3/3 > 3/4.

Question 18.
Higher Order Thinking John says that when you compare two fractions with the same numerator, you look at the denominators because the fraction with the greater denominator is greater. Is he correct? Explain, and give an example.

Answer:
Yes, he was correct.

Explanation:
In the above-given question,
given that,
John says that when you compare two fractions with the same numerator,
3/3 and 3/4.
3/3 = 1.
3/4 = 1/4 + 1/4 + 1/4.
1 > 1/4.
so he was correct.

Assessment Practice

Question 19.
These fractions refer to the same whole. Which of these comparisons are correct? Select all that apply.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 58

Answer:
2/4 > 2/3, 1/2 > 1/4, 5/6 = 5/6, and 3/4 > 3/6.

Explanation:
In the above-given question,
given that,
the fractions are 2/4 and 2/3.
2/4 = 1/4 + 1/4.
2/3 = 1/3 + 1/3.
the fractions are 1/2 and 1/4.
1/4 x 1 = 1/4.
1/2 x 1 = 1/2.
the fractions are 3/4 and 3/6.
3/4 = 1/4 + 1/4 + 1/4.
3/6 = 1/6 + 1/6 + 1/6.
so the four fractions are correct.

Lesson 13.5 Compare Fractions: Use Benchmarks

Solve & Share
Mr. Evans wrote \(\frac{2}{8}, \frac{4}{8}, \frac{6}{8}, \frac{1}{8}, \frac{3}{8}, \frac{5}{8}\) on and \(\frac{7}{8}\) on the board. Then he circled the fractions that are closer to 0 than to 1. Which fractions did he circle? Which fractions did he not circle? Explain how you decided.
I can … use what I know about the size of benchmark numbers to compare fractions.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 59

Look Back! Eric says that \(\frac{3}{8}\) is closer to 1 than to 0 because \(\frac{3}{8}\) is greater than \(\frac{1}{8}\). Is he correct? Use benchmark numbers to evaluate Eric’s reasoning and justify your answer.

Answer:
Yes, Eric was correct.

Explanation:
In the above-given question,
given that,
Eric says that 3/8 is closer to 1.
3/8 is greater than 1/8.
3/8 = 1/8 + 1/8 + 1/8.
so 3/8 > 1/8.
so Eric was correct.

Essential Question
How Can Benchmark Numbers Be Used to Compare Fractions?

Visual Learning Bridge
Keri wants to buy of a container of roasted peanuts. Alan wants to buy of a container of roasted peanuts. The containers are the same size. Who will buy more peanuts?
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 60

Compare each fraction to the benchmark number \(\frac{1}{2}\). Then see how they relate to each other in size.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 61

So, \(\frac{2}{6}\) is less than \(\frac{2}{3}\).
\(\frac{2}{6}\) < \(\frac{2}{3}\)
Alan will buy more peanuts than Keri.

Convince Me! Make Sense and Persevere Candice buys \(\frac{2}{8}\) of a container of roasted peanuts. The container is the same size as those used by Keri and Alan. She says \(\frac{2}{8}\) is between \(\frac{1}{2}\) and 1, so she buys more peanuts than Alan. Is Candice correct? Explain.

Answer:
Candice, she was correct.

Explanation:
In the above-given question,
given that,
Candice buys \(\frac{2}{8}\) of a container of roasted peanuts.
The container is the same size as those used by Keri and Alan.
She says \(\frac{2}{8}\) is between \(\frac{1}{2}\) and 1.
2/8 = 1/8 + 1/8.
1/2 x 1 = 1/2.
so Candice was correct.

Guided Practice

Do You Understand?
Question 1.
Tina used benchmark numbers to decide that \(\frac{3}{8}\) is less than \(\frac{7}{8}\). Do you agree? Explain.

Answer:
Yes, 3/8 is less than 7/8.

Explanation:
In the above-given question,
given that,
Tina used benchmark numbers to decide that 3/8 is less than 7/8.
3/8 = 1/8 + 1/8 + 1/8.
7/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
so 3/8 is less than 7/8.

Question 2.
Write two fractions with a denominator of 6 that are closer to 0 than to 1.

Answer:
The two fractions are 3/6 and 4/6.

Explanation:
In the above-given question,
given that,
the two fractions are 3/6 and 4/6
3/6 = 1/6 + 1/6 + 1/6.
4/6 = 1/6 + 1/6 + 1/6 + 1/6.
so 3/6 and 4/6 equal to 0 and 1.

Question 3.
Write two fractions with a denominator of 8 that are closer to 1 than to 0.

Answer:
The two fractions are 2/8 and 7/8.

Explanation:
In the above-given question,
given that,
the two fractions with a denominator of 8 that are closer to 1 than to 0.
2/8 = 1/8 + 1/8.
7/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
so the two fractions are 2/8 and 7/8 is equal to 0 and 1.

Do You Know How?
In 4-6, choose from the fractions \(\frac{1}{8}, \frac{1}{4}, \frac{6}{8}\) and \(\frac{3}{4}\). Use fraction strips to help.
Question 4.
Which fractions are closer to 0 than to 1?

Answer:
The two fractions are 3/4 and 1/4.

Explanation:
In the above-given question,
given that,
the fractions are 1/8, 1/4, 6/8, and 3/4.
3/4 = 1/4 + 1/4 + 1/4.
1/4 x 1 = 1/4
so the two fractions are 3/4 and 1/4.

Question 5.
Which fractions are closer to 1 than to 0?

Answer:
The fractions are 6/8 and 3/4.

Explanation:
In the above-given question,
given that,
the fractions are 1/8, 1/4, 6/8, and 3/4.
6/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
3/4 = 1/4 + 1/4 + 1/4.
so the fractions closer to 1 than to 0 are 6/8 and 3/4.

Question 6.
Use the two fractions with a denominator of 8 to write a true statement: < .

Answer:
1/8 < 6/8.

Explanation:
In the above-given question,
given that,
the fractions are 1/8, 1/4, 6/8, and 3/4.
6/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
3/4 = 1/4 + 1/4 + 1/4.
the two fractions with a denominator of 8.
so 1/8 < 6/8.

Independent Practice

In 7 and 8, choose from the fractions, \(\frac{2}{3}, \frac{7}{8}, \frac{1}{4}\), and \(\frac{2}{6}\).
Question 7.
Which of the fractions are closer to 0 than to 1?

Answer:
The fractions are closer to 0 than to 1 are 2/3 and 1/4.

Explanation:
In the above-given question,
given that,
the fractions are 2/3, 7/8, 1/4, and 2/6.
2/3 = 1/3 + 1/3.
1/4 x 1 = 1/4.
so the fractions are closer to 0 than to 1 are 2/3 and 1/4.

Question 8.
Which of the fractions are closer to 1 than to 0?

Answer:
The fractions are closer to 1 than to 0 are 7/8 and 2/6.

Explanation:
In the above-given question,
given that,
the fractions are 2/3, 7/8, 1/4, and 2/6.
7/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
2/6 = 1/6 + 1/6.
so the fractions are closer to 1 than to 0 are 7/8 and 2/6.

In 9-14, use a strategy to compare. Write <, >, or =.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 62
Question 9.
\(\frac{5}{8}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{7}{8}\)

Answer:
5/8 < 7/8.

Explanation:
In the above-given question,
given that,
the two fractions are 5/8 and 7/8.
5/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
7/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
so 5/8 < 7/8.

Question 10.
\(\frac{5}{8}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{2}{8}\)

Answer:
5/8 > 2/8.

Explanation:
In the above-given question,
given that,
the two fractions are 5/8 and 2/8.
5/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
2/8 = 1/8 + 1/8.
so 5/8 > 2/8.

Question 11.
\(\frac{3}{4}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{3}{6}\)

Answer:
3/4 > 3/6.

Explanation:
In the above-given question,
given that,
the two fractions are 3/4 and 3/6.
3/4 = 1/4 + 1/4 + 1/4.
3/6 = 1/6 + 1/6 + 1/6.
so 3/4 < 3/6.

Question 12.
\(\frac{4}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{4}{8}\)

Answer:
4/6 < 4/8.

Explanation:
In the above-given question,
given that,
the two fractions are 4/6 and 4/8.
4/6 = 1/6 + 1/6 + 1/6 + 1/6.
4/8 = 1/8 + 1/8 + 1/8 + 1/8.
so 4/6 < 4/8.

Question 13.
\(\frac{2}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{2}{4}\)

Answer:
2/6 > 2/4.

Explanation:
In the above-given question,
given that,
the two fractions are 2/6 and 2/4.
2/6 = 1/6 + 1/6.
2/4 = 1/4 + 1/4.
so 2/6 > 2/4.

Question 14.
\(\frac{2}{3}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{1}{3}\)

Answer:
2/3 > 1/3.

Explanation:
In the above-given question,
given that,
the two fractions are 2/3 and 1/3.
2/3 = 1/3 + 1/3.
1/3 = 1/3 x 1.
so 2/3 > 1/3.

Problem Solving

In 15-17, use the table at the right.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 63
Question 15.
Which people have walked closer to 1 mile than to 0 miles?

Answer:
Mr. Nunez and Miss Lee have walked closer to 1 mile than to 0 miles.

Explanation:
In the above-given question,
given that,
there are 5 people in the chart.
they are 1/6, 5/6, 1/3, 4/8, and 4/6.
the people closer to 1 mile than to 0 miles are Mr. Nunez and Miss.
the fractions closer to 1 mile is 5/6 and 4/6.

Question 16.
Which people have walked closer to 0 miles than to 1 mile?

Answer:
Mrs. Avery and Miss Chang have walked closer to 0 miles than to 1 mile.

Explanation:
In the above-given question,
given that,
there are 5 people in the chart.
they are 1/6, 5/6, 1/3, 4/8, and 4/6.
the people closer to 0 miles than to 1 mile are Mrs. Avery and Miss chang.
the fractions closer to 0 miles is 1/6 and 1/3.

Question 17.
Who has walked a fraction of a mile that is closer to neither 0 nor 1? Explain.

Answer:
Mr. O’Leary has walked closer to neither 0 nor 1.

Explanation:
In the above-given question,
given that,
there are 5 people in the chart.
they are 1/6, 5/6, 1/3, 4/8, and 4/6.
the people closer to neither 0 nor 1.
the fractions are 4/8.

Question 18.
Rahul compares two wholes that are the same size. He says that \(\frac{2}{6}\) < \(\frac{2}{3}\) because \(\frac{2}{6}\) is less than \(\frac{1}{2}\), and \(\frac{2}{3}\) is greater than \(\frac{1}{2}\). Is he correct? Explain.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 64

Answer:
Yes, he was correct.

Explanation:
In the above-given question,
given that,
Rahul compares two wholes that are the same size.
He says that \(\frac{2}{6}\) < \(\frac{2}{3}\).
\(\frac{2}{6}\) is less than \(\frac{1}{2}\).
2/6 < 2/3.
2/6 < 1/2.
2/3 > 1/2.
so he was correct.

Question 19.
Make Sense and Persevere Manish drives 265 more miles than Janice. Manish drives 642 miles. How many miles does Janice drive?

Answer:
The number of miles does Janice drive =

Explanation:
In the above-given question,
given that,
Manish drives 265 more miles than Janice.
Manish drives 642 miles.
642 – 265 = 377.
so the number of miles does Janice drives = 377.

Question 20.
Algebra Nika has 90 pencils. Forty of them are yellow, 13 are green, 18 are red, and the rest are blue. How many blue pencils does Nika have?

Answer:
The number of blue pencils does Nika have = 47.

Explanation:
In the above-given that,
given that,
Algebra Nika has 90 pencils.
Forty of them are yellow, 13 are green, 18 are red, and the rest are blue.
13 + 18 = 43.
90 – 43 = 47.
so the number of blue pencils does Nika have = 47.

Question 21.
Higher Order Thinking Omar says that \(\frac{2}{6}\) < \(\frac{4}{6}\) because \(\frac{2}{6}\) is between 0 and \(\frac{1}{2}\), and \(\frac{4}{6}\) is between \(\frac{1}{2}\) and 1. Is he correct? Explain.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 65

Answer:
Yes, he was correct.

Explanation:
In the above-given question,
given that,
2/6 < 4/6.
2/6 is between 0 and 1/2.
4/6 is between 1/2 and 1.
0, 2/6, and 1/2.
1/2, 4/6, and 1.
so Omar was correct.

Assessment Practice

Question 22.
Each of the fractions in the comparisons at the right refer to the same whole. Use benchmark fractions to reason about the size of each fraction. Select all the correct comparisons.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 66

Answer:
2/3 < 2/4, 3/6 > 3/8, and 3/8 > 5/8.

Explanation:
In the above-given question,
given that,
the fractions are 2/3 < 2/4, 2/4 < 2/3, 3/8 > 5/8, 1/4 < 2/4, and 3/6 > 3/8.
so the 2/3 < 2/4.
2/3 < 1 and 1/2 > 1.
3/6 > 3/8.
3/8 > 5/8.
so the correct fractions are 2/3 < 2/4, 3/6 > 3/8, and 3/8 > 5/8.

Lesson 13.6 Compare Fractions: Use the Number Line

Solve & Share
Tanya, Riaz, and Ryan each used a bag of flour to make modeling clay. The bags were labeled lb, á lb, and Ź lb. Show these fractions on a number line. How can you use the number line to compare two of these fractions?
I can … compare two fractions by locating them on a number line.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 67

Look Back! If the bags were labeled \(\frac{4}{8}\) lb, \(\frac{3}{8}\) lb, and \(\frac{6}{8}\) lb, how could a number line help you solve this problem?

Answer:
3/8 < 4/8 < 6/8.

Explanation:
In the above-given question,
given that,
if the bags were labeled 4/8 lb, 3/8 lb, and 6/8 lb.
so the fractions from least to greatest are 3/8, 4/8, and 6/8.
3/8 is near to 0.
4/8 is in between 0 and 1.
6/8 is near to 1.

Essentials Question
How Can You Compare Fractions Using the Number Line?

Visual Learning Bridge
Talia has two different lengths of blue and red ribbon. Does she have more blue ribbon or more red ribbon?
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 68

The fractions both refer to 1 yard of ribbon. This is the whole.
You can use a number line to compare \(\frac{1}{3}\) and \(\frac{2}{3}\).
The farther the distance of the fraction from zero on the number line, the greater the fraction.
Envision Math Common Core 3rd Grade Answers Topic 13 Fraction Equivalence and Comparison 69
On the number line, \(\frac{2}{3}\) is farther to the right than \(\frac{1}{3}\).
So, \(\frac{2}{3}\) > \(\frac{1}{3}\).
Talia has more blue ribbon than red ribbon.

Convince Me! Use Structure Talia has an additional length of green ribbon that measures \(\frac{2}{4}\) yard. How can you compare the length of the green ribbon to the lengths of the blue and red ribbons?

Guided Practice

Do You Understand?
Question 1.
When two fractions refer to the same whole, what do you notice when the denominators you are comparing are the same?

Answer:
The denominators are greater than the numerators.

Explanation:
In the above-given question,
given that,
if two fractions are the same.
the denominators are greater than the numerators.

Question 2.
Write a problem that compares two fractions with different numerators.

Answer:
1/3 > 2/3.

Explanation:
In the above-given question,
given that,
the two different fractions are 1/3 and 2/5.
1/3 x 1 = 1/3.
2/3 = 1/3 + 1/3.
so 1/3 > 2/3.

Do You Know How?
In 3-5, compare fractions using <, >, or =. Use the number lines to help.
Question 3.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 70

Answer:
2/4 < 2/3.

Explanation:
In the above-given question,
given that,
the two fractions are 2/4 and 2/3.
2/4 = 1/4 + 1/4.
2/3 = 1/3 + 1/3.
2/4 is the half portion in the number line.
so 2/4 > 2/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-36

Question 4.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 71

Answer:
2/6 < 2/3.

Explanation:
In the above-given question,
given that,
the two fractions are 2/6 and 2/3.
2/6 = 1/6 + 1/6.
2/3 = 1/3 + 1/3.
2/6 is below the half portion in the number line.
so 2/6 < 2/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-37

Question 5.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 72

Answer:
5/8 > 3/8.

Explanation:
In the above-given question,
given that,
the two fractions are 5/8 and 3/8.
5/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
3/8 = 1/8 + 1/8 + 1/8.
3/8 is the half portion in the number line.
so 5/8 > 3/8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-38

Independent Practice

In 6-9, use the number lines to compare the fractions. Write >, <, or =.
Question 6.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 73

Answer:
1/4 > 3/4.

Explanation:
In the above-given question,
given that,
the two fractions are 1/4 and 3/4.
1/4 = 1/4 x 1.
3/4 = 1/4 + 1/4 + 1/4.
1/4 is nearest to 0.
so 1/4 > 3/4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-39

Question 7.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 74

Answer:
4/6 < 3/6.

Explanation:
In the above-given question,
given that,
the two fractions are 4/6 and 3/6.
4/6 = 1/6 + 1/6 + 1/6 + 1/6.
3/6 = 1/6 + 1/6 + 1/6.
so 4/6 < 3/6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-40

Question 8.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 75

Answer:
1/2 > 1/4.

Explanation:
In the above-given question,
given that,
the two fractions are 1/4 and 1/2.
1/2 = 1/2 x 1.
1/4 = 1/4 x 1
1/4 is nearest to 0.
so 1/2 > 1/4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-41

Question 9.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 76

Answer:
1/3 > 1/8.

Explanation:
In the above-given question,
given that,
the two fractions are 1/3 and 1/8.
1/3 = 1/3 x 1.
1/8 = 1/8 x 1.
1/8 is nearest to 0.
so 1/3 > 1/8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-42

Problem Solving

Question 10.
Number Sense Randy wants to save $39. The table shows how much money he has saved. Explain how you can use estimation to decide if he has saved enough money.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 77

Answer:
Yes, he has saved enough money.

Explanation:
In the above-given question,
given that,
Randy wants to save $39.
in march month he saved $14.
in April he saved $11.
in May he saved $22.
14 + 11 + 22 = 47.
so he has saved enough money.

Question 11.
Scott ate \(\frac{2}{8}\) of a fruit bar. Anne ate \(\frac{4}{8}\) of a same-sized fruit bar. Can you tell who ate more of a fruit bar, Scott or Anne? Explain.

Answer:
Anne ate more of a fruit bar.

Explanation:
In the above-given question,
given that,
Scott ate \(\frac{2}{8}\) of a fruit bar.
Anne ate \(\frac{4}{8}\) of a same-sized fruit bar.
2/8 = 1/8 + 1/8.
4/8 = 1/8 + 1/8 + 1/8 + 1/8.
4 > 2.
so the whole is 8.
so Anne ate more of a fruit bar.

Question 12.
Be Precise Matt and Adara have identical pieces of cardboard for an art project. Matt uses \(\frac{2}{3}\) of his piece. Adara uses \(\frac{2}{6}\) of her piece. Who uses more, Matt or Adara? Draw two number lines to help explain your answer.

Answer:
Matt uses more cardboard.

Explanation:
In the above-given question,
given that,
Matt and Adara have identical pieces of cardboard for an art project.
matt uses 2/3 of his piece.
Adara uses 2/6 of her piece.
2/3 = 1/3 + 1/3.
2/6 = 1/6 + 1/6.
in 1st 3 is the whole part.
2 is near to 3.
so matt uses more cardboard.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-43

Question 13.
Higher Order Thinking Some friends shared a pizza. Nicole ate \(\frac{2}{8}\) of the pizza. Chris ate \(\frac{1}{8}\) more than Johan. Mike ate \(\frac{1}{8}\) of the pizza. Johan ate more than Mike. Who ate the most pizza?
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 78

Answer:
Chris ate more pizza.

Explanation:
In the above-given question,
given that,
Some friends shared a pizza.
Nicole ate \(\frac{2}{8}\) of the pizza.
Chris ate \(\frac{1}{8}\) more than Johan.
Mike ate \(\frac{1}{8}\) of the pizza.
1/8 + 1 = 2/8.
2/8 + 1 = 3/8.
so Chris ate more pizza.

Question 14.
Inez has 2 rows of plants. There are 8 plants in each row. Each plant has 3 flowers. How many flowers are there in all?

Answer:
The number of flowers is there = 48.

Explanation:
In the above-given question,
given that,
Inez has 2 rows of plants.
there are 8 plants in each row.
each plant has 3 flowers.
8 x 2 =16.
16 x 3 = 48.
so the number of flowers is there = 48.

Assessment Practice

Question 15.
Daniel walked \(\frac{3}{4}\) of a mile. Theo walked \(\frac{3}{8}\) of a mile. Use the number lines to show 0 the fraction of a mile Daniel and Theo each walked. Then select all the correct statements that describe the fractions.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 79
☐ \(\frac{3}{4}\) is equivalent to \(\frac{3}{8}\) because the fractions mark the same point.
☐ \(\frac{3}{4}\) is greater than \(\frac{3}{8}\) because it is farther from zero.
☐ \(\frac{3}{4}\) is less than \(\frac{3}{8}\) because it is farther from zero.
☐ \(\frac{3}{8}\) is less than \(\frac{3}{4}\) because it is closer to zero.
☐ \(\frac{3}{8}\) is greater than \(\frac{3}{4}\) because it is closer to zero.

Answer:
Option B is the correct answer.

Explanation:
In the above-given question,
given that,
Daniel walked \(\frac{3}{4}\) of a mile.
Theo walked \(\frac{3}{8}\) of a mile.
in the 1st line, the 3 is farther from the 0.
so 3/4 > 3/8.
so option B is the correct answer.

Lesson 13.7 Whole Numbers and Fractions

Solve & Share
Jamie’s family ate 12 pieces of apple pie during the week. Each piece was \(\frac{1}{6}\) of a whole pie. How many whole pies did Jamie’s family eat? What fraction of a pie was left over? Explain how you decided.
I can … use representations to find fraction names for whole numbers.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 80

Look Back! Jamie cuts another pie into smaller pieces. Each piece of pie is \(\frac{1}{8}\) of the whole. Jamie gives away 8 pieces. Does Jamie have any pie left over? Explain how you know.

Answer:
Jamie does not have left any pie.

Explanation:
In the above-given question,
given that,
Jamie cuts another pie into smaller pieces.
Each piece of pie is \(\frac{1}{8}\) of the whole.
Jamie gives away 8 pieces.
8 – 8 = 0.
so Jamie does not have left any pie.

Essential Question
How Can You Use Fraction Names to Represent Whole Numbers?

Visual Learning Bridge
What are some equivalent fraction names for 1, 2, and 3?
You can write a whole number as a fraction by writing the whole number as the numerator and
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 81
The number line shows 3 wholes. Each whole is divided into 1 equal part.
1 whole divided into 1 equal part can be written as \(\frac{1}{1}\).
2 wholes each divided into 1 equal part can be written as \(\frac{2}{1}\).
3 wholes each divided into 1 equal part can be written as \(\frac{1}{1}\)
1 = \(\frac{1}{2}\)
2 = \(\frac{2}{1}\)
3 = \(\frac{3}{1}\)

You can find other equivalent fraction names for whole numbers.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 82

Convince Me! Reasoning What equivalent fraction names can you write for 4 using denominators of 1, 2, or 4?

Another Example!
You can use fractions to name whole numbers.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 83
Twelve \(\frac{1}{3}\) fraction strips equal 4 whole fraction strips.
All whole numbers have fraction names. You can write 4 = \(\frac{12}{3}\).
You also know 4 = \(\frac{4}{1}\), so you can write 4 = \(\frac{4}{1}\) = \(\frac{12}{3}\).

Guided Practice

Do You Understand?
Question 1.
Explain how you know that \(\frac{4}{1}\) = 4.

Answer:
4/1 = 4.

Explanation:
In the above-given question,
given that,
12/3 = 4/1.
3 x 1 = 3.
3 x 4 = 12.
so 4/1 = 4.

Do You Know How?
Question 2.
Complete the number line.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 84

Answer:
The missing numbers in upside are 1/3, 3/3, 4/3, and 6/3.
the missing numbers on the downside are 1/6, 2/6, 4/6, 5/6, 6/6, 7/6, 9/6, 10/6, 11/6, and 12/6.

Explanation:
In the above-given question,
given that,
the number line is 1/3, 2/3, 3/3, 4/3, 5/3, 6/3.
2/6 = 1/3.
1 x 2 = 2.
3 x 2 = 6.
6/6 = 1.
9/6 = 3/2.
3 x 3 = 9.
3 x 2 = 6.
so the missing numbers are 1/3, 3/3, 4/3, and 6/3.
1/6, 2/6, 4/6, 5/6, 6/6, 7/6, 9/6, 10/6, 11/6, and 12/6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-44

Question 3.
Look at the number line. Write two equivalent fractions for each whole number.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 85

Answer:
1 = 3/3 = 6/6.
2 = 6/3 = 12/6.

Explanation:
In the above-given question,
given that,
the two numbers are 1 and 2.
1 = 3/3.
6 / 6 = 1.
6/3 = 2.
12 / 6 = 2.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-45

Independent Practice

In 4-7, write two equivalent fractions for each whole number. You can draw number lines to help.
Question 4.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 86

Answer:
4 = 8/2 = 4/1.

Explanation:
In the above-given question,
given that,
the number is 4.
8/2 = 4.
2 x 1 = 2.
2 x 4 = 8.
4 / 1 = 4.
so the missing numbers are 8 and 4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-46

Question 5.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 87

Answer:
1 = 4/4 = 1/1.

Explanation:
In the above-given question,
given that,
the number is 1.
4/4 = 1.
4 x 1 = 4.
1 x 4 = 4.
1 / 1 = 1.
so the missing numbers are 4 and 1.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-47

Question 6.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 88

Answer:
2 = 6/3 = 2/1.

Explanation:
In the above-given question,
given that,
the number is 2.
6/3 = 2.
3 x 1 = 3.
3 x 2 = 6.
2 / 1 = 2.
so the missing numbers are 6 and 1.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-48

Question 7.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 89

Answer:
5 = 10/2 = 5/1.

Explanation:
In the above-given question,
given that,
the number is 5.
10/2 = 5.
2 x 1 = 2.
2 x 5 = 10.
5 / 1 = 5.
so the missing numbers are 10 and 5.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-49

In 8-11, for each pair of fractions, write the equivalent whole number.
Question 8.
\(\frac{6}{2}\) = \(\frac{3}{1}\) =

Answer:
\(\frac{6}{2}\) = \(\frac{3}{1}\) = 3.

Explanation:
In the above-given question,
given that,
for each pair of fractions, write the equivalent whole number.
6/2 = 3.
3/1 = 3.
so \(\frac{6}{2}\) = \(\frac{3}{1}\) = 3.

Question 9.
\(\frac{3}{3}\) = \(\frac{6}{6}\) =

Answer:
\(\frac{3}{3}\) = \(\frac{6}{6}\) = 1.

Explanation:
In the above-given question,
given that,
for each pair of fractions, write the equivalent whole number.
3/3 = 1.
6/6 = 1.
so \(\frac{3}{3}\) = \(\frac{6}{6}\) = 1.

Question 10.
\(\frac{8}{4}\) = \(\frac{6}{3}\) =

Answer:
\(\frac{8}{4}\) = \(\frac{6}{3}\) = 2.

Explanation:
In the above-given question,
given that,
for each pair of fractions, write the equivalent whole number.
8/4 = 2.
6/3 = 2.
so \(\frac{8}{4}\) = \(\frac{6}{3}\) = 2.

Question 11.
\(\frac{9}{3}\) = \(\frac{12}{4}\) =

Answer:
\(\frac{9}{3}\) = \(\frac{12}{4}\) = 3.

Explanation:
In the above-given question,
given that,
for each pair of fractions, write the equivalent whole number.
9/3 = 3.
12/4 = 3.
so \(\frac{9}{3}\) = \(\frac{12}{4}\) = 3.

Problem Solving

Question 12.
Henry needs to fix or replace his refrigerator. It will cost $376 to fix it. How much more will it cost to buy a new refrigerator than to fix the current one?
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 90

Answer:
The more it costs to buy a new refrigerator = $593.

Explanation:
In the above-given question,
given that,
Henry needs to fix or replace his refrigerator.
It will cost $376 to fix.
the new refrigerator cost is $969.
969 – 376 = 593.
so more it costs to buy a new refrigerator = $593.

Question 13.
Declan says, “To write an equivalent fraction name for 5, I can write 5 as the denominator and 1 as the numerator.” Do you agree with Declan? Explain.

Answer:
No, Declan was wrong.

Explanation:
In the above-given question,
given that,
To write an equivalent fraction name for 5, I can write 5 as the denominator and 1 as the numerator.
5/1 = 5.
so Declan was wrong.

Question 14.
Look for Relationships Describe a pattern in fractions equivalent to 1 whole.

Answer:

Question 15.
enVision® STEM There are four stages in a butterfly’s life cycle: egg, caterpillar, chrysalis, and butterfly. Dan makes one whole poster for each stage. Use a fraction to show the number of whole posters Dan makes.

Answer:
Dan makes the fractions 1/4, 2/4, 3/4, and 4/4.

Explanation:
In the above-given question,
given that,
There are four stages in a butterfly’s life cycle: egg, caterpillar, chrysalis, and butterfly.
1st stage is egg = 1/4.
2nd stage is caterpillar = 2/4.
3rd stage is chrysalis = 3/4.
4th stage is butterfly = 4/4.
so the fractions are 1/4, 2/4, 3/4, and 4/4.

Question 16.
Karen bought 4 movie tickets for $9 each. She has $12 left over. How much money did Karen have to start? Explain.

Answer:
The money Karen has to start = $48.

Explanation:
In the above-given question,
given that,
Karen bought 4 movie tickets for $9 each. She has $12 left over
4 x 9 = 36.
36 + 12 = 48.
so the money Karen has to start = $48.

Question 17.
Higher Order Thinking Peggy has 4 whole sandwiches. She cuts each whole into halves. Then Peggy gives away 1 whole sandwich. Show the number of sandwiches Peggy has left as a fraction.

Each sandwich is cut into equal parts.

Answer:
The number of sandwiches Peggy has left as a fraction = 6/8.

Explanation:
In the above-given question,
given that,
Peggy has 4 whole sandwiches.
She cuts each whole into halves.
4 x 2 = 8.
Then Peggy gives away 1 whole sandwich.
8 – 2 = 6.
so the number of sandwiches Peggy has left as a fraction = 6/8.

Assessment Practice

Question 18.
Complete the equations. Match the fractions with their equivalent whole numbers.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 91

Answer:
6/1 = 12/2 = 6.
6/3 = 4/2 = 2.
4/4 = 1/1 = 1.
8/2 = 16/4 = 4.

Explanation:
In the above-given question,
given that,
the numbers are 1, 2, 4, and 6.
6/1 = 12/2 = 6.
6/3 = 4/2 = 2.
4/4 = 1/1 = 1.
8/2 = 16/4 = 4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-50

Lesson 13.8 Problem Solving

Construct Arguments
Solve & Share
Lindsey and Matt are running in a 1-mile race. They have both run the same distance so far. Write a fraction that shows how far Lindsey could have run. Write a different fraction that shows how far Matt could have run. Construct a math argument to support your answer.
I can … construct math arguments using what I know about fractions.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 92

Thinking Habits
Be a good thinker! These questions can help you.

  • How can I use numbers, objects, drawings, or actions to justify my argument?
  • Am I using numbers and symbols correctly?
  • Is my explanation clear and complete?
    Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 93

Look Back! Construct Arguments Are the two fractions you wrote equivalent? Construct a math argument using pictures, words, and numbers to support your answer.

Essential Question
How Can You Construct Arguments?

Visual Learning Bridge
Clara and Ana are making rugs. The rugs will be the same size. Clara has finished of her rug. Ana has finished of her rug. Who has finished more of her rug? Conjecture: Clara has finished a greater portion of her rug than Ana.

A conjecture is a statement that you think is true. It needs to be proved.

How can I explain why my conjecture is correct?
I need to construct an argument to justify my conjecture.

How can I construct an argument?
I can

  • use numbers, objects, drawings, or actions correctly to explain my thinking.
  • make sure my explanation is simple, complete, and easy to understand.

Here’s my thinking…
I will use drawings and numbers to explain my thinking.
The number lines represent the same whole. One is divided into fourths. One is divided into eighths.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 94
The number lines show that 3 of the fourths is greater than 3 of the eighths.
So, \(\frac{3}{4}\) > \(\frac{3}{8}\). The conjecture is correct.

Convince Me! Construct Arguments Use numbers to construct another math argument to justify the conjecture above. Think about how you can look at the numerator and the denominator.

Guided Practice

Construct Arguments Paul and Anna were eating burritos. The burritos were the same size. Paul ate \(\frac{2}{6}\) of a burrito. Anna ate \(\frac{2}{3}\) of a burrito. Conjecture: Paul and Anna ate the same amount.
Question 1.
Draw a diagram to help justify the conjecture.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 95

Answer:
No, Paul and Anna were correct.

Explanation:
In the above-given question,
given that,
Paul and Anna were eating burritos.
The burritos were the same size.
Paul ate \(\frac{2}{6}\) of a burrito.
Anna ate \(\frac{2}{3}\) of a burrito.
paul ate 2 of the sixths is less than the 2 of the thirds.
2/6 = 1/6 + 1/6.
2/3 = 1/3 + 1/3.
yes, the conjecture is not correct.

Question 2.
Is the conjecture correct? Construct an argument to justify your answer.

Answer:
No, the conjecture was not correct.

Explanation:
In the above-given question,
given that,
Paul and Anna were eating burritos.
The burritos were the same size.
Paul ate \(\frac{2}{6}\) of a burrito.
Anna ate \(\frac{2}{3}\) of a burrito.
paul ate 2 of the sixths is less than the 2 of the thirds.
2/6 = 1/6 + 1/6.
2/3 = 1/3 + 1/3.
yes, the conjecture is not correct.

Independent Practice

Construct Arguments Reyna has a blue ribbon that is 1 yard long and a red ribbon that is 2 yards long. She uses \(\frac{2}{4}\) of the red ribbon and \(\frac{2}{4}\) of the blue ribbon.

Conjecture: Reyna uses the same amount of red and blue ribbon.
Question 3.
Draw a diagram to help justify the conjecture.

Answer:
Yes, the conjecture was correct.

Explanation:
In the above-given question,
given that,
Reyna has a blue ribbon that is 1 yard long and a red ribbon that is 2 yards long.
She uses \(\frac{2}{4}\) of the red ribbon and \(\frac{2}{4}\) of the blue ribbon.
2/4 = 1/4 + 1/4.
2/4 = 1/4 + 1/4.
yes, the conjecture is correct.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-51

Question 4.
Is the conjecture correct? Construct an argument to justify your answer.

Answer:
Yes, the conjecture is correct.

Explanation:
In the above-given question,
given that,
Reyna has a blue ribbon that is 1 yard long and a red ribbon that is 2 yards long.
She uses \(\frac{2}{4}\) of the red ribbon and \(\frac{2}{4}\) of the blue ribbon.
2/4 = 1/4 + 1/4.
2/4 = 1/4 + 1/4.
yes, the conjecture is correct.

Question 5.
Explain another way you could justify the conjecture.
Answer:

Problem Solving

Performance Task School Fair Twenty-one students worked at the school fair. Mrs. Gold’s students worked at a class booth. The table shows the fraction of 1 hour that her students worked. Mrs. Gold wants to know the order of the work times for the students from least to greatest.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 96

Question 6.
Make Sense and Persevere What comparisons do you need to make to find out who worked the least?

Answer:
The student who worked least is Pedro.

Explanation:
In the above-given question,
given that,
School Fair Twenty-one students worked at the school fair.
Gold’s students worked at a class booth.
The table shows the fraction of 1 hour that her students worked.
Tim worked 4 hours.
Cathy worked 2/4 hours.
Jose worked 2/6 hours.
Pedro worked 3/4 hours.
3/4 < 2/4 < 2/6.
so the student who worked least is Pedro.

Question 7.
Be Precise What is the whole for each student’s time? Do all the fractions refer to the same whole?

Answer:
The same whole is 4.

Explanation:
In the above-given question,
given that,
School Fair Twenty-one students worked at the school fair.
Gold’s students worked at a class booth.
The table shows the fraction of 1 hour that her students worked.
Tim worked 4 hours.
Cathy worked 2/4 hours.
Jose worked 2/6 hours.
Pedro worked 3/4 hours.
3/4 < 2/4 < 2/6.
so the students who worked least is Pedro.

Question 8.
Use Appropriate Tools What tool could you use to solve this problem? Explain how you would use this tool.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 97

Answer:

Question 9.
Construct Arguments What is the order of the work times from least to greatest? Construct a math argument to justify your answer.

Answer:
The student who worked the least is Pedro.

Explanation:
In the above-given question,
given that,
School Fair Twenty-one students worked at the school fair.
Gold’s students worked at a class booth.
The table shows the fraction of 1 hour that her students worked.
Tim worked 4 hours.
Cathy worked 2/4 hours.
Jose worked 2/6 hours.
Pedro worked 3/4 hours.
3/4 < 2/4 < 2/6.
so the student who worked least is Pedro.

Topic 13 Fluency Practice Activity

Find a Match
Work with a partner. Point to a clue. Read the clue.
Look below the clues to find a match. Write the clue letter in the box next to the match.
Find a match for every clue.
I can … multiply and divide within 100.

Clues
A. ls equal to 3 × 3
B. is equal to 4 × 4
C. is equal to 9 × 4
D. is equal to 0 ÷ 10
E. is equal to 35 ÷ 5
F. is equal to 12 ÷ 4
G. is equal to 5 × 4
H. is equal to 3 × 8
I. Is equal to 2 × 5
J. Is equal to 3 × 10
K. is equal to 9 × 2
L. is equal to 2 × 4
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 98

Answer:
6 x 6 = 36, 40 / 4 = 10, 0 x 9 = 0, 3 x 6 = 18, 32 / 4 = 8, 10 x 2 = 20, 5 x 6 = 30, 7 / 21 = 3, 8 x 2 = 16, and 6 x 4 = 24.

Explanation:
In the above-given question,
given that,
A is not equal to 9.
B is equal to 16.
C is equal to 36.
D is equal to 0.
E is equal to 35 / 5 = 7.
F is equal to 3.
G is equal to 20.
H is equal to 24.
I is equal to 10.
J is equal to 30.
K is equal to 18.
L is equal to 8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-52

Topic 13 Vocabulary Review

Word List

  • denominator
  • equivalent fractions
  • fraction
  • number line
  • numerator
  • unit fraction

Understand Vocabulary

Write T for true or F for false.
Question 1.
______ \(\frac{1}{6}\) and \(\frac{2}{6}\) have the same numerator.

Answer:
True.

Explanation:
In the above-given question,
given that,
the fractions are 1/6 and 2/6.
2/6 = 1/3.
2 x 1 = 2.
2 x 3 = 6.
so both the fractions have the same numerator.

Question 2.
________ \(\frac{1}{2}\) and \(\frac{4}{8}\) are equivalent fractions.

Answer:
True.

Explanation:
In the above-given question,
given that,
the fractions are 1/2 and 4/8.
4/8 = 1/2.
4 x 1 = 4.
4 x 2 = 8.
so both the fractions are equivalent fractions.

Question 3.
_______ \(\frac{3}{8}\) is a unit fraction.

Answer:
True.

Explanation:
In the above-given question,
given that,
the fraction is 3/8.
3/8 = 1/8 + 1/8 + 1/8.
so 3/8 is a unit fraction.

Question 4.
_________ A whole number can be written as a fraction.

Answer:
True.

Explanation:
In the above-given question,
given that,
A whole number can be written as a fraction.
2 / 2 = 1.
so the whole number can be written as a fraction.

Question 5.
________ The denominators in \(\frac{1}{3}\) and \(\frac{2}{3}\) in are the same.

Answer:
True.

Explanation:
In the above-given question,
given that,
the fractions are 1/3 and 2/3.
2/3 = 1/3 + 1/3.
in both the fractions, the numerator, and denominator are the same.
so both the fractions have the same denominators.

Question 6.
_______ A number line always shows fractions.

Answer:
A unit fraction is a number line that always shows fractions.

Explanation:
In the above-given question,
given that,
3/8 is a unit fraction.
3 is the numerator and 8 is a denominator.
so the unit fraction is a number line that always shows fractions.

For each of these terms, give an example and a non-example.
Envision Math Common Core Grade 3 Answer Key Topic 13 Fraction Equivalence and Comparison 99

Answer:
1/2 is a fraction.
3/8 is a unit fraction.
1/2 = 2/4 are equivalent fractions.

Explanation:
In the above-given question,
given that,
the terms are fraction, unit fraction, and equivalent fractions.
1/2 is a fraction.
3/8 is a unit fraction.
1/2 = 2/4 are equivalent fractions.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-53

Use Vocabulary in Writing
Question 10.
Use at least 2 terms from the Word List to explain how to compare \(\frac{1}{2}\) and \(\frac{1}{3}\).

Answer:
The two terms have different denominators.

Explanation:
In the above-given question,
given that,
the two fractions are 1/2 and 1/3.
1/2 = 2/4.
1/3 = 2/6.
so both the fractions have different denominators.

Topic 13 Reteaching

Set A pages 485-488

Two fractions are equivalent if they name the same part of a whole.
What is one fraction that is equivalent to \(\frac{6}{8}\)?
You can use fraction strips to find equivalent fractions.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 100
\(\frac{6}{8}\) = \(\frac{3}{4}\)
You also can use area models to see that a I are equivalent fractions. The shaded fractions both show the same part of the whole.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 101

Remember to check that both sets of strips are the same length

In 1 and 2, find an equivalent fraction. Use fraction strips and models to help.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 102

Answer:
4/6 = 2/3.

Explanation:
In the above-given question,
given that,
the fraction is 4/6.
4/6 = 2/3.
2 x 2 = 4.
2 x 3 = 6.
so the equivalent fraction is 2/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-54

Question 2.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 103

Answer:
2/6 = 1/3.

Explanation:
In the above-given question,
given that,
the fraction is 2/6.
2/6 = 1/3.
1 x 2 = 2.
2 x 3 = 6.
so the equivalent fraction is 1/3.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-55

Set B pages 489-492

Riley says the library is \(\frac{2}{8}\) of a mile from their house. Sydney says it is \(\frac{1}{4}\) of a mile.
Use the number lines to find who is correct.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 104
The fractions \(\frac{2}{8}\) and \(\frac{1}{4}\) are equivalent. They are the same distance from 0 on a number line. Riley and Sydney are both correct.

Remember that equivalent fractions have different names, but they represent the same point on a number line.

In 1 and 2, write two fractions that name the same location on the number line.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 105

Answer:
The two fractions that name the same location on the number line = 1.

Explanation:
In the above-given question,
given that,
the fractions are 8/8 and 4/4.
8/8 = 1.
4/4 = 1.
so the two fractions that name the same location on the number line = 1.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-56

Question 2.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 106

Answer:
The two fractions that name the same location on the number line = 3/6 and 1/2.

Explanation:
In the above-given question,
given that,
the fractions are 3/6 and 1/2.
3/6 = 1/2.
3 x 1 = 3.
3 x 2 = 6.
so the two fractions that name the same location on the number line = 3/6 and 1/2.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-57

Set C pages 493-496

You can use fraction strips to compare fractions with the same denominator.
Compare \(\frac{3}{4}\) to \(\frac{2}{4}\).
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 107
The denominator of each fraction is 4.
Three \(\frac{1}{4}\) fraction strips show \(\frac{3}{4}\).
Two \(\frac{1}{4}\) fraction strips show \(\frac{2}{4}\).
The fraction strips showing \(\frac{3}{4}\) have 1 more unit fraction than the strips showing \(\frac{2}{4}\).
So \(\frac{3}{4}\) > \(\frac{2}{4}\).

Remember that if fractions have the same denominator, the greater fraction has a greater numerator.

In 1-3, compare. Write <, >, or =. Use fraction strips to help.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 108

Answer:
3/6 < 5/6.

Explanation:
In the above-given question,
given that,
the two fractions are 3/6 and 5/6.
3/6 = 1/6 + 1/6 + 1/6.
5/6 = 1/6 + 1/6 + 1/6 + 1/6 + 1/6.
3/6 < 5/6.

Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-58

Question 2.
\(\frac{4}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{5}{6}\)

Answer:
4/6 < 5/6.

Explanation:
In the above-given question,
given that,
the two fractions are 4/6 and 5/6.
4/6 = 1/6 + 1/6 + 1/6 + 1/6.
5/6 = 1/6 + 1/6 + 1/6 + 1/6 + 1/6.
4/6 < 5/6.

Question 3.
\(\frac{5}{8}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{3}{8}\)

Answer:
5/8 > 3/8.

Explanation:
In the above-given question,
given that,
the two fractions are 5/8 and 3/8.
5/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
3/8 = 1/8 + 1/8 + 1/8.
5/8 > 3/8.

Set D pages 497-500

You can use fraction strips to compare fractions with the same numerator.
Compare \(\frac{1}{6}\) to \(\frac{1}{2}\).
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 109
The numerator of each fraction is 1.
The \(\frac{1}{6}\) fraction strip is less than the \(\frac{1}{2}\) strip.
So \(\frac{1}{6}\) < \(\frac{1}{2}\)
You can use reasoning to understand. Think about dividing a whole into 6 pieces and dividing it into 2 pieces. One of 6 pieces is less than 1 of 2 pieces.

Remember that if fractions have the same numerator, the greater fraction has a lesser denominator.

In 1-3, compare. Write <, >, or=. Use fraction strips to help.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 110

Answer:
3/4 < 3/8.

Explanation:
In the above-given question,
given that,
the two fractions are 3/4 and 3/8.
3/4 = 1/4 + 1/4 + 1/4.
3/8 = 1/8 + 1/8 + 1/8.
3/4 < 3/8.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-59

Question 2.
\(\frac{5}{6}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{5}{8}\)

Answer:
5/6 < 5/8.

Explanation:
In the above-given question,
given that,
the two fractions are 5/6 and 5/8.
5/6 = 1/6 + 1/6 + 1/6 + 1/6 + 1/6.
5/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8.
5/6 < 5/8.

Question 3.
\(\frac{1}{3}\) Envision Math Common Core 3rd Grade Answer Key Topic 13 Fraction Equivalence and Comparison 2 \(\frac{1}{2}\)

Answer:
1/3 > 1/2.

Explanation:
In the above-given question,
given that,
the two fractions are 1/3 and 1/2.
1/3 = 2/6.
2/6 = 1/6 + 1/6.
1/3 > 1/2.

Set E pages 501-504

You can compare fractions using benchmark numbers such as 0, \(\frac{1}{2}\), and 1.

Chris and Mary are painting pictures. The pictures are the same size. Chris painted \(\frac{3}{4}\) of his picture. Mary painted her picture. Who painted the greater amount?
\(\frac{3}{4}\) is greater than \(\frac{1}{2}\).
\(\frac{3}{8}\) is less than \(\frac{1}{2}\).
Chris painted the greater amount.

Remember that you can compare each fraction to a benchmark number to see how they relate to each other.

In 1 and 2, use benchmark numbers to help solve.
Question 1.
Mike had \(\frac{2}{6}\) of a candy bar. Sally had \(\frac{4}{6}\) of a candy bar. Whose fraction of a candy bar was closer to 1? Closer to 0?

Answer:
Sally was closer to 1.

Explanation:
In the above-given question,
given that,
Mike had \(\frac{2}{6}\) of a candy bar.
Sally had \(\frac{4}{6}\) of a candy bar.
2/6 = 1/3.
4/6 = 2/3.
2/3 is closer to 1.
so sally was closer to 1.

Question 2.
Paul compared two bags of rice. One weighs \(\frac{4}{6}\) pound, and the other weighs \(\frac{4}{8}\) pound. Which bag is heavier?

Answer:
The 4/6 pounds bag is heavier.

Explanation:
In the above-given question,
given that,
Paul compared two bags of rice.
One weighs 4/6 pound.
the other weighs 4/8 pound.
4/6 = 2/3.
4/8 = 2/4.
so the 4/6 pounds bag is heavier.

Set F pages 505-508

You can use a number line to compare fractions.
Which is greater, \(\frac{3}{6}\) or \(\frac{4}{6}\)?
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 111
\(\frac{4}{6}\) is farther from zero than \(\frac{3}{6}\), so \(\frac{4}{6}\) is greater.
You also can compare two fractions with the same numerator by drawing two number lines.

Which is greater, \(\frac{2}{4}\) or \(\frac{2}{3}\)?
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 112
\(\frac{2}{3}\) is farther from zero than \(\frac{2}{4}\), so \(\frac{2}{3}\) is greater.

Remember to draw two number lines that are equal in length when comparing fractions with different denominators.

In 1 and 2, compare. Write <, >, or=. Use number lines to help.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 113

Answer:
2/6 < 3/6.

Explanation:
In the above-given question,
given that,
the two fractions are 2/6 and 3/6.
2/6 = 1/3.
2/6 = 1/6 + 1/6.
3/6 = 1/2.
3/6 = 1/6 + 1/6 + 1/6.
so 2/6 < 3/6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-60

Question 2.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 114

Answer:
3/4 > 3/6.

Explanation:
In the above-given question,
given that,
the two fractions are 3/4 and 3/6.
3/4 = 1/4 + 1/4 + 1/4.
3/6 = 1/6 + 1/6 + 1/6.
3/6 = 1/2.
so 3/4 > 3/6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-61

Set G pages 509-512

How many thirds are in 2 wholes?
You can use a number line or fraction strips to find a fraction name for 2 using thirds.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 115
2 = \(\frac{6}{3}\)
The whole number 2 can also be written as the fraction \(\frac{6}{3}\).

Remember that when you write whole numbers as fractions, the numerator can be greater than the denominator.

In 1-4, write an equivalent fraction for each whole number.
Question 1.
3

Answer:
The equivalent fraction is 12/4.

Explanation:
In the above-given question,
given that,
the whole number is 3.
12/4 = 3.
3 x 4 = 12.
3 x 1 = 3.
so the equivalent fraction is 12/4.

Question 2.
2

Answer:
The equivalent fraction is 4/2.

Explanation:
In the above-given question,
given that,
the whole number is 2.
4/2 = 2/1.
2 x 2 = 4.
2 x 1 = 2.
so the equivalent fraction is 4/2.

Question 3.
5

Answer:
The equivalent fraction is 15/3.

Explanation:
In the above-given question,
given that,
the whole number is 5.
15/3 = 5.
3 x 1 = 3.
3 x 5 = 15.
so the equivalent fraction is 15/3.

Question 4.
1

Answer:
The equivalent fraction is 3/3.

Explanation:
In the above-given question,
given that,
the whole number is 1.
3/3 = 1.
so the equivalent fraction is 3/3.

In 5-8, write the equivalent whole number for each fraction.
Question 5.
\(\frac{6}{3}\)

Answer:
The equivalent whole number is 2.

Explanation:
In the above-given question,
given that,
The fraction is 6/3.
6/3 = 2.
3 x 1 = 3.
3 x 2 = 6.
so the equivalent whole number is 2.

Question 6.
\(\frac{10}{2}\)

Answer:
The equivalent whole number is 5.

Explanation:
In the above-given question,
given that,
The fraction is 10/2.
10/2 = 5.
2 x 1 = 2.
2 x 5 = 10.
so the equivalent whole number is 5.

Question 7.
\(\frac{14}{2}\)

Answer:
The equivalent whole number is 7.

Explanation:
In the above-given question,
given that,
The fraction is 14/2.
14/2 = 7.
2 x 1 = 2.
7 x 2 = 14.
so the equivalent whole number is 7.

Question 8.
\(\frac{8}{8}\)

Answer:
The equivalent whole number is 1.

Explanation:
In the above-given question,
given that,
The fraction is 8/8.
8/8 = 1.
8 x 1 = 8.
1 x 8 = 8.
so the equivalent whole number is 1.

Set H pages 513-516

Think about these questions to help construct arguments.
Thinking Habits

  • How can I use numbers, objects, drawings, or actions to justify my argument?
  • Am I using numbers and symbols correctly?
  • Is my explanation clear and complete?
    Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 116

Remember that when you construct an argument, you explain why your work is correct.

Odell and Tamra paint two walls with the same dimensions. Odell paints \(\frac{1}{6}\) of a wall. Tamra paints \(\frac{1}{3}\) of the other wall. Conjecture: Odell paints less than Tamra.
Question 1.
Draw a diagram to justify the conjecture.

Answer:
Yes, Odell paints less than Tamra.

Explanation:
In the above-given question,
given that,
Odell and Tamra paint two walls with the same dimensions.
Odell paints \(\frac{1}{6}\) of a wall.
Tamra paints \(\frac{1}{3}\) of the other wall.
1/6 < 1/3.
so Odell paints less than Tamra.

Question 2.
Use the diagram to justify the conjecture.
Answer:

Topic 13 Assessment Practice

Question 1.
Two friends are working on a project. So far, Cindy has done \(\frac{4}{8}\) of the project, and Kim has done \(\frac{3}{8}\) of the project. Who has done more of the project? Explain.

Answer:
Cindy has done more of the project.

Explanation:
In the above-given question,
given that,
Two friends are working on a project.
Cindy has done \(\frac{4}{8}\) of the project.
Kim has done \(\frac{3}{8}\) of the project.
4/8 = 1/8 + 1/8 + 1/8 + 1/8.
3/8 = 1/8 + 1/8 + 1/8.
so Cindy has done more of the project.

Question 2.
Serena can compare \(\frac{3}{4}\) and \(\frac{3}{6}\) without using fraction strips. She says that a whole divided into 4 equal parts will have larger parts than the same whole divided into 6 equal parts. Three larger parts must be more than three smaller parts, so \(\frac{3}{4}\) is greater than \(\frac{3}{6}\). Is Serena correct? If not, explain Serena’s error. Then, write the correct comparison using symbols.

Answer:
Yes, Serena is correct.

Explanation:
In the above-given question,
given that,
Serena can compare 3/4 and 3/6 without using fraction strips.
3/4 = 1/4 + 1/4 + 1/4.
3/6 = 1/2.
3 x 1 = 3.
3 x 2 = 6.
so Serena is correct.

Question 3.
Jill finished reading \(\frac{2}{3}\) of a book for a summer reading project. Owen read \(\frac{2}{8}\) of the same book. Use the number lines to compare how much Jill and Owen each read. Who reads more of the book?
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 117

Answer:
The missing fractions are 1/3 and 2/3.
1/8, 2/8, 3/8, 4/8, 5/8, 6/8, and 7/8.

Explanation:
In the above-given question,
given that,
Jill finished reading \(\frac{2}{3}\) of a book for a summer reading project
Owen read \(\frac{2}{8}\) of the same book.
2/8 = 1/4.
2 x 1 = 2.
4 x 2 = 8.
so Jill read more of the book.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-62

Question 4.
A small cake is cut into 4 equal pieces. What fraction represents the entire cake? Explain.

Answer:
The fraction 4/4 represents the entire cake.

Explanation:
In the above-given question,
given that,
A small cake is cut into 4 equal pieces.
4 / 4 = 1.
so the fraction 4/4 represents the entire cake.

Question 5.
Mark and Sidney each have a piece of wood that is the same size. Mark paints \(\frac{2}{8}\) of his piece of wood. Sidney paints \(\frac{5}{8}\) of her piece of wood. Who painted a fraction that is closer to 1 than to 0? Explain how you found your answer. Then tell who painted less of his or her piece of wood.

Answer:
Sidney is closer to 1 than to 0.

Explanation:
In the above-given question,
given that,
Mark and Sidney each have a piece of wood that is the same size.
Mark paints \(\frac{2}{8}\) of his piece of wood.
Sidney paints \(\frac{5}{8}\) of her piece of wood.
2/8 is near to 0.
5/8 is closer to 1.
so Sidney is closer to 1 than to 0.

Question 6.
Greg colored the fraction model below.
A. Which fractions name the purple part of the model? Select all that apply.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 118

Answer:
The fraction 6/8 names the purple part of the model.

Explanation:
In the above-given question,
given that,
the fractions are 1/2, 3/4, 2/3, 4/6, 6/8.
6 boxes are filled with purple color.
so the fraction 6/8 names the purple part of the model.

B. Does \(\frac{1}{4}\) name the unshaded part of the model? Explain.

Answer:
Yes, the fraction 1/4 names the unshaded part of the model.

Explanation:
In the above-given question,
given that,
the fractions are 1/2, 3/4, 2/3, 4/6, 6/8.
2 boxes are not filled with purple color.
so the fraction 2/8 names the unshaded part of the model.

Question 7.
Carl, Fiona, and Jen each had a sandwich. The sandwiches were the same size and cut into eighths. Carl ate \(\frac{7}{8}\) of a sandwich, Fiona ate \(\frac{3}{8}\) of a sandwich, and Jen ate \(\frac{6}{8}\) of a sandwich. Who ate the most? Explain.

Answer:
Carl ate more sandwiches.

Explanation:
In the above-given question,
given that,
Carl, Fiona, and Jen each had a sandwich.
The sandwiches were the same size and cut into eighths.
Carl ate \(\frac{7}{8}\) of a sandwich.
Fiona ate \(\frac{3}{8}\) of a sandwich.
Jen ate \(\frac{6}{8}\) of a sandwich.
3/8, 6/8, 7/8.
so carl ate more sandwiches.

Question 8.
George wants to know if two pieces of wire are the same length. One wire is \(\frac{6}{8}\) foot. The other is \(\frac{3}{4}\) foot. Are they the same length? Fill in the fractions on the number line to compare the lengths of the pieces of wire. Then explain your answer.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 119
Answer:
The missing fractions are 1/4, 2/4, and 3/4.
2/8, 4/8, and 6/8.

Explanation:
In the above-given question,
given that,
George wants to know if two pieces of wire are the same length.
One wire is \(\frac{6}{8}\) foot.
The other is \(\frac{3}{4}\) foot.
6/8 = 3/4.
2 x 3 = 6.
2 x 4 = 8.
so the missing fractions are 1/4, 2/4, and 3/4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-63

Question 9.
Lezlie hiked \(\frac{3}{8}\) mile on Monday. On Wednesday she hiked \(\frac{3}{6}\) mile. She hiked a mile on Friday. Use benchmark fractions to arrange the lengths of the hikes in order from shortest to longest hike.

Answer:
The lengths of hikes in order from shortest and longest = 3/4, 3/6, and 3/8.

Explanation:
In the above-given question,
given that,
Lezlie hiked \(\frac{3}{8}\) mile on Monday.
On Wednesday she hiked \(\frac{3}{6}\) mile.
She hiked a mile on Friday.
8 – 2 = 6, 6 – 2 = 4.
so the lengths of hikes in order from shortest and longest = 3/4, 3/6, and 3/8.

Question 10.
A mural is divided into 3 equal parts. What fraction represents the entire mural? Explain.

Answer:
The entire mural is 3/3.

Explanation:
In the above-given question,
given that,
A mural is divided into 3 equal parts.
3/3 = 1.
so the entire mural is divided into 3 parts.

Question 11.
Meagan ate \(\frac{3}{4}\) of a cookie. Write an equivalent fraction for the amount of cookie Meagan did NOT eat. Then write a fraction that is equivalent to the amount of the cookie that Meagan did eat, and explain why your answer is correct.

Answer:
Megan did not eat = 1/4.

Explanation:
In the above-given question,
given that,
Meagan ate \(\frac{3}{4}\) of a cookie.
3/4 + 1/4 = 1.
3/4 = 1/4 + 1/4 + 1/4.
so megan did not ate = 1/4.

Question 12.
Circle each fraction that is equivalent to 1. Explain your reasoning. Then give another fraction that is equal to 1.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 120

Answer:
The fraction that is equivalent to 1 is 3/3 and 6/6.

Explanation:
In the above-given question,
given that,
the fractions are 2/4, 3/3, 3/6, 4/6, and 6/6.
circle each fraction that is equivalent to 1.
3/3 = 1, and 6/6 = 1.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-64

Question 13.
Use the number line to help order the fractions from least to greatest. Then explain how you found your answer.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 121

Answer:
The fractions from least to greatest = 0/4, 1/2, 1/4, 6/8, and 4/4.

Explanation:
In the above-given question,
given that,
The fractions are 6/8, 4/4, 1/4, 1/2, and 0/4.
6/8 = 3/4.
2 x 3 = 6.
2 x 4 = 8.
so the fractions from least to greatest = 0/4, 1/2, 1/4, 6/8, and 4/4.

Question 14.
Eva and Landon had the same math homework. Eva finished the homework. Landon finished of the homework. Conjecture: Eva and Landon finished the same amount of their homework.
A. Complete the number lines to help think about the conjecture.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 122

Answer:
The fractions are 1/4, 2/4, 3/4, and 4/4.
1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8, and 8/8.

Explanation:
In the above-given question,
given that,
Eva and Landon had the same math homework.
Eva finished the homework.
2/4 = 1/2.
2 x 1 = 2.
2 x 2 = 4.
so the missing fractions are 1/4, 2/4, 3/4, and 4/4.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-65

B. Use your diagram to decide if the conjecture is correct. Explain.
Answer:

Question 15.
For each pair of fractions, write the equivalent whole number in the box.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 123

Answer:
16/4 = 8/2 = 4.
6/3 = 4/2 = 2.
8/8 = 6/6 = 1.

Explanation:
In the above-given question,
given that,
the pair of fractions are 16/4, 8/2, 6/3, 4/2, 8/8, and 6/6.
16/4 = 8/2 = 4.
6/3 = 4/2 = 2.
8/8 = 6/6 = 1.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-66

Topic 13 Performance Task

Clothing Store Devin, Jenna, Eli, and Gabby work at a clothing store. On Saturday they each worked the same number of hours.

The Time Spent at Cash Register table shows the fraction of time each person spent checking out customers. The Time Spent on Customer Calls table shows the fraction of an hour Jenna spent answering phone calls for the store.

Use the Time Spent at Cash Register table to answer Questions 1-3.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 124
Question 1.
Draw fraction strips to show the fraction of time each person worked at the cash register.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 125

Answer:
The fraction of time each person worked at the cash register = 3/6, 2/6, 6/6, and 5/6.

Explanation:
In the above-given question,
given that,
Devin, Jenna, Eli, and Gabby work at a clothing store.
Devin worked 3/6 hours a day.
Jenna worked 2/6 hours a day.
Eli worked 6/6 hours a day.
Gabby worked 5/6 hours a day.
the fraction of hours is 3/6, 2/6, 6/6, and 5/6.
so the fraction of time each person worked at the cash register = 3/6, 2/6, 6/6, and 5/6.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-67

Question 2.
Who spent the most time at the cash register?

Answer:
The most time spent at the cash register = Gabby.

Explanation:
In the above-given question,
given that,
Devin, Jenna, Eli, and Gabby work at a clothing store.
Devin worked 3/6 hours a day.
Jenna worked 2/6 hours a day.
Eli worked 6/6 hours a day.
Gabby worked 5/6 hours a day.
3/6 = 1/2.
3 x 1 = 3.
3 x 2 = 6.
2/6 = 1/3.
2 x 1 = 2.
2 x 3 = 6.
6 / 6 = 1.
so the number of hours Gabby worked = 5/6.

Question 3.
Write a comparison to show the time Gabby spent at the cash register compared to the time Devin spent. Use >, <, or =.

Answer:
Gabby worked more hours than Devin.

Explanation:
In the above-given question,
given that,
Devin, Jenna, Eli, and Gabby work at a clothing store.
Devin worked 3/6 hours a day.
Jenna worked 2/6 hours a day.
Eli worked 6/6 hours a day.
Gabby worked 5/6 hours a day.
5/6 is greater than 3/6.
so Gabby worked more hours than Devin.

Question 4.
Use the Time Spent on Customer Calls table to answer this question: On which day did Jenna spend closest to one hour on the phone? Explain how you know.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 126

Answer:
Jenna spends the closest to one hour on Monday.

Explanation:
In the above-given question,
given that,
on Saturday he spends a 3/6 fraction of an hour.
on Sunday he spends 3/5 fraction of an hour.
on Monday he spends 3/4 fraction of an hour.
3/6 = 1/2.
3/4 is nearest to the 1.
so Jenna spends the closest to one hour on Monday.

The store sells different colors of men’s socks. The Socks table shows the fraction for each sock color in the store.

Use the Socks table to answer Questions 5 and 6.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 127

Question 5.
Part A
Complete the fractions on the number line. Label the fraction that represents each sock color.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 128

Answer:
The fraction that represents each sock color = 1/4, 2/4, 3/4, and 1.
1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8, and 1.

Explanation:
In the above-given question,
given that,
The store sells different colors of men’s socks.
the white color socks are 1/8.
the black color sock is 1/4.
the brown color socks are 3/8.
the gray color socks are 2/8.
so the fraction that represents each sock color = 1/4, 2/4, 3/4, and 1.
1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8, and 1.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-13- Fraction Equivalence and Comparision-68

Part B
Does the store have more brown socks or more white socks?

Answer:
The store has more brown socks = 3/8.

Explanation:
In the above-given question,
given that,
The store sells different colors of men’s socks.
the white color socks are 1/8.
the black color sock is 1/4.
the brown color socks are 3/8.
the gray color socks are 2/8.
3/8 is greater than 1/8.
so brown color socks are more than white color socks.

Question 6.
Use the number line in Exercise 5 Part A to construct an argument to justify the following conjecture: The store has an equal number of gray socks and black socks.

Answer:
Yes, the store has an equal number of gray socks and white socks.

Explanation:
In the above-given question,
given that,
The store sells different colors of men’s socks.
the white color socks are 1/8.
the black color sock is 1/4.
the brown color socks are 3/8.
the gray color socks are 2/8.
2/8 = 1/4.
2 x 1 = 2.
4 x 2 = 8.
so the store has the equal number of gray socks and white socks.

Question 7.
Use the Miguel’s Socks table to answer the question.
Envision Math Common Core Grade 3 Answers Topic 13 Fraction Equivalence and Comparison 129
Miguel bought some socks at the clothing store. After he washed them, he counted the number of individual socks he has. Each sock is \(\frac{1}{2}\) of a pair. How many pairs of black socks does he have? Write this number as a fraction.

Answer:
The number of pairs of black socks does he have = 3 pairs.

Explanation:
In the above-given question,
given that,
Miguel bought some socks at the clothing store.
the number of black color socks = 6.
the number of gray color socks = 8.
3/6 and 4/8.
3/6 = 1/2.
4/8 = 1/2.
so the number of pairs of black socks does he have = 3 pairs.

Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers

Envision Math 4th Grade Textbook Answer Key Topic 2.2 Rounding Whole Numbers

Rounding Whole Numbers

How can you round numbers?
Round 293,655,404 to the nearest thousand and to the nearest hundred thousand. You can use place value to round numbers.
Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers 1

Guided Practice*

Do you know HOW?

In 1 through 6, round each number to the place of the underlined digit.

Question 1.
128,955
Answer:

Question 2.
85,639
Answer:

Question 3.
9,924
Answer:

Question 4.
1,194,542
Answer:

Question 5.
160,656
Answer:

Question 6.
149,590
Answer:

Do You Understand ?

Question 7.
Writing to Explain Explain how to round a number when 7 is the digit to the right of the rounding place.
Answer:

Question 8.
In 2000 the population of the United States was 281,421,906. Round 281,421,906 to the nearest hundred thousand.
Answer:

independent Practice

Leveled Practice In 9 through 28, round each number to the place of the underlined digit. You may use a number line to help you.

Question 9.
493,295
Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers 40
Answer:

Rounding Whole Numbers 1

Question 10.
39,230
Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers 41
Answer:

Question 11.
77,292
Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers 43
Answer:

Question 12.
54,846
Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers 44
Answer:

Question 13.
4,028
Answer:

Question 14.
6,668,365
Answer:

Question 15.
453,280
Answer:

Question 16.
17,909
Answer:

Question 17.
1,406
Answer:

Question 18.
55,560
Answer;

Question 19.
21,679
Answer;

Question 20.
3,417,547
Answer:

Question 21.
117,821
Answer:

Question 22.
75,254
Answer:

Question 23.
9,049
Answer:

Question 24.
1,666,821
Answer:

Question 25.
2,420
Answer:

Question 26.
9,000,985
Answer:

Question 27.
9,511
Answer:

Question 28.
73,065
Answer:

Round 293,655,404 to the nearest thousand.
Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers 20
If the digit to the right of the rounding place is 5 or more, add 1 to the rounding digit. If it is less than 5, leave the rounding digit alone.

293,655,000
Since 4 < 5, leave the rounding digit as is. Change the digits to the right of the rounding place to zeros.
So, 293,655,404 rounds to 293,655,000.

Round 293,655,404 to the nearest hundred thousand.
Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers 21

The digit to the right of the rounding place is 5.

Since the digit is 5, round by adding 1 to the digit in the hundred thousands place.
So, 293,655,404 rounds to 293,700,000.

Problem Solving

Envision Math Grade 4 Answer Key Topic 2.2 Rounding Whole Numbers 23

Question 29.
For each zoo in the chart, round the attendance to the nearest hundred thousand.
Answer:

Question 30.
Reasoning Which zoo had the greatest number of visitors?
Answer:

Question 31.
Number Sense Write four numbers that round to 700 when rounded to the nearest hundred.
Answer:

Question 32.
Reasoning Write a number that when rounded to the nearest thousand and hundred will have a result that is the same.
Answer:

Question 33.
Jonas read that about 1,760,000 people will graduate from high school in California in the next four years. Jonas thinks this number
is rounded to the nearest ten thousand. What would the number be if it was rounded to the nearest hundred thousand?
Answer:

Question 34.
Liz had attended class every day since she started school as a kindergartner. She said she had been in school for about 1,000 days. What could the actual number of school days be if she rounded to the nearest ten?
Answer:

Question 35.
When rounded to the nearest ten thousand, which number would be rounded to 120,000?
A. 123,900
B. 126,480
C. 128,770
D. 130,000
Answer:

Question 36.
A fruit market sold 3,849 apples, 3,498 oranges, and 3,894 pears in one day. Write these numbers in order from greatest to least.
Answer:

Envision Math Grade 4 Answer Key Topic 2.1 Understanding Rounding

Envision Math 4th Grade Textbook Answer Key Topic 2.1 Understanding Rounding

Review What You Know

Vocabulary

Choose the best term from the box.
Envision Math Grade 4 Answers Topic 2.1 Understanding Rounding 1

Question 1.
In order to subtract 141 from 530, you need to __.
Answer:

Question 2.
___ tells about how many or about how much.
Answer:

Question 3.
When you subtract two numbers, the answer is the __.
Answer:

Question 4.
When you add numbers together, you find the __.

Addition Facts

Find the sum.

Question 5.
4 + 6
Answer:

Question 6.
7 + 5
Answer:

Question 7.
9 + 8
Answer:

Question 8.
14 + 5
Answer:

Question 9.
3 + 7
Answer:

Question 10.
37 + 7
Answer:

Question 11.
9 + 6
Answer:

Question 12.
6 + 5
Answer:

Question 13.
15 + 7
Answer:

Question 14.
3 + 8
Answer:

Question 15.
14 + 6
Answer:

Question 16.
25 + 5
Answer:

Subtraction Facts

Find the difference.

Question 17.
27 – 3
Answer:

Question 18.
6 – 4
Answer:

Question 19.
15 – 8
Answer:

Question 20.
11 – 8
Answer:

Question 21.
6 – 2
Answer:

Question 22.
17 – 8
Answer:

Question 23.
16 – 4
Answer:

Question 24.
20 – 5
Answer:

Question 25.
11 – 6
Answer:

Question 26.
14 – 6
Answer:

Question 27.
15 – 10
Answer:

Question 28.
13 – 7
Answer:

Question 29.
Writing to Explain Why does 843 round to 840 rather than to 850?

Understanding Rounding

Why do you round numbers?
Rounding replaces one number with another number that tells about how many or how much.

The Golden Gate Bridge’s towers reach a height of 746 feet. What is 746 rounded to the nearest ten? to the nearest hundred?

Guided Practice*

Do you know HOW?

In 1 through 4, use a number line to round each number to the place of the underlined digit.

Question 1.
2, 286
Answer:

Question 2.
5,747
Answer:

Question 3.
153
Answer:

Question 4.
8,639
Answer:

Do You Understand?

Question 5.
In the number lines above, why are the halfway point numbers different?
Answer:

Question 6.
In New York, the Verrazano-Narrows Bridge’s towers reach a height of 693 feet. What is 693 rounded to
the nearest ten?
Answer:

Independent Practice

Leveled Practice For 7 and 8, use the number line to round each number to the place of the underlined digit.

Question 7.
656
Envision Math Grade 4 Answers Topic 2.1 Understanding Rounding 30
Answer:

Question 8.
9,129
Envision Math Grade 4 Answers Topic 2.1 Understanding Rounding 31
Answer:

For 9 through 23, use a number line to round each number to the place of the underlined digit.

Question 9.
7,241
Answer:

Question 10.
3,414
Answer:

Question 11.
2,639
Answer:

Question 12.
561
Answer:

Question 13.
295
Answer:

Question 14.
206
Answer:

Question 15.
6,028
Answer:

Question 16.
873
Answer:

Question 17.
123
Answer:

Question 18.
1,999
Answer:

Question 19.
4,183
Answer:

Question 20.
647
Answer:

Question 21.
3,809
Answer:

Question 22.
792
Answer:

Question 23.
8,299
Answer:

Use a number line to round 746 to the nearest ten.
Compare 746 to the halfway point, which is 745.
Envision Math Grade 4 Answers Topic 2.1 Understanding Rounding 30.3
746 is to the right of the halfway point, so round to 750.

Use a number line to round 746 to the nearest hundred.
Compare 746 to the halfway point, which is 750.
Envision Math Grade 4 Answers Topic 2.1 Understanding Rounding 31.2
746 is to the left of the halfway point, so round to 700.

Problem Solving

For 24 and 25, use the table at the right.

Envision Math Grade 4 Answers Topic 2.1 Understanding Rounding 32

Question 24.
Write the number of cities in each state in expanded form. Then order the numbers from greatest to least.
Answer:

Question 25.
Round each number in the table to the nearest ten. Then order the rounded numbers from least to greatest.
Answer:

Question 26.
Number Sense Write four numbers that round to 500 when rounded to the nearest hundred.
Answer:

Question 27.
The attendance at a football game at California Memorial Stadium was 54,387. What is this number rounded to the nearest hundred?
Answer:

Question 28.
At a football game, a scoreboard showed the attendance at the game to be 35,396. Which choice is this number rounded to the nearest ten?
A. 35,000
B. 35,300
C. 35,390
D. 35,400
Envision Math Grade 4 Answers Topic 2.1 Understanding Rounding 50
Answer:

Question 29.
Writing to Explain Use the number line below. A car rental agency recorded the mileage of three cars in its fleet. What place
can you round each number to and still be able to accurately order the numbers? Explain.
Envision Math Grade 4 Answers Topic 2.1 Understanding Rounding 40
Answer:

Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions

Go through the enVision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions regularly and improve your accuracy in solving questions.

Envision Math Common Core 6th Grade Answers Key Topic 3 Numeric And Algebraic Expressions

?Topic essential Question  What are expressions and how they can be written and evaluated?
Answer:
Expressions are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.
To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number. To evaluate an expression, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations.

TOPIC 3 enVision STEM Project

Did You Know?
There are more than 600,000 bridges in the United States.

Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 1

Your Task: Design a Bridge
Suppose the proposed ma×imum weight limit for a new bridge in your community is 100,000 pounds. How many and what types of vehicles can be allowed to cross the bridge? How can the weight on the bridge be controlled? You and your classmates will begin the engineering design process to understand the problem, do necessary research, and brainstorm solutions.

Topic 3 GET READY!

Review What You Know!

Vocabulary

Choose the best term from the box to complete each definition.

composite number
formula
numerical expression
prime number

Numeric And Algebraic Expressions 1

Question 1.
A ____ is a rule that uses symbols to relate two or more quantities.
Answer:
We know that,
A “Formula” is a rule that uses symbols to relate two or more quantities
Hence, from the above,
We can conclude that
The best term that is suitable for the given definition is: Formula

Question 2.
The number 12 is a ____ because it has more than two factors.
Answer:
We know that,
The number 12 is a “Composite number” because it has more than two factors.
Hence, from the above,
We can conclude that
The best term that is suitable for the given definition is: Composite number

Question 3.
A ___ is a mathematical phrase that includes numbers and at least one operation.
Answer:
We know that,
A “Numerical expression” is a mathematical phrase that includes numbers and at least one operation.
Hence, from the above,
We can conclude that
The best term that is suitable for the given definition is: Numerical expression

Perimeter and Area
Use the formulas P = 2l + 2w and A = l × w, where l is the length and w is the width, to find the perimeter, P, and the area, A, of each figure.

Question 4.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 1.1
P = ___
A = ____
Answer:
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 1.1
Now,
From the given figure,
We can observe that
The length of a rectangle (L) is: 13 cm
The width of a rectangle (W) is: 13 cm
Now,
We know that,
The perimeter of a rectangle (P) is: 2 (L + W)
The area of a rectangle (A) is: Length × Width
So,
P = 2 × (13 + 13)
= 2 ×26
= 52 cm
A = 13 × 13
= 169 cm²
Hence, from the above,
We can conclude that
The perimeter of the given rectangle is: 52 cm
The area of the given rectangle is: 169 cm²

Question 5.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 1.2
P = ___
A = ____
Answer:
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 1.2
Now,
From the given figure,
We can observe that
The length of a rectangle (L) is 5 in.
The width of a rectangle (W) is 21 in.
Now,
We know that,
The perimeter of a rectangle (P) is: 2 (L + W)
The area of a rectangle (A) is: Length × Width
So,
P = 2 × (21 + 5)
= 2 ×26
= 52 in.
A = 21 × 5
= 105 in.²
Hence, from the above,
We can conclude that
The perimeter of the given rectangle is 52 in.
The area of the given rectangle is 105 in.²

Question 6.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 1.3
P = ___
A = ____
Answer:
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 1.3
Now,
From the given figure,
We can observe that
The length of a rectangle (L) is 9 m
The width of a rectangle (W) is 15 m
Now,
We know that,
The perimeter of a rectangle (P) is: 2 (L + W)
The area of a rectangle (A) is: Length × Width
So,
P = 2 × (9 + 15)
= 2 ×24
= 48 m
A = 9 × 15
= 135 m²
Hence, from the above,
We can conclude that
The perimeter of the given rectangle is 48 m
The area of the given rectangle is 135 m²

Multiples
Write the first five multiples of each number.

Question 7.
8
Answer:
The given number is: 8
Now,
We know that,
A multiple is a number that can be divided by another number a certain number of times without a remainder
Hence, from the above,
We can conclude that
The first 5 multiples of 8 are: 8, 16, 24, 32, and 40

Question 8.
9
Answer:
The given number is: 9
Now,
We know that,
A multiple is a number that can be divided by another number a certain number of times without a remainder
Hence, from the above,
We can conclude that
The first 5 multiples of 9 are: 9, 18, 27, 36, and 45

Question 9.
10
Answer:
The given number is: 10
Now,
We know that,
A multiple is a number that can be divided by another number a certain number of times without a remainder
Hence, from the above,
We can conclude that
The first 5 multiples of 10 are: 10, 20, 30, 40, and 50

Question 10.
6
Answer:
The given number is: 6
Now,
We know that,
A multiple is a number that can be divided by another number a certain number of times without a remainder
Hence, from the above,
We can conclude that
The first 5 multiples of 6 are: 6, 12, 18, 24, and 30

Question 11.
4
Answer:
The given number is: 4
Now,
We know that,
A multiple is a number that can be divided by another number a certain number of times without a remainder
Hence, from the above,
We can conclude that
The first 5 multiples of 4 are: 4, 8, 12, 16, and 20

Question 12.
3
Answer:
The given number is: 3
Now,
We know that,
A multiple is a number that can be divided by another number a certain number of times without a remainder
Hence, from the above,
We can conclude that
The first 5 multiples of 3 are: 3, 6, 9, 12, and 15

Factors

Question 13.
How can you find the factors of 12 and 15? Explain.
Answer:
The given numbers are: 12 and 15
Now,
We know that,
A factor is a number that divides into another number exactly and without leaving a remainder
Hence, from the above,
We can conclude that
The factors of 12 are: 1, 2, 3, 4, 6, and 12
The factors of 15 are: 1, 3, 5, and 15

Operations

Question 14.
How are the terms difference, sum, quotient, and product alike?
Answer:
Sum:
The sum is the result of adding two or more numbers.
Product:
The product of two or more numbers is the result of multiplying these numbers.
Quotient:
The quotient of two numbers is the result of the division of these numbers
Difference:
The word difference is the result of subtracting one number from another

Language Development
Write terms and phrases related to Numeric expressions and Algebraic expressions in the Venn diagram.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.1

In the box below, draw pictures to represent the terms and phrases in the overlap section of your diagram.

Topic 3 PICK A PROJECT

PROJECT 3A
What is the most inspiring poem you have read?
PROJECT: WRITE AN ALGEBRAIC POEM
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.2

PROJECT 3B
What equipment do you need to play your favorite sport?
PROJECT: PLAN A TEAM PURCHASE
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.3

PROJECT 3C
Where is the most interesting place you have gone swimming?
PROJECT: DESIGN A POOL PATIO
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.4

PROJECT 3D
In what ways have you seen exponents used in the real world?
PROJECT: CALCULATE WITH exPONENTS
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.5

Lesson 3.1 Understand and Represent exponents

Solve & Discuss It!

ACTIVITY

Fold a sheet of paper in half. Record the number of sections you see when it is unfolded. Continue folding the paper in half 4 more times. Record the number of sections each time. Describe any patterns you see.

Answer:
It is given that
Fold a sheet of paper in half. Record the number of sections you see when it is unfolded. Continue folding the paper in half 4 more times.
Now,
The given figure is:

Now,
From the given figure,
We can observe that,
When we fold a sheet of paper in half, there are 2 sections when we unfold the sheet of paper
So,
The number of sections when we fold the paper 4 more times in half = (The number of times a sheet of paper folded) × (The number of sections present when a sheet of paper is unfolded)
= 4 × 2
= 8 sections
Hence, from the above,
We can conclude that
The number of sections when we fold the paper 4 more times in half is: 8 sections

Look for Relationships How are the number of sections related to the number of folds?
Answer:
The figure from the above problem is:

Now,
When we observe the above figure,
We can say that
The number of sections present when we folded a paper in half is: 2 sections
So,
The number of sections = 2 × (The number of folds)
Hence, from the above,
We can conclude that
The relationship between the number of sections and the number of folds is:
The number of sections = 2 × (The number of folds)

Focus on math practices
Use Structure How many sections will there be after 6 folds? 7 folds?
Answer:
From the above problem,
We know that,
The number of sections = 2 × (The number of folds)
So,
The number of sections when there are 6 folds = 2 × 6
= 12 sections
The number of sections when there are 7 folds = 2 × 7
= 14 sections
Hence, from the above,
We can conclude that
The number of sections when there are 6 folds is: 12 sections
The number of sections when there are 7 folds is: 14 sections

VISUAL LEARNING

? Essential Question How can you write and evaluate numbers with exponents?
Answer:
You can use the “Order of operations” to evaluate the expressions containing exponents.
First, evaluate anything in Parentheses or grouping symbols.
Next, look for Exponents, followed by Multiplication and Division (reading from left to right)
Lastly, addition and subtraction (again, reading from left to right)

Example 1
The expression 2 × 2 × 2 represents the number of cells after 1 hour if there is 1 cell at the start. How can you write this expression using exponents? How many cells will there be after 1 hour?

Reasoning Repeated multiplication can be represented in more than one way.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.50

Some bacteria cells divide every 20 minutes to make 2 cells.

You can use an exponent to write the repeated multiplication of a number.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.6
A number that can be written using exponents is called a power.

You can use repeated multiplication to evaluate or find the value of power.

Multiply the first two factors, 2 × 2 = 4.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.7
There will be 8 cells after 1 hour.

Try It!
There are 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 bacteria cells after 3 hours. Write the repeated multiplication as power and then evaluate.
Answer:
It is given that
There are 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 bacteria cells after 3 hours
Now,
We know that,
The number that is repeatedly multiplied is the “Base”
The “Exponent” tells us how many times the base is used as a factor
A number that can be written using “Exponents” is called a “Power”
So,
The representation of the given repeated multiplication in the form of power is: 29
So,
29 = 25 × 24
= 32 × 16
= 512 cells
Hence, from the above,
We can conclude that
There are 512 bacteria cells present after 3 hours

Numeric And Algebraic Expressions 2

Convince Me! Why can you represent the number of cells after two hours as power 26?
Answer:
From Example 1,
It is given that
The number of bacteria cells present in 1 hour is: 23
Now,
We know that,
am × an = am + n
So,
The number of bacteria cells present in 2 hours = 23 × 23
= 26 bacteria cells
Hence, from the above,
We can conclude that
We can represent the number of cells after 2 hours as 2

Try It!
Evaluate (\(\frac{1}{3}\))³?
Answer:
The given expression is: (\(\frac{1}{3}\))³
So,
(\(\frac{1}{3}\))³
= \(\frac{1}{3}\) × \(\frac{1}{3}\) × \(\frac{1}{3}\)
= \(\frac{1 × 1}{3 × 3}\) × \(\frac{1}{3}\)
= \(\frac{1}{9}\) × \(\frac{1}{3}\)
= \(\frac{1 × 1}{9 × 3}\)
= \(\frac{1}{27}\)
Hence, from the above,
We can conclude that
(\(\frac{1}{3}\))³ = \(\frac{1}{27}\)

Try It!
Rafael calculated the foil as 1.8 × 104 units thick. Evaluate Rafael’s expression.
Answer:
It is given that
Rafael calculated the foil as 1.8 × 104 units thick.
Now,
We know that,
104 = 102 × 102
= 100 × 100
= 10,000
So,
1.8 × 104 = 18,000
Hence, from the above,
We can conclude that
Rafael calculated the foil as 18,000 units thick

KEY CONCEPT
You can represent a repeated multiplication expression using an exponent.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 6.10
You can evaluate a power using repeated multiplication.
54 = 5 × 5 × 5 × 5 = 625

Do You Understand?

Question 1.
? Essential Question How can you write and evaluate numbers with exponents?
Answer:
You can use the “Order of operations” to evaluate the expressions containing exponents.
First, evaluate anything in Parentheses or grouping symbols.
Next, look for Exponents, followed by Multiplication and Division (reading from left to right)
Lastly, addition and subtraction (again, reading from left to right)

Question 2.
Look for Relationships How many times is 4 used as a factor in the expression 45? Write the numerical expression as repeated multiplication.
Answer:
The given expression is: 45
Now,
We know that,
The “Exponent” tells how many times the base is used as a factor
So,
In the given expression,
4 is used 5 times as a factor
So,
The representation of the given expression in the form of a repeated multiplication is:
4 × 4 × 4 × 4 × 4
Hence, from the above,
We can conclude that
4 is used 5 times as a factor
The representation of the given expression in the form of a repeated multiplication is:
4 × 4 × 4 × 4 × 4

Question 3.
Be Precise What is a power that has the same value as 18? Explain.
Answer:
The given expression is: 18
Now,
We know that,
The value of 1 raised to an exponent of any whole number is always equal to 1
So,
The power that has the same value as the given expression is: 1n
Where,
n = 0, 1, 2,…..
Hence, from the above,
We can conclude that
The power that has the same value as the given expression is: 1n
Where,
n = 0, 1, 2,…..

Question 4.
Construct Arguments Does 2.5 × 100 equal 0, 1, 2.5, or 25? Justify your answer.
Answer:
The given expression is: 2.5 × 100
Now,
We know that,
Any nonzero number raised to an exponent of zero has a value of 1
So,
2.5 × 100 = 2.5 × 1
= 2.5
Hence, from the above,
We can conclude that
The value of the given expression is: 2.5

Question 5.
Model with Math
How would you write (\(\frac{1}{2}\))3 as repeated multiplication?
Answer:
The given expression is: (\(\frac{1}{2}\))3
Now,
We know that,
The number that is repeatedly multiplied is the “Base”
The “Exponent” tells how many times the base is used as a factor
So,
The representation of the given expression as a repeated multiplication is:
\(\frac{1}{2}\) × \(\frac{1}{2}\) × \(\frac{1}{2}\)
Hence, from the above,
We can conclude that
The representation of the given expression as a repeated multiplication is:
\(\frac{1}{2}\) × \(\frac{1}{2}\) × \(\frac{1}{2}\)

Do You Know How?

Question 6.
Write 81 as a repeated multiplication of 3s. Then write it as a power.
Answer:
The given number is: 81
Now,
We know that,
81 = 9 × 9
= 3 × 3 × 3 × 3
Now,
We know that,
The number that is repeatedly multiplied is the “Base”
The “Exponent” tells how many times the base is used as a factor
So,
The representation of 81 in the form of power is:
81 = 34
Hence, from the above,
We can conclude that
The representation of 81 as a repeated multiplication is:
81 = 3 × 3 × 3 × 3
The representation of 81 as power is:
81 = 34

Question 7.
Write 125 as a repeated multiplication of 5s. Then write it as a power.
Answer:
The given number is: 125
Now,
We know that,
125 = 25 × 5
= 5 × 5 × 5
Now,
We know that,
The number that is repeatedly multiplied is the “Base”
The “Exponent” tells how many times the base is used as a factor
So,
The representation of 125 in the form of power is:
125 = 53
Hence, from the above,
We can conclude that
The representation of 125 as a repeated multiplication is:
125 = 5 × 5 × 5
The representation of 125 as power is:
125 = 53

Question 8.
What is 0.75 × 0.75 × 0.75 × 0.75 × 0.75 written as a power?
Answer:
The given expression is: 0.75 × 0.75 × 0.75 × 0.75 × 0.75
Now,
We know that,
The number that is repeatedly multiplied is the “Base”
The “Exponent” tells how many times the base is used as a factor
So,
The representation of 0.75 × 0.75 × 0.75 × 0.75 × 0.75 in the form of power is:
0.75 × 0.75 × 0.75 × 0.75 × 0.75 = 0.755
Hence, from the above,
We can conclude that
The representation of 0.75 × 0.75 × 0.75 × 0.75 × 0.75 as power is:
0.75 × 0.75 × 0.75 × 0.75 × 0.75 = 0.755

Question 9.
What is \(\frac{3}{8}\) × \(\frac{3}{8}\) × \(\frac{3}{8}\) written as a power?
Answer:
The given expression is: \(\frac{3}{8}\) × \(\frac{3}{8}\) × \(\frac{3}{8}\)
Now,
We know that,
The number that is repeatedly multiplied is the “Base”
The “Exponent” tells how many times the base is used as a factor
So,
The representation of \(\frac{3}{8}\) × \(\frac{3}{8}\) × \(\frac{3}{8}\) in the form of power is:
\(\frac{3}{8}\) × \(\frac{3}{8}\) × \(\frac{3}{8}\) = (\(\frac{3}{8}\))3
Hence, from the above,
We can conclude that
The representation of \(\frac{3}{8}\) × \(\frac{3}{8}\) × \(\frac{3}{8}\) as power is:
\(\frac{3}{8}\) × \(\frac{3}{8}\) × \(\frac{3}{8}\) = (\(\frac{3}{8}\))3

In 10-13, evaluate each power.

Question 10.
(\(\frac{1}{6}\))2
Answer:
The given expression is: (\(\frac{1}{6}\))2
So,
(\(\frac{1}{6}\))2
= \(\frac{1}{6}\) × \(\frac{1}{6}\)
= \(\frac{1 × 1}{6 × 6}\)
= \(\frac{1}{36}\)
Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{1}{36}\)

Question 11.
450
Answer:
The given expression is: 450
Now,
We know that,
Any nonzero number raised to an exponent of zero has a value of 1
So,
450 = 1
Hence, from the above,
We can conclude that
The value of the given expression is: 1

Question 12.
0.15
Answer:
The given given expression is: 0.15
So,
0.15
= 0.1 × 0.1 ×0.1 × 0.1 × 0.1
= 0.00001
Hence, from the above,
We can conclude that
The value of the given expression is: 0.00001

Question 13.
73
Answer:
The given expression is: 73
So,
73
= 7 × 7 × 7
= 49 × 7
= 343
Hence, from the above,
We can conclude that
The value of the given expression is: 343

In 14-16, evaluate each expression.

Question 14.
4.5 × 104
Answer:
The given expression is: 4.5 × 104
Now,
We know that,
104 = 10,000
So,
4.5 × 104
= 45 × 103
= 45,000
Hence, from the above,
We can conclude that
The value of the given expression is: 45,000

Question 15.
0.6 × 106
Answer:
The given expression is: 0.6 × 106
Now,
We know that,
106 = 10,00,000
So,
0.6 × 106
= 6 × 105
= 6,00,000
Hence, from the above,
We can conclude that
The value of the given expression is: 6,00,000

Question 16.
3.4 × 100
Answer:
The given expression is: 3.4 × 100
Now,
We know that,
Any nonzero value raised to an exponent of zero has a value of 1
So,
100 = 1
So,
3.4 × 100
= 3.4 × 1
= 3.4
Hence, from the above,
We can conclude that
The value of the given expression is: 3.4

Practice & Problem Solving

Scan for Multimedia

In 17-20, write the exponent for each expression.

Question 17.
9 × 9 × 9 × 9
Answer:
The given expression is: 9 × 9 × 9 × 9
Now,
We know that,
The “Exponent” tells how many times the base is used as a factor
So,
From the given expression,
We can observe that
9 is repeated 4 times
Hence, from the above,
We can conclude that
The exponent for the given expression is: 4

Question 18.
1.29
Answer:
The given expression is: 1.29
Now,
We know that,
The “Exponent” tells how many times the base is used as a factor
So,
From the given expression,
We can observe that
1.2 is repeated 9 times
Hence, from the above,
We can conclude that
The exponent for the given expression is: 9

Question 19.
\(\frac{1}{6}\) × \(\frac{1}{6}\) × \(\frac{1}{6}\)
Answer:
The given expression is: \(\frac{1}{6}\) × \(\frac{1}{6}\) × \(\frac{1}{6}\)
Now,
We know that,
The “Exponent” tells how many times the base is used as a factor
So,
From the given expression,
We can observe that
\(\frac{1}{6}\) is repeated 3 times
Hence, from the above,
We can conclude that
The exponent for the given expression is: 3

Question 20.
7
Answer:
The given expression is: 7
Now,
We know that,
The “Exponent” tells how many times the base is used as a factor
So,
From the given expression,
We can observe that
7 is repeated 1 time
Hence, from the above,
We can conclude that
The exponent for the given expression is: 1

Leveled Practice In 21-26, evaluate each power or expression.

Question 21.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 8.1
Answer:
The given expression is: 83
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 512

Question 22.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 8.2
Answer:
The given expression is: (\(\frac{1}{5}\))4
So,

Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{1}{625}\)

Question 23.
0.62
Answer:
The given expression is 0.6²
So,
0.6² = 0.6 × 0.6
= 0.36
Hence, from the above,
We can conclude that
The value of the given expression is: 0.36

Question 24.
(\(\frac{1}{4}\))2
Answer:
The given expression is: (\(\frac{1}{4}\))²
So,
(\(\frac{1}{4}\))² = \(\frac{1}{4}\) × \(\frac{1}{4}\)
= \(\frac{1 × 1}{4 × 4}\)
= \(\frac{1}{16}\)
Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{1}{16}\)

Numeric And Algebraic Expressions 3

Question 25.
580
Answer:
The given expression is: 580
Now,
We know that,
Any nonzero value raised to an exponent of zero has a value of 1
So,
580 = 1
Hence, from the above,
We can conclude that
The value of the given expression is: 1

Question 26.
6.2 × 103
Answer:
The given expression is: 6.2 × 103
So,
6.2 × 103 = 62 ×102
= 62 × 100
= 6,200
Hence, from the above,
We can conclude that
The value of the given expression is: 6,200

Question 27.
A company rents two storage units. Both units are cube-shaped. What is the difference in the volume between the two storage units? Note that the volume of a cube is s3, where s is the side length. Explain.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 9.1
Answer:
It is given that
A company rents two storage units. Both units are cube-shaped
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 9.1
Now,
From the given figure,
We can observe that
The side length of the first storage unit is: 6.5 ft
The side length of the second storage unit is: 6 ft
Now,
We know that,
The volume of a cube = (Side)³
So,
The difference in volume between the two storage units = (The volume of the first storage unit) – (The volume of the second storage unit)
= (6.5)³ – 6³
= 274.625 – 216
= 58.63 ft³
Hence, from the above,
We can conclude that
The difference in volume between the two storage units is: 58.63 ft³

Question 28.
Jia is tiling a floor. The floor is a square with a side length of 12 feet. Jia wants the tiles to be squares with a side length of 2 feet. How many tiles does Jia need to cover the entire floor? Note that the area of a square is s2, where s is the side length. Explain.
Answer:
It is given that
Jia is tiling a floor. The floor is a square with a side length of 12 feet. Jia wants the tiles to be squares with a side length of 2 feet.
Now,
We know that,
The area of a square = (Side)²
So,
The area of the square floor = (The sidelength of the square floor)²
= 12²
= 144 feet²
So,
The area of the square tiles = (The sidelength of the square tiles)²
= 2²
= 4 feet²
Now,
The number of tiles Jia needed to cover the entire floor = (The area of the square floor) ÷ (The area of the square tiles)
= \(\frac{144}{4}\)
= 36 tiles
Hence, from the above,
We can conclude that
The number of tiles Jia needed to cover the entire floor is: 36 tiles

Question 29.
A marine biologist studies the population of seals in a research area. How many seals are in the research area?
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 9.2
Answer:
It is given that
A marine biologist studies the population of seals in a research area
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 9.2
Now,
From the given figure,
We can observe that
The population of Seals is: 3.27 × 10²
Now,
We know that,
10² = 10 × 10
= 100
So,
3.27 × 10² = 32.7 × 10
= 327 Seals
Hence, from the above,
We can conclude that
The number of Seals that are present in the research area is: 327 Seals

Question 30.
Higher-Order Thinking Zach invested $50 and tripled his money in two years. Kayla also invested $50, and after two years the amount was equal to 50 to the third power. Who had more money after two years? Explain.
Answer:
It is given that
Zach invested $50 and tripled his money in two years. Kayla also invested $50, and after two years the amount was equal to 50 to the third power
So,
According to the given information,
The amount of money invested by Zach in two years = $50 × 3
= $150
The amount of money invested by Kayla in two years = ($50)³
= $1,25,000
So,
From the above values,
We can say that
$1,25,000 > $150
Hence, from the above,
We can conclude that
Kayla had more money after two years

Question 31.
Malik read that the land area of Alaska is about 5.7 × 105 square miles. About how many square miles is the land area of Alaska?
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 9.3
Answer:
It is given that
Malik read that the land area of Alaska is about 5.7 × 105 square miles.
Now,
We know that,
105 = 1,00,000
104 = 10,000
So,
5.7 × 105 = 57 × 104
= 57 × 10,000
= 57,000 square miles
Hence, from the above,
We can conclude that
The land area of Alaska is about 57,000 square miles

Numeric And Algebraic Expressions 4

Question 32.
Explain why the expressions 100, 14, and 1 × 1.00 have the same value.
Answer:
The given expressions are: 100, 14, 1 × 1.04
Now,
We know that,
Any nonzero value that has raised to an exponent of zero has a value of 1
Any value of 1 that is raised to an exponent that contained a whole number has always a value of 1
Hence, from the above,
We can conclude that
The given expressions have the same value since some expressions have raised to an exponent of zero and some expressions have the value of 1 that is to an exponent of any whole number

Question 33.
Solve the equation 0.33 = n.
Answer:
The given equation is:
0.3³ = n
So,
By using the repeated multiplication,
n = 0.3 × 0.3 × 0.3
n = 0.09 × 0.3
n = 0.027
Hence, from the above,
We can conclude that
The value of “n” for the given equation is: 0.027

Question 34.
Construct Arguments The same digits are used for the expressions 25 and 52. Explain how to compare the values of the expressions.
Answer:
It is given that
The same digits are used for the expressions 25 and 52
Now,
We know that,
The number that is repeatedly multiplied is the “Base”
The “Exponent” tells how many times the base is used as a factor
So,
25 = 2 × 2 × 2 × 2 × 2
= 4 × 4 × 2
= 16 × 2
= 32
So,
52 = 5 ×5
= 25
So,
From the obtained values,
32 > 25
Hence, from the above,
We can conclude that 25 is greater than 52

Question 35.
Critique Reasoning Kristen was asked to write each of the numbers in the expression 80,000 × 25 using exponents. Her response was (8 × 103) × 52. Was Kristen’s response correct? Explain.
Answer:
It is given that
Kristen was asked to write each of the numbers in the expression 80,000 × 25 using exponents. Her response was (8 × 103) × 52
Now,
The given expression is: 80,000 × 25
Now,
80,000 × 25 = 8 × 10,000 × 25
= 2³ × 10,000 × 5²
Now,
We know that,
10,000 = 104
So,
80,000 × 25 = 23 × 4 × 52
= (8 × 104) × 52
Hence, from the above,
We can conclude that
Kristen’s response was not correct

Question 36.
Consider the equation 1,000,000 = 106. Why is 10 used as the base to write 106?
Answer:
The given equation is: 1,000,000 = 106
Now,
We know that,
In base-10, each digit of a number can have an integer value ranging from 0 to 9 (10 possibilities) depending on its position. The places or positions of the numbers are based on powers of 10. Each number position is 10 times the value to the right of it, hence the term base-10
Hence, from the above,
We can conclude that
We used 10 as the base to write 106 because of the position and the possibilities

Question 37.
Isabella saved 2 nickels today. If she doubles the number of nickels she saves each day, how many days, including today, will it take her to save more than 500 nickels?
Answer:
It is given that
Isabella saved 2 nickels today and she doubles the number of nickels she saves each day,
So,
The number of nickels she saved today is: 2
The number of nickels she saved the second day is 4 (or) 2²
The number of nickels she saved the third day is 8 (or) 2³
So,
The pattern for the number of nickels she saves each day will be like
2, 2², 2³, …..
Now,
The number of days it will take for her to save more than 500 nickels is: 28
Hence, from the above,
We can conclude that
The number of days she will take to save more than 500 nickels each day is about 8 days

Assessment Practice

Question 38.
Select all expressions equivalent to 5 × 5 × 5 × 5.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 11 51 × 54
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 11 54
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 11 52 × 52
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 11 45
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 11 4(51)
Answer:
The given expression is: 5 × 5 × 5 × 5
Now,
The representation of the given expression in the form of an exponent is:
5 × 5 × 5 × 5 = 5² × 5²
= 54
Hence, from the above,
We can conclude that
All the expressions equivalent to 5 × 5 × 5 × 5 are:

Question 39.
Which expression is equivalent to \(\frac{1}{36}\)?
A. \(\frac{1}{3}\) × \(\frac{1}{6}\)
B. \(\frac{1}{4}\) × (\(\frac{1}{3}\))3
C. (\(\frac{1}{2}\))2 × (\(\frac{1}{3}\))2
D. \(\frac{1}{2}\) × \(\frac{1}{3}\) × \(\frac{1}{3}\) × \(\frac{1}{3}\)
Answer:
The given expression is: \(\frac{1}{36}\)
Now,
The representation of the givene xpression in various forms is:
\(\frac{1}{36}\) = (\(\frac{1}{6}\))²
= \(\frac{1}{9}\) × \(\frac{1}{4}\)
= (\(\frac{1}{3}\))² × (\(\frac{1}{2}\))²
Hence, from the above,
We can conclude that
The expression is equivalent to \(\frac{1}{36}\) is:

Lesson 3.2 Find Greatest Common Factor and Least Common Multiple

Solve & Discuss It!

ACTIVITY

Mark sets the dinner table every 2 days and dries the dishes every 3 days. If he sets the table on Day 2 and dries the dishes on Day 3, on what day would Mark first perform both chores on the same day?
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12
Answer:
It is given that
Mark sets the dinner table every 2 days and dries the dishes every 3 days and he sets the table on Day 2 and dries the dishes on Day 3
Now,
To find the days that Mark would perform both chores on the same day,
Find the common multiplies of 2 and 3
So,
The common multiples of 2 and 3 are: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60….
Hence, from the above,
We can conclude that
The days that Mark would perform both chores on the same day must be the multiple of 6

Look for Relationships What is the relationship between the chores that Mark does each day?
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.1
Answer:
The completed list of days and chores is:

Now,
From the above list,
We can observe that
For every day that is multiple of 2,
Mark sets the dinner table
For every day that is multiple of 3,
Mark dries the dishes
For every day that is both the multiple of 2 and 3,
Mark sets the dinner table and dries the dishes
Hence, from the above,
We can conclude that
The relationship between the chores Mark does each day is:
a. For every day that is multiple of 2,
Mark sets the dinner table
b. For every day that is multiple of 3,
Mark dries the dishes
c. For every day that is both the multiple of 2 and 3,
Mark sets the dinner table and dries the dishes

Focus on math practices
Generalize on what day will Mark do both chores on the same day again? How can you find on which days Mark does both chores without making a list?
Answer:
From the above problem,
We can observe that
The days that Mark would perform both chores on the same day must be the multiple of 6 i.e., the common multiple of both 2 and 3
Hence, from the above,
We can conclude that
The days that Mark would perform both chores on the same day must be the multiple of 6 i.e., the common multiple of both 2 and 3

VISUAL LEARNING

? Essential Question How can you write the prime factorization and find the greatest common factor and least common multiple of two numbers?
Answer:
The steps to Write Prime Factorization of Composite Numbers are:
a. Put a prime factor on the outside left and the result or quotient (the number of times it divides evenly) underneath.
b. Divide the quotient (the number underneath) by another prime number and keep doing this until the bottom number is a prime
Examples:

The steps to find the GCF of a set of numbers, using prime factorization are:
a. List the prime factors of each number.
b. Circle every common prime factor i.e., every prime factor that’s a factor of every number in the set.
c. Multiply all the circled numbers. The result is the GCF.
The steps to find the LCM using the prime factorization method are:
a. Find the prime factorization of each number.
b. Write each number as a product of primes, matching primes vertically when possible.
c. Bring down the primes in each column.
d. Multiply the factors to get the LCM.

Try It!
Find the prime factorization of 56. Start with the least prime factor.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.2
Answer:
The given number is: 56
Now,
By using the Prime factorization method,

So,

Hence, from the above,
We can conclude that
The prime factorization of 56 is: 2³ × 7

Convince Me! A number is greater than 2 and it has 2 as a factor. Is the number prime or composite? Explain.
Answer:
It is given that
A number is greater than 2 and it has 2 as a factor
Now,
We know that,
2 is both prime and composite. The definition of prime is a number whose two factors are one and itself. If it has two, it must be composite, because that is not one or itself
Now,
According to the given information,
One of the numbers that are greater than 2 and have 2 as a factor will be: 4
Now,
We know that,
4 has more than 2 factors
Hence, from the above,
We can conclude that
A number that is greater than 2 and has 2 as a factor is a “Composite number”

Try It!
Keesha has 24 beads to add equally to each bag. Can she still make 6 bags and have no supplies left over? Explain.
Answer:
It is given that
Keesha has 24 beads to add equally to each bag.
Now,
The GCF of 24 and 6 is:

Now,
We can say that
The highest number of bags Keesha can make is: 6 bags
Hence, from the above,
We can conclude that
Keesha can still make 6 bags and have no supplies leftover

Try It!
Use the GCF and the Distributive Property to find the sum of 12 and 36.
Answer:
The given numbers are: 12 and 36
Now,
Step 1:
The GCF of 12 and 36 is:

Step 2:
Write 12 and 36 as a product using the GCF as a factor
Now,
By using the Distributive Property,
12 + 36 = (12 × 1) + (12 × 3)
= 12 × (1 + 3)
= 12 × 4
= 48
Hence, from the above,
We can conclude that
The sum of 12 and 36 is: 48

Try It!
Grant also buys bottled water and juice pouches for the picnic. There are 12 bottles of water in each case and 10 juice pouches in each box. Grant wants to buy the least amount but still have as many bottles of water as juice pouches. How many of each should he buy? Explain.
Answer:
It is given that
Grant also buys bottled water and juice pouches for the picnic. There are 12 bottles of water in each case and 10 juice pouches in each box. Grant wants to buy the least amount but still have as many bottles of water as juice pouches
Now,
To find the number of bottles and juice pouches Grant bought,
Find the LCM of 12 and 10
Now,
The LCM of 12 and 10 is:

So,
The number of bottles Grant should buy = \(\frac{60}{12}\)
= 5 bottles
The number of juice pouches Grant should buy = \(\frac{60}{10}\)
= 6 juice pouches
Hence, from the above,
We can conclude that
The number of bottles Grant should buy is: 5 bottles
The number of juice pouches Grant should buy is: 6 juice pouches

KEY CONCEPT
The greatest common factor (GCF) of two numbers is the greatest number that is a factor of both numbers.
Factors of 12: 1, 2, 3, 4, 6, 12
Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40
2 and 4 are common factors of 12 and 40. 4 is the greatest common factor.
The GCF of 12 and 40 is 4.

The least common multiple (LCM) of two numbers is the least multiple, not including zero, common to both numbers. Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48 …
Multiples of 9: 9, 18, 27, 36, 45, 54 …
18 and 36 are common multiples of 6 and 9.
18 is the least common multiple.
The LCM of 6 and 9 is 18.

Do You Understand?

Question 1.
? Essential Question How can you write the prime factorization and find the greatest common factor and the least common multiple of two numbers?
Answer:
The steps to Write Prime Factorization of Composite Numbers are:
a. Put a prime factor on the outside left and the result or quotient (the number of times it divides evenly) underneath.
b. Divide the quotient (the number underneath) by another prime number and keep doing this until the bottom number is a prime
Examples:

The steps to find the GCF of a set of numbers, using prime factorization are:
a. List the prime factors of each number.
b. Circle every common prime factor i.e., every prime factor that’s a factor of every number in the set.
c. Multiply all the circled numbers. The result is the GCF.
The steps to find the LCM using the prime factorization method are:
a. Find the prime factorization of each number.
b. Write each number as a product of primes, matching primes vertically when possible.
c. Bring down the primes in each column.
d. Multiply the factors to get the LCM.

Question 2.
What are two different ways in which you can use prime factorization to find the prime factors of a number?
Answer:
There are two common ways to perform prime factorization. The first is called the “Prime Factor Tree”, and the second is known as the “Upside-Down Division”
An example of the Prime Factor Tree method is:

An example of the Upside Down Division method is:

Question 3.
Generalize Why is the GCF of two prime numbers always 1?
Answer:
GCF stands for Greatest Common Factor. Since 1 is a factor of every number, any two or more numbers have a GCF, because even if the numbers are prime, or if they don’t share any prime factors, then the GCF will be 1. If they do share any prime factors, then the GCF will be the product of those shared prime factors.

Question 4.
Construct Arguments In example 4, Grant finds applesauce that comes in packages of 8, but now he finds juice bottles in only packages of 3. Will the LCM change? Explain.
Answer:
It is given that
In example 4, Grant finds applesauce that comes in packages of 8, but now he finds juice bottles in only packages of 3
Now,
In Example 4,
We can observe that
Grant should buy 8 packages of juice bottles and 6 packages of applesauce
Now,
From the given information,
We can observe that
Instead of 6 packages of applesauce, there are only 3 packages of applesauce now
Now,
We know that,
Since 3 and 6 are multiples, the LCM will be the same as in Example 4
Hence, from the above,
We can conclude that
The LCM will not change

Question 5.
Critique Reasoning Sarah says that you can find the LCM of any two whole numbers by multiplying them together. Provide a counterexample to show that Sarah’s statement is incorrect.
Answer:
We know that,
“LCM” means the “Lowest Common Multiple”
Now,
To find the LCM of the two whole numbers means finding the least common multiple of the two whole numbers
Example:
Find the LCM of 30 and 40
Now,
30 × 40 = 1,200
But,
1,200 is not the LCM of 30 and 40
Now,
The LCM of 30 and 40 are:

Hence, from the above,
We can conclude that
Sarah’s statement is incorrect

Do You Know How?

In 6-8, write the prime factorization of each number. If the number is prime, write prime.

Question 6.
33
Answer:
The given number is: 33
So,
The representation of the factors for the given number using the prime factorization method is:

Hence, from the above,
We can conclude that
The factors for the given number using the Prime factorization method is:
33 = 3 × 11

Question 7.
32
Answer:
The given number is: 32
So,
The representation of the factors for the given number using the prime factorization method is:

Hence, from the above,
We can conclude that
The factors for the given number using the Prime factorization method is:
32 = 2 × 2 × 2 × 2 × 2

Question 8.
19
Answer:
The given number is: 19
Now,
We know that,
19 has the factors of 1 and itself
Hence, from the above,
We can conclude that the given number is a prime number

In 9-11, find the GCF for each pair of numbers.

Question 9.
18, 36
Answer:
The given numbers are: 18, 36
Now,

Hence, from the above,
We can conclude that
The GCF of 18 and 36 is: 18

Question 10.
22, 55
Answer:
The given numbers are: 22, 55
Now,

Hence, from the above,
We can conclude that
The GCF of 22 and 55 is: 11

Question 11.
100, 48
Answer:
The given numbers are: 100, 48
Now,

Hence, from the above,
We can conclude that
The GCF of 100 and 48 is: 4

In 12-14, find the LCM for each pair of numbers.

Question 12.
2, 5
Answer:
The given numbers are: 2, 5
Now,

Hence, from the above,
We can conclude that
The LCM of 2 and 5 is: 10

Question 13.
8, 12
Answer:
The given numbers are: 8, 12
Now,

Hence, from the above,
We can conclude that
The LCM of 8 and 12 is: 24

Question 14.
8, 10
Answer:
The given numbers are: 8, 10
Now,

Hence, from the above,
We can conclude that
The LCM of 8 and 10 is: 40

Practice & Problem Solving

Leveled Practice
In 15-18, find the prime factorization of each number. If it is prime, write prime.

Question 15.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.3
Answer:
The given number is: 27
Now,
The representation of the factors for the given number using the Prime factorization method is:

Hence, from the above,
We can conclude that
The factors of 27 by using the Prime Factorization method is: 3 × 3 × 3

Question 16.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.4
Answer:
The given number is: 30
Now,
The representation of the factors for the given number using the Prime factorization method is:

Hence, from the above,
We can conclude that
The factors of 30 by using the Prime Factorization method is: 2 × 3 × 5

Question 17.
26
Answer:
The given number is: 26
Now,
The representation of the factors for the given number using the Prime factorization method is:

Hence, from the above,
We can conclude that
The factors of 26 by using the Prime Factorization method is: 2 × 13

Question 18.
47
Answer:
The given number is: 47
Now,
We know that,
47 has factors of 1 and only itself
Hence, from the above,
We can conclude that
47 is a prime number

In 19-21, find the GCF for each pair of numbers.

Question 19.
21, 49
Answer:
The given numbers are: 21, 49
Now,

Hence, from the above,
We can conclude that GCF of 21, 49 is: 7

Question 20.
8, 52
Answer:
The given numbers are: 8, 52
Now,

Hence, from the above,
We can conclude that GCF of 8, 52 is: 4

Question 21.
32, 81
Answer:
The given numbers are: 32, 81
Now,

Hence, from the above,
We can conclude that GCF of 32, 81 is: 1

In 22-24, use the GCF and the Distributive Property to find each sum.

Question 22.
30 + 66
Answer:
The given expression is: 30 + 66
Now,
Step 1: Find the GCF of 30 and 66
So,

So,
The GCF of 30 and 66 is: 6
Step 2: Write each number as a product using GCF as a factor
So,
30 + 66 = (6 × 5) + (6 × 11)
= 6 × (5 + 11)
= 6 × 16
= 96
Hence, from the above,
We can conclude that
The sum of 30 and 66 is: 96

Question 23.
34 + 51
Answer:
The given expression is: 34 + 51
Now,
Step 1: Find the GCF of 34 and 51
So,

So,
The GCF of 34 and 51 is: 17
Step 2: Write each number as a product using GCF as a factor
So,
34 + 51 = (17 × 2) + (17 × 3)
= 17 × (2 + 3)
= 17 × 5
= 85
Hence, from the above,
We can conclude that
The sum of 34 and 51 is: 85

Question 24.
15 + 36
Answer:
The given expression is: 15 + 36
Now,
Step 1: Find the GCF of 15 and 36
So,

So,
The GCF of 15 and 36 is: 3
Step 2: Write each number as a product using GCF as a factor
So,
15 + 36 = (3 × 5) + (3 × 12)
= 3 × (5 + 12)
= 3 × 17
= 51
Hence, from the above,
We can conclude that
The sum of 15 and 36 is: 51

In 25-27, find the LCM for each pair of numbers.

Question 25.
12, 11
Answer:
The given numbers are: 12, 11
Now,

Hence, from the above,
We can conclude that
The LCM of 12 and 11 is: 132

Question 26.
4, 12
Answer:
The given numbers are: 4, 12
Now,

Hence, from the above,
We can conclude that
The LCM of 4 and 12 is: 12

Question 27.
5, 8
Answer:
The given numbers are: 5, 8
Now,

Hence, from the above,
We can conclude that
The LCM of 5 and 8 is: 40

Question 28.
Critique Reasoning Gabrielle and John each wrote the prime factorization of 64. Analyze their work and explain any errors.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.6
Answer:
It is given that
Gabrielle and John each wrote the prime factorization of 64
Now,
According to Gabrielle,
The factors of 64 by using the Prime factorization method is:

So,
The representation of factors of 64 using the Prime factorization method is:
64 = 2 × 2 × 2 × 2 ×2 × 2 = 26
Now,
According to John,
The factors of 64 are:
64 = 2 × 32
= 2 × 2 ×16
= 2 × 2 × 2 × 8
= 2 × 2 × 2 × 2 × 4
= 2 × 2 × 2 × 2 × 2 × 2
Hence, from the above,
We can conclude that
There are no errors in Gabriel’s and John’s work

Question 29.
To celebrate its grand opening, a store is giving customers gift certificates. Which customer is the first to get two gift certificates?
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.7
Answer:
It is given that
To celebrate its grand opening, a store is giving customers gift certificates.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.7
Now,
To find the customer who is the first that will get two gift certificates,
Find the LCM of 6 and 8
Now,

Hence, from the above,
We can conclude that
The 24th customer is the first to get the two gift certificates

Question 30.
A Model with Math
The Venn diagram at the right shows the factors of 24 and 40.
a. What is the meaning of each of the three shaded regions?
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.8
Answer:
The given numbers are: 24 and 40
Now,
The given Venn diagram is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.8
Now,
From the given Venn diagram,
We can observe that
The left side region of the Venn diagram shows: The factors of 24
The right side region of the Venn diagram shows: The factors of 40
The midle region of the Venn diagram shows: The common factors of 24 and 40
Hence, from the above,
We can conclude that
The meaning of the shaded regions is:
The left side region of the Venn diagram shows: The factors of 24
The right side region of the Venn diagram shows: The factors of 40
The midle region of the Venn diagram shows: The common factors of 24 and 40

b. Explain how you use the Venn diagram to find the GCF of 24 and 40. What is the GCF of 24 and 40?
Answer:
The given Venn diagram is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 12.8
Now,
We know that,
The GCF of the two numbers can be find out by identifying the highest factor in the common factors of a and b
So,
In he given Venn diagram,
The middle region represents the common factors of 24 and 40
In the common factors of 24 and 40, 8 is the highest factor
Hence, from the above,
We can conclude that
The GCF of 24 and 40 is: 8

Question 31.
Reasoning You have 50 blueberry scones and 75 cranberry scones. You want to make as many identical bags as possible. Each bag should have an equal number of blueberry scones and an equal number of cranberry scones. What is the greatest number of bags you can fill? Explain.
Answer:
It is given that
You have 50 blueberry scones and 75 cranberry scones. You want to make as many identical bags as possible. Each bag should have an equal number of blueberry scones and an equal number of cranberry scones
Now,
To find the greatest number of bags that you can fill an equal number of blueberry scones and cranberry scones,
Find the GCF of 50 and 75
Now,

Hence, from the above,
We can conclude that
The greatest number of blueberry scones bags and cranberry scones bags that you can fill is: 25 bags

Question 32.
Make Sense and Persevere The prime factorizations of A and B are shown. Find the value of n that needs to be listed as a prime factor of B so that the greatest common factor (GCF) of A and B is 9.
Prime factorization of A: 3 × 3 × 3
Prime factorization of B: 2 × 2 × 3 × n
Answer:
It is given that
The prime factorizations of A and B are shown and the greatest common factor (GCF) of A and B is 9.
Now,
The given prime factorizations of A and B are:
Prime factorization of A: 3 × 3 × 3
Prime factorization of B: 2 × 2 × 3 × n
Now,
To make GCF of A and B to be 9,
The numbers must be 27 and 36
Now,
27 = 3 × 3 × 3
36 = 2 × 2 × 3 × 3
So,
The missing number is: 3
Hence, from the above,
We can conclude that
The value of n is: 3

Question 33.
Higher-Order Thinking Gena has 28 trading cards, Sam has 91 trading cards, and Tiffany has 49 trading cards. Use the GCF and the Distributive Property to find the total number of trading cards Gena, Sam, and Tiffany, have.
Answer:
It is given that
Gena has 28 trading cards, Sam has 91 trading cards, and Tiffany has 49 trading cards.
Now,
To find the total number of trading cards Gena, Sam, and Tiffany have, the following steps that used to solve are:
Step 1: Find the GCF of 28, 91, and 49
So,

So,
The GCF of 28, 91, and 49 is: 7
Step 2: Write each number as a product using the GCF as a factor
So,
28 + 91 + 49 = (7 × 4) + (7 × 13) + (7 × 7)
= 7 × (4 + 13 + 7)
= 7 × 24
= 168 trading cards
Hence, from the above,
We can conclude that
The total number of trading cards Gena, Sam, and Tiffany have is: 168 trading cards

Question 34.
Periodical cicada species emerge in large numbers from their larval stage at different yearly intervals. What is the GCF of the years?
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.6
Answer:
It is given that
Periodical cicada species emerge in large numbers from their larval stage at different yearly intervals.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.6
Now,
From the given figure,
We can observe that
The two years are: 13 years and 17 years
Now,
The GCF of 13 and 17 is:

Hence, from the above,
We can conclude that
The GCF of the given years is: 1

Question 35.
People are waiting in line for a theater premiere. Every 5th person in line will receive a free theater ticket. Every 6th person will receive a gift card for $40. Which person is the first to receive both prizes?
Answer:
It is given that
People are waiting in line for a theater premiere. Every 5th person in line will receive a free theater ticket. Every 6th person will receive a gift card for $40
Now,
To find the person who is the first to receive both prizes,
Find the LCM of 5 and 6
Now,

Hence, from the above,
We can conclude that
The 30th person is the first to receive both prizes

Question 36.
Two volunteer groups plant trees. Group A plants the trees in clusters of 3. Group B plants the trees in clusters of 10. Both groups plant the same number of trees. What is the least number of clusters that Group B plants?
Answer:
It is given that
Two volunteer groups plant trees. Group A plants the trees in clusters of 3. Group B plants the trees in clusters of 10. Both groups plant the same number of trees
Now,
To find the least number of clusters that Group B plants,
Find the LCM of 3 and 10
Now,

Hence, from the above,
We can conclude that
The least number of clusters that Group B plants is: 30 clusters

Question 37.
Find the LCM of the two numbers. Then use the LCM to find the corresponding letter in the key. Write that letter in the box. What word did you decode?
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.7
Answer:
The given data is:

Now,
a.
The LCM of 2 and 3 is:

So,
The LCM of 2 and 3 is: 6
The letter that corresponds to the LCM of 2 and 3 is: F
b.
The LCM of 3 and 7 is:

So,
The LCM of 3 and 7 is: 21
The letter that corresponds to the LCM of 3 and 7 is: U
c.
The LCM of 2 and 7 is:

So,
The LCM of 2 and 7 is: 14
The letter that corresponds to the LCM of 2 and 7 is: N
So,
The word did you decode is: FUN
Hence, from the above,
We can conclude that

The word you decoded is: FUN

Question 38.
Rami has swimming lessons every 3 days and guitar lessons every 8 days. If he has both lessons on the first day of the month, in how many days will Rami have both lessons on the same day again?
Answer:
It is given that
Rami has swimming lessons every 3 days and guitar lessons every 8 days and he has both lessons on the first day of the month
Now,
To find the number of days will Rami have both lessons on the same day again,
Find the LCM of 3 and 8
Now,

Hence, from the above,
We can conclude that
In 24 days, Rami will have both lessons on the same day again

Question 39.
A number is between 58 and 68. It has prime factors of 2, 3, and 5. What is the number?
Answer:
It is given that
A number is between 58 and 68. It has prime factors of 2, 3, and 5
Now,
Let the number that has the given prime factors be x
Now,
If x has the prime factor of 5, then it must be a multiple of 5
So,
The multiples of 5 between 58 and 68 are: 60, 65
Now,
The factors of 65 using the Prime Factorization method are:
65 = 5 × 13
The factors of 60 using the Prime Factorization method are:
60 = 2 × 30
= 2 × 2 × 15
= 2 × 2 × 3 × 5
So,
60 has the prime factors of 2, 3, and 5 as given
Hence, from the above,
We can conclude that
The number that is between 58 and 68 and has the prime factors 2, 3, and 5 is: 60

Question 40.
A college offers shuttle service from Dickson Hall or Lot B to its campus quad. Both shuttles first depart their locations at 9:10 A.M. They run from each location to campus and back at the intervals shown. When is the next time both shuttles will depart for the campus at the same time? Explain.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.8
Answer:
It is given that
A college offers shuttle service from Dickson Hall or Lot B to its campus quad. Both shuttles first depart their locations at 9:10 A.M. They run from each location to campus and back at the intervals shown.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.8
Now,
From the given figure,
We can observe that
The shuttle departs every 10 minutes from Lot B
The shuttle departs every 12 minutes from Dickson Hall
Now,
To find the next time both shuttles will depart for the campus at the same time,
Find the LCM of 10 and 12
Now,

Now,
We know that,
1 hour = 60 minutes
So,
The next time both shuttles will depart from the campus at the same time = (The first time both shuttles departed from the campus at the same time) + 1 hour
= 9:10 A.M + 1 hour
= 10:10 A.M
Hence, from the above,
We can conclude that
The next time both shuttles will depart from the campus at the same time is: 10:10 A.M

Assessment Practice

Question 41.
Match each pair of numbers with the pair(s) of numbers that have the same LCM.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.9
Answer:
The given pairs of numbers are: (6, 9), (3, 4), (6, 12), (2, 9), (3, 9), (4, 6), and (9, 12)
Now,
The LCMs of the given pairs of numbers are:
The LCM of 6 and 9 is: 18
The LCM of 3 and 4 is: 12
The LCM of 6 and 12 is: 12
The LCM of 2 and 9 is: 18
The LCM of 3 and 9 is: 9
The LCM of 4 and 6 is: 12
The LCM of 9 and 12 is: 36
Hence, from the above,
We can conclude that
The matched pair of numbers with the pair of numbers that has the same LCM is:

Question 42.
Which expression is equivalent to 48 + 60?
A. 12(4 + 5)
B. 12(8 + 5)
C. 6(6 + 10)
D. 6(8 + 12)
Answer:
The given expression is: 48 + 60
Now,
Step 1: Find the GCF of 48 and 60
So,

Step 2: Write each number as a product by using the GCF as a factor
So,
48 + 60 = (12 × 4) + (12 × 5)
= 12 × (4 + 5)
Hence, from the above,
We can conclude that
The expression that is equivalent to 48 + 60 is:

Lesson 3.3 Write and Evaluate Numerical expressions

Solve & Discuss It!

ACTIVITY
An airline company charges additional fees for bags that do not meet the weight and size limits. For one flight, fees were charged for a total of 50 bags that were over the weight limit and 6 oversized bags. Find the total amount of fees collected for that flight.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.10
Look for Relationships You can use the order of operations to evaluate numerical expressions.
Answer:
It is given that
An airline company charges additional fees for bags that do not meet the weight and size limits. For one flight, fees were charged for a total of 50 bags that were over the weight limit and 6 oversized bags.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.10
So,
The total amount of fees collected for the given flight = (The total number of overweight bags) × (The extra fees for each overweight bag) + (The total number of oversized bags) × (The extra fees for each oversized bag)
= (50 × $49) + (6 × $75)
Now,

Hence, from the above,
We can conclude that
The total amount of fees collected for the given flight is: $2900

Focus on math practices
A Model with Math
Tamara was charged for two bags that were over the weight limit and another bag that was over the size limit. Write and evaluate a numerical expression to find the additional fees Tamara was charged for her bags.
Answer:
It is given that
Tamara was charged for two bags that were over the weight limit and another bag that was over the size limit.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.10
So,
The total additional fees Tamara charged for her bags = (The total number of overweight bags) × (The extra fees for each overweight bag) + (The total number of oversized bags) × (The extra fee for each oversized bag)
= (2 × $49) + (1 × $75)
Now,

Hence, from the above,
We can conclude that
The total additional fees Tamara charged for her bags is: $173

VISUAL LEARNING

? Essential Question How do you write and evaluate numerical expressions?
Answer:
We write a numerical expression by using numbers and mathematical operators which are addition, subtraction, multiplication, and division.
Example:
The expression of the mathematical statement “4 added to 2”, will be 2+4.
To evaluate a numerical expression means to find the value of the expression by using the order of operations. To evaluate an expression, we follow the rules of the order of operations in the expression and then simplify the expression using the order of operations.

Scan for Multimedia

Try It!
Evaluate the numerical expression at the right.
Envision Math Common Core Grade 6 Answer Key Topic 3 Numeric And Algebraic Expressions 15.11
Answer:
The given numerical expression is: \(\frac{1}{8}\) [6³ + (48 ÷ 6)] – 20
Now,

Hence, from the above,
We can conclude that
The value of the given numerical expression is: 8

Convince Me! Why is it important to follow the order of operations?
Answer:
The order of operations is a rule that tells you the right order in which to solve different parts of a math problem. Subtraction, multiplication, and division are all examples of operations. The order of operations is important because it guarantees that people can all read and solve a problem in the same way

Try It!
A. Evaluate the numerical expression: 3.22 – [(9 × 4) + 9] × (\(\frac{1}{3}\))2?
Answer:
The given numerical expression is: 3.22 – [(9 × 4) + 9] × (\(\frac{1}{3}\))2
Now,

Hence, from the above,
We can conclude that
The value of the given numerical expression is: 5.24

B. Insert grouping symbols so that the numerical expression has a value of 80.
6 + 12 × (\(\frac{2}{3}\))2 × 3 + 7
Answer:
The given expression is:
6 + 12 × (\(\frac{2}{3}\))2 × 3 + 7
Now,
It is given that
The value of the given expression is: 80
Now,
Case 1:
6 + 12 × (\(\frac{2}{3}\))² × (3 + 7)
= 6 + 12 × \(\frac{4}{9}\) × 10
= 6 + \(\frac{160}{3}\)
= 6 + 53
= 59
Case 2:
(6 + 12) × (\(\frac{2}{3}\))² × (3 + 7)
= 18 × \(\frac{4}{9}\) × 10
= 2 × 4 ×10
= 8 × 10
= 80
Hence, from the above,
We can conclude that
The complete numerical expression with inserted grouping symbols and has a value of 80 is:
(6 + 12) × (\(\frac{2}{3}\))² × (3 + 7)

KEY CONCEPT
The order of operations is a set of rules used to evaluate expressions that include more than one operation.

Order of Operations

1 Evaluate inside grouping symbols,
such as parentheses or brackets.
2 Evaluate powers.
3 Multiply or divide from left to right.
4 Add or subtract from left to right.

Do You Understand?

Question 1.
? Essential Question How do you write and evaluate numerical expressions?
Answer:
We write a numerical expression by using numbers and mathematical operators which are addition, subtraction, multiplication, and division.
Example:
The expression of the mathematical statement “4 added to 2”, will be 2+4.
To evaluate a numerical expression means to find the value of the expression by using the order of operations. To evaluate an expression, we follow the rules of the order of operations in the expression and then simplify the expression using the order of operations.

Question 2.
Make Sense and Persevere Explain why grouping symbols can change the value of a numerical expression. Then insert grouping symbols to show four different values for the following expression. 80 ÷ 8 × 5 + 4
Answer:
We know that,
“Grouping symbols” are used in math to show a part of a math expression or equation that must be solved first, before any other calculations are done. The part between the two grouping symbols is treated like one number. Operations inside grouping symbols can be done before any other operations in order to simplify the problem
The position of grouping symbols decide the single value of the numerical expression based on the order of operations
Now,
The given expression is: 80 ÷ 8 × 5 + 4
Case 1:
The given expression with the grouping symbols is: (80 ÷ 8) × 5 + 4
So,

Case 2:
The given expression with the grouping symbols is: 80 ÷ (8 × 5) + 4
So,

Case 3:
The given expression with the grouping symbols is: 80 ÷ 8 × (5 + 4)
So,

Case 4:
The given expression with the grouping symbols is: 80 ÷ (8 × (5 + 4))
So,

Question 3.
In the expression (21 – 3) × (7 + 2) ÷ (12 – 4), what operation should you perform last? Explain.
Answer:
The given expression is:
(21 – 3) × (7 + 2) ÷ (12 – 4)
To decide the order of operation,
We will follow BODMAS RULE
Where,
B – Brackets (or) Grouping symbols
O – Of
D – Division
M – Multiplication
A – Addition
S – Subtraction
Hence, from the above,
We can conclude that
The operation you should perform last for the given expression is: Multiplication

Question 4.
Critique Reasoning Charles says that 2 × 3 – 2 is 4, and Seth says that 2 × 3 – 2 is 2. Who is correct? Explain.
Answer:
It is given that
Charles says that 2 × 3 – 2 is 4, and Seth says that 2 × 3 – 2 is 2.
Now,
We know that,
To decide the order of operation,
We will follow BODMAS RULE
Where,
B – Brackets (or) Grouping symbols
O – Of
D – Division
M – Multiplication
A – Addition
S – Subtraction
So,
According to Charles:
The expression is: 2 × 3 – 2
So,
(2 × 3) – 2
= 6 – 2
= 4
According to Seth:
The expression is: 2 × 3 – 2
So,
2 × (3 – 2)
= 2 × 1
= 2
Hence, from the above,
We can conclude that
Charles is correct since he followed the order of operations correctly

Do You Know How?

In 5-9, evaluate each expression.

Question 5.
52 + (6.7 – 3.1)
Answer:
The given expression is: 52 + (6.7 – 3.1)
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 28.6

Question 6.
(8.2 + 5.3) ÷ 5
Answer:
The given expression is: (8.2 + 5.3) ÷ 5
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 2.7

Question 7.
(1.5 – 0.52) ÷ [(3 + 2) × 2]
Answer:
The given expression is: (1.5 – 0.52) ÷ [(3 + 2) × 2]
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 0.125

Question 8.
36.8 ÷ [11.5 – (2.5 × 3)]2
Answer;
The given expression is: 36.8 ÷ [11.5 – (2.5 × 3)]2
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 2.3

Question 9.
6 + 4 × 5 ÷ 2 – 8 × 1.5
Answer:
The given expression is: 6 + 4 × 5 ÷ 2 – 8 × 1.5
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 4

In 10-12, insert grouping symbols so that the expression has the given value.

Question 10.
12 × 32 + 36 Target value: 540
Answer:
The given expression is: 12 × 32 + 36
Now,
It is given that
The value of the given expression is: 540
Now,
Case 1:
12 × 32 + 36
= (12 × 32 ) + 36
= (12 × 9) + 36
= 108 + 36
= 144
Case 2:
12 × 3² + 36
= 12 × (3² + 36)
= 12 × (9 + 36)
= 12 × 45
= 540
Hence, from the above,
We can conclude that
The representation of the given expression with the grouping values and a target value of 540 is:
12 × (3² + 36)

Question 11.
32 ÷ 23 – 4 Target value: 8
Answer:
The given expression is: 32 ÷ 23 – 4
Now,
It is given that
The value of the given expression is: 8
Now,
Case 1:
32 ÷ 2³ – 4
= (32 ÷ 2³) – 4
= (32 ÷ 8) – 4
= 4 – 4
= 0
Case 2:
32 ÷ 2³ – 4
= 32 ÷ (2³  – 4)
= 32 ÷ (8 – 4)
= 32 ÷4
= 8
Hence, from the above,
We can conclude that
The representation of the given expression with the grouping values and a target value of 8 is:
32 ÷ (2³ – 4)

Question 12.
2.32 + 9 × 4 ÷ 2 Target value: 28.58
Answer:
The given expression is: 2.32 + 9 × 4 ÷ 2
Now,
It is given that
The value of the given expression is: 28.58
Now,
Case 1:
2.32 + 9 × 4 ÷ 2
= 2.32 + (9 × 4) ÷ 2
= 2.32 + (36) ÷ 2
= 2.32 + 18
= 23.29
Case 2:
2.32 + 9 × 4 ÷ 2
= (2.32 + 9 × 4) ÷ 2
= (5.29 + 36) ÷ 2
= 20.64
Case 3:
2.32 + 9 × 4 ÷ 2
= (2.32 + 9) × (4 ÷ 2)
= 14.29 × 2
= 28.58
Hence, from the above,
We can conclude that
The representation of the given expression with the grouping values and a target value of 28.58 is:
(2.32 + 9) × (4 ÷ 2)

Practice & Problem Solving
Leveled Practice
In 13-18, use the order of operations to evaluate.

Question 13.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 20.1
Answer:
The given expression is: 4² – (3.1 + 6.4) + 4.5
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 11

Question 14.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 20.2
Answer:
The given expression is: (8.7 + 3.3) × (\(\frac{1}{2}\))²
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 3

Question 15.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 20.3
Answer:
The given expression is: 157.8 – (3² + 6) × 3
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 112.8

Question 16.
4.3 + (8.4 – 5.1)
Answer:
The given expression is: 4.3 + (8.4 – 5.1)
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 7.6

Question 17.
1.25 × 4 + 3 × 2 ÷ (\(\frac{1}{2}\))3
Answer:
The given expression is: 1.25 × 4 + 3 × 2 ÷ (\(\frac{1}{2}\))3
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 29

Question 18.
[23 × (152 ÷ 8)] – 52
Answer:
The given expression is: [23 × (152 ÷ 8)] – 52
So,

Hence, from the above,
We can conclude that
The value of the given expression is: 100

In 19-21, insert grouping symbols so that the expression has the given value.

Question 19.
Target value: 32
2 × 9 + 7
Answer:
The given expression is: 2 × 9 + 7
Now,
It is given that
The value of the given expression is: 32
Now,
Case 1:
2 × 9 + 7
= (2 × 9) + 7
= 18 + 7
= 25
Case 2:
2 × 9 + 7
= 2 × (9 + 7)
= 2 × 16
= 32
Hence, from the above,
We can conclude that
The representation of the given expression with the grouping values and a target value of 32 is:
2 × (9 + 7)

Question 20.
Target value: 6
\(\frac{1}{3}\) × 21 – 3
Answer:
The given expression is: \(\frac{1}{3}\) × 21 – 3
Now,
It is given that
The value of the given expression is: 6
Now,
Case 1:
\(\frac{1}{3}\) × 21 – 3
= (\(\frac{1}{3}\) × 21) – 3
= 7 – 3
= 4
Case 2:
\(\frac{1}{3}\) × 21 – 3
= \(\frac{1}{3}\) × (21 – 3)
= \(\frac{1}{3}\) × 18
= 6
Hence, from the above,
We can conclude that
The representation of the given expression with the grouping values and a target value of 6 is:
\(\frac{1}{3}\) × (21 – 3)

Question 21.
Target value: 43
2.5 + 5 × 6 – 2
Answer:
The given expression is: 2.5 + 5 × 6 – 2
Now,
It is given that
The value of the given expression is: 43
Now,
Case 1:
2.5 + 5 × 6 – 2
= (2.5 + 5) × (6 – 2)
= 7.5 × 4
= 30
Case 2:
2.5 + 5 × 6 – 2
= [(2.5 + 5) × 6] – 2
= (7.5 × 6) – 2
= 45 – 2
= 43
Hence, from the above,
We can conclude that
The representation of the given expression with the grouping values and a target value of 43 is:
[(2.5 + 5) × 6] – 2

Question 22.
Cory bought some baseball equipment. He used a coupon for \(\frac{1}{2}\) off the price of the bat and glove. Write and evaluate a numerical expression to find the total cost of the bat, the glove, and
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 25.1
Answer:
It is given that
Cory bought some baseball equipment. He used a coupon for \(\frac{1}{2}\) off the price of the bat and glove
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 25.1
Now,
From the given information,
The new cost of the bat will become \(\frac{1}{2}\) of the old price of the bat
The new cost of the glove will become \(\frac{1}{2}\) of the old price of the glove
So,
The total cost of the bat, the glove and 3 baseballs = (The new cost of the bat) + (The new cost of the glove) + (3 × The cost of the baseball)
= \(\frac{$69}{2}\) + \(\frac{$75}{2}\) + (3 × $5.50)
= \(\frac{1}{2}\) (69 + 75) + (3 × $5.50)
= \(\frac{$144}{2}\) + $16.50
= $72 + $16.50
= $88.50
Hence, from the above,
We can conclude that
The total cost of the bat, the glove, and 3 baseballs is: $88.50

Question 23.
Make Sense and Persevere Write a numerical expression, with at least three operations, that has the same value as the following expression. Justify your answer.
5 + (8 – 4) ÷ 2 + 3
Answer:
The given expression is: 5 + (8 – 4) ÷ 2 + 3
Now,

So,
The value of the given expression is: 10
Now,
The expression that has the same value as the given expression and has at least 3 operations is:
(5 × 2) + 4 – (36 ÷ 9)

Question 24.
Use Structure How do you know which part of the numerical expression to evaluate first? Explain.
(26 + 2.5) – [(8.3 × 3) + (13 – 0.25)]
Answer:
The given expression is:
(26 + 2.5) – [(8.3 × 3) + (13 – 0.25)]
Now,
To solve an expression,
We will use the order of operations using the BODMAS rule and solve the part of the expression that involves more operations in it
So,
In the given expression,
We have to first evaluate [(8.3 × 3) + (13 – 0.25)]
Hence, from the above,
We can conclude that
By using the order of operations using the BODMAS rule and the part of the expression that involves more operations in it,
We have to first evaluate [(8.3 × 3) + (13 – 0.25)]

Question 25.
Construct Arguments Evan says that the value of the numerical expression 0.22 + 12 ÷ (1.5 × 4) is 32.04. Do you agree? Explain.
Answer:
The given expression is: 0.22 + 12 ÷ (1.5 × 4)
So,

But,
For the given expression,
It is given that the value is: 32.04
But,
We got the value of the expression as 2.04
Hence, from the above,
We can conclude that
We can not agree with Evan

Question 26.
The width of the rectangular drawing is one-third the length plus 3 inches. What is the perimeter of the drawing? Write and evaluate an expression to solve the problem.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 20.6
Answer:
It is given that
The width of the rectangular drawing is one-third the length plus 3 inches.
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 20.6
Now,
From the given figure,
We can observe that
The length of the rectangular drawing is 12 in.
Now,
According to the given information,
The width of the rectangular drawing = (The length of the rectangular drawing ÷ 3) + 3
= \(\frac{12}{3}\) + 3
= 4 + 3
= 7 in.
Now,
We know that,
The perimeter of a rectangle = 2 × (Length + Width)
So,
The perimeter of a rectangular drawing = 2 × (12 + 7)
= 2 × 19
= 38 in.
Hence, from the above,
We can conclude that
The perimeter of the rectangular drawing is 38 in.

Question 27.
Higher-Order Thinking Frederick evaluates the numerical expression [(53.7 + 37.2) – (33 + 3.8)] – 8.6 and records the answer as 51.5. Lana evaluates the numerical expression 53.7 + 37.2 – 33 + 3.8 – 8.6 and records the answer as 59.1. The expressions have the same numbers and operations. Explain how Frederick and Lana can both be correct.
Answer:
It is given that
Frederick evaluates the numerical expression [(53.7 + 37.2) – (33 + 3.8)] – 8.6 and records the answer as 51.5. Lana evaluates the numerical expression 53.7 + 37.2 – 33 + 3.8 – 8.6 and records the answer as 59.1. The expressions have the same numbers and operations
Now,
According to Fredrick:
The given expression is: [(53.7 + 37.2) – (33 + 3.8)] – 8.6
So,

Now,
According to Lana:
The given expression is: 53.7 + 37.2 – 33 + 3.8 – 8.6
So,

Now,
From both answers,
We can observe that
Even though the operations and the numbers are the same, the only difference between the expressions is the grouping symbols
Hence, from the above,
We can conclude that
Both Fredrick and Lana are correct and the only difference between their expressions is the grouping of symbols

Question 28.
Model with Math
Lillian went to the gift shop on the boardwalk and bought four bags of dyed seashells at $3.99 each. She had a coupon for $1 off. Her mom paid for half of the remaining cost. Write and evaluate a numerical expression to find how much Lillian paid toward the purchase of the seashells.
Answer:
It is given that
Lillian went to the gift shop on the boardwalk and bought four bags of dyed seashells at $3.99 each. She had a coupon for $1 off. Her mom paid for half of the remaining cost.
Now,
The cost of 4 bags of dyed seashells = 4 × (The cost of each bag of dyed seashells)
= 4 × $3.99
= $15.96
Now,
It is given that
She had a coupon for $1 off
So,
The amount Lilian paid to purchase 4 bags of dyed seashells = $15.96 – $1
= $14.96
Now,
It is given that
Lilian’s mom paid for half of the remaining cost
So,
The amount Lilian’s mom paid = \(\frac{$14.96}{2}\)
= $7.48
So,
The  total amount Lilian paid toward the purchase of the seashells = $14.96 – $7.48
= $7.48
Hence, from the above,
We can conclude that
The total amount Lilian paid toward the purchase of the seashells is: $7.48

Question 29.
In an ecosystem, some animals get energy by eating plants. Write and evaluate an expression to find how many pounds of plants a herd of 18 elk can eat in one week.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 20.7
Answer:
It is given that
In an ecosystem, some animals get energy by eating plants
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 20.7
Now,
We know that,
1 week = 7 days
So,
The number of pounds of plants a herd of 18 elk can eat in one week = (The number of elks) × (The number of pounds of plants an elk eats each day) × (The number of days in a  week)
= (18 × 20 × 7) pounds
= (126 × 20) pounds
= 2,520 pounds
Hence, from the above,
We can conclude that
The number of pounds of plants a herd of 18 elk can eat in one week is: 2,520 pounds

Assessment Practice

Question 30.
Select all expressions that are equivalent to 24 ÷ [(3.2 × 0.8) + 1.44].
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 21 24 ÷ [(4 × 0.64) + 1.44]
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 21 16 ÷ [(22 × 0.64) + (0.72 × 2)]
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 21 8 ÷ [(3.2 × 0.8) + (0.48 × 3)]
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 21 24 ÷ [2.56 + (0.48 × 4)]
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 21 42 ÷ [2.56 + (0.48 × 4)]
Answer:
The given expression is: 24 ÷ [(3.2 × 0.8) + 1.44]
So,

Now,
The given expressions and its values are:
A.  24 ÷ [(4 × 0.64) + 1.44] = 4
B.  16 ÷ [(22 × 0.64) + (0.72 × 2)] = 4
C.  8 ÷ [(3.2 × 0.8) + (0.48 × 3)] = 2
D.  24 ÷ [2.56 + (0.48 × 4)] = 3.57
E.  4² ÷ [2.56 + (0.48 × 4)] = 3.57
Hence, from the above,
We can conclude that
All expressions that are equivalent to 24 ÷ [(3.2 × 0.8) + 1.44] are:

Question 31.
Which value is equivalent to the expression 18.9 × [(2 × 2.7) – 4.6] – 22?
A. 1,112
B. 111.2
C. 11.12
D. 1.112
Answer:
The given expression is: 18.9 × [(2 × 2.7) – 4.6] – 22
So,

Hence, from the above,
We can conclude that
The value is equivalent to the expression 18.9 × [(2 × 2.7) – 4.6] – 2² is:

Topic 3 MID-TOPIC CHECKPOINT

Question 1.
Vocabulary Describe the relationship between the base and the exponent in 43. Lesson 3-1
Answer:
The given expression is: 4³
Now,
From the given expression,
We can observe that
“4” is called the “Base”
“3” is called the “Exponent”
Now,
We know that,
The number that is repeatedly multiplied is the “Base”
The “Exponent” tells how many times the Base is used as a factor
Hence, from the above,
We can conclude that
“4” is the number that is repeatedly multiplied
“3” is the number that tells how many times “4” is used as a factor

Question 2.
What is the GCF of 14 and 42? Lesson 3.2
Answer:
The given numbers are: 14 and 42
Now,

Hence, from the above,
We can conclude that
The GCF of 14 and 42 is: 14

Question 3.
Which pair of numbers has a GCF of 5? Lesson 3.2
A. 15 and 30
B. 5 and 21
C. 45 and 9
D. 20 and 55
Answer:
The given numbers are:
A) 15 and 30   – GCF is 15
B) 5 and 21     – GCF is 1
C) 45 and 9     – GCF is 9
D) 20 and 55   – GCF is 5
Hence, from the above,
We can conclude that
The pair of numbers that has a GCF of 5 is:

Question 4.
What is the LCM of 12 and 9? Lesson 3.2
Answer:
The given numbers are: 12 and 9
So,

Hence, from the above,
We can conclude that
The LCM of 12 and 9 is: 36

Question 5.
Evaluate the numerical expression. Lesson 3.3
0.52 × (20 – 22 × 3) × (\(\frac{2}{5}\) × 25)
Answer:
The given numerical expression is:
0.52 × (20 – 22 × 3) × (\(\frac{2}{5}\) × 25)
So,

Hence, from the above,
We can conclude that
The value of the given numerical expression is: 20

Question 6.
Select all the expressions that are equal to (\(\frac{2}{3}\))2? Lesson 3.1
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 22 \(\frac{4}{9}\)
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 22 \(\frac{4}{3}\)
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 22 \(\frac{1}{3}\) × \(\frac{1}{3}\)
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 22 \(\frac{1}{9}\) × 4
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 22 \(\frac{2}{3}\) × \(\frac{2}{3}\)
Answer:
The given expression is: (\(\frac{2}{3}\))²
So,
(\(\frac{2}{3}\))²
= \(\frac{2}{3}\) × \(\frac{2}{3}\)
= \(\frac{2 × 2}{3 × 3}\)
= \(\frac{4}{9}\)
= 4 × \(\frac{1}{9}\)
Hence, from the baove,
We can conclude that
All the expressions that are equivalent to (\(\frac{2}{3}\))² are:

Question 7.
Liam bought 2 vintage movie posters, 2 rock posters, and 1 rap poster. He applied a $35 gift card to the total purchase and a \(\frac{1}{2}\)-off coupon to the rap poster. Write and evaluate a numerical expression to show how much Liam paid for the posters. Lesson 3.3
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 30.1
Answer:
It is given that
Liam bought 2 vintage movie posters, 2 rock posters, and 1 rap poster. He applied a $35 gift card to the total purchase and a \(\frac{1}{2}\)-off coupon to the rap poster
Now,
The given table is:
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 30.1
Now,
The amount Liam has to pay for the posters = (The number of vintage movie posters) × (The cost of each vintage movie poster) + (The number of rap posters) × (The cost of each rap poster) + (The number of rock posters) × (The cost of each rock poster)
= (2 × $28.50) + (1 × $19.50) + (2 × $29.75)
Now,

So,
The amount Liam has to pay for the posters is: $136
Now,
With a $35 gift coupon,
The amount Liam has to pay for the posters = $136 – $35
= $101
Now,
With the \(\frac{1}{2}\) off coupon of rap poster,
The total cost of rap poster = \(\frac{$19.50}{2}\)
= $9.75
So,
The amount Liam has to pay for the posters = $101 – $9.75
= $91.25
Hence, from the above,
We can conclude that
The amount of money Liam paid for the products is: $91.25

Question 8.
Eva counts up by 3s, while Jin counts up by 5s. What is the smallest number that they both say? Lesson 3-2
Answer:
It is given that
Eva counts up by 3s, while Jin counts up by 5s
Now,
To find the smallest number that both Evan and Jin can say,
Find the LCM of 3 and 5
Now,

Hence, from the above,
We can conclude that
The smallest number that both Eva and Jin can say is: 15

How well did you do on the mid-topic checkpoint? Fill in the stars. Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 30.2

Topic 3 MID-TOPIC PERFORMANCE TASK

Monique and Raoul are helping teachers make gift bags and gather supplies for a student celebration day at Pineville Middle School.

PART A
Raoul has 72 wristbands and 96 movie passes to put in gift bags. The greatest common factor for the number of wristbands and the number of movie passes is equal to the number of gift bags Raoul needs to make. Find the number of gift bags Raoul needs to make. Then find how many wristbands and how many movies passes Raoul can put in each gift bag if he evenly distributes the items.
Answer:
It is given that
Monique and Raoul are helping teachers make gift bags and gather supplies for a student celebration day at Pineville Middle School.
Raoul has 72 wristbands and 96 movie passes to put in gift bags. The greatest common factor for the number of wristbands and the number of movie passes is equal to the number of gift bags Raoul needs to make.
Now,
According to the given information,
The number of gift bags Raoul needs to make = The GCF of the number of wristbands and the number of movies passes
So,

So,
The number of gift bags Raoul needs to make is: 24 gift bags
Now,
The number of wristbands = (The number of gift bags Raoul needs to make) ÷ 2
= \(\frac{24}{2}\)
= 12 wristbands
The number of movie tickets = (The number of gift bags Raoul needs to make) ÷ 2
= \(\frac{24}{2}\)
= 12 movie tickets
Hence, from the above,
We can conclude that
The number of gift bags Raoul needs to make is: 24 gift bags
The number of wristbands is: 12
The number of movie tickets is: 12

PART B
Monique wants to have an equal number of cups and napkins. What are the least number of packages of cups and the least number of packages of napkins Monique should buy to have an equal number of cups and napkins? Justify your answer.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 30.5
Answer:
It is given that
Monique wants to have an equal number of cups and napkins
Now,
The given table is:
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 30.5
Now,
To find the least number of packages of cups and the least number of packages of napkins,
Find the LCM of the number of cups and napkins present in each package
So,
We have to find the LCM of 12 and 10 to find the least number of packages of cups and napkins
Now,

Hence, from the above,
We can conclude that
The least number of packages of cups and the least number of packages of napkins Monique should buy to have an equal number of cups and napkins is: 60

PART C
Which numerical expressions show the equal number of both cups and napkins that Monique will have in Part B? Select all that apply.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 31 21 × 30
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 31 102 × 60
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 31 22 × 15
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 31 4600
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 31 40 × 60
Answer:
From part B,
We can observe that
The least number of packages of cups and the least number of packages of napkins Monique should buy to have an equal number of cups and napkins is: 60
Hence, from the above,
We can conclude that
The numerical expressions that show the equal number of both cups and napkins that Monique will have in Part B are:

PART D
The teachers have $25 to buy supplies. Write and evaluate a numerical expression to show how much more money they will need to buy the cups and napkins.
Answer:
It is given that
The teachers have $25 to buy supplies
Now,
The given table is:
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 30.5
Now,
From the given table,
We can observe that
The total cost of cups and Napkins = (The number of cups per package) × (The cost of each cup) + (The number of Napkins per package) × (The cost of each Napkin)
= (12 × $3.80) + (10 × $4.25)
= $45.60 + $42.50
= $88.10
Now,
The amount of more money than the teachers need to buy cups and napkins = (The total cost of cups and Napkins) – (The amount of money the teachers have)
= $88.10 – $25
= $63.10
Hence, from the above,
We can conclude that
The more money the teachers will need to buy the cups and napkins is: $63.10

Lesson 3.4 Write Algebraic expressions

Explore It!
The table shows the number of games the Hornets won and the number of games the Lynx won.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 32

A. What pattern do you see in the data in the table? Explain how the pattern relates to the number of games won.
Answer:
It is given that
The table shows the number of games the Hornets won and the number of games the Lynx won.
Now,
The given table is:
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 32
Now,
From the given table,
We can observe that
The number of games won by Lynx is 2 more than the number of games won by Hornets
Hence, from the above,
We can conclude that
The pattern that is related to the number of games won is:
The number of games won by Lynx = (The number of games won by Hornet) + 2

B. Look for Relationships Write numerical expressions to relate the number of games won by the Lynx to the number of games won by the Hornets.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 33
Answer:
From part A,
We know that,
The number of games won by Lynx = (The number of games won by Hornet) + 2
Hence, from the above,
We can conclude that
The numerical expressions that relate the number of games won by the Lynx to the number of games won by the Hornets is:

C. Explain how to complete the table above for the Lynx if the Hornets won n games.
Answer:
From Part A,
We know that,
The number of games won by Lynx = (The number of games won by Hornet) + 2
Now,
It is given that
Hornets won n games
Hence, from the above,
We can conclude that
The number of games won by Lynx = n + 2
Where,
n is the number of games won by Hornets

Focus on math practices
Reasoning
Suppose the Lynx won g games. What mathematical expression could you write to show how many games the Hornets won? How is this expression related to the expression you wrote to find the number of games the Lynx won when the Hornets won n games? Explain.
Answer:
From Part A,
We know that,
The number of games won by Lynx = (The number of games won by Hornets) + 2
Now,
If Lynx won g games, then
The number of games won by Hornets = g – 2
Where,
g is the number of games won by Lynx
The expression when Hornets won n games is the same as the above expression as we replace the variable g with the variable n

VISUAL LEARNING

? Essential Question How can you write an algebraic expression?
Answer:
Algebraic expressions are useful because they represent the value of an expression for all of the values a variable can take on. Similarly, when we describe an expression in words that includes a variable, we are describing an algebraic expression, an expression with a variable

Try It!
Darius’s sister Rachel bought m mystery books for $6.50 each. Show three ways to write an algebraic expression that represents the total cost of the mystery books.
Answer:
It is given that
Darius’s sister Rachel bought m mystery books for $6.50 each
So,
The cost of m books bought by Rachel = (The total number of books) × (The cost of each book)
= m × $6.50
= $6.50m
Now,
The representation of the algebraic expression that represents the total cost of the mystery books in 3 ways is:
$6.50m (or) $6.50 × m (or) $6050(m)
Hence, from the above,
We can conclude that
The representation of the algebraic expression that represents the total cost of the mystery books in 3 ways is:
$6.50m (or) $6.50 × m (or) $6050(m)

Convince Me! How do you know that the expressions you wrote for the cost of the mystery books are algebraic expressions?
Answer:
We know that,
Algebraic expressions are combinations of variables, numbers, and at least one arithmetic operation.
For example,
2x+4y−9 is an algebraic expression.
Now,
When we observe the total cost of m mystery books,
We can observe that
m is a variable
Hence, from the above,”
We can conclude that
Since the expression that represents the total cost of the mystery books,
We can say that the expression that represents the total cost of the mystery books is an algebraic expression

Try It!

Write an algebraic expression that represents “8 minus the quantity b divided by 6.”
Answer:
The given algebraic expression in words is: 8 minus the quantity divided by 6
So,
The representation of the given algebraic expression that is in words into a symbolic form is:
(8 – b) ÷ 6 (or) \(\frac{8 – b}{6}\)
Hence, from the above,
We can conclude that
The representation of the given algebraic expression that is in words into a symbolic form is:
(8 – b) ÷ 6 (or) \(\frac{8 – b}{6}\)

Try It!
How many terms does the expression r ÷ 9 + 5.5 have? Explain.
Answer:
The given expression is: r ÷ 9 + 5.5
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
So,
The number of terms the given expression contains is: 2 terms
Hence, from the above,
We can conclude that
The number of terms the given expression contains is: 2 terms

KEY CONCEPT
A variable, written as a letter, represents a quantity that can change. You can use a variable to write an algebraic expression that has at least one operation.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 50.1

Do You Understand?

Question 1.
? Essential Question How can you write an algebraic expression?
Answer;
Algebraic expressions are useful because they represent the value of an expression for all of the values a variable can take on. Similarly, when we describe an expression in words that includes a variable, we are describing an algebraic expression, an expression with a variable

Question 2.
Be Precise Identify the variable and the operation in the algebraic expression \(\frac{6}{x}\)
Answer:
The given algebraic expression is: \(\frac{6}{x}\)
Now,
We know that,
A “Variable”, written as a letter, represents a quantity that can change
So,
In the given expression,
The variable is: x
The operation in the given algebraic expression is: Division
Hence, from the above,
We can conclude that
In the given expression,
The variable is: x
The operation in the given algebraic expression is: Division

Question 3.
Vocabulary Explain why 15 + \(\frac{1}{2}\)n is an algebraic expression.
Answer:
The given expression is: 15 + \(\frac{1}{2}\)n
Now,
We know that,
Algebraic expressions are useful because they represent the value of an expression for all of the values a variable can take on. Similarly, when we describe an expression in words that includes a variable, we are describing an algebraic expression, an expression with a variable
Hence, from the above,
We can conclude that
15 + \(\frac{1}{2}\)n is an algebraic expression

Question 4.
Reasoning Could you describe the expression 2(3 + 4) as a product of two factors? Explain.
Answer:
The given expression is: 2 (3 + 4)
Now,
By using the Distributive Property,
2 (3 + 4) = 2 × (3 + 4)
= (2 × 3) + (2 × 4)
Hence, from the above,
We can conclude that
The given expression could be described as a product of two factors

Question 5.
Which part of the expression 2(3 + 4) is the sum of two terms? Explain.
Answer:
The given expression is: 2 (3 + 4)
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
So,
In the given expression,
We can observe that
(3 + 4) contains two terms separated by an addition operation
Hence, from the above,
We can conclude that
In the given expression,
(3 + 4) is the sum of two terms

Do You Know How?

In 6 and 7, write an algebraic expression for each situation.

Question 6.
five less than y
Answer:
The given situation is: five less than y
Now,
We know that,
When we see the word “Less” in a situation, the operation that takes place in that situation must be “Subtraction”
Hence, from the above,
We can conclude that
The representation of the given situation into an algebraic expression is: y – 5

Question 7.
six times the quantity two x plus three y
Answer:
The given situation is: six times the quantity two x plus three y
Now,
We know that,
When we see the word “times the quantity” in a situation, the operation that takes place in that situation must be “Multiplication”
Hence, from the above,
We can conclude that
The representation of the given situation into an algebraic expression is: 6 (2x + 3y)

In 8-10, use the expression \(\frac{w}{4}\) + 12.5 – 7z.

8. How many terms does the expression have?
Answer:
The given expression is: \(\frac{w}{4}\) + 12.5 – 7z
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
Hence, from the above,
We can conclude that
The number of terms the given expression contains: 3 terms

Question 9.
Which term has a coefficient? Explain.
Answer:
The given expression is: \(\frac{w}{4}\) + 12.5 – 7z
Now,
We know that,
A “Coefficient” is the number that is multiplied by a variable
Hence, from the above,
We can conclude that
The term that has a coefficient in the given expression is: 7z

Question 10.
Which term is a constant numerical value?
Answer:
The given expression is: \(\frac{w}{4}\) + 12.5 – 7z
Now,
We know that,
A “Constant” is nothing but a numerical value
Hence, from the above,
We can conclude that
The term that is a constant numerical value in the given expression is: 12.5

Practice & Problem Solving

In 11-14, write an algebraic expression for each situation.

Question 11.
12 times a number g
Answer:
The given situation is: 12 times a number g
Now,
We know that,
When we see the word “times a number” in a situation, the operation that takes place in that situation must be “Multiplication”
Hence, from the above,
We can conclude that
The representation of the given situation into an algebraic expression is: 12 (g) (or) 12g

Question 12.
p pennies added to 22 pennies
Answer:
The given situation is: p pennies added to 22 pennis
Now,
We know that,
When we see the word “Add” in a situation, the operation that takes place in that situation must be “Addition”
Hence, from the above,
We can conclude that
The representation of the given situation into an algebraic expression is: p + 22

Question 13.
22 divided by a number s
Answer:
The given situation is: 22 divided by a number s
Now,
We know that,
When we see the word “Divide” in a situation, the operation that takes place in that situation must be “Division”
Hence, from the above,
We can conclude that
The representation of the given situation into an algebraic expression is: 22 ÷ s (or) \(\frac{22}{s}\)

Question 14.
12\(\frac{3}{4}\) less than the product of 7 and a number x
Answer:
The given situation is: 12\(\frac{3}{4}\) less than the product of 7 and a number x
Now,
We know that,
When we see the word “Less” and “Product” in a situation, the operation that takes place in that situation must be “Subtraction” and “Multiplication”
Hence, from the above,
We can conclude that
The representation of the given situation into an algebraic expression is: 7x – 12\(\frac{3}{4}\)

In 15-18, tell how many terms each expression has.

Question 15.
5 – g
Answer:
The given expression is: 5 – g
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
Hence, from the above,
We can conclude that
The number of terms the given expression contains is: 2 terms

Question 16.
3 + \(\frac{1}{2}\)b
Answer:
The given expression is: 3 + \(\frac{1}{2}\)b
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
Hence, from the above,
We can conclude that
The number of terms the given expression contains is: 2 terms

Question 17.
\(\frac{v}{3}\) + 2 • 5
Answer:
The given expression is: \(\frac{v}{3}\) + 2 • 5
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
Hence, from the above,
We can conclude that
The number of terms the given expression contains is: 2 terms

Question 18.
16.2 – (3 • 4) + (14 ÷ 2)
Answer:
The given expression is: 16.2 – (3 • 4) + (14 ÷ 2)
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
Hence, from the above,
We can conclude that
The number of terms the given expression contains is: 3 terms

In 19 and 20, use the expression 5.3t – (20 ÷ 4) + 11.

Question 19.
Which part of the expression is a quotient? Describe its parts.
Answer:
The given expression is: 5.3t – (20 ÷ 4) + 11
Now,
We know that,
The “Quotient” is only possible when there is a “Division” operation
Hence, from the above,
We can conclude that
The part of the expression that is a quotient is: 20 ÷ 4

Question 20.
Which part of the expression is a product of two factors? Describe its parts.
Answer:
The given expression is: 5.3t – (20 ÷ 4) + 11
Now,
We know that,
The “product” is possible when there are 2 numbers or a number and a variable
Hence, from the above,
We can conclude that
The part of the expression that is a product of two factors is: 5.3t

In 21 and 22, use the table at the right.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 52.1

Question 21.
Model with Math
Write an expression to show how much longer the round-trip to San Diego is than the round-trip to San Jose. How many terms does the expression have?
Answer:
The given information is:

Now,
From the given table,
We can observe that
The distance of the round trip to San Jose is: 236 miles
The distance of the round trip to San Diego is: 1,012 miles
So,
The expression that shows how much longer the round-trip to San Diego is than the round-trip to San Jose
= (The distance of the round trip to San Diego) – (The distance of the round trip to San Jose)
= 1,012 – 236
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
So,
The number of terms in the above expression is: 2 terms
Hence, from the above,
We can conclude that
The expression that shows how much longer the round-trip to San Diego is than the round-trip to San Jose is: 1,012 – 236
The number of terms in the above expression is: 2 terms

Question 22.
Make Sense and Persevere Last month, a truck driver made 5 round-trips to Los Angeles and some round-trips to San Diego. Write an expression that shows how many miles he drove in all. Identify and describe the part of the expression that shows how many miles he drove and trips he made to San Diego.
Answer:
It is given that
Last month, a truck driver made 5 round-trips to Los Angeles and some round-trips to San Diego
Now,
The given information is:

Now,
From the above table,
We can observe that
The distance of the round trip to Los Angeles is: 770 miles
The distance of the round trip to San Diego is: 1,012 miles
Now,
Let the number of round trips to San Diego be: x
Let the number of miles the truck driver drove to Los Angeles be: p
Let the number of miles the truck driver drove to San Diego be: q
Now,
We know that,
The total distance traveled by the truck driver = (The number of round trips made to Los Angeles) × (The number of miles the truck driver drove to Los Angeles) + (The number of round trips to San Diego) × (The number of miles the truck driver drove to San Diego)
= 5p + xq
So,
The number of miles the truck driver drove is: 5p + xq
The number of trips the truck driver made to san Diego is: x
Hence, from the above,
We can conclude that
The number of miles the truck driver drove is: 5p + xq
The number of trips the truck driver made to san Diego is: x

Question 23.
Use the expression y ÷ 3(4 – 2) + 5.5 to complete the table. Identify the parts of the expression that correspond to the descriptions.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 52.2
Answer:
The given expression is: y ÷ 3 (4 – 2) + 5.5
Now,
We know that,
A “Variable”, written as a letter, represents a quantity that can change
The symbol of Difference is: –
The symbol of Product is () (or) ×
Hence, from the above,
We can conclude that
The completed table with the corresponding descriptions is:

Question 24.
The floats in the Orlando Citrus parade may use as many citrus fruits as a small orchard produces in 6 years. If f is the number of citrus fruits a small orchard produces in 1 year, write an algebraic expression to represent the number of citrus fruits the floats in the parade may use.
Answer:
It is given that
The floats in the Orlando Citrus parade may use as many citrus fruits as a small orchard produces in 6 years and f is the number of citrus fruits a small orchard produces in 1 year
So,
The number of citrus fruits the floats in the parade may use in 6 years = 6 × (The number of citrus fruits a small orchard produces in 1 year)
= 6 × f
= 6f citrus fruits
Hence, from the above,
We can conclude that
The number of citrus fruits the floats in the parade may use in 6 years is: 6f citrus fruits

Question 25.
Critique Reasoning Anthony says that the expression abc has three terms because it uses three different variables. Critique Anthony’s reasoning and explain whether he is correct
Answer:
It is given that
Anthony says that the expression abc has three terms because it uses three different variables.
Now,
The given expression is: abc
Now,
We know that,
Each part of an expression that is separated by a plus sign or a minus sign is called a “Term”
Now,
From the given expression,
We can observe that
There are not any plus or minus signs
So,
The given expression is a single term
Hence, from the above,
We can conclude that
Anthony’s reasoning is incorrect

Question 26.
Yuri walked p poodles and b bulldogs on Monday. He walked the same number of poodles and bulldogs each day Tuesday through Friday as he did on Monday. Write an algebraic expression to represent how many total dogs were walked in this 5-day period.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 35.1
Answer:
It is given that
Yuri walked p poodles and b bulldogs on Monday. He walked the same number of poodles and bulldogs each day Tuesday through Friday as he did on Monday
So,
The total dogs walked on Monday = (The number of poodles) + (The number of bulldogs)
= p + b
Now,
It is given that
The same number of dogs walked from Tuesday to Friday as on Monday
So,
The total number of dogs that were waked from Monday to Friday = (The number of days from Monday to Friday) × (The number of dogs walked on Monday)
= 5 × (p + b) dogs
Hence, from the above,
We can conclude that
The total number of dogs that were waked from Monday to Friday is: 5(p + b) dogs

Question 27.
Higher-Order Thinking Some students equally share 2 baskets of oranges. Each basket has 12 oranges. Write an algebraic expression to represent this situation. Then explain how you chose which variable and operations to use.
Answer:
It is given that
Some students equally share 2 baskets of oranges. Each basket has 12 oranges
Now,
Let the number of students be: x
Let the number of apples each student gets be: y
Now,
The total number of oranges in 2 baskets = 2(The number of baskets in each basket)
= 2 (12)
= 24 oranges
So,
The algebraic expression that represents the given situation is:
The number of apples each student gets = (The total number of apples in 2 baskets) ÷ (The number of students)
y = \(\frac{24}{x}\)
Hence, from the above,
We can conclude that
The algebraic expression that represents the given situation is:
y = \(\frac{24}{x}\)

Question 28.
Model with Math
The figure at the right is a regular octagon with side length s. Write two algebraic expressions that use different operations to represent the perimeter of the figure.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 53.2
Answer:
It is given that
The figure at the right is a regular octagon with side length s.
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 53.2
Now,
We know that,
The “Perimeter” of any figure is the sum of all the sides of the given figure
Now,
Let the perimeter of the regular Octagon be: P
So,
The perimeter of the given regular Octagon is:
P = s + s + s + s + s + s + s + s
P = 8 (s) = 8s
Hence, from the above,
We can conclude that
The two algebraic expressions that use different operations to represent the perimeter of the given figure is:
P = s + s + s + s + s + s + s + s
P = 8s

Assessment Practice

Question 29.
Which algebraic expression represents the phrase Four more than the product 3 times the number of c cats?
A. 4 + 3c
B. (4 + 3)c
C. 3 + 4c
D. 4 × 3 × c
Answer:
The given phrase is: Four more than the product 3 times the number of c cats
So,
The representation of the given phrase in the form of an algebraic expression is: 4 + 3c
Hence, from the above,
We can conclude that
The algebraic expression represents the phrase Four more than the product 3 times the number of c cats is:

Question 30.
Select all of the phrases that could be represented by the algebraic expression \(\frac{w}{4}\) – 4.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 55 four less than the quotient of a number w and four
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 55 the difference between a number w and 4
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 55 four less than w divided by 4
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 55 four less than a number w
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 55 the quotient of four and a number w
Answer:
The given algebraic expression is: \(\frac{w}{4}\) – 4
So,
The representation of the given algebraic expression in the form of a phrase is:
a. 4 less than the quotient of w and 4
b. The difference between the quotient of w and 4 and 4
c. 4 less than w divided by 4
Hence, from the above,
We can conclude that
All of the phrases that could be represented by the algebraic expression \(\frac{w}{4}\) – 4. are:

Lesson 3.5 Evaluate Algebraic expressions

Solve & Discuss It!

A bike shop charges by the hour to rent a bike. Related items are rented for flat fees. Write an expression that represents how much it will cost to rent a bike and helmet for h hours. How much would it cost to rent a bike and a helmet for 3 hours?
Model with Math
You can write an algebraic expression with decimals in the same way you do with whole numbers.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 55.1

Answer:
It is given that
A bike shop charges by the hour to rent a bike. Related items are rented for flat fees
Now,
The given table is:

So,
The total cost of renting a bike and a helmet for h hours = (The cost of renting a bike per hour) × (The total number of hours) + The cost of a helmet
= $12.50 ×h + $5.25
So,
The total cost of renting a bike and a helmet for 3 hours = (The cost of renting a bike per hour) × (The total number of hours) + The cost of a helmet
= $12.50 ×3 + $5.25
= $37.50 + $5.25
= $42.75
Hence, from the above,
We can conclude that
The expression that represents the total cost to rent a bike and a helmet for h hours is:
The total cost of renting a bike and a helmet for h hours =$12.50 ×h + $5.25
The total cost of renting a bike and a helmet for 3 hours is: $42.75

Focus on math practices
Use Structure Write an expression that represents renting a bike, a lock, and a basket for h hours. What is the cost of renting this equipment for 4 hours?
Answer:
The given table is:

Now,
From the given table,
We can observe that
The cost to rent a bike, a lock, and a basket for h hours = (The cost of renting a bike per hour) × (The total number of hours) + The cost of renting a lock + The cost of renting a basket
= $12.50 × h + $1.75 + $2.25
= $12.50 × h + 4
Now,
The cost to rent a bike, a lock, and a basket for 4 hours = (The cost of renting a bike per hour) × (The total number of hours) + The cost of renting a lock + The cost of renting a basket
= $12.50 × 4 + $1.75 + $2.25
= $12.50 × 4 + $4
= $50 + $4
= $54
Hence, from the above,
We can conclude that
The expression that represents renting a bike, a lock, and a basket for h hours is:
The expression that represents renting a bike, a lock, and a basket for h hours = $12.50 × h + 4
The cost to rent a bike, a lock, and a basket for 4 hours is: $54

VISUAL LEARNING

? Essential Question How can you evaluate an algebraic expression?
Answer:
To evaluate an algebraic expression means to determine the value of the expression for a given value of each variable in the expression. Replace each variable in the expression with the given value, then simplify the resulting expression using the order of operations.

Try It!
Evaluate the expression 50 – t when t equals 10, 20, or 25. Then complete the table to show the values.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 53.1
Answer:
The given expression is: 50 – t
Where,
The value of t is: 10, 20, and 25
Now,
For t = 10, 20, and 25,

Hence, from the above,
We can conclude that

Convince Me! What does it mean to use substitution to evaluate an algebraic expression?
Answer:
To substitute the values of the numerals into an algebraic expression means to replace all numerals with their respective values (or numbers). Once the values of the numerals are substituted, the expression can be evaluated. While evaluating, the correct order of operations must be observed

Try It!
Evaluate the expression 3.4 + 12a ÷ 4 for a = 10.
Answer:
The given expression is 3.4 + 12a ÷ 4 for a = 10
Now,
For a = 10,
3.4 + 12a ÷4
= 3.4 + 12 (10) ÷ 4
= 3.4 + 120 ÷ 4
= 3.4 + 30
= 33.4
Hence, from the above,
We can conclude that
The value of the given expression is: 33.4

Try It!
Suppose Mr. Grant decides to buy square tiles that have side lengths of \(\frac{3}{4}\) foot. How many of these tiles will he need to buy?
Answer:
It is given that
Suppose Mr. Grant decides to buy square tiles that have side lengths of \(\frac{3}{4}\) foot
Now,
From Example 3,
It is given that
The expression to find the number of tiles Mr. Grant needs to buy is 27 ÷ s²
Where,
s is the sidelength
Now,
When s = \(\frac{3}{4}\) foot,
The number of tiles Mr.Grant needs to buy = 27 ÷ (\(\frac{3}{4}\))²
= 27 ÷ \(\frac{9}{16}\)
= 27 × \(\frac{16}{9}\)
= \(\frac{27 × 16}{9}\)
= 3 × 16
= 48 tiles
Hence, from the above,
We can conclude that
The number of tiles Mr.Grant needed to buy when the side length is \(\frac{3}{4}\) foot is: 48 tiles

KEY CONCEPT
To evaluate an expression, use substitution to replace a variable with its numerical value. Then use the order of operations to simplify.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 53.4

Do You Understand?

Question 1.
? Essential Question How can you evaluate an algebraic expression?
Answer:
To evaluate an algebraic expression means to determine the value of the expression for a given value of each variable in the expression. Replace each variable in the expression with the given value, then simplify the resulting expression using the order of operations

Question 2.
Construct Arguments Why is it important to use the order of operations to evaluate algebraic expressions?
Answer:
The order of operations is a rule that tells you the right order in which to solve different parts of a math problem. The order of operations is important because it guarantees that people can all read and solve a problem in the same way

Question 3.
How is evaluating an expression with fractions like evaluating an expression with whole numbers? How is it different?
Answer:
The fractions have the same denominators so you can start by adding the first two fractions. Add the fractions before adding the whole numbers. Then, take the sum and subtract the third fraction. Before evaluating the expression, rewrite the fractions with one common denominator
To evaluate an expression with a whole number, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations. in the expression that involves fractions, first, we have to simplify the fractions into whole numbers and follow the order of operations to evaluate them

Question 4.
Reasoning Annalise earns $4 an hour walking pets in her neighborhood. She evaluates the expression 4h, where h represents the number of hours, to find the amount she earns. Can any number be substituted for h? Explain.
Answer:
It is given that
Annalise earns $4 an hour walking pets in her neighborhood. She evaluates the expression 4h, where h represents the number of hours, to find the amount she earns.
Now,
According to the given information,
The total amount of money earned by Annalise = $4h
Where,
h is the number of hours
Now,
We know that,
h will be any number i.e., either a whole number or a fraction
Hence, from the above,
We can conclude that
We can substitute any number for h

Do You Know How?

In 5-8, evaluate each expression for t = 8, w = \(\frac{1}{2}\), and x = 3.

Question 5.
3t – 8
Answer:
The givene xpression is: 3t – 8
Now,
For t = 8,
3t – 8
= 3 (8) – 8
= 24 – 8
= 16
Hence, from the baove,
We can conclude that
The value of the given expression is: 16

Question 6.
6w ÷ x + 9
Answer:
The given expression is: 6w ÷ x + 9
Now,
For w = \(\frac{1}{2}\), and x = 3,
6w ÷ x + 9
= 6 (\(\frac{1}{2}\)) ÷ 3 + 9
= \(\frac{6}{2}\) ÷ 3 + 9
= 3 ÷ 3 + 9
= 1 + 9
= 10
Hence, from the above,
We can conclude that
The value of the given expression is: 10

Question 7.
t2 – 12w ÷ ×
Answer:
The given expression is: t2 – 12w ÷ ×
Now,
For t = 8, w = \(\frac{1}{2}\), and x = 3,
t2 – 12w ÷ ×
= 82 – 12 (\(\frac{1}{2}\)) ÷ 3
= 64 – \(\frac{12}{2}\) ÷ 3
= 64 – 6 ÷ 3
= 64 – 2
= 62
Hence, from the above,
We can conclude that
The value of the given expression is: 62

Question 8.
5x – 2w + t
Answer:
The given expression is: 5x – 2w + t
Now,
For t = 8, w = \(\frac{1}{2}\), and x = 3,
5x – 2w + t
= 5 (3) – 2 (\(\frac{1}{2}\)) + 8
= 15 – \(\frac{2}{2}\) + 8
= 15 – 1 + 8
= 15 + 7
= 22
Hence, from the above,
We can conclude that
The value of the given expression is: 22

In 9-14, evaluate each expression for the value given.

Question 9.
z ÷ 4; z = 824
Answer:
The given expression is: z ÷ 4 with z = 824
Now,
For z = 824,
z ÷ 4
= 824 ÷ 4
= 206
Hence, from the above,
We can conclude that
The value of the given expression is: 206

Question 10.
6t ÷ 9 – 22; t = 60
Answer:
The given expression is: 6t ÷ 9 – 22 with t = 60
Now,
For t = 60,
6t ÷ 9 – 22
= 6 (60) ÷ 9 – 22
= 360 ÷ 9 – 22
= 40 – 22
= 18
Hence, from the above,
We can conclude that
The value of the given expression is: 18

Question 11.
r ÷ 2.4; r = 16.8
Answer:
The given expression is: r ÷2.4 with r = 16.8
Now,
For r = 16.8,
r ÷2.4
= 16.8 ÷ 2.4
= 7
Hence, from the above,
We can conclude that
The value of the given expression is: 7

Question 12.
9.85 × s; s = 4
Answer:
The given expression is: 9.85 × s with s = 4
Now,
For s = 4,
9.85 × s
= 9.85 × 4
= 39.40
Hence, from the above,
We can conclude that
The value of the given expression is: 39.40

Question 13.
x ÷ 12; x = \(\frac{2}{3}\)
Answer:
The given expression is: x ÷ 12, with x = \(\frac{2}{3}\)
Now,
For x = \(\frac{2}{3}\),
x ÷ 12
= \(\frac{2}{3}\) ÷ 12
= \(\frac{2}{3}\) × \(\frac{1}{12}\)
= \(\frac{2 ×1}{3 × 12}\)
= \(\frac{2}{36}\)
= \(\frac{1}{18}\)
Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{1}{18}\)

Question 14.
\(\frac{3}{4}\) + 4y ÷ 3; y = 1\(\frac{1}{2}\)
Answer:
The given expression is: \(\frac{3}{4}\) + 4y ÷ 3 with y = 1\(\frac{1}{2}\)
Now,
For y = 1\(\frac{1}{2}\),
\(\frac{3}{4}\) + 4y ÷ 3
= \(\frac{3}{4}\) + 4 (1\(\frac{1}{2}\) ÷ 3
= \(\frac{3}{4}\) + 3 ÷ 3
= \(\frac{3}{4}\) + 1
= \(\frac{7}{4}\)
Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{7}{4}\)

Practice & Problem Solving

Scan for Multimedia

In 15-17, evaluate each expression for w = 5, x = 3, y = 4, and z = 8.

Question 15.
9x
Answer:
The given expression is: 9x
Now,
For x = 3,
9x = 9 × 3
= 27
Hence, from the above,
We can conclude that
The value of the given expression is: 27

Question 16.
3y + 6 ÷ 2x
Answer:
The given expression is: 3y + 6 ÷ 2x
Now,
For x = 3, and y = 4,
3y + 6 ÷ 2x
= (3 × 4) + 6 ÷ (2 × 3)
= 12 + 6 ÷ 6
= 12 + 1
= 13
Hence, from the above,
We can conclude that
The value of the given expression is: 13

Question 17.
w2 + 2 + 48 ÷ 2z
Answer:
The given expression is: w2 + 2 + 48 ÷ 2z
Now,
For w = 5, and z = 8,
w2 + 2 + 48 ÷ 2z
= 5² + 2 + 48 ÷ (2 × 8)
= 25 + 2 + 48 ÷ 16
= 27 + 3
= 30
Hence, from the above,
We can conclude that
The value of the given expression is: 30

In 18-20, evaluate each expression for x = 1.8, x = 5, and x = 6.4.

Question 18.
x ÷ 4
Answer:
The given expression is: x ÷ 4
Now,
For x = 1.8
x ÷ 4 = 1.8 ÷ 4
= 0.45
Now,
For x = 5,
x ÷ 4 = 5 ÷ 4
= 1.25
Now,
For x = 6.4,
x ÷ 4 = 6.4 ÷ 4
= 1.6
Hence, from the above,
We can conclude that
The value of the given expression for x = 1.8 is: 0.45
The value of the given expression for x = 5 is: 1.25
The value of the given expression for x = 6.4 is: 1.6

Question 19.
x(3.35)
Answer:
The given expression is: x (3.35)
Now,
For x = 1.8,
x (3.35) = 1.8 (3.35)
= 6.03
Now,
For x = 5,
x (3.35) = 5 (3.35)
= 16.75
Now,
For x = 6.4,
x (3.35) = 6.4 (3.35)
= 21.44
Hence, from the above,
We can conclude that
The value of the given expression for x = 1.8 is: 6.03
The value of the given expression for x = 5 is: 16.75
The value of the given expression for x = 6.4 is: 21.44

Question 20.
2x + 3.1
Answer:
The given expression is: 2x + 3.1
Now,
For x = 1.8,
2x + 3.1 = (2 × 1.8) + 3.1
= 6.7
Now,
For x = 5,
2x + 3.1 = (2 × 5) + 3.1
= 10 + 3.1
= 13.1
Now,
For x = 6.4,
2x + 3.1 = (2 × 6.4) + 3.1
= 15.9
Hence, from the above,
We can conclude that
The value of the given expression for x = 1.8 is: 6.7
The value of the given expression for x = 5 is: 13.1
The value of the given expression for x = 6.4 is: 15.9

In 21-23, evaluate each expression for the value given.

Question 21.
j + \(\frac{3}{8}\); j = \(\frac{3}{4}\)
Answer:
The given expression is: j + \(\frac{3}{8}\)
Now,
For j = \(\frac{3}{4}\),
j + \(\frac{3{8}\)
= \(\frac{3}{8}\) + \(\frac{3}{4}\)
= \(\frac{3}{8}\) + \(\frac{6}{8}\)
= \(\frac{3 + 6}{8}\)
= \(\frac{9}{8}\)
Hence, from the baove,
We can conclude that
The value of the given expression is: \(\frac{9}{8}\)

Question 22.
8 – g ÷ \(\frac{7}{8}\); g = \(\frac{5}{6}\)
Answer:
The given expression is: 8 – g ÷ \(\frac{7}{8}\)
Now,
For g = \(\frac{5}{6}\),
8 – g ÷ \(\frac{7}{8}\)
= 8 – \(\frac{5}{6}\) ÷ \(\frac{7}{8}\)
= 8 – \(\frac{5}{6}\) × \(\frac{8}{7}\)
= 8 – \(\frac{5 × 8}{6 × 7}\)
= 8 – \(\frac{40}{42}\)
= 8 – \(\frac{20}{21}\)
= \(\frac{168 – 20}{21}\)
= \(\frac{148}{21}\)
Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{148}{21}\)

Question 23.
3m ÷ \(\frac{2}{5}\); m = \(\frac{2}{3}\)
Answer:
The given expression is: 3m ÷ \(\frac{2}{5}\)
Now,
For m = \(\frac{2}{3}\),
3 × \(\frac{2}{3}\) ÷ \(\frac{2}{5}\)
= 2 ÷ \(\frac{2}{5}\)
= 2 × \(\frac{5}{2}\)
= 5
Hence, from the above,
We can conclude that
The value of the given expression is: 5

Question 24.
Evaluate the expression for the values of b.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 60.1
Answer:
The given expression is: b (3) + 20.4
Now,
For b = 8.9,
b (3) + 20.4
= 8.9 (3) + 20.4
= 47.1
Now,
For b = 5.1,
b (3) + 20.4
= 5.1 (3) + 20.4
= 35.7
Now,
For b = 0.2,
b (3) + 20.4
= 0.2 (3) + 20.4
= 21
Hence, from the above,
We can conclude that
The value of the given expression for the given values of b is:

Question 25.
Evaluate the expression for the values of j.
Envision Math Common Core 6th Grade Answers Topic 3 Numeric And Algebraic Expressions 60.2
Answer:
The given expression is: 2j + \(\frac{3}{5}\)
Now,
For j = \(\frac{1}{2}\),
2j + \(\frac{3}{5}\)
= 2 (\(\frac{1}{2}\)) + \(\frac{3}{5}\)
= 1 + \(\frac{3}{5}\)
= \(\frac{8}{5}\)
= 1.6
Now,
For j = \(\frac{4}{5}\),
2j + \(\frac{3}{5}\)
= 2 (\(\frac{4}{5}\)) + \(\frac{3}{5}\)
= \(\frac{8}{5}\) + \(\frac{3}{5}\)
= \(\frac{11}{5}\)
= 2.2
For j = 1\(\frac{3}{4}\),
2j + \(\frac{3}{5}\)
= 2 (1\(\frac{3}{4}\)) + \(\frac{3}{5}\)
= \(\frac{14}{4}\) + \(\frac{3}{5}\)
= \(\frac{82}{20}\)
= 4.1
Hence, from the above,
We can conclude that
The value of the given expression for the values of j is:

In 26-28, use the table at the right.

Question 26.
Model with Math
a. Ms. White wants to rent a small car for a week. It will cost the weekly fee plus $0.30 per mile driven. Let m= the number of miles Ms. White drives during the week. Write an expression that shows the amount she will pay for the car.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 60.3
Answer:
It is given that
Ms. White wants to rent a small car for a week. It will cost the weekly fee plus $0.30 per mile driven. Let m= the number of miles Ms. White drives during the week.
Now,
The given table is:

So,
The total amount Ms. White will pay for the car = (The rent of a small car for a week) + (The extra fee for a small car per mile during the week) × (The total number of miles)
= $250 + $0.30m
Hence, from the above,
We can conclude that
The expression that represents the total amount Ms. White will pay for the car is: $250 + $0.30m

b. Evaluate the expression you wrote to find how much Ms. White will pay if she drives 100 miles.
Answer:
From Part (a),
We can observe that
The expression that represents the total amount Ms. White will pay for the car is: $250 + $0.30m
Now,
When Ms. White drives for 100 miles,
The total amount Ms. White will pay for the car if she drives 100 miles = $250 + $0.30 (100)
= $250 + $30
= $280
Hence, from the above,
We can conclude that
The total amount Ms. White will pay for the car if she drives 100 miles is: $280

Question 27.
Mr. Black rents a lu×ury car for one week and a few days, d. He does not pay a per-mile fee. Evaluate the expression 325 + 120d to find how much Mr. Black will pay for an 11-day rental.
Answer:
It is given that
Mr. Black rents a lu×ury car for one week and a few days, d. He does not pay a per-mile fee.
Now,
The given table is:

Now,
According to the given information,
The expression that represents the total amount paid by Mr.Black for one week and a few days is: $325 + $120d
Where
d is the number of few days
Now,
For an 11-day rental,
The total amount paid by Mr.Black for one week and a few days = $325 + $120d
= $325 + $120 (11)
– $325 + $132
= $457
Hence, from the above,
We can conclude that
The total amount Mr.Black will pay for an 11-day rental is: $457

Question 28.
For any of the vehicles listed in the table, how many days can you rent the vehicle before it would be less expensive to rent for the week?
Answer:
The given list of vehicles is:

Now,
When we observe the list,
The least expensive rent is: $250 for a week
Now,
When we observe the rents for a day,
There are only 2 days’ rents that are less than the least expensive rent for a week
Hence, from the above,
We can conclude that
We can rent the vehicle for 2 days before it would be less expensive to rent for the week

In 29 and 30, use the table at the right.

Question 29.
Model with Math
Tamara is making a medium-length necklace. Write an expression that shows how much it will cost Tamara for the chain, pendant, and b beads that cost $0.25 each. Then find the total cost of the necklace if Tamara uses 30 beads.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 60.4
Answer:
It is given that
Tamara is making a medium-length necklace
Now,
The given table is:

So,
The total cost of the medium-length necklace made by Tamara = (The cost of medium length necklace) + (The cost of medium length pendant) + (The cost of each bead) × (The total number of beads)
= $1.80 + $3.72 + $0.25b
= $5.52 + $0.25b
Now,
When there are 30 beads,
The total cost of the medium length necklace made by Tamara when there are 30 beads = $5.52 + $0.25b
= $5.52 + $0.25 (30)
= $13.02
Hence, from the above,
We can conclude that
The total cost of the medium-length necklace made by Tamara, when there are 30 beads, is: $13.02

Question 30.
Higher-Order Thinking Ronnie is making short and long necklaces with only one chain and one pendant per necklace. Write an expression that shows how much it will cost Ronnie to make s short necklaces and n long necklaces. Then find the cost for 3 short necklaces and 2 long necklaces.
Answer:
It is given that
Ronnie is making short and long necklaces with only one chain and one pendant per necklace.
Now,
The given table is:

Now,
The cost of a necklace made by Ronnie = [(The cost of a short-chain) + (The cost of a short pendant)] × (The number of short necklaces) + [(The cost of a long chain) + (The cost of a long pendant)] × (The number of long necklaces)
= ($1.15 + $2.39) × s + ($2.25 + $4.50) × n
= $3.54s +  $6.75n
Where,
s is the number of short necklaces
n is the number of long necklaces
Now,
The cost of 3 short necklaces = $3.54s
= $3.54 × 3
= $10.62
Now,
The cost of 2 long necklaces = $6.75n
= 6.75 × 2
= $13.50
Hence, from the above,
We can conclude that
The expression that represents the cost of a necklace made by Ronnie is: $3.54s + $6.75n
The cost of 3 short necklaces is: $10.62
The cost of 2 long necklaces is: $13.50

Question 31.
Critique Reasoning Katrina says that the expression 5,432 + 4,564 + 13,908 = 61n can be evaluated by adding 5,432 + 4,564 + 13,908 and then dividing by the value of 61n. Do you agree? Explain.
Answer:
It is given that
Katrina says that the expression 5,432 + 4,564 + 13,908 = 61n can be evaluated by adding 5,432 + 4,564 + 13,908 and then dividing by the value of 61n.
Now,
The given expression is: 5,432 + 4,564 + 13,908 = 61n
Now,
We have to find the value of n in the given expression,
Now,
To find the value of n, the following steps have to be followed:
Step 1:
Add 5,432, 4,54, and 13,908
Step 2:
Divide the result that we obtained in step 1 by 61 to get the value of n
But,
According to the given information,
To find the value of the given expression, we have to divide the result that we obtained in step 1 by 61n
Hence, from the above,
We can conclude that
We can not agree with Katrina

Question 32.
The density, d, of an object can be found by using the formula d = \(\frac{m}{V}\), where m is the mass of the object and visits volume. What is the density of an object that has a mass of 73,430 kilograms and a volume of 7 m3?
Answer:
It is given that
The density, d, of an object can be found by using the formula d = \(\frac{m}{v}\), where m is the mass of the object and visits volume
Now,
The given expression is: d = \(\frac{m}{V}\)
Now,
For m = 73,430 Kilograms, and V = 7 m³,
d = \(\frac{73,430}{7}\)
d = 10,490 Kg / m³
Hence, from the above,
We can conclude that
The density of the given object for the given values of m and V is: 10,490 Kg / m³

Question 33.
The formula V = s3 can be used to find the volume of a cube. Use the formula to find the volume, V, of a cube-shaped bin with side length s of \(\frac{2}{3}\) yard.
Answer:
It is given that
The formula V = s3 can be used to find the volume of a cube.
Now,
The given side length of the cube is: \(\frac{2}{3}\) yard
So,
V = (\(\frac{2}{3}\))³
= \(\frac{2}{3}\) × \(\frac{2}{3}\) × \(\frac{2}{3}\)
= \(\frac{2 × 2 × 2}{3 × 3 × 3}\)
= \(\frac{8}{27}\) yard³
Hence, from the above,
We can conclude that
The volume of the cube-shaped bin with the given side length is: \(\frac{8}{27}\) yard³

Question 34.
Katie is evaluating the expression 15.75 ÷ p + 3p when p = 3.15. Explain each step that she should follow.
Answer:
It is given that
Katie is evaluating the expression 15.75 ÷ p + 3p when p = 3.15.
Now,
The given expression is: 15.75 ÷ p + 3p with p = 3.15
Now,
For p = 3.15,
15.75 ÷ p + 3p
= 15.75 ÷ 3.15 + 3 (3.15)
= 5 + 9.45
= 14.45
Hence, from the above,
We can conclude that
The value of the given expression is: 14.45

Assessment Practice

Question 35.
An equation is shown.
5x + (x ÷ 3) = 38.4
Which value of x makes the equation true?
A. x = 5.1
B. x = 5.2
C. x = 6.1
D. x = 7.2
Answer:
The given expression is:
5x + (x ÷ 3) = 38.4
Now,
5x + \(\frac{x}{3}\) = 38.4
\(\frac{16x}{3}\) = 38.4
16x = 38.4 (3)
16x = 115.2
x = \(\frac{115.2}{16}\)
x = 7.2
Hence, from the above,
We can conclude that
The value of x that makes the given equation true is:

3-Act Mathematical Modeling: The Field Trip

3-ACT MATH

Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 62.2

ACT 1

Question 1.
After watching the video, what is the first question that comes to mind?
Answer:

Question 2.
Write the Main Question you will answer.
Answer:

Question 3.
Construct Arguments Make a prediction to answer this Main Question. Explain your prediction.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 62.4
Answer:

Question 4.
On the number line below, write a number that is too small to be the answer. Write a number that is too large.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 62.5
Answer:

Question 5.
Plot your prediction on the same number line.
Answer:

ACT 2

Question 6.
What information in this situation would be helpful to know? How would you use that information?
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 62.6
Answer:

Question 7.
Use Appropriate Tools What tools can you use to solve the problem? Explain how you would use them strategically.
Answer:

Question 8.
Model with Math Represent the situation using mathematics. Use your representation to answer the Main Question.
Answer:

Question 9.
What is your answer to the Main Question? Is it higher or lower than your prediction? Explain why.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 62.7
Answer:

ACT 3

Question 10.
Write the answer you saw in the video.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 62.8
Answer:

Question 11.
Reasoning Does your answer match the answer in the video? If not, what are some reasons that would explain the difference?
Answer:

Question 12.
Make Sense and Persevere Would you change your model now that you know the answer? Explain.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 62.9
Answer:

Reflect

Question 13.
Model with Math explain how you used a mathematical model to represent the situation. How did the model help you answer the Main Question?
Answer:

Question 14.
Critique Reasoning A classmate said your model works for any number of students and adults. Do you agree? Justify your reasoning or explain your classmate’s error.
Answer:

SEQUEL

Question 15.
Generalize Suppose the entire grade goes on the field trip: 283 students and 10 teachers. Each bus holds 72 people and costs $610 for transport. How much money is needed? Explain how you reused your model.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 65.1
Answer:

Lesson 3.6 Generate Equivalent expressions

ACTIVITY

Explain It!
Juwon says all three expressions are equivalent.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 65.3

A. Find the value of each expression for n = 1.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 65.4
Answer:
It is given that
Juwon says all three expressions are equivalent.
Now,
For n = 1,
The value of each expression will be:

Hence, from the above,
We can conclude that

B. Find the value of each expression for n = 2.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 65.5
Answer:
It is given that
Juwon says all three expressions are equivalent.
Now,
For n = 2,
The value of each expression will be:

Hence, from the above,
We can conclude that

C. Critique Reasoning Do you agree with Juwon that all three expressions are equivalent? Explain.
Answer:
According to Juwon,
The expressions are:
a. 8n + 6
b. 2 (4n + 3)
c. 14n
Now,
From (a),
8n + 6 = 2 (4n + 3) ≠ 14n
Hence, from the above,
We can conclude that
We can not agree with Juwon that all the three expressions are equivalent

Focus on math practices
Generalize When a number is substituted for the same variable in two expressions, how many times must those two expressions have different values before you know they are not equivalent? Explain.
Answer:
When a number is substituted for the same variable in two expressions, those two expressions must have  2 different values before you know they are not equivalent

VISUAL LEARNING

? Essential Question How can you identify and write equivalent expressions?
Answer:
Combine any like terms on each side of the equation x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.

Try It!
Write an expression that is equivalent to 3y – 9.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 70.1
Answer:
The given expression is: 3y – 9
Now,

Hence, from the above,
We can conclude that
3y – 9 is equivalent to 3 (y – 3)

Convince Me! Why can you use properties of operations to write equivalent expressions?
Answer:
The properties of operations used to write equivalent expressions are:
a. Commutative Property of Addition: When adding, changing the order of the numbers does not change the sum.
b. Commutative Property of Multiplication
c. Associative Property of Addition
d. Associative Property of Multiplication
e. Distributive Property

Try It!
Which of the following expressions are equivalent? Explain.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 70.2
Answer:
The given expressions are:
a. 10y + 5    b. 15y     c. 5 (2y + 1)
Now,
10y + 5 = 5 (2y + 1)
Hence, from the above,
We can conclude that
10y + 5 and 5 (2y + 1) are equivalent expressions

Try It!
Are 2(x – 3) + 1 and 2x + 6 equivalent expressions? Use substitution to justify your work.
Answer:
The given expressions are: 2 (x – 3) + 1 and 2x + 6
Now,
2 (x – 3) + 1 = 2 (x) – 2 (3) + 1
= 2x – 6 + 1
= 2x – 5
So,
2x – 5 ≠ 2x + 6
Hence, from the above,
We can conclude that
2 (x – 3) + 1 and 2x + 6 are not equivalent expressions

KEY CONCEPT
Two algebraic expressions are equivalent if they have the same value when any number is substituted for the variable. You can use the properties of operations to write equivalent expressions.

Properties of Operations
1 Commutative Property
of Addition a + b = b + a
of Multiplication a × b = b × a
2 Associative Property
of Addition (a + b) + c = a + (b + c)
of Multiplication (a × b) × c = a × (b × c)
3 Distributive Property
across Addition a(b + c) = a(b) + a(c)
across Subtraction a(b – c) = a(b) – a(c)

Do You Understand?

Question 1.
? Essential Question How can you identify and write equivalent expressions?
Answer:
Combine any like terms on each side of the equation x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.

Question 2.
Use Structure which property of operations could you use to write an equivalent expression for y + \(\frac{1}{2}\)? Write the equivalent expression.
Answer:
The given expression is: y + \(\frac{1}{2}\)
Now,
To write the equivalent expression for the given expression,
We will use “Distributive Property of Addition”
Now,
y + \(\frac{1}{2}\)
= \(\frac{2 (y) + 1}{2}\)
= \(\frac{2y + 1}{2}\)
So,
The equivalent expression for the given expression is: \(\frac{2y + 1}{2}\)
Hence, from the above,
We can conclude that
The property of operation you could use to write y + \(\frac{1}{2}\) is: Distributive Property of Addition
The equivalent expression for y + \(\frac{1}{2}\) is: \(\frac{2y + 1}{2}\)

Question 3.
Generalize Are z3 and 3z equivalent expressions? Explain.
Answer:
The given expressions are: z³ and 3z
Now,
z³ = z × z × z
3z = z + z + z
Hence, from the above,
We can conclude that
z³ and 3z are not equivalent expressions

Question 4.
Are the expressions 3(y + 1) and 3y + 3 equivalent for y = 1? y = 2? y = 3?
Answer:
The given expressions are: 3 (y + 1) and 3y + 3
Now,
For y = 1,
3 (y + 1) = 3 (1 + 1)
= 3 (2) = 6
3y + 3 = 3 (1) + 3
= 3 + 3 = 6
Now,
For y = 2,
3 (y + 1) = 3 (2 + 1)
= 3 (3) = 9
3y + 3 = 3 (2) + 3
= 6 + 3 = 9
Now,
For y = 3,
3 (y + 1) = 3 (3 + 1)
= 3 (4) = 12
3y + 3 = 3 (3) + 3
= 9 + 3 = 12
So,
For y = 1, y = 2, and y = 3
3 (y + 1) = 3y + 3
Hence, from the above,
We can conclude that
3 (y + 1) is equivalent to 3y + 3 for y = 1, y = 2, and y = 3

Question 5.
Construct Arguments Are the expressions 3(y + 1) and 3y + 3 equivalent for any value of y? Explain.
Answer:
The given expressions are: 3 (y + 1) and 3y + 3
Now,
3 (y + 1) = 3 (y) + 3 (1)
= 3y + 3
So
3 (y + 1) = 3y + 3
Where,
y will be an integer or a whole number
Hence, from the above,
We can conclude that
The expressions 3 (y + 1) and 3y + 3 are equivalent for any value of y

Do You Know How?

In 6-8, use properties of operations to complete the equivalent expressions.

Question 6.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 80.1
Answer:
The given expression is: 2 (r + 3)
Now,

Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 2r + 6

Question 7.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 80.2
Answer:
The given expression is: 6 (4s – 1)
Now,

Hence, from the above,
We can conclude that
The equivalent expression for the given expression is 24s – 6

Question 8.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 80.3
Answer:
The given expression is: 8t + 2
Now,

Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 2 (4t + 1)

Question 9.
Complete the table below.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 80.4
Answer:
The given expressions are:
a. 12x – 6    b. 3x + 3    c. 6 (2x – 1)
Now,
a.
For x = 1,
12x – 6 = 12 (1) – 6
= 12 – 6
= 6
For x = 2,
12x – 6 = 12 (2) – 6
= 24 – 6
= 18
For x = 3,
12x – 6 = 12 (3) – 6
= 36 – 6
= 30
b.
For x = 1,
3x + 3 = 3 (1) + 3
= 3 + 3
= 6
For x = 2,
3x + 3 = 3 (2) + 3
= 6 + 3
= 9
For x = 3,
3x + 3 = 3 (3) + 3
= 9 + 3
= 12
c.
For x = 1,
6 (2x – 1) = 6 [ 2 (1) – 1]
= 6
For x = 2,
6 (2x – 1) = 6 [2 (2) – 1]
= 18
For x = 3,
6 (2x – 1) = 6 [2 (3) – 1]
= 30
Hence, from the above,
We can conclude that
The completed table is:

Question 10.
In exercise 9, which expressions in the table are equivalent?
Answer:
From Exercise 9,
The completed table is:

Now,
From the given table,
We can observe that
The values are the same for 12x – 6 and 6 (2x – 1) i.e.,
12x – 6 = 6 (2x – 1)
Hence, from the above,
We can conclude that
12x – 6 and 6 (2x – 1) are equivalent expressions

Practice & Problem Solving

Scan for Multimedia

Leveled Practice
In 11-20, write equivalent expressions.

Question 11.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 80.5
Answer:
The given expression is: 3 (m + 3)
Now,
3 (m + 3) = 3 (m) + 3 (3)
= 3m + 9
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 3m + 9

Question 12.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 80.6
Answer:
The given expression is: 20n – 4m
Now,
20n – 4m = 4 (5n) – 4 (m)
= 4 (5n – m)
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 4 (5n – m)

Question 13.
3(x – 6)
Answer:
The given expression is: 3 (x – 6)
Now,
3 (x – 6) = 3 (x) – 3 (6)
= 3x – 18
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 3x – 18

Question 14.
2x + 10
Answer:
The given expression is: 2x + 10
Now,
2x + 10 = 2 (x) + 2 (5)
= 2 (x  + 5)
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 2 (x + 5)

Question 15.
8(2y + \(\frac{1}{4}\))
Answer:
The given expression is: 8 (2y + \(\frac{1}{4}\))
Now,
8 (2y + \(\frac{1}{4}\)) = 8 (2y) + 8 (\(\frac{1}{4}\))
= 16y + 2
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 16y + 2

Question 16.
5.7 + (3z + 0.3)
Answer:
The given expression is: 5.7 + (3z + 0.3)
Now,
5.7 + (3z + 0.3) = 3z + (5.7 + 0.3)
= 3z + 6
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 3z + 6

Question 17.
5w – 15
Answer:
The give expression is: 5w – 15
Now,
5w – 15 = 5 (w) – 5 (3)
= 5 (w – 3)
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 5 (w – 3)

Question 18.
2x + 4y
Answer:
The given expression is: 2x + 4y
Now,
2x + 4y = 2 (x) + 2 (2y)
= 2 (x + 2y)
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 2 (x + 2y)

Question 19.
10(y2 + 2.45)
Answer:
The given expression is: 10 (y² + 2.45)
Now,
10 (y² + 2.45) = 10 (y²) + 10 (2.45)
= 10y² + 24.5
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 10y² + 24.5

Question 20.
\(\frac{3}{4}\) • (z3•4)
Answer:
The given expression is: \(\frac{3}{4}\) × (z³ × 4)
Now,
\(\frac{3}{4}\) × (z³ × 4) = z³ × \(\frac{3}{4}\) × 4
= 3z³
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 3z³

In 21-24, write the letters of the expressions that are equivalent to the given expression.

Question 21.
5(2x + 3)
a. 10x + 15
b. 5x + 15 + 5x
c. 10x + 8
Answer:
The given expression is: 5 (2x + 3)
Now,
5 (2x + 3) = 5 (2x) + 5 (3)
= 10x + 15
Hence, from the above,
We can conclude that
The expression that is equivalent to the given expression is:

Question 22.
4x – 8
a. 2(2x – 6)
b. 2(2x – 4)
c. x – 8 + 3x
Answer:
The given expression is: 4x – 8
Now,
4x – 8 = 4 (x – 2)
= 3x + x – 8
= 2 (2x – 4)
Hence, from the above,
We can conclude that
The expressions that are equivalent to the given expression is:

Question 23.
12x – 16
a. 9.6x – 16+ 2.4x
b. 3(3x – 5)
c. 4(3x – 4)
Answer:
The given expression is: 12x – 16
Now,
12x – 16 = 4 (3x – 4)
= 9.6x + 2.4x – 16
Hence, from the above,
We can conclude that
The expressions that are equivalent to the given expression is:

Question 24.
2(6x + \(\frac{1}{2}\))
a. 12x + 2
b. 12x + 1
c. 6x + \(\frac{1}{2}\) + 6x + \(\frac{1}{2}\)
Answer:
The given expression is: 2 (6x + \(\frac{1}{2}\))
Now,
2 (6x + \(\frac{1}{2}\))
= 6x + 6x + \(\frac{1}{2}\) + \(\frac{1}{2}\)
= 12x + 1
Hence, from the above,
We can conclude that
The expressions that are equivalent to the given expression is:

In 25-27, use the signs at the right.

Question 25.
Write an algebraic expression that represents each purchase.
a. Mr. Tonkery bought x number of soccer balls and 3 baseballs.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 82.1

Answer:
It is given that
Mr. Tonkery bought x number of soccer balls and 3 baseballs.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 82.1
So,
The total purchase made by Mr. Tonkery = (The number of soccer balls) × (The cost of each soccer ball) + (The number of baseballs) × (The cost of each baseball)
= (x × $15) + (3 × $6)
= $15x + $18
Hence, from the above,
We can conclude that
The algebraic expression that represents Mr. Tonkery’s purchase is: $15x + $18

b. Dennis, Eddie, and Felix are on a baseball team. They each bought a baseball and x pairs of sweat socks.
Answer:
It is given that
Dennis, Eddie, and Felix are on a baseball team. They each bought a baseball and x pairs of sweat socks.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 82.1
So,
The total purchase made by Dennis, Eddie, and Felix = (The number of baseballs purchased by the three of them) × (The cost of each baseball) + (The number of sweat socs purchased by the three of them) × (The cost of each sweat socks)
= (3 × $6) + (3x × $5)
= $15x + $18
Hence, from the above,
We can conclude that
The algebraic expression that represents the total purchase made by Dennis, Eddie, and Felix is: $15x + $18

Question 26.
Make Sense and Persevere Suppose x has the same value in both of the expressions you wrote for exercise 25. Are the two expressions you wrote equivalent? Explain.
Answer:
It is given that
x has the same value in both of the expressions you wrote for exercise 25.
So,
From Part (a) and part (b) of Exercise 25,
$15x + $18 = $15x + $18
Hence, from the above,
We can conclude that
The two expressions in exercise 25’s part (a) and part (b) are equivalents

Question 27.
Critique Reasoning Wendy says that soccer balls cost 2\(\frac{1}{2}\) times as much as baseballs. Do you agree? Explain.
Answer:
It is given that
Wendy says that soccer balls cost 2\(\frac{1}{2}\) times as much as baseballs.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 82.1
Now,
From the given figure,
We can observe that
The cost of each soccer ball is: $15
The cost of each baseball is: $6
Now,
Let the number of times as soccer balls as many as base balls be x
So,
x × $6 = $15
x = \(\frac{15}{6}\)
x = \(\frac{5}{2}\)
x = 2\(\frac{1}{2}\)
Hence, from the above,
We can conclude that
We can agree with Wendy

Question 28.
Use Structure Write an algebraic expression to represent the area of the rectangular rug. Then use properties of operations to write an equivalent expression.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 83.1
Answer:
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 83.1
Now,
From the above figure,
We can observe that
The length of the rectangular rug is: 2 (x – 1)
The width of the rectangular rug is: 5
Now,
We know that,
The area of a rectangle = Length × Width
So,
The area of a rectangular rug = 2 (x – 1) × 5
= [2 (x) – 2 (1)] × 5
= (2x – 2) × 5
= 5 (2x) – 5 (2)
= 10x – 10
Hence from the above,
We can conclude that
The algebraic expression that represents the area of the given rectangular rug is: 10x – 10

Question 29.
Critique Reasoning Jamie says that the expressions 6x – 2x + 4 and 4(x + 1) are not equivalent because one expression has a term that is subtracted and the other does not. Do you agree? Explain.
Answer:
It is given that
Jamie says that the expressions 6x – 2x + 4 and 4(x + 1) are not equivalent because one expression has a term that is subtracted and the other does not.
Now,
The given expressions are: 6x – 2x + 4 and 4 (x + 1)
Now,
6x – 2x + 4 = 4x + 4
Now,
4 (x + 1) = 4 (x) + 4 (1)
= 4x + 4
So,
6x – 2x + 4 = 4x + 4
Hence, from the above,
We can conclude that
We can not agree with Jamie

Question 30.
Are the two expressions shown below equivalent? Explain.
4(n + 3) – (3 + n) and 3n + 9
Answer:
The given expressions are: 4 (n + 3) – (3 + n) and 3n + 9
Now,
4 (n + 3) – (3 + n) = 4 (n) + 4 (3) – 3 – n
= 4n + 12 – 3 – n
= 3n + 9
So,
4 (n + 3) – (3 + n) = 3n + 9
Hence, from the above,
We can conclude that
The given two expressions are equivalent expressions

Question 31.
Critique Reasoning Chris says that the expression 4n – 2 can be written as 2(2n – 1). Do you agree? Explain.
Answer:
It is given that
Chris says that the expression 4n – 2 can be written as 2(2n – 1)
Now,
The given expression is: 4n – 2
Now,
4n – 2 = 2 (2n – 1)
Hence, from the above,
We can conclude that
We can agree with Chris

Question 32.
Higher Order Thinking Write an expression that has only one term and is equivalent to the expression below.
(f • g2) + 5 – (g2 • f)
Answer:
The given expression is: (f × g²) + 5 – (g² ×f )
Now,
We know that,
According to the Associative Property of Multiplication,
a × b = b × a
So,
f × g² = g² × f
So,
(f × g²) + 5 – (g² ×f ) = 0 + 5
= 5
Hence, from the above,
We can conclude that
The expression that has only one term and is equivalent to the given expression is: 5

Question 33.
Construct Arguments A Florida college golf team with 14 members is planning an awards banquet. To find the total cost of the meals, the team uses the expression 5(g + 14), where g is the number of guests attending the banquet. A team member says that an equivalent expression is 5g + 14. Do you agree? Explain.
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 84.1
Answer:
It is given that
A Florida college golf team with 14 members is planning an awards banquet. To find the total cost of the meals, the team uses the expression 5(g + 14), where g is the number of guests attending the banquet. A team member says that an equivalent expression is 5g + 14
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 3 Numeric And Algebraic Expressions 84.1
Now,
The given expression is:
5 (g + 14) = 5 (g) + 5 (14)
= 5g + 70
So,
5 (g + 14) ≠ 5g + 14
Hence, from the above,
We can conclude that
We can not agree that the equivalent expression of 5 (g + 14) is 5g + 14

Assessment Practice

Question 34.
Select each expression that is equivalent to 8.5 + (2s + 0.5).
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 (8.5 + 2s) + 0.5
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 (8.5 + 0.5) + 2s
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 9 + 2
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 2(4.5 + s)
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 8.5(2s + 0.5)
Answer:
The given epression is: 8.5 + (2s + 0.5)
Hence, from the above,
We can conclude that
The expressions that are equivalent to 8.5 + (2s + 0.5) are:

Question 35.
Select each expression that is equivalent to 5(n + 4).
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 5n + 4
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 5n + 20
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 15 + 5n + 5
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 5(n + 3) + 5
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85 5n + 54
Answer:
The given expression is: 5 (n + 4)
Hence, from the above,
We can conclude that
The expressions that are equivalent to 5 (n + 4) are:

Lesson 3.7 Simplify Algebraic expressions

Solve & Discuss It!

Write an expression equivalent to x + 5 + 2x + 2.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85.1
Make Sense and Persevere Use what you know about algebraic expressions and properties of operations to make sense of the problem.
Answer:
The given expression is: x + 5 + 2x + 2
Now,
We know that,
The terms that have the same variable are called “Like terms” and we use the Order of operations to write the equivalent expression
So,
x + 5 + 2x + 2 = (x + 2x) + (5 + 2)
= 3x + 7
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 3x + 7

Focus on math practices
Be Precise How do you know that the expression you wrote is equivalent to x + 5 + 2x + 2?
Answer:
The given expression is: x + 5 + 2x + 2
Now,
We know that,
The terms that have the same variable are called “Like terms” and we use the Order of operations to write the equivalent expression
Hence, from the above,
We can conclude that
We will use the Order of operations and “Like terms” to solve the given expression for its equivalent expression

VISUAL LEARNING

? Essential Question How can you simplify algebraic expressions?
Answer:
The steps to simplify the algebraic expressions are:
a. When simplifying mathematical expressions perform the operations in the following order: Parentheses and other Grouping Symbols.
b. Exponents.
c. Multiplication and Division.
d. Addition and Subtraction.

Try It!
Simplify the expression 4z – z + z – 2z.

4z – z + z – 2z
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 85.2
Answer:
The given expression is: 4z – z + z – 2z
Now,

Hence, from the above,
We can conclude that
The value of the given expression is: 2z

Convince Me! How do you know that the expression 2x + 4y is not equivalent to 6xy?
Answer:
The given expressions are: 2x + 4y and 6xy
Now,
2x + 4y = 2 (x + 2y)
Now,
When we observe the two expressions,
2x + 4y contains “Addition” operation
6xy contains only the “Product” operation
So,
2x + 4y ≠ 6xy
Hence, from the above,
We can conclude that
2x + 4y is not equivalent to 6xy with the help of arithmetic symbols

Try It!
Park rangers add another section to the trail, represented by the expression in \(\frac{1}{2}\)n + n + \(\frac{1}{2}\). Write an expression for the new total length of the trail. Then write a simplified equivalent expression.
Answer:
It is given that
Park rangers add another section to the trail, represented by the expression in \(\frac{1}{2}\)n + n + \(\frac{1}{2}\)
Now,
The given figure is:

So,
The new total length of the trail = (The old total length of the trail that is present in Example 2) + \(\frac{1}{2}\) + n + \(\frac{1}{2}\)
= 3\(\frac{2}{3}\)n + 4 + \(\frac{1}{2}\)n + n + \(\frac{1}{2}\)
= \(\frac{11}{3}\)n + 4 + \(\frac{1}{2}\)n + n + \(\frac{1}{2}\)
= \(\frac{11}{3}\)n + \(\frac{3}{2}\)n + \(\frac{9}{2}\)
= \(\frac{31}{6}\)n + \(\frac{9}{2}\)
Hence, from the above,
We can conclude that
The simplified expression of the new total length of the trail is: \(\frac{31}{6}\)n + \(\frac{9}{2}\)

Try It!
Suppose Vanna increases her rate by 3.5 times and her expenses also increase by 3.5 times this summer. Write two equivalent expressions to represent how much she can earn mowing and raking grass.
Answer:
It is given that
Vanna increases her rate by 3.5 times and her expenses also increase by 3.5 times this summer.
Now,
The given figure is:

So,
The algebraic expression that represents the amount of money Vanna can earn from mowing and raking grass = 3.5 ($20.50x + $5.50x – $10)
Now,
By using the Distributive Property,
3.5 ($20.50x + $5.50x – $10)
= 3.5 ($26x – $10)
= 3.5 ($26x) – 3.5 ($10)
= $91x – $35
= 7 ($13x – $5)
Hence, from the above,
We can conclude that
The two equivalent expressions that represent the amount of money Vanna earned from mowing and raking grass is:
$91x – $35 (or) 7 ($13x – $5)

KEY CONCEPT
You can combine like terms to write equivalent expressions. Like terms have the same variable part.
2x + 6 + 5x + 4 ……… Identify like terms
= 2x + 5x + 6 + 4 ………… Commutative Property of Addition
= 7x + 10
2x + 6 + 5x + 4 = 7x + 10

Do You Understand?

Question 1.
? Essential Question How can you simplify algebraic expressions?
Answer:
The steps to simplify the algebraic expressions are:
a. When simplifying mathematical expressions perform the operations in the following order: Parentheses and other Grouping Symbols.
b. Exponents.
c. Multiplication and Division.
d. Addition and Subtraction.

Question 2.
Explain how you know which terms to combine when combining like terms.
Answer:
The terms that have identical variable parts (same variable(s) and same exponent(s)) are called “Like terms”. When simplifying using addition and subtraction, you combine “like terms” by keeping thelike term” and adding or subtracting the numerical coefficients

Question 3.
Construct Arguments Explain why the expression 2y – y can be written as y.
Answer:
The given expression is: 2y – y
Now,
By using the Order of operations,
2y – y = 2y – 1y
= y (2 – 1)
= y (1)
= y
Hence, from the above,
We can conclude that
2y – y can be written as y by using the Order of operations

Question 4.
Explain why the expressions \(\frac{1}{2}\)x + \(\frac{1}{2}\)x and x are equivalent.
Answer:
The given expression is: \(\frac{1}{2}\)x + \(\frac{1}{2}\)x
Now,
By using the order of Operations,
\(\frac{1}{2}\)x + \(\frac{1}{2}\)x
= \(\frac{x}{2}\) + \(\frac{x}{2}\)
= \(\frac{x + x}{2}\)
= \(\frac{2x}{2}\)
= \(\frac{x}{1}\)
= x
So,
\(\frac{1}{2}\)x + \(\frac{1}{2}\)x = x
Hence, from the above,
We can concldue that
\(\frac{1}{2}\)x + \(\frac{1}{2}\)x and x are equivalents by using the properties of addition in fraction and order of operations

Question 5.
Critique Reasoning Henry wrote 4z2 – z2 as 4. Are 4z2 – z2 and 4 equivalent expressions? Explain.
Answer:
The given expression is: 4z² – z²
Now,
By using the order of operations,
4z2 – z2
= 4z2 – 1z2
= z2 (4 – 1)
= z2 (3)
= 3z2
So,
4z2 – z2  ≠ 4
Hence, from the above,
We can conclude that
4z2 – z2 is not equivalent to 4

Do You Know How?

In 6-15, simplify each expression.

Question 6.
x + x + x + x
Answer:
The given expression is: x + x + x + x
Now,
By using the Order of Operations,
x + x + x + x
= 1x + 1x + 1x + 1x
= x (1 + 1 + 1 + 1)
= x (4)
= 4x
Hence, from the above,
We can conclude that
The value of the given expression is: 4x

Question 7.
4y – y
Answer:
The given expression is: 4y – y
Now,
By using the Order of Operations,
4y – y
= 4y – 1y
= y (4 – 1)
= y (3)
= 3y
Hence, from the above,
We can conclude that
The value of the given expression is: 3y

Question 8.
7y – 4.5 – 6y
Answer:
The given expression is: 7y – 4.5 – 6y
Now,
By using the Order of Operations,
7y – 4.5 – 6y
= (7y – 6y) – 4.5
= y – 4.5
Hence, from the above,
We can conclude that
The value of the given expression is: y – 4.5

Question 9.
4x + 2 – \(\frac{1}{2}\)x
Answer:
The given expression is: 4x + 2 – \(\frac{1}{2}\)x
Now,
By using the Order of Operations,
4x + 2 – \(\frac{1}{2}\)x
= (4x – \(\frac{1}{2}\)x) + 2
= \(\frac{8x – x}{2}\) + 2
= \(\frac{7x}{2}\) + 2
Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{7x}{2}\) + 2

Question 10.
3 + 3y – 1 + y
Answer:
The given expression is: 3 + 3y – 1 + y
Now,
By using the Order of Operations,
3 + 3y – 1 + y
= (3 – 1) + (3y + y)
= 2 + 4y
= 4y + 2
Hence, from the above,
We can conclude that
The value of the given expression is: 4y + 2

Question 11.
x + 6x
Answer:
The given expression is: x + 6x
Now,
By using the Order of Operations,
x + 6x
= 1x + 6x
= x (1 + 6)
= x (7)
= 7x
Hence, from the above,
We can conclude that
The value of the given expression is: 7x

Question 12.
0.5w + 1.7w – 0.5
Answer:
The given expression is: 0.5w + 1.7w – 0.5
Now,
By using the Order of Operations,
0.5w + 1.7w – 0.5
= (0.5w + 1.7w) – 0.5
= w (0.5 + 1.7) – 0.5
= 2.2w – 0.5
Hence, from the above,
We can conclude that
The value of the given expression is: 2.2w – 0.5

Question 13.
12\(\frac{1}{3}\)b + 6\(\frac{2}{3}\) – 10\(\frac{2}{3}\)b
Answer:
The given expression is:
12\(\frac{1}{3}\)b + 6\(\frac{2}{3}\) – 10\(\frac{2}{3}\)b
Now,
Convert the given mixed numbers into fractions
So,
The given expression is: \(\frac{37}{3}\)b + \(\frac{20}{3}\) – \(\frac{32}{3}\)b
Now,
By using the Order of Operations,
\(\frac{37}{3}\)b + \(\frac{20}{3}\) – \(\frac{32}{3}\)b
= (\(\frac{37}{3}\)b – \(\frac{32}{3}\)b) + \(\frac{20}{3}\)
= b (\(\frac{37}{3}\) – \(\frac{32}{3}\)) + \(\frac{20}{3}\)
= \(\frac{5}{3}\)b + \(\frac{20}{3}\)
= \(\frac{1}{3}\) (5b + 20)
Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{1}{3}\) (5b + 20)

Question 14.
\(\frac{3}{4}\)x + 2 + 3x – \(\frac{1}{2}\)
Answer:
The given expression is: \(\frac{3}{4}\)x + 2 + 3x – \(\frac{1}{2}\)
Now,

Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{15}{4}\)x + \(\frac{3}{2}\)

Question 15.
3.2x + 6.5 – 2.4x – 4.4
Answer:
The given expression is: 3.2x + 6.5 – 2.4x – 4.4
Now,
By using the Order of Operations,
3.2x + 6.5 – 2.4x – 4.4
= (3.2x – 2.4x) + (6.5 – 4.4)
= x (3.2 – 2.4) + 2.1
= x (0.8) + 2.1
= 0.8x + 2.1
Hence, from the above,
We can conclude that
The value of the given expression is: 0.8x + 2.1

Practice & Problem Solving

Scan for Multimedia

Leveled Practice
In 16-26, combine like terms to simplify each expression.

Question 16.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 90.1
Answer:
The given expression is: 2.1x² + 3 – 0.5x² – 1
Now,
2.1x² + 3 – 0.5x² – 1

Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{8}{5}\)x² + 2

Question 17.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 90.2
Answer:
The given expression is: \(\frac{2}{3}\)n + 6 +3n – \(\frac{2}{3}\)
Now,
\(\frac{2}{3}\)n + 6 +3n – \(\frac{2}{3}\)

Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{11}{3}\)n + \(\frac{16}{3}\)

Question 18.
5 + 3w + 3 – w
Answer:
The given expression is: 5 + 3w + 3 – w
Now,
5 + 3w + 3 – w

Hence, from the above,
We can conclude that
The value of the given expression is: 2w + 8

Question 19.
5w – 5w
Answer:
The given expression is: 5w – 5w
Now,
5w – 5w
= w (5 – 5)
= w (0)
= 0
Hence, from the above,
We can conclude that
The value of the given expression is: 0

Question 20.
2x + 5 + 3x + 6
Answer:
The givene xpression is: 2x + 5 + 3x + 6
Now,
2x + 5 + 3x + 6

Hence, from the above,
We can conclude that
The value of the given expression is: 5x + 11

Question 21.
\(\frac{3}{4}\)z3 + 4 – \(\frac{1}{4}\)z3
Answer:
The given expression is: \(\frac{3}{4}\)z3 + 4 – \(\frac{1}{4}\)z3
Now,
\(\frac{3}{4}\)z3 + 4 – \(\frac{1}{4}\)z3

Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{1}{2}\)z³ + 4

Question 22.
3.4m + 2.4m
Answer:
The given expression is: 3.4m + 2.4m
Now,
3.4m + 2.4m
= m (3.4 + 2.4)
= m (5.8)
= 5.8m
Hence, from the above,
We can conclude that
The value of the given expression is: 5.8m

Question 23.
4.2n + 5 – 3.2n
Answer:
The givene xpression is: 4.2n + 5 – 3.2n
Now,
4.2n + 5 – 3.2n
= (4.2n – 3.2n) + 5
= n (4.2 – 3.2) + 5
= n (1) + 5
= n + 5
Hence, from the above,
We can conclude that
The value of the given expression is: n + 5

Question 24.
q5 + q5 + q5
Answer:
The given expression is: q5 + q5 + q5
Now,
q5 + q5 + q5
= q5 (1 + 1 + 1)
= q5 (3)
= 3q5
Hence, from the above,
We can conclude that
The value of the given expression is: 3q5

Question 25.
3x + \(\frac{1}{4}\) + 2y + \(\frac{1}{4}\) + 7x – y
Answer:
The given expression is: 3x + \(\frac{1}{4}\) + 2y + \(\frac{1}{4}\) + 7x – y
Now,
3x + \(\frac{1}{4}\) + 2y + \(\frac{1}{4}\) + 7x – y

Hence, from the above,
We can conclude that
The value of the given expression is: 10x + y + \(\frac{1}{2}\)

Question 26.
1.5z2 + 4.5 + 6z – 0.3 – 3z + z2
Answer:
The given expression is: 1.5z2 + 4.5 + 6z – 0.3 – 3z + z2
Now,
1.5z2 + 4.5 + 6z – 0.3 – 3z + z2

Hence, from the above,
We can conclude that
The value of the given expression is: \(\frac{5}{2}\)z² + 3z + \(\frac{21}{5}\)

Question 27.
Use Structure Use the table at the right. Yolanda is planning a party that will take place in three rooms.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 90.6
a. Write an expression that can be used to represent the total amount Yolanda will need to rent all three rooms and the sound system for t hours.
Answer:
It is given that
Yolanda is planning a party that will take place in three rooms.
Now,
The given table is:
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 90.6
So,
The amount of money Yolanda will need to rent all three rooms and the sound system for t hours =
(The total rental fee of the three rooms per hour) × (The total number of hours the three rooms are rented) + (The total fee of Sound system)
= ($25 + $20 + $50) × t + ($15 + $10)
= $95 × t + $25
= $95t + $25
Hence, from the above,
We can conclude that
The expression that can be used to represent the total amount Yolanda will need to rent all three rooms and the sound system for t hours is: $95t + $25

b. How can you use a property to write a simplified equivalent expression?
Answer:
The properties used to write a simplified equivalent expression are:
a. Commutative Property of Addition : When adding, changing the order of the numbers does not change the sum.
b. Commutative Property of Multiplication
c. Associative Property of Addition
d. Associative Property of Multiplication
e. Distributive Property

In 28-30, use the diagram at the right.

Question 28.
Write an algebraic expression for the perimeter of the swimming pool.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 91.1
Answer:
The given figure is:
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 91.1
Now,
From the given figure,
We can observe that
The swimming pool is in the form of a rectangle
Now,
From the given figure,
We can observe that
The length of the swimming pool is: 2y + 1
The width of the swimming pool is: y
Now,
We know that,
The perimeter of a recatngle = 2 × (Length + Width)
So,
The perimeter of the given swimming pool = 2 × (Length of the swimming pool + Width of the swimming pool)
= 2 × (2y + 1 + y)
= 2 × (3y + 1)
= 2 (3y + 1)
Hence,f rom the above,
We can conclude that
The algebraic expression that represents the perimeter of the swimming pool is: 2 (3y + 1)

Question 29.
Use Structure Write a new expression equivalent to the expression you wrote for exercise 28.
Answer:
From Exercise 28,
We know that,
The algebraic expression that represents the perimeter of the swimming pool is: 2 (3y + 1)
Now,
The given expression is: 2 (3y + 1)
Now,
2 (3y + 1)
= 2 (3y) + 2 (1)
= 6y + 2
Hence, from the above,
We can conclude that
The new expression that is equivalent to the expression you wrote for Exercise 28 is: 6y + 2

Question 30.
Justify that the two expressions are equivalent.
Answer:
From Exercise 28 and 29
We know that,
The expressions are: 2 (3y + 1) and 6y + 2
Now,
2 (3y + 1) = 2 (3y) + 2 (1)
= 6y + 2
So,
2 (3y + 1) = 6y + 2
Hence, from the above,
We can conclude that
The two expressions that are from Exercise 28 and Exercise 29 are equivalent expressions

Question 31.
Rodney rewrote the expression \(\frac{1}{2}\)(2x + 7) as x + 3\(\frac{1}{2}\). Which property of operations did Rodney use?
Answer:
It is given that
Rodney rewrote the expression \(\frac{1}{2}\)(2x + 7) as x + 3\(\frac{1}{2}\).
Now,
The given expression is: \(\frac{1}{2}\) (2x + 7)
Now,
By using the Distributive Property,
\(\frac{1}{2}\) (2x + 7)
= \(\frac{1}{2}\) (2x) + \(\frac{1}{2}\) (7)
= \(\frac{2x}{2}\) + \(\frac{7}{2}\)
= x + \(\frac{7}{2}\)
= x + 3\(\frac{1}{2}\)
Hence, from the above,
We can conclude that
Rodney used “Distributive Property” to solve the given expression

Question 32.
Construct Arguments Annie said that she simplified the expression 6.5(x + 0.5x + 1) by writing the equivalent expression 6.5x + 3.25x + 6.5. Do you agree? Explain.
Answer:
It is given that
Annie said that she simplified the expression 6.5(x + 0.5x + 1) by writing the equivalent expression 6.5x + 3.25x + 6.5
Now,
The given expression is: 6.5 (x + 0.5x + 1)
Now,
By using the Distributive Property,
6.5 (x + 0.5x + 1)
= 6.5 (x) + 6.5 (0.5x) + 6.5 (1)
= 6.5x + 3.25x + 6.5
Hence,from the above,
We can conclude that
We can agree with Annie

Question 33.
Critique Reasoning Thea said that the expressions 4x – 3x + 2 and x + 2 are equivalent. Is Thea correct? Explain.
Answer:
It is given that
Thea said that the expressions 4x – 3x + 2 and x + 2 are equivalent.
Now,
The given expression is: 4x – 3x + 2
Now,
4x – 3x + 2
= (4x – 3x) + 2
= x + 2
So,
4x – 3x + 2 = x + 2
Hence, from the above,
We can conclude that
Thea is correct

Question 34.
Higher Order Thinking Write an equivalent expression for the expression shown below.
\(\frac{a}{3}\) + \(\frac{a}{3}\) + \(\frac{a}{3}\)
Answer:
The given expression is:
\(\frac{a}{3}\) + \(\frac{a}{3}\) + \(\frac{a}{3}\)
Now,
\(\frac{a}{3}\) + \(\frac{a}{3}\) + \(\frac{a}{3}\)

Hence, from the above,
We can conclude that
The value of the given expression is: a

Assessment Practice

Question 35.
Select all expressions that are equivalent to 8x + 3 + 5x – 2x.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 93 13x + 3 – 2x
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 93 11x + 3x
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 93 11 + 3x
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 93 14x
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 93 11x + 3
Answer:
The given expression is: 8x + 3 + 5x – 2x
Now,
By using the Order of Operations,
8x + 3 + 5x – 2x
= (8x + 5x) + 3 – 2x
= 13x + 3 – 2x
= (13x – 2x) + 3
= 11x + 3
Hence, from the above,
We can conclude that
All expressions that are equivalent to 8x + 3 + 5x – 2x are:

Question 36.
Select which expression is equivalent to or NOT equivalent to the given expression.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 94.1
Answer:
The givene xpression is: 2x + 7 + 6x – x
Now,
By using the Order of Operations,
2x + 7 + 6x – x
= (2x + 6x – x) + 7
= (8x – x) + 7
= 7x + 7
= 7 + 7x
Hence, from the above,
We can conclude that
The expression is equivalent to or not equivalent to the given expression is:

Topic 3 Review

? Topic Essential Question

What are expressions and how can they be written and evaluated?
Answer:
Expressions are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.
To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number. To evaluate an expression, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations.

Vocabulary Review

Complete each definition with a vocabulary word.

Vocabulary
algebraic expression
factor tree
coefficient
like terms
exponent
variable

Question 1.
A(n) ____ tells the number of times the base is used as a factor.
Answer:
We know that,
An “Exponent” tells the number of times the base is used as a factor.
Hence, from the above,
We can conclude that
The term that is suitable for the given definition is: Exponent

Question 2.
A letter or symbol that represents an unknown quantity is a(n) _____
Answer:
We know that,
A letter or symbol that represents an unknown quantity is a “variable”
Hence, from the above,
We can conclude that
The term that is suitable for the given definition is: Variable

Question 3.
A diagram that shows the prime factors of a composite number is a(n) ____
Answer:
We know that,
A diagram that shows the prime factors of a composite number is a “factor tree”
Hence, from the above,
We can conclude that
The term that is suitable for the given definition is: Factor tree

Draw a line from each pair of numbers in Column A to the least common multiple (LCM) of the numbers in Column B.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 95.1
Answer:
The given pair of numbers are: (9, 6), (9, 12), and (8, 7)
So,
The LCM of (9, 6) is: 18
The LCM of (9, 12) is: 36
The LCM of (8, 7) is: 56
Hence, from the above,
We can conclude that
The matched pairs of Column A and Column B are:

Question 7.
Look at the variables in each expression below. Write Y if the terms of each expression are like terms. Write N if they are NOT like terms.
a. 3a + 3z
b. \(\frac{x}{3}\) + \(\frac{x}{4}\)
c. 4j – j + 3.8j
Answer:
The given expressions are:
a. 3a + 3z
b. \(\frac{x}{3}\) + \(\frac{x}{4}\)
c. 4j – j + 3.8j
Now,
We know that,
“Like terms” are terms whose variables (and their exponents such as the 2 in x2) are the same. In other words, terms that are “like” each other
Hence, from the above,
We can conclude that
The representation of Y and N for the given expressions are:
a. 3a + 3z                                                                         –  N
b. \(\frac{x}{3}\) + \(\frac{x}{4}\)        –  Y
c. 4j – j + 3.8j                                                                    –  Y

Use Vocabulary in Writing
Explain one way to simplify the expression 4(3q – q). Use vocabulary words in your explanation.
Answer:
The given algebraic expression is: 4 (3q – q)
Now,
When we observe the given expression,
In 3q, “3” is the coefficient
3q and q are the like terms
Now,
4 (3q – q) = 4 (3q – 1q)
= 4q (3 – 1)
= 4q (2)
= 8q
Hence, from the above,
We can conclude that
The value of the given expression is: 8q

Concepts and Skills Review

LESSON 3.1 Understand and Represent exponents

Quick Review
An exponent is a way to show repeated multiplication.

Example
Use an exponent to write the expression 6 × 6 × 6. Then evaluate the expression.
6 is used as a factor 3 times.
6 is the base and 3 is the exponent.
6 × 6 × 6 = 63 = 216

Find 60

A number with an exponent of 0 is always equal to 1.
60 = 1

Practice

Write each expression using an exponent.

Question 1.
8 × 8 × 8 × 8 × 8 × 8 × 8
Answer:
The given repeated multiplication is: 8 × 8 × 8 × 8 × 8 × 8 × 8
Now,
We know that,
An “Exponent” tells the number of times the base i.e., the given number is used as afactor
So,
8 × 8 × 8 × 8 × 8 × 8 × 8 = 87
Hence, from the above,
We can conclude that
The representation of the given expression using an exponent is: 87

Question 2.
4
Answer:
The given repeated multiplication is: 4
Now,
We know that,
An “Exponent” tells the number of times the base i.e., the given number is used as afactor
So,
4 = 41
Hence, from the above,
We can conclude that
The representation of the given expression using an exponent is: 41

Question 3.
10 × 10 × 10 × 10
Answer:
The given repeated multiplication is: 10 × 10 × 10 × 10
Now,
We know that,
An “Exponent” tells the number of times the base i.e., the given number is used as afactor
So,
10 × 10 × 10 × 10 = 104
Hence, from the above,
We can conclude that
The representation of the given expression using an exponent is: 104

Evaluate each expression.

Question 4.
92
Answer:
The given expression is: 9²
Now,
We know that,
An “Exponent” tells the number of times the base is used as a factor
So,
9² = 9 × 9
= 81
Hence, from the above,
We can conclude that
The value of the given expression is: 81

Question 5.
991
Answer:
The given expression is: 991
Now,
We know that,
An “Exponent” tells the number of times the base is used as a factor
So,
991 = 99
Hence, from the above,
We can conclude that
The value of the given expression is: 99

Question 6.
3,1050
Answer:
The given expression is: 3,1050
Now,
We know that,
An “Exponent” tells the number of times the base is used as a factor
Any nonzero number raised to an exponent of zero has always a value of 1
So,
3,1050 = 1
Hence, from the above,
We can conclude that
The value of the given expression is: 1

Question 7.
222
Answer:
The given expression is: 222
Now,
We know that,
An “Exponent” tells the number of times the base is used as a factor
So,
222 = 22 × 22
= 484
Hence, from the above,
We can conclude that
The value of the given expression is: 484

Question 8.
27
Answer:
The given expression is: 27
Now,
We know that,
An “Exponent” tells the number of times the base is used as a factor
So,
27 = 2 × 2 × 2 × 2 × 2 × 2 × 2
= 128
Hence, from the above,
We can conclude that
The value of the given expression is: 128

Question 9.
34
Answer:
The given expression is: 34
Now,
We know that,
An “Exponent” tells the number of times the base is used as a factor
So,
34 = 3 × 3 × 3 × 3
= 81
Hence, from the above,
We can conclude that
The value of the given expression is: 81

LESSON 3.2 Find Greatest Common Factor and Least Common Multiple

Quick Review
You can use prime factorization to find the greatest common factor and the least common multiple of two numbers.

Example
Find the greatest common factor (GCF) and the least common multiple (LCM) of 12 and 6.

List the prime factors of both numbers.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 95.8

Practice
Find the GCF for each pair of numbers. Use the GCF and the Distributive Property to find the sum of each pair of numbers.

Question 1.
30, 100
Answer:
The given numbers are: 30, 100
Now,

Hence, from the above,
We can conclude that
The GCF of the given numbers is: 10

Question 2.
8, 52
Answer:
The given numbers are: 8, 52
Now,

Hence, from the above,
We can conclude that
The GCF of the given numbers is: 4

Question 3.
28, 42
Answer:
The given numbers are: 28, 42
Now,

Hence, from the above,
We can conclude that
The GCF of the given numbers is: 14

Question 4.
37, 67
Answer:
The given numbers are: 37, 67
Now,

Hence, from the above,
We can conclude that
The GCF of the given numbers is: 1

Question 5.
12, 24
Answer:
The given numbers are: 12, 24
Now,

Hence, from the above,
We can conclude that
The GCF of the given numbers is: 12

Question 6.
8, 12
Answer:
The given numbers are: 8, 12
Now,

Hence, from the above,
We can conclude that
The GCF of the given numbers is: 4

Find the LCM for each pair of numbers.

Question 7.
4, 9
Answer:
The given numbers are: 4, 9
Now,

Hence, from the above,
We can conclude that
The LCM of the given numbers is: 36

Question 8.
3, 6
Answer:
The given numbers are: 3, 6
Now,

Hence, from the above,
We can conclude that
The LCM of the given numbers is: 6

Question 9.
8, 10
Answer:
The given numbers are: 8, 10
Now,

Hence, from the above,
We can conclude that
The LCM of the given numbers is: 40

Question 10.
3, 5
Answer:
The given numbers are: 3, 5
Now,

Hence, from the above,
We can conclude that
The LCM of the given numbers is: 15

Question 11.
12, 5
Answer:
The given numbers are: 12, 5
Now,

Hence, from the above,
We can conclude that
The LCM of the given numbers is: 60

Question 12.
4, 11
Answer:
The given numbers are: 4, 11
Now,

Hence, from the above,
We can conclude that
The LCM of the given numbers is: 44

LESSON 3.3 Write and Evaluate Numerical expressions

Quick Review
Use the order of operations to evaluate numerical expressions.

Example
Evaluate the expression 32 + 2[(21 – 9) ÷ 4].
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 96.3

Practice
Evaluate each expression.

Question 1.
80 – 42 ÷ 8
Answer:
The given expression is: 80 – 42 ÷ 8
Now,

Hence, from the above,
We can conclude that
The value of the given expression is: 78

Question 2.
92.3 – (3.2 ÷ 0.4) × 23
Answer:
The given expression is: 92.3 – (3.2 ÷ 0.4) × 23
Now,

Hence, from the above,
We can conclude that
The value of the given expression is: 28.3

Question 3.
[(23 × 2.5) ÷ \(\frac{1}{2}\)] + 120
Answer:
The given expression is: [(23 × 2.5) ÷ \(\frac{1}{2}\)] + 120
Now,

Hence, from the above,
We can conclude that
The value of the given expression is: 160

Question 4.
[20 + (2.5 × 3)] – 33
Answer:
The given expression is: [20 + (2.5 × 3)] – 33
Now,

Hence, from the above,
We can conclude that
The value of the given expression is: 0.5

Question 5.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 97.1
Answer:
The given expression is: [(2 × 100 ) ÷ \(\frac{1}{3}\)] + 8
Now,

Hence, from the above,
We can conclude that
The value of the given expression is: 14

LESSONS 3.4 AND 3.5 Write and Evaluate Algebraic expressions

Quick Review
An algebraic expression can be written to represent a situation with an unknown quantity. Use a variable to represent the unknown quantity. An algebraic expression can be evaluated by substituting a value for the variable and performing the operations.

Example
Write an algebraic expression for 9 times the difference of 12 and a divided by 2. Then evaluate the expression for a = 4.
9 times the difference of 12 and a divided by 2″ is represented by 9 × (12 – a) ÷ 2.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 98.1

Practice
Write an algebraic expression to represent each situation.

Question 1.
22 less than 5 times a number f
Answer:
The given situation is: 22 less than 5 times a number f
Now,
We know that,
The term “Less than” represents the subtraction
The term”many times” (or) “times” represents the multiplication
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an algebraic expression is: 5f – 22

Question 2.
48 times a number of game markers, g
Answer:
The given situation is: 48 times a number of game markers, g
Now,
We know that,
The term”many times” (or) “times” represents the multiplication
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an algebraic expression is: 48g

Question 3.
A number of eggs, e, divided by 12
Answer:
The given situation is: A number of eggs, e, divided by 12
Now,
We know that,
The term”Division” (or) “Divide” represents the division
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an algebraic expression is: \(\frac{e}{12}\)

Question 4.
3 times the sum of m and 7
Answer:
The given situation is: 3 times the sum of m and 7
Now,
We know that,
The term”many times” (or) “times” represents the multiplication
The term “Sum” (or) “Add” represents the addition
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an algebraic expression is: 3 (m + 7)

Evaluate each expression for n = 7, x = 4, y = 8, and z = 1.

Question 5.
12x – 7
Answer:
The given expression is: 12x – 7
Now,
For x = 4,
12x – 7 = 12 (4) – 7
= 48 – 7
= 41
Hence, from the above,
We can conclude that
The value of the given expression is: 41

Question 6.
x2 ÷ y
Answer:
The given expression is: x² ÷ y
Now,
For x = 4, and y = 8,
x² ÷ y = 4² ÷ 8
= 16 ÷ 8
= 2
Hence, from the above,
We can conclude that
The value of the given expression is: 2

Question 7.
5z + 3n – z3
Answer:
The given expression is: 5z + 3n – z3
Now,
For z = 1, and n = 7,
5z + 3n – z3 = 5 (1) + 3 (7) – 13
= 5 + 21 – 1
= 25
Hence, from the above,
We can conclude that
The value of the given expression is: 25

Question 8.
y2 ÷ 2x + 3n – z
Answer:
The given expression is: y2 ÷ 2x + 3n – z
Now,
For x = 4, n = 7, z = 1, and y = 8,
y2 ÷ 2x + 3n – z = 8² ÷ 2 (4) + 3 (7) – 1
= 64 ÷ 8 + 21 – 1
= 8 + 20
= 28
Hence, from the above,
We can conclude that
The value of the given expression is: 28

LESSON 3.6 Generate Equivalent expressions

Quick Review
Equivalent expressions are expressions that have the same value. The properties of operations and substitution can be used to write and identify equivalent expressions.

Example
Are the expressions 5x + 20, 5(x + 4), and x + 4 equivalent?
For algebraic expressions to be equivalent, each expression must name the same value no matter what value is substituted for the variable.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 99.1
Use the Distributive Property to write
5x + 20 as 5(x + 4).
5x + 20 = 5 • x + 5 • 4
= 5(x + 4)
Properties of operations cannot be used to write 5x + 20 or 5(x + 4) as x + 4.
5x + 20 and 5(x + 4) are equivalent expressions.

Practice
Complete the table. Then circle the expressions that are equivalent.

Question 1.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 99.5
Answer:
The given expressions are:
a. 5 (2.2y + 1) – 3   b. 11y + 5 – y   c. 11y + 2
Now,
a.
For y = 1,
5 (2.2y + 1) – 3 = 5 (2.2 + 1) – 3
= 13
For y = 2,
5 (2.2y + 1) = 5 (2.2 (2) + 1) – 3
= 24
For y = 3,
5 (2.2y + 1) – 3 = 5 (2.2 (3) + 1) – 3
= 35
Now,
b.
For y = 1,
11y + 5 – y = 11 + 5 – 1
= 15
For y = 2,
11y + 5 – y = 22 + 5 – 2
= 25
For y = 3,
11y + 5 – y = 33 + 5 – 3
= 35
Now,
c.
For y = 1,
11y + 2 = 11 + 2
= 13
For y = 2,
11y + 2 = 22 + 2
= 24
For y = 3,
11y + 2 = 33 + 2
= 35
Hence, from the above,
We can conclude that
The completed table and the expressions (Circled in the table) that are equivalent is:

In 2-4, write Yes or No to indicate whether the expressions are equivalent.

Question 2.
10x – 3 + 2x – 5 and 4(3x – 2)
Answer:
The given expressions are: 10x – 3 + 2x – 5 and 4(3x – 2)
Now,
10x – 3 + 2x – 5 = (10x + 2x) – (3 + 5)
= 12x – 8
= 4 (3x – 2)
So,
10x – 3 + 2x – 5 = 4 (3x – 2)
Hence, from the above,
We can conclude that
We can indicate YES since the given expressions are equivalent

Question 3.
3y + 3 and 9(y + \(\frac{1}{3}\))
Answer:
The given expressions are: 3y + 3 and 9(y + \(\frac{1}{3}\))
Now,
9(y + \(\frac{1}{3}\)) = 9 (y) + 9 (\(\frac{1}{3}\))
= 9y + 3
So,
3y + 3 ≠ 9y + 3
Hence, from the above,
We can conclude that
We can indicate NO since the given expressions are not equivalent

Question 4.
6(3x + 1) and 9x + 6 + 9x
Answer:
The given expressions are: 6(3x + 1) and 9x + 6 + 9x
Now,
9x + 6 + 9x = (9x + 9x) + 6
= 18x + 6
= 6 (3x + 1)
So,
6 (3x + 1) = 9x + 6 + 9x
Hence, from the above,
We can conclude that
We can indicate YES since the given expressions are equivalent

In 5-7, use properties of operations to complete the equivalent expressions.

Question 5.
2(x + 4) and ___x + ____
Answer:
The given expression is: 2 (x + 4)
Now,
By using the Distributive Property,
2 (x + 4) = 2 (x) + 2 (4)
= 2x + 8
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 2x + 8

Question 6.
5x – 45 and 5(___ – ___ )
Answer:
The given expression is: 5x – 45
Now,
By using the Distributive Property,
5x – 45 = 5 (x – 9)
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 5 (x – 9)

Question 7.
3(x + 7) and ___ ×+ ____
Answer:
The given expression is: 3 (x + 7)
Now,
By using the Distributive Property,
3 (x + 7) = 3 (x) + 3 (7)
= 3x + 21
Hence, from the above,
We can conclude that
The equivalent expression for the given expression is: 3x + 21

LESSON 3.7 Simplify Algebraic expressions

Quick Review
Combine like terms to simplify algebraic expressions.

Example
Simplify the expression 3x + 7 + 6x.
Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 99.9

Practice
Simplify each expression.

Question 1.
9y + 4 – 6y
Answer:
The given expression is: 9y + 4 – 6y
Now,
9y + 4 – 6y
= (9y – 6y) + 4
= 5y + 4
Hence, from the above,
We can conclude that
The value of the given expression is: 5y + 4

Question 2.
3x + 5 + 7x
Answer:
The given expression is: 3x + 5 + 7x
Now,
3x + 5 + 7x
= (3x + 7x) + 5
= 10x + 5
= 5 (2x + 1)
Hence, from the above,
We can conclude that
The value of the given expression is: 5 (2x + 1)

Question 3.
8x + 13 – 3x + 9
Answer:
The given expression is: 8x + 13 – 3x + 9
Now,
8x + 13 – 3x + 9
= (8x – 3x) + (13 + 9)
= 5x + 22
Hence, from the above,
We can conclude that
The value of the given expression is: 5x + 22

Question 4.
y2 + 3y2
Answer:
The given expression is: y² + 3y²
Now,
y² + 3y²
= y² (1 + 3)
= y² (4)
= 4y²
Hence, from the above,
We can conclude that
The value of the given expression is: 4y²

Question 5.
4x + 15 – 3x + 10
Answer:
The given expression is: 4x + 15 – 3x + 10
Now,
4x + 15 – 3x + 10
= (4x – 3x) + (15 + 10)
= x + 25
Hence, from the above,
We can conclude that
The value of the given expression is: x + 25

Question 6.
10x + 2x – 12x
Answer:
The given expression is: 10x + 2x – 12x
Now,
10x + 2x – 12x
= x (10 + 2 – 12)
= x (12 – 12)
= x (0)
= 0
Hence, from the above,
We can conclude that
The value of the given expression is: 0

Topic 3 Fluency Practice

Crisscrossed

Envision Math Common Core 6th Grade Answer Key Topic 3 Numeric And Algebraic Expressions 99.20