Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles

enVision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles

Go through the enVision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles regularly and improve your accuracy in solving questions.

enVision Math Common Core 1st Grade Answers Key Topic 15 Equal Shares of Circles and Rectangles

Essential Question:
What are some different names for equal shares?
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 1

Find Out Talk to friends and relatives about different objects that have wheels. Ask them how they use wheels in their everyday lives.
Journal: Make a Book Show what you found out. In your book, also:

  • Draw pictures of different objects that have wheels. Describe the shapes you see. How could you divide the shapes into equal shares?
  • Tell how wheels are used to move people or things.

Review What You Know

Vocabulary
Question 1.
Put an X on the circle.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 2
Answer:

Question 2.
Draw a rectangle.
Answer:

Explanation:
Draw a rectangle using a scale and pencil.

Question 3.
Draw the hands on the clock to show a time to the half hour.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 3
Answer:

Different kinds of Rectangles
Question 4.
Color all the rectangles.
Then draw an X on the rectangle that is a square.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 4
Answer:

Explanation:
Color all the rectangles
Then put X on the rectangle that is square

Question 5.
How many rectangles do you see?
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 5
____________ rectangles
Answer:
2 rectangles
Explanation:
A rectangle has four sides
The envelope has 4 sides
The unicorn puzzle has 4 sides
So there are 2 rectangles

What’s the Time?
Question 6.
Cody gets home at 4:30. Draw the hour and minute hands on the clock to show at what time Cody gets home.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 6
Answer:

Explanation:
Draw the minutes hand at 6 [30 minutes]
Draw the hours hand between 4 and 5

Pick a Project

PROJECT 15A
What games do you play at recess? Project: Design and Play a Game

Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 76
PROJECT 15A
Answer:

PROJECT 15B
Do you have a favorite dance? Project: Create Your Own Square Dance
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 77
Answer:

PROJECT 15C
Is every game fair? Project: Make a Pair of Spinners
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 78

3-ACT MATH PREVIEW

Math Modeling Pieced Out
Before watching the video, think: What shapes can you use to make a square? Can you find another way to use shapes to make a square? What kind of designs can you make?
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 7
I can … model with math to solve a problem that involves making a design with 2-D shapes
Answer:

Explanation:
We can create a square using equal shares of triangles and one fourths of a square
the first 2 squares are patterns using triangles
the last square are patterns using rectangles and squares

Lesson 15.1 Make Equal Shares

Solve & Share
Draw a line inside the blue circle to show 2 parts that are the same size.

Draw a line inside the yellow circle to show 2 parts that are NOT the same size.

How do you know the 2 parts you made in the blue circle are the same size?
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 8
I can … determine if shapes are divided into equal shares.
Answer:

Explanation:
In the blue circle the line is drawn exactly in the middle dividing the circle into 2 equal shares.

Visual Learning Bridge
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 9

Convince Me! Is this shape divided into equal shares? Explain how you know.
Answer:
In the second picture the rectangle is divided into 2 equal shares
In the third picture the rectangle is divided into 4 equal share.

Guided Practice

Decide if each picture shows equal shares. Then circle Yes or No.
Question 1.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 10

Question 2.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 11
Answer:

Question 3.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 12
Answer:

Question 4.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 13
Answer:

Question 5.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 14
Answer:

Question 6.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 15
Answer:

Independent Practice

Write the number of equal shares in each shape. Practice If the shares are NOT equal, write 0.
Question 7.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 16
__________ equal shares
Answer:
0 equal shares
Explanation:
The shares are not equal.

Question 8.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 17
________ equal shares
Answer:
2 equal shares
Explanation:
The shares are equal.

Question 9.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 18
________ equal shares
Answer:
2 equal shares
Explanation:
The shares are equal.

Question 10.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 19
_________ equal shares
Answer:
4 equal shares
Explanation:
The shares are equal.

Question 11.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 20
________ equal shares
Answer:
4 equal shares
Explanation:
The shares are equal.

Question 12.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 21
_________ equal shares
Answer:
2 equal shares
Explanation:
The shares are equal.

Question 13.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 22
_________ equal shares
Answer:
0 equal shares
Explanation:
The shares are not equal.

Question 14.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 23
_________ equal shares
Answer:
4 equal shares
Explanation:
The shares are equal.

Question 15.
Higher Order Thinking
Draw a square, a circle, or a rectangle. Divide your shape into equal shares. Then write the number of equal shares in your shape.
_________ equal shares
Answer:
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 19
4 equal shares.

Problem Solving

Solve each problem below.
Question 16.
Be Precise Matt makes a flag with 4 equal shares. Which flag did he make? Circle the correct flag.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 24
Answer:

Explanation:
The red flag has equal shares

Question 17.
Be Precise Ruth picks a flag with equal shares. Which flag did she pick? Circle the correct flag.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 25
Answer:

Explanation:
The yellow flag has equal shares

Question 18.
Higher Order Thinking Mr. Kelly made 2 pizzas. He sliced each one into 4 slices. Each slice is the same size piece. How many slices are there? Draw a picture. Then write an equation.
Answer:

Explanation:
8 slices
1 pizza is divided into 4 slices
4 + 4 = 8 slices

Question 19.
Assessment Practice Which square does NOT show 4 equal shares?
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 26
Answer:
D
Explanation:
In all the options the square is divided into 4 equal shares, But in option D the square is divided into 3 shares.

Lesson 15.2 Make Halves and Fourths of Rectangles and Circles

Solve & Share
Draw a line inside the circle to show 2 equal shares. Color 1 of the shares. Then write numbers to tell how many shares you colored.

Draw lines inside the rectangle to show 4 equal shares. Color 2 of the shares. Then write numbers to tell how many shares you colored.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 27
I can … divide shapes into 2 and 4 equal shares and use words to describe those shares.
Answer:

I colored 2 out of 4 equal shares.

Visual Learning Bridge
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 28

Convince Me! What share of the rectangle is green?
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 29
Answer:
The 3rd share of the rectangle is Green.

Guided Practice

Circle the correct shapes for each problem.
Question 1.
One quarter blue
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 30
Explanation:
one quarter blue means we have to color one fourth blue.

Question 2.
One half yellow
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 31
Answer:

Independent Practice

Color the shapes for each problem.
Question 3.
One half red
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 32
Answer:

Explanation:
We have to color one half of the figure red.

Question 4.
One fourth orange
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 33
Answer:

Explanation:
one fourth means we have to color one of the Orange.

Question 5.
One quarter green
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 34
Answer:

Explanation:
one fourth means we have to color one of the Green.

Question 6.
One half blue
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 35
Answer:

Explanation:
one half blue means we have to color one of the halves blue.

Question 7.
Higher Order Thinking
Alex has one half of an oatmeal bar. Jen has one quarter of a different oatmeal bar. Jen’s piece is bigger. How could Jen’s piece be bigger? Use words or pictures to solve.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 36
Answer:
Alex has one half of an oatmeal bar. Jen has one quarter of a different oatmeal bar. Both oatmeal bars are of different size, as shown in the picture, hence Jen’s piece is bigger

Jens oat meal bar is bigger.

Question 8.
Explain Sam says the rectangle is divided into halves. Is he correct? Circle Yes or No. Then explain how you know.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 37
Answer:
Yes
Explanation:
The rectangle is divided in to two equal parts or two halves by the diagonal.

Question 9.
Explain Mia says the circle is divided into fourths. Lucy says it is divided into quarters. Who is correct? Explain how you know.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 38
Answer:
Lucy is correct
Explanation:
The difference between Fourth and Quarter. When used as nouns, fourth means the person or thing in the fourth position, whereas quarter meaning in math is 1/4 . When used as adjectives, fourth means the ordinal form of the number four, whereas quarter means pertaining to an aspect of a quarter.

Question 10.
Higher Order Thinking Dana draws a rectangle divided into fourths. She colors one half of the rectangle blue and one quarter of the rectangle green. Draw a rectangle to match the one Dana drew.
Answer:

Question 11.
Assessment Practice Yao colors a circle. One half of the circle is blue. The other half is NOT blue. Which shows the shape Yao could have colored? Choose two that apply.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 39
Answer:

Lesson 15.3 Understand Halves and Fourths

Which is larger: one half or one fourth of the same sandwich?
Divide the sandwiches. Then circle the sandwich that has larger equal shares.

I can … tell that more equal shares of the same whole creates smaller shares.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 40
Answer:

Visual Learning Bridge
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 41

Convince Me! David has a sandwich. Is half of the sandwich more or less food than one fourth of the sandwich? Explain.
Answer:
The half sandwich is more than the one fourth of the sandwich
Explanation:
One fourths means the sandwich is divided into 4 parts
whereas the half of sandwich means the sandwich is divided into 2 parts
half = 1 fourth + 1 fourth
so half of sandwich is more than one fourth of a sandwich

Guided Practice

Circle the shape that has more equal shares. Put an X on the shape that has larger equal shares.

Question 1.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 42

Question 2.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 43
Answer:

Question 3.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 44
Answer:

Question 4.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 45
Answer:

Independent Practice

Solve each Problem
Question 5.
Draw a line to divide this shape in half.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 46
Answer:

Explanation:
If we draw a line exactly in the middle of the rectangle the rectangle will be divided into 2 equal halves

Question 6.
Shade one quarter of this shape.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 47
Answer:

Explanation:
Shade 1 quarter of the circle.

Question 7.
Draw lines in the orange square to make smaller equal shares than are in the blue square.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 48
Answer:

Explanation:
Draw a line dividing the orange square into 2 equal shares like in the blue squares

Question 8.
Higher Order Thinking Joan cuts a rectangle into 2 equal shares. Then she cuts each share in half. How many equal shares are there now? What are these shares called? Use words or pictures to explain.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 49
Answer:
The rectangle is divided into 2 equal shares
The 2 equal shares are then divided into 2 equal share. which means
1 rectangle into 2 parts 2 parts into 2 parts each = 4 shares
These shares are called one fourth or quarters

Problem Solving

Solve each problem.
Question 9.
Reasoning Steve cuts one pan of cornbread into halves. He cuts another pan of cornbread into fourths. Each pan is the same size.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 50
How many pieces did Steve cut in all? Which pieces are larger, the halves or the fourths? Use the picture to help you solve.
_______ pieces in all
The _______ are larger.
Answer:
6 pieces in all
The halves are larger.
Explanation:
1st pan is cut into 2 shares
And the 2nd pan is cut into 4 shares
2 + 4 = 6 pieces in all.
So the half pieces are larger.

Question 10.
Higher Order Thinking Burke and Alisha each have a sheet of paper. Both sheets are the same size. Burke uses one half of his sheet. Alisha uses two fourths of her sheet. Alisha says that they used equal amounts of paper.
Is she correct? Explain your answer. You can draw a picture to help.
Answer:
Yes. Alisha is correct
Explanation:
Bruke uses one half of the sheet
Alisha uses 2 fourths of the sheet


1 half = 1 fourth + 1 fourth
1 half = 2 fourth
So Alisha is correct
They used equal amounts of paper.

Question 11.
Assessment Practice Joey has two circles of the same size. He cuts one into halves and the other into fourths. Which words describe how the halves compare to the fourths?
A. smaller, more
B. smaller, fewer
C. larger, more
D. larger, fewer
Answer:
D
Explanation:
The halves are larger and fewer than the fourths.

Lesson 15.4 Problem Solving

Model with Math

Mary’s blanket is divided into 2 equal shares. One share of the blanket is yellow and the other is orange. How can you describe the share of the blanket that is yellow? Draw and color the blanket to show your work.
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 51

I can … make a drawing or diagram to show a problem about equal shares.
Answer:

Thinking Habits Can I use a drawing, diagram, table, graph, or objects to show the problem?
Envision Math Common Core 1st Grade Answer Key Topic 15 Equal Shares of Circles and Rectangles 52

Visual Learning Bridge
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 53

Convince Me! Amy buys a green and blue rug. It is divided into 4 equal shares. Half of the rug is green. The rest is blue. How many shares are blue? How do you know?
Answer:
Amy buys a green and blue rug
She divides the rug into 4 equal shares

half of the rug is green = 2 fourths
that means the other half is colored blue = 2 fourths
that means 2 shares are blue

Guided Practice

Draw a picture to solve the problem. Then complete the sentence.
Question 1.
Pete makes a purple and yellow flag. The flag is divided into fourths. 2 shares are yellow. The rest of the flag is purple. How many of the shares are purple?
2 out of 1 equal shares are purple.
Answer:

2 out of 1 equal shares are purple.
2 out of 1 equal shares are yellow
there are 2 purple shares

Independent Practice

Draw a picture to solve each problem. Then complete the sentence.
Question 2.
Tracy’s pizza is cut into halves. She eats 1 of the shares. How many shares of the pizza does she eat?
Tracy eats _________ out of _________ equal shares.
Answer:
Tracy eats 1 out of 2 equal shares.
Explanation:
The pizza is cut into 2 equal shares
She eats 1 of the shares
2 halves – 1 halves = 1half
she eats 1 share of the pizza

Question 3.
Mia cut her sandwich into quarters. 2 of the shares have cheese. What share of the sandwich does NOT have cheese?
_________ out of _________ shares do NOT have cheese.
Answer:
2 out of 4 shares do NOT have cheese.

Question 4.
Algebra Color the correct number of shares to continue the pattern.
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 54
Answer:

Problem Solving

Performance Task
Question 5.
Pizza Shares
Kim cuts a pizza into 4 equal shares. She gives half of the pizza to Stephen.
Model Draw a picture to show the shares of the pizza that Stephen has.
Answer:

Question 6.
Reasoning How many shares of the pizza are left after Kim gives half to Stephen? Write the missing numbers.
_________ out of _________ shares are left.
Answer:
2 out of 4 shares are left.

Question 7.
Explain What if kim gives Stephen only I share of the pizza?
Explain how you can find the number of shares that Kim has left.
Answer:
Kim gave Stephen 1 share
no of shares Kim has now : 4 – 1 = 3 shares

Topic 15 Fluency Practice Activity

Find a partner. Point to a clue. Read the clue. Look below the clues to find a match. Write the clue letter in the box next to the match. Find a match for every clue.
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 55
I can … add and subtract within 10.

Clues
A. 4 + 2 + 1
B. 4 – 1
C. 5 – 3
D. 2 + 2 + 2
E. 5 – 1
F. 1 + 3 + 1
G. 4 + 4
H. 1 + 3 + 6
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 56

Vocabulary Review
Understand Vocabulary

Word List
• Equal shares
• Fourths
• Halves
• Quarters

Question 1.
Fill in the blank.
I can cut my sandwich into two equal parts called _______.
Answer:
Halves
Explanation:
I can cut my sandwich into two equal parts called halves.

Question 2.
Fill in the blank.
When you share a sandwich equally with three other people, you cut it into _______.
Answer:
Equal shares
Explanation:
When you share a sandwich equally with three other people, you cut it into equal shares.

Question 3.
Fill in the blank.
If you want everyone to get the same amount of a sandwich, you need to cut it into _______.
Answer:
Quarters
If you want everyone to get the same amount of a sandwich, you need to cut it into quarters.

Question 4.
Fill in the blank.
Four people share one whole carton of juice and each person gets the same amount. The whole carton is divided into _______.
Answer:
Fourths
Explanation:
Four people share one whole carton of juice and each person gets the same amount. The whole carton is divided into fourths.

Use Vocabulary in Writing
Question 5.
Explain one way you could share a snack with one or more friends. Use at least one term from the Word List.
Answer:
I could share a snack with one or more friend by dividing it into equal shares among the friends.

Topic 15 Reteaching

Set A
You can divide a whole into shares.
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 57
4 equal shares

Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 58
0 equal shares

Write the number of equal shares in each shape. If the shares are NOT equal, write 0.
Question 1.
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 59
_______ equal shares
Answer:
2 equal shares

Question 2.
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 60
_______ equal shares
Answer:
0 equal shares

Set B

You can divide shapes into equal shares. You can describe the shares using the words half or fourth.
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 61

Divide and color the shapes for each problem.
Question 3.
one half green
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 62
Answer:

Explanation:
Divide the circle into halves and color one half of the circle green.

Question 4.
One fourth orange
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 63
Answer:

Explanation:
Divide the square into one fourths and color one fourth of the square orange

Set C

You can compare shares of the same shape that are different sizes.
These circles are the same size, but they are divided differently.
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 64
The red circle has larger equal shares.
The yellow circle has more equal shares.

Divide the shapes. Then circle the words that complete the sentences.
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 65
Answer picture:

Question 5.
The blue square has smaller / larger equal shares than the green square.
Answer:
Smaller
Explanation:
The blue square has smaller equal shares than the green square.

Question 6.
The green square has more / fewer equal shares than the blue square.
Answer:
Fewer
Explanation:
The green square has fewer equal shares than the blue square.

Set D

Thinking Habits
Model with Math
How can I use math words I know to help solve the problem?
Can I use a drawing, diagram, table, graph, or objects to show the problem?
Envision Math Common Core 1st Grade Answers Topic 15 Equal Shares of Circles and Rectangles 66

Draw a picture to solve the problem.
Question 7.
Maya’s scarf is divided into 4 equal shares. 1 share is green. 2 shares are yellow. The rest is blue. What share of the scarf is blue?
_______ out of _______ equal shares is blue.
Answer:
1 out of 4 equal shares is blue.

Topic 15 Assessment Practice

Question 1.
A. Which shape shows 2 equal shares?
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 67
Answer:
C

B. Describe the shares in your answer to A.
Answer:
C
Explanation:
If we cut the circle along the line the two pieces overlap each other,
that means the 2 halves are equal

Question 2.
A. Which shape does NOT show one fourth colored blue?
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 68
Answer:
D

B. How do you know your answer to A is correct?
Answer:
The answer to A is correct as D is not divided into 4 equal parts so it does not have one fourth of the figure colored blue.

Question 3.
Divide the rectangle into halves. Then color half of the rectangle.
Explain how you know that you colored the right amount.
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 69
Answer:

Explanation:
First draw a line to divide the rectangle into 2 equal shares
Color 1 half of the rectangle

Question 4.
Compare the two shapes. Circle two ways to describe the equal shares in each.
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 70
Answer:

Question 5.
Ron draws a flag divided into 4 equal shares. 2 shares are purple and the rest are blue. How many shares of the flag are blue?
Draw a picture to solve the problem. Then complete the sentence.
_______ out of _______ equal shares are blue.
Answer:
2 out of 4 equal shares are blue.
Explanation:
Total shares : 4
Purple shares : 2
Blue share :4 – 2 = 2 shares

Topic 15 Performance Task

Kerry’s Kitchen Kerry loves to cook! She makes many different foods.
Question 1.
Kerry bakes a loaf of bread. She cuts it into equal shares. How many equal shares are there?
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 71
Answer:
4 equal shares.
Explanation:
Count the number of shares of the bread

There are 4 equal shares.

Question 2.
Kerry makes a pizza.
She cuts it so that she and her sister each get an equal share. What are the shares called? _______
Show two ways that Kerry could divide the pizza.
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 72
Answer:
One fourths

Explanation:
Kerry divided the pizza into 4 equal shares
So she and her sister gets equal amount of shares

Question 3.
Kerry makes a sandwich. She eats one half of it. Color to show how much she ate.
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 73
How many halves make the whole sandwich?
_______ halves
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 74
Answer:
2 halves

Explanation:
Half means 2 equal shares
If we divide the sandwich into 2 equal shares
There will be 2 halves
Kerry eats 1 half
so there is 1 more half of the sandwich left
Draw a line in the middle of the sandwich
Color one of the halves of the sandwich like in the picture below

Question 4.
Kerry makes a pan of oatmeal bars. She cuts up the bars.
Kerry says that she divided the bars into fourths.
Envision Math Common Core Grade 1 Answer Key Topic 15 Equal Shares of Circles and Rectangles 75
Is she correct? Circle Yes or No.
Explain your answer.
Answer:

Explanation:
Dividing into fourths means every bar is the same size
Kerry divided incorrectly
Kerry must divide it like in the picture below:

Question 5.
Kerry makes a salad.
She cuts a tomato into four equal shares. She puts I equal share of the tomato in the salad.
Part A
Draw a picture to show the share of the tomato that is in the salad.

Part B
The equal shares that Kerry cut are called fourths.
What is another name for these shares?
Answer:
Quarters

Part C
How many fourths are in the whole tomato?
There are _______ fourths in the whole tomato.
Answer:
There are 4 fourths in the whole tomato.

enVision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers

Go through the enVision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers regularly and improve your accuracy in solving questions.

enVision Math Common Core 4th Grade Answers Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers

Essential Questions:
How can sums and differences of whole numbers be estimated? What are standard procedures for adding and subtracting whole numbers?
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 1

enVision STEM Project: The World’s Fastest Vehicles
Do Research Since 1970, the speed record has been broken many times. Use the Internet or other sources to find five vehicles that can go faster than 1,000 kilometers per hour.
Journal: Write a Report Include what you found. Also in your report:

  • Make a table that includes the type of vehicle, whether the vehicle moves on land, water, or in space, and the speed of the vehicle.
  • Use place value to find the fastest and the slowest vehicle in your table.
  • Calculate the difference between the speeds of two of the vehicles in your table.

Review What You Know

Vocabulary
Choose the best term from the box. Write it on the blank.

  • equation
  • estimate
  • period
  • rounding

Question 1.
An __________ is an approximate number or answer.
Answer:
An estimate is an apporoximate number or answer.

Question 2.
A process that determines which multiple of 10, 100, 1,000, and so on a number is closest to is called _________.
Answer:
A process that determines which multiple of 10, 100, 1000, and So on a number is closest to is called rounding.

Question 3.
A number sentence that uses the equal sign (=) to show two expressions have the same value is an __________.
Answer:
A number sentence that uses the equal sign(=) to show two expressions have the same value is an equation.

Addition Facts and Mental Math

Find each sum.
Question 4.
4 + 6
Answer:
4 + 6 = 10

Question 5.
7 + 5
Answer:
7 + 5 = 12

Explanation:
The sum of 7 and 5 is 12.

Question 6.
29 + 8
Answer:
29 + 8 = 37

Explanation:
The sum of 29 and 8 is 37.

Question 7.
14 + 5
Answer:
14 + 5 = 19

Question 8.
13 + 7
Answer:
13 + 7 = 20

Explanation:
The sum of 13 and 7 is 20.

Question 9.
37 + 7
Answer:
37 + 7 = 42

Question 10.
289 + 126
Answer:
289 + 126 = 415

Explanation:
The sum of 289 and 126 is 415.

Question 11.
468 + 329
Answer:
468 + 329 =797

Explanation:
The sum of 468 and 329 is 797.

Question 12.
157 + 211
Answer:
157 + 211 = 368

Explanation:
The sum of 15 and 211 is 368.

Subtraction Facts and Mental Math

Find each difference.
Question 13.
27 – 3
Answer:
27 – 3 = 24

Question 14.
6 – 4
Answer:
6 – 4 = 2

Question 15.
15 – 8
Answer:
15 – 8 = 7

Question 16.
11 – 8
Answer:
11 – 8 = 3

Explanation:
The difference between 11 and 8 is 3.

Question 17.
66 – 2
Answer:
66 – 2 = 64

Question 18.
17 – 8
Answer:
17 – 8 = 9

Explanation:
The difference between 17 and 8 is 9.

Question 19.
416 – 404
Answer:
416 – 404 = 12

Explanation:
The difference between 416 and 404 is 12.

Question 20.
220 – 205
Answer:
220 – 205 = 15

Explanation:
The difference between 220 and 205 is 15.

Question 21.
148 – 106
Answer:
148 – 106 = 132

Explanation:
The difference between 148 and 106 is 42.

Rounding

Question 22.
Construct Arguments Why does 843,000 round to 840,000 rather than 850,000 when rounded to the nearest ten thousand?
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 2
Answer:
The rule for rounding to the nearest ten thousand is to look at the last four digits.If the last four digits are  5000 or greater, then we round our ten thousands digit up, and if it is less than 5000, then we keep our ten thousands digit the same.
So, 843,000 rounds downs to 840000.

Pick a Project

PROJECT 2A
What are the largest cities in your home state?
Project: Map the Population of Your State’s Largest Cities
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 3

PROJECT 2B
How did the United States become a nation?
Project: Write a Report on U.S. Expansion
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 4

PROJECT 2C
How do the sizes of the planets compare to the size of Earth?
Project: Make a Model of the Solar System
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 5

PROJECT 2D
How high is high?
Project: Compare Mountain Elevations
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 6

Lesson 2.1 Finding Sums and Differences with Mental Math

Solve & Share
Luke collected 1,034 baseball cards, 1,289 football cards, and 1,566 hockey cards. Use mental math to find the number of cards in Luke’s collection. Solve this problem any way you choose.
I can … use properties and strategies to change a problem to add and subtract with mental math.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 7

Look Back! Construct Arguments How could you use mental math to solve 1,289 + 1,566? 1,034 + 1,566? How is the thinking different?

Essential Question
How Can You Use Mental on Math to Solve Problems?

Visual Learning Bridge
Katy’s dad washes windows at one of the tallest buildings in Miami, the Four Seasons Hotel. He worked Saturdays in October and earned more money than in September. How much did he earn in the two months combined?
Find $1,985 + $2,595 with mental math.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 8

Washing Windows Earned $1,985 in Sept. Earned $2,595 in Oct.
+5+10 +80 +500 +2,000
Make Ten

Break apart 1,985 to get a number that makes a ten, hundred, or thousand when added to 2,595. Then, use the Associative Property of Addition to change the grouping.
1,985 + 2,595
= (1,580 + 405) + 2,595
= 1,580 + (405 + 2,595)
= 1,580 + 3,000
= 4,580
Katy’s dad earned $4,580.

Add On
Break one addend apart and add on.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 9
You can start with either addend because of the Commutative Property of Addition.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 10
Katy’s dad earned $4,580.

Use Compensation
Add 15 to 1,985. Then subtract 15 from 2,595 to compensate. Adding 15 and subtracting 15 is the same as adding zero. Adding zero doesn’t change the sum because of the Identity Property of Addition.
1,985 + 2,595
= (1,985 + 15) + (2,595 – 15)
= 2,000 + 2,580
= 4,580
Katy’s dad earned $4,580.

Convince Me! Use Structure How could you make ten by breaking apart 2,595?

Another Example!
Subtract 2,595 – 1,985 with mental math.

Count Up
Count from 1,985 up to 2,595.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 11
Find how much you counted up.
5 + 10 + 595 = 610

Count Down
Count down 1,985 from 2,595.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 12

Use Compensation
Adding the same amount to both numbers in a subtraction problem doesn’t change the difference.
1,990
2,510
(2,595 + 15) – (1,985 + 15)
= 2,610 – 2,000
= 610

Guided Practice

Do You Understand?
Question 1.
Explain how to find 2,987 + 4,278 with mental math. What property does your strategy use?
Answer:
7265

Explanation:
Use Compensation
Add 13 to 2,987. Then subtract 13 from 4278 to compensate. Adding 13 and subtracting 13 is the same as adding zero. Adding zero doesn’t change the sum because of the Identity Property of Addition.
2987 + 4278
= (2987 + 13) + (4278 – 13)
= 3000 + 4265
= 7265
Therefore, the sum of 2987 and 4278 is 7265.

Do You Know How?
For 2-4, use mental math strategies to solve.
Question 2.
6,794 – 999
Answer:

Explanation:
1+794+5000=5795
The difference between 6794 and 999 is 5795.

Question 3.
4,505 + 3,515
Answer:
7620

Explanation:
Make Ten

Break apart 4505 to get a number that makes a ten, hundred, or thousand when added to 3515. Then, use the Associative Property of Addition to change the grouping.
4505 + 3115
= (4000+505) + 3115
= 4000 + (505 + 3115)
= 4000 + 3620
= 7620
Therefore, the sum of 4505 and 3115 is 7620.

Question 4.
9,100 + 2,130 + 900
Answer:
7620

Explanation:
Make Ten

Break apart 9100 to get a number that makes a ten, hundred, or thousand when added to 2130 and 900. Then, use the Associative Property of Addition to change the grouping.
9100 + 2130 + 900
=(9000+100) + 2130 + 900
=9000 + (100+900) + 2130
=9000 + 1000 + 2130
=10000 + 2130
=12130
Therefore, the sum of 9100, 2130 and 900 is 12130.

Independent Practice

For 5-10, use mental math to solve.
Question 5.
7,000 – 827
Answer:

Explanation:
3+170+6000=6173
The difference between 7000 and 827 is 6173.

Question 6.
1,225 + 975
Answer:
2200

Explanation:
Use Compensation
Add 75 to 1,225. Then subtract 75 from 975 to compensate. Adding 15 and subtracting 15 is the same as adding zero. Adding zero doesn’t change the sum because of the Identity Property of Addition.
1,225 + 975
= (1225 + 75) + (975 – 75)
= 1300 + 900
= 2200
The sum of 1225 and 975 is 2200.

Question 7.
5,491 – 2,860
Answer:

Explanation:
40+60+2491=2591
The difference between 5491 and 2860 is 2591.

Question 8.
6,686 – 1,443
Answer:

Explanation:
7+50+500+4686=5243
The difference between 16686 and 1443 is 5243

Question 9.
8,375 + 31,145
Answer:
39520

Explanation:
Make Ten

Break apart 8375 to get a number that makes a ten, hundred, or thousand when added to 31145. Then, use the Associative Property of Addition to change the grouping.
8375 + 31145
= (8000+375) + 31145
= 000 + (375 + 31145)
= 8000 + 31520
= 39520
Therefore, the sum of 8375 and 31145 is 39520.

Question 10.
23,100 + 74,900
Answer:
98000

Explanation:
Make Ten

Break apart 23100 to get a number that makes a ten, hundred, or thousand when added to 74900. Then, use the Associative Property of Addition to change the grouping.
23100 + 74900
= (23000+100) + 74900
= 23000 + (100 + 74900)
= 23000 + 75000
= 98000
Therefore, the sum of 23100 and 74900 is 98000.

Problem Solving

For 11-12, use the table at the right.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 13
Question 11.
Precision How much greater is the area of California than Montana? Explain how to use mental math to solve.
Answer:

Question 12.
Round the land area of the state with the least number of square miles to the nearest ten thousand.
Answer:

Question 13.
The town of Worman Grove has collected 28,481 pens for a school supplies drive. Their goal is 30,000 pens. Show how to use counting on to find how many more pens they need to reach their goal.
Answer:

Question 14.
Conservationists weigh two Northern elephant seals. An adult seal weighs 6,600 pounds, and its pup weighs 3,847 pounds. What is their combined weight? Explain how to use mental math to solve.
Answer:

Question 15.
Higher Order Thinking Is Kelly’s answer correct? What mistake did she make?
Kelly’s Work
5,356 + 2,398
= (5,356 + 2) +(2,398 + 2)
5,358 + 2,400 = 7,758
Answer:
Kelly’s work is wrong.her mistake is she has to add and subtract the number if the question is to find the sum.

Explanation:
Add and subtract same number, the answer will not differ.
(5356-2) + (2398+2)
5354 + 2400
7754
Therefore 5356 + 2398 = 7754.

Assessment Practice

Question 16.
Use mental math to find 1,218 + 1,598.
A. 2,716
B. 2,720
C. 2,816
D. 2,820
Answer:
C.2816

Explanation:
1218+1598
Break apart 1218 as 1000 and 218 and and the second part with 1598.
=(1000+218)+1598
=1000+(218+1598)
=1000+1816
=2816
1218+1598=2816

Question 17.
Use mental math to find 5,280 – 1,997.
A. 3,177
B. 3,180
C. 3,277
D. 3,283
Answer:
D.3283

Explanation:
5280-1997
Adding the same amount to both numbers in a subtraction problem doesn’t change the difference
=(5280+3) – (1997+3)
=5283 – 2000
=3823
5280-1997=3823

Lesson 2.2 Estimate Sums and Differences

Solve & Share
A manufacturer in Detroit produces three new cars that weigh 6,127 pounds, 4,652 pounds, and 3,393 pounds. If these are are loaded on a truck, has the truck reached its 15,000-pound maximum? Use an estimate to decide. Solve this problem any way you choose.
I can … use rounding and place value to estimate sums and differences.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 14
Answer:

Explanation:
When these three cars are loaded in the truck, the truck doesn’t reach the maximum limit of 15000pounds as the estimated total weight of the three cars is 14200.

Look Back! Why can you solve the problem using only an estimate rather than finding the exact weight of the three cars?

Essential Question
How Can You Estimate Sums and Differences of Whole Numbers?
Answer:
We can estimate the sums and difference of whole numbers by rounding of them to the nearest hundreds and thousands.

Visual Learning Bridge
Books, magazines, and movies were checked out of the public library. About how many more books were checked out than magazines and movies combined?
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 15

Estimate: Round to the nearest thousand.
Find the number of magazines and movies.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 16
Subtract the number of magazines and movies from the rounded number of books.
13,000 – 6,000 = 7,000
About 7,000 more books were checked out.

Estimate: Round to the nearest hundred.
Find the number of magazines and movies.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 17
Subtract the number of magazines and movies from the rounded number of books.
12,600 – 6,400 = 6,200
About 6,200 more books were checked out.

Convince Me! Construct Arguments The head librarian at the public library says she will establish a separate checkout desk for magazines and movies if the difference between the number of books and the number of these other materials is greater than 6,500. Which of the estimates above should you use to help her make her decision? Explain.

Another Example!
Decide if each computation is reasonable.
You can use an estimate to decide whether or not an exact answer is reasonable.
39,482 + 26,357 = 65,839
39,482 + 26,357 is about 40,000 + 26,000 = 66,000
The sum, 65,839, is reasonable because it is close to the estimate of 66,000.

8,215 – 5,852 = 3,643
8,215 – 5,852 is about 8,000 – 6,000 = 2,000
The difference, 3,643, is not reasonable because it is not close to the estimate of 2,000.

Guided Practice

Do You Understand?
Question 1.
Is 2,793 a reasonable difference for 6,904 – 4,111? Explain.
Answer:

Explanation:
Yes, 2793 is a reasonable difference for 6,904 – 4,111 as estimated difference is 2800 and 2793 is very close to 2800.

Do You Know How?
For 2-4, estimate each sum or difference.
Question 2.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 18
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated sum is 9400.

Question 3.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 19
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated sum is 88500.

Question 4.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 20
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated difference is 13200.

Independent Practice

Leveled Practice For 5-13, estimate each sum or difference.
Question 5.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 21
Answer:

Explanation:
When rounded to the nearest thousands,
The estimated sum is 8000.

Question 6.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 22
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated difference is 515400.

Question 7.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 23
Answer:

Explanation:
When rounded to the nearest ten thousands,
The estimated sum is 110000.

Question 8.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 24
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated sum is 4300.

Question 9.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 25
Answer:

Explanation:
When rounded to the thousands
The estimated sum is 766200.

Question 10.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 26
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated difference is 14260.

Question 11.
485,635 – 231,957
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated difference is 253600.

Question 12.
9,668 – 2,489
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated difference is 7200.

Question 13.
368,545 + 114,254
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated sum is 482800.

Problem Solving

Question 14.
The table shows the number of students at each school in the district. Is 2,981 reasonable for the total number of students at Wilson Elementary and Kwame Charter School? Explain.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 27
Answer:

Explanation:
When rounded to the nearest hundreds,
The estimated sum is 3000.
Therefore, as 2,981 is close to 3000, it is reasonable for the total number of students at Wilson Elementary and Kwame Charter School

Question 15.
enVision® STEM A satellite moves at a speed of 27,950 kilometers per hour. A satellite at a higher orbit travels at a speed of 11,190 kilometers per hour. About how much faster is one satellite than the other? Explain how to estimate.
Answer:

Explanation:
When rounded to nearest thousands,
The estimated difference is 17000.

Question 16.
Critique Reasoning Elle says, “When rounding to the nearest thousand, 928,674 rounds to 930,000.” Do you agree? Explain.
Answer:
No, I don’t agree with Elle as she rounded of to the nearest then thousands rather tha nearest thousand.
The nearest thousand for 928674 is 929000.
When we round of o the nearest thousand we have to look at the last three digits and if it lessthan 500 we hav eto round of to the same digit in the thousands place, if it is more than 500 then we have to roundof to the net thousand than the digit in thousands place.

Question 17.
Higher Order Thinking A football team needs to sell at least 20,000 tickets to two games to cover expenses. They sell 10,184 tickets to one game and 9,723 to the other. Estimate by rounding to the nearest thousand and by rounding to the nearest hundred. Did the team sell enough tickets? Explain your answer.
Answer:

Explanation:
The estimated sum of tickets sold when rounded to hundreds is 20900
The estimated sum of tickets sold when rounded to thousands is 20000
As both sums are same or close to 20000.
Therefore, the team could sell enough ticketsto cover their expenses.

Assessment Practice

Question 18.
Last week, Mallory flew two round trips. They were 3,720 miles and 5,985 miles. Which is the best estimate of the total distance Mallory flew?
A. 11,000 miles
B. 9,700 miles
C. 8,700 miles
D. 8,000 miles
Answer:
B.9700

Explanation:
The sum of miles Mallory flew when rounded to hundreds is 9700,
The sum of miles Mallory flew when rounded to thousands is 10000,
As the option B.9700 is close to the estimates So, rounded to hundreds is the best estimate.

Question 19.
Use estimation to decide which is a reasonable difference.
38,041 – 19,558
A. 21,374
B. 20,973
C. 18,473
D. 16,483
Answer:
C.18473

Explanation:
As the estimated difference whrn roundrev to the nearest hundreds is 18400 and as 18473 is close to 18400, 18473 is reasonable.

Lesson 2.3 Add Whole Numbers

Solve & Share
Students collect empty plastic water bottles to recycle. How many bottles were collected in the first two months? How many bottles were collected in all three months? Solve this problem using any strategy you choose.
I can … connect place-value concepts to using addition algorithms.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 28

Look Back! When adding, how do you know when there are enough tens to make one hundred?

Essential Question
How Do You Add Whole Numbers Efficiently?

Visual Learning Bridge
The Florida Legislature set a statewide recycling goal. To help meet this goal, Kennedy Elementary school students collected newspaper. How many pounds of newspaper did they collect in all?
Add 358 + 277.
Estimate.
350 + 250 = 600
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 29

Add using partial sums.
Add using the standard algorithm.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 31

Convince Me! Use Structure in the problem above, when you add partial sums you can add the ones first or the hundreds. Can you do the same when you add using the standard algorithm?

Guided Practice

Do You Understand?
Question 1.
When you place a 1 above the tens values, what does it mean?
Answer:
If i place 1 above the tens values it means that i regrouped ones.

Question 2.
When you place a 1 above the hundreds values, what does it mean?
Answer:
If i place 1 above the hundreds values it means that i regouped tens.

Do You Know How?
Find the sum by using partial sums and by using the standard algorithm.
Question 3.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 32
Answer:

Explanation:
The sum of 378 and 557 is 935.

Find each sum using the strategy you choose.
Question 4
a.
Envision Math Common Core 4th Grade Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 33
Answer:

Explanation:
The sum of 678 and 253 is 931.

b.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 34
Answer:

Explanation:
The sum of 325 and 256 is 581.

c.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 35
Answer:

Explanation:
The sum of 185 and 253 is 438.

Independent Practice

In 5-16, find each sum.
Question 5.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 36
Answer:

Explanation:
The sum of 148 and 157 is 305.

Question 6.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 37
Answer:

Explanation:
The sum of 389 and 461 is 850.

Question 7.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 38
Answer:

Explanation:
The sum of 365 and 458 is 823.

Question 8.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 39
Answer:

Explanation:
The sum of 126 and 138 is 264.

Question 9.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 40
Answer:

Explanation:
The sum of 371 and 454 is 825.

Question 10.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 41
Answer:

Explanation:
The sum of 357 and 498 is 855.

Question 11.
142 + 178
Answer:

Explanation:
The sum of 142 and 178 is 320.

Question 12.
565 + 694
Answer:

Explanation:
The sum of 565 and 694 is 1259.

Question 13.
375 + 548
Answer:

Explanation:
The sum of 375 and 548 is 923.

Question 14.
718 + 865
Answer:

Explanation:
The sum of 718 and 865 is 1583.

Question 15.
909 + 624
Answer:

Explanation:
The sum of 909 and 624 is 1533.

Question 16.
129 + 587
Answer:

Explanation:
The sum of 129 and 587 is 716.

Problem Solving

Question 17.
Construct Arguments Harmony solved this problem using the standard algorithm, but she made an error. What was her error, and how can she fix it?
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 42
Answer:

Explanation:
The sum of 437 and 175 is 612.
Harmony didnot regroup tens.she should regroup tens and place 1 above the hundreds place to solve the problem.

Question 18.
Higher Order Thinking For which problems would you use a mental strategy or the standard algorithm to solve? Explain.
499 + 121
827 +385
175 + 325
Answer:
I use mental strategy to solve 499+121 and 175+325 as the number in hundreds place is small and it is easy to slove mentally, I use standard algorithm to solve 827+385 as the number in hundreds place is big.

Question 19.
A Little League team played a doubleheader (two back-to-back baseball games). The first game lasted 155 minutes. The second game lasted 175 minutes. There was a 30-minute break between games. What was the total time of the doubleheader?
Answer:

Explanation:
A Little League team played a doubleheader, The first game lasted 155 minutes. The second game lasted 175 minutes. There was a 30-minute break between games.
To find the total time of the doubleheader we need to add 155, 165 and 30.
The the total time of the doubleheader is 360.

Assessment Practice

Question 20.
Select all the correct sums.
☐ 742 + 353 = 1,095
☐ 428 + 247 = 665
☐ 604 + 684 = 1,288
☐ 735 + 298 = 1,033
☐ 912 + 198 = 1,010
Answer:

Explanation:
The marked sums are correct.

Question 21.
What is the missing digit in the addition problem?
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 43
Answer:

Explanation:
To find the missing number first subtract 1004 and 659, we get 345 as the answer.The missing tens is 4.

Lesson 2.4 Add Greater Numbers

Solve & Share
Erica’s class collected 4,219 bottles for the recycling center. Ana’s class collected 3,742 bottles. Leon’s class collected 4,436 bottles. How many bottles did the three classes collect? Solve this problem any way you choose.
I can … use the standard algorithm and place value to add multi-digit numbers.

Look Back! Generalize Which properties allow you to change the order and grouping of numbers to add? How did you use these properties?

Essential Question
baby How Do You Add Greater Numbers?

Visual Learning Bridge
Plans for remodeling a sports stadium include adding an additional 19,255 seats. How many seats will be in the remodeled stadium?
Seats in the original stadium:
20,000 + 4,595 = 24,595
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 45

Step 1
Use the standard algorithm for addition
To add 24,595 + 19,255, add the ones, then the tens, and then the hundreds. Regroup if necessary
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 46

Step 2
Add the thousands and the ten thousands. Regroup if necessary.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 47
The remodeled stadium will have 43,850 seats.
You can add two or more numbers when you line up the numbers by place value. Add one place at a time.

Step 3
Use an estimate to check if your answer is reasonable.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 48
43,850 is close to the estimate of 44,000, so the answer is reasonable.

Convince Me! Construct Arguments When using the standard algorithm to add 24,595 + 19,255, how do you regroup 1 ten + 9 tens + 5 tens?

Another Example!
Find 30,283 + 63,423 + 6,538.
Explain how to check that your answer is reasonable.
Estimate:
30,000 + 63,000 + 7,000 = 100,000
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 49
The sum is reasonable because it is close to the estimate of 100,000.

Guided Practices

Do You Understand?
Question 1.
When adding 36,424 and 24,482, why is there no regrouping in the final step?
Answer:

Explanation:
When 36424 and 24482 are added there is no regrouping in the final step because the sum of the final numbers donot exceed 9.

Question 2.
Science-volunteer teams catalog 7,836 species of insects and 4,922 species of spiders. How many species did the volunteers catalog?
Answer:

Explanation:
12758 species the volunteers cataloged.

Do You Know How?
For 3-6, find each sum. Check that your answer is reasonable.
Question 3.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 50
Answer:

Explanation:
The sum of 14926 and 3382 is 18308.Answer is reasonable as the estimate 18000 is close to the answer.

Question 4.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 51
Answer:

Explanation:
The sum of 423156 and 571607 is 994763.Answer is reasonable as the estimate 99500 is close to the answer.

Question 5.

Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 52
Answer:

Explanation:
The sum of 3258 and 1761 is 5019.Answer is reasonable as the estimate 5100 is close to the answer.

Question 6.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 53
Answer:

Explanation:
The sum of 82385 and 49817 is 132202.Answer is reasonable as the estimate 132000 is close to the answer.

Independent Practice

For 7-16, find each sum. Check that your answer is reasonable.

Question 7.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 54
Answer:

Explanation:
The sum of 14312 and 9617 is 23929.Answer is reasonable as the estimate 24000 is close to the answer.

Question 8.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 55
Answer:

Explanation:
The sum of 275558 and 605131 is 880689.Answer is reasonable as the estimate 881000 is close to the answer.

Question 9.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 56
Answer:

Explanation:
The sum of 38911 and 45681 is 84592.Answer is reasonable as the estimate 85000 is close to the answer.

Question 10.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 57
Answer:

Explanation:
The sum of 5801 and 4189 is 9990.Answer is reasonable as the estimate 10000 is close to the answer.

Question 11.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 58
Answer:

Explanation:
The sum of 8818 and 1182 is 10000.Answer is reasonable as the estimate 10000 is close to the answer.

Question 12.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 59
Answer:

Explanation:
The sum of 5555 and 7412 is 12967.Answer is reasonable as the estimate 13000 is close to the answer.

Question 13.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 60
Answer:

Explanation:
The sum of 21009 and 5529 is 26538.Answer is reasonable as the estimate 26600 is close to the answer.

Question 14.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 61
Answer:

Explanation:
The sum of 30080 and 19187 is 49267.Answer is reasonable as the estimate 49000 is close to the answer.

Question 15.
29,634 + 12,958 + 6,835
Answer:

Explanation:
The sum of 29634, 12958 and 6835 is 49427.

Question 16.
64,673 + 48,262 + 8,918
Answer:

Explanation:
The sum of 64673, 48262 and 8918 is 121853.

Problem Solving

Question 17.
Aubrey writes a blog. 29,604 people read her first post. The next week, 47,684 people read her second post. Aubrey’s third post had 41,582 readers. What is the total number of readers?
Answer:

Explanation:
The sum of 29604, 47684 and 4152 is 81440.
Therefore the total number of readers are 81440.

Question 18.
Write the number name for 21,604.
Answer:
Number name of 21604 is Twenty one thousand six hundred four.

Question 19.
Higher Order Thinking Explain the mistake made when finding the sum at the right. What is the correct sum?
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 62
Answer:
The correct sum is 872879.

Explanation:
The sum of 638528 and 234351 is 872879.
The mistake is regrouping 8 and 4 thousands as 1 tensthousand is not done in the given sum.

Question 20.
Number Sense Maria added 45,273 and 35,687 and got a sum of 70,960. Is Maria’s answer reasonable? Explain.
Answer:

Explanation:
Estimate:
45273-45000, 35687-36000
45000+36000=81000
The sum of 45273 and 35687 is 80960.Maria’s answer is not reasonable as the estimate is not close to the answer.

Question 21.
Make Sense and Persevere There were 130,453 pairs of skates rented at an ice rink in one year. The next year, 108,626 pairs were rented. The following year 178,119 pairs were rented. How many pairs were rented during the busiest two years? How many pairs were rented during all three years?
Answer:

Explanation:
308572 pairs were rented during the busiest two years.
417198 pairs were rented during all three years

Assessment Practice

Question 22.
Select all the correct sums.
☐ 5,742 + 8,353 = 14,095
☐ 9,428 + 18,247 = 27,665
☐ 29,604 + 47,684 = 77,288
☐ 66,288 + 145,280 = 211,568
☐ 235,912 + 19,847 = 434,382
Answer:

Question 23.
Select all the addition expressions that have a sum of 89,405.
☐ 78,487 + 7,998
☐ 79,562 + 9,843
☐ 2,222 + 77,183
☐ 52,514 + 36,891
☐ 6,573 + 82,832
Answer:

Lesson 2.5 Subtract Whole Numbers

Solve & Share
Carly’s parents own a motel in Orlando with 224 rooms. Last night, 176 rooms were rented. How many rooms were not rented? Solve this problem using any strategy you choose.
I can … connect place-value concepts to using the standard algorithm for subtraction
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 63

Look Back! How can you use properties to find the number of rooms not rented?

Essential Question
How Can You Subtract Whole Numbers Efficiently?

Visual Learning Bridge
The movie theater already sold 172 seats. How many seats are still available?
Subtract 358 – 172.
Estimate: 400 – 200 = 200
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 64

What You Show
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 65

What You Write
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 66

Convince Me! Use Structure How many times do you need to regroup to subtract 483 – 295? Explain.

Guided Practice

Do You Understand?
Question 1.
To subtract 859 – 583, how do you regroup 8 hundreds 5 tens?
Answer:

Explanation:
The difference of 859 and 583 is 276.
I regrouped 8hundreds 5tens as 7hundreds 15tens.

Question 2.
What do you need to regroup to subtract 753 – 489 using the standard algorithm?
Answer:

Explanation:
The difference of 753 and 489 is 264.
I need to regroup 5tens 3ones and 7hundreds 4tens.

Do You Know How?
In 3-6, subtract. Use an estimate to check that your answer is reasonable.
Question 3.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 67
Answer:
Estimate: 154 — 150, 89 — 90
150-90 = 60

Explanation:
The difference of 154 and 89 is 65.
The difference 65 is reasonable as it is close to the estimated difference 60.

Question 4.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 68
Answer:
Estimate: 592 — 590, 357 — 360
590-360=230

Explanation:
The difference of 592 and 357 is 235.
The difference 235 is reasonable as it is close to the estimated difference 230.

Question 5.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 69
Answer:
Estimate: 915 — 920, 288 — 290
920-290=630

Explanation:
The difference of 915 and 288 is 627.
The difference 627 is reasonable as it is close to the estimated difference 630.

Question 6.
Envision Math Common Core 4th Grade Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 70
Answer:
Estimate: 743 — 740, 694 — 690
740-690=50

Explanation:
The difference of 743 and 694 is 49.
The difference 49 is reasonable as it is close to the estimated difference 50.

Independent Practice

In 7-18, subtract. Use an estimate to check that your answer is reasonable.
Question 7.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 71
Answer:
Estimate: 289 — 290, 145 — 150
290-150=140

Explanation:
The difference of 289 and 145 is 144.
The difference 144 is reasonable as it is close to the estimated difference 140.

Question 8.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 72
Answer:
Estimate: 326 — 330, 184 — 180
330-180=150

Explanation:
The difference of 326 and 184 is 142.
The difference 142 is reasonable as it is close to the estimated difference 150.

Question 9.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 73
Answer:
Estimate: 736 — 740, 218 — 220
740-220=520

Explanation:
The difference of 736 and 218 is 518.
The difference 518 is reasonable as it is close to the estimated difference 520.

Question 10.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 74
Answer:
Estimate: 525 — 530, 267 — 270
530-270=260

Explanation:
The difference of 525 and 267 is 258.
The difference 258 is reasonable as it is close to the estimated difference 250.

Question 11.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 75
Answer:
Estimate: 683 — 680, 295 — 300
680-300=380

Explanation:
The difference of 683 and 295 is 388.
The difference 388 is reasonable as it is close to the estimated difference 380.

Question 12.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 76
Answer:
Estimate: 847 — 850, 387 — 390
850-390=460

Explanation:
The difference of 847 and 837 is 460.
The difference 460 is reasonable as it is close to the estimated difference 460.

Question 13.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 77
Answer:
Estimate: 475 — 480, 98 — 100
480-100=380

Explanation:
The difference of 475 and 98 is 377.
The difference 377 is reasonable as it is close to the estimated difference 380.

Question 14.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 78
Answer:
Estimate: 826 — 830, 184 — 180
830-180=650

Explanation:
The difference of 826 and 184 is 642.
The difference 642 is reasonable as it is close to the estimated difference 650.

Question 15.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 79
Answer:
Estimate: 936 — 940, 218 — 220
940-220=720

Explanation:
The difference of 936 and 218 is 718.
The difference 718 is reasonable as it is close to the estimated difference 720.

Question 16.
167 – 79
Answer:

Explanation:
The difference of 167 and 79 is 88.

Question 17.
284 – 167
Answer:

Explanation:
The difference of 284 and 167 is 117.

Question 18.
817 – 548
Answer:

Explanation:
The difference of 817 and 548 is 269.

Problem Solving

Question 19.
How much greater is the area of Hernando County than Union County?
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 80
Answer:

Explanation:
The difference of 473 and 244 is 229.
Therefore, the area of Hernando County is 229squaremiles than Union County.

Question 20.
Make Sense and Persevere How much greater is the area of Monroe County than the area of Union County and Hernando County combined? Explain.
Answer:
The area of union country and hernando country combines is 719sqmiles


Explanation:
The difference of 983 and 719 is 264.
Therefore, the area of Monroe County is 264sqmiles greater than the area of Union County and Hernando County combined.

Question 21.
Population density is measured in people per square mile. It indicates how crowded an area is. How many more people per square mile does Brevard County have than neighboring Volusia County?
Answer:

Explanation:
The difference of 535 and 449 is 86.
Therefore, Brevard County have 86more people per square mile than neighboring Volusia County .

Question 22.
Higher Order Thinking What mistake did Leon make? What is the correct difference?
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 81
Answer:

Explanation:
The difference of 793 and 576 is 217.
The correct difference is 217,The mistake made by leon is he unnecessarily regrouped hundreds.to find the differene of the above numbers their is no need of regrouping hundreds.

Assessment Practice

Question 23.
What is the difference?
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 82
A. 1,183
B. 335
C. 266
D. 265
Answer:
D.265.

Explanation:
The difference of 724 and 459 is 265.

Question 24.
What is the missing digit in the subtraction statement?
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 83
Answer:

Explanation:
The difference of 634 and 297 is 337.
Therefore, the missing number in the subtraction statement is 9.

Lesson 2.6 Subtract Greater Numbers

Solve & Share
Nevada has a land area of 109,781 square miles. Colorado has a land area of 103,642 square miles. How much larger is Nevada than Colorado? Solve this problem any way you choose.
I can … use the standard algorithm and place value to subtract whole numbers.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 84

Look Back! Estimate the difference in the areas of the two states. Is your answer close to this estimate?

Essential Question
How Do You Subtract Greater Numbers Efficiently?

Visual Learning Bridge
Three of the country’s most scenic national parks are in Alaska. How much larger is the area of Gates of the Arctic than the combined area of Denali and Kenai Fjords?
Find the total area of Denali and Kenai Fjords.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 85

Step 1
Find 34,287 – 21,893.
Subtract the ones. Regroup if necessary
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 86

Step 2
Subtract the tens, hundreds, thousands, and ten thousands.
Regroup if necessary
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 87
Gates of the Arctic is 12,396 square kilometers larger.

Step 3
Operations that undo each other are inverse operations. Addition and subtraction have an inverse relationship. Add to check your answer.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 88

Convince Me! Critique Reasoning The work shown is NOT correct. What errors were made? Show how to find the correct answer.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 89

Another Example!
Find 38,792. – 33,215.
Estimate:
39,000 – 33,000 = 6,000
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 90

Guided Practice

Do You Understand?
Question 1.
In the subtraction problem above, why was the zero in the ten thousands place not written in the answer?
Answer:

Question 2.
The total land area of New Jersey is 19,047 square kilometers. Write and solve an equation to show how to find how much more land area Gates of the Arctic has than New Jersey.
Answer:
34287-19407 sqkm = 14880 sqkm

Explanation:
The Gates of the Arctic has 14880sqkilometers more land area than New Jersey.

Do You Know How?
For 3-6, subtract. Estimate to check whether your answers are reasonable.
Question 3.
139,484 – 116,691
Answer:
Estimate: 140000-120000=20000

Explanation:
The difference of 139484 and 116691 is 22793.
The difference 22793 is reasonable as it is close to the estimate 20000.

Question 4.
2,164 – 1,398
Answer:
Estimate:2200-1400=800

Explanation:
The difference of 2164 and 1398 is 766.
The difference 766 is reasonable as it is close to the estimate 800.

Question 5.
49,735 – 25,276
Answer:
Estimate: 50000-25000=25000

Explanation:
The difference of 49735 and 25276 is 24459.
The difference 24459 is reasonable as it is close to the estimate 25000.

Question 6.
281,311 – 3,427
Answer:
Estimate: 281000-3000=278000

Explanation:
The difference of 281311 and 3427 is 277884.
The difference 277884 is reasonable as it is close to the estimate 280000.

Independent Practice

For 7-14, subtract. Estimate to check if your answers are reasonable.
Question 7.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 91
Answer:
Estimate: 82000-47000=35000

Explanation:
The difference of 82376 and 47294 is 35082.
The difference 35082 is reasonable as it is close to the estimate 35000.

Question 8.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 92
Answer:
Estimate: 654000-562000=92000

Explanation:
The difference of 653642 and 562410 is 91232
The difference 91232 is reasonable as it is close to the estimate 92000.

Question 9.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 93
Answer:
Estimate: 9000-4000=5000

Explanation:
The difference of 9128 and 3753 is 5375
The difference 5375 is reasonable as it is close to the estimate 5000.

Question 10.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 94
Answer:
Estimate: 43000-8000=35000

Explanation:
The difference of 42648 and 8169 is 34479
The difference 34479 is reasonable as it is close to the estimate 35000.

Question 11.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 95
Answer:
Estimate: 426000-87000=339000

Explanation:
The difference of 425637 and 86942 is 338695
The difference 338695 is reasonable as it is close to the estimate 339000.

Question 12.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 96
Answer:
Estimate: 8500-2000=6500

Explanation:
The difference of 8457 and 1946 is 6511
The difference 6511 is reasonable as it is close to the estimate 6500.

Question 13.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 97
Answer:
Estimate: 216000-176000=40000.

Explanation:
The difference of 215714 and 176313 is 39401
The difference 39401 is reasonable as it is close to the estimate 40000.

Question 14.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 98
Answer:
Estimate: 86000-74000=12000

Explanation:
The difference of 85968 and 74084 is 11884
The difference 11884 is reasonable as it is close to the estimate 12000.

Problem Solving

Question 15.
Reasoning A crayon company makes 87,491 blue crayons, 36,262 red crayons, and 25,063 gray crayons. How many more blue crayons are made than red and gray crayons combined?
Answer:
There are 61325 red and gray crayons combined


Explanation:
The difference of 87491 and 61325 is 26166.
Therefore there are 26166 blur crayons are made more than red and grey crayons.

Question 16.
Number Sense Patrick subtracted 4,832 – 2,322 and got 2,510. Is his difference reasonable? Explain.
Answer:
Yes, Patrick’s answer is reasonable.

Explanation:
Estimate: 4800-2300=2500
The difference 2510 is reasonable as it is close to estimate 2500.

Question 17.
Higher Order Thinking Nadia found 9,476 – 8,185 using the algorithm shown. Show how to find 1,784 – 1,339 with Nadia’s algorithm.
9,476 – 8,185 = 1,000 + 300 – 10 + 1
= 1,291
Answer:
1784-1339 = 500-100+40+5

Explanation:
Using Nadia’s algorithm i shown the difference 1784 and 1339 by adding and subtracting numbers.

Question 18.
How many more people attended the street fair in 2019 than in 2017 and 2018 combined?
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 99
Answer:
193301 people attended the street fair in 2017 and 2018 combined

Explanation:
The difference of 362839 and 169538 is 169538.
Therefore, 169538 more people attended the street fair in 2019 than in 2017 and 2018 combined.

Question 19.
On Monday, from the peak of Mount Kilimanjaro, a group of mountain climbers descended 3,499 feet. On Tuesday, they descended another 5,262 feet. How many feet did the mountain climbers descend after 2 days? How many more feet do they have to descend to reach the bottom?
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 100
Answer:
8761 feet the mountain climbers descend after 2 days

Explanation:
The difference of 19341 and 8761 is 10580.
10580 feet they have to descend to reach the bottom.

Assessment Practice

Question 20.
What is the missing digit in the subtraction statement?
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 101
Answer:


Explanation:
The difference of 365928 and 187669 is 178259.
So, the missing digit in the number 178259 in the above question is 8.

Question 21.
What is the difference 62,179 – 31,211?
A. 31,968
B. 30,986
C. 30,968
D. 30,000
Answer:
C.30968

Explanation:
The difference of 62179 and 31211 is 30968.

Lesson 2.7 Subtract Across Zeros

Solve & Share
London, England, is 15,710 kilometers from the South Pole. Tokyo, Japan, is 13,953 kilometers from the South Pole. How much farther is London than Tokyo from the South Pole? Solve this problem any way you choose.
I can … use the standard algorithm to subtract from numbers with zeros.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 102

Look Back! Explain how you decided what operation to use to find how much farther London is than Tokyo from the South Pole.

Essential Question
How Do You Subtract Across Zeros?

Visual Learning Bridge
A music hall is hosting a concert. The hall sells 4,678 tickets to the show. How many tickets are still available?
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 103

Regroup.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 104

Subtract.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 105
Since the difference 1,322 is close to the estimate 1,300, the difference is reasonable.
There are still 1,322 tickets available for the concert.

Convince Me! Use Structure How would you regroup if the hall had 5,900 seats?

Guided Practice

Do You Understand?
Question 1.
Leesa used compensation to solve the problem on the previous page. She subtracted (6,000 – 1) – (4,678 – 1) = 5,999 – 4,677 = 1,322. How could you use Leesa’s approach to subtract 5,000 – 1,476?
Answer:
3524

Explanation:
Using Leesa’s approach we can solve 5000-1476 by subrtacting 1 from both the numbers as shown below
=(5000-1)-(1476-1)
=4999-1475
=3524
Therefore, the difference of 5000 and 1476 is 3524.

Question 2.
One passenger flew 11,033 kilometers from Oslo to Lima. Another passenger flew 8,593 kilometers from Oslo to Los Angeles. How many more kilometers was the flight to Lima?
Answer:

Do You Know How?
For 3-8, subtract.
Question 3.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 106
Answer:

Question 4.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 107
Answer:

Question 5.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 108
Answer:

Question 6.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 109
Answer:

Question 7.
101,001 – 8,915
Answer:

Question 8.
9,050 – 3,461
Answer:

Independent Practice

For 9-23, subtract.
Estimate to check if your answer is reasonable.
Question 9.
Envision Math Common Core Grade 4 Answer Key Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 110
Answer:

Question 10.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 111
Answer:

Question 11.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 112
Answer:

Question 12.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 113
Answer:

Question 13.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 114
Answer:

Question 14.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 115
Answer:

Question 15.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 116
Answer:

Question 16.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 117
Answer:

Question 17.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 118
Answer:

Question 18.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 119
Answer:

Question 19.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 120
Answer:

Question 20.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 121
Answer:

Question 21.
6,090 – 5,130
Answer:

Question 22.
11,246 – 9,489
Answer:

Question 23.
790,008 – 643,829
Answer:

Problem Solving

Question 24.
Construct Arguments Will the difference between 44,041 and 43,876 be greater or less than 1,000? Explain.
Answer:

Question 25.
Vocabulary Define variable and give an example of how a variable is used in an equation.
Answer:

For 26-27, use the table at the right.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 122
Question 26.
How many more hip-hop than country downloads were sold?
Answer:

Question 27.
Higher Order Thinking How many more hip-hop and Latin downloads were sold than rock and country downloads? Explain.
Answer:

Assessment Practice

Question 28.
Select all the correct differences.
☐ 5,000 – 1,856 = 3,244
☐ 10,700 – 8,243 = 2,457
☐ 64,002 – 43,178 = 20,934
☐ 98,000 – 59,214 = 38,786
☐ 600,482 – 428,531 = 171,951
Answer:

Question 29.
Find the difference.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 123
A. 17,355
B. 20,757
C. 21,757
D. 98,243
Answer:

Lesson 2.8 Problem Solving

Reasoning
Solve & Share
A group of students collected donations for a toy drive. They collected a total of 3,288 toys one week and 1,022 toys the next week. They donated 1,560 toys to the Coal City Charity and the rest were donated to Hartville Charity. How many toys were donated to Hartville Charity? Use reasoning about numbers to show and explain how the two quantities of toys given to charity are related.
I can … make sense of quantities and relationships in problem situations.

Thinking Habits
Be a good thinker! These questions can help you.

  • What do the numbers and symbols in the problem mean?
  • How are the numbers or quantities related?
  • How can I represent a word problem using pictures, numbers, or equations?

Look Back! Reasoning Over three weeks, the students collected a total of 8,169 toys. How many toys did they collect in the third week? Complete the bar diagram to show your reasoning. Did the students collect more toys in the third week than in weeks 1 and 2 combined? Explain.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 124

Essential Question
How Can You Use Quantitative Reasoning to Solve Problems?

Visual Learning Bridge
Kara and Carl join their mother on a boat off the coast of the Florida Keys. Their mother is a scientist studying blue marlins. Each child gets to help weigh two marlins. How much more did Kara’s marlins weigh than Carl’s?
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 125
How can you draw a diagram to help reason how the numbers in the problem are related?
I can represent the relationship between the numbers with a bar diagram.

How can I use reasoning to solve this problem?
I can

  • identify the quantities I know.
  • draw diagrams and write equations to show relationships.
  • connect the solution back to the real world problem.

Here’s my thinking.
K = the total weight of Kara’s marlins, and C = the total weight of Carl’s marlins.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 126
Kara’s marlins weighed 299 pounds more than Carl’s.

Convince Me! Reasoning Write a problem that can be solved using the bar diagram below. Write an equation to solve. Use reasoning to think about the meaning of each number before starting.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 127

Guided Practice

Reasoning
A manufacturer shipped 12,875 fidget spinners one week and 9,843 of them were sold. The next week, they shipped 19,175 and 12,752 of them were sold. How many fidget spinners had not sold yet?
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 128

Question 1.
What quantities are given in the problem, and what do the numbers mean?
Answer:

Question 2.
Use the bar diagrams that show the relationships of the numbers in the problem. Write and solve equations which could be used to find f, the spinners not sold the first week; s, the spinners not sold the second week; and t, the total spinners not sold.
Answer:

Independent Practice

Reasoning A wall is being built with 16,351 stones. The builders have placed 8,361 stones, and they have 7,944 stones left. Do they have enough stones? How many more stones do they need?

Use Exercises 3-5 to answer the question.
Question 3.
What quantities are given in the problem, and what do the numbers mean?
Answer:

Question 4.
Complete the bar diagram to show how to find s, the number of stones the builders have in all. Then, write and solve an equation. Do they have enough? Explain.
Answer:

Question 5.
Complete the bar diagram to show how to find the difference, d, of how many more stones the builders need. Then, write and solve an equation.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 129
Answer:

Problem Solving

Performance Task
Bird Migration Ornithology is the scientific study of birds. Every year, some birds travel great distances, or migrate, to find food and start families. The table shows the distances five species of birds flew over one year, as observed by an ornithologist. How much farther did the Arctic Tern fly than the Pectoral Short-Tailed Shearwater and the Pied Wheatear combined?
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 130

Question 6.
Reasoning What quantities are given in the problem and what do the numbers mean?
Answer:

Question 7.
Make Sense and Persevere What strategy can you use to solve the problem?
Answer:

Question 8.
Make Sense and Persevere What is the hidden question?
The hidden questions are the questions which must be answered before answering the main question asked in the problem.
Answer:

Question 9.
Model with Math Complete the bar diagrams to show how to find the answer to the hidden question and the main question. Write and solve equations.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 131
Answer:

Topic 2 Fluency Practice Activity

Follow the Path
Shade a path from START to FINISH. Follow the sums that are correct. You can only move up, down, right, or left.
I can.. add multi-digit whole numbers.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 132

Topic 2 Vocabulary Review

Understand Vocabulary
Word List

  • add on
  • algorithm
  • Associative Property of Addition
  • Commutative Property of Addition
  • compensation
  • Identity Property of Addition
  • inverse operations
  • variable

Question 1.
Circle the property of addition shown by 126 + 0 = 126.
Associative
Commutative
Identity
Answer:

Question 2.
Circle the property of addition shown by 21 + 34 = 34 + 21.
Associative
Commutative
Identity
Answer:

Question 3.
Circle the property of addition shown by (1 + 3) + 7 = 1 + (3 + 7).
Associative
Commutative
Identity
Answer:

Question 4.
Draw a line from each term to its example.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 133
Answer:

Use Vocabulary in Writing
Question 5.
Rob found 103 + 1,875 = x using mental math. Use at least 3 terms from the Word List to describe how Rob could find the sum.
Answer:

Topic 2 Reteaching

Set A pages 37-40

Find 3,371 + 2,429. Use mental math.
Make Ten
3,371 + 2,429 = 3,371 + (29 + 2,400)
= (3,371 +29) + 2,400
= 3,400 + 2,400 = 5,800
S0, 3,371 + 2,429 = 5,800.

Remember to adjust the sum or difference when you use the compensation strategy.
Question 1.
4,153 + 2,988
Answer:

Question 2.
92,425 + 31,675
Answer:

Question 3.
5,342 + 1,999
Answer:

Question 4.
22,283 – 14,169
Answer:

Question 5.
47,676 – 16,521
Answer:

Question 6.
1,089 – 961
Answer:

Set B pages 41-44

Estimate the sum by rounding each number to the nearest ten thousand.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 134
241,485 rounds to 240,000.
429,693 rounds to 430,000.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 135

Remember that you can round numbers to any place when estimating sums and differences.

Estimate each sum or difference.
Question 1.
652,198 + 49,753
Answer:

Question 2.
8,352 – 3,421
Answer:

Question 3.
17,586 – 9,483
Answer:

Question 4.
823,725 + 44,851
Answer:

Question 5.
1,440 – 933
Answer:

Question 6.
55,748 – 28,392
Answer:

Question 7.
4,981 + 6,193
Answer:

Question 8.
995,275 + 4,921
Answer:

Set C pages 45-52

Find 72,438 + 6,854.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 136
The answer 79,292 is close to the estimate of 79,000, so the answer is reasonable.

Remember to regroup if necessary when adding whole numbers.
Question 1.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 137
Answer:

Question 2.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 138
Answer:

Question 3.
215 + 8,823
Answer:

Question 4.
142,968 + 44,456
Answer:

Question 5.
2,417 + 3,573
Answer:

Question 6.
572,941 + 181,662
Answer:

Set D pages 53-60

Find 52,839 – 38,796.
Estimate: 53,000 – 39,000 = 14,000
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 139
The answer is reasonable.

Remember that you may need to regroup to subtract.

Question 1.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 140
Answer:

Question 2.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 141
Answer:

Question 3.
41,542 – 32,411
Answer:

Question 4.
4,978 – 2,766
Answer:

Question 5.
735,184 – 255,863
Answer:

Question 6.
44,558 – 22,613
Answer:

Set E pages 61-64

Find 60,904 – 54,832.
Estimate: 61,000 – 55,000 = 6,000
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 142
The answer is reasonable.

Remember you may need to regroup more than one place at a time to subtract across zeros.
Question 1.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 143
Answer:

Question 2.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 144
Answer:

Question 3.
70,000 – 25,228
Answer:

Question 4.
560,043 – 312,562
Answer:

Question 5.
8,052 – 1,205
Answer:

Question 6.
20,008 – 16,074
Answer:

Set F pages 65-68

Think about these questions to help you reason abstractly and quantitatively.
Thinking Habits

  • What do the numbers and symbols in the problem mean?
  • How are the numbers or quantities related?
  • How can I represent a word problem using pictures, numbers, or equations?
    Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 145

Remember that you can draw a bar diagram and use it to reason about a problem.

Raahil traveled 11,469 kilometers from home to visit his mother’s family in Qatar. He then traveled 12,332 kilometers from Qatar to visit his father’s family in Brisbane, Australia.
Question 1.
Draw a bar diagram that shows the distance Raahil traveled to Brisbane.
Answer:

Question 2.
Write and solve an equation for your bar diagram.
Answer:

Topic 2 Assessment Practice

Question 1.
The table shows the number of hot dogs Frank’s hot dog stand sold this weekend.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 146
A. Estimate the number of hot dogs sold by rounding each number in the table to the nearest thousand and finding the sum.
Answer:

B. Write and solve an equation to find how many hot dogs were sold.
Answer:

Question 2.
Find 8,000 – 6,280.
Answer:

Question 3.
Enter the missing digit to complete the subtraction.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 147
Answer:

Question 4.
Find the difference.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 148
A. 6,811
B. 6,351
C. 6,333
D. 6,331
Answer:

Question 5.
Complete the equation to make it true. Write your answer in the box.
12,769 + 16,065 = _________ + 15,402
Answer:

Question 6.
Find the difference. Then use addition to check your work.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 149
Answer:

Question 7.
Which of the following statements is true? Select all that apply.
☐ 12,395 + 14,609 = 27,004
☐ 76,237 – 4,657 = 42,430
☐ 67,407 – 38,227 = 29,180
☐ 69,844 + 1,014 = 70,452
☐ 34,980 – 1,999 = 32,981
Answer:

Question 8.
Find the sum.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 150
Answer:

Question 9.
Sandra used addition properties to rewrite the equation below. Select all the equations Sandra might have written.
1,450 + 1,125 + 1,050 = n
☐ (1,400 + 1,100 + 1,000) + (50 + 25 + 50) = n
☐ 1,450 + 1,050 = n 1,125 + 1,050 + 1,450 = n
☐ 1,000 + 1,000 + 1,000 + 450 + 50 + 125 = 1
☐ (1,450 + 1,050) + 1,125 = n
Answer:

Question 10.
Joe and Sara recorded the number of birds they saw in the park over two summers.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 151

A. Write and solve equations to find how many more total birds Joe and Sara saw this year than last year.
Answer:

B. Estimate how many more birds were seen in the park this year than last year by rounding each number in the table and solving the problem. Use the estimate to check if your answer to Part A is reasonable.
Answer:

Topic 2 Performance Task

Taking Inventory Jiao runs a wholesale art supply website. She fills bulk orders for craft and hobby stores.
Question 1.
Use the Wooden Beads table to answer the questions.
Part A
Crafts and Stuff ordered oak and ebony beads. Explain how to use mental math and properties of addition to find how many beads Jiao sent.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 152
Answer:

Part B
Jiao sends an order of oak and bayong beads to Jill’s Crafts and an order of ash and ebony beads to Create. How much larger is the order for Create? Write and solve equations to find j, the number of beads in the order to Jill’s Crafts; c, the number of beads in the order to Create; and d, the difference.
Answer:

Question 2.
Use the Glass Beads table to answer the questions.
Part A
Write and solve an equation to show how many glass beads, b, Create will have if they order the bubble and smoky beads.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 153
Answer:

Part B
Jiao sends the molded and stained beads to Hometown Craft Supply. Explain how to use compensation to find how many more molded beads than stained beads were sent.
Answer:

Question 3.
Use the Metal Beads table to answer the questions.
Part A
Write and solve an equation to show how many more beads, b, are in an order of gold beads than in an order of platinum beads.
Envision Math Common Core Grade 4 Answers Topic 2 Fluently Add and Subtract Multi-Digit Whole Numbers 154
Answer:

Part B
Craftology orders the brass and copper beads. After they arrive, the store sells 29,735 of them. How many beads does Craftology have left from their order? Show your computations.
Answer:

enVision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems

enVision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems

Go through the enVision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems regularly and improve your accuracy in solving questions.

enVision Math Common Core 3rd Grade Answers Key Topic 14 Solve Time, Capacity, and Mass Problems

Essential Question:
How can time, capacity, and mass be measured and found?
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 1

Answer:
The time is measured in hours.
the capacity is measured in liters.
the mass is measured in grams.

Explanation:
In the above-given question,
given that,
1 hour = 60 min.
1000 ml = 1 liter.
1000 g = 1 kg.
The time is measured in hours.
the capacity is measured in liters.
the mass is measured in grams.

enVision STEM Project: Forces and Interactions
Do Research Use the Internet or other sources to find information about magnets. How are magnets used? What types of magnets are there? Attach different amounts of paper together using a metal paper clip. How can you lift the paper using the magnet? How much mass can the magnet lift?

Answer:
There are three types of magnets are there.

Explanation:
In the above-given question,
given that,
there are three types of magnets are there.
they are permanent magnets, temporary magnets, and electromagnets.
Magnet is defined as a material that can produce its own magnetic field.
permanent magnets are magnets that are used permanently.
temporary magnets are used as per the situation.
electro magnets are used due to the support of an electric field.

Journal: Write a Report Include what you found. Also in your report:

  • Give examples of magnetic and non-magnetic materials.
  • Find the masses of the paper clip and of the paper.
  • Write an equation to show how much mass you can lift using the magnet.

Review What You Know

Vocabulary

  • denominator
  • numerator
  • number line
  • unit fraction

Choose the best term from the box. Write it on the blank.
Question 1.
The _________ tells the number of repetitions of the unit fraction.

Answer:
The numerator tells the number of repetitions of the unit fraction.

Explanation:
In the above-given question,
given that,
the numerator tells the number of repetitions of the unit fraction.
for example:
the numerator is 1.
the denominator tells how many equal parts are there.
examples of the unit fractions are 1/2, 1/3, 1/4, and 1/8.
so the numerator tells the number of repetitions of the unit fraction.

Question 2.
The ________ tells what fractional part is being counted.

Answer:
The denominator tells what fractional part is being counted.

Explanation:
In the above-given question,
given that,
the denominator tells what fractional part is being counted.
for example:
2/8 = 1/4.
so the denominator tells what fractional part is being counted.

Question 3.
One equal part of a whole can be represented using a _________

Answer:
One equal part of a whole can be represented using a number line.

Explanation:
In the above-given question,
given that,
one equal part of a whole can be represented using a number line.
for example:
if the number line is divided into 4 parts.
the fractions can be written as 1/4, 2/4, 3/4, and 4/4.
one equal part of a whole can be represented using a number line.

Solving 2-Step Problems
Question 4.
Mr. Vernon rides a train for 188 miles. Then he rides a subway for 9 stops. Each stop is 2 miles apart. How far does he travel?

Answer:
The number of miles Mr. Vernon rides = 206 miles.

Explanation:
In the above-given question,
given that,
Mr. Vernon rides a train for 188 miles.
then he rides a subway for 9 stops.
each stop is 2 miles apart.
9 x 2 = 18.
188 + 18 = 206.
so the number of miles Mr.Vernon rides = 206 miles.

Question 5.
Ms. Slate has a box of 320 new light bulbs. She replaces the light bulbs in 50 lamps. Each lamp has 5 sockets. How many new light bulbs does Ms. Slate have left?

Answer:
The number of light bulbs does Ms. Slate has left = 70 bulbs.

Explanation:
In the above-given question,
given that,
Ms. Slate has a box of 320 new light bulbs.
She replaces the light bulbs in 50 lams.
each lamp has 5 sockets.
50 x 5 = 250.
320 – 250 = 70.
so the number of light bubls does Ms. Slate has left = 70 bulbs.

Number Lines

Label the missing numbers on the number lines.
Question 6.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 2

Answer:
The missing numbers on the number line are 2/6, 4/6, 5/6, 6/6, 7/6, and 1.

Explanation:
In the above-given question,
given that,
label the missing numbers on the number lines.
the number line is divided into 6 parts.
the missing numbers are 2/6, 4/6, 5/6, 6/6, 7/6, and 1.
so the missing number is 2/6, 4/6, 5/6, 7/6, and 1.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-1

Question 7.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 3

Answer:
The missing numbers are 50, 100, 150, 200, 350, and 400.

Explanation:
In the above-given question,
given that,
label the missing numbers on the number line.
the distance between each point is 50.
so the starting point is 50.
50 + 50 = 100, 100 + 50 = 150, 150 + 50 = 200, 200 + 50 = 250, 250 + 50 = 300.
so the missing numbers are 50, 100, 150, 200, 350, and 400.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-2

Fractions

Question 8.
Rena divides a square into 8 equal parts. What unit fraction should she write as a label for each of the parts?
A. \(\frac{0}{8}\)
B. \(\frac{1}{8}\)
C. \(\frac{8}{8}\)
D. \(\frac{8}{1}\)

Answer:
Option B is the correct answer.

Explanation:
In the above-given question,
given that,
Rena divides a square into 8 equal parts.
1/8 is the correct fraction.
so option B is the correct answer.

Question 9.
Write two fractions that are equal to 1.

Answer:
The two fractions are 5/5 and 1/1.

Explanation:
In the above-given question,
given that,
the two fractions that are equal to 1 are,
5/5 = 1.
1/1 = 1.
so the two fractions are 5/5 and 1/1.

Pick a Project

PROJECT 14A
How do you show elapsed time on a clock?
Project: Write and Tell a Story About Time
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 4

Answer:
The time is 11:55.

Explanation:
In the above-given question,
given that,
the minute hand is on the 11.
the hour hand is on the 12.
so the time is 11:55.
5 x 11 = 55.
so the time is 11:55.

PROJECT 14B
What is the best way to plan for a full day?
Project: Create and Play a Matching Game
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 5

Answer:
The numbers 12 and 29 comes on Saturday and Tuesday.

Explanation:
In the above-given question,
given that,
the numbers on the calendar are:
1, 2, 3, 4, 5, 6, …..and 31.
the numbers are 12 and 29 comes on Saturday and Tuesday.

PROJECT 14C
How did people tell time before clocks?
Project: Design and Make a Sundial
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 6

PROJECT 14D
What is your favorite recipe?
Project: Perform a Song About the Masses of Objects
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 7

Lesson 14.1 Time to the Minute

Solve & Share
Xander and his mother are visiting a store. In the store, there are many clocks on the shelves. The clocks show different times. Tell the times shown on each of the clocks below.
I can … show and tell time to the minute using clocks.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 8

Answer:
The times are 1’o clock, 5’30, and 5:55.

Explanation:
In the above-given question,
given that,
in the 1st watch, the minute hand is on the 12 and the hour hand on the 1.
so the time is 1:00.
in the 2nd watch, the minute hand is on the 6 and the hour hand on the 5.
so the time is 5:30.
in the 3rd watch, the minute hand is on the 11 and the hour hand on the 6.
so the time is 5:55.

Look Back! Xander and his mother leave the store at 8:47. How can you use the clock to show this time?
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 9

Answer:
The minute hand is on the 9 and the hour hand is on the 8.

Explanation:
In the above-given question,
given that,
Xander and his mother leave the store at 8:47.
the minute hand is on the 9.
the hour hand is on the 8.
so the time is 8:47.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-3

Essential Question
How Do You Tell Time to on the Nearest Minute?

Visual Learning Bridge
The clock shows the time a train from Memphis is scheduled to arrive at Central Station. What time is the train scheduled to arrive? Write the time in digital form and in two other ways.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 10

Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 11

Convince Me! Model with Math A train arrives from Atlanta one hour after the Memphis train. Write the arrival time of the Atlanta train in digital form and two other ways. Use a clock face to help.

Guided Practice

Do You Understand?
Question 1.
In the Memphis train example, why is 42 minutes after 12 o’clock the same as 18 minutes before 1 o’clock? Explain.

Answer:
The 42 minutes after 12 o’clock is the same as 18 minutes before 1 o’clock.

Explanation:
In the above-given question,
given that,
the minute hand is on the 8 after two small points.
5 x 8 = 40.
40 + 2 = 42.
the hour hand is in between 12 and 1.
the time is 12:42.
so the 42 minutes after 12 o’clock is the same as 18 minutes before 1 o’clock.

Question 2.
An airplane landed at 3:55. Does the clock show the time the airplane landed? Explain.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 12

Answer:
Yes, the time is correct.

Explanation:
In the above-given question,
given that,
the minute hand is on the 11.
the hour hand is on the 3.
5 x 11 = 55.
so the time is 3:55.
the time is correct.

Do You Know How?
In 3 and 4, write the time shown on each clock in two ways.
Question 3.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 13

Answer:
The time is 3:12 and 12 minutes after 3 o’clock.

Explanation:
In the above-given question,
given that,
the minute hand is on the 2.
the hour hand is on the 3.
the time is 12 minutes after 3 o’clock.
5 x 2 = 10.
10 + 2 = 12.
so the time is 3:12.

Question 4.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 14

Answer:
The time is 5:43 and 43 minutes after 5 o’clock .

Explanation:
In the above-given question,
given that,
the minute hand is on the 5.
the hour hand is on the 8.
5 x 8 = 40.
40 + 3 = 43.
so the time is 5:43.
the time is 43 minutes after 5 o’clock.

Independent Practice

In 5-7, write the time shown on each clock in two ways.
Question 5.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 15

Answer:
The time is 11:20 and 20 minutes after 11 o’clock.

Explanation:
In the above-given question,
given that,
the minute hand is on the 4.
the hour hand is on the 11.
the time is 20 minutes after 11 o’clock.
5 x 4 = 20.
so the time is 11:20.

Question 6.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 16

Answer:
The time is 7:39 and 21 minutes before 8 o’clock.

Explanation:
In the above-given question,
given that,
the minute hand is on the 7.
the hour hand is on the 7.
the time is 21 minutes before 8 o’clock.
5 x 7 = 35.
35 + 2 = 37.
so the time is 7:39.

Question 7.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 17

Answer:
The time is 8:44.

Explanation:
In the above-given question,
given that,
the minute hand is on the 2.
the hour hand is on the 3.
5 x 2 = 10.
10 + 2 = 12.
so the time is 3:12.

Problem Solving

In 8 and 9, use the table.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 18

Question 8.
Roy says that the scarf and the hat together cost about the same amount as a blanket and a hat. Is this a reasonable estimate? Explain.

Answer:
No, it is not reasonable.

Explanation:
In the above-given question,
given that,
Roy says that the scarf and the hat together cost about the same amount as a blanket and a hat.
the scarf cost $18.
the hat cost $12.
blanket cost $19.
18 + 12 = 30.
19 + 12 = 31.
so both are not same.

Question 9.
What did Jorge buy at the sale if $19 + $19+ $19+ $18 stands for the total cost of his purchase?

Answer:
The total cost is $75.

Explanation:
In the above-given question,
given that,
Jorge buy at the sale $19 + $19 + $19 + $18.
19 + 19 = 38.
19 + 18 = 37.
37 + 38 = 75.
so the total cost is $75.

Question 10.
Be Precise Mia left her house at 25 minutes before 3 o’clock. Draw hands on the clock to show when she left.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 19

Answer:
The time is 2:35.

Explanation:
In the above-given question,
given that,
Mia left her house 25 minutes before 3 o’clock.
the minute hand is on the 7.
the hour hand is on the 2.
5 x 7 = 35.
so the time is 2:35.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-4

Question 11.
Higher Order Thinking Sandra’s party started at 7:00. Her friends Theo and Lily arrive at 10 minutes after 7 o’clock. Her friend Marcus arrives 35 minutes after Theo and Lily. What time did Marcus arrive? Write this time in two other ways.

Answer:
The time did Marcus arrive = 7:45.

Explanation:
In the above-given question,
given that,
Sandra’s party started at 7:00.
Theo and Lily arrive 10 minutes after 7 o’clock.
Her friend Marcus arrives 35 minutes after Theo and Lily.
7:10 + 35 = 7:45.
so the time Marcus arrive = 7:45.

Assessment Practice

Question 12.
Clay and his family sit down to eat dinner at the time shown on the clock. Which of the following are other ways to write that time? Select all that apply.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 20
☐ 3 : 25
☐ 5 : 16
☐ 16 minutes after 5 o’clock
☐ 44 minutes before 5 o’clock
☐ 16 minutes before 5 o’clock

Answer:
The time is 5:16 and 16 minutes after 5 o’clock.

Explanation:
In the above-given question,
given that,
the minute hand is on the 3 after 1 point.
the hour hand is on the 5.
5 x 3 = 15.
15 + 1 = 16.
so the time is 5:16 and 16 minutes after 5 o’clock.

Question 13.
Mary Ann called her grandmother. She ended the call at the time shown on the clock. Which of the following are NOT other ways to write this time? Select all that apply.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 21
☐ 14 minutes before 9 o’clock
☐ 3 : 46
☐ 46 minutes after 3 o’clock
☐ 9 : 19
☐ 14 minutes before 4 o’clock

Answer:
The wrong options are 3:46 and 14 minutes before 9 o’clock.

Explanation:
In the above-given question,
given that,
Mary Ann called her grandmother.
She ended the call at the time shown on the clock.
so the minute hand is on the 9.
the hour hand is in between 3 and 4.
5 x 9 = 45.
45 + 1 = 46.
so the time is 3:46.

Lesson 14.2 Units of Time: Measure Elapsed Time

Solve & Share
Denise went to see a movie. The movie started at 1:05 P.M. It ended at 2:35 P.M. How long did the movie last? Explain your reasoning.
I can… measure intervals of time in hours and minutes.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 22

Look Back! Without counting hours and minutes, how do you know the movie Denise went to see was less than 2 hours long?

Answer:
The number of minutes the movie lasts = 1 hour 30 minutes.

Explanation:
In the above-given question,
given that,
Denise went to see a movie. The movie started at 1:05 P.M.
It ended at 2:35 P.M.
2:35 – 1:05 = 1:30.
so the number of minutes the movie lasts = 1 hour 30 minutes.

Essential Question
How Can You Find Elapsed Time?

Visual Learning Bridge
Janey took part in a charity walk. The walk started at 7:10 A.M. It ended at 11:20 A.M. How long did the walk last?
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 23

Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 24

Convince Me! Make Sense and Persevere After the charity walk, Janey talked with friends from 11:25 A.M. to 11:40 A.M. Then lunch was served from 11:45 A.M. until 2:10 P.M. How long did lunch last?

Another Example!
You can also use a number line to measure elapsed time.
Janey’s charity walk lasted 4 hours, 10 minutes.
The number line shows the number of hours and minutes that elapsed during the walk.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 25

Guided Practice

Do You Understand?
Question 1.
If a start time is 7:15 A.M. and an end time is 7:45 A.M., why do you not have to count hours to find the elapsed time?

Answer:
The elapsed time is 7:30 A.M.

Explanation:
In the above-given question,
given that,
If a start time is 7:15 A.M. and an end time is 7:45 A.M.
7:45 – 7:15 = 7:30.
so the elapsed time is 7 hours 30 minutes.

Question 2.
A movie started at 2:30 P.M. and ran for 2 hours, 15 minutes. What time did the movie end?

Answer:
The time did the movie end = 4:45 P.M.

Explanation:
In the above-given question,
given that,
The movie started at 2:30 P.M and ran for 2 hours, 15 minutes.
30 + 15 = 45.
2 + 2 = 4.
so the time did movie end = 4:45 P.M.

Do You Know How?
Question 3.
Draw a number line to count the hours from 11:00 A.M. to 5:00 P.M. What is the elapsed time?

Answer:
The elapsed time = 6 hours.

Explanation:
In the above-given question,
given that,
hours from 11 to 5 is 6 hours.
the time is 11:A.M to 5:00 P.M.
11 + 1 = 12.
1 + 5 = 6.
so the elapsed time is 6 hours.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-5

Independent Practice

Leveled Practice In 4-7, use clocks or number lines to find the elapsed or end time.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 26
Question 4.
Hours from 6:30 P.M. to 9:30 P.M. ___________
Minutes from 9:30 P.M. to 9:50 P.M. ___________
The elapsed time is ___________ hours, ___________ minutes.

Answer:
3 hours.
20 minutes.
the elapsed time is 3 hours and 20 minutes.

Explanation:
In the above-given question,
given that,
the hours from 6:30 P.M to 9:30 P.M is 6 + 3 = 9.
the minutes from 9:30 P.M to 9:50 P.M is 30 + 20 = 50.
9 – 6 = 3.
50 – 20 = 30.
so the elapsed time is 3 hours and 20 minutes.

Question 5.
Start Time: 10:00 A.M.
End Time: 3:00 P.M.
Elapsed Time: ___________

Answer:
The elapsed time = 5 hours.

Explanation:
In the above-given question,
given that,
Start Time: 10:00 A.M.
End Time: 3:00 P.M.
10 A.M + 1 = 11 + 1 = 12.
12 + 1 = 1.
1 + 2 = 3.
3  + 2 = 5 hours.

Question 6.
Start Time: 9:15 A.M.
End Time: 10:45 A.M.
Elapsed Time: ___________

Answer:
The elapsed time = 1 hour 30 minutes.

Explanation:
In the above-given question,
given that,
Start Time: 9:15 A.M.
End Time: 10:45 A.M.
45 – 15 = 30.
10 – 1 = 9.
so the elapsed time is 1 hour 30 minutes.

Question 7.
Start Time: 11:30 A.M.
Elapsed Time: 5 hours, 25 minutes
End Time: ___________

Answer:
The End time = 4:55 P.M.

Explanation:
In the above-given question,
given that,
Start Time: 11:30 A.M.
Elapsed Time: 5 hours, 25 minutes
11:30 + 5 = 4:30.
30 + 25 = 55.
so the End Time = 4:55 P.M.

Problem Solving

In 8 and 9, use the list at the right.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 27
Question 8.
Reasoning Mr. Flores made a list of the times it takes for different items to bake. Which items will take less than \(\frac{1}{2}\) hour to bake?

Answer:
The items that take half an hour to bake are bread, granola bars, vegetables.

Explanation:
In the above-given question,
given that,
Mr. Flores made a list of the times it takes for different items to bake.
1/2 hour = 30 minutes.
bread will bake in 27 minutes.
granola bars bake in 21 minutes.
vegetables bake in 24 minutes.
The pasta dish bakes in 48 minutes.
so the items that take half an hour to bake are bread, granola bars, vegetables.

Question 9.
Which two items, when you add their baking time together, take less time to bake than the pasta dish?

Answer:
The two items that take less time to bake are granola bars and vegetables.

Explanation:
In the above-given question,
given that,
Mr. Flores made a list of the times it takes for different items to bake.
1/2 hour = 30 minutes.
bread will bake in 27 minutes.
granola bars bake in 21 minutes.
vegetables bake in 24 minutes.
The pasta dish bakes in 48 minutes.
21 + 24 = 45.
so the two items that take less time to bake are granola bars and vegetables.

Question 10.
Sally finds elapsed time using these clock faces. She counts the hours by 1s, but counts the minutes by 5s. Why does she count the minutes by 5s instead of by 1s?
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 28

Answer:
The elapsed time = 5 hours 15 minutes.

Explanation:
In the above-given question,
given that,
Sally finds elapsed time using these clock faces.
She counts the hours by 1s but counts the minutes by 5s.
minutes hand is between 5 seconds.
hours hand is between 5 minutes.
the start time = 3 :30.
the end time = 8:45.
45 – 30 = 15.
8 – 3 = 5.
so the elapsed time = 5 hours 15 minutes.

Question 11.
Higher Order Thinking A basketball tournament started at 12:15 P.M. and ended at 4:00 P.M. Did the tournament last more than 4 hours? Explain.

Answer:
No, the tournament did not last more than 4 hours.

Explanation:
In the above-given question,
given that,
A basketball tournament started at 12:15 P.M. and ended at 4:00 P.M.
12:15 + 1 hour = 1:15.
1 :15 + 2 hours = 3:15.
3 :15 + 1 hour = 4:15.
so the tournament last for 3 hours 15 minutes.

Question 12.
Algebra A farmer is selling 744 pieces of produce. He has 162 watermelons, 345 ears of sweet corn, and some avocados. Write and solve an equation to find how many avocados the farmer is selling. Let x stand for the unknown quantity of avocados.

Answer:
The number of avocados = 237.

Explanation:
In the above-given question,
given that,
A farmer is selling 744 pieces of produce.
He has 162 watermelons, 345 ears of sweet corn, and some avocados.
345 + 162 = 507.
744 – 507 = 237.
so the number of avocados = 237.

Assessment Practice

Question 13.
Geo is taking a train from Carlton to Elgin. The train leaves Carlton at 9:25 A.M. and reaches Elgin 9:25 A.M. at 10:55 A.M. How long does the ride last? Use the leave number line to help.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 29
A. 30 minutes
B. 1 hour
C. 1 hour, 30 minutes
D. 2 hours

Answer:
Option C is the correct answer.
The long does the ride last = 1 hour 30 minutes.

Explanation:
In the above-given question,
given that,
Geo is taking a train from Carlton to Elgin.
The train leaves Carlton at 9:25 A.M. and reaches Elgin at 9:25 A.M. at 10:55 A.M.
9 + 1 = 10.
25 + 30 = 55.
so the time is 10:55.
option c is the correct answer.

Lesson 14.3 Units of Time: Solve Word Problems

Solve & Share
Madison wants to exercise 30 minutes every day. Before school, she only has enough time to exercise for 10 minutes or less. One day, she exercised for 8 minutes before school and 22 minutes after school. This is one way she can exercise for 30 minutes. Find two other ways she can exercise before school and after school to reach her goal of exercising for 30 minutes each day.
I can … use representations to solve word problems about time.
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 30

Look Back! Do you think there are more than two ways to solve the problem above? Explain.

Answer:
She exercised for 4 minutes before school and 26 minutes after school.
the other way is 5 minutes before school and 25 minutes after school.

Explanation:
In the above-given question,
given that,
Madison wants to exercise 30 minutes every day.
4 + 26 = 30.
5 + 25 = 30.
so she exercised for 4 minutes before school and 26 minutes after school.
the other way is 5 minutes before school and 25 minutes after school.

Essential Question
How Can You Add or Subtract on Time Intervals?

Visual Learning Bridge
Joaquin made a list of the time he should spend on different activities. Joaquin has practiced playing the piano 35 minutes so far. How much longer does he need to practice?
Envision Math Common Core 3rd Grade Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 31

One Way
You can use a bar diagram to represent the problem and show time intervals.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 32

Another Way
You can use a number line to represent the problem and show time intervals.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 33

Convince Me! Model with Math How much longer will it take Joaquin to finish all of his after-school activities? Show one way to represent and solve.

Answer:
The longer will it take Joaquin to finish all of his after-school activities = 155 minutes.

Explanation:
In the above-given question,
given that,
play with Ron for 50 minutes.
practice piano for 45 minutes.
homework 60 minutes.
50 + 45 + 60 = 155.
so the longer will it take Joaquin to finish all of his after-sccool activities = 155 minutes.

Guided Practice

Do You Understand?
In 1 and 2, complete the bar diagram or number line to solve.
Question 1.
Rhody plans to ride his bicycle for 55 minutes. So far, he has ridden for 29 minutes. How many more minutes does he have to ride?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 34

Answer:
The more minutes he wants to ride = 26 minutes.

Explanation:
In the above-given question,
given that,
Rhody plans to ride his bicycle for 55 minutes.
So far, he has ridden for 29 minutes.
55 – 29 = 26.
so the more minutes he wants to ride = 26 minutes.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-6

Do You Know How?
Question 2.
Ms. Darren spends the reading period working with two different reading groups. She meets with the first group for 23 minutes and meets with the second group for 17 minutes. How long is the reading period?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 35

Answer:
The long is the reading period = 40 minutes.

Explanation:
In the above-given question,
given that,
Ms. Darren spends the reading period working with two different reading groups.
She meets with the first group for 23 minutes and meets with the second group for 17 minutes.
23 + 17 = 40.
so the long is the reading period = 40 minutes.

Independent Practice

Leveled Practice In 3-6, complete or draw a bar diagram or number line to solve.
Question 3.
Claire and Owen played video games. The first game lasted 24 minutes. After the first game, Claire and Owen had lunch for 30 minutes. The second game lasted 36 minutes. How many minutes did they play the games?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 36

Answer:
The number of minutes did they play the games = 60.

Explanation:
In the above-given question,
given that,
Claire and Owen played video games.
The first game lasted 24 minutes.
After the first game, Claire and Owen had lunch for 30 minutes.
The second game lasted 36 minutes.
24 + 36 = 60.
so the number of minutes did they play the games = 60.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-7

Question 4.
Yan jogged for 60 minutes on Friday. Dino jogged 12 fewer minutes than Yan. Both friends swim for 40 minutes each week. How many minutes did Dino jog on Friday?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 37

Answer:
The number of minutes did Dino jog on Friday = 48 minutes.

Explanation:
In the above-given question,
given that,
Yan jogged for 60 minutes on Friday.
Dino jogged 12 fewer minutes than Yan.
Both friends swim for 40 minutes each week.
60 -12 = 48.
so the number of minutes did Dino jog on Friday = 48 minutes.

Question 5.
Mr. Hart’s class is putting on a play. The play is divided into two acts. Each act lasts 27 minutes. How many minutes long is the play?

Answer:
The number of minutes that long the play = 54 minutes.

Explanation:
In the above-given question,
given that,
Mr. Hart’s class is putting on a play.
The play is divided into two acts.
Each act lasts 27 minutes.
27 + 27 = 54.
so the number of minutes that long the play = 54 minutes.

Question 6.
A chef wants to bake a dish for 30 minutes. So far, the dish has been baking for 12 minutes. How many more minutes does the dish need to bake?

Answer:
The more minutes the dish needs to bake = 18 minutes.

Explanation:
In the above-given question,
given that,
A chef wants to bake a dish for 30 minutes.
So far, the dish has been baking for 12 minutes.
30 – 12 = 18.
so the more minutes the dish needs to bake = 18 minutes.

Problem Solving

Question 7.
Reasoning Ms. Merrill spends 55 minutes washing all the windows in her two-story house. How much time could she have spent on each floor? Complete the chart to show three different ways.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 38

Answer:
25 + 30 = 55.
30 + 25 = 55.
20 + 35 = 55.

Explanation:
In the above-given question,
given that,
Ms. Merrill spends 55 minutes washing all the windows in her two-story house.
On the 1st floor, he spends 25 minutes, and 2nd floor he spends 30 minutes.
30 + 25 = 55.
20 + 35 = 55.
so that are the three ways to wash all the windows.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-8

Question 8.
Number Sense Harry measures a sticker that is \(\frac{4}{2}\) inches. Rhea’s sticker is \(\frac{6}{2}\) inches. Whose sticker is longer? Explain.

Answer:
Rhea’s sticker was long.

Explanation:
In the above-given question,
given that,
Harry measures a sticker that is \(\frac{4}{2}\) inches.
Rhea’s sticker is \(\frac{6}{2}\) inches.
4/2 = 2.
6/2 = 3.
so Rhea’s sticker was long.

Question 9.
Higher Order Thinking Mr. Collins is learning to drive a truck. He drives 22 minutes on Monday and 14 minutes on Tuesday. Finally, he drives 6 more minutes on Wednesday than he did on Tuesday. How many total minutes does he practice driving a truck?

Answer:
The total number of minutes does he practice driving a truck = 56 minutes.

Explanation:
In the above-given question,
given that,
Mr. Collins is learning to drive a truck.
He drives 22 minutes on Monday and 14 minutes on Tuesday.
he drives 6 more minutes on Wednesday than he did on Tuesday.
22 + 14 + 20 = 56.
so the total number of minutes does he practice driving a truck = 56 minutes.

Assessment Practice

Question 10.
Sonya hikes up a mountain. It takes her 25 minutes to hike to a cliff that is partway up the mountain. After that, she hikes for 17 more minutes to the summit. Use the number line and complete the table to show how many total minutes Sonya spends hiking.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 39

Answer:
The total number of minutes Sonya spends hiking = 42.

Explanation:
In the above-given question,
given that,
Sonya hikes up a mountain.
It takes her 25 minutes to hike to a cliff that is partway up the mountain.
After that, she hikes for 17 more minutes to the summit.
25 + 17 = 42.
so the total number of minutes Sonya spends hiking = 42.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-9

Question 11.
Meg walks a dog named Shep for 12 minutes. Then she walks Sparky. Finally, she walks Brownie for 18 minutes. Meg spends 52 minutes walking all three dogs. Use the number line and complete the table to show how many minutes Meg spends walking each dog.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 40

Answer:
The number of minutes Meg spends walking each dog = 22 minutes.

Explanation:
In the above-given question,
given that,
Meg walks a dog named Shep for 12 minutes.
Then she walks Sparky.
Finally, she walks Brownie for 18 minutes.
Meg spends 52 minutes walking all three dogs.
18 + 12 = 30.
52 – 30 = 22.
so the number of minutes Meg spends walking each dog = 22 minutes.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-10

Lesson 14.4 Estimate Liquid Volume

Solve & Share
The water bottle below has a capacity of 1 liter. Estimate the capacity of a small bowl, a large bowl, and a pitcher to the nearest half liter. Use an actual 1-liter water bottle, small and large bowls, and a pitcher to solve this problem.
I can … use a standard unit to estimate liquid volume.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 41

Look Back! After you estimate the capacity of the containers, how can you use a 1-liter water bottle to check that your estimate for each container is reasonable? Check your estimates.

Essential Question
Do You Estimate Capacity?

Visual Learning Bridge
What is the capacity of the pail?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 42

Compare the capacity of the water bottle to the capacity of the pail.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 43
The pail appears to be large enough to hold several liters.
Count how many times you can fill a liter container and empty it into the pail.
This pail holds about 8 liters.

Convince Me! Be Precise Suppose you want to estimate the capacity of the pail to the nearest half liter. How can you check that your estimate is reasonable?

Guided Practice

Do You Understand?
Question 1.
Susie estimates the capacity of a water glass as 3 liters. Hakim estimates the capacity as á liter. Is Susie’s or Hakim’s estimate more reasonable? Explain.

Answer:
Hakim estimates the capacity as a liter was more reasonable.

Explanation:
In the above-given question,
given that,
Susie estimates the capacity of a water glass as 3 liters.
Hakim estimates the capacity as a liter.
so Hakim’s estimation was correct.

Question 2.
Find a container that you predict will hold more than a liter and another that you predict will hold less than a liter. Use a liter container to check your predictions by finding the actual capacity of each container.

Answer:
The containers are a small bowl and a large bowl.

Explanation:
In the above-given question,
given that,
container that you predict will hold more than a liter and another that you predict will hold less than a liter.
container hold exactly 1 liter.
a small bowl holds less than a liter.
A large bowl holds more than a liter.
so the containers are a small bowl and a large bowl.

Do You Know How?
In 3-6, circle the better estimate for each.
Question 3.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 44
\(\frac{1}{4}\) L or 2 L

Answer:
The better estimate is 1/4 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/4 liter and 2 liters.
the glass holds 1/4 liter.
so the better estimate is 1/4 liters.

Question 4.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 45
100 L or 1 L

Answer:
The better estimate is 100 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1 liter and 100 liters.
the bucket holds 100 liters.
so the better estimate is 100 liters.

Question 5.
Bottle of juice
3 L or 1L

Answer:
The better estimate is 1 liter.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1 liter and 3 liters.
the bottle holds 1 liter.
so the better estimate is 1 liter.

Question 6.
Cereal bowl
\(\frac{1}{4}\) L or 3 L

Answer:
The better estimate is 1/4 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/4 liter and 3 liters.
the cereal bowl holds 1/4 liter.
so the better estimate is 1/4 liters.

Independent Practice

In 7-14, circle the better estimate for each.
Question 7.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 46
\(\frac{1}{4}\) L or 40 L

Answer:
The better estimate is 40 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/4 liter and 40 liters.
the glass aquarium holds 40 liters.
so the better estimate is 40 liters.

Question 8.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 47
\(\frac{1}{8}\) L or 1 L

Answer:
The better estimate is 1/8 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/8 liter and 1 liter.
the spoon holds 1/8 liter.
so the better estimate is 1/8 liters.

Question 9.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 48
\(\frac{1}{2}\) L or 14 L

Answer:
The better estimate is 1/2 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/2 liter and 14 liters.
the glass holds 1/2 liter.
so the better estimate is 1/2 liters.

Question 10
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 49
\(\frac{1}{4}\) L or 250 L

Answer:
The better estimate is 1/4 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/4 liter and 250 liters.
the juice holds 1/4 liter.
so the better estimate is 1/4 liters.

Question 11.
Teacup
\(\frac{1}{4}\) L or 15 L

Answer:
The better estimate is 1/4 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/4 liter and 15 liters.
the teacup holds 1/4 liter.
so the better estimate is 1/4 liters.

Question 12.
Bathtub
15 L or 115 L

Answer:
The better estimate is 115 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
15 liter and 115 liters.
the bathtub holds 115 liters.
so the better estimate is 115 liters.

Question 13.
Soup bowl
\(\frac{1}{2}\) L or 3 L

Answer:
The better estimate is 1/2 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/2 liter and 3 liters.
the soup bowl holds 1/2 liter.
so the better estimate is 1/2 liters.

Question 14.
Teapot
1 L or 10 L

Answer:
The better estimate is 1 liter.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1 liter and 10 liters.
the teapot holds 1/4 liter.
so the better estimate is 1 liters.

Question 15.
Write an estimate for the capacity of a dog bowl. _________

Answer:
The better estimate is 1/4 liters.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1/4 liter and 2 liters.
the dogbowl holds 1/4 liter.
so the better estimate is 1/4 liters.

Question 16.
Write an estimate for the capacity of a flower vase. __________

Answer:
The better estimate is 1 liter.

Explanation:
In the above-given question,
given that,
circle the better estimates for each.
1 liter and 2 liters.
the flower vase holds 1 liter.
so the better estimate is 1 liter.

Problem Solving

Question 17.
Generalize Which cooler has the greater capacity? Explain your thinking
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 50

Answer:
Cooler B has the greatest capacity.

Explanation:
In the above-given question,
given that,
the two coolers with different capacities.
cooler A has a small capacity.
cooler B has a larger capacity.

Question 18.
List these containers in order from least capacity to greatest capacity.
Washing machine
Large pot
Soup spoon
Travel mug

Answer:
The containers from least to greatest = soup spoon, travel mug, large pot, and washing machine.

Explanation:
In the above-given question,
given that,
there are 4 containers.
they are a washing machine, large pot, soup spoon, travel mug.
soup spoon, travel mug, large pot, and washing machine.
so the containers from least to greatest = soup spoon, travel mug, large pot, and washing machine.

Question 19.
A basketball team scores 27 points in its first game and 41 points in its second game. After three games, it scores 100 points in all. How many points does the team score in its third game?

Answer:
The number of points does the team score in its third game = 32 points.

Explanation:
In the above-given question,
given that,
A basketball team scores 27 points in its first game and 41 points in its second game.
After three games, it scores 100 points in all.
27 + 41 = 68.
100 – 68 = 32.
so the number of points does the team score in its third game = 32 points.

Question 20.
Higher Order Thinking Becky wants to measure the capacity of her brother’s baby pool. She has a 1-liter container and a 10-liter container. Which should she use? Explain your reasoning.

Answer:
The capacity of her brother’s baby pool is a 10-liter container.

Explanation:
In the above-given question,
given that,
Becky wants to measure the capacity of her brother’s baby pool.
She has a 1-liter container and a 10-liter container.
so a 10-liter container is the capacity of her brother’s pool.

Question 21.
A sandgrouse can soak up water in its fluffy feathers. It can carry the water a long way to its chicks. Does a sandgrouse carry \(\frac{1}{10}\) liter of water or 2 liters of water?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 51

Answer:
Sandgrouse carries 1/10 liter of water.

Explanation:
In the above-given question,
given that,
A sandgrouse can soak up water in its fluffy feathers.
It can carry the water a long way to its chicks.
sandgrouse can carry 1/10 liter of water.

Assessment Practice

Question 22.
Gary is painting a small storage shed. He estimates that he can do the job with one can of paint. Which of the following is the best estimate of the total liquid volume of a can of paint?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 52
A. \(\frac{1}{4}\) liter
B. 4 liter
C. 40 liters
D. 400 liters

Answer:
The best estimate of the total liquid volume of a can of paint = 4 liters.

Explanation:
In the above-given question,
given that,
Gary is painting a small storage shed.
He estimates that he can do the job with one can of paint.
the best estimate of the total liquid volume of a can of paint = 4 liters.

Lesson 14.5 Measure Liquid Volume

Solve & Share
Select six different containers. Estimate the capacity of each container. Record your estimates in the table, and arrange the containers in order from least to greatest liquid volume. Then use a marked liter beaker to measure the capacity of each container. Record your measurements in the table. Compare your estimates to your measures. Using your measures, rearrange the containers in order from least to greatest liquid volume.
I can … use a standard unit to measure liquid volume.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 53

Answer:
The containers in order from least to greatest are teacup, glass, mug, bottle, tea jar, kettle, and bucket.

Explanation:
In the above-given question,
given that,
they have given 7 containers.
they are teacup, glass, mug, bottle, tea jar, kettle, and bucket.
teacup = 1/4 liter.
glass = 1/3 liter.
mug = 1/8 liter.
bottle = 1 liter.
tea jar = 1/2 liter.
kettle = 3/4 liter.
bucket = 10 liters.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-11

Look Back! How did you measure the capacity of containers that are less than 1 liter? Is there another way to measure?

Essential Question
How Do You Measure Capacity?

Visual Learning Bridge
Eric is cleaning his fishbowl and wants to know how much water he needs to refill the fishbowl. How can he find the capacity of the fishbowl?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 54

Pour from the filled fishbowl into the 1-liter container. Empty the container and repeat until the fishbowl is empty.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 55
It is helpful to keep a record of measurements made.
The 1-liter container was filled 5 times.
So, the capacity of the fishbowl is 5 liters.

Convince Me! Critique Reasoning Jason says, “I think it is better to find the measurement of the fishbowl by filling the fishbowl with liters of water instead of emptying the fishbowl into liter beakers.” Is Jason correct?

Another Example!
When only part of the 1-liter container is filled, use fractions of liters.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 56
The capacity of the pot is 2\(\frac{1}{2}\) liters.

Guided Practice

Do You Understand?
Question 1.
What is the capacity of 2 pots like the one shown in the Another Example! above?

Answer:
The capacity of the 2 pots like the one shown is 5 liters.

Explanation:
In the above-given question,
given that,
the capacity of one pot is 2 and 1/2 liters.
2 + 2 + 1 = 5.
so the capacity of the 2 pots like the one shown is 5 liters.

Question 2.
Find a container that you think holds less than a liter. Estimate, and then check your estimate for the capacity of the container.

Answer:
The container that holds less than a liter = teacup.

Explanation:
In the above-given question,
given that,
the container is a teacup.
teacup holds 1/8 of a liter.
so the container that holds less than a liter = teacup.

Do You Know How?
In 3 and 4, find the total capacity represented in each picture.
Question 3.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 57

Answer:
The total capacity represented in each picture = 2 liters.

Explanation:
In the above-given question,
given that,
there are 4 containers.
the containers each weight is 1/2 liter.
1/2 + 1/2 + 1/2 + 1/2 = 2 liters.
so the total capacity represented in each picture = 2 liters.

Question 4.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 58

Answer:
The total capacity represented is 1 and 1/2 liter.

Explanation:
In the above-given question,
given that,
there are 2 containers.
they are 1 is totally filled and the other one is half-filled.
1 + 1/2 = 1.5 liters.
so the total capacity represented is 1 and 1/2 liter.

Independent Practice

In 5-7, find the total capacity represented in each picture.
Question 5.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 59

Answer:
The total capacity represented is 18 liters.

Explanation:
In the above-given question,
given that,
there are 2 containers.
they are 1 is totally filled and the other one is 8 liters filled.
10 + 8 = 18 liters.
so the total capacity represented is 18 liters.

Question 6.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 60

Answer:
The total capacity represented is 20 liter.

Explanation:
In the above-given question,
given that,
there are 2 containers.
they are totally filled.
10 + 10 + 10 + 10 = 20 liters.
so the total capacity represented is 20 liters.

Question 7.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 61

Answer:
The total capacity represented is 24 liters.

Explanation:
In the above-given question,
given that,
there are 3 containers.
they are 2 is totally filled and the other one is half-filled.
10 + 10 + 4 = 24 liters.
so the total capacity represented is 24 liters.

Problem Solving

Question 8.
Lawrence manufactures jam. He makes 200 liters of grape jam and 350 liters of strawberry jam. He then sells 135 liters of the grape jam. How much jam does Lawrence have left?

Answer:
The quantity of jam does Lawrence has left = 415 liters.

Explanation:
In the above-given question,
given that,
Lawrence manufactures jam.
He makes 200 liters of grape jam and 350 liters of strawberry jam.
He then sells 135 liters of grape jam.
200 – 135 = 65.
350 + 65 = 415.
so the quantity of jam does Lawrence have left = 415 liters.

Question 9.
Use Appropriate Tools Find a container that you think holds more than a liter. Estimate, and then check your estimate for the capacity of the container.

Answer:
The capacity of the container is more than 2 liters and it is a kettle.

Explanation:
In the above-given question,
given that,
the container is a kettle.
the kettle holds 2 liters.

Question 10.
How many 2-liter cartons can be filled with 18 liters of juice?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 62

Answer:
The number of 2-liter cartons can be filled with 18 liters of juice = 9 liters.

Explanation:
In the above-given question,
given that,
2 x 9 = 18.
so the number of 2-liter cartons can be filled = 9.

Question 11.
Which of the following measurements is NOT reasonable for the capacity of a full bathroom sink: 15 liters, \(\frac{1}{2}\) liter, 10 liters, 9 liters, or 12 liters? Explain.

Answer:
The 1/2 liter is not reasonable for the capacity of a full bathroom sink.

Explanation:
In the above-given question,
given that,
the capacity of a full bathroom sink is 15 liters, 1/2 liter, 10 liters, 9 liters, 12 liters.
so I am thinking that the capacity of a full bathroom sink is 12 liters.
so half-liter is not reasonable.

Question 12.
Higher Order Thinking Emma prepares 72 liters of punch for an event. She pours all of the punch equally into the pitchers on 9 different tables. If there are 4 pitchers on each table, how many liters of punch are in each pitcher?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 63

Answer:
The number of liters of punch is in each pitcher = 32.

Explanation:
In the above-given question,
given that,
Emma prepares 72 liters of punch for an event.
She pours all of the punch equally into the pitchers on 9 different tables.
9 x 8 = 72.
8 x 4 = 32.
so the number of liters of punch are in each pitcher = 32.

Assessment Practice

Question 13.
Use the picture of the water jugs to find the amount of water the team drank during soccer practice.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 64
A. 6 liters
B. 7 liters
C. 8 liters
D. 23 liters

Answer:
Option B is the correct answer.

Explanation:
In the above-given question,
given that,
the amount of water before soccer practice is 15 liters.
15 – 8 = 7liters.
so the amount of water before soccer is 15 liters.
option B is the correct answer.

Lesson 14.6 Estimate Mass

Solve & Share
Look at the measurements for the mass of the book and the mass of the olive. List 4 items that should be measured using kilograms and 4 items that should be measured using grams. Explain your reasoning.
I can … use standard units to estimate the masses of solid objects.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 65

Look Back! How could you use tools to check that the items in part of your list are reasonable choices for measuring mass with grams? Explain.

Answer:
The weight of the cup = 250 grams.

Explanation:
In the above-given question,
given that,
1kilo gram = 1000 grams.
so the weight of the cup = 250 grams.
the weight of the bottle is 1000 grams.

Essential Question
How Can You Use Reasoning to Estimate Mass?

Visual Learning Bridge
Stephen and Marissa estimated the mass of an apple. Stephen’s estimate is 250 grams. Marissa’s estimate is 2 kilograms. Which is the better estimate of the mass of an apple?
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 66

Step 1
Use known masses and the table to compare grams to kilograms. Select the unit that will give a better estimate.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 67
The apple is smaller than the cantaloupe. A kilogram is too large of a unit to estimate the mass of the apple.
The grape is smaller than the apple. Grams are smaller units that can be used to estimate the mass of the apple.

Step 2
Use a pan balance to find the mass of the apple. Then evaluate Stephen’s estimate.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 68
The apple has a mass of 262 grams.
250 grams is close to 262 grams. Stephen’s estimate is reasonable.
250 grams is a better estimate than 2 kilograms.

Convince Me! Critique Reasoning Zoe says two apples would have a mass greater than a kilogram. Do you agree? Explain.

Answer:
No, i do not agree with it.

Explanation:
In the above-given question,
given that,
Zoe says two apples would have a mass greater than a kilogram.
one apple = 250 grams.
250 x 2 = 500.
250 + 250 = 500 grams.
so zeo says wrong.

Guided Practice

Do You Understand?
Question 1.
In Step 2 on the previous page, why do you need to find the actual mass of the apple?

Answer:
The actual mass of the object is 262 grams.

Explanation:
In the above-given question,
given that,
the actual mass of the object is 262 grams.
262 grams is approximately equal to 250 grams.
262 + 262 = 524.
so the actual mass of the object is 262 grams.

Question 2.
Find an object that you think has a mass more than a kilogram and another that has a mass less than a kilogram. Then determine what tools to use to check your estimate.

Answer:
The tools are apple and jaggery.

Explanation:
In the above-given question,
given that,
the object that you think has a mass more than a kilogram and has a mass less than a kilogram.
the weight of the apple is 250 grams.
the weight of the jaggery is 1200 grams.
so the tools are apple and jaggery.

Do You Know How?
In 3-6, circle the better estimate for each
Question 3.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 69
5 g or 5 kg

Answer:
The better estimation of the coin is 5 g.

Explanation:
In the above-given question,
given that,
the measurements are 5 g and 5 kg.
the weight of the coin is 5 g.
so the better estimation of the coin is 5 g.

Question 4.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 70
40 g or 4 kg

Answer:
The better estimation of the dog is  4 kg.

Explanation:
In the above-given question,
given that,
the measurements are 40 g and 4 kg.
the weight of the dog is 4 kg.
so the better estimation of the dog is 4 kg.

Question 5.
Sunglasses
16 g or 1 kg

Answer:
The better estimation of the sunglasses is 16 g.

Explanation:
In the above-given question,
given that,
the measurements are 16 g and 1 kg.
the weight of the sunglasses is 16 g.
so the better estimation of the sunglasses is 16 g.

Question 6.
Envelope
1 g or 70 g

Answer:
The better estimation of the Envelope is 1 g.

Explanation:
In the above-given question,
given that,
the measurements are 1 g and 70 g.
the weight of the Envelope is 1 g.
so the better estimation of the Envelope is 1 g.

Independent Practice

Leveled Practice In 7-18, circle the better estimate for each.
Question 7.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 71
100 g or 10 kg

Answer:
The better estimation of the blanket is 10 kg.

Explanation:
In the above-given question,
given that,
the measurements are 100 g and 10 kg.
the weight of the blanket is 10 kg.
so the better estimation of the coin is 10 kg.

Question 8.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 72
15 g or 15 kg

Answer:
The better estimation of the monitor is 15 kg.

Explanation:
In the above-given question,
given that,
the measurements are 15 g and 15 kg.
the weight of the monitor is 15 kg.
so the better estimation of the monitor is 15 kg.

Question 9.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 73
4g or 400 g

Answer:
The better estimation of the spectacles box is 400 g.

Explanation:
In the above-given question,
given that,
the measurements are 4 g and 400 g.
the weight of the spectacles box is 400 g.
so the better estimation of the spectacles box is 400 g.

Question 10.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 74
200 g or 2 kg

Answer:
The better estimation of the net bag is 2 kg.

Explanation:
In the above-given question,
given that,
the measurements are 200 g and 2 kg.
the weight of the bag is 2 kg.
so the better estimation of the net bag is 2 kg.

Question 11.
Bicycles
2 kg or 12 kg

Answer:
The better estimation of the bicycles is 12 kg.

Explanation:
In the above-given question,
given that,
the measurements are 2 kg and 12 kg.
the weight of the bicycles is 12 kg.
so the better estimation of the bicycles is 12 kg.

Question 12.
Feather
1 g or 1 kg

Answer:
The better estimation of the feather is 1 g.

Explanation:
In the above-given question,
given that,
the measurements are 1 g and 1 kg.
the weight of the feather is 1 g.
so the better estimation of the feather is 1 g.

Question 13.
Horse
5 kg or 550 kg

Answer:
The better estimation of the horse is 550 kg.

Explanation:
In the above-given question,
given that,
the measurements are 5 kg and 550 kg.
the weight of the horse is 550 kg.
so the better estimation of the horse is 550 kg.

Question 14.
Penny
3 g or 300 g

Answer:
The better estimation of the penny is 3 g.

Explanation:
In the above-given question,
given that,
the measurements are 3 g and 300 g.
the weight of the penny is 3 g.
so the better estimation of the penny is 3 g.

Question 15.
Dining table
350 g or 35 kg

Answer:
The better estimation of the dining table is 35 kg.

Explanation:
In the above-given question,
given that,
the measurements are 350 g and 35 kg.
the weight of the dining table is 35 kg.
so the better estimation of the dining is 35 kg.

Question 16.
Microwave oven
1,500 g or 15 kg

Answer:
The better estimation of the microwave oven is 15 kg.

Explanation:
In the above-given question,
given that,
the measurements are 1500 g and 15 kg.
the weight of the microwave oven is 15 kg.
so the better estimation of the microwave oven is 15 kg.

Question 17.
Kitten
2 kg or 20 kg

Answer:
The better estimation of the kitten is 2 kg.

Explanation:
In the above-given question,
given that,
the measurements are 2 kg and 20 kg.
the weight of the kitten is 2 kg.
so the better estimation of the kitten is 2 kg.

Question 18.
Crayon
20 g or 200 g

Answer:
The better estimation of the crayon is 20 g.

Explanation:
In the above-given question,
given that,
the measurements are 20 g and 200 g.
the weight of the crayon is 20 g.
so the better estimation of the crayon is 20 g.

Problem Solving

Question 19.
Use Appropriate Tools Choose the best tool to measure each item described. Write the correct letter of the tool on the blank.
Envision Math Common Core 3rd Grade Answers Topic 14 Solve Time, Capacity, and Mass Problems 75
The capacity of a mug _______
The temperature of water _______
The length of a box _______
The mass of a pear _______
The time you finish lunch _______

Answer:
The capacity of a mug is 1 liter.
the temperature of the water is 1000 degrees celsius.
the length of a box is 1 cm.
the mass of a pear is 100 g.
the time you finish lunch is 12:15.

Explanation:
In the above-given question,
given that,
the items are mug, pear, temperature, and box.
The capacity of a mug is 1 liter.
the temperature of the water is 1000 degrees celsius.
the length of a box is 1 cm.
the mass of a pear is 100 g.
the time you finish lunch is 12:15.

Question 20.
Number Sense Ethan will subtract a 3-digit number from 920. He says the difference could be a 1-digit number, a 2-digit number, or a 3-digit number. Write three subtraction equations that show each difference. Be sure you start with 920 and subtract a 3-digit number each time.
You can use place value and mental math to solve this problem.

Answer:
The three subtraction equations are 917, 10, and 3.

Explanation:
In the above-given question,
given that,
Ethan will subtract a 3-digit number from 920.
He says the difference could be a 1-digit number, a 2-digit number, or a 3-digit number.
920 – 3 = 917.
920 – 10 = 920.
920 – 917 = 3.
so the three subtraction equations are 917, 10, and 3.

Question 21.
en Vision® STEM Clay learned that solids have a definite shape. Now he wants to measure some solids, so he measures the mass of a bead. The bead has a mass of 10 grams. He estimates that 10 beads will have a mass of 1 kilogram. Is he correct? Explain.

Answer:
No, he was not correct.

Explanation:
In the above-given question,
given that,
Clay learned that solids have a definite shape.
the bead has a mass of 10 grams.
10 beads will have a mass of 1 kilogram.
1000 grams = 1 kilogram.
so he was not correct.

Question 22.
Higher Order Thinking Correct the mistakes in the shopping list below.
Shopping List
2 L of apples
3 kg of milk
5 cm of flour

Answer:
The shopping list contains 2 liters of milk, 3 kg of apples, and 5 cm of flour.

Explanation:
In the above-given question,
given that,
2 l of apples, 3 kg of milk, 5 cm of flour.
the mistakes in the shopping list are apples, milk, and flour.
so the shopping list contains 2 liters of milk, 3 kg of apples, and 5 cm of flour.

Assessment Practice

Question 23.
Todd is thinking of an animal with a mass greater than 1 kilogram, but less than 20 kilograms. Which animal could Todd be thinking of?
A. Horse
B. Cat
C. Elephant
D. Rhinoceros

Answer:
Option A is correct.

Explanation:
In the above-given question,
given that,
the animal with a mass greater than 1 kilogram, but less than 20 kilograms.
the animals are horse, cat, elephant, and rhinoceros.
the weight of the horse is more than 1 kilogram and less than 20 kilograms.
so option A is correct.

Question 24.
Anna has a bar of soap. She estimates its mass before measuring to find the actual mass. Which units should Anna use for her measure?
A. Grams
B. Kilograms
C. Liters
D. Inches

Answer:
The actual mass of the soap is grams.

Explanation:
In the above-given question,
given that,
the measurements are grams, kilograms, liters, and inches.
so the mass of the soap will be in grams.

Lesson 14.7 Measure Mass

Solve & Share
Work with a group to choose 6 objects whose masses can be measured using a pan balance. Estimate the mass of each object. Then use metric weights to find the actual mass for each in grams (g) or kilograms (kg). Use the table and explain your reasoning.
I can … use grams and kilograms to measure the mass of objects.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 76

Look Back! How did you decide which metric unit(s) to use when making your estimates? Explain.

Essential Question
How Do You Measure Mass?

Visual Learning Bridge
A pan balance with gram and kilogram weights can be used to find the mass of an object. What is the mass of a box of chalk?
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 77

Place the box on one pan. Place enough gram and kilogram weights on the other pan so the pans balance.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 78

The box balances with one 1-kilogram weight, two 100-gram weights, and four 10-gram weights.
So, the mass of the box is 1 kilogram 240 grams or 1,240 grams.
Write the larger unit before the smaller unit when recording measurements.

Convince Me! Be Precise What metric units would you use to estimate the mass of half of a box of chalk? Explain.

Answer:
The mass of the half of the box of chalk = 620 grams.

Explanation:
In the above-given question,
given that,
the mass of the box is 1 kilogram 240 grams or 1,240 grams.
1kg = 1000 g.
1240 / 2 = 620.
so the mass of the half of box of chalk = 620 grams.

Guided Practice

Do You Understand?
Question 1.
Find an object that you think has a mass greater than a kilogram. Find another object that has a mass less than a kilogram. Use a pan balance with gram and kilogram weights to measure the mass of each object.

Answer:
The weight of Malachi is 1 g and the mass of the cat is 1200 g.

Explanation:
In the above-given question,
given that,
the object that has a mass greater than a kilogram and has a mass less than a kilogram.
the mass of Malachi is 1 g.
the mass of the cat is 1200g.
the mass of Malachi is less than a kilogram.
the mass of the cat is greater than a kilogram.
so the weight of Malachi is 1 g and the mass of the cat is 1200 g.

Question 2.
If you use a pan balance to measure the mass of a pen, would you use any kilogram weights? Explain.

Answer:
We will use one gram weight.

Explanation:
In the above-given question,
given that,
the mass of a pen is 2 grams.
so we will use the gram weights.

Do You Know How?
In 3 and 4, write the total mass represented in each picture.
Question 3.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 79

Answer:
The total mass is 3500 g.

Explanation:
In the above-given question,
given that,
there are 3 1 kg and 1 500 g.
1 kg = 1000 g.
1000 + 1000 + 1000 + 500 = 3500 g.
so the total mass is 3500 g.

Question 4.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 80

Answer:
The total mass is 245 g.

Explanation:
In the above-given question,
given that,
there are 2 100 g objects, 4 10 g, and 5 1 g objects.
100 + 100 = 200.
10 + 10 + 10 + 10 = 40.
1 + 1 + 1 + 1 + 1 = 5.
200 + 40 + 5 = 245g.
so the total mass is 245 g.

Independent Practice

In 5-7, write the total mass represented in each picture.
Question 5.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 81

Answer:
The total mass is 931 g.

Explanation:
In the above-given question,
given that,
there are 1 500 g.
4 100 g and 3 10 g and 1 g.
500 + 100 + 100 + 100 + 100 = 900.
3 x 10 = 30.
30 + 1 = 31.
900 + 30 + 1 = 931.
so the total mass is 931 g.

Question 6.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 82

Answer:
The total mass is 6 kg.

Explanation:
In the above-given question,
given that,
there are 6 1 kg objects.
1 + 1 + 1 + 1 + 1 + 1 = 6.
so the total mass is 6 kg.

Question 7.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 83

Answer:
The total mass is 2106 g.

Explanation:
In the above-given question,
given that,
there are 2-1 kg objects.
2 x 1000 = 2000.
1 x 100 = 100.
6 x 1 = 6.
2000 + 100 + 6 = 2016 g.

Problem Solving

Question 8.
Algebra Olivia put 220 grams of nuts in a bag. Then she added more nuts to the bag. The total mass of Olivia’s bag of nuts was 850 grams. Use the equation 220 + a = 850 to find the mass in grams of the nuts Olivia added to her bag.

Answer:
The mass of the grams she added = 630 g.

Explanation:
In the above-given question,
given that,
Algebra Olivia put 220 grams of nuts in a bag.
Then she added more nuts to the bag.
The total mass of Olivia’s bag of nuts was 850 grams.
220 + a = 850.
a = 850 – 220.
a = 630.
so she added the 630 grams into the bag.

Question 9.
An adult manatee has a mass of about 450 kilograms. What is the mass of 2 adult manatees?
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 84

Answer:
The mass of 2 adult manatees = 900 kg.

Explanation:
In the above-given question,
given that,
An adult manatee has a mass of about 450 kilograms.
450 + 450 = 900.
so the mass of 2 adult manatees = 900 kg.

Question 10.
Reasoning Sophie used a pan balance to measure the mass of a pineapple. The pans balanced when she used one 500-gram weight and three 100-gram weights. Zach measured the same pineapple but used eight 100-gram weights. Did someone make a mistake? Explain.

Answer:
No one makes a mistake.

Explanation:
In the above-given question,
given that,
The pans balanced when she used one 500-gram weight and three 100-gram weights.
Zach measured the same pineapple but used eight 100-gram weights.
500 + 100 + 100 + 100 = 800 gram.
100 + 100 + 100 + 100 + 100 + 100 + 100 + 100 = 800 gram.
so no one makes a mistake.

Question 11.
Higher Order Thinking Lawrence bought some red potatoes with a mass of 410 grams. He also bought white potatoes with a mass of 655 grams. Did he buy more or less than 1 kilogram of potatoes? Explain how you know.

Answer:
He buys more than 1 kilogram of potatoes.

Explanation:
In the above-given question,
given that,
Lawrence bought some red potatoes with a mass of 410 grams.
He also bought white potatoes with a mass of 655 grams.
410 + 655 = 1065.
so he buys more than 1 kilogram of potatoes.

Question 12.
Meg uses 16 kilograms of butter to make 8 large batches of cookies. She uses an equal amount of butter for each batch. How many kilograms of butter are used for each batch?

Answer:
The number of kilograms of butter is used for each batch = 2 kg.

Explanation:
In the above-given question,
given that,
Meg uses 16 kilograms of butter to make 8 large batches of cookies.
She uses an equal amount of butter for each batch.
16 / 8 = 2.
he uses 2 kilograms of butter for each batch.
so the number of kilograms of butter is used for each batch = 2 kg.

Question 13.
Kalista has 154 grams of glitter. She uses 97 grams to sprinkle the tops of the tables. How many grams of glitter remain?

Answer:
The number of grams of glitter remains = 57.

Explanation:
In the above-given question,
given that,
Kalista has 154 grams of glitter.
She uses 97 grams to sprinkle the tops of the tables.
154 – 97 = 57.
so the number of grams of glitter remains = 57.

Assessment Practice

Question 14.
Evan used a pan balance and metric weights to measure the total mass of 3 bricks. What is the mass of the 3 bricks?
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 85
A. 6 kilograms
B. 5 kilograms
C. 4 kilograms
D. 3 kilograms

Answer:
The mass of the 3 bricks = 3 kg.

Explanation:
In the above-given question,
given that,
Evan used a pan balance and metric weights to measure the total mass of 3 bricks.
3 x 1000 = 3000.
so the mass of the 3 bricks = 3 kg.

Lesson 14.8 Solve Word Problems Involving Mass and Liquid Volume

Solve & Share
The animals at a pet store eat 80 kilograms of vegetables each day. How many kilograms of vegetables do they eat in one week?
I can … solve problems about mass and liquid volume.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 86

Look Back! Describe the plan you used to solve the problem.

Answer:
The number of vegetables does they eat in 1 week = 560 kg.

Explanation:
In the above-given question,
given that,
The animals at a pet store eat 80 kilograms of vegetables each day.
1 week = 7 days.
80 x 7 = 560.
so the number of vegetables do they eat in 1 week = 560 kg.

Essential Question
How Can You Solve Problems Involving Mass and Liquid Volume?

Visual Learning Bridge
In a juice factory, one 50-liter container had 28 liters of juice in it. An hour later, it had 45 liters of juice. How many liters of juice were added?
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 87

Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 88

Convince Me! Make Sense and Persevere In the example above, another beaker had 33 liters of juice. How many total liters of juice were there in all? How can you solve this problem?

Answer:
The liters of juice that were added = 5 liters.

Explanation:
In the above-given question,
given that,
another beaker had 33 liters of juice.
one 50-liter container had 28 liters of juice.
33 – 28 = 5.
so the number of liters that were added = 5 liters.

Guided Practice

Do You Understand?
Question 1.
Suppose 42 liters of juice were evenly divided into 6 batches. How many liters of juice are in each batch? Write and solve an equation.

Answer:
The number of liters is in each batch = liters.

Explanation:
In the above-given question,
given that,
Suppose 42 liters of juice were evenly divided into 6 batches.
42 /6 = 7.
6 x 7 = 42.
so the number of liters are in each batch = 7 liters.

Do You Know How?
Question 2.
Alex buys a box of pudding mix and a box of cocoa. The mass of the box of pudding mix is 100 grams. The total mass of the 2 boxes is 550 grams. What is the mass of the box of cocoa?
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 89

Answer:
The mass of the box of cocoa is 450 g.

Explanation:
In the above-given question,
given that,
Alex buys a box of pudding mix and a box of cocoa.
The mass of the box of pudding mix is 100 grams.
The total mass of the 2 boxes is 550 grams.
550 – 100 = 450.
so the mass of the box of cocoa is 450 g.

Independent Practice

Leveled Practice In 3-6, use bar diagrams or equations to help solve.
Question 3.
Peter divided 120 liters of water equally into 3 containers. How many liters did Peter pour into each container?
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 90

Answer:
The number of liters did peter pour into each container = 40 liters.

Explanation:
In the above-given question,
given that,
peter divided 120 liters of water equally into 3 containers.
c + c + c = 120.
3c = 120.
c = 120/3.
c = 40.
so the number of liters did peter pour into each container = 40 liters.

Question 4.
Adeela pours 235 liters of milk into a blue vat and 497 liters of milk into a red vat. How many liters of milk does she pour in all? Write and solve an equation.

Answer:
The quantity of milk she pours in all = liters.

Explanation:
In the above-given question,
Adeela pours 235 liters of milk into a blue vat and 497 liters of milk into a red vet.
235 + 497 = 732.
so the quantity of milk she pours in all = 732 liters.

Question 5.
Samantha bought 523 grams of grapes. After eating some grapes, she had 458 grams. How many grams did she eat?

Answer:
The number of grams did she eat = 65 g.

Explanation:
In the above-given question,
given that,
Samantha bought 523 grams of grapes.
After eating some grapes, she had 458 grams.
523 – 458 = 65.
so the number of grams did she eat = 65 g.

Question 6.
Omar is shipping 3 boxes. Each has a mass of 8 kilograms. What is the total mass of all of the boxes?

Answer:
The total mass of all the boxes = 24.

Explanation:
In the above-given question,
given that,
Omar is shipping 3 boxes.
each has a mass of 8 kilograms.
8 x 3 = 24.
so the total mass of all the boxes = 24.

Problem Solving

In 7 and 8, use the table. In 8, use the bar diagram.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 91
Question 7.
Professor Newman has collected a soil sample from the forest preserve in her town. What is the total mass of the 3 minerals in the soil sample?

Answer:
The total mass of the 3 minerals in the soil sample is 279 g.

Explanation:
In the above-given question,
given that,
Professor Newman has collected a soil sample from the forest preserve in her town.
the sample of quartz is 141 g.
calcite is 96 g.
feldspar is 42 g.
141 + 96 + 42 = 279.
so the total mass of the 3 minerals in the soil sample is 279 g.

Question 8.
Higher Order Thinking The professor finds that there is the same amount of feldspar in each of the soil samples that she takes. If there are 210 grams of feldspar in all, how many soil samples does she collect?

Answer:
The number of soil samples does she collect = 447 g.

Explanation:
In the above-given question,
given that,
If there are 210 grams of feldspar in all.
141 + 96 + 210 = 447 g.
so the number of soil samples does she collect = 447 g.

Question 9.
Elijah has 2 hours before dinner. He spends the first 37 minutes practicing his guitar and the next 48 minutes doing his homework. How much time is left until dinner?

Answer:
The number of times is left until dinner is 35.

Explanation:
In the above-given question,
given that,
Elijah has 2 hours before dinner.
He spends the first 37 minutes practicing his guitar and the next 48 minutes doing his homework.
37 + 48 = 85.
1 hour = 60 minutes.
60 + 60 = 120.
120 – 85 = 35.
so the number of time is left unit dinner is 35.

Question 10.
Make Sense and Persevere Write and solve a word problem about the bar diagram.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 92

Answer:
The mass of the a is 339 g.

Explanation:
In the above-given question,
given that,
the total mass of the object is 678 g.
678 – 239 = 339.
so the mass of the a is 339 g.

Assessment Practice

Question 11.
Eric filled a container to the 18-liter mark with juice an hour ago. The juice is now at the 15-liter mark. Mark the amount of juice Eric had on the beakers. Then find how many liters of juice have been poured out.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 93
A. 3 liters
B. 4 liters
C. 5 liters
D. 6 liters

Answer:
The number of liters of juice that has been poured out = 3 liters.

Explanation:
In the above-given question,
given that,
Eric filled a container to the 18-liter mark with juice an hour ago.
The juice is now at the 15-liter mark.
18 – 15 = 3.
so the number of liters of juice has been poured out = 3 liters.

Lesson 14.9 Problem Solving

Reasoning
Solve & Share
Nina wants to arrive at the community center at 9:30 A.M. for an art class. It takes her 15 minutes to walk to the center, 30 minutes to make and eat breakfast, and 15 minutes to get ready after eating. What time should Nina start making breakfast? Use reasoning to decide.
I can … make sense of quantities and relationships in problem situations.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 94

Thinking Habits
Be a good thinker! These questions can help you.

  • What do the numbers and symbols in the problem mean?
  • How are the numbers or quantities related?
  • How can I represent a word problem using pictures, numbers, or equations?

Look Back! Reasoning Does it make sense to use “minutes” as the unit for the answer to this problem? Explain.

Essential Question
How Can You Use Reasoning to Solve Problems?

Visual Learning Bridge
Eric’s family wants to arrive at a movie theater at 2:30 P.M. It takes them 30 minutes to eat lunch, 15 minutes to get ready after eating, and 30 minutes to travel to the theater.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 95
What do I need to do to solve this problem?
I need to start with the end time. Then I need to use the time lengths given and work backward to find the starting time.

Answer:
The starting time is 1:15 P.M.

Explanation:
In the above-given question,
given that,
Eric’s family wants to arrive at a movie theater at 2:30 P.M.
It takes them 30 minutes to eat lunch.
15 minutes to get ready after eating, and 30 minutes to travel to the theater.
30 + 30 + 15 = 1 hour 15 minutes.
so the starting time is 1:15 P.M.

How can I use reasoning to solve this problem?
I can

  • identify the quantities I know.
  • draw a number line to show relationships.
  • give the answer using the correct unit.

Here’s my thinking..
I used a number line to show the quantities and my reasoning.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 96
30 minutes before 2:30 P.M. is 2:00 P.M.
15 minutes before 2:00 P.M. is 1:45 P.M.
30 minutes before 1:45 P.M. is 1:15 P.M.
Eric’s family should start eating lunch at 1:15 P.M.

Convince Me! Reasoning How can you check that the solution given above makes sense?

Guided Practice

Reasoning Kevin’s doctor appointment is at 10:30 A.M. It takes Kevin 30 minutes to clean his room, 20 minutes to get ready after he cleans, and 20 minutes to walk to the doctor’s office. What time should Kevin start cleaning his room? Use reasoning to decide.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 97
Question 1.
Describe the quantities you know.

Answer:
The starting time is 9:20 A.M.

Explanation:
In the above-given question,
given that,
Kevin’s doctor appointment is at 10:30 A.M.
It takes Kevin 30 minutes to clean his room,
20 minutes to get ready after he cleans, and 20 minutes to walk to the doctor’s office.
10 : 30 – 30 = 10.
10 – 20 = 9:40.
9: 40 – 20 = 9:20.
so the starting time is 9:20 A.M.

Question 2.
Solve the problem and explain your reasoning. You can use a picture to help.

Answer:
The starting time is 9:20 A.M.

Explanation:
In the above-given question,
given that,
Kevin’s doctor appointment is at 10:30 A.M.
It takes Kevin 30 minutes to clean his room,
20 minutes to get ready after he cleans, and 20 minutes to walk to the doctor’s office.
10 : 30 – 30 = 10.
10 – 20 = 9:40.
9: 40 – 20 = 9:20.
so the starting time is 9:20 A.M.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-12

Independent Practice

Reasoning Doreen’s favorite television show begins at 5:30 P.M. She will get her hair cut before the show. It takes Doreen 10 minutes to walk to the hair salon and 10 minutes to walk home. Her haircut takes 25 minutes. What time should Doreen leave home so that she will get back in time for her show? Use reasoning to decide.
Question 3.
Describe the quantities you know.

Answer:
The time should Doreen leave home so that she will get back in time for her show = 4: 45 P.M.

Explanation:
In the above-given question,
given that,
Doreen’s favorite television show begins at 5:30 P.M.
She will get her hair cut before the show.
It takes Doreen 10 minutes to walk to the hair salon and 10 minutes to walk home.
Her haircut takes 25 minutes.
10 + 10 + 25 = 45.
4 : 45 P.M + 45 = 5:30.
so the time should Doreen leave home so that she will get back in time for her show = 4:45 P.M.

Question 4.
Solve the problem and explain your reasoning. You can use a picture to help.

Answer:
The time should Doreen leave home so that she will get back in time for her show = 4 : 45 P.M.

Explanation:
In the above-given question,
given that,
Doreen’s favorite television show begins at 5:30 P.M.
She will get her hair cut before the show.
It takes Doreen 10 minutes to walk to the hair salon and 10 minutes to walk home.
Her haircut takes 25 minutes.
10 + 10 + 25 = 45.
4 : 45 P.M + 45 = 5:30.
so the time should Doreen leave home so that she will get back in time for her show = 4:45 P.M.

Question 5.
How did you know whether to use A.M. or P.M. in your answer to Exercise 4 above?

Answer:
We have to use P.M.

Explanation:
In the above-given question,
given that,
Doreen’s favorite television show begins at 5:30 P.M.
She will get her hair cut before the show.
It takes Doreen 10 minutes to walk to the hair salon and 10 minutes to walk home.
Her haircut takes 25 minutes.
10 + 10 + 25 = 45.
4 : 45 P.M + 45 = 5:30.
so the time should Doreen leave home so that she will get back in time for her show = 4:45.

Problem Solving

Performance Task
School Talent Show Karina is planning a talent show for 28 students. The table below tells how long each act lasts. Karina needs 5 minutes to introduce each act. She also needs to allow a 20-minute break. The break does not need to be introduced. The show must end at 9:00 P.M.
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 98
Question 6.
Be Precise What is the total time needed for all the acts before the break? Explain your thinking.

Answer:
The total time needed for all the acts before the break = 45 minutes.

Explanation:
In the above-given question,
given that,
the 3rd-grade dancers = 10 minutes.
the 3rd-grade singers = 10 minutes.
the 4th-grade singers = 10 minutes.
the 4th-grade magic act = 15 minutes.
10 + 10 + 10 + 15 = 45.
so the total time needed for all the acts before the break = 45 minutes.

Question 7.
Critique Reasoning Sachi says that the 5th grade singers should begin at 7:40 P.M. Phil says that the 5th grade singers should begin at 8:00 P.M. Who is correct?
Envision Math Common Core Grade 3 Answer Key Topic 14 Solve Time, Capacity, and Mass Problems 99

Answer:
Phil says was correct.

Explanation:
In the above-given question,
given that,
Sachi says that the 5th-grade singers should begin at 7:40 P.M.
Phil says that the 5th-grade singers should begin at 8:00 P.M.
fifth-grade singers will sing in 10 minutes.
10 + 10 + 10 + 30 = 60.
so fifth grade singers will start at 8:00 P.M.
so Phil was correct.

Question 8.
Reasoning What time should the talent show begin? Explain your reasoning. You can draw a picture to help.

Answer:
The talent show begins at 7:15 P.M.

Explanation:
In the above-given question,
given that,
the 3rd-grade dancers = 10 min.
3rd-grade singers = 10 min.
4th-grade singers = 10 min.
4th-grade magic act = 15 min.
5th-grade singers = 10 min.
5th-grade magic act = 10 min.
5th grade dancers = 10 min.
finale = 30 min.
10 + 10 + 10 + 15 + 10 + 10 + 10 + 30 = 7:45 P.M.

Topic 14 Fluency Practice Activity

Point & Tally
Find a partner. Get paper and a pencil. Each partner chooses a different color: light blue or dark blue.
Partner 1 and Partner 2 each point to a black number at the same time. Both partners subtract the lesser number from the greater number.
If the answer is on your color, you get a tally mark. Work until one partner has seven tally marks.
While playing the game, partners can use addition to check their subtraction.

I can… add and subtract within 1,000.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 100

Topic 14 Vocabulary Review

Understand Vocabulary
Question 1.
Cross out any units below that are NOT measurement units of capacity.
gram
inch
kilogram
hour
liter

Answer:
The not measured units of capacity are gram and kilogram.

Explanation:
In the above-given question,
given that,
the units are gram, inch, kilogram, hour, and liter.
so the not measured units of capacity are gram and kilogram.

Question 2.
Cross out any units below that are NOT measurement units of mass.
kilogram
minute
hour
gram
liter

Answer:
The units that are not measured units of mass = gram and kilogram.

Explanation:
In the above-given question,
given that,
the units are kilogram, hour, gram, and liter.
mass is measured in weight.
so the units that are not measured units of mass = gram, and kilogram.

Question 3.
Cross out any amounts below that are shown in grams or kilograms.
5 kg
2L
80 in.
250 g
12 kg

Answer:
The amounts that are shown in grams or kilograms = 5 kg, 250 g, and 12 kg.

Explanation:
In the above-given question,
given that,
the units are 5 kg, 2 l, 80 in, 250 g, and 12 kg.
so the amounts that are shown in grams or kilograms = 5 kg, 250 g, and 12 kg.

Choose the right term from the box. Write it in the blank.
Word List

  • A.M.
  • capacity
  • elapsed time
  • gram
  • hour
  • kilogram
  • liter
  • mass
  • minute
  • P.M.
  • time interval

Question 4.
The hours between midnight and noon are ________ hours.

Answer:
The hours between midnight and noon are A.M hours.

Explanation:
In the above-given question,
given that,
the words are P.M and A.M.
so the hours between midnight and noon are:
for example,
if it is the morning we will say it is 10:30 A.M.
if it is the evening we will say it is 4:00 P.M.

Question 5.
An amount of time is a __________.

Answer:
An amount of time is a time interval.

Explanation:
In the above-given question,
given that,
if we want to know the start time and end time we will use the time interval.
so an amount of time is a time interval.

Question 6.
The hours between noon and midnight are ________ hours.

Answer:
The hours between noon and midnight are P.M hours.

Explanation:
In the above-given question,
given that,
the words are P.M and A.M.
so the hours between midnight and noon are:
for example,
if it is the morning we will say it is 10:30 A.M.
if it is an evening we will say it is 4:00 P.M.

Question 7.
1 _________ equals 1,000 grams.

Answer:
1 kilogram equals 1000 grams.

Explanation:
In the above-given question,
given that,
the words are grams and kilograms.
1 kg = 1000 grams.

Question 8.
The total amount of time that passes from the beginning time to the ending time is called the _________.

Answer:
The time that passes from beginning to ending time is elapsed time.

Explanation:
In the above-given question,
given that,
the words are beginning time and elapsed time.
for example:
beginning time is 10:00 A.M.
ending time is 1: 00 P.M.
so the elapsed time is 3 hours.

Use Vocabulary in Writing
Question 9.
Maggie wants to measure this container. Use at least 3 terms from the Word List to explain how Maggie can measure the container in different ways.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 101

Answer:
The container is 500 grams and half kg.

Explanation:
In the above-given question,
given that,
the container is a paint bucket.
so the container weight is 500 grams and half kg.

Topic 14 Reteaching

Set A pages 533-536

What is the time to the nearest minute?
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 102
The digital time is 10:27.
It is 27 minutes after 10 o’clock or 33 minutes before 11 o’clock.

Remember that, for minutes, count numbers on the clock by 5s, then count marks by 1.

Write the time shown on each clock in two ways.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 103

Answer:
The time is 12:17.

Explanation:
In the above-given question,
given that,
the hour hand is between 12 and 1.
count by 5’s from 12 to 5.
that is 5, 10, 15.
count by 1’s from 15, 16, and 17.
so the time is 12:17.

Question 2.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 104

Answer:
The time is 6:44.

Explanation:
In the above-given question,
given that,
the hour hand is between 6 and 7.
count by 5’s from 12 to 5.
that is 5, 10, 15, 20, 25, 30, 35, 40.
count by 1’s from 40, 41,42, 43, and 44.
so the time is 6:44.

Set B pages 537-540

Tomaz starts practicing his viola at 4:25 P.M. He practices until 5:05 P.M. How much time does he practice?

The amount of time is under 1 hour, so count the minutes from the start time to the end time, by 5s.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 105
There are 40 minutes between 4:25 P.M. and 5:05 P.M. So, Tomaz practices for 40 minutes.

Remember that you can use a clock face to find elapsed time.

In 1-3, find the elapsed time.
Question 1.
Basketball practice begins at 6:30 P.M. and lasts until 8:15 P.M. How much time does practice last?

Answer:
The time does practice last = 1:45 min.

Explanation:
In the above-given question,
given that,
Basketball practice begins at 6:30 P.M.
lasts until 8:15 P.M.
6:30 + 1 hour = 7:30.
1 hour = 60 minutes.
7:30 + 45 min = 8:15.
so the time is 1:45 min.

Question 2.
Mr. Walters starts preparing breakfast at 6:45 A.M. He finishes at 7:50 A.M. How long does it take for him to prepare breakfast?

Answer:
The time it takes for him to prepare breakfast = 1 hour 5 min.

Explanation:
In the above-given question,
given that,
Mr. Wallets starts preparing breakfast at 6:45 A.M.
He finishes at 7:50 A.M.
7:50 – 6:45 = 1:05.
so the time it takes for him to prepare breakfast = 1 hour 5 min.

Question 3.
Jean goes for a horseback ride. She leaves the barn on her horse at 2:10 P.M., and comes back at 2:50 P.M. How long was her ride?

Answer:
The long was her ride = 40 min.

Explanation:
In the above-given question,
given that,
Jean goes for a horseback ride.
She leaves the barn on her horse at 2:10 P.M.
and comes back at 2:50 P.M.
2:50 – 2:10 = 40.
so the long was her ride = 40 min.

Set C pages 541-544

You can show addition and subtraction of time intervals on a number line.
In the morning, Xavier runs for 19 minutes. In the evening, he runs for 27 minutes. How much time does he spend running in all?
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 106
19 + 27 = ?
19 + 27 = 46
So, Xavier runs for 46 minutes.

Remember to decide whether you need to add or subtract.

In 1, solve by drawing a number line or a bar diagram.
Question 1.
It takes Don 52 minutes to drive to work. He has already driven for 16 minutes. How many more minutes will it take Don to drive to work?

Answer:
The more minutes will it take Don to drive to work = 36 minutes.

Explanation:
In the above-given question,
given that,
It takes Don 52 minutes to drive to work.
He has already driven for 16 minutes.
52 – 16 = 36.
so the more minutes will it take Don to drive to work = 36 minutes.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-13

Set D pages 545-548

Estimate the capacity of a pitcher.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 107
Think about what you already know. A liter is about the same size as a large water bottle. A pitcher usually holds more liquid than a water bottle. So, 2 liters seems like a good estimate.

Remember that capacity can be measured using liters.

In 1-4, circle the better estimate.

Question 1.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 108
1 L or 10 L

Answer:
The better estimation of a bottle is 1 l.

Explanation:
In the above-given question,
given that,
the given measurements are 1 L or 10 L.
1000 ml = 1 liter.
500 ml = 1/2 liter.
so the better estimation of a bottle is 1 liter.

Question 2.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 109
\(\frac{1}{4}\) L or 8 L

Answer:
The better estimation of a bucket is 8 l.

Explanation:
In the above-given question,
given that,
the given measurements are 1/4 L or 8 L.
1000 ml = 1 liter.
500 ml = 1/2 liter.
so the better estimation of a bucket is 8 liter.

Question 3.
Drinking glass
5 L or \(\frac{1}{2}\) L

Answer:
The better estimation of drinking glass is 1/2 l.

Explanation:
In the above-given question,
given that,
the given measurements are 5 L or 1/2 L.
1000 ml = 1 liter.
500 ml = 1/2 liter.
so the better estimation of a drinking bottle is 1/2 liter.

Question 4.
Washing machine
40 L or 4L

Answer:
The better estimation of a washing machine is 40 l.

Explanation:
In the above-given question,
given that,
the given measurements are 40 L or 4 L.
1000 ml = 1 liter.
500 ml = 1/2 liter.
so the better estimation of a washing machine is 40 liter.

Set E pages 549-552

How much water is in this beaker?
Use the scale to determine how full the beaker is. Think of the scale as a number line. Each mark represents 1 liter. The water is 3 marks : – 10 liters above 5 liters.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 110
There are 8 liters in the beaker.

Remember to use the correct units when measuring capacity.

In 1 and 2, find the total capacity.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 111

Answer:
The total capacity of two beakers = 3 liters.

Explanation:
In the above-given question,
given that,
the 1st beaker contains 1 n 1/2 liter.
the 2nd beaker contains 1 n 1/2 liter.
1.5 + 1.5 = 3 liters.
so the total capacity of two beakers = 3 liters.

Question 2.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 112

Answer:
The total capacity of the beaker = 6 liters.

Explanation:
In the above-given question,
given that,
the 1st beaker contains 6 liters.
5 + 1 = 6 liters.
so the total capacity of beakers = 6 liters.

Set F pages 553-556

Estimate the mass of a battery.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 113
A kilogram is too heavy, so estimate using grams.

Think about what you already know. A gram is about the same weight as a grape. A battery weighs about as much as a bunch of grapes. So 30 grams seems like a good estimate.

Remember that mass can be measured using grams and kilograms.

In 1-6, circle the better estimate for the mass.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 114
15 g or 15 kg

Answer:
The better estimation of the pen is 15 g.

Explanation:
In the above-given question,
given that,
the given measurements are 15 g or 15 kg.
1000 g = 1 kg.
500 g = 1/2 kg.
so the better estimation of a washing machine is 15 g.

Question 2.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 115
500 g or 500 kg

Answer:
The better estimation of the pen is 500 g.

Explanation:
In the above-given question,
given that,
the given measurements are 500 g or 500 kg.
1000 g = 1 kg.
500 g = 1/2 kg.
so the better estimation of a washing machine is 500 g.

Question 3.
One sheep
800 g or 80 kg

Answer:
The better estimation of sheep is 80 kg.

Explanation:
In the above-given question,
given that,
the given measurements are 800 g or 80 kg.
1000 g = 1 kg.
500 g = 1/2 kg.
so the better estimation of a sheep is 80 kg.

Question 4.
Bag of flour
2 g or 2 kg

Answer:
The better estimation of the bag of flour is 2 kg.

Explanation:
In the above-given question,
given that,
the given measurements are 2 g or 2 kg.
1000 g = 1 kg.
500 g = 1/2 kg.
so the better estimation of a bag of flour is 2 kg.

Question 5.
Notebook computer
3 g or 3 kg

Answer:
The better estimation of the Notebook computer is 3 kg.

Explanation:
In the above-given question,
given that,
the given measurements are 3 g or 3 kg.
1000 g = 1 kg.
500 g = 1/2 kg.
so the better estimation of a washing machine is 3 kg.

Question 6.
Quarter
5 g or 500 g

Answer:
The better estimation of the Quarter is 500 g.

Explanation:
In the above-given question,
given that,
the given measurements are 5 g or 5 00 g.
1000 g = 1 kg.
500 g = 1/2 kg.
so the better estimation of a quarter is 500 g.

Set G pages 557-560

What is the mass of this bar of soap?
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 116
When a pan balance is even, the mass on the left side equals the mass on the right side.
Find the total of the weights on the left side. Use mental math and place value to help add.
100 + 10 + 5 + 1 + 1 + 1 = 118
The bar of soap has a mass of 118 grams.

Remember to use the correct units when measuring mass.

In 1 and 2, find the total mass.
Question 1.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 117

Answer:
The total mass is 701g.

Explanation:
In the above-given question,
given that,
they have given 1 500 g.
2 100 g.
1 hundred g.
500 + 200 + 1 = 701.
so the total mass is 701 g.

Question 2.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 118

Answer:
The total mass is 2210 g.

Explanation:
In the above-given question,
given that,
they have given 1 100 kg.
2 100 g.
2 5 g.
1000 + 1000 + 200 +10 = 2210.
so the total mass is 2210 g.

Set H pages 561-564

There are 7 people bowling together. Each owns their own bowling ball. The mass of each bowling ball is 5 kilograms. What is the total mass of the team’s bowling balls?
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 119

Remember that you can use bar diagrams or equations to represent problems.

In 1 and 2, use bar diagrams or equations to help solve.
Question 1.
The water tank in Mary’s yard holds 60 liters of water. She used 13 liters to water her plants. How many liters of water remain in the water tank?

Answer:
The quantity of water that remains in the water tank = 47 liters.

Explanation:
In the above-given question,
given that,
the water tank in mary’s yard holds 60 liters of water.
she used 13 liters to water her plants.
60 – 13 = 47.
so the quantity of water remains in the water tank = 47 liters.

Question 2.
Eric has 3 dogs that each have a mass of 8 kilograms. What is the total mass of all of Eric’s dogs?

Answer:
The total mass of all of Eric’s dogs = 24 kg.

Explanation:
In the above-given question,
given that,
Eric has 3 dogs that each have a mass of 8 kilograms.
8 x 3 = 24.
24 /8 = 3.
so the total mass of all of Eric’s dogs = 24 kg.

Set I pages 565-568

Think about these questions to help you reason abstractly and quantitatively.
Thinking Habits

  • What do the numbers and symbols in the problem mean?
  • How are the numbers or quantities related?
  • How can I represent a word problem using pictures, numbers, or equations?
    Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 120

Remember to consider the units in the information you are given.

At 1:00 P.M., Ted will meet a friend in the park.. Ted needs 30 minutes to walk to the park. Ted needs 15 minutes to eat lunch and 10 minutes to prepare lunch. When must Ted start to prepare lunch?
Question 1.
Describe the quantities you know.

Answer:
Ted start to prepare lunch = 12:05 P.M.

Explanation:
In the above-given question,
given that,
Ted will meet a friend in the park.
Ted needs 30 minutes to walk to the park.
Ted needs 15 minutes to eat lunch and 10 minutes to prepare lunch.
30 + 15 + 10 = 55 minutes.
so ted start to prepare lunch = 12:05 P.M.

Question 2.
How can you show the relationships in this problem?

Answer:
Ted start to prepare lunch = 12:05 P.M.

Explanation:
In the above-given question,
given that,
Ted will meet a friend in the park.
Ted needs 30 minutes to walk to the park.
Ted needs 15 minutes to eat lunch and 10 minutes to prepare lunch.
30 + 15 + 10 = 55 minutes.
so ted start to prepare lunch = 12:05 P.M.

Question 3.
When must Ted start to prepare lunch?

Answer:
Ted start to prepare lunch = 12:05 P.M.

Explanation:
In the above-given question,
given that,
Ted will meet a friend in the park.
Ted needs 30 minutes to walk to the park.
Ted needs 15 minutes to eat lunch and 10 minutes to prepare lunch.
30 + 15 + 10 = 55 minutes.
so ted start to prepare lunch = 12:05 P.M.

Topic 14 Assessment Practice

Question 1.
Draw hands on the clock to show 8:36. What time will it be in 2 hours and 6 minutes?
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 121

Answer:
The time is 6:42.

Explanation:
In the above-given question,
given that,
the hour hand is on the 8.
the minute hand is on the 8.
the second’s hand is on the 42.
so the time is 6:42.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-14

Question 2.
Jessica and Cody ran a long-distance race during an afternoon. The start times were different so that all the runners did not start at the same time. Who finished faster, and by how many minutes?
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 122
A. Jessica; 5 minutes faster than Cody
B. Cody; 5 minutes faster than Jessica
C. Jessica; 10 minutes faster than Cody
D. They finished in the same amount of time.

Answer:
Option D is the correct answer.

Explanation:
In the above-given question,
given that,
Jessica and Cody ran a long-distance race during the afternoon.
The start times were different so that all the runners did not start at the same time.
Jessica starts at 3:55 and ends at 4:40.
Cody starts at 4:15 and ends at 5:05.
5:05 – 4:15 = 90 min.
4:40 – 3:55 = 85 min.
so option D is the correct answer.

Question 3.
Two stores in a small town sell bags of apples. At Store A, each bag weighs 2 kilograms. At Store B, each bag weighs 4 kilograms. If you buy 6 bags at each store, how many more kilograms of apples will you buy from Store B?

Answer:
The kilograms of apples will you buy from store B = 24 kg.

Explanation:
In the above-given question,
given that,
Two stories in a small town sell bags of apples.
At Store A, each bag weighs 2 kilograms.
At Store B, each bag weighs 4 kilograms.
6 x 2 = 12 kg.
4 x 6 = 24 kg.
so the number of kilograms of apples will you buy from store B = 24 kg.

Question 4.
Name the metric unit that could be used to measure the capacity of a kitchen sink. Then, using that unit, write a reasonable estimate for the capacity of a kitchen sink.

Answer:
The reasonable estimate for the capacity of a kitchen sink = 30 kg.

Explanation:
In the above-given question,
given that,
the unit is kg.
the weight of the kitchen sink is 30 kg.
so the reasonable estimate for the capacity of a kitchen sink = 30 kg.

Question 5.
A. Mason is looking for a tool to measure the mass of an apple. Which tool should he use?
A. Pan balance
B. Ruler
C. 1-cup container
D. Clock

Answer:
Option A is correct.

Explanation:
In the above-given question,
given that,
the units are panned balance, ruler, 1-cup container, and clock.
pan balance is used to measure the mass of an apple.
so option A is correct.

B. Using the tool identified in Part A, what unit will Mason use to measure the mass of the apple?
A. Grams
B. Minutes
C. Cups
D. Inches

Answer:
Grams are the unit that measures the mass of the apple.

Explanation:
In the above-given question,
given that,
the units are grams, minutes, cups, and inches.
mass of the apple is measured in grams.
so grams is the unit that measures the mass of the apple.

Question 6.
Dale’s school bus picks him up at 7:45 A.M. To get ready for school, Dale needs 15 minutes to eat breakfast, 10 minutes to make lunch, and 10 minutes to get dressed. What time does Dale need to begin getting ready for school?
A. Describe the quantities you know.

Answer:
Dale needs to get ready for school = 7:10.

Explanation:
In the above-given question,
given that,
Dale’s school bus picks him up at 7:45 A.M.
To get ready for school, Dale needs 15 minutes to eat breakfast, 10 minutes to make lunch, and 10 minutes to get dressed.
15 + 10 + 10 = 35 min.
7:45 – 35 = 7:10.
so Dale needs to getting ready for school = 7:10

B. Solve the problem. Explain your reasoning. You can use a picture to help.

Answer:
Dale needs to get ready for school = 7:10.

Explanation:
In the above-given question,
given that,
Dale’s school bus picks him up at 7:45 A.M.
To get ready for school, Dale needs 15 minutes to eat breakfast, 10 minutes to make lunch, and 10 minutes to get dressed.
15 + 10 + 10 = 35 min.
7:45 – 35 = 7:10.
so Dale needs to getting ready for school = 7:10

Question 7.
Mary has a total of 18 liters of water in 6 bottles. Jess has a total of 15 liters in 3 bottles. If the bottles are equally filled, how much more water is in each of Jess’s bottles than in Mary’s bottles?

Answer:
One more bottle of water is filled in Jess.

Explanation:
In the above-given question,
given that,
Mary has a total of 18 liters of water in 6 bottles.
Jess has a total of 15 liters in 3 bottles.
18/6 = 3.
15/3 = 5.
15 + 3 = 18.
so one more bottle of water is filled in Jess.

Question 8.
Eric played the guitar for 33 minutes on Monday and 19 minutes on Tuesday. Write and solve an equation to find how many more minutes Eric played the guitar on Monday.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 123

Answer:
The more minutes Eric played the guitar on Monday = 14 min.

Explanation:
In the above-given question,
given that,
Eric played the guitar for 33 minutes on Monday and 19 minutes on Tuesday.
33 – 19 = 14.
so the more minutes eric played the guitar on Monday = 14 min.

Question 9.
Mrs. Griggs writes a shopping list saying she needs to buy 1 gram of apples. Is this reasonable? Explain.

Answer:
No, it is not reasonable.

Explanation:
In the above-given question,
given that,
Mrs. Griggs writes a shopping list saying she needs to buy 1 gram of apples.
1000 grams = 1 kg.
the mass of the apple is 100 g.
so it is not reasonable.

Question 10.
Irene measured the mass of a bag of apples using kilograms. Forest measured the same bag using grams. How did the measurements compare? Select all the sentences that are true.
☐ There were more grams than kilograms.
☐ There were more kilograms than grams.
☐ There was an equal number of grams and kilograms.
☐ There were fewer grams than kilograms.
☐ There were fewer kilograms than grams.

Answer:
Options A, C, and E are correct.

Explanation:
In the above-given question,
given that,
Irene measured the mass of a bag of apples using kilograms.
Forest measured the same bag using grams.
there were more grams than kilograms.
there was an equal number of grams and kilograms.
there were fewer kilograms than grams.
so options A, C, and E are correct.

Question 11.
Jason said the mass of his book is about 1 kilogram. Julie said it is 1 liter. Who is correct? Select the best answer.
A. Jason is correct because kilograms are units of mass, and liters are units of capacity.
B. Julie is correct because liters are metric units.
C. They are both correct because kilograms and liters are units of mass.
D. Neither is correct because their estimates are not reasonable.

Answer:
The best answer is option A.

Explanation:
In the above-given question,
given that,
Jason said the mass of his book is about 1 kilogram.
Julie said it is 1 liter.
Jason is correct because kilograms are units of mass and liters are units of capacity.
so Option A is correct.

Question 12.
Explain why it would be better to use grams rather than kilograms to measure the mass of a crayon.

Answer:
It is better to use grams.

Explanation:
In the above-given question,
given that,
crayon is a very small object.
it is measured in grams.
so it is better to use grams for crayons.

Question 13.
It took Wallace 45 minutes to read part of a chapter of his science book. He finished reading the rest of the chapter in 17 minutes. Write and solve an equation to find how much time Wallace spent reading the chapter.

Answer:
The time he spent reading the chapter is 62 minutes.

Explanation:
In the above-given question,
given that,
It took Wallace 45 minutes to read part of a chapter of his science book.
He finished reading the rest of the chapter in 17 minutes.
45 + 17 = 62.
so the time he spent reading the chapter is 62 minutes.

Question 14.
Four brothers, Raphael, Don, Leo, and Mike, went to the gym to exercise. Don and Mike both started at 2:21 P.M. and exercised for 33 minutes. Raphael and Leo both started when Don and Mike finished and exercised until 3:36 P.M. For how many minutes did the brothers exercise in total?

Answer:
The number of minutes the brothers exercise in total = 75 minutes

Explanation:
In the above-given question,
given that,
Four brothers, Raphael, Don, Leo, and Mike, went to the gym to exercise.
Don and Mike both started at 2:21 P.M. and exercised for 33 minutes.
Raphael and Leo both started when Don and Mike finished and exercised until 3:36 P.M.
33 + 2:21 = 2:54.
3:36 – 2:54 = 82.
42 + 33 = 75.
so the number of minutes the brothers exercise in total = 75 minutes.

Question 15.
Mark used a pan balance to find the mass of his basketball. He said it was 580 kilograms. Is his answer reasonable? Explain.

Answer:
No, his answer was not reasonable.

Explanation:
In the above-given question,
given that,
Mark used a pan balance to find the mass of his basketball.
He said it was 580 kilograms.
the mass of the basketball is 5 kgs.
so the answer not reasonable.

Question 16.
Look at the time on the clock below.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 124
A. Select all of the ways to write this time.
☐ 3 : 46
☐ 14 minutes before 4 o’clock
☐ 46 minutes after 3 o’clock
☐ 9 minutes before 4 o’clock
☐ 4 : 14

Answer:
Option A is the correct answer.

Explanation:
In the above-given question,
given that,
the hour hand is in between 3 and 4.
the minute’s hand is in between 9 and 10.
5 x 9 = 45.
45 + 1 = 46.
so Option A is the correct answer.

B. What time was it 2 hours, 45 minutes ago?

Answer:
The time was 1 hour 1 minute.

Explanation:
In the above-given question,
given that,
the time is 3:46.
3:46 – 2:45 = 1:01.
so the time is 1 hour 1 minute.

Question 17.
Maryann went to the grocery store at 3:10 P.M. She arrived home 1 hour, 15 minutes later.
A. What time did she arrive home?

Answer:
The time did she arrive = 4:25.

Explanation:
In the above-given question,
given that,
Maryann went to the grocery store at 3:10 P.M.
she arrived home 1 hour 15 minutes later.
3:10 + 1:15 = 4:25.
so the time did she arrive = 4:25.

B. Her neighbor Betty Sue got to the grocery store at the same time as Maryann and got home at 4:02 P.M. How much less time did Betty Sue spend shopping?

Answer:
The less time did Betty Sue spend shopping is 23 minutes.

Explanation:
In the above-given question,
given that,
Her neighbor Betty Sue got to the grocery store at the same time as Maryann and got home at 4:02 P.M.
4:25 – 4:02 = 23.
so the less time did Betty Sue spend shopping is 23 minutes.

Question 18.
Ricardo used 337 grams of flour to bake in the afternoon. He had already used 284 grams of flour to bake in the morning. Write and solve an equation to find how many grams of flour Ricardo used in all.

Answer:
The number of grams of flour Ricardo used in all = 53 g.

Explanation:
In the above-given question,
given that,
Ricardo used 337 grams of flour to bake in the afternoon.
He had already used 284 grams of flour to bake in the morning.
337 + a = 284.
a = 337 – 284.
a = 53.
so the number of grams of flour Ricardo used in all = 53 g.

Question 19.
A tank contained 750 liters of water. After some water drained out, the tank had 250 liters of water. Write and solve an equation to find how many liters of water drained out.

Answer:
The number of liters of water drained out = 500 liters.

Explanation:
In the above-given question,
given that,
A tank contained 750 liters of water.
After some water drained out, the tank had 250 liters of water.
750 + w = 250.
w = 750 – 250.
w = 500.
so the number of liters of water drained out = 500 liters.

Topic 14 Performance Task

Family Reunion
Anita and her brother Logan make plans for a family reunion.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 125

Question 1.
Use the Fruit Bought table to answer the question. Logan estimated the mass of the fruit. He forgot to include the unit of mass. For each item, explain if he used a gram or kilogram.

Answer:
The missing values of mass are 4 kg, 90 g, and 3 kgs.

Explanation:
In the above-given question,
given that,
the estimated unit of the mass is grape is 4 kg.
one lemon has an estimated mass of 90 g.
the mass of the watermelon is 3 kgs.
so the missing values of mass are 4kg, 90 g, and 3 kgs.

Question 2.
Use the Mass of One Lime picture to answer the questions.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 126
Part A
Each lime has the mass shown at the right. What is the mass of one lime?

Answer:
The mass of one lime is 30 g.

Explanation:
In the above-given question,
given that,
there is 3 mass of lime.
10 + 10 + 10 = 30.
3 x 10 = 30.
so the mass of one lime is 30 g.

Part B
Logan needs to buy at least 200 grams of limes. He plans to buy 7 limes. Will he buy enough? Use your response to Part A to explain.

Answer:
Yes, he will buy enough limes.

Explanation:
In the above-given question,
given that,
Logan needs to buy at least 200 grams of limes.
He plans to buy 7 limes.
7 x 30 = 210.
so he will buy enough limes.

Question 3.
Use the Liquids Needed table to answer the question.
Logan measures the liquids they need. Complete the table to show if the capacity of each container will likely be less than or greater than 1 liter.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 127

Answer:
The container contains a spoon of vinegar, milk, and water.

Explanation:
In the above-given question,
given that,
the ingredients are vinegar, milk, and water.
the spoon of vinegar is measured in grams.
the measuring cup of milk is liters.
the large pot is measured in kilograms.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-14- Solve Time, Capacity, and Mass Problems-15

The Broth Used picture shows the amount of broth that Anita started with and the amount she had left after she poured some into two different soups.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 128

Question 4.
Use the Broth Used picture to answer the questions.
Part A
How much broth did Anita use?

Answer:
The amount Anita used is 22 liters.

Explanation:
In the above-given question,
given that,
The Broth Used picture shows the amount of broth that Anita started with and the amount she had left.
20 + 2 = 22.
so the amount Anita used is 22 liters.

Part B
Anita poured an equal amount of broth into 2 pots. How much did she pour into 1 pot?

Answer:
The water she poured into 1 pot = 20 liters.

Explanation:
In the above-given question,
given that,
Anita poured an equal amount of broth into 2 pots.
Anita poured 20 liters in 1 both.
she poured 2 liters in 2nd both.
20 + 2 = 22.
so the water she poured into 1 pot = 20 liters.

Question 5.
Logan’s recipe says it takes 50 minutes to cook chicken. After 22 minutes pass, Logan flips the chicken. How many more minutes does the chicken have to bake after Logan flips it? Show your work on a number line.

Answer:
The many more minutes does the chicken have to bake after logan flips it = 28 minutes.

Explanation:
In the above-given question,
given that,
Logan’s recipe says it takes 50 minutes to cook chicken.
After 22 minutes pass, Logan flips the chicken.
50 – 22 = 28.
so the more minutes does the chicken have to bake after logan flips it = 28 minutes.

Question 6.
Use the Before Reunion table to answer the question.
Envision Math Common Core Grade 3 Answers Topic 14 Solve Time, Capacity, and Mass Problems 129
Anita and Logan want to be at the reunion at 1:45 P.M. They need to clean, pack, and drive to the reunion. What time should they start? Explain.

Answer:
The time should they start = 12:15 P.M.

Explanation:
In the above-given question,
given that,
Anita and Logan want to be at the reunion at 1:45 P.M.
they have to clean for 20 min.
they have to pack for 15 min.
they have to drive for 55 min.
20 + 15 + 55 = 90.
1 hour = 60 min.
90 min = 1 and half hours.
1:45 – 12:15 = 1:30.
so the time should they start = 12:15 P.M.

enVision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000

enVision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000

Go through the enVision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 regularly and improve your accuracy in solving questions.

enVision Math Common Core 3rd Grade Answers Key Topic 9 Fluently Add and Subtract within 1,000

Essential Question: What are the procedures for adding and subtracting whole numbers?

Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 1
enVision STEM Project: Changing Environments
Do Research Forest fires destroy, but they also make room for new growth. Use the Internet or other sources to find information about forest fires. Describe the effect of forest fires on plant and animal populations.
Journal: Write a Report Include data with numbers for the population you researched. Also in your report:

  • Choose a kind of animal or plant. Tell how a change in the environment can affect the number of animals or plants.
  • Write and solve an addition and a subtraction problem using your data.

Review What You Know

Vocabulary

Choose the best term from the box. Write it on the blank.

• Associative Property of Addition
• Commutative Property of Addition
• compatible numbers
• inverse operations

Question 1.
___ are easy to add or subtract mentally.
Answer:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally.
Thus, Compatible numbers are easy to add or subtract mentally.

Question 2.
According to the _______, the grouping of addends can be changed, and the sum will remain the same.
Answer:
The commutative property of addition says that changing the order of addends does not change the sum.
So, According to the commutative property of addition, the grouping of addends can be changed, and the sum will remain the same.

Question 3.
Addition and subtraction are ___
Answer:
Inverse operations are pairs of mathematical manipulations in which one operation undoes the action of the other.
Thus Addition and subtraction are inverse operations.

Rounding

Round each number to the nearest ten.

Question 4.
57
Answer:
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.
Here 7 is greater than 5.
So, 57 round to the nearest ten is 60.

Question 5.
241
Answer:
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
So, 241 round to the nearest ten is 240.

Question 6.
495
Answer:
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.
Thus 495 round to the nearest ten is 500.

Round each number to the nearest hundred.

Question 7.
732
Answer:
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
Thus the number 732 to the nearest hundred is 700.

Question 8.
81
Answer:
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
Thus the number 81 to the nearest hundred is 100.

Question 9.
553
Answer:
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
Thus the number 553 to the nearest hundred is 600.

Estimating Sums

Use compatible numbers to estimate each sum.

Question 10.
27 + 12
Answer:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally.
Write 27 and 12 to the nearest ten.
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
27 to the nearest ten is 30.
12 to the nearest ten is 10.
30 + 10 = 40
Thus the estimated sum is 40.

Question 11.
133 + 102
Answer:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally.
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
133 to the nearest ten is 130.
102 to the nearest ten is 100.
130 + 100 = 230
Thus the estimated sum is 230.

Question 12.
504 + 345
Answer:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally.
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
Thus the number 504 to the nearest hundred is 500.
Thus the number 345 to the nearest hundred is 300.
500 + 300 = 800
Thus the estimated sum is 800.

Question 13.
52 + 870
Answer:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally.
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
Thus the number 52 to the nearest ten is 50.
Thus the number 870 to the nearest hundred is 900.
900 + 50 = 950
Thus the estimated sum is 950.

Question 14.
293 + 278
Answer:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally.
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
Thus the number 293 to the nearest hundred is 300.
Thus the number 278 to the nearest hundred is 300.
300 + 300 = 600
Thus the estimated sum is 600.

Question 15.
119 + 426
Answer:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally.
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
Thus the number 119 to the nearest hundred is 100.
Thus the number 426 to the nearest hundred is 400.
100 + 400 = 500
Thus the estimated sum is 500.

Estimating Differences

Question 16.
Tony and Kim play a video game. Tony scores 512 points. Kim scores 768 points. About how many more points does Kim score than Tony? Which estimation method did you use?
Answer:
Given,
Tony and Kim play a video game. Tony scores 512 points. Kim scores 768 points.
768 – 512
Write the nearest hundred values for both the numbers to estimate the sum.
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
Thus the number 512 to the nearest hundred is 500.
Thus the number 768 to the nearest hundred is 800.
800 – 500 = 300
Thus Kim scores nearly .00 points than Tony.

Question 17.
Which number sentence shows the most reasonable estimate for
A. 425 – 250 = 175
B. 500 – 200 = 300
C. 400 – 300 = 100
D. 470 – 230 = 240
Answer: 500 – 200 = 300

Pick a Project

PROJECT 9A
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.1
How do you know which is the tallest building?
Project: Research the Heights of Tall Buildings

PROJECT 9B
How can you record what you bought over time? Project: Create an Addition Skit
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.2

PROJECT 9C
How long before the space shuttle launches?
Project: Write a Report About Your Vacation
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.3

3-ACT MATH PREVIEW

Math Modeling
Fun Raiser

Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.4
Before watching the video, think: When a school needs extra money for a field trip or a student club, it might hold a fundraiser to collect that money.
This check is SO BIG, we must have collected a ton of money!

Lesson 9.1 Use Partial Sums to Add

Activity

Solve & Share
There are 2 bins of oranges. One bin has 378 oranges. The other bin has 243 oranges. Find the sum of 378 + 243. Think about place value.

You can use structure. You can break apart the problem to show each of the addends in expanded form.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.6

Look Back! Adam has 9 bags of oranges with 8 oranges in each. He also has a bin with 325 oranges. How many oranges does Adam have in all? Think about how you can use place value or other tools to help solve the problem. Explain your solution, what tool you used, and why.

Essential Question How Can You Break Apart Addition Problems to Solve?

Visual Learning Bridge

A.
Margot counted 243 manatees one year and 179 manatees the next. How many manatees did Margot count all together?
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.7

B.
You can estimate and then use place value to add the numbers.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.8
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.9
The sum is about 400 manatees.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.10

C.
One Way
Add each place value. Start with hundreds.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.11
300, 110, and 12 are partial sums.
243 + 179 = 422 manatees

D.
Another Way
Add each place value. Start with ones.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.12
When you add by place value, you add the hundreds, the tens, and the ones.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.14
243 + 179 = 422 manatees
422 is close to the estimate of 400.
So, 422 is a reasonable sum.

Convince Me!
Critique Reasoning Lexi used partial sums to complete the problem. Critique Lexi’s reasoning. Is her work correct? Explain.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 5.15

Guided Practices

Do You Understand?

Question 1.
Suppose you were adding 527 + 405. What numbers would you combine when adding the tens? Why?
Answer:
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
Add 3 to 527 = 530
530
410
940
Thus, It would be 3 because when you add it, it gets to be 932 and the tens place is 3.

Question 2.
Find the error. Show how to find the correct answer.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 6.1
Answer:
First round the numbers to the nearest hundred.
237 to the nearest hundred is 200
285 to the nearest hundred is 300
200 + 300 = 500
So, the estimated answer is 500.

Do You Know How?

In 3, estimate the sum. Use place-value blocks or drawings and partial sums to add.

Question 3.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 6.2
Answer:
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
365 to the nearest hundred is 400
422 to the nearest hundred is 400
400 + 400 = 800
So, the estimated answer is 800.

Independent Practice

Leveled Practice In 4-11, estimate each sum. Use place-value blocks or drawings and partial sums to add.

Question 4.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 6.3
Answer:
When rounding to the nearest hundred, look at the tens place of the number.
If the tens digit is 0, 1, 2, 3, or 4, you will round down to the previous hundred.
If that digit is 5, 6, 7, 8, or 9, you will round up to the next hundred.
356 to the nearest hundred is 400
123 to the nearest hundred is 100
400 + 100 = 500
So, the estimated answer is 500.

Question 5.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 6.4
Answer:
550 + 423 = 973
973 is close to 1000.
So, the estimated sum is 1000.

Question 6.
185 + 613
Answer:
185 + 613 = 798
798 is close to 800.
So, the estimated sum is 800.

Question 7.
730 + 168
Answer:
730 + 168 = 898
898 is close to 900.
So, the estimated sum is 900.

Question 8.
546 + 143
Answer:
546 + 143 = 689
689 is close to 700.
So, the estimated sum is 700.

Question 9.
362 + 524
Answer:
362 + 524 = 886
886 is close to 900.
So, the estimated sum is 900.

Question 10.
644 + 101
Answer:
644 + 101 = 745
745 is close to 700.
So, the estimated sum is 700.

Question 11.
463 + 315
Answer:
463 + 315 = 778
778 is close to 800.
So, the estimated sum is 800.

Problem Solving

Question 12.
Model with Math John read a book with 377 pages. Jess read a book with 210 pages. How many pages did John and Jess read? Use place-value blocks and partial sums to solve. Draw a model to represent the problem.
Answer:
Given,
John read a book with 377 pages. Jess read a book with 210 pages.
377 + 210 = 587
587 is close to 600.
So, the estimated sum is 600.

Question 13.
Explain how the solids shown in Group A and Group B could have been sorted.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 6.5
Answer:

Question 14.
Henry believes the sum of 275 + 313 is 598. Is Henry correct? Use place-value blocks or drawings and partial sums in your explanation.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 6.6
Answer:
Given,
Henry believes the sum of 275 + 313 is 598.
The sum of 275 and 313 os 588.
Henry is not correct.

Question 15.
Higher Order Thinking A school cafeteria sold 255 lunches on Monday, 140 lunches on Tuesday, and 226 lunches on Wednesday. Did the cafeteria sell more lunches on Monday and Tuesday or on Tuesday and Wednesday? Use place value blocks or drawings to solve.
Answer:
Given,
A school cafeteria sold 255 lunches on Monday, 140 lunches on Tuesday, and 226 lunches on Wednesday.
225 + 140 = 365
140 + 226 = 366
Thus cafeteria sells more lunches on Tuesday and Wednesday.

Assessment Practice

Question 16.
Which shows breaking 622 + 247 apart by place value to find the sum?
A. 600 + 200; 22 + 40; 2 + 7
B. 600 + 300; 20 + 40; 2 + 7
C. 600 + 200; 20 + 40; 2 + 7
D. 600 + 200; 20 + 47; 2 + 7
Answer: A. 600 + 200; 22 + 40; 2 + 7

Question 17.
Break 331 + 516 apart by place value. Find the sum.
A. 848
B. 847
C. 748
D. 488
Answer:
331 + 516 = 847
Thus the correct answer is option B.

Lesson 9.2 Use Regrouping to Add

Activity

Solve & Share

Suppose a bus travels 276 miles on Monday and 248 miles on Tuesday. How many miles does the bus travel?

You can use appropriate tools, such as place-value blocks, to add larger numbers. What other strategies can you use to solve
this problem?
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 9.1

Look Back! On Wednesday, the bus gets stuck in traffic. It travels 8 miles each hour for 8 hours. The bus needs to travel 600 miles total from Monday to Wednesday to make it to its destination. Does the bus make it to its destination? Why would it be a good idea to estimate first before you solve this problem?

Visual Learning Bridge

Essential Question
How Can You Use Regrouping to Solve Addition Problems?

You know one way to record partial sums.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 15.1
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 15.2

A.
Jason’s family drove from Ocala, Florida to Miami. They drove 139 miles in the morning and 187 miles in the afternoon. How far did Jason’s family drive? Find 139 + 187. ?
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 15.3
Estimate: 139 + 187 is about 100 + 200, or 300 miles.
Jason’s family drove 326 miles. 300 is close to 326, so the sum is reasonable.

B.
Here is another way. Write the partial sums.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 15.4
Regroup the ones. 16 ones = 1 ten + 6 ones
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 15.5
Regroup the tens. 12 tens = 1 hundred + 2 tens
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 15.6

When you regroup, you name a whole number in a different way.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 15.7

139 + 187 = 326
Jason’s family drove 326 miles.

Convince Me!
Model with Math Show how to use place-value blocks to find 128 +235 using regrouping.

Another Example!

Find 154 + 163.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 16.1

You can find partial sums. Then you can regroup place values to find the final sum.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 16.2
Regroup the tens.
1 hundred + 1 ten = 11 tens
154 + 163 = 317

Guided Practice

Do You Understand?

Question 1.
When you add 3-digit numbers, how do you know if you need to regroup?
Answer: When you add 3-digit numbers if the sum of the place value is greater than 9 then we can know we have to regroup the addend.

Question 2.
To add 546 + 327, would you need to regroup? Explain.
Answer:
546 + 327
7 + 6 = 13, yes we need to regroup
546 + 327 = 873

Do You Know How?

In 3 and 4, estimate by rounding. Then find each sum. Use place-value blocks or drawings to help.

Question 3.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 17.1
Answer:
Envision-Math-Common-Core-Grade-3-Answer-Key-Topic-9-Fluently-Add-and-Subtract-within-1000-17.1

Question 4.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 17.2
Answer:
Envision-Math-Common-Core-Grade-3-Answer-Key-Topic-9-Fluently-Add-and-Subtract-within-1000-17.2

Independent Practice

In 5-12, estimate and then find each sum.

Question 5.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 17.3
Answer:
The estimated number of 136 is 100.
The estimated number of 252 is 300.
The sum of 100 and 300 is 400.
Envision-Math-Common-Core-Grade-3-Answer-Key-Topic-9-Fluently-Add-and-Subtract-within-1000-17.3

Question 6.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 17.4
Answer:
The estimated number of 678 is 700.
The estimated number of 129 is 100.
The sum of 700 and 100 is 800.
Envision-Math-Common-Core-Grade-3-Answer-Key-Topic-9-Fluently-Add-and-Subtract-within-1000-17.4

Question 7.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 17.5
Answer:
The estimated number of 564 is 600.
The estimated number of 283 is 300.
The sum of 600 and 300 is 900.
Envision-Math-Common-Core-Grade-3-Answer-Key-Topic-9-Fluently-Add-and-Subtract-within-1000-17.5

Question 8.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 17.6
Answer:
The estimated number of 118 is 100.
The estimated number of 335 is 300.
The sum of 100 and 300 is 400.
Envision-Math-Common-Core-Grade-3-Answer-Key-Topic-9-Fluently-Add-and-Subtract-within-1000-17.6

Question 9.
172 + 534
Answer:
The estimated number of 172 is 200.
The estimated number of 534 is 500.
The sum of 200 and 500 is 700.

Question 10.
324 + 508
Answer:
The estimated number of 324 is 300.
The estimated number of 508 is 500.
The sum of 300 and 500 is 800.

Question 11.
582 + 230
Answer:
The estimated number of 582 is 600.
The estimated number of 230 is 200.
The sum of 600 and 200 is 800.

Question 12.
207 + 238
Answer:
The estimated number of 207 is 200.
The estimated number of 238 is 200.
The sum of 200 and 200 is 400.

Problem Solving

In 13 and 14, use the table at the right.

Question 13.
How many soup can labels did Grades 1 and 2 collect? Estimate by rounding to the nearest hundred. Then solve. Write an equation that represents the problem.
Envision Math Common Core Grade 3 Answer Key Topic 9 Fluently Add and Subtract within 1,000 20.1
Answer:
Estimate: 400 + 300 = 700
385 + 294 = 679, grade 1 and 2 collected 679 labels.

Question 14.
Make Sense and Persevere Is your answer to Exercise 13 reasonable? Explain.
Answer: Yes, 679 is close to my estimate of 700, so 679 is a reasonable answer.

Question 15.
Number Sense The roller coaster Kingda Ka is 192 feet taller than the first Ferris wheel. Use the symbols < and > to compare the heights of the two rides in two different ways.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 20.2

Answer: 264 feet < 456 feet; 456 feet > 264 feet

Question 16.
Higher Order Thinking Pete can run 178 yards in one minute. Sharon can run 119 more yards than Pete in one minute. How many yards can they both run in one minute?
Answer:
Given,
Pete can run 178 yards in one minute.
Sharon can run 119 more yards than Pete in one minute.
178 + 119 = 297 yards
178 + 297 = 475 yards

Question 17.
Abi practiced her flute for 215 minutes last week and 178 minutes this week. How many minutes has Abi practiced?
Answer:
Given,
Abi practiced her flute for 215 minutes last week and 178 minutes this week.
215 + 178 = 393
Thus Abi practiced 393 minutes.

Assessment Practice

Question 18.
What is 126 + 229?
A. 355
B. 345
C. 255
D. 245
Answer: 355
The sum of 126 and 229 is 355.
Thus the correct answer is option A.

Question 19.
What is the value of the unknown in 248 + Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 25 = 521?
A. 248
B. 263
C. 273
D. 283
Answer: 273
Let the missing number be x.
248 + x = 521
x = 521 – 248
x = 273
Thus the correct answer is option C.

Lesson 9.3 Add 3 or More Numbers

Activity

Solve & Share

A pet store has 162 goldfish, 124 angelfish, and 6 bowls with 9 pufferfish in each. How many fish are there in all?

You can generalize. Use what you know about adding two numbers to add three numbers.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 26.1

Look Back! How can you decide if your answer is reasonable?

Visual Learning Bridge

Essential Question
How Can You Add More Than Two Numbers?

A.
Different kinds of birds are for sale at a pet store. How many birds are for sale?
Find 137 + 155 + 18.
Round to the nearest ten to estimate: 140 + 160 + 20 = 320.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 26.2

B.
One Way
Use partial sums.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 26.4
In all, 310 birds are for sale.

C.
Another Way
Use column addition.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 26.5
The answer is reasonable because 310 is close to the estimate of 320.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 26.6
In all, 310 birds are for sale.

Convince Me!
Model with Math For the partial sums above, Billy said, “20 plus 90 is 110. 110 plus 200 equals 310.” Is Billy correct? Use models, properties, or equations to represent and explain your thinking.

Guided Practice

Do You Understand?

In 1 and 2, look at the example on the previous page.

Question 1.
If you add the numbers in this order, do you get the same sum? Explain why or why not.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 31.1
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-31.1

Question 2.
Why is the 20 crossed out in the column addition problem?
Answer: 5 + 7 + 8 = 20

Do You Know How?

In 3 and 4, estimate and then find each sum.

Question 3.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 31.2
Answer:
The number 123 round to the nearest ten is 120.
The number 168 round to the nearest ten is 170.
The number 36 round to the nearest ten is 40.
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-31.2
Thus the estimated sum is 330.

Question 4.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 31.3
Answer:
The number 247 round to the nearest ten is 250.
The number 362 round to the nearest ten is 360.
The number 149 round to the nearest ten is 150.
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-31.3
Thus the estimated sum is 760.

You can use partial sums or column addition to add.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 31.4

Independent Practice

Leveled Practice In 5-15, estimate and then find each sum.

Question 5.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 31.6
Answer:
The number 64 round to the nearest ten is 60.
The number 42 round to the nearest ten is 40.
The number 88 round to the nearest ten is 90.
60 + 40 + 90 = 190
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-31.6
Thus the estimated sum is 190.

Question 6.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 31.7
Answer:
The number 354 round to the nearest ten is 350.
The number 85 round to the nearest ten is 90.
The number 72 round to the nearest ten is 70.
350 + 90 + 70 = 510
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-31.7
Thus the estimated sum is 510.

Question 7.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 31.8
Answer:
The number 307 round to the nearest ten is 310.
The number 37 round to the nearest ten is 40.
The number 234 round to the nearest ten is 230.
310 + 40 + 230 = 580
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-31.8
Thus the estimated sum is 580.

Question 8.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 31.9
Answer:
The number 714 round to the nearest ten is 710.
The number 163 round to the nearest ten is 160.
The number 99 round to the nearest ten is 100.
710 + 160 + 100 = 970
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-31.9
Thus the estimated sum of the above numbers is 970

Question 9.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 40.1
Answer:
The number 602 round to the nearest ten is 600.
The number 125 round to the nearest ten is 130.
The number 231 round to the nearest ten is 230.
600 + 130 + 230 = 960
Thus the estimated sum of the above numbers is 960.
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-40.1

Question 10.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 40.2
Answer:
The number 64 round to the nearest ten is 60.
The number 42 round to the nearest ten is 40.
The number 88 round to the nearest ten is 90.

Question 11.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 40.3
Answer:
The number 64 round to the nearest ten is 60.
The number 42 round to the nearest ten is 40.
The number 88 round to the nearest ten is 90.

Question 12.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 40.4
Answer:
The number 125 round to the nearest ten is 130.
The number 35 round to the nearest ten is 40.
The number 124 round to the nearest ten is 120.
The number 239 round to the nearest ten is 240.
130 + 40 + 120 + 240 = 530
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-40.4
So, the sum of 125, 35, 124, 239 is 523.

Question 13.
32 + 9 + 56 +8
Answer:
When we add 32 + 9 + 56 +8 we get 105.
The number 105 round to the nearest hundred is 100.
Thus the estimated sum is 100.

Question 14.
481 + 78 + 42
Answer:
When we add 481 + 78 + 42 we get 601.
The number 601 round to the nearest hundred is 600.
Thus the estimated sum is 600.

Question 15.
398 + 219 + 23 + 251
Answer:
When we add 398 + 219 + 23 + 251 we get 891.
The number 891 round to the nearest hundred is 900.
Thus the estimated sum is 900.

Problem Solving

Question 16.
Use the picture at the right to find the height of President Washington’s head carved in Mt. Rushmore. Write an equation to solve the problem.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.1
Answer:
Add all the numbers to find the height of President Washington’s head carved in Mt. Rushmore.
228 + 252 + 240 = 720 inches

Question 17.
Algebra Jada spends $74 on a hat, shoes, and shorts. If the hat costs $22 and the shoes cost $33, how much were the shorts? Write and solve an equation. Use an unknown to represent the cost of the shorts.
Answer:
Given,
Jada spends $74 on a hat, shoes, and shorts.
The hat costs $22 and the shoes cost $33
22 + 33 + x = 74
55 + x = 74
x = 74 – 55
x = 19
Thus the cost of shorts is $19.

Question 18.
Higher Order Thinking Meg says 95 + 76 + 86 is greater than 300, but less than 400. Is Meg correct? Why or why not?
Answer:
No Meg is not correct.
95 + 76 + 86 = 257
So, 257 is smaller than 300.
By this we can say that Meg is wrong.

Question 19.
Reasoning Karin had cereal, a glass of milk, and a banana for breakfast. How many calories were in her meal? Round to the nearest ten to estimate and then solve. Write an equation that includes your solution.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.4
Answer:
Given,
Karin had cereal, a glass of milk, and a banana for breakfast.
105 round to the nearest ten is 100.
110 round to the nearest ten is 110.
150 round to the nearest ten is 150.
Now add the numbers 100 + 110 + 150 = 360
Thus the equation is 100 + 110 + 150 = 360

Assessment Practice

Question 20.
Use place value, partial sums, or properties of operations to find each sum.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.5
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-52.5

Question 21.
Use place value, column addition, or of operations to find each sum.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.6
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-52.6

Lesson 9.4 Use Partial Differences to Subtract

Activity

Solve & Share

Find the difference of 534 – 108. Think about how place value can help you subtract.

You can use structure. How could you use place value to help solve the problem?
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.7

Look Back! Jim had 388 marbles. He gave 8 marbles to each of 7 friends. How many marbles does Jim have left? How can place value help you to subtract 3-digit numbers?

Visual Learning Bridge

Essential Question
How Can You Use Partial Differences to Subtract?

A.
At the end of the fourth round of a game of Digit Derby, Marco’s score was 462 points. During the fifth round of the game, Marco loses points. What is Marco’s score at the end of the fifth round? Find 462 – 181.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.8
Estimate first.
462 – 181 = ?
500 – 200 = 300
Place value can help you break a subtraction problem into smaller problems.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.9

B.
What You Think
Use place value to subtract.
Count back by hundreds, tens, and ones.
181 = 100 + 80 + 1
Start at 462. Count back 100 to 362.
Count back 80 to 282
Break apart 80 into 60 and 20.
Count back 1 to 281.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.10

C.
What You Write
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 52.11
At the end of the fifth round, Marco’s score is 281 points.
The score is close to the estimate.
The difference is reasonable.

Convince Me!
Be Precise Why was 80 broken into 60 and 20 in the computation above?

Guided Practice

Do You Understand?

Question 1.
Why do you need to record the numbers you subtract at each step?
Answer:
To keep track of where you are in an equation, and to allow you to retrace your steps if you happen to do something wrong.

Question 2.
Ana is trying to find 634 – 210. She decides to start by subtracting 10 from 634. Do you agree with Ana? Explain.
Answer:

Do You Know How?

In 3 and 4, estimate and then use partial differences to subtract. Use open number lines to help.

Question 3.
Find 374 – 236.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 55.1
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-55.1

Question 4.
Find 369 – 175.
Envision Math Common Core 3rd Grade Answers Topic 9 Fluently Add and Subtract within 1,000 55.2
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-55.2

Independent Practice

In 5-10, estimate and then use partial differences to subtract. Use open number lines to help.

Question 5.
738 – 523
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 55.3
Answer: 215

Question 6.
755 – 315
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 55.4
Answer: 440

Question 7.
336 – 217
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 55.5
Answer: 119

Question 8.
455 –   182
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 55.6
Answer: 273

Question 9.
865 – 506
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 55.7
Answer: 359

Question 10.
794 – 355
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 55.8
Answer: 439

Problem Solving

Question 11.
Don’s book has 316 pages. He read 50 pages last week. He read another 71 pages this week. How many more pages does Don have left to read?
Answer:
total number of pages in Don’s book = 316
Don’s read pages in last week = 50
Don’s read pages in this week = 71
Don have to left to read pages = 316 – 50 + 71 = 195

Question 12.
Vocabulary Explain why it is necessary to regroup when adding 172 + 264.
Answer:
264
172
436
Regrouping is used when the addition of two numbers is greater than 9.
Here 7 + 6 = 13
13 > 10
So, regrouping is necessary here.
Therefore regrouping is necessary when adding 172 + 264

Question 13.
Use Structure Beth had a necklace with 128 beads. The string broke, and she lost 49 beads. How many beads does Beth have left? Explain how you can break the problem into smaller problems to solve.
Answer:
Beth had a necklace with beads = 128
The string broke and she lost beads =49
Beads left with Beth = 128 – 49 = 79

Question 14.
Write the time shown on the clock in two different ways.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 60.1
Answer:
9: 15
21 : 15

Question 15.
Higher Order Thinking Which weighs more, two Basset Hounds or one Great Dane? Show the difference in pounds between two Basset Hounds and a Great Dane. Draw bar diagrams to represent and help solve the problem.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 60.3
Answer:
The weight of two basset hounds = 66 + 66 = 132pounds
The weight of one great dane = 145  pounds
The weight of one grate dane is greater than two basset hounds.

Assessment Practice

Question 16.
Which have a difference of 181? Use place value and partial differences to solve. Select all that apply.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 61 428 – 247 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 61 562 – 381 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 61 498 – 307 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 61 875 – 696 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 61 946 – 765 = ?
Answer:
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-62428 – 247 = 181
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-62562 – 381 = 181
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-61498 – 307 = 191
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-61875 – 696 = 179
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-62946 – 765 = 181

Question 17.
Which have a difference of 237? Select all that apply.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 62 877 – 640 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 62 412 – 176 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 62 652 – 415 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 62 700 – 459 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 62 802 – 565 = ?
Answer:
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-62 877 – 640 = 237
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-61412 – 176 = 236
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-62 652 – 415 = 237
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-61700 – 459 = 241
Envision-Math-Common-Core-Grade-3-Answers-Topic-9-Fluently-Add-and-Subtract-within-1000-62 802 – 565 = 237

Lesson 9.5 Use Regrouping to Subtract

Activity

Solve & Share

Last year, there were 347 houses for sale in Mill County and 289 houses for sale in Hunter County. Of the houses for sale in both counties, 162 were sold. How many houses were not sold? Solve this problem two different ways.

You can generalize when you subtract 3-digit numbers. Think about all the strategies you can use.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 63.1

Look Back! How are your solution strategies alike and how are they different?

Visual Learning Bridge

Essential Question

How Can You Use Regrouping to Solve Subtraction Problems?

Glossary

A.
Mike and Linda play a game. Linda has 528 points. Mike has 349 points. How many more points does Linda have than Mike? Find 528 – 349.
Estimate:
528 – 349 = ?
530 – 350 = 180
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 63.2

B.
Draw place-value blocks to show 528.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 63.3

C. Subtract 9 ones.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 63.33
Regroup 1 ten as 10 ones.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 63.5
You can use place value to regroup when subtracting.

Subtract 4 tens. 528
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 63.6
Regroup 1 hundred as 10 tens.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 63.7

Subtract 3 hundreds.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 63.8
179 is close to the estimate.

Convince Me!
Use Appropriate Tools How could you use a tool to find 326 – 143?

Guided Practice

Do You Understand?

Question 1.
In the example on the previous page, explain how to decide if regrouping is necessary
Answer:

Question 2.
What strategies could you use to find 507 – 348?
Answer:
using the mental math
500 + 7 – 300 + 40 + 8
500 + 7 – 300 + 48
200 +7 -48  = 159
Do You Know How?

In 3 and 4, estimate each difference and then use partial differences to subtract.

Question 3.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 67.1
Answer:
estimated difference
370
–  180
190  

Question 4.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 67.2
Answer:
estimated difference
860
– 220 
   640 

Independent Practice

In 5-12, estimate each difference and then use partial differences to subtract.

Question 5.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 67.3
Answer:
estimated difference
430
-140
   290 

Question 6.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 67.4
Answer:
estimated difference
280
–  100 
   180 

Question 7.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 67.5
Answer:
estimated difference
520
–  400 
   120  

Question 8.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 67.6
Answer:
estimated difference
530
–  240 
   290   

Question 9.
574 – 86
Answer:
estimated difference
570 – 90 = 480

Question 10.
629 – 453
Answer:
estimated difference
630 – 450 = 180

Question 11.
979 – 569
Answer:
estimated difference
980 – 570 = 410

Question 12.
764 – 237
Answer:
estimated difference
760 – 240 = 520

Problem Solving

Question 13.
At the end of their game, Lora had 426 points and Theo had 158 points. How many more points did Lora have than Theo?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 68.1
Answer: 268
Given
Lora had 426 points and Theo had 158 points
to find How many more points did Lora have than Theo
hence 426 subtract with 158 we get 268

Question 14.
Model with Math Zac and Malcolm each wrote short stories. Zac’s story is 272 lines long. Malcolm’s story is 145 lines longer than Zac’s. How long is Malcolm’s story? Explain how you can model with math to solve this problem.
Answer:
Given,
Zac and Malcolm each wrote short stories. Zac’s story is 272 lines long.
Malcolm’s story is 145 lines longer than Zac’s.
272 + 145 = 417
Therefore, Malcolm wrote 417 lines long.

Question 15.
The world’s largest basket is 186 feet tall from the base to the top of the handles. What is the height of the handles?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 68.2
Answer: 83 feet
given
The world’s largest basket is 186 feet tall from the base to the top of the handles.
base to basket 103 feets
to find the height of the handles
hence 186 feet subtract with 103 feet we get 83 feet

Question 16.
Higher Order Thinking How many more swimmers signed up for the 1st session at Oak Pool than the 1st and 2nd sessions at Park Pool combined? Write an equation that represents the problem and includes the solution.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 68.3
Answer:
given data
we have to find How many more swimmers signed up for the 1st session at Oak Pool than the 1st and 2nd sessions at Park Pool combined
hence oak pool 1st session 763 subtract with 2nd session 586 we get 177
oak pool 1st session 314 subtract with 2nd session 179 we get  135
oak pool 1st session 256 subtract with 2nd session 163 we get  93

Assessment Practice

Question 17.
Which shows the estimate of 627 – 441 by rounding to the nearest ten, and then the correct difference?
A. 200; 186
B. 200; 176
C. 190; 186
D. 190; 176
Answer: C
estimate of 627 – 441 we get 186
estimated 630 – 440 we get 190

Question 18.
Which shows the estimate of 901 – 512 by rounding to the nearest ten, and then the correct difference?
A. 390; 389
B. 390; 379
C. 400; 389
D. 400; 379
Answer: A
estimate of 901 – 512 we get 389
estimated 900 – 510 we get 390

Lesson 9.6 Use Strategies to Add and Subtract

Activity

Solve & Share

Rick is allowed to receive 1,000 text messages each month. How many more text messages can Rick receive this month? Solve any way you choose. Explain how you found the answer.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 68.11
Use reasoning. First think about the operations you should use.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 68.22
Look Back! Is your answer reasonable? How can you check?

Visual Learning Bridge

Essential Question How Can You Use Strategies to Add and Subtract?

A.
There are 136 fewer cell phone towers in Jurloe County than in Fraser County. How many cell phone towers are there in Jurloe County? Choose a strategy, and then solve.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 70.1
402 is about 400.
136 is about 100.
The difference is about 300.

You can use addition or subtraction to solve.
402 = ? + 136
402 – 136 = ?
Addition and subtraction are inverse operations.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 70.33
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 70.3

B.
One Way Use the adding on strategy.
Find 402 = ? + 136.
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 70.4
There are 266 cell phone towers in Jurloe County.

C.
Another Way
The answer is reasonable because it is close to the estimate of 300.
Use partial differences to subtract.
The answer is reasonable because it differences to is close to the estimate of 300.
Find 402 – 136 = ?
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 75.1
Envision Math Common Core Grade 3 Answers Topic 9 Fluently Add and Subtract within 1,000 75.2
There are 266 cell phone towers in Jurloe County.

Convince Me! Use Appropriate Tools Show how to use a tool (such as a number line or place-value blocks) to solve the problem above.

Another Example!
The Yellowstone River is 692 miles long. It is 51 miles shorter than the Kansas River. How long is the Kansas River? Choose a strategy, and then solve. Find 692 + 51 = ?
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.3
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.4
The Kansas River is 743 miles long.

Guided Practice

Do You Understand?

Question 1.
To subtract 507 – 348, how can you regroup the tens if there are 0 tens?
Answer:
Subtract the ones.
7 ones > 8 ones
Since there are no tens in 507, regroup the hundreds.
5 hundreds and 0 tens = 4 hundreds 10 tens
Regroup the tens
10 tens and 7 ones = 9 tens and 17 ones
Subtract the ones, tens and then the hundreds.
So, 507 – 348 = 159

Question 2.
How is using partial sums to add like using place-value blocks and regrouping?
Answer: Thinking of the place value of digits in the numbers, Finding partial sums by adding parts of numbers according to their place value, and • Adding partial sums together to get a total.

Do You Know How?

In 3-6, estimate and then find each sum or difference.

Question 3.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.6
Answer:
816 subtract with 335 we get 481
estimated 820 subtract with 340 we get 480

Question 4.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.7
Answer:
163 add with 50 we get 213
estimated 160 add with 50 we get 210

Question 5.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.8
Answer:
900 subtract with 375 we get 535
estimated 900 subtract with 370 we get 530

Question 6.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.9
Answer:
508 subtract with 247we get 261
estimated 510 subtract with 250 we get 260

Independent Practice

In 7-14, find each sum or difference. Then use estimation to check your answer.

Question 7.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.10
Answer:
549 subtract with 167 we get 382
estimated 550 subtract with 170 we get 380

Question 8.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.11
Answer:
411 subtract with 238 we get 173
estimated 410 subtract with 240 we get 170

Question 9.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.12
Answer:
560 add with 144 we get 704
estimated 560 add with 140 we get 700

Question 10.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 75.13
Answer:
783 add with 68 we get 851
estimated 780 add with 70 we get 850

Question 11.
400 – 219
Answer:
400 subtract with 219 we get 619
estimated 400 subtract with 220 we get 620

Question 12.
904 – 703
Answer:
904 subtract with 703 we get 201
estimated 900 subtract with 700 we get 200

Question 13.
700 + 64
Answer:
700 add with 64 we get 764
estimated 700 add with 60 we get 760

Question 14.
807 + 38
Answer:
807 add with 38 we get 845
estimated 800 add with 40 we get 840

Problem Solving

Question 15.
How much more money does the Elm School Art Club need to raise? Complete the bar diagram and solve the problem.
Elm School
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 78.1
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 78.2
Answer:
By seeing the above figure we can find the amount of money to reach the goal.
Envision-Math-Common-Core-3rd-Grade-Answer-Key-Topic-9-Fluently-Add-and-Subtract-within-1000-78.1
$305 – $178 = $127
Therefore, the amount of money to reach goal is $127.

Question 16.
There were some ears of corn for sale at the farmers’ market. Three hundred eighty-eight ears of corn were sold. At the end, there were 212 ears left. How many ears of corn were for sale at the start?
Answer:
Given,
There were some ears of corn for sale at the farmers’ market.
Three hundred eighty-eight ears of corn were sold.
At the end, there were 212 ears left.
388 + 212 = 600
Thus there were 600 ears of corn for sale at the start.

Question 17.
Dina was adding books to the library shelves. She put 117 nonfiction books on the shelves. Then there were 204 nonfiction books. How many nonfiction books were on the shelves before?
Answer:
Given,
Dina was adding books to the library shelves.
She put 117 nonfiction books on the shelves.
Then there were 204 nonfiction books.
204 – 117 = 87
Thus there were 87 on the shelves before.

Question 18.
Construct Arguments The students at Cleveland School are collecting soda can tabs. The goal of each class is to collect 500 tabs. So far, the second graders have collected 315 tabs. The third graders have collected 190 more tabs than the second graders. Have the third graders reached their goal? Construct an argument to explain.
Answer:
Given,
The students at Cleveland School are collecting soda can tabs.
The goal of each class is to collect 500 tabs.
So far, the second graders have collected 315 tabs.
The third graders have collected 190 more tabs than the second graders.
315 + 190 = 505
505 > 500
Yes, the third graders reached their goal.

Question 19.
Higher Order Thinking Dylan had $405 in his savings account and spent $253. Brian had $380 in his savings account and spent $48 less than Dylan. Now who has more money in his savings account? How much more?
Answer:
Given,
Dylan had $405 in his savings account and spent $253.
$405 – $253 = $152
Brian had $380 in his savings account and spent $48 less than Dylan.
$253 – $48 = $205
$380 – $205 = $175
Brian has more money in his savings account.

Assessment Practice

Question 20.
Use a place-value strategy to find the value of the unknown in 426 + ? = 712.
A. 186
B. 216
C. 284
D. 286
Answer: D
by subtracting 712 with 426 we get 286
hence 426+286 = 712

Question 21.
Use the relationship between addition and subtraction to find the value of the unknown in ? +334 = 800.
A. 434
B. 466
C. 534
D. 566
Answer: B
by subtracting 800 with 334 we get 466
hence 466 +334 = 800

Lesson 9.7 Construct Arguments

Activity

Problem Solving

Solve & Share

Use each of the digits 0, 1, 2, 3, 4, and 5 only once. Write the digits in the space below to make two 3-digit addends with the greatest sum. Write the sum of the two addends. How do you know you have made the greatest sum?
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.1

Thinking Habits
Be a good thinker! These questions can help you.
• How can I use numbers, objects, drawings, or actions to justify my argument?
• Am I using numbers and symbols correctly?
• Is my explanation clear and complete?
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.2

Look Back! Construct Arguments Make different 3-digit addends to find the least possible sum. What is the difference between the greatest possible sum and the least possible sum? Construct an argument to explain how you know that your answer is correct.

Visual Learning Bridge

Essential Question
How Can You Construct Arguments?

A.
Nancy has $457 in her savings account and wants to have $500 by the end of the year. Christopher has $557 in his savings account and wants to have $600 by the end of the year. Who needs to save more money by the end of the year? My conjecture: They both need to save the same amount.

A conjecture is a statement that you think is true. It needs to be proved or disproved.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.3
How can I explain why my conjecture is correct?
I need to construct an argument to justify my conjecture.

Here’s my thinking.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.4

B.
How can I construct an argument?
I can
• use numbers, objects, drawings, or actions correctly to explain my thinking.
• make sure my explanation is simple, complete, and easy to understand.

C.
I will use drawings and numbers to explain my thinking.
The distance from 457 to 500 on the number line is the same as the distance from 557 to 600.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.6
The number lines show that it takes the same amount of money to get from $457 to $500 as it takes to get from $557 to $600.
So, 500 – 457 = 600 – 557. My conjecture is correct.

Convince Me! Construct Arguments Construct another math argument to justify the conjecture above.

Guided Practice

Construct Arguments
Mr. Lee had $375 in the bank. Then he spent $242. Ms. Davis had $675 in the bank, and then spent $542. Who has more money left? Conjecture: They both have the same amount of money left.

Question 1.
Draw a diagram to represent the math.
Diagrams can help you support an argument.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.7
Answer:

Question 2.
Use your diagram to justify the conjecture.
Answer:

Independent Practice

Construct Arguments

A Grade 2 class has made 165 paper cranes and wants to reach a total of 250. A Grade 3 class has made 255 paper cranes and wants to reach a total of 350. Which class has fewer paper cranes left to make to reach its goal?
Conjecture: The Grade 2 class has to make fewer paper cranes to reach its goal.

Question 3.
Draw a diagram at the right to represent the math.
Answer:

Question 4.
Use your diagram to justify the conjecture.
Answer:

Question 5.
Explain another way you could justify the conjecture.
Answer:

Problem Solving

Performance Task

Band Practice
Some musicians set goals for the number of minutes they want to practice before a concert, which is 5 days away. They want to know who has to practice the least number of minutes to reach his or her goal.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.8

Question 6.
Make Sense and Persevere How can you find the number of minutes Aria has to practice to reach her goal?
Answer:

Question 7.
Reasoning So far Dexter and Sawyer have both practiced the same number of minutes. Do they need the same amount of practice time to reach their goals? Explain.
Answer:

When you construct arguments, you explain why your work is right.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.9

Question 8.
Reasoning Who has the least number of minutes left to practice to reach his or her goal?
Answer;

Question 9.
Construct Arguments Construct a math argument to explain why your answer to Exercise 8 is correct.
Answer:

Topic 9 Fluency Practice

Activity

Point&Tally

Find a partner. Get paper and a pencil. Each partner chooses a different color: light blue or dark blue. Partner 1 and Partner 2 each point to a black number at the same time. Both partners add those numbers.
If the answer is on your color, you get a tally mark. Work until one partner has seven tally marks. While playing the game, partners can use subtraction to check their addition.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.11

Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.10

Topic 9 Vocabulary Review

Word List

• conjecture
• estimate
• inverse operations
• place value
• regroup
• round

Understand Vocabulary

Draw a line to match each term to an example.

Question 1.
place value 515 + 141 is about 660.
Answer:
515
+414
656
The actual number is 656.
Here ones place is greater than 5.
So, we have to add 1 to the next ten.
Thus the estimated number of 656 is 660.

Question 2.
estimate 305 + 299 = 604 and 604 – 299 = 305
Answer:
The estimated number of 305 is 300.

Question 3.
regroup 232 = 2 hundreds 3 tens 2 ones
Answer:
Given,
regroup 232 = 2 hundreds 3 tens 2 ones
We can regroup 232 as
1 hundred 13 tens 2 ones

Question 4.
inverse operations 47 = 3 tens 17 ones
Answer:
47 = 3 tens 17 ones
We can regroup 47 as 4 tens 7 ones

Write always, sometimes, or never.

Question 5.
When rounding to the nearest ten, a number with a 5 in the ones digit ___ rounds to the next ten.
Answer: When rounding to the nearest ten, a number with a 5 in the ones digit always rounds to the next ten.

Question 6.
A conjecture is ___ true.
Answer: A conjecture is never true.

Question 7.
A digit with a greater place value is ____ written to the right of a digit with a lesser place value.
Answer: A digit with a greater place value is sometimes written to the right of a digit with a lesser place value.

Question 8.
A ten can ____ be regrouped as 10 hundreds.
Answer: A ten can never be regrouped as 10 hundreds.

Use Vocabulary in Writing

Question 9.
Explain how to find 600 – 281, and then explain how to check that the difference is correct. Use at least 2 terms from the Word List in your explanation.
Answer:
We can find the difference of 600 and 281 by using estimation.
The estimation of 281 is 300.
600 – 300 = 300
Actual difference:
600 – 281 = 319
The nearest hundred to 319 is 300.

Topic 9 Reteaching

Set A
pages 337–340
Find the sum of 257 + 186.
You can break apart 257 + 186 by place value to solve.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.20
Break apart each number by place value and find the sum of the numbers in each place. Then add the sums.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 80.21
So, 257 + 186 = 443.

Remember that you can use place value to add numbers by breaking large addition problems into smaller addition problems.

In 1-5, use place-value blocks or drawings and partial sums to add.

Question 1.
135 + 152
Answer: 287

Question 2.
650 + 138
Answer: 788

Question 3.
535 + 423
Answer: 958

Question 4.
475 + 264
Answer: 739

Question 5.
Yvette took 137 photographs on Friday. She took 248 photographs on Saturday. How many did she take in all?
Answer:
Given,
Yvette took 137 photographs on Friday.
She took 248 photographs on Saturday.
137 + 248 = 385
Thus Yvette takes 385 photographs in all.

Set B
pages 341-344
Find 235 + 187.
Estimate by rounding: 240 + 190 = 430. Use place-value blocks to represent each number and find partial sums. Regroup to find the final sum.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 83.1

Remember that an estimate can help you check whether your answer is reasonable.
In 1-6, estimate and find each sum.

Question 1.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 83.2
Answer:
236 add with 217 we get 453
estimated 240 add with 220 we get 460

Question 2.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 83.3
Answer:
407 add with 436 we get 843
estimated 410 add with 440 we get 850

Question 3.
235 +59
Answer:
235 add with 59 we get 294
estimated 230 add with 60 we get  290

Question 4.
584 + 326
Answer:
584 add with 326  we get 910
estimated 590 add with 230  we get  820

Question 5.
196 + 243
Answer:
196 add with 243 we get 439
estimated 200 add with 240 we get  440

Question 6.
465 + 357
Answer:
465 add with 357 we get 822
estimated 460 add with 360 we get  820

Set C
pages 345–348
Find 124 + 32 + 238.
Estimate by rounding:
120 + 30 + 240 = 390.
You can solve using partial sums.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 85.1
You can solve using column addition.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 85.2
So, 124 + 32 + 238 = 394.

Remember that adding three numbers is like adding two numbers. In 1-7, estimate and then use partial sums to add.

Question 1.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 85.3
Answer:
estimated
210
50
+ 310
570 

Question 2.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 85.4
Answer:
estimated
410
270
+ 140
820

Question 3.
146 +86 + 53
Answer:
estimated
150+90+50 by adding we get 290

Question 4.
125 + 224 + 306
Answer:
by adding 120,220,and 310 we get 650

Question 5.
A flower shop has 124 tulips, 235 roses, and 85 carnations. How many flowers does the flower shop have?
Answer: 444
given
A flower shop has 124 tulips, 235 roses, and 85 carnations
to find How many flowers does the flower shop have
hence by adding 124 tulips, 235 roses, and 85 carnations we get 444

Question 6.
Mike’s Café sells 237 sandwiches on Friday. It sells 448 sandwiches on Saturday and 102 sandwiches on Sunday. How many sandwiches are sold on all 3 days?
Answer:
Given,
Mike’s Café sells 237 sandwiches on Friday.
It sells 448 sandwiches on Saturday and 102 sandwiches on Sunday.
237 + 448 + 102 = 787
Therefore Mike’s cafe sold 787 sandwiches on all 3 days.

Question 7.
Three planes leave an airport. Each plane has 239 seats. The first plane has 224 passengers. The second plane has 189 passengers. The third plane has 122 passengers. How many passengers are on all 3 planes?
Answer:
Given,
Three planes leave an airport.
Each plane has 239 seats. The first plane has 224 passengers. The second plane has 189 passengers. The third plane has 122 passengers.
Add all the number of passengers in 3 planes.
224 + 189 + 122 = 535
Therefore, there are 535 passengers in all 3 planes.

Set D
pages 349-352
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 90.1
So, 548 – 263 = 285.

Remember that place value can help you break a subtraction problem into smaller problems.

In 1-6, find each difference. Estimate and then use place value and partial differences to subtract.

Question 1.
489 – 253
Answer:
489 subtract with 253 we get 236
estimated 490 subtract with 250 we get 240

Question 2.
544 – 162
Answer:
544 subtract with 162 we get 382
estimated 540 subtract with 160  we get 380

Question 3.
856 – 328
Answer:
856 subtract with 328 we get 528
estimated 860 subtract with 330 we get 530

Question 4.
349 – 98
Answer:
349 subtract with 98 we get 251
estimated 350 subtract with 100 we get 250

Question 5.
873 – 184
Answer:
873 subtract with 184 we get 689
estimated 870 subtract with 180 we get 690

Question 6.
526 – 207
Answer:
526 subtract with 207 we get 733
estimated 530 subtract with 210 we get 740

Set E
pages 353-356
Find 416 – 243.
Estimate: 420 – 240 = 180.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 91.2

Remember to regroup if necessary.

In 1-8, estimate each difference. Then find each difference.

Question 1.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 91.3
Answer:
458 subtract with 176 we get 634
estimated 460 subtract with 180 we get 640

Question 2.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 91.4
Answer:
236 subtract with 79 we get 315
estimated 240  subtract with 80 we get 320

Question 3.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 91.5
Answer:
863 subtract with 526 we get 337
estimated 860 subtract with 530 we get 330

Question 4.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 91.6
Answer:
748 subtract with 279 we get 469
estimated 750 subtract with 280 we get 470

Question 5.
400 – 227
Answer:
400 subtract with 227 we get 173
estimated 400 subtract with 230 we get 170

Question 6.
306 – 198
Answer:
306 subtract with 198 we get 108
estimated 310 subtract with 200 we get 110

Question 7.
220 – 187
Answer:
220 subtract with 187 we get 33
estimated 220 subtract with 190 we get 30

Question 8.
657 – 122
Answer:
657 subtract with 122 we get 535
estimated 660 subtract with 120 we get 540

Set F
pages 357-360

Two hundred seventy-three people have finished a marathon. A total of 458 people entered the marathon. How many people are still running?

You can use a bar diagram and addition or subtraction to solve.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 92.8

Remember to regroup when needed.
In 1 and 2, estimate. Then solve.

Question 1.
Damian’s conservation club wants to plant 640 seedlings. They have 172 seedlings that they still need to plant to meet their goal. How many seedlings have they planted so far?
Answer:
Given,
Damian’s conservation club wants to plant 640 seedlings.
They have 172 seedlings that they still need to plant to meet their goal.
640 – 172 = 468
Therefore they have planted 468 seedlings so far.

Question 2.
The Smith family is driving to Dallas. The trip is 450 miles. So far, they have driven 315 miles. How many miles are left in the trip?
Answer:
Given,
The Smith family is driving to Dallas.
The trip is 450 miles. So far, they have driven 315 miles.
450 – 315 = 135
Thus 135 miles are left in the trip.

Set G
pages 361-364

Think about these questions to help you construct arguments.

Thinking Habits
• How can I use numbers, objects, drawings, or actions to justify my argument?
• Am I using numbers and symbols correctly?
• Is my explanation clear and complete?
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 98.2

Remember that a conjecture needs to be proved to be true.
Emma has $191. She spends $105. She donates $52 to charity. Can Emma save $30?
Conjecture: Emma can save $30.

Question 1.
Draw a diagram to represent the math.
Answer:

Question 2.
Use your diagram to justify the conjecture.
Answer:

Topic 9 Assessment Practice

Question 1.
Find the sum of 337 and 285. Use place value and find the sums of the hundreds, tens, and ones.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 98.3
Answer:

Question 2.
An estimate of 431 – 249 using compatible numbers is 425 – 250 = 175. Would it be reasonable for the exact difference to be 182? Explain.
Answer:

Question 3.
Which addends are broken apart correctly? broken apart correctly. Select all that apply.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99 320 + 148
(300 + 100) + (20 + 40) + (20 + 8)
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99 270 + 341
(2 + 70) + (3+ 4+1)
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99 318 + 393
300 + (10 + 90) + (8 + 3)
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99 532 + 360
(500 + 300) + (30 + 60) + 2
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99 526 + 230
(500 + 200) + (20 + 30) + 6
Answer:

Question 4.
Find the sum of 176, 204, and 59.
A. 329
B. 339
C. 429
D. 439
Answer: D
the sum of 176, 204, and 59
176+204+59 we get 439

Question 5.
What is 276 + 289?
A. 509
B. 537
C. 565
D. 593
Answer: C
by adding 276 and 289 we get 565

Question 6.
Find 237 + 20. Then subtract the sum from 302.
Answer:
The sum of 237 + 20 = 257
302 – 257 = 45

Question 7.
Subtract 168 from 300.
A. 32
B. 122
C. 132
D. 142
Answer:
300 – 168 = 132
Thus the correct answer is option C.

Question 8.
A. Is 268 + 37 less than 346? Make a conjecture.
B. Construct an argument to prove your conjecture.
Answer:
305 < 346

Question 9.
What is 825 – 647?
A. 78
B. 82
C. 128
D. 178
Answer:
The subtraction of 825 and 647 is 178.
Thus the correct answer is option D.

Question 10.
Find 335 + 108 + 12. Then subtract the sum from 600.
Answer:
The sum of 335 + 108 + 12 = 455
600 – 455 = 145

Question 11.
Find 283 + 45. Then subtract 139 from the sum. What is the difference?
A. 189
B. 328
C. 377
D. 467
Answer:
283 + 45 = 328
328 – 139 = 189
Thus the correct answer is option A.

Question 12.
Describe how to use place-value blocks to regroup to solve the subtraction problem below. What is the difference?
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99.2
Answer:
3 hundreds 1 tens 6 ones
-2 hundreds 2 tens 6 ones
This can be regrouped as
2 hundreds 11 tens 6 ones
– 2 hundeds 2 tens 6 ones
0 hundreds 9 tens 0 ones
The solution is 90

Question 13.
Find the difference between 254 and 125.
A. If you need to regroup to find the difference, explain how to do it. If you do not need to regroup, explain why not.
B. Find the difference.
Answer: 129

Question 14.
Put the steps in order to find 756 – 345.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99.5
Answer:

Question 15.
What is the difference between 408 + 240 and 259?
Answer:
408 + 240 = 648
648 – 259 = 389

Question 16.
Use place value to subtract 639 from 737. How many times do you have to regroup?
A. 3
B. 2
C. 1
D. 0
Answer: 2

Question 17.
Subtract.
457 – 338
A. 109
B. 119
C. 121
D. 129
Answer:
457 – 338 = 119
Thus the correct answer is option B.

Question 18.
Subtract 246 from 332.
Answer:
332 – 246 = 82

Topic 9 Performance Task

Video Arcade
Nita, Arif, and Sarah have been playing games at the video arcade.
The Tickets Estimates list below shows the number of tickets the friends estimated they would win before they started playing.
The Tickets Won table shows the numbers of tickets each friend won.

Tickets Estimates
• Nita estimated she would win 165 tickets.
• Arif estimated he would win 150 tickets.
• Sarah estimated she would win 175 tickets.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99.10

Question 1.
How many tickets did each of the friends win in all?
Answer:
Tickets won playing sports games by Nita = 96 + 112 = 208
Tickets won playing sports games by Arif = 94 + 91 = 185
Tickets won playing sports games by Sarah= 104 + 117 = 221
208 + 185 + 221 = 614 tickets

Question 2.
Show how many more tickets each friend won than his or her estimate.
Answer:

Question 3.
Arif says if he won 24 more tickets, he would have won more tickets than Nita. Is he correct? Explain.
Answer:
Tickets won playing sports games by Nita = 96 + 112 = 208
Tickets won playing sports games by Arif = 94 + 91 = 185
208 – 185 = 23

Question 4.
The three friends put all of their tickets together. How many tickets did they win in all?
Answer:
Tickets won playing sports games by Nita = 96 + 112 = 208
Tickets won playing sports games by Arif = 94 + 91 = 185
Tickets won playing sports games by Sarah= 104 + 117 = 221
208 + 185 + 221 = 614 tickets

Tickets can be used to buy prizes. The Arcade Prizes table shows how many tickets each prize costs.

Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99.15
Use the Arcade Prizes table to answer Question 5.

Question 5.
Use the total number of tickets you found in Question 4. The 3 friends will use this number of tickets to get 1 prize each and 1 more prize as a gift. Stuffed Animal
There are 2 rules the friends must follow.
• They cannot use more than their total number of tickets.
• After their purchases, they do not want more than 50 tickets remaining.
Part A
Arif starts a prize log to record the prizes they will get. In the table below, record some prizes the friends could choose, the cost of the prize, and show how many tickets they will have left.
Envision Math Common Core 3rd Grade Answer Key Topic 9 Fluently Add and Subtract within 1,000 99.20

Part B
If the friends made your choices from Part A, how many of their tickets would they use to get prizes? Explain how you found the answer.
Answer:

enVision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies

enVision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies

Go through the enVision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies regularly and improve your accuracy in solving questions.

enVision Math Common Core 2nd Grade Answers Key Topic 10 Add Within 1,000 Using Models and Strategies

Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 1
enVision STEM Project: Building Up to 1,000

Find Out Use drinking straws and pieces of tape. The total number of straws and pieces of tape cannot be more than 1,000. First, decide how many of each to use. Then share. Build the tallest buildings you can.
Journal: Make a Book Describe your building in a book. In your book, also:

  • Tell how many drinking straws and pieces of tape you used.
  • Tell how you would make a better building if you did it again.

Review What You Know

Vocabulary

Question 1.
Circle all of the hundreds digits in the numbers below.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 2
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Vocabulary-Question-1
Explanation:
The digit place
Thousands   Hundreds   Tens  Ones
5                0       2
5       8
1              0                0       0
5 and 0 are in the hundreds place and these values are circled.

Question 2.
Write the expanded form of the number.
846
____
Answer:
800 + 40 + 6 is the expanded form of 846.
Explanation:
Given number is a three digit number
8 in Hundreds place
4 in Tens place
6 in Ones place

Question 3.
Write the word form of the number.
265
_____
Answer:
265 = Two hundred and sixty five.
Explanation:
Given number is a three digit number
2 in Hundreds place
6 in Tens place
5 in Ones place

Open Number Lines

Question 4.
Use the open number line to find the sum.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 3
54 + 13 = ___
Answer:
54 + 13 = 67
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Open-Number-Lines-Question-4

Mental Math

Question 5.
Use mental math to find each sum.
40 + 37 = ____
6 + 77 + 4 = ___
Answer:
40 + 37 = 40 + (30 + 7) = (40 + 30) + 7 = 70 + 7 = 77.
6 + 77 + 4 = (6 + 4) + 77 = 10 + 77 = 87.
Explanation:
Mental math we break the number of one addend and then giving park of one addend to the other addend.
Here in 40 + 37
we break 37 as 30 + 7
now we add 40 + 30 =70 + 7 = 77.
This simplify the adding of numbers.
In 2nd Sum
6 + 77 + 4
we add 6 + 4 =10 and then 10 + 77 = 87.

Partial Sums

Question 6.
Use partial sums to add.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.1
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Partial-Sums-Question-6
Explanation:
Using partial sum
we add the place values of the numbers separately.
Hundreds place value + Hundreds place value
Tens place value + Tens place value
Ones place value + Ones place value
Here
46 + 53 = (40+50) + (6 + 3) = 90 + 9 = 99
29 + 61 = (20 + 60) + (9 + 1) = 80 + 10 = 90.

pick a Project

PROJECT 10A
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.2
What are the run times of two of your favorite movies?
Project: Write Movie Reviews

PROJECT 10B
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.3
How many shots do basketball teams block?
Project: Make a Basketball Poster

PROJECT 10C
How many miles are between a State Capital and other cities?
Project: Draw a State Map
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.4

PROJECT 10D
How far can people hike in the Sierra Nevada Mountains?
Project: Create a Hiking Guide
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.5

Lesson 10.1 Add 10 and 100

Solve & Share

Activity

Forest Park Nursery sells trees.
Sal buys a maple tree for $125. A spruce free costs $10 more than a maple tree. An elm tree costs $100 more than a maple tree. What is the cost of a spruce tree? An elm tree?
Use dollar bills, place-value blocks, or mental math to solve. Be ready to explain how you solved the problem.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.6

Visual Learning Bridge
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.7

Convince Me!
Use mental math to find 567 + 10 and 567 + 100. Explain your reasoning.

Guided Practice
Add. Use place-value blocks or mental math.

Question 1.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.8
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Lesson-10.1-Add-10-and-100- Guided-Practice-Question-1

Question 2.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.9
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Lesson-10.1-Add-10-and-100- Guided-Practice-Question-2
Explanation:
The square cube represents 100 square and hundreds place
cube stick represents 10 cubes and tens place
single cube represents 1 cube and ones place.
In the above image
(4 square cube + 1 cube stick + 2 cubes) + 1 cube stick
(400 + 10 + 2) + 10
Adding tens place
10 +10 = 20
the value of the  image = 400+20+2=422.

Question 3.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.10
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Lesson-10.1-Add-10-and-100- Guided-Practice-Question-3
Explanation:
The square cube represents 100 square and hundreds place
cube stick represents 10 cubes and tens place
single cube represents 1 cube and ones place.
In the above image
(3 square cube + 2 square cube) + 1 square cube
(300 + 200) + 100
Adding hundreds place
500 + 100 = 600
the value of the  image = 500 + 100 = 600.

Question 4.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 5.11
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Lesson-10.1-Add-10-and-100- Guided-Practice-Question-4
Explanation:
The square cube represents 100 square and hundreds place
cube stick represents 10 cubes and tens place
single cube represents 1 cube and ones place.
In the above image
(2 square cube + 5 cube stick + 3 cubes) + 1 Square cube
(200 + 50 + 3) + 100
Adding Hundreds place values
200 + 100 = 300
the value of the  image = 400+20+2=422.

Independent Practice
Add. Use place-value blocks or mental math.

Question 5.
164 + 100 =
Answer:
Using mental math
164 + 100
Dividing 164 into smaller parts
= (100 + 64 ) + 100
Now adding hundreds place values
100 + 100 = 200
200 + 64 = 264.
Sum = 264.

Question 6.
$837 + $10 = ___
Answer:
Using mental math
837 + 10
Dividing 837 into smaller parts
(800 + 30 + 7 ) + 10
Adding tens places
30 + 10 = 40
800+40+7 = 847.
Sum = $847.

Question 7.
329 + 100 = ___
Answer:
Using mental math
329 + 100
Dividing 329 into smaller parts
(300+ 20 + 9) + 100
Adding hundreds place
300+ 100 = 400
400+20+9 = 429
Sum = 429.

Question 8.
610 + 10 = ___
Answer:
Dividing 610 into its smaller values
(600 + 10 ) + 10
Adding tens places
10+10 = 20
= 600 + 20 =  620.
Sum = 620.

Question 9.
295 + 10 = ___
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Lesson-10.1-Add-10-and-100-Independent-Practice-Question-9

Question 10.
$497 + $100 = ___
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Lesson-10.1-Add-10-and-100-Independent-Practice-Question-10

Question 11.
790 + 10 = ___
Answer:
Dividing 790 into its smaller values
(700 + 90 ) + 10
Adding tens places
90+10 = 100
= 700 + 100 =  800.
Sum = 800.

Question 12.
693 + 100 = ___
Answer:
Dividing 693 into its smaller values
(600 + 90 + 3 ) + 100
Adding hundreds places
6 + 1 = 7
= 600 + 100 =  700.
= 700 + 90 + 3
= 793
Sum = 793.

Question 13.
900 + 100 = ___
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies-Lesson-10.1-Add-10-and-100-Independent-Practice-Question-13

Question 14.
460 + 10 = ___
Answer:
Dividing 460 into its smaller values
(400 + 60 ) + 10
Adding tens places
6 + 1 = 7
= 60 + 10 =  70.
=400 + 70
= 470
Sum = 470.

Question 15.
185 + 10 = ___
Answer:
Dividing 185 into its smaller values
(100 + 80 + 5 ) + 10
Adding Tens places
8 + 1 = 9
= 80 + 10 =  90.
=100 + 90 + 5
= 195
Sum = 195.

Question 16.
723 + 100 = ___
Answer:
Dividing 723 into its smaller values
(700 + 20 + 3 ) + 100
Adding hundreds places
7 + 1 = 8
= 700 + 100 =  800.
= 800 + 20 + 3
= 823
Sum = 823.

Algebra Find the missing numbers. Use mental math to solve.

Question 17.
572 + Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.1 = 672
Answer:
Given
One addend 572 and
Sum 672
Both are 3-digit number
Hundred  Tens  Ones
5              7        2
6              7        2
The values in the tens place and ones place are same but the values in the hundreds place are different
Subtract the hundreds place values
6 – 5 = 1
600 – 500 = 100.
The missing addend is 100.
572 + 100 = 672.

Question 18.
285 + Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.1 = 385
Answer:
Given
One addend 285 and
Sum 385
Both are 3-digit number
Hundred  Tens  Ones
2              8        5
3              8        5
The values in the tens place and ones place are same but the values in the hundreds place are different
Subtract the hundreds place values
3 – 2 = 1
300 – 200 = 100.
The missing addend is 100.
285 + 100 = 385.

Question 19.
709 = 699 + Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.1
Answer:
Given
One addend 699 and
Sum 709
Both are 3-digit number
Hundred  Tens  Ones
6              9       9
7              0       9
The values in the  ones place are same but the values in the tens and hundreds place are different
Adding 1 to  the tens place values
9 + 1 = 10
Now the value in the tens place is 0 and 1 is carried to the hundreds place
1 is added to hundreds place vale
6 + 1 = 7
10 is the missing number.
699 + 10 = 709.

Question 20.
422 = 322 + Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.1
Answer:
Given
One addend 422 and
Sum 322
Both are 3-digit number
Hundred  Tens  Ones
3             2        2           -Addend
4              2        2           – Sum
The values in the tens place and ones place are same but the values in the hundreds place are different
Subtract the hundreds place values
4 – 3 = 1
400 – 300 = 100.
The missing addend is 100.
322 + 100 = 422.

Question 21.
615 + Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.1 = 625
Answer:
Given
One addend 699 and
Sum 709
Both are 3-digit number
Hundred  Tens  Ones
6              1       5       –   Addend
6              2       5       – Sum
The values in the  ones place and hundreds place are same but the values in the tens are different
subtracting   the tens place values
2 – 1 = 1
Now adding 1 to the addends tens place
1 + 1 = 2
10 is the missing number.
615 + 10 = 625.

Question 22.
600 = Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.1 + 590
Answer:
Given
One addend 590 and
Sum 600
Both are 3-digit number
Hundred  Tens  Ones
5              9       0
6              0        0
The values in the  ones place are same but the values in the tens and hundreds place are different
Adding 1 to  the tens place values of addend
9 + 1 = 10
Now the value in the tens place is 0 and 1 is carried to the hundreds place
1 is added to hundreds place vale
5 + 1 = 6
10 is the missing number.
590 + 10 = 600.

Problem Solving

Solve each problem. Show your work.

Question 23.
enVision® STEM The Science Club asked 178 people about recycling. The club wants to ask a total of 188 people about recycling. How many more people will the Science Club need to ask?
___ more people
Answer:
Number of people The Science Club asked about recycling = 178 people
Total number of people The Science Club wants to ask about recycling = 188 people.
Number of more people  The Science Club need to ask = 188 – 178 = 10.
10 more people.
Th given number is 3 digit number
Hundred place   Tens place   Once place
1                      8                   8
1                      7                   8
The Hundreds place value and ones place values are same. but the tens place value is different
8 – 7 = 1
80 – 70 = 10.
10 more people.

Question 24.
Use Structure Jordan has four $100 bills, three $20 bills, one $10 bill, and seven $1 bills. What will Jordan’s total be if Jayla gives him one more $10 bill? What will his total be if she gives him one more $100 bill?
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.10
Answer:
Number of $100 bills Jordan has = 4
Number of $20 bills Jordan has = 3
Number of $10 bills Jordan has = 1
Number of $1 Jordan has = 7
Number of $10 bills Jayla gave to Jordan = 1
Total money Jordan have after adding Jayla’s $10 bill = $400 + $60 + $10 + $10 + $7 = $487
Jayla gave more $100 bill to Jordan
Total money Jordan have after adding 1 more $100 bill = $487 + $100 = $587.
The value of the hundreds place  = 4
adding 1
4 + 1 = 5.
The value of the hundreds place is 5. The remaining values remain same.
Total money Jordan has = $587.

Question 25.
Higher Order Thinking Think of a 3-digit number. Write a story about adding 100 to your number. Then write an equation to show your solution.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.11
Answer:
A hotel has 250 rooms. Their is an event organized at the hotel the hotel is booked completely. Before the day of event there are 150 rooms filled. How many rooms need to be filled?
Number of room filled = 150
Total number of rooms in the hotel = 250
Number of more rooms to be filled = 250 – 150 = 100 rooms.
100 more rooms need to be filled.
Here the tens and ones place values are same but the Hundreds place value is different.
2 – 1 = 1
The difference in the hundreds place value is 1.
The difference is 100.

Question 26.
Assessment Practice Which equations are true? Choose all that apply.
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.12 $251 + $10 = $351
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.12 528 + 100 = 628
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.12 528 + 10 = 538
Envision Math Common Core Grade 2 Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 6.12 $251 + $100 = $351
Answer:
The Equations that are true are
2. 528 + 100 = 628
Adding the hundreds place values
5 + 1 = 6
Sum = 528 + 100 =  628
3. 528 + 10 = 538
Adding the tens places
2 + 1 = 3
Sum = 528 + 10 = 538.
4. $251 + $100 = $ 351
Adding the hundreds place values
2 + 1 = 3
Sum = $251 + $100 =  $351

Lesson 10.2 Add on an Open Number Line

Activity

Solve & Share

Use the open number line to find 598 + 123. Explain your work.

Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.1

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.2

Convince Me!
Explain how you can use an open number line to find 599 + 205.

Guided Practice
Use an open number line to find each sum.

Question 1.
375 + 118 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.3
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies- Lesson-10.2-Add-on-an-Open-Number-Line- Guided-Practice-Question-1
Explanation:
Here we are breaking the addend into hundreds , tens, ones which does not change its value.
The equation is 375 + 118
118 is the addend
Breaking the addend 118
118 = 100+ 10+5+3
So, adding these to 375
375+100=475
475+10 = 485
485+  5 =   490
490 + 3=  493
375 +118 = 493.

Question 2.
670 + 232 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.4
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies- Lesson-10.2-Add-on-an-Open-Number-Line- Guided-Practice-Question-2

Explanation:
Here we are breaking the addend into hundreds , tens, ones which does not change its value.
The equation is 670 + 232
232 is the addend
Breaking the addend 232
232 = 100+ 100 + 20 + 10 + 2
So, adding these to 670
670 +100 = 770
770 +100 = 870
870 + 20 = 890
890 + 10 = 900
900 + 2 =  902
670 + 232 = 902.

Independent Practice
Use an open number line to find each sum.

Question 3.
269 + 156 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.5
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies- Lesson-10.2-Add-on-an-Open-Number-Line-Independent-Practice-Question-3
Explanation:
Here we are breaking the addend into hundreds , tens, ones which does not change its value.
The equation is 269 + 156
156 is the addend
Breaking the addend 156
156 = 100 + 20 + 20 + 10 + 5 + 1
So, adding these to 269
269 + 100 = 369
369 + 20 = 389
389 + 20 = 409
409 + 10 =  419
419 + 5 = 424
424 + 1 = 425

Question 4.
637 + 242 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.6
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies- Lesson-10.2-Add-on-an-Open-Number-Line-Independent-Practice-Question-4

Explanation:
Here we are breaking the addend into hundreds , tens, ones which does not change its value.
The equation is 637 + 242
242 is the addend
Breaking the addend 242
242 = 100+ 100 + 20 + 20 + 2
So, adding these to 637
637 +100 = 737
737 +100 = 837
837 + 20 = 857
857 + 20 = 877
877 + 2 = 879
637 + 242 = 879.

Question 5.
886 + 114 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.7
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies- Lesson-10.2-Add-on-an-Open-Number-Line-Independent-Practice-Question-5

Explanation:
Here we are breaking the addend into hundreds , tens, ones which does not change its value.
The equation is 886 + 114
114 is the addend
Breaking the addend 114
114 = 100+ 10 + 4
So, adding these to 886
886 +100 = 986
986 +10 = 996
996 + 4 = 1000
886 + 114 = 1000.

Question 6.
208 + 598 =
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.8
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies- Lesson-10.2-Add-on-an-Open-Number-Line-Independent-Practice-Question-6

Explanation:
Here we are breaking the addend into hundreds , tens, ones which does not change its value.
The equation is 208 + 598
598 is the addend
Breaking the addend 598
598 = 100+ 100 + 100 + 100 + 100 + 50 + 40 + 5 + 3
598 = 500 + 50+ 40 + 5 + 3
So, adding these to 208
208 + 100 = 308
308 + 100 = 408
408 + 100 = 508
508 + 100 = 608
608 + 100 = 708
708 + 50 = 758
758 + 40 = 798
798 + 5 = 803
803 + 3 = 806

Question 7.
Higher Order Thinking Lisa finds 550 + 298 using the open number line below. Is her work correct? Explain.
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.9
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.10
Answer:
No, Lisa work is not correct as of addition expression.
The correct way is as below
550 + 298
breaking the addend 298 into hundreds , tens, ones
298 = 100 + 100 + 50 + 40 + 5 + 3 or
298 = 200 + 90 + 8.

Problem Solving
Use an open number line to find each sum.

Question 8.
Reasoning José has 181 cards. He collects 132 more cards. How many cards does he have now?
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.11
Answer:
Envision-Math-Common-Core-2nd-Grade-Answers-Key-Topic-10-Add-Within-1,000-Using-Models-and-Strategies- Lesson-10.2-Add-on-an-Open-Number-Line-Problem-Solving-Question-8

Question 9.
Vocabulary Complete the sentence using two of these terms.
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.12>
Answer:

Question 10.
Higher Order Thinking Use open number lines to find 446 +215 in two different ways.
446 + 215 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 100
Answer:

Question 11.
Assessment Practice Mary uses an open number line to find 286 + 137. All of the jumps she draws are greater than 1. Draw what Mary could have done. Write the sum.
286 + 137 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.13
Answer:

Lesson 10.3 Add Using Models

Solve & Share

Activity

Use place-value blocks to find 243 + 354. Tell which place value you added first and why. Then draw a picture to show your work.
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.14

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 7.15

Convince Me!
Are the tens regrouped in the example above? How do you know?

Guided Practice

Use place-value blocks to find each sum. Regroup if needed.

Question 1.
223 + 106 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.1
Answer:

Question 2.
149 + 362 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.2
Answer:

Independent Practice
Use and draw blocks to find each sum. Regroup if needed.

Question 3.
151 + 324 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.3
Answer:

Question 4.
250 + 298 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.4
Answer:

Question 5.
258 + 109 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.5
Answer:

Question 6.
187 + 246 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.6
Answer:

Question 7.
236 + 318 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.7
Answer:

Question 8.
432 + 365 = ___
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.8
Answer:

Question 9.
Number Sense Jamal says that the sum of 183 + 198 is less than 300. Is Jamal’s answer reasonable? Why or why not?
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.9
Answer:

Problem Solving

Solve the problems below. Show your work.

Question 10.
Reasoning 156 children in a school are girls. 148 children in that school are boys. How many children go to that school?
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.10
___ children
Answer:

Question 11.
Higher Order Thinking Write an addition problem about stickers. Use 3-digit numbers. Then solve the problem.
Envision Math Common Core 2nd Grade Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.11
Answer:

Question 12.
Assessment Practice which is the sum of 129 +268?
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.12
A. 292
B. 294
C. 389
D. 397
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.13
Answer:

Lesson 10.4 Continue to Add Using Models and Place Value

Activity

Solve & Share

Oak School has 256 students. Pine School has 371 students. How many students do the schools have in all?
Use place-value blocks to help. Draw your blocks below and solve.

Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.14

Visual Learning Bridge
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 8.15

Convince Me!
Look at the example above. Why don’t the Il tens need to be regrouped to get the final sum?

Guided Practice
Draw blocks to find the partial sums.
Record the partial sums to find the sum.

Question 1.
236 + 252 = ___
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.1
Answer:

Question 2.
328 + 124 = ___
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.2
Answer:

Independent Practice

Question 3.
372 + 281 = ___
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.3
Answer:

Question 4.
429 + 163 = ___
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.4
Answer:

Question 5.
174 + 245 =
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.5
Answer:

Question 6.
Higher Order Thinking Ben said that the sum of 157 and 137 is 284. Nikki said that Ben made a mistake. Who is correct? Explain.
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.6
Answer:

Problem Solving

Solve each problem below. You can use models to help.

Question 7.
Model On Friday, 354 people went to the fair. On Saturday, 551 people went to the fair.
How many people went to the fair in all?
___ people
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.7
Answer:

Question 8.
Higher Order Thinking Write an addition problem in which the partial sum for tens is greater than 10 tens. Draw blocks and show partial sums to solve.
___ + ___ = ___
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.8
Answer:

Question 9.
Assessment Practice Find 448 + 323. Draw place-value blocks and show partial sums to solve.
448 + 323 = ___
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 9.9
Answer:

Lesson 10.5 Add Using Place Value and Partial Sums

Activity

Solve & Share
On Monday, 248 people visit the museum. On Tuesday, 325 people visit the museum. How many people visit the museum on Monday and Tuesday? Solve any way you choose. Be prepared to explain your thinking.
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.1

Visual Learning Bridge
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.2

Convince Me!
Can the problem above be solved by adding the ones first, then the tens, and then the hundreds ? Explain.

Guided Practice
Add. Use partial sums. Show your work. Use place-value blocks if needed.

Question 1.
425 + 148 = ___
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.3
Answer:

Question 2.
394 + 276 = ___
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.4
Answer:

Independent Practice

Add. Use partial sums. Show your work.

Question 3.
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.5
Answer:

Question 4.
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.6
Answer:

Question 5.
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.7
Answer:

Question 6.
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.8
Answer:

Question 7.
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 10.9
Answer:

Question 8.
Higher Order Thinking Mark found the sum of 127 and 345. Explain his mistake. What is the correct sum?
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 11.1
Answer:

Question 9.
Reasoning Rhea has a $100 bill, four $20 bills, one $10 bill, and three $5 bills. Is this amount greater or less than $210? Explain.
Answer:

Problem Solving
Solve each problem. Show your work.

Question 10.
Look for Patterns 349 people are on a boat. 255 people are on another boat. How many people are on both boats?
Envision Math Common Core Grade 2 Answers Topic 10 Add Within 1,000 Using Models and Strategies 101
___ people
Answer:

Question 11.
163 students are in first grade. 217 students are in second grade. How many students are in both grades?
___ students
Answer:

Question 12.
Higher Order Thinking Choose a number between 100 and 400. Add 384 to your number. What is the sum? Show your work. Explain the steps you took to find the sum.
Answer:

Question 13.
Assessment Practice which is the same amount as 238 + 164? Choose all that apply.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 12.1 200 + 190 + 12
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 12.1 300 + 90 + 12
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 12.1 402
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 12.1 400 + 10 + 2
Answer:

Lesson 10.6 Explain Addition Strategies

Activity

Solve & Share

Find 375 + 235. Explain your strategy. Then explain why your strategy works.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 12.3

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 12.4

Convince Me!
Choose a strategy shown above. Explain why it works.

Guided Practice

Use the strategy to solve the problem. Show your work. Then explain your work.

Question 1.
624 + 248 = 872
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 12.5
Answer:

Independent Practice

Choose any strategy to solve each addition problem. Show your work. Then explain why the strategy works.

Question 2.
212 + 487 = ___
Answer:

Question 3.
874 + 109 = ___
Answer:

Question 4.
419 + 532 = ___
Answer:

Question 5.
650 + 270 = ___
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 12.17
Answer:

Problem Solving

Solve each problem any way you choose. Show your work.

Question 6.
Reasoning Lee School needs 407 folders for its students. Jefferson School needs 321 folders for its students. How many folders do both schools need?
___ folders
Answer:

Question 7.
Reasoning There are 229 people at the football game. 108 more people arrive at the game. How many people are at the football game now?
___ people
Answer:

Question 8.
Higher Order Thinking Tommy found 125 + 598. Since 598 is close to 600, he added 125 + 600 = 725. Then he subtracted 2 to get 723. Why did Tommy subtract 2? Explain.
Answer:

Question 9.
Assessment Practice There are 192 ants on an ant farm. 397 more ants join the ant farm. How many ants are on the ant farm now? Use the number line to solve. Explain.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 13.2
Answer:

Lesson 10.7 Repeated Reasoning

Problem Solving

Activity

Solve & Share

Solve these problems any way you choose. Explain patterns you see.
63 + 28 = ?
263 + 128 = ?

Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 13.3

Thinking Habits
What can I use from one problem to help with another problem? Are there things that repeat?

Visual Learning Bridge
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 13.4

Convince Me!
If you start with 36 and add on 24, in the example above, will you get the same sum? Explain.

Guided Practice
Use repeated reasoning to solve the two problems. Circle the digits that are the same in the sums. Explain why the sums are different.

Question 1.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 13.5
Answer:

Independent Practice

Solve each problem.

Question 2.
Write a problem where you need to regroup to make a ten or a hundred. Each addend must be three digits. Draw place-value blocks to solve your problem. Then explain why you needed to regroup.
___ + ___ = ____
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 14.1
Answer:

Question 3.
Write a problem where you do not need to regroup to make a ten or a hundred. Each addend must be three digits. Draw place value blocks to solve your problem. Then explain why you did not need to regroup.
___ + ___ = ____
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 14.2
Answer:

Problem Solving

Performance Task

Tickets Sold
The table shows how many tickets were sold at a theater. How many tickets were sold on Thursday and Saturday in all?
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 14.4

Question 4.
Make Sense Which numbers and operation can you use to solve the problem?
Answer:

Question 5.
Model Write an equation that shows the problem you need to solve.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 105
Answer:

Question 6.
Generalize Use what you know about adding 3-digit numbers to solve the problem. Explain what you did.
Answer:

Topic 10 Fluency Practice

Point&Tally

Find a partner. Get paper and a pencil. Each partner chooses a different color: light blue or dark blue.
Partner I and Partner 2 each point to a black number at the same time. Both partners subtract Partner 2’s number from Partner l’s number.
If the answer is on your color, you get a tally mark. Work until one partner gets seven tally marks.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 15.1

Topic 10 Vocabulary Review

Understand Vocabulary

Choose a term from the Word List to complete each sentence.

Word List
• addend
• break apart
• digits
• hundreds
• mental math
• open number line
• partial sum
• sum

Question 1.
When adding 193 + 564, the sum of 90 + 60 is called a ___
Answer:

Question 2.
In 709 + 187, 709 is an ___
Answer:

Question 3.
You can use an ___ to count on.
Answer:

Question 4.
In 841, there are ___ hundreds
Answer:

Question 5.
Give the value of each digit in 610.
Answer:

Question 6.
Use mental math to find 198 + 362.
Answer:

Use Vocabulary in Writing

Question 7.
Use words to tell how to find 249 + 201. Use terms from the Word List.
Answer:

Topic 10 Reteaching

Set A
You can use mental math to add 10 or 100 to 362.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 20.1

Add using place-value blocks or mental math.

Question 1.
600 + 10 = ___
Answer:

Question 2.
345 + 100 = ___
Answer:

Question 3.
543 + 100 = ___
Answer:

Question 4.
800 + 100 = ___
Answer:

Question 5.
799 + 10 = ___
Answer:

Question 6.
119 + 10 = ___
Answer:

Set B
You can use an open number line to add. Find 327 + 126.
First, place 327 on the line and then count on by 100s, 10s, and 1s.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 22.11
Use an open number line to find each sum.

Question 7.
594 + 132 = ___
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 22.5
Answer:

Question 8.
157 + 245 = ___
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 22.6
Answer:

Set C
You can use or draw place-value blocks and use partial sums to add. Find 276 + 137.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 30.1

Add. Use partial sums. Show your work. Use drawings of blocks if needed.

Question 9.
408 + 326 = ___
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 30.2
Answer:

Set D

Thinking Habits
Repeated Reasoning
What can I use from one problem to help with another problem? Are there things that repeat?
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 30.3

Solve each problem. Use partial sums and repeated reasoning. Use drawings of blocks if needed.

Question 10.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 40.1
Circle the digits that are alike in each sum.
Answer:

Topic 10 Assessment Practice

Question 1.
Emily has 100 sun stickers. She has 382 star stickers and 10 moon stickers. How many sun and star stickers does Emily have?
Answer:

Question 2.
Tyrone collects baseball cards. He gives 138 cards to his friend. Now he has 428 cards. How many cards did Tyrone have before he gave some away?
___ cards
Answer:

Question 3.
Use the open number line to solve the problem. Write the missing numbers in the boxes.
421 + 250 = ?
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.1
Answer:

Question 4.
Which is the same amount as 528 + 167? Choose all that apply.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.2 500 + 80 + 15
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.2 500 + 180 + 15
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.2 600 + 90 + 5
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.2 600 + 80 + 15
Answer:

Question 5.
Choose all the equations in which the sum is 488.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.2 478 + 10 = ?
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.2 388 + 100 = ?
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.2 248 + 240 = ?
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.2 200 + 265 = ?
Answer:

Question 6.
Rich has 335 pennies. Beth has 58 more pennies than Rich. How many pennies do they have in all?
Hundreds
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 60.20
A. 277
B. 393
C. 628
D. 728
Answer:

Question 7.
Use place value and partial sums to find 472 + 256. Show your work.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 62.1
472 + 256 = ___
Answer:

Question 8.
Molly reads 184 pages. Pat reads 294 pages. What is the total number of pages they read in all?
Use any strategy. Show your work and explain.
Envision Math Common Core 2nd Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 63.0
Answer:

Question 9.
On Saturday, 449 people visit the zoo. On Sunday, 423 people visit the zoo. How many people visit the zoo in all? Use the open number line to solve. Explain your work.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 63.1
Answer:

Topic 10 Performance Task

Recycling Race
Westbrook School is having a recycling contest. The table shows the number of cans each grade collected in February.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 63.2
Answer:

Question 1.
How many cans did the first-grade students and the second-grade students collect in all?
Use the open number line to solve.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 72.1
__ cans
Answer:

Question 2.
Bruce used partial sums to find how many cans the third-grade students and fourth-grade students collected in all.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 72.2
Do you agree with his answer?
Circle yes or no.
Explain your answer.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 72.3
Answer:

Question 3.
Which two grades collected a total of 689 cans? Choose any strategy to solve the problem. Show your work. Explain which strategy you used.

The ___ grade and the ___ grade collected a total of 689 cans.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 80.1
Answer:

Question 4.
The second-grade collected 432 cans in March. They collected 198 cans in April. Tom and Bill find how many cans the class collected in March and April.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 80.2
Who added correctly? Explain.
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 80.3
Who answered incorrectly? What did he do?
Envision Math Common Core 8th Grade Answer Key Topic 10 Add Within 1,000 Using Models and Strategies 80.4
Answer:

enVision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers

Go through the enVision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers regularly and improve your accuracy in solving questions.

enVision Math Common Core 6th Grade Answers Key Topic 1 Use Positive, Rational Numbers

Topic Essential Question How can you fluently add, subtract, multiply, and divide decimals? How can you multiply and divide fractions?
Answer:
The steps to add, subtract, multiply, and divide decimals are:
a. Write the numbers vertically with the decimals lined up (if the number is a whole number then the decimal goes on the right end of the number)
b. Add zeros to make sure there is the same number of digits in each number.
c. Add or subtract as normal.
d. Multiply just as you would if the numbers were all whole numbers and add at the end.
e. After that count how many decimals places the two factors have (start at the far right of each number) and then give the answer that the total number of decimal places.
f. To divide decimals, always use long division.
The process to multiply and divide fractions is:
a. Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction.
b. The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction.
c. Next, multiply the two numerators. Then, multiply the two denominators.

enVision STEM Project

VIDEO

Did You Know?

Engineers design equipment to make you safer.

Engineering is the application of math and science to solve problems.

Engineers solve problems by designing and building products, materials, machinery, structures, transportation vehicles, and so many other things.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 1
Engineers work in nearly every area from chemical and electrical engineering to biomedical and oceanographic engineering.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 1.1
Engineers help keep you healthy.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 1.2
Engineers find ways to improve and enhance performance of all kinds of products.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 1.3

Your Task: Improve Your School

Think like an engineer! Take a walk around the inside and the outside of your school building. Make a list of specific things or areas that need improvement. Then choose one idea and do some background research to gain an understanding of factors that might impact improvement efforts. In the next topic, you and your classmates will learn about and implement the engineering design process to propose possible ways to make the improvements.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 1.4

Topic 1 GET READY!

Review What You Know!

Vocabulary
Choose the best term from the box to complete each definition.

compatible numbers
decimal
divisor
estimate
quotient

Question 1.
Numbers that are easy to compute mentally are ____
Answer:
We know that,
Numbers that are easy to compute mentally are called “Compatible numbers”
Hence, from the above,
We can conclude that the best term to complete the given definition is: Compatible numbers

Question 2.
The number used to be divided is the _____
Answer:
We know that,
The number used to be divided is the “Divisor”
Hence, from the above,
We can conclude that the best term to complete the given definition is: Divisor

Question 3.
A(n) _____ is an approximate answer.
Answer:
We know that,
An “Estimate” is an approximate answer
Hence, from the above,
We can conclude that the best term to complete the given definition is: Estimate

Question 4.
The result of a division problem is a(n) ____
Answer:
We know that,
The result of a division problem is a “Quotient”
Hence, from the above,
We can conclude that the best term to complete the given definition is: Quotient

Whole Number Operations
Calculate each value.

Question 5.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 1.6
Answer:
The given division problem is: 348 ÷ 4
Now,
By using the Long Division method,

Hence, from the above,
We can conclude that
The value of the quotient for the given division problem is: 87

Question 6.
9,007 – 3,128
Answer:
The given subtraction problem is: 9,007 – 3,128
So,
9,007 – 3,128 = 5,879
Hence, from the above,
We can conclude that
The result for the given subtraction problem is: 5,879

Question 7.
35 × 17
Answer:
The given multiplication problem is: 35 × 17
Now,
By using the Partial Products method,
35 × 17
= (30 + 5) × (10 + 7)
= (30 × 10) + (30 × 7) + (5 × 10) + (5 × 7)
= 300 + 210 + 50 + 35
= 595
Hence, from the above,
We can conclude that
The value of product for the given multiplication problem is: 595

Question 8.
7,964 + 3,872
Answer:
The given addition problem is: 7,964 + 3,872
So,
7,964 + 3,872 = 11,836
Hence, from the above,
We can conclude that
The result for the given addition problem is: 11,836

Question 9.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 1.7
Answer:
The given division problem is: 4,638 ÷ 22
Now,
By using the Long Division method,

Hence, from the above,
We can conclude that
The value of quotient for the given division problem is: 210

Question 10.
181 × 42
Answer:
The given multiplication problem is: 181 × 42
Now,
By using the Partial Products method,
181 × 42
= (100 + 80 + 1) × (40 + 2)
= (100 ×40) + (100 × 2) + (80 × 40) + (80 × 2) + (1 × 40) + (1 × 2)
= 4,000 + 200 + 3,200 + 160 + 40 + 2
= 7,602
Hence, from the above,
We can conclude that
The value of the product for the given multiplication problem is: 7,602

Mixed Numbers and Fractions
Write each mixed number as a fraction. Write each fraction as a mixed number.

Question 11.
8\(\frac{1}{3}\)
Answer:
The given mixed number is: 8\(\frac{1}{3}\)
So,
To convert the given mixed number into a fraction,
8\(\frac{1}{3}\)
= \(\frac{3 × 8 + 1}{3}\)
= \(\frac{24 + 1}{3}\)
= \(\frac{25}{3}\)
Hence, from the above,
We can conclude that
The representation of the given mixed number into a fraction is: \(\frac{25}{3}\)

Question 12.
5\(\frac{3}{5}\)
Answer:
The given mixed number is: 5\(\frac{3}{5}\)
So,
To convert the given mixed number into a fraction,
5\(\frac{3}{5}\)
= \(\frac{5 × 5 + 3}{5}\)
= \(\frac{25 + 3}{5}\)
= \(\frac{28}{5}\)
Hence, from the above,
We can conclude that
The representation of the given mixed number into a fraction is: \(\frac{28}{5}\)

Question 13.
2\(\frac{5}{8}\)
Answer:
The given mixed number is: 2\(\frac{5}{8}\)
So,
To convert the given mixed number into a fraction,
2\(\frac{5}{8}\)
= \(\frac{2 × 8 + 5}{8}\)
= \(\frac{16 + 5}{8}\)
= \(\frac{21}{8}\)
Hence, from the above,
We can conclude that
The representation of the given mixed number into a fraction is: \(\frac{21}{8}\)

Question 14.
3\(\frac{4}{9}\)
Answer:
The given mixed number is: 3\(\frac{4}{9}\)
So,
To convert the given mixed number into a fraction,
3\(\frac{4}{9}\)
= \(\frac{3 × 9 + 4}{9}\)
= \(\frac{27 + 4}{9}\)
= \(\frac{31}{9}\)
Hence, from the above,
We can conclude that
The representation of the given mixed number into a fraction is: \(\frac{31}{9}\)

Question 15.
\(\frac{24}{7}\)
Answer:
The given fraction is: \(\frac{24}{7}\)
So,
To convert the given fraction into a mixed number,
Quotient\(\frac{Remainder}{Divisor}\)
So,
\(\frac{24}{7}\) = 3\(\frac{3}{7}\)
Hence, from the above,
We can conclude that
The representation of the given fraction into a mixed number is: 3\(\frac{3}{7}\)

Question 16.
\(\frac{43}{9}\)
Answer:
The given fraction is: \(\frac{43}{9}\)
So,
To convert the given fraction into a mixed number,
Quotient\(\frac{Remainder}{Divisor}\)
So,
\(\frac{43}{9}\) = 4\(\frac{7}{9}\)
Hence, from the above,
We can conclude that
The representation of the given fraction into a mixed number is: 4\(\frac{7}{9}\)

Question 17.
\(\frac{59}{8}\)
Answer:
The given fraction is: \(\frac{59}{8}\)
So,
To convert the given fraction into a mixed number,
Quotient\(\frac{Remainder}{Divisor}\)
So,
\(\frac{59}{8}\) = 7\(\frac{3}{8}\)
Hence, from the above,
We can conclude that
The representation of the given fraction into a mixed number is: 7\(\frac{3}{8}\)

Question 18.
\(\frac{32}{5}\)
Answer:
The given fraction is: \(\frac{32}{5}\)
So,
To convert the given fraction into a mixed number,
Quotient\(\frac{Remainder}{Divisor}\)
So,
\(\frac{32}{5}\) = 6\(\frac{2}{5}\)
Hence, from the above,
We can conclude that
The representation of the given fraction into a mixed number is: 6\(\frac{2}{5}\)

Verbal Expressions

Question 19.
How are the expressions “\(\frac{1}{4}\) of 12″ and “12 divided by 4” related?
Answer:
The given expressions are: \(\frac{1}{4}\) × 12 and 12 ÷ 4
So,
We can write
12 ÷ 4
= \(\frac{12}{4}\)
= 12 × \(\frac{1}{4}\)
Hence,f rom the above,
We can conclude that the given expressions 12 × \(\frac{1}{4}\) and 12 ÷ 4 are the same

Decimals

Question 20.
What decimal does this model represent? Explain.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.1
Answer:
The given model is:
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.1
Now,
From the given model,
We can observe that
The total number of parts are: 100
The number of shaded parts is: 73
So,
The fraction of the shaded part in the given model = \(\frac{Shaded parts}{Total parts}\)
= \(\frac{73}{100}\)
= 0.73
Hence, from the above,
We can conclude that
The decimal number that the given model represents is: 0.73

Language Development

Fill in the boxes with terms and phrases related to Decimals and Fractions from the given bank. Include illustrations or examples.

annex zeroes (1-1)
compatible numbers (1-1)
decimal point (1-1)
estimate (1-1)
hundredths (1-1)
line up place value (1-1)
rounding (1-1)
tenths (1-1)
algorithm (1-2)
the denominator (1-3)
mixed number (1-3)
the numerator (1-3)
unit fraction (1-3)
reciprocal (1-4)
rewrite (1-4)
multistep problems (1-7)

Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.5

Topic 1 PICK A PROJECT

PROJECT 1A
What is the most challenging board game you have ever played?
PROJECT: MAKE YOUR OWN BOARD GAME
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.8

PROJECT 1B
What is your favorite party food?
PROJECT: PLAN THE MENU FOR A SCHOOL FUNDRAISER
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.9

PROJECT 1C
If you planted a garden, what would be in it?
PROJECT: DESIGN A VEGETABLE AND HERB GARDEN
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.10

PROJECT 10D
How much food does a tiger eat?
PROJECT: PRESENT A PROPOSAL FOR A TIGER EXHIBIT
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.11

Lesson 1.1 Fluently Add, Subtract and Multiply Decimals

ACTIVITY

Solve & Discuss It!

Maxine is making a model windmill for a science fair. She is connecting 4 cardboard tubes together vertically. Each tube is 0.28 meters in length. What is the combined measure of the connected tubes?

Use Appropriate Tools You can use decimal grids to calculate with decimals.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.12
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 2.13
Answer:
It is given that
Maxine is making a model windmill for a science fair. She is connecting 4 cardboard tubes together vertically. Each tube is 0.28 meters in length
So,
The combined measure of the connected tubes = (The number of cardboard tubes) × (The length of each tube)
= 4 × 0.28
= 4 × (0.20 + 0.08)
= (4 × 0.20) + (4 × 0.08)
= 0.8 + 0.32
= 1.12 meters
So,
The representation of the length of 4 cardboard tubes in the decimal grid is:

Hence, from the above,
We can conclude that
The combined measure of the 4 connected tubes is: 1.12 meters

Focus on math practices Look for Relationships Suppose that Maxine made another windmill model by connecting 4 cardboard tubes that are each 2.8 meters long. What is the combined measure of this model? What relationships do you see in the factors you used here and above? Explain how this helps you solve the problem.
Answer:
It is given that
Maxine made another windmill model by connecting 4 cardboard tubes that are each 2.8 meters long
So,
The combined measure of another model made by Maxine = (The number of cardboard tubes of another model) × (The length of each tube)
= 4 × 2.8
= 4 × (2 + 0.8)
= (4 × 2) + (4 × 0.8)
= 8 + 3.2
= 11.2 meters
Now,
From the above problem,
We can observe that
The combined measure of 4 connected tubes is: 1.12 meters
So,
When we multiply 1.12 meters by 10,
We will get the combined measure of the other model made by Maxine
Hence, from the above,
We can conclude that
The relationship do you see in the factors you used in this problem and the above problem is:
(The combined measure of 4 connected tubes of the above problem) × 10 = (The combined measure of the 4 connected tubes of this problem)

? Essential Question How can you add, subtract, and multiply with decimals?
Answer:
The steps to add, subtract, multiply, and divide decimals are:
a. Write the numbers vertically with the decimals lined up (if the number is a whole number then the decimal goes on the right end of the number)
b. Add zeros to make sure there is the same number of digits in each number.
c. Add or subtract as normal.
d. Multiply just as you would if the numbers were all whole numbers and add at the end.
e. After that count how many decimals places the two factors have (start at the far right of each number) and then give the answer that the total number of decimal places.
f. To divide decimals, always use long division.

Try It!
Suppose that Martin finished the race 0.47 seconds after Kim. What was Martin’s time in the race? Use an estimate to check that your answer is reasonable.
Answer:
It is given that
Martin finished the race 0.47 seconds after Kim
Now,
We know that,
The time Kim took to complete the race is: 50.9 seconds
So,
The time took by Martin in the race = (The time took by Kim to complete the race) + (The more time taken by Martin to finish the race more than Kim)
= 50.9 + 0.47
= 50.90 + 0.47
= 51.37 seconds
Now,
Estimate:
The time took by Kim to complete the race is: 51 seconds
The more time taken by Martin to finish the race more than Kim is: 0.50 seconds
So,
The time took by Martin to complete the race = (The time took by Kim in the race) + (The more time taken by Martin to finish the race more than Kim)
= 51 + 0.50
= 51.50 seconds
Hence, from the above,
We can conclude that
The time took by Martin in the race is: 51.37 seconds
Since the estimated time and the exact time is near, your answer is reasonable

Convince Me! If Martin finished the race 0.267 seconds after Kim, you would need to add 0.267 to 50.9 to solve the problem. How is adding 0.267 to 50.9 different from adding 0.26 to 50.9?
Answer:
It is given that
If Martin finished the race 0.267 seconds after Kim, you would need to add 0.267 to 50.9 to solve the problem
So,
The time took by Martin in the race = (The time took by Kim in the race) + (The more time taken by Martin to finish the race more than Kim)
= 50.9 + 0.267
= 50.900 + 0.267
= 51.167 seconds ——(1)
So,
The time took by Martin in the race = (The time took by Kim in the race) + (The more time taken by Martin to finish the race more than Kim)
= 50.9 + 0.26
= 50.90 + 0.26
= 51.16 seconds —— (2)
So,
When we compare eq (1) and eq (2),
We can observe that
eq (1) gives the more accurate time when compared to eq (2)
Hence, from the above,
We can conclude that
The difference between the results of eq(1) and eq (2) is the accuracy and precision

Try It!
Suppose that Katie finished the race 0.13 seconds before Amy. What was Katie’s time in the race? Use an estimate to check that your answer is reasonable.
Answer:
It is given that
Katie finished the race 0.13 seconds before Amy
Now,
We know that,
The time Amy took to complete the race is: 20.7 seconds
So,
The time took by Katie in the race = (The time took by Amy to complete the race) – (The time taken by Katie to finish the race before Amy)
= 20.7 – 0.13
= 20.70 – 0.13
= 20.57 seconds
Now,
Estimate:
The time took by Amy to complete the race is: 21 seconds
The time is taken by Katie to finish the race before Amy is: 0.10 seconds
So,
The time took by Katie to complete the race = (The time took by Amy in the race) + (The time taken by Katie to finish the race before Amy)
= 21 – 0.10
= 21.00 – 0.10
= 20.90 seconds
Hence, from the above,
We can conclude that
The time took by Martin in the race is: 20.57 seconds
Since the estimated time and the exact time is near, your answer is reasonable

Try It!
How do you determine where to place the decimal point in the product?
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 3.1
Answer:
We know that,
Decimals are multiplied as if they were whole numbers, and then the decimal point is placed in the product. To find out where the decimal point should be placed, count the number of decimal places after the decimal point in each factor.
Hence,
The representation of the decimal point in the given product is:

KEY CONCEPT
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 3.2

Do You Understand?

Question 1.
? Essential Question How can you add, subtract, and multiply with decimals?
Answer:
The steps to add, subtract, multiply, and divide decimals are:
a. Write the numbers vertically with the decimals lined up (if the number is a whole number then the decimal goes on the right end of the number)
b. Add zeros to make sure there is the same number of digits in each number.
c. Add or subtract as normal.
d. Multiply just as you would if the numbers were all whole numbers and add at the end.
e. After that count how many decimals places the two factors have (start at the far right of each number) and then give the answer that the total number of decimal places.
f. To divide decimals, always use long division.

Question 2.
Generalize How is adding and subtracting decimals similar to and different from adding and subtracting whole numbers?
Answer:
We know that,
Adding and subtracting decimal numbers, numbers with a decimal point is just like adding and subtracting whole numbers.
The only difference is that we line up the numbers according to the decimal point.
For subtraction, the number we are subtracting goes to the bottom.

Question 3.
What can you do if a decimal product has final zeros to the right of the decimal point?
Answer:
We can drop the zeros on the right once the decimal point has been placed in the product. If the number of decimal places is greater than the number of digits in the product, you can insert zeros in front of the product.

Question 4.
Critique Reasoning Diego says that the product of 0.51 × 2.427 will have five decimal places. Is Diego correct? Explain.
Answer:
It is given that
Diego says that the product of 0.51 × 2.427 will have five decimal places
Now,
We know that,
Decimals are multiplied as if they were whole numbers, and then the decimal point is placed in the product. To find out where the decimal point should be placed, count the number of decimal places after the decimal point in each factor.
So,
In
0.51 × 2.427,
We can observe that
There are 2 decimal places in 0.51
There are 3 decimal places in 2.427
So,
In 0.51 × 2,427,
There are 5 decimal places
Hence, from the above,
We can conclude that Diego is correct

Do You Know How?

In 5-10, find each sum or difference.

Question 5.
5.9 + 2.7
Answer:
The given addition problem is: 5.9 + 2.7
So,
By using the Long Addition,

Hence, from the above,
We can conclude that the value of the given addition problem is: 8.6

Question 6.
4.01 – 2.95
Answer:
The given subtraction problem is: 4.01 – 2.95
So,
By using the Long Subtraction,

Hence, from the above,
We can conclude that the value of the given subtraction problem is: 1.06

Question 7.
6.8 – 1.45
Answer:
The given subtraction problem is: 6.8 – 1.45
So,
By using the Long Subtraction,

Hence, from the above,
We can conclude that the value of the given subtraction problem is: 5.35

Question 8.
9.62 – 0.3
Answer:
The given subtraction problem is: 9.62 – 0.3
So,
By using the Long Subtraction,

Hence, from the above,
We can conclude that the value of the given subtraction problem is: 9.32

Question 9.
2.57 + 7.706
Answer:
The given addition problem is: 2.57 + 7.706
So,
By using the Long Addition,

Hence, from the above,
We can conclude that the value of the given addition problem is: 10.276

Question 10.
15 – 6.108
Answer:
The given subtraction problem is: 15 – 6.108
So,
By using the Long Subtraction,

Hence, from the above,
We can conclude that the value of the given subtraction problem is: 8.892

In 11-16, place the decimal point in the correct location in the product.

Question 11.
4 × 0.94 = 376
Answer:

Hence, from the above,
We can conclude that
4 × 0.94 = 3.76

Question 12.
5 × 0.487 = 2435
Answer:

Hence, from the above,
We can conclude that
5 × 0.487 = 2.435

Question 13.
3.4 × 6.8 = 2312
Answer:

Hence, from the above,
We can conclude that
3.4 × 6.8 = 23.12

Question 14.
3.9 × 0.08 = 312
Answer:

Hence, from the above,
We can conclude that
3.9 × 0.08 = 0.312

Question 15.
0.9 × 0.22 = 198
Answer:

Hence, from the above,
We can conclude that
0.9 × 0.22 = 0.198

Question 16.
9 × 1.2 = 108
Answer:

Hence, from the above,
We can conclude that
9 × 1.2 = 10.8

In 17 and 18, find each product.

Question 17.
5.3 × 2.7
Answer:
The given multiplication equation is: 5.3 × 2.7
So,
By using the Long Multiplication method,

Hence, from the above,
We can conclude that
The value of the product for the given multiplication equation is: 14.31

Question 18.
8 × 4.09
Answer:
The given multiplication is: 8 × 4.09
So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The value of the product for the given multiplication equation is: 32.72

Practice & Problem Solving

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In 19-27, find each sum or difference.

Question 19.
2.17 – 0.8
Answer:
The given subtraction equation is: 2.17 – 0.8
So,
By using the Long subtraction,

Hence, from the above,
We can conclude that
2.17 – 0.8 = 1.37

Question 20.
4.3 + 4.16
Answer:
The given addition equation is: 4.3 + 4.16
So,
By using the Long Addition,

Hence, from the above,
We can conclude that
4.3 + 4.16 = 8.46

Question 21.
46.91 – 28.7
Answer:
The given subtraction equation is: 46.91 – 28.7
So,
By using the Long subtraction,

Hence, from the above,
We can conclude that
46.91 – 28.7 = 18.21

Question 22.
4.815 + 2.17
Answer:
The given addition equation is: 4.815 + 2.17
So,
By using the Long Addition,

Hence, from the above,
We can conclude that
4.815 + 2.17 = 6.985

Question 23.
5.1 – 0.48
Answer:
The given subtraction equation is: 5.1 – 0.48
So,
By using the Long subtraction,

Hence, from the above,
We can conclude that
5.1 – 0.48 = 4.62

Question 24.
27 + 0.185
Answer:
The given addition equation is: 27 + 0.185
So,
By using the Long Addition,

Hence, from the above,
We can conclude that
27 + 0.185 = 27.185

Question 25.
9.501 – 9.45
Answer:
The given subtraction equation is: 9.501 – 9.45
So,
By using the Long subtraction,

Hence, from the above,
We can conclude that
9.501 – 9.45 = 0.051

Question 26.
14 + 9.8
Answer:
The given addition equation is: 14 + 9.8
So,
By using the Long Addition,

Hence, from the above,
We can conclude that
14 + 9.8 = 23.8

Question 27.
12.65 + 14.24
Answer:
The given addition equation is: 12.65 + 14.24
So,
By using the Long Addition,

Hence, from the above,
We can conclude that
12.65 + 14.24 = 26.89

In 28-33, find each product.

Question 28.
7 × 0.5
Answer:
The given multiplication equation is: 7 × 0.5
So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
7 × 0.5 = 3.5

Question 29.
12 × 0.08
Answer:
The given multiplication equation is: 12 × 0.08
So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
12 × 0.08 = 0.96

Question 30.
24 × 0.17
Answer:
The given multiplication equation is: 24 × 0.17
So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
24 × 0.17 = 4.08

Question 31.
0.4 × 0.17
Answer:
The given multiplication equation is: 0.4 × 0.17
So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
0.4 × 0.17 = 0.068

Question 32.
1.9 × 0.46
Answer:
The given multiplication is: 1.9 × 0.46
So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
1.9 × 0.46 = 0.874

Question 33.
3.42 × 5.15
Answer:
The given multiplication is: 3.42 × 5.15
So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
3.42 × 5.15 = 17.6130

Question 34.
Write an equation that illustrates the following: A number with two decimal places multiplied by a number with one decimal place. The product has only two nonzero digits.
Answer:
It is given that
A number with two decimal places is multiplied by a number with one decimal place. The product has only two nonzero digits.
Now,
Let the number with two decimal places be: 2.55
Let the number with one decimal be: 1.6
So,
We have to find the product of 2.55 × 1.6
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The multiplication equation with the product value that has only two non-zero digits is: 2.55 × 1.6

Question 35.
The Bright-o Shampoo Factory includes 1.078 ounces of vanilla oil in a 6.35-ounce bottle of shampoo. How much of the bottle of shampoo is NOT vanilla oil?
Answer:
It is given that
The Bright-o Shampoo Factory includes 1.078 ounces of vanilla oil in a 6.35-ounce bottle of shampoo.
So,
The total content present in Bright-o-Shampoo = (The amount of vanilla oil) + (The amount of other content)
Now,
Let the amount of other content be: x
So,
6.35 = 1.078 + x
So,
x = 6.35 – 1.078
Now,
By using the Long Subtraction,

Hence, from the above,
We can conclude that
The amount of the bottle of a shampoo that is not vanilla oil is: 5.272 ounces

In 36-38, use the graph to solve.

Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 5.1

Question 36.
The fastest speed a table tennis ball has been hit is about 13.07 times as fast as the speed for the fastest swimming. What is the speed of the table tennis ball?
Answer:
It is given that
The fastest speed a table tennis ball has been hit is about 13.07 times as fast as the speed for the fastest swimming.
Now,
The given graph is:
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 5.1
Now,
The speed of the table tennis ball = 13.07 × (The speed for the fastest swimming)
= 13.07 × 5.35
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that the speed of the tennis ball is about 70 miles per hour

Question 37.
Look for Relationships How fast would 1.5 times the fastest rowing speed be? Before you solve, tell the number of decimal places in your answer.
Answer:
The given graph is:
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 5.1
Now,
From the given graph,
We can observe that
The fastest rowing speed is: 13.99 miles per hour
So,
The speed of 1.5 times the fastest rowing speed = 1.5 × 13.99
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
1.5 times of the fastest rowing speed is: 209.85 miles per hour

Question 38.
Which activity has a recorded speed about 7 times as fast as the fastest rowing speed?
Answer:
The given graph is:
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 5.1
Now,
From the given graph,
We can observe that
The fastest rowing speed is: 13.99 miles per hour
Now,
7 times of the fastest rowing speed is: 7 × 13.99
Now,
By using the Long Multiplication,

So,
The fastest rowing speed is about: 98 miles per hour
Now,
From the given graph,
We can observe that
The fastest Luge is: 95.69 miles per hour
Hence, from the above,
We can conclude that
“Fastest Luge” has a recorded speed about 7 times as fast as the fastest rowing speed

Question 39.
Matthew a pennant, and a hat. He paid with a $50 bill and some money he borrowed from his friend. If Matthew got $6.01 in change from the cashier, how much did he borrow from his friend to pay for all the items?
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.1
Answer:
It is given that
Matthew a pennant, and a hat. He paid with a $50 bill and some money he borrowed from his friend. If Matthew got $6.01 in change from the cashier
Now,
Let the amount Matthew borrowed from his friend be: x
So,
According to the given information,
The amount Matthew borrowed from his friend = (The amount of bill) – (The amount Matthew got in change from the cashier)
x = $50 – $6.01
Now,
By using the Long Subtraction,

Hence, from the above,
We can conclude that
The amount Matthew borrowed from his friend is: $43.99

Question 40.
Anna’s running time for a race was 23.1 seconds. Another runner’s time was 5.86 seconds faster. Find the other runner’s time.
Answer:
It is given that
Anna’s running time for a race was 23.1 seconds. Another runner’s time was 5.86 seconds faster
So,
The time took by another runner = 5.86 + (Anna’s running time)
= 5.86 + 23.1
Now,
By using the Long Addition,

Hence, from the above,
We can conclude that
The time took by another runner is: 28.96 seconds

Question 41.
Higher-Order Thinking Explain why 0.25 × 0.4 has only one decimal place in the product.
Answer:
The given multiplication equation is: 0.25 × 0.4
Now,
By using the Long Multiplication,

Now,
We know that,
In the decimal numbers,
If there are zeros on the right side, then we can neglect those zeros
So,
0.100 can become 0.1
Hence, from the above,
We can conclude that
0.25 × 0.4 has only one decimal place in the product because of the following property:
In the decimal numbers,
If there are zeros on the right side, then we can neglect those zeros

Question 42.
The wings of some hummingbirds beat 52 times per second when hovering. If a hummingbird hovers for 35.5 seconds, how many times do its wings beat?
Answer:
It is given that
The wings of some hummingbirds beat 52 times per second when hovering and a hummingbird hovers for 35.5 seconds
So,
The number of times the wings of a hummingbird beat in 35.5 seconds = (The time a hummingbird hovers) × (The number of times the wings of a hummingbird beat)
= 35.5 × 52
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The number of times the wings of a hummingbird beat in 35.5 seconds is: 1,846 times

Question 43.
The students at Walden Middle School are selling tins of popcorn to raise money for new uniforms. They sold 42 tins in the first week. How much money did they make in the first week?
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.10
Answer:
It is given that
The students at Walden Middle School are selling tins of popcorn to raise money for new uniforms. They sold 42 tins in the first week
Now,
The given figure is:

So,
The money did the students at Walden Middle School made in the first week = (The number of tins) × (The cost of each tin)
= 42 × $9.25
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The money did the students at Walden Middle School made in the first week is: $388.50

Assessment Practice

Question 44.
Use the information in the table to solve each problem.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.3
PART A
What is the combined length in kilometers of the Bayshore Loop trail and the Rowdy Bend trail?
Answer:
The given information is:
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.3
So,
The combined length of the Bayshore Loop trail and the Rowdy Bend trail = 3.2 + 4.2
Now,
By using the Long Addition,

Hence, from the above,
We can conclude that
The combined length of the Bayshore Loop trail and the Rowdy Bend trail is: 7.4 Kilometers

PART B
How many kilometers longer is the Coastal Prairie trail than the Snake Bight trail?
Answer:
The given information is:
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.3
So,
The difference between the length of the Coastal Prairie trail and the Snake Bight trail = 12.1 – 2.6
Now,
By using the Long Subtraction,

Hence, from the above,
We can conclude that
The Coastal Prairie trail is 9.5 Kilometers longer than the Snake Bight trail

Lesson 1.2 Fluently Divide Whole Numbers and Decimals

Solve & Discuss It!
Some friends went to lunch and split the bill equally. If each person paid $6.75, how many people went to lunch? Use a diagram or equation to explain your thinking.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.4
Answer:
Some friends went to lunch and split the bill equally and each person paid $6.75
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.4

So,
The number of people that went for lunch – (The total bill) ÷ (The amount paid by each person)
= \(\frac{$27}{$6.75}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of people that went for lunch is: 4 people

Reasoning How can you use reasoning to create a representation of the problem?
Answer:
Reasoning in maths is the process of applying logical thinking to a situation to derive the correct problem-solving strategy for a given question and using this method to develop and describe a solution. Put more simply, mathematical reasoning is the bridge between fluency and problem-solving.

Focus on math practices
Reasoning Suppose $7.00 was added to the bill for a dessert that everyone shared. How much more does each person have to pay?
Answer:
It is given that
Suppose $7.00 was added to the bill for a dessert that everyone shared
So,
The total bill = $27 + $7
= $34
So,
The amount each person has to pay = (The total bill) ÷ (The number of people that the bill was split)
= \(\frac{$34}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The amount that each person has to pay is about $8

? Essential Question How can you divide whole numbers and decimals?
Answer:
The steps to divide decimals by Whole Numbers are:
a. Bring down the next digit from the dividend. Continue dividing.
b. Place the decimal point in the quotient.
c. Check your answer: Multiply the divisor by the quotient to see if you get the dividend.

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Try It!
Workers at an electronics company pack 2,610 smartphones in the boxes. Each box holds 9 smartphones. How many boxes do they fill?
Answer:
It is given that
Workers at an electronics company pack 2,610 smartphones in the boxes. Each box holds 9 smartphones
So,
The number of boxes does the workers fill = (The total number of smartphones in the box) ÷ (The number of smartphones each box holds)
= \(\frac{2,610}{9}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of boxes does the workers fill are: 290 boxes

Convince Me! Why is the first digit of the quotient in the Try It! not in the same place as the first digit of the quotient in Example 1?
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.5
Answer:
We know that,
Use place value to place the first digit. Look at the first digit. If the first digit is less than the divisor, then the first digit of the quotient will be in the hundreds place. If the first digit is greater than or equal to the divisor, then the first digit of the quotient will be in the thousands place
Hence, from the above,
We can conclude that the first digit of the quotient in the Try It! is not in the same place as the first digit of the quotient in Example 1

Try It!

Divide.

a. 65 ÷ 8
Answer:
The given division equation is: 65 ÷ 8
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
65 ÷ 8 = 8.12

b. 14.4 ÷ 8
Answer:
The given division equation is: 14.4 ÷ 8
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
14.4 ÷ 8 = 1.8

c. 128.8 ÷ 1.4
Answer:
The given division equation is: 128.8 ÷ 1.4
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
128.8 ÷ 1.4 = 92

KEY CONCEPT
To divide by a decimal, rewrite the decimal so that you are dividing by a whole number. Multiply both the divisor and the dividend by the same power of 10. Then divide as you would with whole numbers.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 6.6

Do You Understand?

Question 1.
? Essential Question How can you divide whole numbers and decimals?
Answer:
The steps to divide decimals by Whole Numbers are:
a. Bring down the next digit from the dividend. Continue dividing.
b. Place the decimal point in the quotient.
c. Check your answer: Multiply the divisor by the quotient to see if you get the dividend.

Question 2.
When dividing with decimals, why is it necessary to multiply both the divisor and the dividend by the same power of 10?
Answer:
In cases like this, you can use powers of 10 to help create an easier problem to solve.
Example:
In this case, you can multiply the divisor, 0.3, by 10 to move the decimal point 1 place to the right. If you multiply the divisor by 10, then you also have to multiply the dividend by 10 to keep the quotient the same.

Question 3.
Use Structure Explain how you can decide where to place the first digit of the quotient for 6,139 ÷ 153.
Answer:
We know that,
Use place value to place the first digit. Look at the first digit. If the first digit is less than the divisor, then the first digit of the quotient will be in the hundreds place. If the first digit is greater than or equal to the divisor, then the first digit of the quotient will be in the thousands place
Hence, from the above,
We can conclude that
For 6,139 ÷ 153,
The first digit of the quotient will be in the hundred’s place

Question 4.
Use Structure How do you know where to place the decimal point in the quotient when dividing a decimal by a whole number?
Answer:
We know that,
The decimal point in the quotient is directly above the decimal point in the dividend. To divide a decimal by a whole number, we place the decimal point in the quotient above the decimal point in the dividend and then divide as usual.

Do You Know How?

Question 5.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 7.1
Answer:
The given division equation is: 9,853 ÷ 48
So,
By using the Long Division,

Hence, from the above,
We can conclude that
9,853 ÷ 48 = 205 R 13

In 6 and 7, divide. Record remainders.

Question 6.
2,789 ÷ 36
Answer:
The given division equation is: 2,789 ÷ 36
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2,879 ÷ 36 = 77 R 17
The remainder for the given division equation is: 17

Question 7.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 7.3
Answer:
The given division equation is: 153 ÷ 18
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
153 ÷ 18 = 8 R 8
The remainder for the given division equation is: 8

In 8 and 9, divide. Write remainders as decimals.

Question 8.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 7.4
Answer:
The given division equation is: 139 ÷ 4
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
139 ÷ 4 = 34 R 3
The remainder for the given division equation is: 3

Question 9.
215 ÷ 2
Answer:
The given division equation is: 215 ÷ 2
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
215 ÷ 2 = 107 R 1
The remainder for the given division equation is: 1

In 10 and 11, divide.

Question 10.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 8.1
Answer:
The given division equation is: 34.75 ÷ 5
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
34.75 ÷ 5 = 6.95

Question 11.
215.25 ÷ 5
Answer:
The given division equation is: 215.25 ÷ 5
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
215.25 ÷ 5 = 43.05

In 12 and 13, divide. Annex zeros if needed to write remainders as decimals.

Question 12.
5.3 ÷ 0.2
Answer:
The given division equation is: 5.3 ÷ 0.2
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
5.3 ÷ 0.2 = 26.5

Question 13.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 8.2
Answer:
The given division equation is: 8.9 ÷ 0.4
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
8.9 ÷ 0.4 = 22.2

Practice & Problem Solving

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Leveled Practice
In 14 and 15, divide.

Question 14.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 8.3
Answer:
The given division equation is: 5,841 ÷ 62
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
5,841 ÷ 62 = 94 R 13

Question 15.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 8.4
Answer:
The given division equation is: 350 ÷ 4
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
350 ÷ 4 = 87.5

In 16-19, divide. Record remainders.

Question 16.
2,593 ÷ 21
Answer:
The given division equation is: 2,593 ÷ 21
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2,593 ÷ 21 = 123 R 10
The remainder for the given division equation is: 10

Question 17.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 8.5
Answer:
The given division equation is: 6,927 ÷ 19
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
6,927 ÷ 19 = 364 R 11
The remainder for the given division equation is: 11

Question 18.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 8.6
Answer:
The given division equation is: 2,483 ÷ 9
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2,483 ÷ 9 = 276 R 8
The remainder for the given division equation is: 8

Question 19.
968 ÷ 38
Answer:
The given division equation is: 968 ÷ 38
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
968 ÷ 38 = 25 R 18
The remainder for the given division equation is: 25 R 18

In 20-23, divide. Write remainders as decimals.

Question 20.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 8.7
Answer:
The given division equation is: 56 ÷ 5
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
56 ÷ 5 = 11.2

Question 21.
232 ÷ 40
Answer:
The given division equation is: 232 ÷ 40
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
232 ÷ 40 = 5.8

Question 22.
44 ÷ 10
Answer:
The given division equation is: 44 ÷ 10
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
44 ÷ 10 = 4.4

Question 23.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 9.1
Answer:
The given division equation is: 2,626 ÷ 4
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2,626 ÷ 4 = 656.5

In 24-27, divide.

Question 24.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 9.5
Answer:
The given division equation is: $54.18 ÷ 6
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
$54.18 ÷ 6 = $9.03

Question 25.
187.2 ÷ 8
Answer:
The given division equation is: 187.2 ÷ 8
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
187.2 ÷ 8 = 23.4

Question 26.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 9.51
Answer:
The given division equation is: 6.3 ÷ 7
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
6.3 ÷ 7 = 0.9

Question 27.
137.5 ÷ 5
Answer:
The given division equation is: 137.5 ÷ 5
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
137.5 ÷ 5 = 27.5

In 28-31, divide. Annex zeros if needed to write remainders as decimals.

Question 28.
6.4 ÷ 0.8
Answer:
The given division equation is: 6.4 ÷ 0.8
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
6.4 ÷ 0.8 = 8

Question 29.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 9.6
Answer:
The given division equation is: 0.2430 ÷ 0.6
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
0.2430 ÷ 0.6 = 0.405

Question 30.
52.056 ÷ 7.23
Answer:
The given division equation is: 52.056 ÷ 7.23
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
52.056 ÷ 7.23 = 7.2

Question 31.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 10.1
Answer:
The given division equation is: 9.089 ÷ 0.745
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
9.089 ÷ 0.745 = 12.2

Question 32.
Ants are one of the Thorny Devil lizard’s favorite foods. It can eat 45 ants per minute. How long would it take this lizard to eat 1,080 ants? Express your answer in minutes.
Envision Math Common Core Grade 6 Answer Key Topic 1 Use Positive Rational Numbers 10.2
Answer:
It is given that
Ants are one of the Thorny Devil lizard’s favorite foods. It can eat 45 ants per minute.
So,
The time it will take for Thorny Devil lizard to eat 1,080 ants = (The total number of ants) ÷ (The number of ants Thorny Devil lizard eat per minute)
= 1,080 ÷ 45
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The time it will take for Thorny Devil lizard to eat 1,080 ants is: 24 minutes

Question 33.
Critique Reasoning Henrieta divided 0.80 by 20 as shown. Is her work correct? If not, explain why and give a correct response.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 10.3
Answer:
It is given that
Henrieta divided 0.80 by 20 as shown
So,
The representation of the division equation Henrieta divided is: 0.80 ÷ 20
Now,
By using the Long Division,

So,
From the above,
We can observe that
0.80 ÷ 20 = 0.04
Hence, from the above,
We can conclude that Henrieta’s work is not correct

Question 34.
Which brand of fruit snacks costs less per pound? How much less?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 10.4
Answer:
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 10.4
Now,
The cost per pound of Brand A’s fruit snacks = (The cost of Brand A fruit snacks) ÷ (The amount of Brand A fruit snacks)
= $16.20 ÷ 15
Now,
By using the Long Division,

So,
The cost per pound of Brand A’s fruit snacks is: $1.08
Now,
The cost per pound of Brand B’s fruit snacks = (The cost of Brand B fruit snacks) ÷ (The amount of Brand B fruit snacks)
= $22.25 ÷ 25
Now,
By using the Long Division,

So,
The cost per pound of Brand B’s fruit snacks is: $0.89
So,
The difference between the cost per pound of two brands = $1.08 – $0.89
Now,
By using the Long Subtraction,

So,
The difference between the cost per pound of two brands is: $0.19
Hence, from the above,
We can conclude that
The cost per pound of Brand B’s fruit snacks is: $0.89
The difference between the cost per pound of two brands is: $0.19

Question 35.
Be Precise How many times as much does each item cost in 2010 as in 1960?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 10.5
Answer:
The given data is:

Now,
Let the number of times as much does each item cost in 2010 as in 1960 be x
So,
For the Movie Ticket,
x = $9.75 ÷ $0.75
Now,
By using the Long Division,

So,
For Regular popcorn,
x = $4.10 ÷ $0.25
Now,
By using the Long Division,

So,
For Regular Drink,
x = $3.08 ÷ $0.35
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of times as much does the movie ticket cost in 2010 as in 1960 is: 13 times
The number of times as much does the regular ticket cost in 2010 as in 1960 is: 16.40 times
The number of times as much does the regular drink cost in 2010 as in 1960 is: 8.80 times

Question 36.
Higher-Order Thinking Kendra has 5.5 pounds of popcorn and wants to package it equally in 50 bags. How can she use place-value reasoning to find the amount of popcorn to put in each bag?
Answer:
It is given that
Kendra has 5.5 pounds of popcorn and wants to package it equally in 50 bags.
Now,
We know that,
Use place value to place the first digit. Look at the first digit. If the first digit is less than the divisor, then the first digit of the quotient will be in the hundreds place. If the first digit is greater than or equal to the divisor, then the first digit of the quotient will be in the thousands place
So,
The amount of popcorn Kendra put in each bag = (The total number of pounds of popcorn Kendra has) ÷ (The number of bags Kendra wants to package the popcorn equally)
= 5.5 ÷ 50
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The amount of popcorn Kendra put in each bag is: 0.11 pounds

Question 37.
You and a friend are paid $38.25 for doing yard work. You worked 2.5 hours and your friend worked 2 hours. You split the money according to the amount of time each of you worked. How much is your share of the money? Explain.
Answer:
It is given that
You and a friend are paid $38.25 for doing yard work. You worked 2.5 hours and your friend worked 2 hours. You split the money according to the amount of time each of you worked
So,
The amount of money that is your share = (The amount of money you and your friend are paid for doing yard work) ÷ (The number of hours you worked)
= $38.25 ÷ 2.5
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The amount of money that is your share is: $15.30

Assessment Practice

Question 38.
What is the value of the expression 1,248 ÷ 25?
A. 49
B. 49 R9
C. 49.9
D. 49 R 23
Answer:
The given division equation is: 1,248 ÷ 25
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The value of the expression 1,248 ÷ 25 is:

Question 39.
Which expression has the same solution as 3,157 ÷ 41?
A. 1,852 ÷ 24
B. 1,928 ÷ 25
C. 2,079 ÷ 27
D. 2,184 ÷ 28
Answer:
The given division equation is: 3,157 ÷ 41
Now,
By using the Long Division,

Now,
The expressions that have the same value as the given expression by using the Long Division are:
A. 1,852 ÷ 24

B. 1,928 ÷ 25

C. 2,079 ÷ 27

D. 2,184 ÷ 28

Hence, from the above,
We can conclude that
The expressions that have the same value as the given expression are:

Lesson 1-3 Multiply Fractions

Solve & Discuss It!

ACTIVITY

The art teacher gave each student half of a sheet of paper. Then she asked the students to color one-fourth of their pieces of paper. What part of the original sheet did the students color?
Answer:
It is given that
The art teacher gave each student half of a sheet of paper. Then she asked the students to color one-fourth of their pieces of paper
So,
The part of the original sheet did the students color = (The piece of paper the art teacher gave to each student) × (The part of the paper the are teacher asked the students to color)
= \(\frac{1}{2}\) × \(\frac{1}{4}\)
= \(\frac{1 × 1}{2 × 4}\)
= \(\frac{1}{8}\) of the piece of paper
Hence, from the above,
We can conclude that
The part of the original sheet did the students color is: \(\frac{1}{8}\) of the piece of paper

A model with Math
How can you use a picture to represent the problem?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 11.1
Answer:
By representing units of measurement and other objects visually, students can begin to think about the problem mathematically. Pictures and diagrams are also good ways of describing solutions to problems; therefore they are an important part of mathematical communication.

Focus on math practices
Reasoning
Should your answer be less than or greater than 1? Explain.
Answer:
From the above problem,
We can observe that
The part of the original sheet did the students color is: \(\frac{1}{8}\) of the piece of paper
Now,
By using the Long Division,
The value of \(\frac{1}{8}\) is:

Hence, from the above,
We can conclude that
Your answer is less than 1

? Essential Question How can you multiply fractions and mixed numbers?
Answer:
The steps that are used to multiply mixed numbers and fractions are:
a. Convert the given mixed fraction to an improper fraction.
b. Write the whole number in the form of a fraction with denominator 1.
c. Multiply the numerators of both the fractions.
d. Multiply the denominators of both the fractions.
e. Combine them and simplify the fraction to its lowest form.

Try It!

Find \(\frac{1}{4}\) × \(\frac{1}{5}\) using the area model. Explain.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 11.2
Answer:
The given multiplication equation is:
\(\frac{1}{4}\) × \(\frac{1}{5}\)
Now,
By using the Area model,

So,

So,
\(\frac{1}{4}\) × \(\frac{1}{5}\)
= \(\frac{1 × 1}{4 × 5}\)
= \(\frac{1}{20}\)
Hence, from the above,
We can conclude that
\(\frac{1}{4}\) × \(\frac{1}{5}\) = \(\frac{1}{20}\)

Convince Me! Why is the product of \(\frac{1}{4}\) × \(\frac{1}{5}\) less than each factor?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 11.3
Answer:
The given multiplication equation is:
\(\frac{1}{4}\) × \(\frac{1}{5}\)
So,
\(\frac{1}{4}\) × \(\frac{1}{5}\)
= \(\frac{1}{20}\)
Now,
When we compare the denominators,
4 < 5 and 5 < 20
So,
20  > 5 > 4 —- (1)
But,
When we compare the denominators,
The same relationship of eq (1) will be reversed
So,
20 < 5 < 4
Hence, from the above,
We can conclude that
\(\frac{1}{4}\) × \(\frac{1}{5}\) is less than each factor

Try It!
Find \(\frac{3}{4}\) × \(\frac{4}{6}\) using the number line. Explain.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 11.4
Answer:
The given multiplication equation is:
\(\frac{3}{4}\) × \(\frac{4}{6}\)
So,
\(\frac{3}{4}\) × \(\frac{4}{6}\)
= \(\frac{3 × 4}{4 × 6}\)
= \(\frac{12}{24}\)
= \(\frac{3}{6}\)
So,
The representation of the product of \(\frac{3}{4}\) × \(\frac{4}{6}\) in the number line is:

Hence, from the above,
We can concldue that
\(\frac{3}{4}\) × \(\frac{4}{6}\) = \(\frac{3}{6}\)

Try It!
A clothing factory makes T-shirts. If each machine makes 3\(\frac{1}{3}\) T-shirts per hour, how many T-shirts does one machine make in 4\(\frac{1}{2}\) hours? Write and solve an equation.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 11.5
Answer:
It is given that
A clothing factory makes T-shirts. If each machine makes 3\(\frac{1}{3}\) T-shirts per hour
So,
The number of T-shirts does 1 machine makes in 4\(\frac{1}{2}\) hours = (The number of T-shirts made by each machine in a hour) × 4\(\frac{1}{2}\) hours
Now,
The representation of 3\(\frac{1}{3}\) into a fraction is: \(\frac{10}{3}\)
The representation of 4\(\frac{1}{2}\) into a fraction is: \(\frac{9}{2}\)
So,
The number of T-shirts does 1 machine makes in 4\(\frac{1}{2}\) hours = \(\frac{10}{3}\) × \(\frac{9}{2}\)
= \(\frac{10 ×9}{3 ×2}\)
= \(\frac{90}{6}\)
= 15 T-shirts
Hence, from the above,
We can conclude that
The number of T-shirts does 1 machine makes in 4\(\frac{1}{2}\) hours is: 15 T-shirts

KEY CONCEPT
You can find the product of fractions or mixed numbers.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 11.6

Do You Understand?

Question 1.
? Essential Question How can you multiply fractions and mixed numbers?
Answer:
The steps that are used to multiply mixed numbers and fractions are:
a. Convert the given mixed fraction to an improper fraction.
b. Write the whole number in the form of a fraction with denominator 1.
c. Multiply the numerators of both the fractions.
d. Multiply the denominators of both the fractions.
e. Combine them and simplify the fraction to its lowest form.

Question 2.
Reasoning Is the product of \(\frac{3}{6}\) × \(\frac{5}{4}\) equal to the product of \(\frac{3}{6}\) × \(\frac{5}{6}\)? Explain.
Answer:
The given multiplication equations are:
\(\frac{3}{6}\) × \(\frac{5}{4}\)
\(\frac{3}{6}\) × \(\frac{5}{6}\)
Now,
By using the Long Multiplication,

Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The product of \(\frac{3}{6}\) × \(\frac{5}{4}\)  is not equal to the product of \(\frac{3}{6}\) × \(\frac{5}{6}\)

Question 3.
Construct Arguments Why is adding \(\frac{3}{9}\) and \(\frac{6}{9}\) different from multiplying the two fractions?
Answer:

Question 4.
Tina has \(\frac{1}{2}\) of a pan of cornbread left from a dinner party. She eats \(\frac{1}{2}\) of the leftover part the next night. How much of the whole pan does Tina eat? Write and solve an equation.
Answer:
It is given that
Tina has \(\frac{1}{2}\) of a pan of cornbread left from a dinner party. She eats \(\frac{1}{2}\) of the leftover part the next night
So,
The amount of the whole pan of cornbread does Tina eat = (The amount of a pan of cornbread left from a dinner party) × (The amount of the leftover from a dinner party that Tine eat the next night)
= \(\frac{1}{2}\) × \(\frac{1}{2}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The amount of the whole pan of cornbread does Tina eat is: \(\frac{1}{4}\) of a pan of cornbread

Question 5.
Construct Arguments Explain how you would multiply 5 × 2\(\frac{1}{2}\).
Answer:
The given multiplication is: 5 × 2\(\frac{1}{2}\)
So,
The representation of 2\(\frac{1}{2}\) into a fraction is:

Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
5 × 2\(\frac{1}{2}\) = \(\frac{25}{2}\)

Question 6.
In Example 1, find the fraction of a whole pan of lasagna that Tom ate if he started with \(\frac{7}{8}\) of a pan.
Answer:
It is given that
Tom has a \(\frac{7}{8}\) of a pan of lasagna left and Tom ate \(\frac{1}{3}\) of this amount
So,
The fraction of a whole pan of lasagna that Tom ate = (The amount of a pan of lasagna left) × (The amount that Tom ate from the amount of lasagna that is left)
= \(\frac{7}{8}\) × \(\frac{1}{3}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The fraction of a whole pan of lasagna that Tom ate is: \(\frac{7}{24}\) of a pan of lasagna

Do You Know How?

Question 7.
Find \(\frac{5}{6}\) × \(\frac{1}{2}\). Use the model to help solve.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 12.1
Answer:
The given multiplication equation is:
\(\frac{5}{6}\) × \(\frac{1}{2}\)
Now,
By using the Area model,

Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{5}{6}\) × \(\frac{1}{2}\) = \(\frac{5}{12}\)

Question 8.
Find \(\frac{3}{4}\) × \(\frac{4}{9}\).
Answer:
The given multiplication equation is:
\(\frac{3}{4}\) × \(\frac{4}{9}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{3}{4}\) × \(\frac{4}{9}\) = \(\frac{1}{3}\)

In 9-16, find each product.

Question 9.
\(\frac{2}{3}\) × \(\frac{1}{2}\)
Answer:
The given multiplication equation is:
\(\frac{2}{3}\) × \(\frac{1}{2}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{2}{3}\) × \(\frac{1}{2}\) = \(\frac{1}{3}\)

Question 10.
\(\frac{5}{9}\) × \(\frac{1}{9}\)
Answer:
The given multiplication equation is:
\(\frac{5}{9}\) × \(\frac{1}{9}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{5}{9}\) × \(\frac{1}{9}\) = \(\frac{5}{81}\)

Question 11.
\(\frac{7}{10}\) × \(\frac{3}{4}\)
Answer:
The given multiplication equation is:
\(\frac{7}{10}\) × \(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{7}{10}\) × \(\frac{3}{4}\) = \(\frac{21}{40}\)

Question 12.
\(\frac{1}{3}\) × \(\frac{1}{4}\)
Answer:
The given multiplication equation is:
\(\frac{1}{3}\) × \(\frac{1}{4}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{3}\) × \(\frac{1}{4}\) = \(\frac{1}{12}\)

Question 13.
\(\frac{5}{6}\) × \(\frac{3}{7}\)
Answer:
The given multiplication equation is:
\(\frac{5}{6}\) × \(\frac{3}{7}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{5}{6}\) × \(\frac{3}{7}\) = \(\frac{5}{14}\)

Question 14.
\(\frac{3}{5}\) × \(\frac{11}{12}\)
Answer:
The give multiplication equation is:
\(\frac{3}{5}\) × \(\frac{11}{12}\)
Now,
By using the Long Multiplication,

Hence, fro the above,
We can conclude that
\(\frac{3}{5}\) × \(\frac{11}{12}\) = \(\frac{11}{20}\)

Question 15.
\(\frac{4}{10}\) × \(\frac{2}{5}\)
Answer:
The given multiplication equation is:
\(\frac{4}{10}\) × \(\frac{2}{5}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{4}{10}\) × \(\frac{2}{5}\) = \(\frac{4}{25}\)

Question 16.
\(\frac{3}{4}\) × \(\frac{2}{9}\)
Answer:
The given multiplication equation is:
\(\frac{3}{4}\) × \(\frac{2}{9}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{3}{4}\) × \(\frac{2}{9}\) = \(\frac{1}{6}\)

In 17 and 18, estimate the product. Then complete the multiplication.

Question 17.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 16.1
Answer:
The given multiplication equation is:
2\(\frac{3}{4}\) × 8
Now,
The representation of 2\(\frac{3}{4}\) into a fraction is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that

Question 18.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 16.2
Answer:
The given multiplication equation is:
4\(\frac{1}{2}\) × 1\(\frac{1}{4}\)
Now,
The representation of 4\(\frac{1}{2}\) into a fraction is:

The representation of 1\(\frac{1}{4}\) into a fraction is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that

Practice & Problem Solving

Scan for Multimedia

In 19 and 20, find each product. Shade the model to help solve.

Question 19.
\(\frac{1}{3}\) × \(\frac{5}{6}\)
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 16.3
Answer:
The given multiplication equation is:
\(\frac{1}{3}\) × \(\frac{5}{6}\)
Now,
The representation of the given multiplication equation in the form of a model is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{3}\) × \(\frac{5}{6}\) = \(\frac{5}{18}\)

Question 20.
\(\frac{2}{3}\) × \(\frac{1}{12}\)
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 16.4
Answer:
The given multiplication equation is:
\(\frac{2}{3}\) × \(\frac{1}{12}\)
So,
The representation of the given multiplication equation in the form of a model is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{2}{3}\) × \(\frac{1}{12}\) = \(\frac{1}{18}\)

In 21-28, find each product.

Question 21.
\(\frac{7}{8}\) × \(\frac{1}{2}\)
Answer:
The given multiplication equation is:
\(\frac{7}{8}\) × \(\frac{1}{2}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{7}{8}\) × \(\frac{1}{2}\) = \(\frac{7}{16}\)

Question 22.
\(\frac{2}{5}\) × \(\frac{1}{12}\)
Answer:
The given multiplication equation is:
\(\frac{2}{5}\) × \(\frac{1}{12}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{2}{5}\) × \(\frac{1}{12}\) = \(\frac{1}{30}\)

Question 23.
\(\frac{5}{7}\) × \(\frac{7}{9}\)
Answer:
The given multiplication equation is:
\(\frac{5}{7}\) × \(\frac{7}{9}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{5}{7}\) × \(\frac{7}{9}\) = \(\frac{5}{9}\)

Question 24.
\(\frac{1}{2}\) × \(\frac{3}{4}\)
Answer:
The given multiplication equation is:
\(\frac{1}{2}\) × \(\frac{3}{4}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{2}\) × \(\frac{3}{4}\) = \(\frac{3}{8}\)

Question 25.
\(\frac{1}{4}\) × \(\frac{7}{8}\)
Answer:
The given multiplication equation is:
\(\frac{1}{4}\) × \(\frac{7}{8}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{4}\) × \(\frac{7}{8}\) = \(\frac{7}{32}\)

Question 26.
\(\frac{5}{6}\) × \(\frac{9}{10}\)
Answer:
The given multiplication equation is:
\(\frac{5}{6}\) × \(\frac{9}{10}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{5}{6}\) × \(\frac{9}{10}\) = \(\frac{3}{4}\)

Question 27.
\(\frac{1}{4}\) × \(\frac{1}{8}\)
Answer:
The given multiplication equation is:
\(\frac{1}{4}\) × \(\frac{1}{8}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{4}\) × \(\frac{1}{8}\) = \(\frac{1}{32}\)

Question 28.
\(\frac{1}{3}\) × \(\frac{3}{7}\)
Answer:
The given multiplication equation is:
\(\frac{1}{3}\) × \(\frac{3}{7}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{3}\) × \(\frac{3}{7}\) = \(\frac{1}{7}\)

In 29-36, estimate the product. Then find each product.

Question 29.
2\(\frac{1}{6}\) × 4\(\frac{2}{9}\)
Answer:
The given multiplication equation is:
2\(\frac{1}{6}\) × 4\(\frac{2}{9}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
2\(\frac{1}{6}\) × 4\(\frac{2}{9}\) = \(\frac{247}{27}\)

Question 30.
\(\frac{3}{4}\) × 8\(\frac{1}{2}\)
Answer:
The given multiplication equation is:
\(\frac{3}{4}\) × 8\(\frac{1}{2}\)
Now,
The representation of 8\(\frac{1}{2}\) into a fraction is:

So,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{3}{4}\) × 8\(\frac{1}{2}\) = \(\frac{51}{8}\)

Question 31.
1\(\frac{1}{8}\) × 3\(\frac{1}{3}\)
Answer:
The given multiplication equation is:
1\(\frac{1}{8}\) × 3\(\frac{1}{3}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
1\(\frac{1}{8}\) × 3\(\frac{1}{3}\) = \(\frac{15}{4}\)

Question 32.
3\(\frac{1}{2}\) × \(\frac{2}{3}\)
Answer:
The given multiplication equation is:
3\(\frac{1}{2}\) × \(\frac{2}{3}\)
Now,
The representation of 3\(\frac{1}{2}\) into a fraction is:

So,
By using the Long Division,

Hence, from the above,
We can conclude that
3\(\frac{1}{2}\) × \(\frac{2}{3}\) = \(\frac{7}{3}\)

Question 33.
3\(\frac{1}{4}\) × 6
Answer:
The given multiplication equation is:
3\(\frac{1}{4}\) × 6
Now,
The representation of 3\(\frac{1}{4}\) into a fraction is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
3\(\frac{1}{4}\) × 6 = \(\frac{39}{2}\)

Question 34.
5\(\frac{1}{3}\) × 3
Answer:
The given multiplication equation is:
5\(\frac{1}{3}\) × 3
Now,
The representation of 5\(\frac{1}{3}\) into a fraction is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
5\(\frac{1}{3}\) × 3 = 16

Question 35.
2\(\frac{3}{8}\) × 4
Answer:
The given multiplication equation is:
2\(\frac{3}{8}\) × 4
Now,
The representation of 2\(\frac{3}{8}\) into a fraction is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
2\(\frac{3}{8}\) × 4 = \(\frac{19}{2}\)

Question 36.
4\(\frac{1}{8}\) × 5\(\frac{1}{2}\)
Answer:
The given multiplication equation is:
4\(\frac{1}{8}\) × 5\(\frac{1}{2}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
4\(\frac{1}{8}\) × 5\(\frac{1}{2}\) = \(\frac{363}{16}\)

In 37 and 38, use the diagram at the right.

Question 37.
Linda walked \(\frac{3}{4}\) of the length of the Tremont Trail before stopping for a rest. How far had Linda walked on the trail?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 20.1
Answer:
It is given that
Linda walked \(\frac{3}{4}\) of the length of the Tremont Trail before stopping for a rest
Now,
The given information is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 20.1
So,
The distance covered by Linda on the trail = (The distance Linda walked of the Tremont trail) × (The length of the Tremont trail)
= \(\frac{3}{4}\) × 3\(\frac{1}{2}\)
Now,
The representation of 3\(\frac{1}{2}\) into a fraction is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The distance covered by Linda on the trail is: \(\frac{25}{8}\) miles

Question 38.
The city plans to extend the Wildflower Trail to make it 2\(\frac{1}{2}\) times its current length in the next 5 years. How long will the Wildflower Trail be at the end of 5 years?
Answer:
It is given that
The city plans to extend the Wildflower Trail to make it 2\(\frac{1}{2}\) times its current length in the next 5 years
Now,
The given information is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 20.1
So,
The length of the Wildflower trail at the end of 5 years = (The extended length of the Wildflower trail at the end of 5 years) × (The current length of the Wildflower trail)
= 2\(\frac{1}{2}\) × 2\(\frac{3}{8}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The length of the Wildflower trail at the end of 5 years will be: \(\frac{95}{16}\) miles

Question 39.
The world’s smallest gecko is \(\frac{3}{4}\) inch long. An adult male Western Banded Gecko is 7\(\frac{1}{3}\) times as long. How long is an adult male Western Banded Gecko?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 20.2
Answer:
It is given that
The world’s smallest gecko is \(\frac{3}{4}\) inch long. An adult male Western Banded Gecko is 7\(\frac{1}{3}\) times as long
So,
The length of an adult male Western Banded Gecko = (The length of the world’s small gecko) × (The number of times an adult male western banded gecko is as larger than the world’s smallest gecko)
= \(\frac{3}{4}\) × 7\(\frac{1}{3}\)
Now,
The representation of 7\(\frac{1}{3}\) into a fraction is:

So,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The length of an adult male Western Banded Gecko is: \(\frac{11}{2}\) inches

Question 40.
Higher-Order Thinking In Ms. Barclay’s classroom, \(\frac{2}{5}\) of the students play chess. Of the students who play chess, \(\frac{5}{6}\) also play sudoku. If there are 30 students in Ms. Barclay’s class, how many play chess and sudoku?
Answer:
It is given that
In Ms. Barclay’s classroom, \(\frac{2}{5}\) of the students play chess. Of the students who play chess, \(\frac{5}{6}\) also play sudoku. If there are 30 students in Ms. Barclay’s class
So,
The number of students who play chess = (The total number of students) × (The fracti of the students that play chess)
= 30 × \(\frac{2}{5}\)
Now,
By using the Long Multiplication,

So,
The number of students who play chess are: 12 students
Now,
The number of students who play Sudoku = (The number of students who play chess) × (The fraction of the students who play Sudoku)
= 12 × \(\frac{5}{6}\)
Now,
By using the Long Multiplication,

So,
The number of students who play sudoku are: 10 students
Now,
The number of students who play chess and sudoku = (The number of students who play chess) – (The number of students who play sudoku)
= 12 – 10
= 2 students
Hence, from the above,
We can conclude that
The number of students who play chess are: 12 students
The number of students who play sudoku are: 10 students
The number of students who play chess and sudoku are: 2 students

Question 41.
The Boca Grande Causeway in Florida is about 1\(\frac{4}{9}\) times as long as the Golden Gate Bridge in San Francisco. The Golden Gate Bridge is about 9,000 feet long. About how long is the Boca Grande Causeway?
Answer:
It is given that
The Boca Grande Causeway in Florida is about 1\(\frac{4}{9}\) times as long as the Golden Gate Bridge in San Francisco. The Golden Gate Bridge is about 9,000 feet long
So,
The length of the Boca Grande causeway = (The number of times the Boca Grande causeway as long as the Golden Gate Bridge) × (The length of the Golden Gate Bridge)
= 1\(\frac{4}{9}\) × 9,000
Now,
The representation of 1\(\frac{4}{9}\) into a fraction is:

Now,
By using the Long Multiplication,

Hence, from the above,
We acn conclude that
The length of the Boca Grande causeway is: 13,000 feet

Question 42.
If \(\frac{7}{8}\) is multiplied by \(\frac{4}{5}\), will the product be greater than either of the two factors? Explain.
Answer:
The given multiplication equation is:
\(\frac{7}{8}\) × \(\frac{4}{5}\)
Now,
The representation of the given multiplication equation in the form of a decimal numbers is:
0.875 × 0.8
Now,
By using the Long Multiplication,

Now,
The representation of the value of the product in the form of a decimal number is: 0.7
Hence, from the above,
We can conclude that
The product would be smaller than either of the two factors

Question 43.
Be Precise To amend the U.S. Constitution, \(\frac{3}{4}\) of the 50 states must approve the amendment. If 35 states approve an amendment, will the Constitution be amended?
Answer:
It is given that
To amend the U.S. Constitution, \(\frac{3}{4}\) of the 50 states must approve the amendment
So,
The number of states that approved the amendment = (The total number of states) × (The number of states who approved the amendment)
= 50 × \(\frac{3}{4}\)
Now,
By using the Long Multiplication,

Now,
We can observe that about 37 states approved the amendment from the above Long Multiplication
Hence, from the above,
We can conclude that
If 35 states approve an amendment, the Constitution will be amended

Question 44.
A scientist had \(\frac{3}{4}\) of a bottle of a solution. She used \(\frac{1}{6}\) of the solution in an experiment. How much of the bottle did she use?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 22.10
Answer:
It is given that
A scientist had \(\frac{3}{4}\) of a bottle of a solution. She used \(\frac{1}{6}\) of the solution in an experiment
So,
The amount of the solution in the bottle did she used = (The total amount of solution in the bottle) × (the amount of solution did she used in an experiment)
= \(\frac{3}{4}\) × \(\frac{1}{6}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The amount of the solution in the bottle did she used is: \(\frac{1}{8}\) of the total amount of solution

Question 45.
In the voting for City Council Precinct 5, only \(\frac{1}{2}\) of all eligible voters cast votes. What fraction of all eligible voters voted for Shelley? Morgan? Who received the most votes?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 20.11
Answer:
It is given that
In the voting for City Council Precinct 5, only \(\frac{1}{2}\) of all eligible voters cast votes
Now,
The given table is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 20.11
So,
The fraction of the eligible voters voted for Shelly = (The fraction of the eligible voters voted) × (The fraction of votes received by Shelly)
= \(\frac{1}{2}\) × \(\frac{3}{10}\)
Now,
By using the Long Multiplication,

So,
The fraction of the eligible voters voted for Shelly is: \(\frac{3}{20}\) votes
So,
The fraction of the eligible voters voted for Morgan = (The fraction of the eligible voters voted) × (The fraction of votes received by Morgan)
= \(\frac{1}{2}\) × \(\frac{5}{8}\)
Now,
By using the Long Multiplication,

So,
The fraction of the eligible voters voted for Morgan is: \(\frac{5}{16}\) votes
Now,
The representation of \(\frac{3}{20}\) into a decimal number is: 0.15
The representation of \(\frac{5}{16}\) into a decimal number is: 0.3125
Hence, from the above,
We can conclude that
Morgan received the most votes

Assessment Practice

Question 46.
Which of these equations is equivalent to 1\(\frac{1}{2}\) × 3\(\frac{1}{5}\) = 4\(\frac{1}{2}\)?
A. 4\(\frac{1}{2}\) ÷ 3\(\frac{1}{5}\) = 1\(\frac{1}{2}\)
B. 1\(\frac{1}{2}\) ÷ 4\(\frac{1}{2}\) = 3\(\frac{1}{5}\)
C. 1\(\frac{1}{2}\) ÷ 3\(\frac{1}{5}\) = 4\(\frac{1}{2}\)
D. 3\(\frac{1}{5}\) ÷ 4\(\frac{1}{2}\) = 1\(\frac{1}{2}\)
Answer:
The given multiplication equation is:
1\(\frac{1}{2}\) × 3\(\frac{1}{5}\) = 4\(\frac{1}{2}\)
Now,
Divide the above equation with 3\(\frac{1}{5}\)
So,
We will get
4\(\frac{1}{2}\) ÷ 3\(\frac{1}{5}\) = 1\(\frac{1}{2}\)
Hence, from the above,
We can conclude that
The equations that are equivalent to 1\(\frac{1}{2}\) × 3\(\frac{1}{5}\) = 4\(\frac{1}{2}\) are:

Question 47.
Which of these equations is equivalent to \(\frac{3}{4}\) × 8\(\frac{1}{5}\) = 6\(\frac{3}{20}\)? Select all that apply.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26 \(\frac{3}{4}\) ÷ 8\(\frac{1}{5}\) = 6\(\frac{3}{20}\)
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26 6\(\frac{3}{20}\) ÷ \(\frac{3}{4}\) = 8\(\frac{1}{5}\)
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26 6\(\frac{3}{20}\) ÷ 8\(\frac{1}{5}\) = \(\frac{3}{4}\)
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26 \(\frac{3}{4}\) ÷ 6\(\frac{3}{20}\) = 8\(\frac{1}{5}\)
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26 8\(\frac{1}{5}\) ÷ 6\(\frac{3}{20}\) = \(\frac{3}{4}\)
Answer:
The given multiplication equation is:
\(\frac{3}{4}\) × 8\(\frac{1}{5}\) = 6\(\frac{3}{20}\)
Now,
Divide the above equation with 8\(\frac{1}{5}\)
So,
We will get
6\(\frac{3}{20}\) ÷ 8\(\frac{1}{5}\) = \(\frac{3}{4}\)
Hence, from the above,
We can conclude that
The equations that are equivalent to \(\frac{3}{4}\) × 8\(\frac{1}{5}\) = 6\(\frac{3}{20}\) are:

Topic 1 MID-TOPIC CHECKPOINT

Question 1.
Vocabulary How can you use a compatible number to estimate a quotient when dividing a decimal by a whole number? Lesson 1.2
Answer:
When dividing a decimal by a whole number, we use the following procedure:
a. Estimate the quotient.
b. Perform the division. Remember to place a zero in the quotient when the divisor is larger than the dividend.
c. Compare your estimate with your quotient to verify that the answer makes sense.

Question 2.
Keaton is building a rectangular tabletop and wants to put a metal border around the edge. The length of the tabletop is 1.83 meters and the width is 0.74 meters. Use the formula P = 2l + 2w to find the perimeter of the tabletop. Lesson 1.1
Answer:
It is given that
Keaton is building a rectangular tabletop and wants to put a metal border around the edge. The length of the tabletop is 1.83 meters and the width is 0.74 meters
So,
To find the length of the metal border around the edge,
We have to find the perimeter of the tabletop
Now,
From the give information,
We can observe that
The perimeter of the tabletop (P) = 2l + 2w
Where,
‘l’ is the length of the tabletop
‘w’ is the width of the tabletop
So,
The perimeter of the tabletop (P) = (2 × 1.83) + (2 × 0.74)
= 3.66 + 1.48
= 5.14 meters
Hence, from the above,
We can conclude that
The perimeter of thetabletop is: 5.14 meters

Question 3.
Norbert’s Nursery is having a sale. Flats of flowers are priced as marked, including tax. Jake buys 2 flats of petunias, 3 flats of daisies, and 1 flat of begonias. If he pays with a $50 bill, how much change should Jake receive? Lesson 1.1
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 21.5
Answer:
It is given that
Norbert’s Nursery is having a sale. Flats of flowers are priced as marked, including tax. Jake buys 2 flats of petunias, 3 flats of daisies, and 1 flat of begonias. If he pays with a $50 bill
Now,
The given table is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 21.5
Now,
The total price of flats of flowers Jack bought = (2 × The price of each flat of Petunia) + (3 × The price of each flat of daisies) + (1 × The price of each flat of begonias)
= (2 × $5.25) + (3 × $7.65) + (1 × $8.40)
= $10.5 + $22.95 + $8.40
= $41.85
Now,
The amount of change should Jack receive = (The total amount of money Jack gave) – (The total price of the flowers Jack bought)
= $50 – $41.85
= $8.15
Hence, from the above,
We can conclude that
The amount of change should Jack receive is: $8.15

Question 4.
Marguerite is selling space in an advertisement book for a community fund-raising event. Each \(\frac{1}{4}\) page in the book costs $15.50. What is the cost for \(\frac{3}{4}\) page? Lesson 1.1
A. $62.00
B. $46.50
C. $20.67
D. $11.63
Answer:
It is given that
Marguerite is selling space in an advertisement book for a community fund-raising event. Each \(\frac{1}{4}\) page in the book costs $15.50
So,
The cost for \(\frac{3}{4}\) page = 3 × (The cost of \(\frac{1}{4}\) page)
= 3 × $15.50
= $46.50
Hence, from the above,
We can conclude that
The cost for \(\frac{3}{4}\) page is:

Question 5.
What is the value of 170 ÷ (4 × 5)? Lesson 1.2
Answer:
The given division expression is: 170 ÷ (4 × 5)
So,
170 ÷ (4 × 5)
= 170 ÷ 20
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
170 ÷ 20 = 8.5

Question 6.
Lucia walks 2\(\frac{3}{4}\) miles on Monday. On Monday, she walks 1\(\frac{1}{2}\) times farther than on Tuesday. Which equation can be used to find how far Lucia walks on Tuesday? Lesson 1-3
A. 2\(\frac{3}{4}\) × 1\(\frac{1}{2}\) = 4\(\frac{1}{8}\)
B. 2\(\frac{3}{4}\) × 1\(\frac{1}{2}\) = 4\(\frac{1}{4}\)
C. 2\(\frac{3}{4}\) ÷ 1\(\frac{1}{2}\) = 1\(\frac{5}{6}\)
D. 1\(\frac{1}{2}\) ÷ 2\(\frac{3}{4}\) = \(\frac{6}{11}\)
Answer:
It is given that
Lucia walks 2\(\frac{3}{4}\) miles on Monday. On Monday, she walks 1\(\frac{1}{2}\) times farther than on Tuesday
So,
The distance Lucia walked on Tuesday = (The distance Lucia walked on Monday) + 1\(\frac{1}{2}\)
= 2\(\frac{3}{4}\) + 1\(\frac{1}{2}\)
Now,
By using the Long Addition,

Hence, from the above,
We can conclude that
The equation that can be used to find how far Lucia walks on Tuesday is:

How well did you do on the mid-topic checkpoint? Fill in the stars. Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 28

Topic 1 MID-TOPIC PERFORMANCE TASK

Nyan Robotics Team received their challenge for the year and has to buy parts to build their robot for competitions.

Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 28.1

PART A
Team members Eric and Natalia secure a grant for $75.00 to buy beams and channels. If the team needs 3 beams and 6 channels, will the grant cover the cost? If so, how much of the grant will remain?
Answer:
It is given that
Team members Eric and Natalia secure a grant for $75.00 to buy beams and channels and the team needs 3 beams and 6 channels
Now,
The given table is;
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 28.1
So,
The cost of 3 beams and 6 channels = (3 × The cost of each Beam) + (6 × The cost of each Channel)
= (3 × $5.95) + (6 × $8.50)
= $17.85 + $51
= $68.85
So,
The grant received > The cost of 3 beams and 6 channels
Now,
The amount of the grant that will remain = (The total grant granted) – (The cost of 3 beams and 6 channels)
= $75 – $68.85
= $6.15
Hence, from the above,
We can conclude that
The amount of grant that will remain is: $6.15

PART B
Team members Corinne, Kevin, and Tomas decide to share the cost of 2 motor controllers and 4 wheels equally. How much does each member need to contribute?
Answer:
It is given that
Team members Corinne, Kevin, and Tomas decide to share the cost of 2 motor controllers and 4 wheels equally
Now,
The given table is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 28.1
So,
The total cost of 2 motor controllers and 4 wheels = (2 × The cost of each motor controller) + (4 × The cost of each wheel)
= (2 × $99.75) + (4 × $18.90)
= $199.5 + $75.6
= $275.1
Now,
The amount of money each member needs to contribute to buy 2 motor controllers and 4 wheels = $275.1 ÷ 3
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The amount of money each member needs to contribute to buy 2 motor controllers and 4 wheels is: $91.70

PART C
Nyan Robotics has a budget of $99 to buy sprockets, axles, and gears. If they spend \(\frac{2}{3}\) of the budget on sprockets, how much money from the budget remains to buy axles and gears?
Answer:
It is given that
Nyan Robotics has a budget of $99 to buy sprockets, axles, and gears and they spend \(\frac{2}{3}\) of the budget on sprockets
Now,
The given table is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 28.1
Now,
The amount of budget remaining after they spent on sprockets to buy axles and gears = \(\frac{2}{3}\) × $99
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The amount of budget remaining after they spent on sprockets to buy axles and gears is: $66

3-Act Mathematical Modeling: Stocking Up

3-ACT MATH

Stocking UP

ACT 1

Question 1.
After watching the video, what is the first question that comes to mind?
Answer:

Question 2.
Write the Main Question you will answer.
Answer:

Question 3.
Construct Arguments Predict an answer to this Main Question. Explain your prediction.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26.1
Answer:

Question 4.
On the number line below, write a number that is too small to be the answer. Write a number that is too large.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26.2
Answer:

Question 5.
Plot your prediction on the same number line.
Answer:

ACT 2

Question 6.
What information in this situation would be helpful to know? How would you use that information?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26.5
Answer:

Question 7.
Use Appropriate Tools What tools can you use to solve the problem? Explain how you would use them strategically.
Answer:

Question 8.
Model with Math Represent the situation using mathematics. Use your representation to answer the Main Question.
Answer:

Question 9.
What is your answer to the Main Question? Is it higher or lower than your prediction? Explain why.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26.6
Answer:

ACT 3

Question 10.
Write the answer you saw in the video.
Answer:

Question 11.
Reasoning Does your answer match the answer in the video? If not, what are some reasons that would explain the difference?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26.7
Answer:

Question 12.
Make Sense and Persevere Would you change your model now that you know the answer? Explain.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26.8
Answer:

Reflect

Question 13.
Model with Math Explain how you used a mathematical model to represent the situation. How did the model help you answer the Main Question?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 26.9
Answer:

Question 14.
Reasoning How did you represent the situation using symbols? How did you use those symbols to solve the problem?
Answer:

SEQUEL

Question 15.
Model with Math
The store purchases boxes of pasta for $0.82 and cans of sauce for $1.62. How much profit does the store make from this purchase?
Answer:

Lesson 1.4 Understand Division with Fractions

ACTIVITY

Explore It!
Students are competing in a 4-kilometer relay race. There are 10 runners.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 30.1

A. Use the number line to represent the data for the race.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 30.2
Answer:
It is given that
Students are competing in a 4-kilometer relay race. There are 10 runners.
Now,
The given data is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 30.1
So,
From the given number line,
We can observe that
There are 10 runners and each runner runs \(\frac{2}{5}\) km and the finish line is at 4 km
Hence,
The representation of the given data in a number line is:

B. Use multiplication or division to describe your work on the number line.
Answer:
It is given that
Students are competing in a 4-kilometer relay race. There are 10 runners.
Now,
The given data is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 30.1
Now,
Using Multiplication,
The total distance covered by 10 runners = 10 × (The distance each runner runs)
= 10 × \(\frac{2}{5}\)
Now,
By using the Long Multiplication,

So,
The total distance covered by 10 runners is: 4 km

Focus on math practices
Model with Math
Describe what a number line would look like if there were 10 runners each running; kilometer in a 5-kilometer
race.
Answer:
It is given that
There were 10 runners each running; kilometer in a 5-kilometer race
So,
The total distance covered by 10 runners = 10 × (The distance each runner runs)
= 10 × \(\frac{1}{2}\)
Now,
By using the Long Multiplication,

So,
The total distance covered by 10 runners is: 5 km
Hence,
The representation of the given information in a number line is:

? Essential Question How can you represent the division of fractions?
Answer:
Interpret a fraction as a division of the numerator by the denominator (\(\frac{a}{b}\) = a ÷ b). Solve word problems involving the division of whole numbers leading to answers in the form of fractions or mixed numbers,
Ex: By using visual fraction models or equations to represent the problem.

Try It!
A board is 6 feet long. How many \(\frac{2}{3}\)-foot-long pieces can be cut from the board? Use the number line to show your work.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 102
Answer:
It is given that
A board is 6 feet long
So,
The number of \(\frac{2}{3}\)-foot-long pieces can be cut from the board = (The length of the board) ÷ \(\frac{2}{3}\)
= 6 ÷ \(\frac{2}{3}\)
= 6 × \(\frac{3}{2}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The number of \(\frac{2}{3}\)-foot-long pieces that can be cut from the board are: 9 pieces

Convince Me! Why is the number of pieces that can be cut from the board greater than the number of feet in the length of the board?
Answer:

Try It!
Make a diagram to find \(\frac{2}{3}\) ÷ 4.
Answer:
The given division expression is: \(\frac{2}{3}\) ÷ 4
Hence,
The representation of the given division expression in the form of an area model is:

Hence, from the above,
We can conclude that
\(\frac{2}{3}\) ÷ 4 = \(\frac{1}{6}\)

Try It!
Use the pattern in the table above to find 8 ÷ \(\frac{3}{4}\).
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 31.2
Answer:
The given division expression is: 8 ÷ \(\frac{3}{4}\)
So,
8 ÷ \(\frac{3}{4}\)
= 8 × \(\frac{4}{3}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that

KEY CONCEPT

To divide a whole number by a fraction:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 31.3
To divide a fraction by a whole number:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 31.4

Do You Understand?

Question 1.
? Essential Question How can you represent the division of fractions?
Answer:
Interpret a fraction as a division of the numerator by the denominator (\(\frac{a}{b}\) = a ÷ b). Solve word problems involving the division of whole numbers leading to answers in the form of fractions or mixed numbers,
Ex: By using visual fraction models or equations to represent the problem.

Question 2.
Reasoning Draw a diagram to represent 8 ÷ \(\frac{2}{3}\). Then write an equation to show the solution.
Answer:

Question 3.
Reasoning is 4 ÷ \(\frac{3}{2}\) the same as 4 ÷ \(\frac{2}{3}\)? Explain.
Answer:
The given division expressions are:
4 ÷ \(\frac{3}{2}\) and 4 ÷ \(\frac{2}{3}\)
So,
4 ÷ \(\frac{3}{2}\)
= 4 × \(\frac{2}{3}\)
So,
4 ÷ \(\frac{2}{3}\)
= 4 × \(\frac{3}{2}\)
Hence, from the above,
We can conclude that
4 ÷ \(\frac{3}{2}\) and 4 ÷ \(\frac{3}{2}\) are not the same

Question 4.
How can you write any nonzero whole number as a fraction?
Answer:
You can multiply the numerator and the denominator of a fraction by any nonzero whole number, as long as you multiply both by the same whole number

Question 5.
Look for Relationships How does the quotient compare to the dividend when the divisor is a fraction less than 1?
Answer:
When the divisor is less than 1, the quotient is larger than the dividend. Decreasing the divisor to \(\frac{1}{2}\) increases the quotient to \(\frac{1}{2}\). When the divisor is smaller than the dividend, the quotient is more than 1.

Question 6.
What division equation is represented by the diagram?
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 33.1
Answer:
The given diagram is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 33.1
Now,
From the given diagram,
We can observe that
The total number of equal parts are: 8
The number of shaded parts are: 6
So,
The division equation that is represented by the given diagram = (The number of shaded parts) ÷ (The total number of equal parts)
= \(\frac{6}{8}\)
= \(\frac{6 ÷ 2}{8 ÷ 2}\)
= \(\frac{3}{4}\)
Hence, from the above,
We can conclude that
The division equation that is represented by the given diagram is: \(\frac{3}{4}\)

Do You Know How?

In 7-14, find each reciprocal.

Question 7.
\(\frac{3}{5}\)
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of \(\frac{3}{5}\) is: \(\frac{5}{3}\)

Question 8.
\(\frac{1}{6}\)
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of \(\frac{1}{6}\) is: \(\frac{6}{1}\)

Question 9.
9
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of 9 is: \(\frac{1}{9}\)

Question 10.
\(\frac{7}{4}\)
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of \(\frac{7}{4}\) is: \(\frac{4}{7}\)

Question 11.
\(\frac{5}{8}\)
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of \(\frac{5}{8}\) is: \(\frac{8}{5}\)

Question 12.
16
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of 16 is: \(\frac{1}{16}\)

Question 13.
\(\frac{7}{12}\)
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of \(\frac{7}{12}\) is: \(\frac{12}{7}\)

Question 14.
\(\frac{11}{5}\)
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of \(\frac{11}{5}\) is: \(\frac{5}{11}\)

In 15-22, find each quotient.

Question 15.
6 ÷ \(\frac{2}{3}\)
Answer:
The given division equation is: 6 ÷ \(\frac{2}{3}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
6 ÷ \(\frac{2}{3}\) = 9
The quotient for the given division equation is: 9

Question 16.
12 ÷ \(\frac{3}{8}\)
Answer:
The given division equation is: 12 ÷ \(\frac{3}{8}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
12 ÷ \(\frac{3}{8}\) = 32
The quotient for the given division equation is: 32

Question 17.
\(\frac{1}{4}\) ÷ 3
Answer:
The given division equation is: \(\frac{1}{4}\) ÷ 3
So,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{1}{4}\) ÷ 3 = \(\frac{1}{12}\)
The quotient for the given division equation is: \(\frac{1}{12}\)

Question 18.
\(\frac{2}{5}\) ÷ 2
Answer:
The given division equation is: \(\frac{2}{5}\) ÷ 2
So,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{2}{5}\) ÷ 2 = \(\frac{1}{5}\)
The quotient for the given division equation is: \(\frac{1}{5}\)

Question 19.
2 ÷ \(\frac{1}{2}\)
Answer:
The given division equation is: 2 ÷ \(\frac{1}{2}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
2 ÷ \(\frac{1}{2}\) = 4
The quotient for the given division equation is: 4

Question 20.
3 ÷ \(\frac{1}{4}\)
Answer:
The given division equation is: 2 ÷ \(\frac{1}{2}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
2 ÷ \(\frac{1}{2}\) = 4
The quotient for the given division equation is: 4

Question 21.
9 ÷ \(\frac{3}{5}\)
Answer:
The given division equation is: 9 ÷ \(\frac{3}{5}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
9 ÷ \(\frac{3}{5}\) = 15
The quotient for the given division equation is: 15

Question 22.
5 ÷ \(\frac{2}{7}\)
Answer:
The given division equation is: 5 ÷ \(\frac{2}{7}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
5 ÷ \(\frac{2}{7}\) = \(\frac{35}{2}\)
The quotient for the given division equation is: \(\frac{35}{2}\)

Practice & Problem Solving

Scan for Multimedia

Leveled Practice In 23 and 24, complete each division sentence.

Question 23.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 40.1
The number line shows 6 wholes.
Answer:
The given number line is:

Hence, from the above,
We can conclude that
The completed division sentence is:

Question 24.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 40.2
Answer:
The given diagram is:

Hence, from the above,
We can conclude that
The completed division sentence is:

In 25 and 26, find each quotient. Draw a diagram to help.

Question 25.
\(\frac{3}{5}\) ÷ 3
Answer:
The given division equation is:
\(\frac{3}{5}\) ÷ 3
Now,
The representation of the given division equation in the form of an area model is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{3}{5}\) ÷ 3 = \(\frac{1}{5}\)
The quotient for the given division equation is: \(\frac{1}{5}\)

Question 26.
2 ÷ \(\frac{2}{5}\)
Answer:
The given division equation is:
2 ÷ \(\frac{2}{5}\)
Now,
The representation of the given division equation in the form of an area model is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2 ÷ \(\frac{2}{5}\) = 5
The quotient for the given division equation is: 5

In 27-30, find each reciprocal.

Question 27.
\(\frac{3}{10}\)
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of \(\frac{3}{10}\) is: \(\frac{10}{3}\)

Question 28.
6
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of 6 is: \(\frac{1}{6}\)

Question 29.
\(\frac{1}{15}\)
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of \(\frac{1}{15}\) is: 15

Question 30.
3
Answer:
We know that,
Two numbers whose product is “1” are called “Reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
Hence, from the above,
We can conclude that
The reciprocal of 3 is: \(\frac{1}{3}\)

In 31-38, find each quotient.

Question 31.
36 ÷ \(\frac{3}{4}\)
Answer:
The given division equation is: 36 ÷ \(\frac{3}{4}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
36 ÷ \(\frac{3}{4}\) = 48
The quotient for the given division equation is: 48

Question 32.
2 ÷ \(\frac{3}{8}\)
Answer:
The given division equation is: 2 ÷ \(\frac{3}{8}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
2 ÷ \(\frac{3}{8}\) = \(\frac{16}{3}\)
The quotient for the given division equation is: \(\frac{16}{3}\)

Question 33.
18 ÷ \(\frac{2}{3}\)
Answer:
The given division equation is: 18 ÷ \(\frac{2}{3}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
18 ÷ \(\frac{2}{3}\) = 27
The quotient for the given division equation is: 27

Question 34.
9 ÷ \(\frac{4}{5}\)
Answer:
The given division equation is: 9 ÷ \(\frac{4}{5}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
9 ÷ \(\frac{4}{5}\) = \(\frac{45}{4}\)
The quotient for the given division equation is: \(\frac{45}{4}\)

Question 35.
\(\frac{1}{6}\) ÷ 2
Answer:
The given division equation is: \(\frac{1}{6}\) ÷ 2
So,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{1}{6}\) ÷ 2 = \(\frac{1}{12}\)
The quotient for the given division equation is: \(\frac{1}{12}\)

Question 36.
\(\frac{2}{3}\) ÷ 3
Answer:
The given division equation is: \(\frac{2}{3}\) ÷ 3
So,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{2}{3}\) ÷ 3 = \(\frac{2}{9}\)
The quotient for the given division equation is: \(\frac{2}{9}\)

Question 37.
\(\frac{3}{5}\) ÷ 2
Answer:
The given division equation is: \(\frac{3}{5}\) ÷ 2
So,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{3}{5}\) ÷ 2 = \(\frac{3}{10}\)
The quotient for the given division equation is: \(\frac{3}{10}\)

Question 38.
\(\frac{1}{4}\) ÷ 4
Answer:
The given division equation is: \(\frac{1}{4}\) ÷ 4
So,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{1}{4}\) ÷ 4 = \(\frac{1}{16}\)
The quotient for the given division equation is: \(\frac{1}{16}\)

Question 39.
A worker is pouring 3 quarts of liquid into \(\frac{3}{8}\)-quart containers. How many of the containers can she fill? Write and solve a division equation.
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 49.1
Answer:
It is given that
A worker is pouring 3 quarts of liquid into \(\frac{3}{8}\)-quart containers
So,
The number of containers she can fill = (The number of quarts of liquid a worker poured) ÷ (The size of each container)
= 3 ÷ \(\frac{3}{8}\)
Now,
By using the Long Division,

In 40-43, use the given information.

Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 40.3

Question 40.
Higher-Order Thinking Without doing any calculations, how can you use the information given to tell which animal moves the fastest?
Answer:
The given information is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 40.3
Now,
The distance covered by a snail in 1 hour = 120 ÷ \(\frac{3}{4}\)
So,
By using the Long Division,

So,
The distance covered by a snail in 1 hour is: 160 ft
Now,
The distance covered by a tortoise in 1 hour = 600 ÷ \(\frac{2}{3}\)
So,
By using the Long Division,

So,
The distance covered by a tortoise in 1 hour is: 900 ft
Now,
The distance covered by a Sloth in 1 hour = 250 ÷ \(\frac{5}{8}\)
So,
By using the Long Division,

So,
The distance covered by a Sloth in 1 hour is: 400 ft
Hence, from the above,
We can conclude that
The animal which moves the fastest is: Tortoise

Question 41.
Reasoning The quotient 250 ÷ \(\frac{5}{8}\) tells about how far a sloth may move in one hour. How far can a sloth go in 90 minutes? Justify your reasoning.
Answer:
It is given that
The quotient 250 ÷ \(\frac{5}{8}\) tells about how far a sloth may move in one hour
Now,
We know that,
1 hour = 60 minutes
1\(\frac{1}{2}\) hour = 90 minutes
So,
The representation of 1\(\frac{1}{2}\) into a fraction is:

So,
The distance covered by a Sloth in 90 minutes = 250 ÷ \(\frac{3}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The distance covered by a Sloth in 90 minutes is: \(\frac{500}{3}\) ft

Question 42.
The quotient 600 ÷ \(\frac{2}{3}\) tells about how far a tortoise may move in one hour. Find that distance.
Answer:
It is given that
The quotient 600 ÷ \(\frac{2}{3}\) tells about how far a tortoise may move in one hour
Now,
According to the given information,
The distance covered by a tortoise in 1 hour = 600 ÷ \(\frac{2}{3}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
The distance covered by a tortoise in 1 hour is: 900 ft

Question 43.
Write and solve an equation to find how far a snail can go in one hour.
Answer:
The given information is:
Envision Math Common Core 6th Grade Answers Topic 1 Use Positive Rational Numbers 40.3
Now,
The distance covered by a snail in 1 hour = 120 ÷ \(\frac{3}{4}\)
So,
By using the Long Division,

Hence, from the above,
We can conclude that
The distance covered by a snail in 1 hour is: 160 ft

Question 44.
A waitress pours \(\frac{3}{4}\) gallon of orange juice equally into 5 pitchers. What fraction of a gallon of orange juice is in each pitcher? Use the rectangle to represent the problem. Then write an equation to show the solution.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 41.3
Answer:
It is given that
A waitress pours \(\frac{3}{4}\) gallon of orange juice equally into 5 pitchers.
Now,
The representation of the given information in the form of an Area model is:

Now,
Let the fraction of a gallon of orange juice that is present in each pitcher be x
So,
According to the given information,
5 ÷ x = \(\frac{3}{4}\)
So,
x = 5 ÷ \(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The fraction of a gallon of orange juice that is present in each pitcher is: \(\frac{20}{3}\) gallons

Assessment Practice

Question 45.
Select all the math statements that have the same quotient.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 54 12 ÷ \(\frac{2}{3}\)
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 54 \(\frac{2}{3}\) ÷ \(\frac{1}{27}\)
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 54 16 ÷ \(\frac{4}{5}\)
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 54 12 ÷ \(\frac{3}{2}\)
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 54 24 ÷ \(\frac{4}{3}\)
Answer:
The given math statements and their quotients are:
a. 12 ÷ \(\frac{2}{3}\)
Now,
By using the Long Division,

b. \(\frac{2}{3}\) ÷ \(\frac{1}{27}\)
Now,
By using the Long Division,

c. 16 ÷ \(\frac{4}{5}\)
Now,
By using the Long Division,

d. 12 ÷ \(\frac{3}{2}\)
Now,
By using the Long Division,

e. 24 ÷ \(\frac{4}{3}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
All the math statements that have the same quotient are:

Question 46.
Select all the math statements that are true.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 55.1
Answer:
All the math statements that are true are:

Lesson 1.5 Divide Fractions by Fractions

ACTIVITY

Solve & Discuss It!

A granola bar was cut into 6 equal pieces. Someone ate part of the granola bar so that \(\frac{2}{3}\) of the original bar remains. How many \(\frac{1}{6}\) parts are left? Use the picture to draw a model to represent and find \(\frac{2}{3}\) ÷ \(\frac{1}{6}\)

Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 55.2
Answer:
It is given that
A granola bar was cut into 6 equal pieces. Someone ate part of the granola bar so that \(\frac{2}{3}\) of the original bar remains
Now,
The given picture is:

Now,
The representation of the given information in the form of a bar diagram is:

Now,
The number of \(\frac{1}{6}\) parts that are left = (The part that is remained in the original granola bar) ÷ \(\frac{1}{6}\)
= \(\frac{2}{3}\) ÷ \(\frac{1}{6}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of \(\frac{1}{6}\) parts that are left is: 4

A model with Math
You can model with math by dividing a whole into equal parts.
Answer:
The representation of the above problem in the form of a bar diagram is:

Focus on math practices
Use Structure How can you use multiplication to check your answer?
Answer:
You can use multiplication to check your division answer the following way:
a. Do the division problem.
b. Multiply the quotient times the divisor.
c. If there is a remainder, add it to the multiplication product.
d. Compare this answer to the dividend. They should be the same number

? Essential Question How can you divide a fraction by a fraction?
Answer:
The easiest way to divide fractions is to follow three simple steps:
a. Flip the divisor into a reciprocal.
b. Change the division sign into a multiplication sign and multiply.
c. Simplify if possible.

Try It!
Use the number line below to represent \(\frac{1}{6}\) × 3 = \(\frac{1}{2}\). Then write an equivalent division sentence.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 55.3
Answer:
The given multiplication equation is:
\(\frac{1}{6}\) × 3 = \(\frac{1}{2}\)
So,
The representation of the given division equation in the given number line is:

Now,
The representation of the given multiplication equation into division equation is:
\(\frac{1}{2}\) ÷ \(\frac{1}{6}\) = 3
Hence, from the above,
We can conclude that
The equivalent division equation for the given multiplication equation is:
\(\frac{1}{2}\) ÷ \(\frac{1}{6}\) = 3

Convince Me! How are the dividend, divisor, and quotient represented on the number line?
Answer:
In a number line,
The dividend represents the “Product”
The divisor represents the “The division of the dividend into equal parts”
The quotient represents the “The number of times the divisor divided”

Try It!
Find \(\frac{1}{4}\) ÷ \(\frac{3}{8}\). Draw an area model.
Answer:
The given division expression is: \(\frac{1}{4}\) ÷ \(\frac{3}{8}\)
Hence,
The representation of the given division expression by using the area model is:

Try It!
How wide is a rectangular strip of land with a length of \(\frac{3}{4}\) mile and an area of \(\frac{1}{2}\) square mile? Use the area formula: A = l × w.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 55.4
Answer:
It is given that
The length of a rectangular strip is \(\frac{3}{4}\) mile and an area of a rectangular strip is \(\frac{1}{2}\) square mile
Now,
It is given that
Area (A) = Length (L) × Width (W)
So,
\(\frac{1}{2}\) = \(\frac{3}{4}\) × Width (W)
Width (W) = \(\frac{1}{2}\) ÷ \(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that

KEY CONCEPT

To divide a fraction by a fraction, rewrite the division equation as a multiplication equation.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.1

Do You Understand?

Question 1.
?Essential Question How can you divide a fraction by a fraction?
Answer:
The easiest way to divide fractions is to follow three simple steps:
a. Flip the divisor into a reciprocal.
b. Change the division sign into a multiplication sign and multiply.
c. Simplify if possible.

Question 2.
Critique Reasoning To find the quotient of \(\frac{2}{5}\) ÷ \(\frac{8}{5}\), Corey rewrites the problem as \(\frac{5}{2}\) × \(\frac{8}{5}\). Explain Corey’s mistake and how to correct it.
Answer:
It is given that
To find the quotient of \(\frac{2}{5}\) ÷ \(\frac{8}{5}\), Corey rewrites the problem as \(\frac{5}{2}\) × \(\frac{8}{5}\)
Now,
The given division expression is: \(\frac{2}{5}\) ÷ \(\frac{8}{5}\)
Now,
We know that,
We have to find the reciprocal of a fraction that is present to the right side of the division symbol
So,
\(\frac{2}{5}\) ÷ \(\frac{8}{5}\)
= \(\frac{2}{5}\) × \(\frac{5}{8}\)
Hence, from the above,
We can conclude that
Corey’s mistake is: He found the reciprocal of a fraction that is present to the left side of the division symbol instead of the right side of the division symbol
The correct form of the given division expression is:
\(\frac{2}{5}\) × \(\frac{5}{8}\)

Question 3.
Reasoning is the quotient of \(\frac{3}{5}\) ÷ \(\frac{6}{7}\) greater than or less than \(\frac{3}{5}\)? Explain.
Answer:
The given division expression is: \(\frac{3}{5}\) ÷ \(\frac{6}{7}\)
Now,
The representation of the given division expression in the decimal form is:
\(\frac{3}{5}\) ÷ \(\frac{6}{7}\)
= 0.60 ÷ 0.85
Now,
By using the Long Division,

So,
The representation of the quotient value for the given divison expression in the decimal form is: 0.7
Hence, from the above,
We can conclude that
The quotient of \(\frac{3}{5}\) ÷ \(\frac{6}{7}\) is greater than \(\frac{3}{5}\)

Question 4.
How is dividing a whole number by a fraction different from dividing a fraction by a fraction?
Answer:
The steps to divide a fraction by a Whole Number are:
1. Turn the whole number into a fraction.
2. Multiply the fraction by the whole number fraction.
3. Multiply the tops together and the bottoms together
The steps to divide a fraction by a fraction are:
1. Arrange the equation
2. Keep the first fraction
3. Change the sign
4. Flip the fraction
5. Multiply the tops together and the bottoms together

Do You Know How?

In 5–7, write a division sentence to represent each model.

Question 5.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.2
Answer:
The given model is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.2
Now,
From the given model,
We can observe that
The division sentence to represent the given model is:
\(\frac{4}{5}\) ÷ 4
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The division sentence to represent the given model is:
\(\frac{4}{5}\) ÷ 4

Question 6.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.3
Answer:
The given model is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.3
Now,
From the given model,
We can observe that
The division sentence to represent the given model is:
\(\frac{1}{2}\) ÷ \(\frac{2}{3}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The division sentence to represent the given model is:
\(\frac{1}{2}\) ÷ \(\frac{2}{3}\)

Question 7.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.4
Answer:
The given model is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.4
Now,
From the given model,
We can observe that
The division sentence for the given model is:
\(\frac{3}{4}\) ÷ \(\frac{1}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The division sentence for the given model is:
\(\frac{3}{4}\) ÷ \(\frac{1}{8}\)

In 8-11, find each quotient.

Question 8.
\(\frac{3}{4}\) ÷ \(\frac{2}{3}\)
Answer:
The given division expression is:
\(\frac{3}{4}\) ÷ \(\frac{2}{3}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{3}{4}\) ÷ \(\frac{2}{3}\) = \(\frac{9}{8}\)
The quotient for the given division expression is: \(\frac{9}{8}\)

Question 9.
\(\frac{3}{12}\) ÷ \(\frac{1}{8}\)
Answer:
The given division expression is:
\(\frac{3}{12}\) ÷ \(\frac{1}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{3}{12}\) ÷ \(\frac{1}{8}\) = 2
The quotient for the given division expression is: 2

Question 10.
\(\frac{1}{2}\) ÷ \(\frac{4}{5}\)
Answer:
The given division expression is:
\(\frac{1}{2}\) ÷ \(\frac{4}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{1}{2}\) ÷ \(\frac{4}{5}\) = \(\frac{5}{8}\)
The quotient for the given division expression is: \(\frac{5}{8}\)

Question 11.
\(\frac{7}{10}\) ÷ \(\frac{2}{5}\)
Answer:
The given division expression is:
\(\frac{7}{10}\) ÷ \(\frac{2}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{7}{10}\) ÷ \(\frac{2}{5}\) = \(\frac{7}{4}\)
The quotient for the given division expression is: \(\frac{7}{4}\)

Practice & Problem Solving

Scan for Multimedia

In 12 and 13, complete each division sentence using the models provided.

Question 12.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.5
Answer:
The given division expression is:
\(\frac{1}{3}\) ÷ \(\frac{1}{12}\)
Now,
The given model is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{1}{3}\) ÷ \(\frac{1}{12}\) = 4

Question 13.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 56.6
Answer:
The given division expression is:
\(\frac{2}{5}\) ÷ \(\frac{1}{10}\)
Now,
The given model is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{2}{5}\) ÷ \(\frac{1}{10}\) = 4

In 14-25, find each quotient.

Question 14.
\(\frac{2}{3}\) ÷ \(\frac{1}{3}\)
Answer:
The given division expression is:
\(\frac{2}{3}\) ÷ \(\frac{1}{3}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{2}{3}\) ÷ \(\frac{1}{3}\) = 2
The quotient for the given division expresion is: 2

Question 15.
\(\frac{1}{2}\) ÷ \(\frac{1}{16}\)
Answer:
The given division expression is:
\(\frac{1}{2}\) ÷ \(\frac{1}{16}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{1}{2}\) ÷ \(\frac{1}{16}\) = 8
The quotient for the given division expresion is: 8

Question 16.
\(\frac{1}{4}\) ÷ \(\frac{1}{12}\)
Answer:
The given division expression is:
\(\frac{1}{4}\) ÷ \(\frac{1}{12}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{1}{4}\) ÷ \(\frac{1}{12}\) = 3
The quotient for the given division expresion is: 3

Question 17.
\(\frac{6}{7}\) ÷ \(\frac{3}{7}\)
Answer:
The given division expression is:
\(\frac{6}{7}\) ÷ \(\frac{3}{7}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{6}{7}\) ÷ \(\frac{3}{7}\) = 2
The quotient for the given division expresion is: 2

Question 18.
\(\frac{5}{14}\) ÷ \(\frac{4}{7}\)
Answer:
The given division expression is:
\(\frac{5}{14}\) ÷ \(\frac{4}{7}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{5}{14}\) ÷ \(\frac{4}{7}\) = \(\frac{5}{8}\)
The quotient for the given division expresion is: \(\frac{5}{8}\)

Question 19.
\(\frac{5}{8}\) ÷ \(\frac{1}{2}\)
Answer:
The given division expression is:
\(\frac{5}{8}\) ÷ \(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{5}{8}\) ÷ \(\frac{1}{2}\) = \(\frac{5}{4}\)
The quotient for the given division expresion is: \(\frac{5}{4}\)

Question 20.
\(\frac{7}{12}\) ÷ \(\frac{3}{4}\)
Answer:
The given division expression is:
\(\frac{7}{12}\) ÷ \(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{7}{12}\) ÷ \(\frac{3}{4}\) = \(\frac{7}{9}\)
The quotient for the given division expresion is: \(\frac{7}{9}\)

Question 21.
\(\frac{2}{7}\) ÷ \(\frac{1}{2}\)
Answer:
The given division expression is:
\(\frac{2}{7}\) ÷ \(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{2}{7}\) ÷ \(\frac{1}{2}\) = \(\frac{4}{7}\)
The quotient for the given division expresion is: \(\frac{4}{7}\)

Question 22.
\(\frac{3}{10}\) ÷ \(\frac{3}{5}\)
Answer:
The given division expression is:
\(\frac{3}{10}\) ÷ \(\frac{3}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{3}{10}\) ÷ \(\frac{3}{5}\) = \(\frac{1}{2}\)
The quotient for the given division expresion is: \(\frac{1}{2}\)

Question 23.
\(\frac{7}{12}\) ÷ \(\frac{1}{8}\)
Answer:
The given division expression is:
\(\frac{7}{12}\) ÷ \(\frac{1}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{7}{12}\) ÷ \(\frac{1}{8}\) = \(\frac{14}{3}\)
The quotient for the given division expresion is: \(\frac{14}{3}\)

Question 24.
\(\frac{3}{10}\) ÷ \(\frac{3}{5}\)
Answer:
The given division expression is:
\(\frac{3}{10}\) ÷ \(\frac{3}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{3}{10}\) ÷ \(\frac{3}{5}\) = \(\frac{1}{2}\)
The quotient for the given division expresion is: \(\frac{1}{2}\)

Question 25.
\(\frac{2}{5}\) ÷ \(\frac{1}{8}\)
Answer:
The given division expression is:
\(\frac{2}{5}\) ÷ \(\frac{1}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{2}{5}\) ÷ \(\frac{1}{8}\) = \(\frac{16}{5}\)
The quotient for the given division expresion is: \(\frac{16}{5}\)

Question 26.
Be Precise A large bag contains \(\frac{12}{15}\) pound of granola. How many \(\frac{1}{3}\) pound bags can be filled with this amount of granola? How much granola is left over?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 103
Answer:
It is given that
A large bag contains \(\frac{12}{15}\) pound of granola
Now,
Let the number of \(\frac{1}{3}\) pound bags that can be filled with the given amount of granola be: x
Now,
According to the given information,
\(\frac{1}{3}\) × x = \(\frac{12}{15}\)
x = \(\frac{12}{15}\) ÷ \(\frac{1}{3}\)
Now,
By using the Long Division,

So,
The number of \(\frac{1}{3}\) pound bags that can be filled with the given amount of granola is about 2 bags
Now,
The amount of granola that is leftover = (The number of \(\frac{1}{3}\) pound bags that can be filled with the given amount of granola) – (The total amount of granola)
= \(\frac{12}{5}\) – \(\frac{12}{15}\)
Now,
By using the Long Subtraction,

Hence, from the above,
We can conclude that
The amount of granola that is leftover is: \(\frac{8}{5}\) pounds

Question 27.
Higher-Order Thinking Find \(\frac{3}{4}\) ÷ \(\frac{2}{3}\). Then draw a picture and write an explanation describing how to get the answer.
Answer:
The given division expression is:
\(\frac{3}{4}\) ÷ \(\frac{2}{3}\)
Now,
By using the Long Division,

Hence,
The representation of the given division expression in the form of an area model is:

\(\frac{3}{4}\) ÷ \(\frac{2}{3}\) = \(\frac{9}{8}\)

Question 28.
The area of a rectangular painting is \(\frac{1}{6}\) square yard. The width is \(\frac{2}{3}\) yard. What is the length of the painting? Use the formula A = l × w.
Answer:
It is given that
The area of a rectangular painting is \(\frac{1}{6}\) square yard. The width is \(\frac{2}{3}\) yard.
Now,
Let the length of the painting be x yard
Now,
From the given information,
A = l × w
So,
\(\frac{1}{6}\) = x × \(\frac{2}{3}\)
x = \(\frac{1}{6}\) ÷ \(\frac{2}{3}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The length of the painting is: \(\frac{1}{4}\) yard

Question 29.
Solve for n in the equation \(\frac{13}{16}\) ÷ \(\frac{1}{6}\) = n.
Answer:
The given division expression is:
\(\frac{13}{16}\) ÷ \(\frac{1}{6}\) = n
Where,
‘n’ is the quotient for the given division expression
Now,
By using the Long Division,

So,
\(\frac{13}{16}\) ÷ \(\frac{1}{6}\) = \(\frac{39}{8}\)
Hence, from the above,
We can conclude that
The value of ‘n’ is: \(\frac{39}{8}\)

Question 30.
Model with Math
A cafeteria uses \(\frac{1}{6}\) pound of coffee to fill a large coffee dispenser. The cafeteria has \(\frac{2}{3}\) pound of coffee to use.
a. Complete the model at the right to find how many coffee dispensers the cafeteria can fill.
b. Write a division sentence that describes the model and tells how many dispensers can be filled.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 60.1
Answer:
It is given that
A cafeteria uses \(\frac{1}{6}\) pound of coffee to fill a large coffee dispenser. The cafeteria has \(\frac{2}{3}\) pound of coffee to use.
Now,
The representation of the given information in the form of a model is:

Now,
From the given model,
We can observe that
The number of coffee dispensers the cafeteria can fill = (The number of pounds of the coffee cafeteria has to use) ÷ (The number of pounds of the coffee a cafeteria has to use)
= \(\frac{2}{3}\) ÷ \(\frac{1}{6}\)
Now,
By using the Long division,

Hence, from the above,
We can conclude that
a. The model to find how many coffee dispensers the cafeteria can fill is:

b. The division sentence that describes the model and tells how many dispensers can be filled is:
\(\frac{2}{3}\) ÷ \(\frac{1}{6}\)

Question 31.
Model with Math A full load for a small truck to haul is \(\frac{2}{3}\) ton of gravel. The truck is hauling \(\frac{1}{2}\) ton of gravel.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 60.2
a. Complete the model below to find how much of a full load the truck is hauling.
b. Write a division sentence that describes the model and tells how much of a full load the truck is hauling.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 60.3
Answer:
It is given that
A full load for a small truck to haul is \(\frac{2}{3}\) ton of gravel. The truck is hauling \(\frac{1}{2}\) ton of gravel.
Now,
The representation of the given information in the form of a model is:

Now,
From the given model,
We can observe that
The amount of a full load the truck is hauling = (The amount of a full load for a small truck to haul) ÷ (The amount of gravel a truck is hauling)
= \(\frac{2}{3}\) ÷ \(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
a. The model below to find how much of a full load the truck is hauling is:

b. The division sentence describes the model and tells how much of a full load the truck is hauling is:
\(\frac{2}{3}\) ÷ \(\frac{1}{2}\)

Question 32.
Use Structure How many \(\frac{1}{4}\)-inch pieces can be cut from a piece of metal \(\frac{5}{4}\) inch long?
Answer:
It is given that
\(\frac{1}{4}\)-inch pieces can be cut from a piece of metal \(\frac{5}{4}\) inch long
So,
The number of \(\frac{1}{4}\)-inch pieces that can be cut from \(\frac{5}{4}\) inch long
= \(\frac{5}{4}\) ÷ \(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of \(\frac{1}{4}\)-inch pieces that can be cut from \(\frac{5}{4}\) inch long is: 5 pieces

Question 33.
Write a problem that could be solved by finding \(\frac{5}{8}\) ÷ \(\frac{2}{5}\).
Answer:
The given division expression is:
\(\frac{5}{8}\) ÷ \(\frac{2}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{5}{8}\) ÷ \(\frac{2}{5}\) = \(\frac{25}{16}\)

Assessment Practice

Question 34.
Which division sentence is shown by the model at the right?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 60.30
A. \(\frac{2}{3}\) ÷ \(\frac{1}{9}\) = 6
B. \(\frac{1}{9}\) ÷ \(\frac{2}{3}\) = \(\frac{1}{6}\)
C. 6 ÷ \(\frac{1}{9}\) = 54
D. 6 ÷ \(\frac{2}{3}\) = 9
Answer:
The given model is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 60.30
Now,
From the given model,
We can observe that
\(\frac{2}{3}\) ÷ \(\frac{1}{9}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The division sentence that is shown by the model is:

Lesson 1.6 Divide Mixed Numbers

Solve & Discuss It!

A jeweler has a 5\(\frac{1}{2}\)inch strip of silver wire that she is cutting into 1\(\frac{3}{8}\)-inch pieces. How many pieces can she make?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 60.4
Answer:
It is given that
A jeweler has a 5\(\frac{1}{2}\)inch strip of silver wire that she is cutting into 1\(\frac{3}{8}\)-inch pieces
So,
The number of pieces of silver wire she can make = (The total length of the silver wire) ÷ (The length of each cutting piece of the silver wire)
= 5\(\frac{1}{2}\) ÷ 1\(\frac{3}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of pieces of silver wire she can make is: 4 pieces

Generalize How can you use what you know about solving problems with fractions to find how many pieces the jeweler can make?
Answer:
The steps to solve problems with fractions with the help of what you know is:
a. Read the problem carefully.
b. Think about what it is asking us to do.
c. Think about the information we need.
d. Solve it.
e Simplify, if necessary.
f. Think about whether our solution makes sense (in order to check it).

Focus on math practices
Generalize Explain how to use estimation to check whether your answer is reasonable.
Answer:
To use estimation, you need to read and understand the problem. There will be clues in the problem to let you know if estimation is a good option for solving that specific problem. Estimating means finding an answer that is an approximate answer

? Essential Question How can you divide with mixed numbers?
Answer:
The steps to divide the mixed numbers are:
Step 1:
Make sure everything is in fraction form (mixed numbers need to be changed to improper fractions).
Step 2:
Flip the second fraction and change the operation to multiply.
Step 3:
Multiply across the top for the new numerator and across the bottom for the new denominator.
Step 4:
Simplify (if needed).

Try It!
How many medium bumper stickers can Damon fit side by side on his car bumper? Find 37\(\frac{1}{2}\) ÷ 10\(\frac{3}{4}\).
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 60.5
Answer:
The given information is:

Now,
The number of medium bumper stickers can Damon fit side by side on his car bumper = (The total length of the car bumper) ÷ (The length of the medium bumper)
= 37\(\frac{1}{2}\) ÷ 10\(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that

Convince Me! Why do you multiply \(\frac{75}{2}\) by \(\frac{4}{43}\) to divide 37\(\frac{1}{2}\) by 10\(\frac{3}{4}\)?
Answer:
The given division expression is:
37\(\frac{1}{2}\) ÷ 10\(\frac{3}{4}\)
Now,
The representation of the given mixed numbers into a fraction is:


So,
37\(\frac{1}{2}\) ÷ 10\(\frac{3}{4}\)
= \(\frac{75}{2}\) ÷ \(\frac{43}{4}\)
Now,
We know that,
Two numbers whose product is “1” are called “reciprocals” of each other. If a nonzero number is named as a fraction \(\frac{a}{b}\), then its reciprocal is \(\frac{b}{a}\)
So,
\(\frac{75}{2}\) ÷ \(\frac{43}{4}\)
= \(\frac{75}{2}\) × \(\frac{4}{43}\)
Hence, from the above,
We can conclude that
You can multiply \(\frac{75}{2}\) by \(\frac{4}{43}\) to divide 37\(\frac{1}{2}\) by 10\(\frac{3}{4}\) due to the property of “Reciprocals”

Try It!
Divide.

a. 20 ÷ 2\(\frac{2}{3}\)
Answer:
The given division expression is:
20 ÷ 2\(\frac{2}{3}\)
So,
The representtaion of 2\(\frac{2}{3}\) into a fraction is:

So,
20 ÷ \(\frac{8}{3}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
20 ÷ 2\(\frac{2}{3}\) = \(\frac{15}{2}\)

b. 12\(\frac{1}{2}\) ÷ 6
Answer:
The given division expression is:
12\(\frac{1}{2}\) ÷ 6
So,
The representation of 12\(\frac{1}{2}\) into a fraction is:

So,
\(\frac{25}{2}\) ÷ 6
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
12\(\frac{1}{2}\) ÷ 6 = \(\frac{25}{12}\)

KEY CONCEPT
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 60.6

Do You Understand?

Question 1.
? Essential Question How can you divide with mixed numbers?
Answer:
The steps to divide the mixed numbers are:
Step 1:
Make sure everything is in fraction form (mixed numbers need to be changed to improper fractions).
Step 2:
Flip the second fraction and change the operation to multiply.
Step 3:
Multiply across the top for the new numerator and across the bottom for the new denominator.
Step 4:
Simplify (if needed).

Question 2.
Generalize When dividing mixed numbers, why is it important to estimate the quotient first?
Answer:
You can estimate to find the approximate quotient of fractions and mixed numbers. Estimating quotients of fractions is similar to estimating products of fractions. To estimate the quotient of two fractions, you will first rewrite the problem as a multiplication problem

Question 3.
Reasoning In Example 1, how many long bumper stickers can Damon fit side by side on his car bumper? Will there be uncovered space? Explain.
Answer:
It is given that
The total length of the bumper is: 37\(\frac{1}{2}\) inches
Now,
The given information is:

Now,
From the given table,
We can observe that
The total length of the bumper = (The length of the short bumper) + (The length of the medium bumper) + (The length of the long bumper)
= 6\(\frac{1}{4}\) + 10\(\frac{3}{4}\) + 15
Now,
By using the Long Addition,

So,
The total length of the bumper = 17 + 15
= 32 inches
Now,
From the answer,
We can observe that
The given total length of the bumper > The calculated total length of the bumper
Hence, from the above,
We can conclude that there will be uncovered space in the bumper

Question 4.
What is the difference between dividing fractions less than 1 and dividing mixed numbers?
Answer:
Dividing mixed numbers is very similar to multiplying mixed numbers. You just add one step i.e., after changing the divisor into an improper fraction, you then find its reciprocal and multiply.

Do You Know How?

In 5–13, find each quotient.

Question 5.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 61.1
Answer:
The given division expression is:
2\(\frac{5}{8}\) ÷ 2\(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2\(\frac{5}{8}\) ÷ 2\(\frac{1}{4}\) = \(\frac{7}{8}\)
The quotient for the given division expression is: \(\frac{7}{6}\)

Question 6.
3 ÷ 4\(\frac{1}{2}\)
Answer:
The given division expression is:
3 ÷ 4\(\frac{1}{2}\)
Now,
The representation of 4\(\frac{1}{2}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
3 ÷ 4\(\frac{1}{2}\) = \(\frac{2}{3}\)
The quotient for the given division expression is: \(\frac{2}{3}\)

Question 7.
18 ÷ 3\(\frac{2}{3}\)
Answer:
The given division expression is:
18 ÷ 3\(\frac{2}{3}\)
Now,
The representation of 3\(\frac{2}{3}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
18 ÷ 3\(\frac{2}{3}\) = \(\frac{54}{11}\)
The quotient for the given division expression is: \(\frac{54}{11}\)

Question 8.
1\(\frac{2}{5}\) ÷ 7
Answer:
The given division expression is:
1\(\frac{2}{5}\) ÷ 7
Now,
The representation of 1\(\frac{2}{5}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
1\(\frac{2}{5}\) ÷ 7 = \(\frac{1}{5}\)
The quotient for the given division expression is: \(\frac{1}{5}\)

Question 9.
5 ÷ 6\(\frac{2}{5}\)
Answer:
The given division expression is:
5 ÷ 6\(\frac{2}{5}\)
Now,
The representation of 3\(\frac{2}{3}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
5 ÷ 6\(\frac{2}{5}\) = \(\frac{25}{32}\)
The quotient for the given division expression is: \(\frac{25}{32}\)

Question 10.
8\(\frac{1}{5}\) ÷ 3\(\frac{3}{4}\)
Answer:
The given division expression is:
8\(\frac{1}{5}\) ÷ 3\(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
8\(\frac{1}{5}\) ÷ 3\(\frac{3}{4}\) = \(\frac{164}{75}\)
The quotient for the given division expression is: \(\frac{164}{75}\)

Question 11.
2\(\frac{1}{2}\) ÷ 4\(\frac{1}{10}\)
Answer:
The given division expression is:
2\(\frac{1}{2}\) ÷ 4\(\frac{1}{10}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2\(\frac{1}{2}\) ÷ 4\(\frac{1}{10}\) = \(\frac{25}{41}\)
The quotient for the given division expression is: \(\frac{25}{41}\)

Question 12.
2\(\frac{2}{3}\) ÷ 6
Answer:
The given division expression is:
2\(\frac{2}{3}\) ÷ 6
Now,
The representation of 2\(\frac{2}{3}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2\(\frac{2}{3}\) ÷ 6 = \(\frac{4}{9}\)
The quotient for the given division expression is: \(\frac{4}{9}\)

Question 13.
6\(\frac{5}{9}\) ÷ 1\(\frac{7}{9}\)
Answer:
The given division expression is:
6\(\frac{5}{9}\) ÷ 1\(\frac{7}{9}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
6\(\frac{5}{9}\) ÷ 1\(\frac{7}{9}\) = \(\frac{59}{16}\)
The quotient for the given division expression is: \(\frac{59}{16}\)

Practice & Problem Solving

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Leveled Practice In 14-25, find each quotient.

Question 14.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 62.1
Answer:
The given division expression is:
10 ÷ 2\(\frac{1}{4}\)
Now,
The representation of 2\(\frac{1}{4}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
10 ÷ 2\(\frac{1}{4}\) = \(\frac{40}{9}\)
The quotient for the given division expression is: \(\frac{40}{9}\)

Question 15.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 67.2
Answer:
The given division expression is:
9\(\frac{1}{3}\) ÷ 6
Now,
The representation of 9\(\frac{1}{3}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
9\(\frac{1}{3}\) ÷ 6 = \(\frac{14}{9}\)
The quotient for the given division expression is: \(\frac{14}{9}\)

Question 16.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.3
Answer:
The given division expression is:
1\(\frac{3}{8}\) ÷ 4\(\frac{1}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
1\(\frac{3}{8}\) ÷ 4\(\frac{1}{8}\) = \(\frac{1}{3}\)
The quotient for the given division expression is: \(\frac{1}{3}\)

Question 17.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.4
Answer:
The given division expression is:
2\(\frac{2}{3}\) ÷ 8
Now,
The representation of 2\(\frac{2}{3}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2\(\frac{2}{3}\) ÷ 8 = \(\frac{1}{3}\)
The quotient for the given division expression is: \(\frac{1}{3}\)

Question 18.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.5
Answer:
The given division expression is:
4\(\frac{1}{3}\) ÷ 3\(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
4\(\frac{1}{3}\) ÷ 3\(\frac{1}{4}\) = \(\frac{4}{3}\)
The quotient for the given division expression is: \(\frac{4}{3}\)

Question 19.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.6
Answer:
The given division expression is:
1 ÷ 8\(\frac{5}{9}\)
Now,
The representation of 8\(\frac{5}{9}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
1 ÷ 8\(\frac{5}{9}\) = \(\frac{9}{77}\)
The quotient for the given division expression is: \(\frac{9}{77}\)

Question 20.
3\(\frac{5}{6}\) ÷ 9\(\frac{5}{6}\)
Answer:
The given division expression is:
3\(\frac{5}{6}\) ÷ 9\(\frac{5}{6}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
3\(\frac{5}{6}\) ÷ 9\(\frac{5}{6}\) = \(\frac{23}{59}\)
The quotient for the given division expression is: \(\frac{23}{59}\)

Question 21.
16 ÷ 2\(\frac{2}{3}\)
Answer:
The given division expression is:
16 ÷ 2\(\frac{2}{3}\)
Now,
The representation of 2\(\frac{2}{3}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
16 ÷ 2\(\frac{2}{3}\) = 6
The quotient for the given division expression is: 6

Question 22.
2\(\frac{5}{8}\) ÷ 13
Answer:
The given division expression is:
2\(\frac{5}{8}\) ÷ 13
Now,
The representation of 2\(\frac{5}{8}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2\(\frac{5}{8}\) ÷ 13 = \(\frac{21}{104}\)
The quotient for the given division expression is: \(\frac{21}{104}\)

Question 23.
3\(\frac{6}{7}\) ÷ 6\(\frac{3}{4}\)
Answer:
The given division expression is:
3\(\frac{6}{7}\) ÷ 6\(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
3\(\frac{6}{7}\) ÷ 6\(\frac{3}{4}\) = \(\frac{4}{7}\)
The quotient for the given division expression is: \(\frac{4}{7}\)

Question 24.
2\(\frac{1}{3}\) ÷ 1\(\frac{1}{3}\)
Answer:
The given division expression is:
2\(\frac{1}{3}\) ÷ 1\(\frac{1}{3}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2\(\frac{1}{3}\) ÷ 1\(\frac{1}{3}\) = \(\frac{7}{4}\)
The quotient for the given division expression is: \(\frac{7}{4}\)

Question 25.
3\(\frac{3}{4}\) ÷ 1\(\frac{1}{2}\)
Answer:
The given division expression is:
3\(\frac{3}{4}\) ÷ 1\(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
3\(\frac{3}{4}\) ÷ 1\(\frac{1}{2}\) = \(\frac{5}{2}\)
The quotient for the given division expression is: \(\frac{5}{2}\)

Question 26.
Beth is making a rope ladder. Each step of the ladder is 2\(\frac{1}{3}\), feet wide. Beth has a rope that is 21 feet long. How many steps can she make from the rope?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.11
Answer:
It is given that
Beth is making a rope ladder. Each step of the ladder is 2\(\frac{1}{3}\), feet wide. Beth has a rope that is 21 feet long
So,
The number of steps Berth can make from the rope = (The total length of the rope) ÷ (The length of each step of the ladder)
= 21 ÷ 2\(\frac{1}{3}\)
Now,
The representation of 2\(\frac{1}{3}\) into a fraction form is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of steps Berth can make from the rope is: 9 steps

Question 27.
The area of this rectangle is 257\(\frac{1}{4}\) in.2. Find side length w.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.12
Answer:
It is given that
The area of this rectangle is 257\(\frac{1}{4}\) in.2
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.12
Now,
We know that,
The area of a rectangle = Length × Width
So,
257\(\frac{1}{4}\) = 10\(\frac{1}{2}\) × w
w = 257\(\frac{1}{4}\) ÷ 10\(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The side length (w) of the given rectangle is: \(\frac{49}{2}\) in.

In 28 and 29, use the picture.

Question 28.
The larger room is twice as long as the smaller room. How long is the larger room?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.13
Answer:
It is given that
The larger room is twice as long as the smaller room.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.13
So,
The length of the larger room = 2 × (The length of the smaller room)
= 2 × 20\(\frac{4}{5}\)
Now,
The representation of 20\(\frac{4}{5}\) into a fraction is:

Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The length of the larger room is: \(\frac{208}{5}\) feet

Question 29.
If the length of the smaller room is divided into 4 equal parts, how long is each part?
Answer:
It is given that
The length of the smaller room is divided into 4 equal parts
So,
According to the given information,
The length of each part in the smaller room = 20\(\frac{4}{5}\) ÷ 4
Now,
The representation of 20\(\frac{4}{5}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The length of each part in the smaller room is: [latx]\frac{26}{5}[/latex] feet

Question 30.
Make Sense and Persevere Luis has 3 pounds of ground turkey to make turkey burgers. He uses \(\frac{3}{8}\) pound per burger to make 6 burgers. How many \(\frac{1}{4}\)-pound burgers can Luis make with the remaining turkey?
Answer:
It is given that
Luis has 3 pounds of ground turkey to make turkey burgers. He uses \(\frac{3}{8}\) pound per burger to make 6 burgers
So,
The remaining amount of ground Turkey Luis has = 3 – \(\frac{3}{8}\)
Now,
By using the Long Subtraction,

So,
The remaining amount of ground turkey Luis has is: \(\frac{21}{8}\) pounds
Now,
The number of \(\frac{1}{4}\)-pound burgers can Luis make with the remaining turkey =
\(\frac{21}{8}\) ÷ \(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of \(\frac{1}{4}\)-pound burgers can Luis make with the remaining turkey is about 11 burgers

Question 31.
Higher Order Thinking If 9 × \(\frac{n}{5}\) = 9 ÷ \(\frac{n}{5}\), then what does n equal? Explain.
Answer:
It is given that
9 × \(\frac{n}{5}\) = 9 ÷ \(\frac{n}{5}\)
So,
According to the Property of Reciprocals,
9 × \(\frac{n}{5}\) = 9 ÷ \(\frac{n}{5}\)
9 × \(\frac{n}{5}\) = 9 × \(\frac{5}{n}\)
\(\frac{n}{5}\) = \(\frac{5}{n}\)
n × n = 5 × 5
n² = 25
n = \(\sqrt{25}\)
n = 5
Hence, from the above,
We can conclude that
The value of “n” is: 5

Question 32.
Margaret uses 1\(\frac{3}{4}\) teaspoons of key lime zest to make 12 key lime cupcakes. She wants to make 30 cupcakes. How much key lime zest will Margaret use?
Answer:
It is given that
Margaret uses 1\(\frac{3}{4}\) teaspoons of key lime zest to make 1\(\frac{1}{2}\) key lime cupcakes
Now,
Let the number of teaspoons of key lime zest to make 30 cupcakes be x
So,
1\(\frac{3}{4}\) × 12 = x × 30
Now,
The representation of 1\(\frac{3}{4}\) into a fraction is:

So,
x = \(\frac{7}{4}\) × \(\frac{12}{30}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The number of teaspoons of key lime zest to make 30 cupcakes is: \(\frac{7}{10}\) teaspoons of key lime zest

Question 33.
Use Structure A gem store in Fort Lauderdale received a shipment of 1\(\frac{1}{2}\) pounds of moonstone crystals. If these moonstone crystals were separated into 6 equal bags, how much would each bag weigh?
Answer:
It is given that
A gem store in Fort Lauderdale received a shipment of 1\(\frac{1}{2}\) pounds of moonstone crystals.
So,
The weight of each bag of moonstone crystals = (The total weight of moonstone crystals) ÷ (The number of bags that moonstone crystals equally divided)
= 1\(\frac{1}{2}\) ÷ 6
Now,
The representation of 1\(\frac{1}{2}\) into a fraction is:

Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The weight of each bag of moonstone crystals is: \(\frac{1}{4}\) pounds

Question 34.
The owner of an aquatic store used 17\(\frac{1}{2}\) gallons of water to fill aquariums. He put 5\(\frac{5}{6}\) gallons of water in each aquarium. How many aquariums did he fill?
Answer:
It is given that
The owner of an aquatic store used 17\(\frac{1}{2}\) gallons of water to fill aquariums. He put 5\(\frac{5}{6}\) gallons of water in each aquarium.
So,
The number of aquariums did he fill = (The total amount of water used to fill aquariums) ÷ (The amount of water in each aquarium)
= 17\(\frac{1}{2}\) ÷ 5\(\frac{5}{6}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of aquariums did he fill is: 3 aquariums

Question 35.
Write an explanation to a friend about how you would estimate 17\(\frac{1}{5}\) ÷ 3\(\frac{4}{5}\).
Answer:
The given division expression is:
17\(\frac{1}{5}\) ÷ 3\(\frac{4}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
17\(\frac{1}{5}\) ÷ 3\(\frac{4}{5}\) = \(\frac{86}{19}\)

Assessment Practice

Question 36.
A restaurant has 15\(\frac{1}{5}\) pounds of alligator meat to make tasty alligator dishes.
PART A
Each pot of alligator stew requires 2\(\frac{3}{8}\) pounds of alligator meat. Which solution shows how many pots of alligator stew can be made?
A. 36 pots; 15\(\frac{1}{5}\) × 2\(\frac{3}{8}\)
B. \(\frac{5}{32}\) pot; 2\(\frac{3}{8}\) ÷ 15\(\frac{1}{5}\)
C. 7 pots; 15\(\frac{1}{5}\) ÷ 2\(\frac{3}{8}\)
D. 6 pots; 15\(\frac{1}{5}\) ÷ 2\(\frac{3}{8}\)
Answer:
It is given that
A restaurant has 15\(\frac{1}{5}\) pounds of alligator meat to make tasty alligator dishes. Each pot of alligator stew requires 2\(\frac{3}{8}\) pounds of alligator meat
So,
The number of pots of alligator stew can be made = 15\(\frac{1}{5}\) ÷ 2\(\frac{3}{8}\)
Now,
By using the Long Division,

So,
The number of pots of alligator stew that can be made is about 6 pots
Hence, from the above,
We can conclude that
The solution that shows how many pots of alligator stew can be made is:

PART B
The restaurant could make a smaller pot of alligator stew that uses 1\(\frac{3}{5}\) pounds of alligator meat. How many smaller pots of alligator stew can be made than the larger pots?
Answer:
It is given that
The restaurant could make a smaller pot of alligator stew that uses 1\(\frac{3}{5}\) pounds of alligator meat
So,
The number of smaller pots of stew that can be made = 15\(\frac{1}{5}\) ÷ 1\(\frac{3}{5}\)
Now,
By using the Long Division,

So,
The number of smaller pots of stew that can be made is about 10 pots
Now,
From Part (A),
We can observe that
The number of larger pots of stew that can be made is about 6 pots
So,
The number of smaller pots more than the larger pots = 10 – 6
= 4 pots
Hence, from the above,
We can conclude that
The number of smaller pots more than the larger pots are: 4 pots

Lesson 1.7 Solve Problems with Rational Numbers

ACTIVITY

Explain It!
Jenna feeds her cat twice a day. She gives her cat \(\frac{3}{4}\) can of cat food each time. Jenna is having a friend take care of her cat for 5 days. To prepare, she bought 8 cans of cat food. Did Jenna buy enough cat food?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.18

A. What do you need to know before you can answer the question?
Answer:
It is given that
Jenna feeds her cat twice a day. She gives her cat \(\frac{3}{4}\) can of cat food each time. Jenna is having a friend take care of her cat for 5 days. To prepare, she bought 8 cans of cat food.
Hence,
The hidden question for the given information is:
How much food will be needed for Jenna’s cat for 5 days?

B. How can you determine which operations to use to solve the problem?
Answer:
It is given that
Jenna feeds her cat twice a day. She gives her cat \(\frac{3}{4}\) can of cat food each time. Jenna is having a friend take care of her cat for 5 days. To prepare, she bought 8 cans of cat food.
So,
The operations we will use to solve the given problem is:
a.
To find the total amount of food Jenna gives her cat ——> Multiplication
b.
To find the amount of food Jenna’s cat will need for 5 days ——->Multiplication
c.
To find the amount of food Jenna’s cat will need for 8 days ——-> Multiplication
d.
To know whether Jenna bought enough food or not ——> Comparison

Focus on math practices
Reasoning To find out whether she has enough cat food, Jenna multiplies, divides, and compares. Explain how Jenna may have solved the problem.
Answer:
The steps Jenna took to solve the given problem are:
a.
To find the total amount of food Jenna gives her cat ——> Multiplication
b.
To find the amount of food Jenna’s cat will need for 5 days ——->Multiplication
c.
To find the amount of food Jenna’s cat will need for 8 days ——-> Multiplication
d.
To know whether Jenna bought enough food or not ——> Comparison

?Essential Question How can you solve problems with rational numbers?
Answer:
We know that,
A “Rational number” is a number that can be written as a fraction.
Fractions, integers, and decimals are all rational numbers.
Example:
Fraction to Decimal:
\(\frac{1}{2}\) = 0.5
Decimal to Fraction:
a. 0.15= \(\frac{3}{20}\)
b. 15÷5=3
c. 100÷5=20

Try It!
The farmer decided that he ordered enough planks for an arena that measured 115\(\frac{1}{4}\) ft by 63\(\frac{1}{2}\) ft. Is he correct? Explain.
Answer:
It is given that
The farmer decided that he ordered enough planks for an arena that measured 115\(\frac{1}{4}\) ft by 63\(\frac{1}{2}\) ft.
So,
The perimeter of the arena = 2 × (115\(\frac{1}{4}\) + 63\(\frac{1}{2}\))
Now,
By using the Long Addition,

Now,
By using the Long Multiplication,

So,
The perimeter of the arena is: \(\frac{715}{2}\) ft
Now,
The number of 8\(\frac{1}{2}\)-foot planks needed = (The perimeter of the arena) ÷ 8\(\frac{1}{2}\)
= \(\frac{715}{2}\) ÷ 8\(\frac{1}{2}\)
Now,
By using the Long Division,

So,
The number of 8\(\frac{1}{2}\)-foot planks needed is about 47 planks
But,
It is given that
A farmer needed 130 8\(\frac{1}{2}\)-foot planks
So,
47 < 130
Hence, from the above,
We can conclude that
The farmer is not correct

Convince Me! What questions do you need to answer to solve the Try It!?
Answer:
The questions you need to answer to solve the Try It is:
a. The perimeter of the arena with the given length and width of the arena
b. The number of 8\(\frac{1}{2}\)-foot planks for the perimeter we find in part (a)

Try It!
The number of runners who finish the marathon is 320. Runners donate $2.50 for each mile they run. How much money is donated? Explain.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 65.18
Answer:
It is given that
The number of runners who finish the marathon is 320. Runners donate $2.50 for each mile they run
Now,
The total number of miles run by 320 runners = (The total length of the marathon) × 320
= 26.2 × 320
Now,
By using the Long Multiplication,

So,
The total number of miles run by 320 runners is: 8,384 miles
Now,
The amount of money donated = (The total number of miles run by 320 runners) × (The amount of money donated by each runner for each mile)
= 8,384 × $2.50
Now,
By using the Long Multiplication,

So,
The amount of money donated is: $20,960
Hence, from the above,
We can conclude that

KEY CONCEPT
When solving multistep problems with fractions or decimals:
• decide the steps to use to solve the problem.
• choose the correct operations.
• identify the information you need from the problem.
• correctly use the information.
• calculate accurately.
• interpret solutions and check that the answer is reasonable.

Do You Understand?

Question 1.
?Essential Question How can you solve problems with rational numbers?
Answer:
We know that,
A “Rational number” is a number that can be written as a fraction.
Fractions, integers, and decimals are all rational numbers.
Example:
Fraction to Decimal:
\(\frac{1}{2}\) = 0.5
Decimal to Fraction:
a. 0.15= \(\frac{3}{20}\)
b. 15÷5=3
c. 100÷5=20

Question 2.
Be Precise Meghan has 5\(\frac{1}{4}\) yards of fabric. She plans to use \(\frac{2}{3}\) of the fabric to make 4 identical backpacks. To find how much fabric she will use to make the backpacks, Meghan multiplies 5\(\frac{1}{4}\) by \(\frac{2}{3}\). What else does Meghan need to do to find how much fabric she needs for each backpack?
Answer:
It is given that
Meghan has 5\(\frac{1}{4}\) yards of fabric. She plans to use \(\frac{2}{3}\) of the fabric to make 4 identical backpacks. To find how much fabric she will use to make the backpacks, Meghan multiplies 5\(\frac{1}{4}\) by \(\frac{2}{3}\)
Now,
The amount of fabric needed to make 4 identical backpacks = (The amount of fabric she planned to use to make the backpacks) × (The total length of the fabric) × (The number of identical backpacks)
= \(\frac{2}{3}\) × 5\(\frac{1}{4}\) × 4
So,
Aside From the given information,
Meghan needed to multiply the number of identical backpacks to the result of \(\frac{2}{3}\) × 5\(\frac{1}{4}\)
Hence, from the above,
We can conclude that
To find how much fabric Meghan needs for each backpack,
Meghan needed to multiply the number of identical backpacks to the result of \(\frac{2}{3}\) × 5\(\frac{1}{4}\)

Question 3.
Critique Reasoning Each side of a square patio is 10.5 feet. The patio is made up of 1.5-foot by 1.5-foot square stones. What is the number of stones on the patio? Look at the solution below. Does it include all the steps needed to solve the problem? Explain.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.30
Answer:
It is given that
Each side of a square patio is 10.5 feet. The patio is made up of 1.5-foot by 1.5-foot square stones
Now,
We know that,
The area of a square = Side × Side
So,
The area of a square patio = 10.5 × 10.5
So,
The area of the square stones = 1.5 × 1.5
So,
The number of stones in the patio = (The area of a square patio) ÷ (The area of the square stones)
= (10.5 × 10.5) ÷ (1.5 × 1.5)
= 110.25 ÷ 2.25
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The given solution did not include all the steps needed to solve the given problem
The number of stones in the patio is: 49 stones

Do You Know How?

Question 4.
Devon records 4 hours of reality shows on her DVR. She records comedy shows for \(\frac{3}{8}\) of that amount of time. Devon watches all the reality and comedy shows in half-hour sittings.
a. Find the number of hours of comedy shows that Devon records.
Answer:
It is given that
Devon records 4 hours of reality shows on her DVR. She records comedy shows for \(\frac{3}{8}\) of that amount of time. Devon watches all the reality and comedy shows in half-hour sittings.
So,
The number of hours of comedy shows that Devon records = \(\frac{3}{8}\) × (The amount of time Devon records the reality shows on her DVR)
= \(\frac{3}{8}\) × 4
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
The number of hours of comedy shows that Devon records are: \(\frac{3}{2}\) hours

b. Find the total number of hours of reality and comedy shows that Devon records.
Answer:
It is given that
Devon records 4 hours of reality shows on her DVR. She records comedy shows for \(\frac{3}{8}\) of that amount of time. Devon watches all the reality and comedy shows in half-hour sittings.
Now,
From part (a),
We can observe that
The number of hours of comedy shows that Devon records are: \(\frac{3}{2}\) hours
So,
The total number of hours of reality and comedy shows that Devon records = (The number of hours of reality shows that Devon records) + (The number of hours of comedy shows that Devon records)
= \(\frac{3}{2}\) + 4
Now,
By using the Long Addition,

Hence, from the above,
We can conclude that
The total number of hours of reality and comedy shows that Devon records are: 5\(\frac{1}{2}\) hours

c. Find the number of half-hour sittings needed to watch all the shows.
Answer:
It is given that
Devon records 4 hours of reality shows on her DVR. She records comedy shows for \(\frac{3}{8}\) of that amount of time. Devon watches all the reality and comedy shows in half-hour sittings.
Now,
From part (b),
We can observe that
The total number of hours of reality and comedy shows that Devon records are: 5\(\frac{1}{2}\) hours
So,
The number of half-hour sittings needed to watch all the shows = (The total number of hours of reality and comedy shows that Devon records) ÷ \(\frac{1}{2}\)
= 5\(\frac{1}{2}\) ÷ \(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of half-hour sittings needed to watch all the shows is: 11 half-hour sittings

Question 5.
An auto mechanic earns $498.75 in 35 hours during the week. His pay is $2.50 more per hour on weekends. If he works 6 hours on the weekend in addition to 35 hours during the week, how much does he earn?
a. What questions do you need to answer to solve the problem?
Answer:
It is given that
An auto mechanic earns $498.75 in 35 hours during the week. His pay is $2.50 more per hour on weekends. If he works 6 hours on the weekend in addition to 35 hours during the week
Hence,
The questions you need to answer to solve the given problem are:
a. How much does an auto mechanic earn per hour?
b. How much does an auto mechanic earn per hour on weekends?

b. How much does the auto mechanic earn? Explain.
Answer:
It is given that
An auto mechanic earns $498.75 in 35 hours during the week. His pay is $2.50 more per hour on weekends. If he works 6 hours on the weekend in addition to 35 hours during the week
So,
The amount of money does an auto mechanic earn per hour = (The amount an auto mechanic earns during the week) ÷ (Number of hours)
= $498.75 ÷ 35
Now,
By using the Long Division,

So,
The amount of money an auto mechanic earns per hour is: $14.25
Now,
The amount of money an auto mechanic earns on weekends per hour = $2.50 + $14.25
Now,
By using the Long Multiplication,

So,
The amount of money an auto mechanic earns during weekends is: $16.75
Now,
The total amount of money an auto mechanic earns = (The total amount of money an auto mechanic earns during weekdays) + (The total amount of money an auto mechanic earns on weekends)
= $498.75 + (6 × $16.75)
= $498.75 + $100.5
= $599.25
Hence, from the above,
We can conclude that
The total amount of money an auto mechanic earns is: $599.25

Practice & Problem Solving

Scan for Multimedia

In 6-8, use the picture at the right.

Question 6.
You buy 3.17 pounds of apples, 1.25 pounds of pears, and 2.56 pounds of oranges. What is your total bill rounded to the nearest cent?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.31
Answer:
It is given that
You buy 3.17 pounds of apples, 1.25 pounds of pears, and 2.56 pounds of oranges
So,
Your total bill rounded to the nearest cent = [(The total weight of apples) × (The cost of each apple)] + [(The total weight of pears) × (The cost of each pear)] + [(The total weight of oranges) × (The cost of each orange)]
= (3.17 × $0.99) + (1.25 × $1.19) + (2.56 × $1.09)
= $3.13 + $1.48 + 2.79
= $4.61 + $2.79
= $7.40
Hence, from the above,
We can conclude that
Your total bill rounded to the nearest cent is: $7.40

Question 7.
A student pays for 8.9 pounds of apples with a $10 bill. How much change does the student receive?
a. What do you do first to solve the problem?
Answer:
It is given that
A student pays for 8.9 pounds of apples with a $10 bill
Hence,
The hidden question you need to answer for the given problem is:
What is the total bill you have to pay for 8.9 pounds of apples for $0.99 each?

b. What do you do next?
Answer:
After completing the solution in part (a),
The thing you have to do next is:
Subtract the amount of money the student received by subtracting the value of the total bill you have to pay for 8.9 pounds of apples for $0.99 each from $10

Question 8.
A customer pays $3.27 for oranges and $4.76 for pears. How many pounds of fruit does the customer buy?
a. What do you do first to solve the problem?
Answer:
It is given that
A customer pays $3.27 for oranges and $4.76 for pears
Hence,
The hidden question you have to answer for the given problem is:
How many pounds of oranges and pears does the customer can buy?

b. What do you do next?
Answer:
After find the solution to the question present in part (a),
The thing you have to do next is:
Add the number of pounds of oranges and pears to find the total number of pounds of fruit doe the customer bought

Question 9.
Critique Reasoning Students put 2\(\frac{1}{4}\) pounds of trail mix into bags that each weigh \(\frac{3}{8}\) pound. They bring \(\frac{2}{3}\) of the bags of trail mix on a hiking trip. Can you determine how many bags of trail mix are left by completing just one step? Explain.
Answer:
It is given that
Students put 2\(\frac{1}{4}\) pounds of trail mix into bags that each weigh \(\frac{3}{8}\) pound. They bring \(\frac{2}{3}\) of the bags of trail mix on a hiking trip.
So,
The number of bags of trail mix = (The total number of pounds of trail mix) ÷ (The weight of each bag of trail mix)
= 2\(\frac{1}{4}\) ÷ \(\frac{3}{8}\)
Now,
By using the Long Division,

So,
The number of bags of trail mix is: 6 bags
Now,
The \(\frac{2}{3}\) of the bags of trail mix = 6 × \(\frac{2}{3}\)
= \(\frac{6 × 2}{3}\)
= 4 bags
So,
The number of bags of trail mix left = (The total number of bags of trail mix) – (The \(\frac{2}{3}\) of the bags of trail mix)
= 6 – 4
= 2 bags
Hence, from the above,
We can conclude that
The number of bags of trail mix that are left is: 2 bags
We can’t determine the number of bags of trail mix by completing just one step

Question 10.
Three-fifths of the T-shirts in a T-shirt shop are blue. Five-eighths of those T-shirts are on sale. One-third of the blue T-shirts that are on sale are size medium. What fraction of the shop’s T-shirts are blue T-shirts that are on sale and are size medium? Explain.
Answer:
It is given that
Three-fifths of the T-shirts in a T-shirt shop are blue. Five-eighths of those T-shirts are on sale. One-third of the blue T-shirts that are on sale are size medium.
So,
The number of blue T-shirts are: \(\frac{3}{5}\) shirts
The number of blue T-shirts that are on sale = \(\frac{3}{5}\) × \(\frac{5}{8}\)
Now,
By using the Long Multiplication,

So,
The number of blue T-shirts that are on sale is: \(\frac{3}{8}\) shirts
Now,
The number of blue T-shirts that are on sale and are medium size = \(\frac{3}{8}\) × \(\frac{1}{3}\)
Now,
By using the Long Multiplication,

So,
The number of blue shirts that are on sale and are medium size is: \(\frac{1}{8}\) shirts
Hence, from the above,
We can conclude that
The number of blue T-shirts that are on sale is: \(\frac{3}{8}\) shirts
The number of blue shirts that are on sale and are medium size is: \(\frac{1}{8}\) shirts

In 11 and 12, use the diagram.
A community garden is made up of three gardens: a vegetable garden, an herb garden, and a flower garden.

Question 11.
The area of the vegetable garden is 0.4 of the area of the community garden. What is the area of the vegetable garden?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.32
Answer:
It is given that
A community garden is made up of three gardens: a vegetable garden, an herb garden, and a flower garden.
The area of the vegetable garden is 0.4 of the area of the community garden.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.32
Now,
From the given figure,
The area of the community garden = (Length of the community garden) × (Width of the community garden)
= 6.2 × 4.5
Now,
By using the Long Multiplication,

So,
The area of the community garden is: 27.9 m²
Now,
The area of the vegetable garden = 0.4 × (The area of the community garden)
= 0.4 × 27.9
= 11.16 m²
Hence, from the above,
We can conclude that
The area of the vegetable garden is: 11.16 m²

Question 12.
The area of the flower garden is 9.7 square meters greater than the herb garden. What is the area of the flower garden?
Answer:
It is given that
The area of the flower garden is 9.7 square meters greater than the herb garden.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.32
Now,
From the given figure,
We can observe that
The area of the Herb garden = 2.2 × 1.6
= 3.52 m²
So,
The area of the flower garden = 9.7 + (The area of the flower garden)
= 9.7 + 3.52
= 13.22 m²
Hence, from the above,
We can conclude that
The area of the flower garden is: 13.22 m²

Question 13.
Reasoning At the end of a party, \(\frac{3}{4}\) cup of smoked fish dip is left. Jim divides \(\frac{4}{5}\) of the leftover smoked fish dip equally between 2 friends. How much dip does each friend get?
Answer:
It is given that
At the end of a party, \(\frac{3}{4}\) cup of smoked fish dip is left. Jim divides \(\frac{4}{5}\) of the leftover smoked fish dip equally between 2 friends.
Now,
The \(\frac{4}{5}\) of the leftover smoked fish = \(\frac{4}{5}\) × \(\frac{3}{4}\)
Now,
By using the Long Multiplication,

So,
The \(\frac{4}{5}\) of the leftover smoked fish is: \(\frac{3}{5}\)
Now,
The amount of dip each friend get = \(\frac{3}{5}\) ÷ 2
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The amount of dip each friend get is: \(\frac{3}{10}\) of the leftover smoked fish dip

Question 14.
Students are planning a 3-day hiking trip in the Everglades. The hike covers a distance of 18.5 kilometers. The students hike 0.28 of the total distance on the first day. If they split the remaining distance equally between the second and third days, how far will they hike on day 3?
Answer:
It is given that
Students are planning a 3-day hiking trip in the Everglades. The hike covers a distance of 18.5 kilometers. The students hike 0.28 of the total distance on the first day and they split the remaining distance equally between the second and third days
So,
The remaining distance of the hike after the first day = (The total distance of hike) – (The distance of hike on the first day)
= 18.5 – (0.28 × 18.5)
= 18.5 – 5.18
= 13.32 kilometers
Now,
The distance of the hike on the second and the third days which are split equally = (The remaining distance of the hike after the first day) ÷ 2
= 13.32 ÷2
= 6.66 kilometers
So,
The amount of distance the students hiked on the third day is: 6.66 kilometers
Hence, from the above,
We can conclude that
The amount of distance the students hiked on the third day is: 6.66 kilometers

Question 15.
Higher-Order Thinking Kelly buys three containers of potato salad at the deli. She brings \(\frac{4}{5}\) of the potato salad to a picnic. How many pounds of potato salad does Kelly bring to the picnic? Describe two different ways to solve the problem.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.33
Answer:
It is given that
Kelly buys three containers of potato salad at the deli. She brings \(\frac{4}{5}\) of the potato salad to a picnic
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.33
So,
The total weight of the containers of potato salad = 1.03 + 1.12 + 1.6
= 3.75 pounds
So,
The total weight of potato salad Kelly brought = 3 × (The total weight of the containers of potato salad)
= 3 × 3.75
= 11.25 pounds
Now,
The amount of potato salad Kelly brought to picnic = \(\frac{4}{5}\) × (The total weight of potato salad Kelly brought)
= \(\frac{4}{5}\) × 11.25
= 9 pounds
Hence, from the above,
We can conclude that
The amount of potato salad Kelly brought to the picnic is: 9 pounds

Assessment Practice

Question 16.
Students make 84\(\frac{1}{2}\) ounces of liquid soap for a craft fair. They put the soap in 6\(\frac{1}{2}\)-ounce bottles and sell each bottle for $5.50. Which expression shows how much students earn if they sell all the bottles of liquid soap?
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 69.34
Answer:
It s given that
Students make 84\(\frac{1}{2}\) ounces of liquid soap for a craft fair. They put the soap in 6\(\frac{1}{2}\)-ounce bottles and sell each bottle for $5.50.
So,
The number of bottles of liquid soap = 84\(\frac{1}{2}\) ÷ 6\(\frac{1}{2}\)
Now,
By using the Long Division,

So,
The number of bottles of liquid soap is: 13 bottles
Now,
The cost of the 13 bottles of liquid soap = 13 × (The cost of each liquid soap)
= 13 × $5.50
= $71.5
Hence, from the above,
We can conclude that
The expression shows how much students earn if they sell all the bottles of liquid soap is:

Question 17.
Claire mowed 5 lawns last week. She mowed each lawn in \(\frac{7}{12}\) hour. She mowed the same lawns this week in \(\frac{5}{12}\) hour each using her new lawnmower. How many times longer was Claire’s time to mow all the lawns last week than this week?
Answer:
It is given that
Claire mowed 5 lawns last week. She mowed each lawn in \(\frac{7}{12}\) hour. She mowed the same lawns this week in \(\frac{5}{12}\) hour each using her new lawnmower
So,
The number of hours Claire mowed last week = (The number of lawns) × (The amount of time each lawn was mowed last week)
= 5 × \(\frac{7}{12}\)
Now,
By using the Long Multiplication,

So,
The number of hours Claire mowed last week is: \(\frac{35}{12}\) hours
Now,
The number of hours Claire mowed this week = (The number of lawns) × (The amount of time each lawn was mowed this week)
= 5 × \(\frac{5}{12}\)
Now,
By using the Long Multiplication,

So,
The number of hours Claire mowed this week is: \(\frac{25}{12}\) hours
Now,
The difference between the number of hours Claire mowed the last week and this week = \(\frac{35}{12}\) – \(\frac{25}{12}\)
= \(\frac{35 – 25}{12}\)
= \(\frac{10}{12}\)
= \(\frac{5}{6}\) hours
Hence, from the above,
We can conclude that
Claire’s time to mow all the lawns last week is \(\frac{5}{6}\) times longer than this week

Topic 1 REVIEW

? Topic Essential Question
How can you fluently add, subtract, multiply, and divide decimals? How can you multiply and divide fractions?
Answer:
The steps to add, subtract, multiply, and divide decimals are:
a. Write the numbers vertically with the decimals lined up (if the number is a whole number then the decimal goes on the right end of the number)
b. Add zeros to make sure there is the same number of digits in each number.
c. Add or subtract as normal.
d. Multiply just as you would if the numbers were all whole numbers and add at the end.
e. After that count how many decimals places the two factors have (start at the far right of each number) and then give the answer that the total number of decimal places.
f. To divide decimals, always use long division.
The process to multiply and divide fractions is:
a. Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction.
b. The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction.
c. Next, multiply the two numerators. Then, multiply the two denominators.

Vocabulary Review

Complete each definition and then provide an example of each vocabulary word.

Vocabulary

reciprocal
dividend
fraction
product

Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 70.
Answer:

Use Vocabulary in Writing

Explain how to use multiplication to find the value of \(\frac{1}{3}\) ÷ \(\frac{9}{5}\) Use the words multiplication, divisor, quotient, and reciprocal in your explanation.
Answer:
The given division expression is:
\(\frac{1}{3}\) ÷ \(\frac{9}{5}\)
Where,
\(\frac{1}{3}\) is the dividend
\(\frac{9}{5}\) is the divisor
Now,
The “Reciprocal” of \(\frac{9}{5}\) is: \(\frac{5}{9}\)
So,
\(\frac{1}{3}\) ÷ \(\frac{9}{5}\)
= \(\frac{1}{3}\) × \(\frac{5}{9}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{3}\) ÷ \(\frac{9}{5}\) = \(\frac{5}{27}\)

Concepts and Skills Review

LESSON 1.1 Fluently Add, Subtract and Multiply Decimals

Quick Review
To add or subtract decimals, line up the decimal points so that place-value positions correspond. Add or subtract as you would with whole numbers, and place the decimal point in the answer. To multiply decimals, multiply as you would with whole numbers, then place the decimal point in the product by starting at the right and counting the number of places equal to the sum of the number of decimal places in each factor.

Example
Add, subtract, or multiply.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 70.2

Practice
Add, subtract, or multiply.

Question 1.
91.2 + 89.9
Answer:
The given Addition expression is: 91.2 + 89.9
Now,
By using the Long Addition,

Hence, from the above,
We can conclude that
91.2 + 89.9 = 181.1

Question 2.
902.3 – 8.8
Answer:
The given Subtraction expression is: 902.3 – 8.8
Now,
By using the Long Subtraction,

Hence, from the above,
We can conclude that
902.3 – 8.8 = 893.5

Question 3.
5 × 98.2
Answer:
The given Multiplication Expression is: 5 × 98.2
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
5 × 98.2 = 491

Question 4.
4 × 0.21
Answer:
The given Multiplication Expression is: 4 × 0.21
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
4 × 0.21 = 0.84

Question 5.
62.99 – 10.83
Answer:
The given Subtraction Expression is: 62.99 – 10.83
Now,
By using the Long Subtraction,

Hence, from the above,
We can conclude that
62.99 – 10.83 = 52.16

Question 6.
423.22 + 98.30
Answer:
The given Addition Expression is: 423.22 + 98.30
Now,
By using the Long Addition,

Hence, from the above,
We can conclude that
423.22 + 98.30 = 521.52

Question 7.
4.4 × 6
Answer:
The given Multiplication Expression is: 4.4 × 6
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
4.4 × 6 = 26.4

Question 8.
7 × 21.6
Answer:
The given Multiplication Expression is: 7 × 21.6
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
7 × 21.6 = 151.2

Question 9.
24.52 – 9.6
Answer:
The given Subtraction Expression is: 24.52 – 9.6
Now,
By using the Long Subtraction,

Hence, from the above,
We can conclude that
24.52 – 9.6 = 14.92

Question 10.
369.45 + 32.42
Answer:
The given Addition Expression is: 369.45 + 32.42
Now,
By using the Long Addition,

Hence, from the above,
We can conclude that
369.45 + 32.42 = 401.87

Question 11.
12.5 × 163.2
Answer:
The given Multiplication Expression is: 12.5 × 163.2
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
12.5 × 163.2 = 2,040

Question 12.
16 × 52.3
Answer:
The given Multiplication Expression is: 16 × 52.3
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
16 × 52.3 = 836.8

Question 13.
121.3 + 435.7
Answer:
The given Addition Expression is: 121.3 + 435.7
Now,
By using the Long Addition,

Hence, from the above,
We can conclude that
121.3 + 435.7 = 557

Question 14.
201.7 – 104.6
Answer:
The given Subtraction Expression is: 201.7 – 104.6
Now,
By using the Long Subtraction,

Hence, from the above,
We can conclude that
201.7 – 104.6 = 97.1

LESSON 1.2 Fluently Divide Whole Numbers and Decimals

Quick Review
To divide decimals, multiply the divisor and the dividend by the same power of 10 so that the divisor is a whole number. Then use an algorithm for whole-number division.

Example
Find 2.75 ÷ 0.05.
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 80.1

Practice
Divide.

Question 1.
9.6 ÷ 1.6
Answer:
The given Division Expression is: 9.6 ÷ 1.6
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
9.6 ÷ 1.6 = 6

Question 2.
48.4 ÷ 0.4
Answer:
The given Division Expression is: 48.4 ÷ 0.4
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
48.4 ÷ 0.4 = 121

Question 3.
13.2 ÷ 0.006
Answer:
The given Division Expression is: 13.2 ÷ 0.006
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
13.2 ÷ 0.006 = 2,200

Question 4.
10.8 ÷ 0.09
Answer:
The given Division Expression is: 10.8 ÷ 0.09
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
10.8 ÷ 0.09 = 120

Question 5.
45 ÷ 4.5
Answer:
The given Division expression is: 45 ÷ 4.5
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
45 ÷ 4.5 = 10

Question 6.
1,008 ÷ 1.8
Answer:
The given Division Expression is: 1,008 ÷ 1.8
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
1,008 ÷ 1.8 = 560

Question 7.
1.26 ÷ 0.2
Answer:
The given Division Expression is: 1.26 ÷ 0.2
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
1.26 ÷ 0.2 = 6.3

Question 8.
2.24 ÷ 3.2
Answer:
The given Division Expression is: 2.24 ÷ 3.2
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2.24 ÷ 3.2 = 0.7

Question 9.
35.75 ÷ 55
Answer:
The given Division Expression is: 35.75 ÷ 55
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
35.75 ÷ 55 = 0.65

Question 10.
120.4 ÷ 602
Answer:
The given Division Expression is: 120.4 ÷ 602
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
120.4 ÷ 602 = 0.2

Question 11.
330 ÷ 5.5
Answer:
The given Division Expression is: 330 ÷ 5.5
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
330 ÷ 5.5 = 60

Question 12.
1.08 ÷ 0.027
Answer:
The given Division Expression is: 1.08 ÷ 0.027
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
1.08 ÷ 0.027 = 40

LESSON 1.3 Multiply Fractions

Quick Review
Multiply the numerators to find the numerator of the product. Multiply the denominators to find the denominator of the product.

Example
Envision Math Common Core Grade 6 Answers Topic 1 Use Positive Rational Numbers 82.1
10 of the 18 rectangles are in the overlap area. So, \(\frac{2}{3}\) × \(\frac{5}{6}\) = \(\frac{10}{8}\) or \(\frac{5}{9}\).

Practice
Find each product.

Question 1.
\(\frac{2}{3}\) × \(\frac{3}{8}\)
Answer:
The given Multiplication Expression is:
\(\frac{2}{3}\) × \(\frac{3}{8}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{2}{3}\) × \(\frac{3}{8}\) = \(\frac{1}{4}\)

Question 2.
\(\frac{1}{4}\) × \(\frac{3}{5}\)
Answer:
The given Multiplication Expression is:
\(\frac{1}{4}\) × \(\frac{3}{5}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{4}\) × \(\frac{3}{5}\) = \(\frac{3}{20}\)

Question 3.
\(\frac{1}{6}\) × \(\frac{1}{8}\)
Answer:
The given Multiplication Expression is:
\(\frac{1}{6}\) × \(\frac{1}{8}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{1}{6}\) × \(\frac{1}{8}\) = \(\frac{1}{48}\)

Question 4.
\(\frac{4}{7}\) × \(\frac{4}{7}\)
Answer:
The given Multiplication Expression is:
\(\frac{4}{7}\) × \(\frac{4}{7}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{4}{7}\) × \(\frac{4}{7}\) = \(\frac{16}{49}\)

Question 5.
\(\frac{6}{7}\) × \(\frac{1}{2}\)
Answer:
The given Multiplication Expression is:
\(\frac{6}{7}\) × \(\frac{1}{2}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{6}{7}\) × \(\frac{1}{2}\) = \(\frac{3}{7}\)

Question 6.
\(\frac{3}{8}\) × \(\frac{8}{3}\)
Answer:
The given Multiplication Expression is:
\(\frac{3}{8}\) × \(\frac{8}{3}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{3}{8}\) × \(\frac{8}{3}\) = 1

Question 7.
\(\frac{2}{3}\) × \(\frac{1}{3}\)
Answer:
The given Multiplication Expression is:
\(\frac{2}{3}\) × \(\frac{1}{3}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{2}{3}\) × \(\frac{1}{3}\) = \(\frac{2}{9}\)

Question 8.
\(\frac{7}{8}\) × \(\frac{3}{2}\)
Answer:
The given Multiplication Expression is:
\(\frac{7}{8}\) × \(\frac{3}{2}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
\(\frac{7}{8}\) × \(\frac{3}{2}\) = \(\frac{21}{16}\)

Question 9.
2\(\frac{1}{3}\) × 4\(\frac{1}{5}\)
Answer:
The given Multiplication Expression is:
2\(\frac{1}{3}\) × 4\(\frac{1}{5}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
2\(\frac{1}{3}\) × 4\(\frac{1}{5}\) = \(\frac{49}{5}\)

Question 10.
4\(\frac{1}{2}\) × 6\(\frac{2}{3}\)
Answer:
The given Multiplication Expression is:
4\(\frac{1}{2}\) × 6\(\frac{2}{3}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
4\(\frac{1}{2}\) × 6\(\frac{2}{3}\) = 30

Question 11.
3\(\frac{3}{5}\) × 2\(\frac{5}{7}\)
Answer:
The given Multiplication Expression is:
3\(\frac{3}{5}\) × 2\(\frac{5}{7}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
3\(\frac{3}{5}\) × 2\(\frac{5}{7}\) = \(\frac{342}{35}\)

Question 12.
14\(\frac{2}{7}\) × 4\(\frac{3}{10}\)
Answer:
The given Multiplication Expression is:
14\(\frac{2}{7}\) × 4\(\frac{3}{10}\)
Now,
By using the Long Multiplication,

Hence, from the above,
We can conclude that
14\(\frac{2}{7}\) × 4\(\frac{3}{10}\) = \(\frac{430}{7}\)

LESSONS 1.4 AND 1.5 Understand and Divide with Fractions

Quick Review
To divide by a fraction, use the reciprocal of the divisor to rewrite the problem as a multiplication problem.
Practice Find each quotient.

Example
Find 4 ÷ \(\frac{4}{5}\).
Envision Math Common Core 6th Grade Answer Key Topic 1 Use Positive Rational Numbers 83.2

Find \(\frac{3}{4}\) ÷ \(\frac{4}{5}\).
Envision Math Common Core 6th Grade Answer Key Topic 1 Use Positive Rational Numbers 83.3

Practice

Find each Quotient

Question 1.
7 ÷ \(\frac{1}{2}\)
Answer:
The given Division Expression is:
7 ÷ \(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
7 ÷ \(\frac{1}{2}\) = 14
The quotient for the given division expression is: 14

Question 2.
6 ÷ \(\frac{2}{5}\)
Answer:
The given Division Expression is:
6 ÷ \(\frac{2}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
6 ÷ \(\frac{2}{5}\) = 15
The quotient for the given division expression is: 15

Question 3.
2 ÷ \(\frac{1}{8}\)
Answer:
The given Division Expression is:
2 ÷ \(\frac{1}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
2 ÷ \(\frac{1}{8}\) = 16
The quotient for the given division expression is: 16

Question 4.
8 ÷ \(\frac{4}{9}\)
Answer:
The given Division Expression is:
8 ÷ \(\frac{4}{9}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
8 ÷ \(\frac{4}{9}\) = 18
The quotient for the given division expression is: 18

Question 5.
\(\frac{1}{2}\) ÷ \(\frac{1}{4}\)
Answer:
The given Division Expression is:
\(\frac{1}{2}\) ÷ \(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{1}{2}\) ÷ \(\frac{1}{4}\) = 2
The quotient for the given division expression is: 2

Question 6.
\(\frac{8}{10}\) ÷ \(\frac{1}{5}\)
Answer:
The given Division Expression is:
\(\frac{8}{10}\) ÷ \(\frac{1}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{8}{10}\) ÷ \(\frac{1}{5}\) = 4
The quotient for the given division expression is: 4

Question 7.
\(\frac{5}{6}\) ÷ \(\frac{3}{8}\)
Answer:
The given Division Expression is:
\(\frac{5}{6}\) ÷ \(\frac{3}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{5}{6}\) ÷ \(\frac{3}{8}\) = \(\frac{20}{9}\)
The quotient for the given division expression is: \(\frac{20}{9}\)

Question 8.
\(\frac{1}{3}\) ÷ \(\frac{1}{2}\)
Answer:
The given Division Expression is:
\(\frac{1}{3}\) ÷ \(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
we can conclude that
\(\frac{1}{3}\) ÷ \(\frac{1}{2}\) = \(\frac{2}{3}\)
The quotient for the given division expression is: \(\frac{2}{3}\)

Question 9.
5 ÷ \(\frac{5}{16}\)
Answer:
The given Division Expression is:
5 ÷ \(\frac{5}{16}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
5 ÷ \(\frac{5}{16}\) = 16
The quotient for the given division expression is: 16

Question 10.
\(\frac{7}{12}\) ÷ \(\frac{3}{4}\)
Answer:
The given Divisio Expression is:
\(\frac{7}{12}\) ÷ \(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{7}{12}\) ÷ \(\frac{3}{4}\) = \(\frac{7}{9}\)
The quotient for the given division expression is: \(\frac{7}{9}\)

Question 11.
20 ÷ \(\frac{5}{6}\)
Answer;
The given Division Expression is:
20 ÷ \(\frac{5}{6}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
20 ÷ \(\frac{5}{6}\) = 24
The quotient for the given division expression is: 24

Question 12.
16 ÷ \(\frac{1}{4}\)
Answer:
The given Division Expression is:
16 ÷ \(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
16 ÷ \(\frac{1}{4}\) = 64
The quotient for the given division expression is: 64

Question 13.
\(\frac{4}{5}\) ÷ \(\frac{1}{8}\)
Answer:
The given Division Expression is:
\(\frac{4}{5}\) ÷ \(\frac{1}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{4}{5}\) ÷ \(\frac{1}{8}\) = \(\frac{32}{5}\)
The quotient for the given division expression is: \(\frac{32}{5}\)

Question 14.
5 ÷ \(\frac{1}{10}\)
Answer:
The given Division Expression is:
5 ÷ \(\frac{1}{10}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
5 ÷ \(\frac{1}{10}\) = 50
The quotient for the given division expression is: 50

Question 15.
\(\frac{7}{11}\) ÷ \(\frac{1}{11}\)
Answer:
The given Division Expression is:
\(\frac{7}{11}\) ÷ \(\frac{1}{11}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
\(\frac{7}{11}\) ÷ \(\frac{1}{11}\) = 7
The quotient for the given division expression is: 7

Question 16.
4 ÷ \(\frac{2}{8}\)
Answer:
The given Division Expression is:
4 ÷ \(\frac{2}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We ca conclude that
4 ÷ \(\frac{2}{8}\) = 16
The quotient for the given division expression is: 16

LESSON 1.6 Divide Mixed Numbers

Quick Review
To divide by a mixed number, rename each mixed number as a fraction. Then use the reciprocal of the divisor to rewrite the problem as a multiplication problem.

Example
Envision Math Common Core 6th Grade Answer Key Topic 1 Use Positive Rational Numbers 88.1
Practice
Find each quotient

Question 1.
6\(\frac{3}{8}\) ÷ 4\(\frac{1}{4}\)
Answer:
The given Division Expression is:
6\(\frac{3}{8}\) ÷ 4\(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
6\(\frac{3}{8}\) ÷ 4\(\frac{1}{4}\) = \(\frac{3}{2}\)
The quotient for the given division expression is: \(\frac{3}{2}\)

Question 2.
9 ÷ 2\(\frac{2}{7}\)
Answer:
The given Division Expression is:
9 ÷ 2\(\frac{2}{7}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
9 ÷ 2\(\frac{2}{7}\) = \(\frac{63}{16}\)
The quotient for the given division expression is: \(\frac{63}{16}\)

Question 3.
3\(\frac{3}{5}\) ÷ 1\(\frac{1}{5}\)
Answer:
The given Division Expression is:
3\(\frac{3}{5}\) ÷ 1\(\frac{1}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
3\(\frac{3}{5}\) ÷ 1\(\frac{1}{5}\) = 3
The quotient for the given division expression is: 3

Question 4.
5\(\frac{1}{2}\) ÷ 3\(\frac{3}{8}\)
Answer:
The given Division Expression is:
5\(\frac{1}{2}\) ÷ 3\(\frac{3}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
5\(\frac{1}{2}\) ÷ 3\(\frac{3}{8}\) = \(\frac{44}{27}\)
The quotient for the given division expression is: \(\frac{4}{27}\)

Question 5.
3\(\frac{2}{5}\) ÷1\(\frac{1}{5}\)
Answer:
The given Division Expression is:
3\(\frac{2}{5}\) ÷1\(\frac{1}{5}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
3\(\frac{2}{5}\) ÷1\(\frac{1}{5}\) = \(\frac{17}{6}\)
The quotient for the given division expression is: \(\frac{17}{6}\)

Question 6.
12\(\frac{1}{6}[/ltex] ÷ 3
Answer:
The given Division Expression is:
12[latex]\frac{1}{6}[/ltex] ÷ 3
Now,
By using the Long Division,

Hence, from the above,
We ca conclude that
12[latex]\frac{1}{6}[/ltex] ÷ 3 = [latex]\frac{73}{18}\)
The quotient for the given division expression is: \(\frac{73}{18}\)

Question 7.
12 ÷ 1\(\frac{1}{2}\)
Answer:
The given Division Expression is:
12 ÷ 1\(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
12 ÷ 1\(\frac{1}{2}\) = 8
The quotient for the given division expression is: 8

Question 8.
3\(\frac{1}{2}\) ÷ 2\(\frac{1}{4}\)
Answer:
The given Division Expression is:
3\(\frac{1}{2}\) ÷ 2\(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
3\(\frac{1}{2}\) ÷ 2\(\frac{1}{4}\) = \(\frac{14}{9}\)
The quotient for the given division expression is: \(\frac{14}{9}\)

Question 9.
8 ÷ 1\(\frac{1}{4}\)
Answer:
The given Division Expression is:
8 ÷ 1\(\frac{1}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
8 ÷ 1\(\frac{1}{4}\) = \(\frac{32}{5}\)
The quotient for the given division expression is: \(\frac{32}{5}\)

Question 10.
10\(\frac{1}{2}\) ÷ 1\(\frac{3}{4}\)
Answer:
The given Division Expression is:
10\(\frac{1}{2}\) ÷ 1\(\frac{3}{4}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
10\(\frac{1}{2}\) ÷ 1\(\frac{3}{4}\) = 6
The quotient for the given division expression is: 6

Question 11.
3\(\frac{3}{4}\) ÷ 2\(\frac{1}{2}\)
Answer:
The given Division Expression is:
3\(\frac{3}{4}\) ÷ 2\(\frac{1}{2}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
3\(\frac{3}{4}\) ÷ 2\(\frac{1}{2}\) = \(\frac{3}{2}\)
The quotient for the given division expression is: \(\frac{3}{2}\)

Question 12.
60 ÷ 3\(\frac{1}{3}\)
Answer:
The given Division Expression is:
60 ÷ 3\(\frac{1}{3}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
60 ÷ 3\(\frac{1}{3}\) = 18
The quotient for the given division expression is: 18

LESSON 1.7 Solve Problems with Rational Numbers

Quick Review
When solving multistep problems:
• decide the steps to solve the problem.
• choose the correct operations.
• identify the information you need from the problem.
• correctly use the information.
• calculate accurately.
• check if the answer is reasonable.

Example
Jane’s garden is 3.4 meters by 6.5 meters. If fencing costs $2.25 per meter, how much will it cost to enclose Jane’s garden?
Step 1: Find how much fence is needed.
3.4 + 3.4 + 6.5 + 6.5 = 19.8 meters
Step 2: Multiply to find the cost.
19.8 × 2.25 = $44.55
Step 3: Estimate to check.
3 + 3 + 7 + 7 = 20 meters
20 × 2.00 = $40.00
$40 is close to $44.55, so the answer is reasonable.

Practice
Daisy has one cucumber that is 3 inches long and another cucumber that is 5 inches long. She cuts the cucumbers into \(\frac{3}{8}\)-inch-thick slices and adds them to a salad. How many \(\frac{3}{8}\)-inch-thick slices does Daisy have?

Question 1.
Write division expressions to represent the first steps in the problem.
Answer:
It is given that
Daisy has one cucumber that is 3 inches long and another cucumber that is 5 inches long. She cuts the cucumbers into \(\frac{3}{8}\)-inch-thick slices and adds them to a salad.
So,
The total length of 2 cucumbers = (The length of the first cucumber) + (The length of the second cucumber)
= 3 + 5
= 8 inches
Now,
The number of \(\frac{3}{8}\)-inch-thick slices does Daisy have = (The total length of 2 cucumbers) ÷ \(\frac{3}{8}\)
= 8 ÷ \(\frac{3}{8}\)
Hence, from the above,
We can conclude that
The division expression to represent the given information is:
The number of \(\frac{3}{8}\)-inch-thick slices do Daisy have = 8 ÷ \(\frac{3}{8}\)

Question 2.
Solve. Then explain your answer.
Answer:
From Question 1,
We can observe that
The number of \(\frac{3}{8}\)-inch-thick slices does Daisy have = (The total length of 2 cucumbers) ÷ \(\frac{3}{8}\)
= 8 ÷ \(\frac{3}{8}\)
Now,
By using the Long Division,

Hence, from the above,
We can conclude that
The number of \(\frac{3}{8}\)-inch-thick slices does Daisy have is about 21 pieces

Topic 1 Fluency Practice

Pathfinder
Shade a path from START to FINISH. Follow the solutions in which the digit in the hundredths place is greater than the digit in the tenths place. You can only move up, down, right, or left.
Envision Math Common Core 6th Grade Answer Key Topic 1 Use Positive Rational Numbers 100

enVision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals

enVision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals

Go through the enVision Math Common Core Grade 5 Answer Key Topic 6 Use Models and Strategies to Divide Decimals regularly and improve your accuracy in solving questions.

enVision Math Common Core 5th Grade Answers Key Topic 6 Use Model Strategies to Divide Decimals

Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 1
enVision STEM Project: States of Water
Do Research

Use the Internet or other sources to learn about the states of water. Find at least 5 examples of water in nature as a solid, as a liquid, and as a gas. At what temperature does liquid water change to ice? At what temperature does liquid water change to water vapor?

Journal: Write a Report Include what you found. Also in your report:
• Explain how liquid water changes to ice and to water vapor.
• At 23°F, 1 inch of rain equals 10 inches of snow. Convert 2 inches of rainfall to snowfall.
• Make up and solve division problems that involve decimals.

Review What You Know

Vocabulary

Choose the best term from the box. Write it on the blank.
• decimal
• dividend
• divisor
• quotient

Question 1.
_____ is the name for the answer to a division problem.
Answer:
Quotient is the name for the answer to a division problem.

Question 2.
A number that is being divided by another number is called the _____
Answer:
A number that is being divided by another number is called the dividend.

Whole Number Operations

Find each value.

Question 3.
9,007 – 3,128
Answer:
9,007 – 3,128 = 5,879
Explanation:
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. Subtraction of two whole numbers may not result in whole numbers. It can be an integer too. Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Subtract 3,128 from 9,007 then the difference is 5,879.
Question 4.
725,864 + 39,798
Answer:
725,864 + 39,798 = 765,662
Explanation:
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. Two whole numbers if added or multiplied will give a whole number itself. Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Perform addition operation on these two numbers 725,864 and 39,798 then the sum is 765,662.

Question 5.
35 × 17
Answer:
35 × 17 = 595
Explanation:
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. Two whole numbers if added or multiplied will give a whole number itself. Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Perform multiplication operation on these two numbers 35 and 17 then the result is 595.

Question 6.
181 × 42
Answer:
181 × 42 = 7,602
Explanation:
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. Two whole numbers if added or multiplied will give a whole number itself.  Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Perform multiplication operation on these two numbers 181 and 42 then the result is 7,602.

Question 7.
768 ÷ 6
Answer:
768 ÷ 6 = 128
Explanation:
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. The inverse operation of multiplication is division. Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Perform division operation on these two numbers 768 and 6. Here 768 is dividend and 6 is divisor then the quotient is 128.

Question 8.
506 ÷ 22
Answer:
506 ÷ 22 = 23
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. The inverse operation of multiplication is division. Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Perform division operation on these two numbers 506 and 22. Here 506 is dividend and 22 is divisor then the quotient is 23.

Question 9.
6,357 ÷ 60
Answer:
6,357 ÷ 60 = 105.95
Explanation:
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. The inverse operation of multiplication is division. Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Perform division operation on these two numbers 6357 and 60. Here 6,357 is dividend and 60 is divisor then the quotient is 105.95.

Question 10.
3,320 ÷ 89
Answer:
3,320 ÷ 89 = 37.30
Explanation:
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. The inverse operation of multiplication is division. Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Perform division operation on these two numbers 3,320 and 89. Here 3,320 is dividend and 89 is divisor then the quotient is 37.30.

Question 11.
88,888 ÷ 20
Answer:
88,888 ÷ 20 = 4,444.4
Explanation:
The properties of whole numbers are based on arithmetic operations such as addition, subtraction, division and multiplication. The inverse operation of multiplication is division. Whole numbers are positive integers along with zero. They are all the natural numbers including zero. Perform division operation on these two numbers 88,888 and 20. Here 88,888 is dividend and 20 is divisor then the quotient is 4,444.4.

Rounding Decimals
Round each number to the place of the underlined digit.

Question 12.
0.34
Answer:
0.3
Explanation:
Rounding is a process to estimate a particular number in a context. To round a number look at the next digit in the right place, if the digit is less than 5, round down and if the digit is 5 or more than 5, round up. The number 0.34 is rounded to 0.3.

Question 13.
96.5
Answer:
97
Explanation:
Rounding is a process to estimate a particular number in a context. To round a number look at the next digit in the right place, if the digit is less than 5, round down and if the digit is 5 or more than 5, round up. The number 96.5 is rounded to 97.

Question 14.
81.27
Answer:
81.3
Explanation:
Rounding is a process to estimate a particular number in a context. To round a number look at the next digit in the right place, if the digit is less than 5, round down and if the digit is 5 or more than 5, round up. The number 81.27 is rounded to 81.3.

Question 15.
205.3
Answer:
205
Explanation:
Rounding is a process to estimate a particular number in a context. To round a number look at the next digit in the right place, if the digit is less than 5, round down and if the digit is 5 or more than 5, round up. The number 205.3 is rounded to 205.

Decimals

Question 16.
An insect measured 1.25 cm long. Which number is less than 1.25?
A. 1.35
B. 1.3
C. 1.26
D. 1.2
Answer:
Option D is correct.
Explanation:
An insect measured 1.25 cm long. We have to find out the number less than 1.25.
A. 1.35 is greater than 1.25. So option A is not correct.
B. 1.3 is greater than 1.25. So option B is not correct.
C. 1.26 is greater than 1.25 . So option C is not correct.
D. 1.2 is less than 1.25. So option D is correct.

Question 17.
Explain The grid in this model represents 1. What decimal does the shaded part represent? Explain.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 2
Answer:
0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.1 + 0.04 = 0.64
The shaded part represents the decimal 0.64.
Explanation:
The above grid represents 1. In that grid 1 column is shaded. The shaded part decimal value is 0.1. The second column shaded part decimal value is 0.1. The third column shaded part decimal value is 0.1. The fourth column shaded part decimal value is 0.1. The fifth column shaded part decimal value is 0.1. The sixth column shaded part decimal value is 0.1. The seventh column shaded part decimal value is 0.04. By adding these columns decimal values the sum is 0.64.

Decimal Operations

Find each value.

Question 18.
23.7 – 11.82
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-6(1)
23.7 – 11.82 = 11.88
Explanation:
Four basic operations on decimals are addition, subtraction, multiplication and division. To add decimals numbers we follow this step.
Step 1: Write numbers under each other and line up vertically the decimal points.
Perform subtraction operation on these two numbers 23.7 and 11.82. Subtract 11.82 from 23.7 then the difference is 11.88.

Question 19.
66.8 + 3.64
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-6(2)
66.8 + 3.64 = 70.44
Explanation:
Four basic operations on decimals are addition, subtraction, multiplication and division. To add decimals numbers we follow this step.
Step 1: Write numbers under each other and line up vertically the decimal points.
Perform addition operation on these two numbers 66.8 and 3.64. Add 66.8 with 3.64 then the sum is 70.44.

Question 20.
9 × 1.4
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-6(3)
9 x 1. 4 = 12. 6
Explanation:
Four basic operations on decimals are addition, subtraction, multiplication and division. To add decimals numbers we follow this step.
Step 1: Write numbers under each other and line up vertically the decimal points.
Perform multiplication operation on these two numbers 9 and 1.4. Multiply 9 with 1.4 then the result is 12.6.

Question 21.
3.2 × 7.6
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-6(4)
3.2 x 7.6 = 24.32
Explanation:
Four basic operations on decimals are addition, subtraction, multiplication and division. To add decimals numbers we follow this step.
Step 1: Write numbers under each other and line up vertically the decimal points.
Perform multiplication operation on these two numbers 3.2 and 7.6. Multiply 3.2 with 7.6 then the result is 24.32.

Pick a Project

PROJECT 6A
Can you throw a dinner party?
Project: Plan a Party
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.1

PROJECT 6B
How much does it cost to run a company?
Project: Build a Company
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.2

PROJECT 6C
How do you organize food?
Project: Open Your Own Fruit Stand
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.3

PROJECT 6D
Would you like to build a house?
Project: Draw Plans for a Doll House
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.5

Lesson 6.1 Patterns for Dividing with Decimals

Activity

Solve & Share

An object is 279.4 centimeters wide. If you divide the object into 10 equal parts, how wide will each part be? Solve this problem any way you choose.

How can you use structure and the relationship between multiplication and division to help you?
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.8

Look Back! What do you notice about the width of the object and the width of each part?
Answer:
The width of the object is 279.4
279.4/10 = 27.94
The width of each part is 27.94
Explanation:
An object is 279.4 centimeters wide. If we divide the object into 10 equal parts. The wide of the each part is 27.94.
Multiplication and division are the reverse or opposite of each other in that when we divide, we break apart, and when we multiply, we put together.

Visual Learning Bridge
Essential Question How Can You Divide Question Decimals by Powers of 10?

A.
Shondra wants to cut a cloth into 10 strips. All the strips should be exactly the same size. You can use place value and what you know about whole numbers to divide decimals by powers of 10. How long will each strip be?

You can divide to find equal parts of a whole.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.9

Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.10

Remember that
10 = 10!
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.11

B.
Find 89.5 ÷ 10.
Place value is based on 10. The value of each place is \(\frac{1}{10}\) the value of the place to the left. Dividing by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 6.12
89.5 ÷ 101 = 8.95
Each cloth strip will be 8.95 cm long.

Convince Me! Use Structure Celinda thought of 89.5 in parts, 80 + 9 + 0.5, and divided each part: 80 ÷ 10 = 8; 9 ÷ 10 = \(\frac{9}{10}\) or 0.9; 0.5 ÷ 10 = 0.05. Then she added the parts to get 8.95. What do you notice?
Answer:
Celinda divided 89.5 into parts as 80 + 9 + 0.5, and divided each part 80 ÷ 10 = 8; 9 ÷ 10 = 0.9; 0.5 ÷ 10 = 0.05. Then she added the parts to get 8.95. I notice when we divide the number 89.5 with 10 then the result is 8.95 and dividing 89.5 into parts also we get same result as 8.95.

Guided Practice999

Do You Understand?

Question 1.
Suppose Shondra wanted to cut the cloth into 102 strips. How long would each strip be?
Answer:
89.5 ÷ 102
89.5 ÷ 100 = 0.895
Each cloth strip will be 0.895 cm long.
Explanation:
Shondra wanted to cut the cloth into 102 strips. Place value is based on 102. The value of each place is 1/100 the value of the place to the left. Dividing by 102 results in moving each digit two places to the right. This looks the same as moving the decimal point two places to the left. Each cloth strip will be 0.895 cm long.

Question 2.
Krista divides a number by 10. Then she divides the same number by 50. Which quotient is greater? How can you tell?
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-6.12(1)
The quotient 10 is greater.
Explanation:
In the above image we can observe the quotient 10 and 2. Krista divides the number 100 by 10 then the quotient is 10. Then she divides the same number 100 by 50 then the quotient is 2. The quotient 10 is greater.

Do You Know How?

In 3-10, use mental math to find each quotient.

Question 3.
370.2 ÷ 102
Answer:
370.2 ÷ 102
370.2 ÷ 100 = 3.702
Explanation:
In the above division method the place value is based on 102. The value of each place is 1/100 the value of the place to the left. Dividing the number 370.2 by 102 results in moving each digit two places to the right. This looks the same as moving the decimal point two places to the left. The quotient for 370.2 ÷ 100 = 3.702.

Question 4.
126.4 ÷ 101
Answer:
126.4 ÷ 101
126.4 ÷ 10 = 12.64
Explanation:
In the above division method the place value is based on 101. The value of each place is 1/10 the value of the place to the left. Dividing the number 126.4 by 101 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 126.4 ÷ 10 = 12.64.

Question 5.
7.25 ÷ 10
Answer:
7.25 ÷ 10 = 0.725
Explanation:
In the above division method the place value is based on 10. The value of each place is 1/10 the value of the place to the left. Dividing the number 7.25 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 7.25 ÷ 10 = 0.725.

Question 6.
72.5 ÷ 103
Answer:
72.5 ÷ 103
72.5 ÷ 1000 = 0.0725
Explanation:
In the above division method the place value is based on 103. The value of each place is 1/1000 the value of the place to the left. Dividing the number 72.5 by 103 results in moving each digit three places to the right. This looks the same as moving the decimal point three places to the left. The quotient for 72.5 ÷ 1000 = 0.0725.

Question 7.
281.4 ÷ 100
Answer:
281.4 ÷ 100
281.4 ÷ 1 = 281.4
Explanation:
In the above division method the place value is based on 100. The value of each place is 1 the value of the place to the left. Dividing the number 281.4 by 1 results in moving each digit zero places to the right. This looks the same as moving the decimal point zero places to the left. The quotient for 281.4 ÷ 1 = 281.4.

Question 8.
2,810 ÷ 104
Answer:
2,810 ÷ 104
2,810 ÷ 10000 = 0.2810
Explanation:
In the above division method the place value is based on 104. The value of each place is 1/10000 the value of the place to the left. Dividing the number 2,810 by 104 results in moving each digit four places to the right. This looks the same as moving the decimal point four places to the left. The quotient for 2,810 ÷ 10000 = 0.2810.

Question 9.
3,642.4 ÷ 102
Answer:
3,642.4 ÷ 102
3,642.4 ÷ 100 = 36.424
Explanation:
In the above division method the place value is based on 102. The value of each place is 1/100 the value of the place to the left. Dividing the number 3,642.4 by 102 results in moving each digit two places to the right. This looks the same as moving the decimal point two places to the left. The quotient for 3,642.4 ÷ 100 = 36.424.

Question 10.
364.24 ÷ 101
Answer:
364.24 ÷ 101
364.24 ÷ 10 = 36.424
Explanation:
In the above division method the place value is based on 101. The value of each place is 1/10 the value of the place to the left. Dividing the number 364.24 by 101 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 364.24 ÷ 10 = 36.424.

Independent Practice

Leveled Practice in 11-25, find each quotient. Use mental math.

Question 11.
4,600 ÷ 10
460 ÷ 10
46 ÷ 10
4.6 ÷ 10
Answer:
4,600 ÷ 10 = 460
460 ÷ 10 = 46
46 ÷ 10 = 4.6
4.6 ÷ 10 = 0.46
Explanation:
In the above division method the place value is based on 10. The value of each place is 1/10 the value of the place to the left.
Dividing the number 4,600 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 4,600 ÷ 10 = 460.
Dividing the number 460 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 460 ÷ 10 = 46.
Dividing the number 46 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 46 ÷ 10 = 4.6.
Dividing the number 4.6 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 4.6 ÷ 10 = 0.46.

Question 12.
134.4 ÷ 103
134.4 ÷ 102
134.4 ÷ 101
134.4 ÷ 100
Answer:
134.4 ÷ 10
134.4 ÷ 1000 = 0.1344
134.4 ÷ 102
134.4 ÷ 100 = 1.344
134.4 ÷ 101
134.4 ÷ 10 = 13.44
134.4 ÷ 100
134.4 ÷ 1 = 134.4 

Explanation:
Dividing the number 134.4 by 103 results in moving each digit three places to the right. This looks the same as moving the decimal point three places to the left. The quotient for 134.4 ÷ 1000 = 0.1344.
Dividing the number 134.4 by 102 results in moving each digit two places to the right. This looks the same as moving the decimal point two places to the left. The quotient for 134.4 ÷ 100 = 1.344.
Dividing the number 134.4 by 101 results in moving each digit one two place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 134.4 ÷ 10 = 13.44.
Dividing the number 134.4 by 100 results in moving each digit zero places to the right. This looks the same as moving the decimal point zero places to the left. The quotient for 134.4 ÷ 1 = 134.4.
Question 13.
98.6 ÷ 1
98.6 ÷ 100
98.6 ÷ 10
98.6 ÷ 1,000
Answer:
98.6 ÷ 1
98.6 ÷ 1 = 98.6
98.6 ÷ 100
98.6 ÷ 100 = 0.986
98.6 ÷ 10
98.6 ÷ 10 = 9.86
98.6 ÷ 1,000
98.6 ÷ 1,000 = 0.0986
Explanation:
Dividing the number 98.6 by 1 results the quotient for 98.6 ÷ 1 = 98.6.
Dividing the number 98.6 by 100 results in moving each digit two places to the right. This looks the same as moving the decimal point two places to the left. The quotient for 98.6 ÷ 100 = 0.986.
Dividing the number 98.6 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 98.6 ÷ 10 = 9.86.
Dividing the number 98.6 by 1000 results in moving each digit three places to the right. This looks the same as moving the decimal point three places to the left. The quotient for 98.6 ÷ 1,000 = 0.0986.

Question 14.
136.5 ÷ 10
Answer:
136.5 ÷ 10 = 13.65
Explanation:
In the above division method the place value is based on 10. The value of each place is 1/10 the value of the place to the left. Dividing the number 136.5 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 136.5 ÷ 10 = 13.65.

Question 15.
753 ÷ 100
Answer:
753 ÷ 100 = 7.53
Explanation:
In the above division method the place value is based on 100. The value of each place is 1/100 the value of the place to the left. Dividing the number 753 by 100 results in moving each digit two place to the right. This looks the same as moving the decimal point two places to the left. The quotient for 753 ÷ 100 = 7.53.

Question 16.
890.1 ÷ 100
Answer:
890.1 ÷ 1 = 890.1
Explanation:
In the above division method the place value is based on 100. Dividing the number 890.1 by 1 results in moving each digit zero places to the right. This looks the same as moving the decimal point zero places to the left. The quotient for 890.1 ÷ 1 = 890.1.

Question 17.
3.71 ÷ 102
Answer:
3.71 ÷ 100 = 0.0371
Explanation:
In the above division method the place value is based on 102. The value of each place is 1/100 the value of the place to the left. Dividing the number 3.71 by 102results in moving each digit two places to the right. This looks the same as moving the decimal point two places to the left. The quotient for 3.71 ÷ 100 = 0.0371.

Question 18.
8,100 ÷ 104
Answer:
8,100 ÷ 10000 = 0.81
Explanation:
In the above division method the place value is based on 104. The value of each place is 1/10000 the value of the place to the left. Dividing the number 8100 by 104 results in moving each digit four places to the right. This looks the same as moving the decimal point four places to the left. The quotient for 8,100 ÷ 10000 = 0.81.

Question 19.
864 ÷ 103
Answer:
864 ÷ 1000 = 0.864
Explanation:
In the above division method the place value is based on 103. The value of each place is 1/1000 the value of the place to the left. Dividing the number 864 by 103 results in moving each digit three places to the right. This looks the same as moving the decimal point three places to the left. The quotient for 864 ÷ 1000 = 0.864.

Question 20.
0.52 ÷ 101
Answer:
0.52 ÷ 10 = 0.052
Explanation:
In the above division method the place value is based on 101. The value of each place is 1/10 the value of the place to the left. Dividing the number 0.52 by 101 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 0.52 ÷ 10 = 0.052.

Question 21.
15.7 ÷ 1,000
Answer:
15.7 ÷ 1,000 = 0.157
Explanation:
In the above division method the place value is based on 1000. Dividing the number 15.7 by 1000 results in moving each digit three places to the right. This looks the same as moving the decimal point three places to the left. The quotient for 15.7 ÷ 1,000 = 0.157.

Question 22.
7,700 ÷ 102
Answer:
7,700 ÷ 100 = 77
Explanation:
In the above division method the place value is based on 100. Dividing the number 7,700 by 100 results in moving each digit two places to the right. This looks the same as moving the decimal point two places to the left. The quotient for 7,700 ÷ 100 = 77.

Question 23.
770 ÷ 102
Answer:
770 ÷ 100 = 7.7
Explanation:
In the above division method the place value is based on 102. The value of each place is 1/100 the value of the place to the left. Dividing the number 770 by 100 results in moving each digit two places to the right. This looks the same as moving the decimal point two places to the left. The quotient for 770 ÷ 100 = 7.7.

Question 24.
77 ÷ 101
Answer:
77 ÷ 10 = 7.7
Explanation:
In the above division method the place value is based on 101. The value of each place is 1/10 the value of the place to the left. Dividing the number 77 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 77 ÷ 10 = 7.7.

Question 25.
7.7 ÷ 101
Answer:
7.7 ÷ 10 = 0.77
Explanation:
In the above division method the place value is based on 101. The value of each place is 1/10 the value of the place to the left. Dividing the number 7.7 by 10 results in moving each digit one place to the right. This looks the same as moving the decimal point one place to the left. The quotient for 7.7 ÷ 10 = 0.77.

Problem Solving

For 26-28, use the table that shows the winning times at the Pacific Middle School swim meet.

Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 15.3

Question 26.
What was the difference between the winning butterfly time and the winning backstroke time?
Answer:
The difference between the winning butterfly time and the winning backstroke time is 4.66 seconds.
Explanation:
The winning butterfly time is 58.49 seconds. The winning backstroke time is 53.83 seconds. Subtract the winning backstroke time from winning butterfly time then the difference is 4.66 seconds.

Question 27.
The winning time for the 100-yard freestyle was twice the time for the 50-yard freestyle. What was the winning time for the 100-yard freestyle?
Answer:
The winning time for the 100-yard freestyle is 44.34 seconds.
Explanation:
The winning time for the 100-yard freestyle was twice the time for the 50-yard freestyle. The winning time for 50-yard freestyle is 22.17 seconds. So add 22.17 seconds with 22.17 seconds then the sum is 44.34 seconds. The winning time for the 100-yard freestyle is 44. 34 seconds.

Question 28.
What was the difference between the winning 100-yard freestyle time and the winning butterfly time?
Answer:
The difference between the winning 100-yard freestyle time and the winning butterfly time is 14.15 seconds.
Explanation:
The winning 100-yard freestyle time is 44.34 seconds. The winning 100-yard butterfly time is 58.49 seconds. Subtract 100-yard freestyle winning time from 100-yard butterfly winning time then the difference is 14.15 seconds.

Question 29.
Reasoning A pickup truck carrying 103 identical bricks weighs 6,755 pounds. If the empty truck weighs 6,240 pounds, what is the weight of each brick? Explain how to solve the problem.
Answer:

Question 30.
Higher Order Thinking Katie noticed a pattern in the answers for each of the expressions below. What do you notice?
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 20.1
Answer:
14.6 x  0.1 = 1.46          14.6 ÷ 10 = 1.46
146 x 0.01 = 1.46          146 ÷ 100 = 1.46
146 x 0.001 = 0.146       146 ÷ 1,000 = 0.146
Explanation:
In first expressions I noticed that if we are multiplying 14.6 x  0.1 results the product as 1.46. When we are dividing 14.6 ÷ 10 results the quotient as 1.46.
In second expressions I noticed that if we are multiplying 146 x  0.01 results the product as 1.46. When we are dividing 146 ÷ 100 results the quotient as 1.46.
In third expressions I noticed that if we are multiplying 146 x  0.001 results the product as 0.146. When we are dividing 146 ÷ 1,000 results the quotient as 0.146.

Assessment Practice

Question 31.
Choose the equations in which n = 1,000 makes the equation true.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 0 2.5 ÷ n = 0.025
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 947.5 ÷ n = 0.9475
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 8,350 ÷ n = 8.35
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 16.4 ÷ n = 0.0164
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 0.57 ÷ n = 0.0057
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-21
Explanation:
If we put n = 1,000 in first equation 0.25 ÷ 1,000 = 0.0025. The First equation is not true.
If we put n = 1,000 in second equation 947.5 ÷ 1,000 = 0.9475. The Second equation is true.
If we put n = 1,000 in third equation 8,350 ÷ 1,000 = 8.35. The third equation is true.
If we put n = 1,000 in fourth equation 16.4 ÷ 1,000 = 0.0164. The fourth equation is true.
If we put n = 1,000 in fifth equation 0.57 ÷ 1,000 = 0.00057. The fifth equation is not true.

Question 32.
Choose the equations in which d = 102 makes the equation true.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 386.2 ÷ d = 3.862
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 4,963.6 ÷ d = 4.9636
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 0.6 ÷ d = 0.006
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 5.8 ÷ d = 0.58
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21 15.3 ÷ d = 0.153
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-21 (1)
Explanation:
If we put d = 100 in first equation 386.2 ÷ 100 = 3.862. The First equation is true.
If we put d = 100 in second equation 4,963.6 ÷ 100 = 49.636. The Second equation is not true.
If we put d = 100 in third equation 0.6 ÷ 100 = 0.006. The third equation is true.
If we put d = 100 in fourth equation 5.8 ÷ 100 = 0.058. The fourth equation is not true.
If we put d = 100 in fifth equation 15.3 ÷ 100 = 0.153. The fifth equation is true.

Lesson 6.2 Estimate Decimal Quotients

Activity

Slove&Share

A 135.8-foot piece of construction material needs to be cut into pieces that are each 16 feet long. About how many pieces can be cut? Solve this problem any way you choose.

Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21.1
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-21.1
135 ÷ 15 = 9
The construction material can be cut into 9 pieces.
Explanation:
A 135.8-foot piece of construction material is about 135. We need to cut the material into pieces that are each 16 feet long. The 16 pieces material is rounded to 15. Apply division method to solve the problem. Divide 135 with 15 then the result is 9. The construction material can be cut into 9 pieces.

You can use reasoning to estimate decimal quotients.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21.2

Look Back! Reasoning Can you find a different way to estimate the answer for the problem above? Explain.

Visual Learning Bridge

Essential Question
How Can You Use Estimation to Find Quotients?

A.
Diego borrowed money from his parents to purchase a video gaming system for $473.89 (including tax). About how much are his monthly payments to his parents if he wants to pay this off in one year?
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21.3

You can use division to find equal groups.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21.4

B.
One Way
Estimate $473.89 ÷ 12. Use rounding.
Round to the nearest ten: 473.89 rounds to 470; 12 rounds to 10
$473.89 ÷ 12 is about $470 ÷ 10 = $47.
Each monthly payment will be about $47.

C.
Another Way
Estimate $473.89 ÷ 12. Use compatible numbers.
Look for compatible numbers.
$473.89 ÷ 12 is close to $480 ÷ 12 = $40.

You know 48 ÷ 12 = 4.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21.5
Each monthly payment will be about $40.

Convince Me! Construct Arguments in the example above, which estimate is closer to the exact answer? Tell how you decided.
Answer:
We use compatible numbers to make the problem easier to solve in our head by rounding each number to the nearest ten, twenty, fifty or hundred. But if we make the numbers compatible and round up to the nearest hundred or ten spot, 300 and 350 are much easier to compute in our heads.

Guided Practice

Do You Understand?

Question 1.
Number Sense Leo is estimating 53.1 ÷ 8.4. Do you think he should use 53 ÷ 8 or 54 ÷ 9 to estimate? Why?
Answer:
Estimate 53.1 ÷ 8.4. Use compatible numbers.
Look for compatible numbers.
53.1 ÷ 8.4 is close to 54 ÷ 9 = 6.
53 ÷ 8 is not easy to find and 54 ÷ 9 is easy to find because 54 is multiple of 9.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 53.1 ÷ 8.4 is closes to 54 ÷ 9. The actual dividend 53.1 is compatible to 54. Perform division operation 54 ÷ 9 = 6. The Estimated quotient is 6. Here 54 is multiple of 9 so we can easily find out the quotient. 53 ÷ 8 = 6.625 so it is difficult to find.

Question 2.
Is each quotient greater than or less than 1?
A. 0.2 ÷ 4
B. 1.35 ÷ 0.6
Answer:
A. 0.2 ÷ 4 = 0.05
0.05 < 1
B. 1.35 ÷ 0.6 = 2.25
2.25 > 1
Explanation:
A. Divide 0.2 by 4 then the quotient is 0.05. 0.05 is less than 1.
B. Divide 1.35 by 0.6 then the quotient is 2.25. 2.25 is greater than 1.

How do you know?

In 3-8, estimate each quotient. Use rounding or compatible numbers.

Question 3.
42 ÷ 6.8
Answer:
Estimate 42 ÷ 6.8. Use compatible numbers.
Look for compatible numbers.
42 ÷ 6.8 is closes to 42 ÷ 7 = 6.
The Estimated quotient is 6.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 42 ÷ 6.8 is closes to 42 ÷ 7. The actual divisor 6.8 is compatible to 7. Perform division operation 42 ÷ 7 = 6. The Estimated quotient is 6.

Question 4.
102 ÷ 9.6
Answer:
Estimate 102 ÷ 9.6. Use rounding.
Round to the nearest ten: 102 rounds to 100; 9.6 rounds to 10
102 ÷ 9.6 is about 100 ÷ 10 = 10.
Explanation:
Rounding means replacing a number with an approximate value. In the above division method 102 ÷ 9.6. Round the numbers to the nearest ten or hundreds. Here 102 is rounded to 100 and 9.6 is rounded to 10. Now perform division operation on 100 ÷ 10 = 10. The estimated quotient is 10.

Question 5.
48.9 ÷ 4
Answer:
Estimate 48.9 ÷ 4. Use compatible numbers.
Look for compatible numbers.
48.9 ÷ 4 is closes to 50 ÷ 5 = 10.
The Estimated quotient is 10.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 48.9 ÷ 4 is closes to 50 ÷ 5. The actual dividend is 48.9 is compatible to 50. The actual divisor 4 is compatible to 5. Perform division operation 50 ÷ 5 =10. The Estimated quotient is 10.

Question 6.
72.59 ÷ 7
Answer:
Estimate 72.59 ÷ 7. Use rounding.
Round to the nearest ten: 72.59 rounds to 70; 7 rounds to 10
72.59 ÷ 7 is about 70 ÷ 10 = 7.
Explanation:
Rounding means replacing a number with an approximate value. In the above division method 72.59 ÷ 7. Round the numbers to the nearest ten or hundreds. Here 72.59 is rounded to 70 and 7 is rounded to 10. Now perform division operation on 70 ÷ 10 = 7. The estimated quotient is 7.

Question 7.
15.4 ÷ 1.9
Answer:
Estimate 15.4 ÷ 1.9. Use compatible numbers.
Look for compatible numbers.
15.4 ÷ 1.9 is closes to 16 ÷ 2 = 8.
The Estimated quotient is 8.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 15.4 ÷ 1.9 is closes to 16 ÷ 2. The actual dividend is 15.4 is compatible to 16. The actual divisor 1.9 is compatible to 2. Perform division operation 16 ÷ 2 =8. The Estimated quotient is 8.

Question 8.
44.07 ÷ 6.3
Answer:
Estimate 44.07 ÷ 6.3. Use compatible numbers.
Look for compatible numbers.
44.07 ÷ 6.3 is closes to 42 ÷ 6 = 7.
The Estimated quotient is 7.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 44.07 ÷ 6.3 is closes to 42 ÷ 6. The actual dividend is 44.07 is compatible to 42. The actual divisor 6.3 is compatible to 6. Perform division operation 42 ÷ 6 =7. The Estimated quotient is 7.

Independent Practice

Leveled Practice In 9 and 10, complete the work to estimate each quotient.

Question 9.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 20.6
Answer:
Estimate 64.5 ÷ 12.3. Use rounding.
Round to the nearest ten: 64.5 rounds to 65 ; 12.3 rounds to 10
64.5 ÷ 12.3 is about 65 ÷ 10 = 6.5.
Explanation:
Rounding means replacing a number with an approximate value. In the above division method 64.5 ÷ 12.3. Round the numbers to the nearest ten or hundreds. Here 64.5 is rounded to 65 and 12.3 is rounded to 10. Now perform division operation on 65 ÷ 10 = 6.5. The estimated quotient is 6.5.

Question 10.
Estimate 64.5 ÷ 12.3 using compatible numbers.
65 ÷ 10 = _____
Answer:
Estimate 64.5 ÷ 12.3. Use compatible numbers.
Look for compatible numbers.
64.5 ÷ 12.3 is closes to 65 ÷ 10 = 6.5.
The Estimated quotient is 6.5.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 64.5 ÷ 12.3 is closes to 65 ÷ 10. The actual dividend is 64.5 is compatible to 65. The actual divisor 12.3 is compatible to 10. Perform division operation 65 ÷ 10 =6.5. The Estimated quotient is 6.5.

In 11-19, estimate each quotient.

Question 11.
7 ÷ 0.85
Answer:
Estimate 7 ÷ 0.85. Use compatible numbers.
Look for compatible numbers.
7 ÷ 0.85 is closes to 7 ÷ 1 = 7.
The Estimated quotient is 7.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 7 ÷ 0.85 is closes to 7 ÷ 1. The actual divisor 0.85 is compatible to 1. Perform division operation 7 ÷ 1 = 7. The Estimated quotient is 7.

Question 12.
9.6 ÷ 0.91
Answer:
Estimate 9.6 ÷ 0.91. Use compatible numbers.
Look for compatible numbers.
9.6 ÷ 0.91 is closes to 10 ÷ 1 = 10.
The Estimated quotient is 10.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 9.6 ÷ 0.91 is closes to 10 ÷ 1. The actual dividend 9.6 is compatible to 10.The actual divisor 0.91 is compatible to 1. Perform division operation 10 ÷ 1 = 10. The Estimated quotient is 10.

Question 13.
17.7 ÷ 3.2
Answer:
Estimate 17.7 ÷ 3.2. Use compatible numbers.
Look for compatible numbers.
17.7 ÷ 3.2 is closes to 18 ÷ 3 = 6.
The Estimated quotient is 6.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 17.7 ÷ 3.2 is closes to 18 ÷ 3. The actual dividend 17.7 is compatible to 18.The actual divisor 3.2 is compatible to 3. Perform division operation 18 ÷ 3 = 6. The Estimated quotient is 6.

Question 14.
91.02 ÷ 4.9
Answer:
Estimate 91.02 ÷ 4.9. Use compatible numbers.
Look for compatible numbers.
91.02 ÷ 4.9 is closes to 90 ÷ 5 = 18.
The Estimated quotient is 18.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 91.02 ÷ 4.9 is closes to 90 ÷ 5. The actual dividend 91.02 is compatible to 90.The actual divisor 4.9 is compatible to 5. Perform division operation 90 ÷ 5 = 18. The Estimated quotient is 18.

Question 15.
45.64 ÷ 6.87
Answer:
Estimate 45.64 ÷ 6.87. Use compatible numbers.
Look for compatible numbers.
45.64 ÷ 6.87 is closes to 49 ÷ 7 = 7.
The Estimated quotient is 7.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 45.64 ÷ 6.87 is closes to 49 ÷ 7. The actual dividend 45.64 is compatible to 49.The actual divisor 6.87 is compatible to 7. Perform division operation 49 ÷ 7 = 7. The Estimated quotient is 7.

Question 16.
821.22 ÷ 79.4
Answer:
Estimate 821.22 ÷ 79.4. Use rounding.
Round to the nearest ten: 821.22 rounds to 800 ; 79.4 rounds to 80
821.22 ÷ 79.4 is about 800 ÷ 80 = 10.
Explanation:
Rounding means replacing a number with an approximate value. In the above division method 821.22 ÷ 79.4. Round the numbers to the nearest ten or hundreds. Here 821.22 is rounded to 800 and 79.4 is rounded to 80. Now perform division operation on 800 ÷ 80 = 10. The estimated quotient is 10.

Question 17.
22.5 ÷ 3
Answer:
Estimate 22.5 ÷ 3. Use compatible numbers.
Look for compatible numbers.
22.5 ÷ 3 is closes to 24 ÷ 3 = 8.
The Estimated quotient is 8.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 22.5 ÷ 3 is closes to 24 ÷ 3. The actual dividend 22.5 is compatible to 24. Perform division operation 24 ÷ 3 = 8. The Estimated quotient is 8.

Question 18.
15.66 ÷ 9.3
Answer:
Estimate 15.66 ÷ 9.3. Use rounding.
Round to the nearest ten: 15.66 rounds to 20 ; 9.3 rounds to 10.
15.66 ÷ 9.3 is about 20 ÷ 10 = 2.
Explanation:
Rounding means replacing a number with an approximate value. In the above division method 15.66 ÷ 9.3. Round the numbers to the nearest ten or hundreds. Here 15.66 is rounded to 20 and 9.3 is rounded to 10. Now perform division operation on 20 ÷ 10 = 2. The estimated quotient is 2.

Question 19.
156.3 ÷ 14.5
Answer:
Estimate 156.3 ÷ 14.5. Use rounding.
Round to the nearest ten: 156.3 rounds to 160 ; 14.5 rounds to 20.
156.3 ÷ 14.5 is about 160 ÷ 20 = 8.
Explanation:
Rounding means replacing a number with an approximate value. In the above division method 156.3 ÷ 14.5. Round the numbers to the nearest ten or hundreds. Here 156.3 is rounded to 160 and 14.5 is rounded to 20. Now perform division operation on 160 ÷ 20 = 8. The estimated quotient is 8.

Problem Solving

Question 20.
Luci’s mother gave her $7.50 to buy 8 spiral notebooks. With tax, the cost of each notebook is $1.05. Does Luci have enough money? Use compatible numbers and estimation to help you decide.
Answer:

Question 21.
Critique Reasoning Kerri said that the quotient of 4.2 ÷ 5 is about 8 tenths because 4.2 ÷ 5 is close to 40 tenths ÷ 5. Do you agree with Kerri’s reasoning? Explain.
Answer:

Question 22.
Higher Order Thinking Write a decimal division problem that has an estimated quotient of 4. Explain how to get that estimate.
Answer:

Question 23.
Lia’s car averages 14.5 miles per gallon while Roman’s car averages 28.5 miles per gallon. Use estimation to find how many times as many miles per gallon Roman’s car gets compared to Lia’s car.
Answer:

In 24-26, use the table.

Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 21.8

Question 24.
enVision® STEM Which sample from the experiment had the least mass? Which had the lowest temperature?
Answer:
In the above table we can observe Sample 3 had the least mass 0.058 g from the experiment. Sample 1 had the lowest temperature as 37.57°C.

Question 25.
Sample 3 was used in another experiment. A temperature of 82.14°C was recorded. How many degrees did the temperature change?
Answer:
In the above table we can observe sample 3 had the temperature 75.50°C. Sample 3 was used in another experiment. A temperature of 82.14°C was recorded. The difference of these two temperatures are 6.64°C

Question 26.
What is the difference in mass between Sample 1 and Sample 2?
Answer:
Sample 1 has the mass 0.98 g.
Sample 2 has the mass 0.58 g.
The difference in mass between Sample 1 and Sample 2 is 0.4.

Assessment Practice

Question 27.
Mauricio scored a total of 34.42 points in five gymnastic events. Which equation shows the best way to estimate Mauricio’s score for each event?
A. 35 ÷ 5 = 7
B. 35 ÷ 7 = 5
C. 30 ÷ 10 = 3
D. 40 ÷ 10 = 4
Answer:
Option A 35 ÷ 5 = 7 is correct.
35 ÷ 5 = 7 is the best way to estimate Mauricio’s score for each event.
Explanation:
Mauricio scored a total of 34.42 points in five gymnastic events. Use compatible method. In the above options option A is correct. The equation 34.42 ÷ 5 is closes to 35 ÷ 5. The actual dividend 34.42 is compatible to 35. Perform division operation 35 ÷ 5 = 7. The Estimated score for each event is 8.

Question 28.
Terry paid $117.50 for 18 identical flash drives. Which is the best estimate for the cost of each flash drive?
A. $6
B. $10
C. $12
D. $60
Answer:
Option A $6 is correct.
$117.50 ÷ 18
$120 ÷ 20 = $6.
The estimated cost of each flash drive is 6.
Explanation:
Terry paid $117.50 for 18 identical flash drives. Use rounding method. Rounding means replacing a number with an approximate value. In the above division method $117.50 ÷ 18. Round the numbers to the nearest ten or hundreds. Here $117.50 is rounded to $120 and 18 is rounded to 20. Now perform division operation on $120 ÷ 20 = $6. The estimated cost of each flash drive is $6.

Lesson 6.3 Use Models to Divide by a 1-Digit Whole Number

Activity

Solve&Share
Chris paid $3.60 for 3 colored pens. Each pen costs the same amount. How much did each pen cost? Solve this problem any way you choose.

You can use appropriate tools such as drawings, money, or place-value blocks to help you divide. Show your work!
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.1
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30
Each pen cost is $1.20.
Explanation:
Chris paid $3.60 for 3 colored pens. Each pen costs the same amount. Divide $3.60 with 3 colored pens then the quotient is $1.20. Each pen cost is $1.20.

Look Back! Without dividing, how do you know that the answer to the problem above must be greater than 1?
Answer:
The answer to the above problem must be greater than 1. Because each pen costs the same amount. we can clearly see that Chris paid $3.60 for 3 colored pens. So we can say without dividing method the answer to the above problem is greater than 1

Visual Learning Bridge

Essential Question How Can You Use Models to Find a Decimal Quotient?

A.
Three friends received $2.58 for aluminum cans they recycled. They decided to share the money equally. How much will each friend get?

You can use place value blocks. Let a 100 square = $1.00, a tenth bar = $0.10, and a hundredth cube = $0.01.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.2
Find 2.58 ÷ 3.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.3

B.
There are not enough ones to put 1 in each group, so regroup the 2 ones into 20 tenths. You can see that there are 25 tenths in 2.58. Divide the 25 tenths into 3 equal groups.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.4

C.
Trade the one extra tenth for 10 hundredths to get 18 hundredths. Divide the 18 hundredths into 3 equal groups. Each group gets 6 hundredths.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.5
Each of the 3 friends will get $0.86.

Convince Me! Reasoning The next week, 4 friends got $8.24 for the cans they collected. How much money will each friend get? Estimate using compatible numbers and then use a strategy to find the answer.

Guided Practice

Do You Understand?

Question 1.
What is a reasonable estimate for 8.24 ÷ 4? Explain.
Answer:
Estimate $8.24 ÷ 4. Use compatible numbers.
Look for compatible numbers.
$8.24 ÷ 4 is closes to $8 ÷ 4 = $2.
The Estimated quotient is $2.
Each friend get $2.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. The next week, 4 friends got $8.24 for the cans they collected. In the above division problem $8.24 ÷ 4 is closes to 8 ÷ 4. The actual dividend 8.24 is compatible to 8. Perform division operation 8 ÷ 4 = 2. The Estimated quotient is 2. Each friend get $2.

Question 2.
How is dividing a decimal by a whole number similar to dividing a whole number by a whole number? Explain.
Answer:

Do You Know How?

Question 3.
Use models to help you divide 2.16 ÷ 4. Complete the division calculation.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.6
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.6
2.16 ÷ 4 = 0.54.
Explanation:
In the above image we can observe the division of 2.16 ÷ 4 = 0.54. There are not enough ones to put 1 in each group, so regroup the 2 ones into 20 tenths. Divide 20 tenths into 4 equal groups. Each group gets 5 tenths. Four groups of 0.5 = 2.0.
Trade the one extra tenth for 10 hundredths to get 16 hundredths. Divide the 16 hundredths into 4 equal groups. Each group gets 4 hundredths. Four groups of 0.04 = 0.16.

Independent Practice

Leveled Practice In 4-9, divide. Use or draw models to help.

Question 4.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.7
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.7
1.35 ÷ 3 = 0.45
Explanation:
In the above image we can observe the division of 1.35 ÷ 3 = 0.45. There are not enough ones to put 1 in each group, so regroup the 1 ones into 10 tenths. We can see that there are 13 tenths in 1.35. Divide the 13 tenths into 3 equal groups. Each group gets 4 tenths. Three groups of 0.4 = 1.2.
Trade the one extra tenth for 10 hundredths to get 15 hundredths. Divide the 15 hundredths into 3 equal groups. Each group gets 5 hundredths. Three groups of 0.05 = 0.15.

Question 5.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.8
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.8
5.72 ÷ 4 = 1.43
Explanation:
In the above image we can observe the division of 5.72 ÷ 4 = 1.43. There are enough ones to put 1 in each group, and extra ones is regrouped. Divide the 5 ones into 4 equal groups. Each group gets 1 ones. Four groups of 1 = 4. Regroup of the 1 ones into 10 tenths. We can see that there are 17 tenths in 5.72. Divide the 17 tenths into 4 equal groups. Each group gets 4 tenths. Four groups of 0.4 = 1.6.
Trade the one extra tenth for 10 hundredths to get 12 hundredths. Divide the 12 hundredths into 4 equal groups. Each group gets 3 hundredths. Four groups of 0.03 = 0.12.

Question 6.
2.38 ÷ 7
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.9
2.38 ÷ 7 = 0.34.
Explanation:
In the above image we can observe the division of 2.38 ÷ 7 = 0.34. There are not enough ones to put 1 in each group, so regroup the 2 ones into 20 tenths. We can see that there are 23 tenths in 2.38. Divide the 23 tenths into 7 equal groups. Each group gets 3 tenths. Seven groups of 0.3 = 2.1.
Trade the two extra tenth for 20 hundredths to get 28 hundredths. Divide the 28 hundredths into 7 equal groups. Each group gets 4 hundredths. Seven groups of 0.04 = 0.28.

Question 7.
4.71 ÷ 3
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.10
4.71 ÷ 3 = 1.57.
Explanation:
In the above image we can observe the division of 4.71 ÷ 3 = 1.57. There are enough ones to put 1 in each group, and extra ones is regrouped. Divide the 3 ones into 3 equal groups. Each group gets 1 ones. Three groups of 1 = 3. Regroup of the 1 ones into 10 tenths. We can see that there are 17 tenths in 4.71. Divide the 17 tenths into 3 equal groups. Each group gets 5 tenths. Three groups of 0.5 = 1.5.
Trade the two extra tenth for 20 hundredths to get 21 hundredths. Divide the 21 hundredths into 3 equal groups. Each group gets 7 hundredths. Three groups of 0.07 = 0.21.

Question 8.
1.76 ÷ 8
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.11
1.76 ÷ 8 = 0.22.
Explanation:
In the above image we can observe the division of 1.76 ÷ 8 = 0.22. There are not enough ones to put 1 in each group, so regroup the 1 ones into 10 tenths. We can see that there are 17 tenths in 1.76. Divide the 17 tenths into 8 equal groups. Each group gets 2 tenths. Eight groups of 0.2 = 1.6.
Trade the one extra tenth for 10 hundredths to get 16 hundredths. Divide the 16 hundredths into 8 equal groups. Each group gets 2 hundredths. Eight groups of 0.02 = 0.16.

Question 9.
5.36 ÷ 2
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.12
5.36 ÷ 2 = 2.68.
Explanation:
In the above image we can observe the division of 5.36 ÷ 2 = 2.68. There are enough ones to put 2 in each group, and extra ones is regrouped. Divide the 5 ones into 2 equal groups. Each group gets 2 ones. Two groups of 2 = 4. Regroup of the 1 ones into 10 tenths. We can see that there are 13 tenths in 5.36. Divide the 13 tenths into 2 equal groups. Each group gets 6 tenths. Two groups of 0.6 = 1.2.
Trade the one extra tenth for 10 hundredths to get 16 hundredths. Divide the 16 hundredths into 2 equal groups. Each group gets 8 hundredths. Two groups of 0.08 = 0.16.

Problem Solving

Question 10.
Reasoning Alan is modeling 2.65 ÷ 5. How should he exchange the place-value blocks so he can make 5 equal shares?
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.88
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.13
2.65 ÷ 5 = 0.53
Explanation:
In the above image we can observe the division of 2.65 ÷ 5 = 0.53. There are not enough ones to put 1 in each group, so regroup the 2 ones into 20 tenths. We can see that there are 26 tenths in 2.65. Divide the 26 tenths into 5 equal groups. Each group gets 5 tenths. Five groups of 0.5 = 2.5.
Trade the one extra tenth for 10 hundredths to get 15 hundredths. Divide the 15 hundredths into 5 equal groups. Each group gets 3 hundredths. Five groups of 0.03 = 0.15.

Question 11.
Algebra Abby wants to know the value of n in the equation 7.913 × n = 791.3. What value for n makes the equation true?
Answer:
7.913 × n = 791.3
7.913 × 100 = 791.3
If n= 100 makes the equation true.

Question 12.
To find 5.16 ÷ 6, should you divide the ones first or the tenths first? Why?
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.14
First we have to divide the ones first.
5.16 ÷ 6 = 0.86
Explanation:
In the above image we can observe the division of 5.16 ÷ 6 = 0.86. There are not enough ones to put 1 in each group, so regroup the 5 ones into 50 tenths. We can see that there are 51 tenths in 5.16. Divide the 51 tenths into 6 equal groups. Each group gets 8 tenths. Six groups of 0.8 = 4.8.
Trade the one extra tenth for 10 hundredths to get 36 hundredths. Divide the 36 hundredths into 6 equal groups. Each group gets 6 hundredths. Six groups of 0.06 = 0.36.

Question 13.
There are 264 children going on a field trip. Are 5 buses enough if each bus holds 52 children? Tell how you decided.
Answer:
264 ÷ 5 = 52.8
5 buses are not enough to hold 52 children in each bus.
Explanation:
There are 264 children going on a field trip. Divide 264 by 5 then the quotient is 52.8. 5 buses are not enough to hold 52 children in each bus.

Question 14.
Higher Order Thinking Ginny earned $49.50 for 6 hours of gardening and $38.60 for 4 hours of babysitting. For which job did she earn more money per hour? How much more per hour did she earn? Explain how you found the answers.

Think about what information in the problem you need to compare.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.9
Answer:
Ginny earned $49.50 for 6 hours of gardening.
$49.50 ÷ 6 = $8.25.
Ginny earns $8.25 per hour.
Ginny earned $38.60 for 4 hours of babysitting.
$38.60 ÷ 4 = $9.65.
Ginny earns $9.65 per hour.
$9.65 – $8.25 = $1.4.
She earns more $1.4 per hour.
Explanation:
Ginny earned $49.50 for 6 hours of gardening. Perform division operation on $49.50 ÷ 6 = $8.25. Ginny earns $8.25 per hour. Ginny earned $38.60 for 4 hours of babysitting. Perform division operation on $38.60 ÷ 4 = $9.65. Ginny earns $9.65 per hour. Now we have to calculate how much more money she is earning. Subtract
$9.65 – $8.25 = $1.4. She earns more $1.4 per hour.

Assessment Practice

Question 15.
Tia drew the model below for 1.35 ÷ 3.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.10
Part A
Explain the mistake Tia made.
Answer:
1.35 ÷ 3 = 0.45.
Explanation:
In the above image we can observe the 4 groups. Tia made a mistake of drawing the model above. She has to draw 3 groups. She drew one extra group of 4 tenths and 5 hundredths.
Part B
Draw the correct model and find the quotient.
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-30.10 (1)
1.35 ÷ 3 = 0.45.
The quotient is 0.45.
Explanation:
In the above image we can observe the division of 1.35 ÷ 3 = 0.45. There are not enough ones to put 1 in each group, so regroup the 1 ones into 10 tenths. We can see that there are 13 tenths in 1.35. Divide the 13 tenths into 3 equal groups. Each group gets 4 tenths. Three groups of 0.4 = 1.2.
Trade the one extra tenth for 10 hundredths to get 15 hundredths. Divide the 15 hundredths into 3 equal groups. Each group gets 5 hundredths. Three groups of 0.05 = 0.15.

Lesson 6.4 Divide by a 2-Digit Whole Number

Activity

Solve&Share

Stan has a rectangular piece of carpet with an area of 23.4 square meters. The piece of carpet is 13 meters long. What is the width of the piece of carpet? Solve this problem any way you choose.

Model with Math You can write an equation to model the problem.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.11

Look Back! How could you estimate the width of the piece of carpet?
Answer:
23.4 ÷ 13 = ?
23.4 ÷ 13 = 1.8
The width of the piece of carpet is 1.8 meters.
Explanation:
Stan has a rectangular piece of carpet with an area of 23.4 square meters. The piece of carpet is 13 meters long. Perform division operation 23.4 ÷ 13 = 1.8. The width of the piece of carpet is 1.8 meters.

Visual Learning Bridge

Essential Question How Do You Divide Decimals Question by 2-Digit Numbers?

A.
Erin’s garden has an area of 84.8 square feet. She knows the length is 16 feet. What is the width of Erin’s garden? How can you solve 84.8 ÷ 16 = w?
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.12

You can use what you know about dividing whole numbers to help.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.13

B.
The total area is 84.8. The pieces of the model represent the areas for the partial quotients.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 30.14

Convince Me! Reasoning How could Amy use estimation to make sure the decimal point is in the correct place in the quotient?

Guided Practice

Do You Understand?
In 1 and 2, use the example on the previous page.

Question 1.
Where is 5.3 shown in the diagram?
Answer:

Question 2.
How can you check that the quotient 5.3 is reasonable? Explain.
Answer:

Do You Know How?

In 3 and 4, complete the division problem.

Question 3.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 40.1
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.1
306.25 ÷ 49 = 6.25
Explanation:
In the above image we can observe the division operation  306.25 ÷ 49 = 6.25. The nearest possible multiple value of 49 is 294(49 x 6). Subtract 294 from 306.25 so as to get the remainder 12.25. 49 cannot be a multiple of 12.25 and so we have kept a decimal in the quotient and now 49 has the least possible multiple value of 9.8(49 x 0.2) near to 12.25. After subtracting 9.8 from 12.25, we are now having 6.2 as quotient and 2.45 as remainder. Now the possible multiple value of 49 near to 2.45 is 2.45 itself(49 x 0.05 = 2.45). Now the remainder is zero and the final quotient is 6.25.

Question 4.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 40.2
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.2
28.5 ÷ 15 = 1.9
Explanation:
In the above image we can observe the division operation  28.5 ÷ 15 = 1.9. The nearest possible multiple value of 15 is 15(15 x 1). Subtract 15 from 28.5 so as to get the remainder 13.5. 15 cannot be a multiple of 13.5 and so we have kept a decimal in the quotient and now the possible multiple value of 15 near to 13.5 is 13.5 itself(15 x 0.9 = 13.5). Now the remainder is zero and the final quotient is 1.9.

Independent Practice

Leveled Practice In 5-6, find each quotient and label the model.

Question 5.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 40.3
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.3
78.2 ÷ 17 = 4.6
Explanation:
In the above image we can observe the division operation  78.2 ÷ 17 = 4.6. The nearest possible multiple value of 17 is 68(17 x 4). Subtract 68 from 78.2 so as to get the remainder 10.2. 17 cannot be a multiple of 10.2 and so we have kept a decimal in the quotient and now the possible multiple value of 17 near to 10.2 is 10.2 itself(17 x 0.6 = 10.2). Now the remainder is zero and the final quotient is 4.6.

Question 6.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 40.4
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.4
304.75 ÷ 53 = 5.75
Explanation:
In the above image we can observe the division operation  304.75÷ 53 = 5.75. The nearest possible multiple value of 53 is 265(53 x 5). Subtract 265 from 304.75 so as to get he remainder 39.75. 53 cannot be a multiple of 39.75 and so we have kept a decimal in the quotient and now 53 has the least possible multiple value of 37.10(53 x 0.7) near to 39.75. After subtracting 37.10 from 39.75, we are now having 5.7 as quotient and 2.65 as remainder. Now the possible multiple value of 53 near to 2.65 is 2.65 itself(53 x 0.05 = 2.65). Now the remainder is zero and the final quotient is 5.75.

In 7-10, find each quotient.

Question 7.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 40.5
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.5
91.8 ÷ 27 = 3.4
The quotient is 3.4
Explanation:
In the above image we can observe the division operation  91.8 ÷ 27 = 3.4. The nearest possible multiple value of 27 is 81(27 x 3). Subtract 81 from 91.8 so as to get the remainder as 10.8. 27 cannot be a multiple of 10.8 and so we have kept a decimal in the quotient and now the possible multiple value of 27 near to 10.8 is 10.8 itself(27 x 0.4 = 10.8). Now the remainder is zero and the final quotient is 3.4.

Question 8.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 40.6
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.6
3.9 ÷ 15 = 0.26
The quotient is 0.26
Explanation:
In the above image we can observe the division operation  3.9 ÷ 15 = 0.26. 15 cannot be a multiple of 3.9 so we have kept a decimal in the quotient and now 15 has the least possible multiple value of 3.0(15 x 0.2) near to 3.9. Subtract 3.0 from 3.9 then the remainder is 0.9.  Now the possible multiple value of 15 near to 0.9 is 0.9 itself(15 x 0.06 = 0.9). Now the remainder is zero and the final quotient is 0.26.

Question 9.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 40.7
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.7
39.6 ÷ 12 = 3.3
The quotient is 3.3
Explanation:
In the above image we can observe the division operation  39.6 ÷ 12 = 3.3. The nearest possible multiple value of 12 is 36(12 x 3). Subtract 36 from 39.6 so as to get the remainder as 3.6. 12 cannot be a multiple of 3.6 and so we have kept a decimal in the quotient and now the possible multiple value of 12 near to 3.6 is 3.6 itself(12 x 0.3 = 3.6). Now the remainder is zero and the final quotient is 3.3.

Question 10.
Envision Math Common Core Grade 5 Answer Key Topic 6 Use Model Strategies to Divide Decimals 40.8
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.8
247.5 ÷ 50 = 4.95
Explanation:
In the above image we can observe the division operation  247.5 ÷ 50 = 4.95. The nearest possible multiple value of 50 is 200(50 x 4). Subtract 200 from 247.5 so as to get the remainder 47.5. 50 cannot be a multiple of 47.5 and so we have kept a decimal in the quotient and now 50 has the least possible multiple value of 45.0(50 x 0.9) near to 47.5. After subtracting 45.0 from 47.5, we are now having 4.9 as quotient and 2.5 as remainder. Now the possible multiple value of 50 near to 2.5 is 2.5 itself(50 x 0.05 = 2.5). Now the remainder is zero and the final quotient is 4.95.

Problem Solving

Question 11.
Sharon pays $98.75 for twenty-five 14-ounce boxes of Yummy Flakes cereal. How much does one box of cereal cost?
Answer:

Question 12.
Javier bought a new TV for $479.76. He will make equal payments each month for 2 years. How can Javier use compatible numbers to estimate each payment?
Answer:
Estimate $479.76 ÷ 24. Use compatible numbers.
Look for compatible numbers.
$479.76 ÷ 24 is closes to $480 ÷ 24 = $20.
The Estimated quotient is $20.
Javier pays each month $20.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. Javier bought a new TV for $479.76. He will make equal payments each month for 2 years. 2years means 24 months. In the above division problem $479.76 ÷ 24 is closes to 480 ÷ 24. The actual dividend $479.76 is compatible to 480. Perform division operation 480 ÷ 24 = 20. The Estimated quotient is 20. Javier pays each month $20.

Question 13.
Higher Order Thinking The area of the rectangular flower bed shown is 20.4 square meters. How many meters of edging are needed to go around the flower bed? Explain.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 40.9
Answer:

Question 14.
Make Sense and Persevere Ms. Wang is shopping for a new refrigerator. Brand A costs $569 and uses 635 kilowatt-hours per year. Brand B costs $647 and uses 582 kilowatt-hours per year. If electricity costs $0.18 per kilowatt-hour, how much would Ms. Wang save on electricity per year by buying Brand B?
Answer:

Question 15.
Pat is driving from Seattle to Los Angeles. The distance is 1,135 miles. For the first 250 miles, it costs Pat $0.29 a mile to drive. After that, her driving cost is $0.16 a mile. What is Pat’s total driving cost?
Answer:

Assessment Practice

Question 16.
Which is equal to 27.3 divided by 13?
A. 0.21
B. 2.01
C. 2.1
D. 21
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.9
27.3 ÷ 13 = 2.1
Option C is correct.
Explanation:
Divide 27.3 by 13 then the quotient is 2.1. So option C is correct.

Question 17.
Which is equal to 73.5 divided by 21?
A. 0.35
B. 3.05
C. 3.5
D. 30.5
Answer:
Envision-Math-Common-Core-Grade-5-Answer-Key-Topic-6-Use-Model-Strategies-to-Divide-Decimals-40.10
73.5 ÷ 21 = 3.5
Option C is correct.
Explanation:
Divide 73.5 by 21 the quotient is 3.5. So option C is correct.

Lesson 6.5 Divide by a Decimal

Activity

Solve & Share
Aaron buys erasers for his pencils. Each eraser costs $0.20. The total cost is $1.20. How many erasers does Aaron buy? Solve this problem any way you choose.

You can model the problem using hundredth grids or other drawings. Show your work!
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 40.888

Look Back! Reasoning How do you know your answer makes sense?
Answer:
$1.20 ÷ ? = $0.20
$1.20 ÷ 6 = $0.20
Aaron buys 6 erasers for his pencils.
Explanation:
Aaron buys erasers for his pencils. Each eraser costs $0.20. The total cost is $1.20. Divide $1.20 by $0.20 then the answer is 6. Aaron buys 6 erasers for his pencils.

Visual Learning Bridge

Essential Question How Can You Divide a Preston Decimal by a Decimal?

A.
Michelle purchases several bottles of water. Before tax is added, the total cost is $3.60 and the cost of each bottle is $1.20. How many bottles did she buy?
Divide $3.60 by $1.20.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 40.99

You can use what you know about division with whole numbers to find how many groups of $1.20 are in $3.60.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 40.10

B.
One Way
Think: $3.60 is the same as 36 dimes. $1.20 is the same as 12 dimes.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 40.11
How many 12s are in 36?
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 40.12
She bought 3 bottles.

C.
Another Way
Think multiplication:
To find 3.60 ÷ 1.20, use the relationship between multiplication and division.
1.20 × ? = 3.60
Writing this another way:
120 hundredths ×? = 360 hundredths
? = 3
She bought 3 bottles.

Convince Me! Construct Arguments Is 3.6 ÷ 1.2 equal to, less than, or greater than 36 ÷ 12? Explain.

Guided Practice

Do You Understand?

Question 1.
How is dividing by a decimal like dividing by a whole number?
Answer:

Question 2.
How can you use multiplication to find 2.8 ÷ 0.7?
Answer:

Do You Know How?

In 3-6, use what you know about decimal division and mental math to find each quotient.

Question 3.
2 ÷ 0.5
Answer:
To find 2 ÷ 0.5, use the relationship between multiplication and division.
0.5 × ? = 2
? = 4
2 ÷ 0.5 = 4
The quotient is 4.
Explanation:
Multiply the divisor 0.5 with 4 then the product is 2. Divide the dividend 2 with the divisor 0.5 then the quotient is 4.

Question 4.
1.25 ÷ 0.25
Answer:
To find 1.25 ÷ 0.25, use the relationship between multiplication and division.
0.25 × ? = 1.25
? = 5
1.25 ÷ 0.25 = 5
The quotient is 5.
Explanation:
Multiply the divisor 0.25 with 5 then the product is 1.25. Divide the dividend 1.25 with the divisor 0.25 then the quotient is 5.

Question 5.
2.1 ÷ 0.7
Answer:
To find 2.1 ÷ 0.7, use the relationship between multiplication and division.
0.7 × ? = 2.1
? = 3
2.1 ÷ 0.7 = 3
The quotient is 3.
Explanation:
Multiply the divisor 0.7 with 3 then the product is 1.25. Divide the dividend 2.1 with the divisor 0.7 then the quotient is 3.

Question 6.
6.6 ÷ 0.3
Answer:
To find 6.6 ÷ 0.3, use the relationship between multiplication and division.
0.3 × ? = 6.6
? = 3
6.6 ÷ 0.3 = 22
The quotient is 22.
Explanation:
Multiply the divisor 0.3 with 22 then the product is 6.6. Divide the dividend 6.6 with the divisor 0.3 then the quotient is 22.

Think about how the dividend, divisor, and quotient are related.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 40.15

Independent Practice

In 7-10, use what you know about multiplication, division, place value, and partial quotients to divide.

Question 7.
2.56 ÷ 0.04
Answer:
To find 2.56 ÷ 0.04, use the relationship between multiplication and division.
0.04 × ? = 2.56
Writing this another way:
4 hundredths × ? = 256 hundredths
? = 64
2.56 ÷ 0.04 = 64
Explanation:
We have to use the relationship between multiplication and division. Multiply the divisor 0.04 with 64 then the product is 2.56. By dividing 2.56 with 0.04 then the quotient is 64.

Question 8.
25.6 ÷ 0.4
Answer:
To find 25.6 ÷ 0.4, use the relationship between multiplication and division.
0.4 × ? = 25.6
Writing this another way:
4 tenths × ? = 256 tenths
? = 64
25.6 ÷ 0.4 = 64
Explanation:
We have to use the relationship between multiplication and division. Multiply the divisor 0.4 with 64 then the product is 25.6. By dividing 25.6 with 0.4 then the quotient is 64.

Question 9.
256 ÷ 4
Answer:
To find 256 ÷ 4, use the relationship between multiplication and division.
4 × ? = 256
Writing this another way:
4 ones × ? = 256 ones
? = 64
256 ÷ 4 = 64
Explanation:
We have to use the relationship between multiplication and division. Multiply the divisor 4 with 64 then the product is 256. By dividing 256 with 4 then the quotient is 64.

Question 10.
Describe the relationship among Problems 7, 8, and 9.
Answer:
The relationship among problems 7, 8, and 9. The quotient is same in all problems. In problem 7 hundredths place value is used. In problem 8 tenths place value is used. In problem 9 ones place value is used.

In 11-18, find each quotient.

Question 11.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.1
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-50.1
4.75 ÷ 0.25 = 19
The quotient is 19.
Explanation:
In this division operation 4.75 ÷ 0.25. The dividend is 4.75 and the divisor is 0.25. By dividing dividend 4.75 with the divisor 0.25 then the quotient is 19.

Question 12.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.2
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-50.2
4.56 ÷ 0.04 = 114
The quotient is 114.
Explanation:
In this division operation 4.56 ÷ 0.04. The dividend is 4.56 and the divisor is 0.04. By dividing dividend 4.56 with the divisor 0.04 then the quotient is 114.

Question 13.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.3
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-50.3
1.05 ÷ 0.05 = 21
The quotient is 21.
Explanation:
In this division operation 1.05 ÷ 0.05. The dividend is 1.05 and the divisor is 0.05. By dividing dividend 1.05 with the divisor 0.05 then the quotient is 21.

Question 14.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.4
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-50.4
182.8 ÷ 0.1 = 1828
The quotient is 1828.
Explanation:
In this division operation 182.8 ÷ 0.1. The dividend is 182.8 and the divisor is 0.1. By dividing dividend 182.8 with the divisor 0.1 then the quotient is 1828.

Question 15.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.5
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-50.5

17.25 ÷ 0.03 = 575
The quotient is 575.
Explanation:
In this division operation 17.25 ÷ 0.03. The dividend is 17.25 and the divisor is 0.03. By dividing dividend 17.25 with the divisor 0.03 then the quotient is 575.

Question 16.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.6
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-50.6
5.68 ÷ 0.8 = 71
The quotient is 71.
Explanation:
In this division operation 5.68 ÷ 0.8. The dividend is 5.68 and the divisor is 0.8. By dividing dividend 5.68 with the divisor 0.8 then the quotient is 71.

Question 17.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.7
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-50.7
6.24 ÷ 0.06 = 104
The quotient is 104.
Explanation:
In this division operation 6.24 ÷ 0.06. The dividend is 6.24 and the divisor is 0.06. By dividing dividend 6.24 with the divisor 0.06 then the quotient is 104.

Question 18.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.8
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-50.8
27.5 ÷ 2.5 = 11
The quotient is 11
Explanation:
In this division operation 27.5 ÷ 2.5. The dividend is 27.5 and the divisor is 2.5. By dividing dividend 27.5 with the divisor 2.5 then the quotient is 11.

Problem Solving

Question 19.
Make up a money story for the equation 3.75 ÷ 0.25 = 15.
Answer:

Question 20.
Carol bought 5 pork chops and 3 steaks. Each pork chop weighed 0.32 pound and each steak weighed 0.8 pound. How many pounds of meat did Carol buy in all?
Answer:

Question 21.
Tim estimates that 60 ÷ 5.7 is about 10. Will the actual quotient be greater than or less than 10? Explain.
Answer:
Estimate 60 ÷ 5.7. Use compatible numbers.
Look for compatible numbers.
60 ÷ 5.7 is close to 60 ÷ 6 = 10.
Tim estimates that 60 ÷ 5.7 is about 10.
60 ÷ 5.7 = 10.53
The actual quotient is 10.53.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 60 ÷ 5.7 is closes to 60 ÷ 10. The actual divisor 5.7 is compatible to 6. Perform division operation 60 ÷ 6 = 10. The Estimated quotient is 10. The actual quotient is 10.53. The actual quotient is greater than 10.

Question 22.
Dex estimates that 4,989 ÷ 0.89 is about 500. Is his estimate reasonable? Why or why not?
Answer:
Estimate 4,989 ÷ 0.89. Use compatible numbers.
Look for compatible numbers.
4,989 ÷ 0.89 is close to 4,990 ÷ 1 = 4,990.
Dex estimates that 4,989 ÷ 0.89 is about 500.
His Estimation is not reasonable.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 4,989 ÷ 0.89 is closes to 4,990 ÷ 1. The actual dividend 4,989 is compatible to 4,990. The actual divisor 0.89 is compatible to 1. Perform division operation 4,990 ÷ 1 = 4,990. The Estimated quotient is 4,990. His Estimation is not reasonable.

Question 23.
Higher Order Thinking Susan solves 1.4 ÷ 0.2 using the diagram at the right. Is her reasoning correct? Explain her thinking.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 50.15
Answer:

Question 24.
Use Structure The same dividend is divided by 0.1 and 0.01. How do the quotients compare? Explain your thinking.
Answer:

Question 25.
A-Z Vocabulary Give three examples of a power of 10. Explain why one of your examples is a power of 10.
Answer:

Assessment Practice

Question 26.
Select the expressions that have a quotient of 4.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 52 2.8 ÷ 0.7
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 52 0.28 ÷ 7
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 52 2.8 ÷ 0.07
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 52 0.28 ÷ 0.07
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-52
Explanation:
In the above image we can observe the expressions that have a quotient of 4. Option 1 and option 4 is correct.
1. When 2.8 is divided by 0.7 then the quotient is 4. So option 1 is correct.
2. When 0.28 is divided by 7 then the quotient is 0.04. So option 2 is not correct.
3. When 2.8 is divided by 0.07 then the quotient is 40. So option 3 is not correct.
4. When 0.28 is divided by 0.07 then the quotient is 4. So option 4 is correct.

Question 27.
Select the expressions that have a quotient of 9.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 52 1.35 ÷ 1.5
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 52 1.35 ÷ 0.15
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 52 13.5 ÷ 1.5
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 52 13.5 ÷ 0.15
Answer:
Envision-Math-Common-Core-5th-Grade-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-52 (1)
Explanation:
In the above image we can observe the expressions that have a quotient of 9. Option 2 and option 3 is correct.
1. When 1.35 is divided by 1.5 then the quotient is 0.9. So option 1 is not correct.
2. When 1.35 is divided by 0.15 then the quotient is 9. So option 2 is correct.
3. When 13.5 is divided by 1.5 then the quotient is 9. So option 3 is  correct.
4. When 13.5 is divided by 0.15 then the quotient is 90. So option 4 is not correct.

Lesson 6.6 Reasoning

Activity

Problem Solving

Reasoning

Solve & Share
Aaron has three slabs of beeswax. He plans to melt them and use all of the wax to form 36 candles. If all the candles are the same size and weight, how much will each candle weigh? Use reasoning to decide.

Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 53.1

Thinking Habits
Be a good thinker! These questions can help you.
• What do the numbers and symbols in the problem mean?
• How are the numbers or quantities related?
• How can I represent a word problem using pictures, numbers, or equations?
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 53.4

Look Back! Reasoning Suppose Aaron wants each candle to weigh 0.5 pound. How many candles could he make with the beeswax?

Visual Learning Bridge

Essential Question How Can You Use Reasoning to Solve Problems?

A.
Ms. Watson is mixing mint green paint for her art class. She combines full bottles of blue, yellow, and white paint. How many 8-fluid ounce jars can she fill? Use reasoning to decide.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 53.5

What do I need to do to solve this problem?
I need to add the three quantities of paint. Then I need to divide the sum by the capacity of a jar.

B.
How can I use reasoning to solve this problem?
I can
• identify the quantities I know
• draw a bar diagram to show relationships.
• give the answer using the correct unit.

Here’s my thinking…
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 53.6

C.
Use bar diagrams to show how the quantities are related.
First, find the sum of the three quantities of paint in the mixture.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 53.7
Then, divide 93.6 by 8 to find the 11.7 number of jars that can be filled.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 53.8
Ms. Watson can fill 11 jars. The 12th jar will be only partially filled.

Convince Me! Reasoning Ms. Watson is mixing 34.6 fluid Ounces of red paint and 18.2 fluid ounces of yellow paint to make orange paint. How many 12-fluid Ounce jars can she fill? Use reasoning to decide.

Guided Practice

Reasoning
Miranda mixed 34.5 fluid Ounces of blue paint, 40.5 fluid ounces of red paint, and 2 fluid Ounces of black paint to make purple paint. She poured the same amount of the purple paint into each of 14 jars. How much paint did she pour in each jar?

Use reasoning to decide how the quantities in the problem are related.
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 53.9

Question 1.
Explain what each of the quantities in the problem means.
Answer:

Question 2.
Describe one way to solve the problem.
Answer:

Question 3.
What is the solution to the problem? Explain.
Answer:

Independent Practice

Reasoning
Sue made chicken soup by combining the entire can of soup shown with a full can of water. How many 10-fluid Ounce bowls can she fill with the soup? How much soup will be left over?
Envision Math Common Core 5th Grade Answers Topic 6 Use Model Strategies to Divide Decimals 54.2

Question 4.
Explain what each of the quantities in the problem means.
Answer:

Question 5.
Describe one way to solve the problem.
Answer:

Question 6.
What is the solution to the problem? Explain.
Answer:

Problem Solving

Performance Task
Cooking Competition
Lucas’s cooking class is having a cooking competition. There are 6 teams. Each student brought supplies that will be shared equally among the teams. The table shows the supplies Lucas brought. If the supplies are shared equally among the teams, how much of each supply will each team get?
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 100

Question 7.
Make Sense and Persevere Do you need all of the information given above to solve the problem? Explain.
Answer:

Question 8.
Reasoning Describe how to solve the problem.
Answer:

Use reasoning to think about what the quantities in the table represent.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 101

Question 9.
Model with Math Write equations to represent how much of each supply each team will get.
Answer:

Question 10.
Be Precise What is the solution to the problem? Explain.
Answer:

Question 11.
Critique Reasoning Lucas says that to find the total cost of the rice, you should multiply 3.5 by $1.89. Do you agree? Explain.
Answer:

Topic 6 Fluency Practice

Activity

Follow the path
Solve each problem. Follow products that are multiples of 20 to shade a path from START to FINISH. You can only move up, down, right, or left.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 55

Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 55.1
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-55.1
In the above image we can observe some multiplication problems. Products that are multiples of 20 to shade a path from START to FINISH. The products that are shaded with green color are multiples of 20.

Topic 6 Vocabulary Review

Glossary

Understand Vocabulary

Write always, sometimes, or never.

Word List
• estimate
• exponent
• hundredths
• power
• quotient
• rounding
• tenths
• thousandths

Question 1.
A digit in the hundredths place has \(\frac{1}{10}\) the value of the same digit in the tenths place. ______
Answer:
A digit in the hundredths place has \(\frac{1}{10}\) the value of the same digit in the tenths place. Sometimes.

Question 2.
The answer to a division problem is less than the divisor. ______
Answer:
The answer to a division problem is less than the divisor. Sometimes

Question 3.
A whole number divided by a decimal number is a whole number. ____
Answer:
A whole number divided by a decimal number is a whole number. Sometimes

Question 4.
Dividing by 103 moves the decimal point in the dividend three places to the left. ____
Answer:
Dividing by 103 moves the decimal point in the dividend three places to the left. Always

Question 5.
Multiplying the dividend and the divisor by the same power of 10 changes the quotient. ____
Answer:
Multiplying the dividend and the divisor by the same power of 10 changes the quotient. Never

Question 6.
The answer to a division problem is greater than the divisor. ______
Answer:
The answer to a division problem is greater than the divisor. Sometimes

Write T for true or F for false.

_____ Question 7.
3.65 ÷ 5.2 < 1
Answer: _____
3.65 ÷ 5.2 < 1
0.70 < 1
True
Explanation:
Perform division operation on 3.65 ÷ 5.2 = 0.70. The quotient is 0.70. The quotient 0.70 is less than 1. So the above expression is True.

Question 8.
48 ÷ 0.6 = 0.8
Answer:
48 ÷ 0.6 = 0.8
48 ÷ 0.6 = 80
The answer for above division operation is not correct.  So the answer is False.
Explanation:
Perform division operation on 48 ÷ 0.6 = 80. The quotient is 80.  In the above division operation the quotient is 0.8. So the above expression is False.

_____ Question 9.
2.42 ÷ 2.1 > 1.
Answer:
2.42 ÷ 2.1 > 1.
1.15 > 1
The answer for above division operation is 1.15 is greater than 1. So the answer is True.
Explanation:
Perform division operation on 2.42 ÷ 2.1 = 1.15. The quotient is 1.15. The quotient 1.15 is greater than 1. So the above expression is True.

_____ Question 10.
4.9 ÷ 0.8 < 4.9
Answer:
4.9 ÷ 0.8 < 4.9
6.125 < 4.9
The answer for above division operation is 6.125 is not less than 4.9. So the answer is False.
Explanation:
Perform division operation on 4.9 ÷ 0.8 = 6.125. The quotient is 6.125. The quotient 6.125 is  not less than 4.9. So the above expression is False.

Use Vocabulary in Writing

Question 11.
Mary says the digits in the quotient of 381.109 0.86 are 4 4 315, but she doesn’t know where to place the decimal point. How can Mary use number sense to place the decimal point? Use at least three terms from the Word List in your answer.
Answer:

Topic 6 Reteaching

Set A
pages 229-232
Find 340.5 ÷ 100.
Dividing by 10, or 101, means moving the decimal point one place to the left.
Dividing by 100, or 102, means moving the decimal point two places to the left.
Dividing by 1,000, or 103, means moving the decimal point three places to the left.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 58.10

Remember that when dividing decimals by a power of 10, you may need to use one or more zeros as placeholders.

Use mental math to find each quotient.

Question 1.
34.6 ÷ 101
Answer:
34.6 ÷ 101
34.6 ÷ 10 = 3.46
The quotient is 3.46.
Explanation:
Dividing by 10, or 101, means moving the decimal point one place to the left. Move the dividend decimal point 34.6 one place to the left then the result is 3.46. The quotient is 3.46.

Question 2.
6,483 ÷ 102
Answer:
6,483 ÷ 102
6,483 ÷ 100 = 64.83
The quotient is 64.83.
Explanation:
Dividing by 100, or 102, means moving the decimal point two places to the left. Move the dividend decimal point 6,483 two places to the left then the result is 64.83. The quotient is 64.83.

Question 3.
148.3 ÷ 100
Answer:
148.3 ÷ 100 = 1.483
The quotient is 1.483.
Explanation:
Dividing by 100, or 102, means moving the decimal point two places to the left. Move the dividend decimal point 148.3 two places to the left then the result is 1.483. The quotient is 1.483.

Question 4.
29.9 ÷ 101
Answer:
29.9 ÷ 101
29.9 ÷ 10 = 2.99
The quotient is 2.99
Explanation:
Dividing by 10, or 101, means moving the decimal point one place to the left. Move the dividend decimal point 29.9 one place to the left then the result is 2.99. The quotient is 2.99.

Question 5.
70.7 ÷ 10
Answer:
70.7 ÷ 10 = 7.07
The quotient is 7.07.
Explanation:
Dividing by 10, or 101, means moving the decimal point one place to the left. Move the dividend decimal point 70.7 one place to the left then the result is 7.07. The quotient is 7.07.

Question 6.
5,913 ÷ 103
Answer:
5,913 ÷ 103
5,913 ÷ 1000 = 5.913
The quotient is 5.913.
Explanation:
Dividing by 1,000, or 103, means moving the decimal point three places to the left. Move the dividend decimal point 5,913 three place to the left then the result is 5.913. The quotient is 5.913.

Set B
pages 233-236
Estimate 27.3 ÷ 7.1. Use compatible numbers.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 59.3
So, 27.3 ÷ 7.1 is about 4.
Estimate 42.5 ÷ 11. Use rounding.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 59.4
So, 42.5 ÷ 11 is about 4.

Remember that compatible numbers are numbers that are easy to compute in your head.

Write a number sentence that shows a way to estimate each quotient.

Question 1.
26.2 ÷ 5
Answer:
Estimate 26.2 ÷ 5. Use compatible numbers.
Look for compatible numbers.
26.2 ÷ 5 is closes to 25 ÷ 5 = 5.
So, 26.2 ÷ 5 is about 5.
The Estimated quotient is 5.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 26.2 ÷ 5 is closes to 25 ÷ 5. The actual dividend 26.2 is compatible to 25. Perform division operation 25 ÷ 5 = 5. The Estimated quotient is 5.

Question 2.
49.6 ÷ 7.8
Answer:
Estimate 49.6 ÷ 7.8. Use compatible numbers.
Look for compatible numbers.
49.6 ÷ 7.8 is closes to 49 ÷ 7 = 7.
So, 49.6 ÷ 7.8 is about 7.
The Estimated quotient is 7.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 49.6 ÷ 7.8 is closes to 49÷ 7. The actual dividend 49 is compatible to 25. The actual divisor 7.8 is compatible to 7. Perform division operation 25 ÷ 5 = 5. The Estimated quotient is 7.

Question 3.
121 ÷ 12.75
Answer:
Estimate 121 ÷ 12.75. Use compatible numbers.
Look for compatible numbers.
121 ÷ 12.75 is closes to 120 ÷ 12 = 10.
So, 121 ÷ 12.75 is about 10.
The Estimated quotient is 10.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 121 ÷ 12.75 is closes to 120 ÷ 12. The actual dividend 121 is compatible to 120. The actual divisor 12.75 is compatible to 12. Perform division operation 120 ÷ 12 = 10. The Estimated quotient is 10.

Question 4.
32.41 ÷ 10.9
Answer:
Estimate 32.41 ÷ 10.9. Use rounding.
Round to the nearest ten: 32 rounds to 30; 10.9 rounds to 10.
32.41 ÷ 10.9 is about 30 ÷ 10 = 3.
Explanation:
Rounding means replacing a number with an approximate value. In the above division method 32.41 ÷ 10.9. Round the numbers to the nearest ten or hundreds. Here 32.41 is rounded to 30 and 10.9 is rounded to 10. Now perform division operation on 30 ÷ 10 = 3. The estimated quotient is 3.

Question 5.
82.4 ÷ 3.7
Answer:
Estimate 82.4 ÷ 3.7. Use compatible numbers.
Look for compatible numbers.
82.4 ÷ 3.7 is closes to 80 ÷ 4 = 20.
So, 82.4 ÷ 3.7 is about 20.
The Estimated quotient is 20.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 82.4 ÷ 3.7 is closes to 80 ÷ 4. The actual dividend 82.4 is compatible to 80. The actual divisor 3.7 is compatible to 4. Perform division operation 80 ÷ 4 = 20. The Estimated quotient is 20.

Question 6.
28.5 ÷ 0.94
Answer:
Estimate 28.5 ÷ 0.94. Use compatible numbers.
Look for compatible numbers.
28.5 ÷ 0.94 is closes to 30 ÷ 1 = 30.
So, 28.5 ÷ 0.94 is about 30.
The Estimated quotient is 30.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 28.5 ÷ 0.94 is closes to 30 ÷ 1. The actual dividend 28.5 is compatible to 30. The actual divisor 0.94 is compatible to 1. Perform division operation 30 ÷ 1 = 30. The Estimated quotient is 30.

Set C
pages 237-240
Find 1.14 ÷ 3.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 60.1

Remember to use estimation to check the placement of the decimal point in the quotient. Divide. Use models to help.

Question 1.
6.58 ÷ 7
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-60.2
6.58 ÷ 7 = 0.94
Explanation:
In the above image we can observe the division of 6.58 ÷ 7 = 0.94. There are not enough ones to put 1 in each group, so regroup the 6 ones into 60 tenths. Divide 65 tenths into 7 equal groups. Each group gets 9 tenths. Seven groups of 0.9 = 6.3.
Trade the two extra tenth for 20 hundredths to get 28 hundredths. Divide the 28 hundredths into 7 equal groups. Each group gets 4 hundredths. Seven groups of 0.04 = 0.28.

Question 2.
156 ÷ 8
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-60.3
156 ÷ 8 = 19.5
Explanation:
In the above image we can observe the division of 156 ÷ 8 = 19.5. There are enough ones to put 1 in each group, and extra ones is regrouped. Divide the 156 ones into 8 equal groups. Each group gets 19 ones. Eight groups of 19 = 152. Regroup of the 4 ones into 40 tenths.  Divide the 40 tenths into 8 equal groups. Each group gets 5 tenths. Eight groups of 0.5 = 4.

Question 3.
34.2 ÷ 3
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-60.4
34.2 ÷ 3 = 11.4
Explanation:
In the above image we can observe the division of 34.2 ÷ 3 = 11.4. There are enough ones to put 1 in each group, and extra ones is regrouped. Divide the 34 ones into 3 equal groups. Each group gets 11 ones. Three groups of 11 = 33. Regroup of the 1 one into 10 tenths.  Divide the 12 tenths into 3 equal groups. Each group gets 4 tenths. Three groups of 0.4 = 1.2.

Question 4.
5.84 ÷ 4
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-60.5
5.84 ÷ 4 = 1.46
Explanation:
In the above image we can observe the division of 5.84 ÷ 4 = 1.46. There are enough ones to put 1 in each group, and extra ones is regrouped. Divide the 5 ones into 4 equal groups. Each group gets 1 ones. Four groups of 1 = 4. Regroup of the 1 ones into 10 tenths. We can see that there are 18 tenths in 5.84. Divide the 18 tenths into 4 equal groups. Each group gets 4 tenths. Four groups of 0.4 = 1.6.
Trade the one extra tenth for 10 hundredths to get 24 hundredths. Divide the 24 hundredths into 4 equal groups. Each group gets 6 hundredths. Four groups of 0.06 = 0.24.

Question 5.
Michelle pays $66.85 for a costume pattern and 8 yards of fabric. The costume pattern costs $4.85. How much does each yard of the fabric cost?
Answer:

Set D
pages 241-244

Find 94.5 ÷ 15.
Estimate first
94.5 ÷ 15 is close to 100 ÷ 20 = 5, so start dividing with the ones place.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 59.8
So, 94.5 ÷ 15 = 6.3

Remember that you can check your calculation by multiplying the quotient by the divisor.

Find each quotient.

Question 1.
91.2 ÷ 16
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-59.8(1)
91.2 ÷ 16 = 5.7
Explanation:
In the above image we can observe the division operation  91.2 ÷ 16 = 5.7. The nearest possible multiple value of 16 is 80(16 x 5). Subtract 80 from 91.2 so as to get the remainder 11.2. 16 cannot be a multiple of 11.2 and so we have kept a decimal in the quotient and now the possible multiple value of 16 near to 11.2 is 11.2 itself(16 x 0.7 = 11.2). Now the remainder is zero and the final quotient is 5.7.

Question 2.
361.5 ÷ 15
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-59.8(2)
361.5 ÷ 15 = 24.1
Explanation:
In the above image we can observe the division operation  361.5 ÷ 15 = 24.1. The nearest possible multiple value of 15 is 360(15 x 24). Subtract 360 from 361.5 so as to get the remainder 1.5. 15 cannot be a multiple of 1.5 and so we have kept a decimal in the quotient and now the possible multiple value of 15 near to 1.5 is 1.5 itself(15 x 0.1 = 1.5). Now the remainder is zero and the final quotient is 24.1.

Question 3.
29.04 ÷ 22
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-59.8(3)
29.04 ÷ 22 = 1.32
Explanation:
In the above image we can observe the division operation  29.04 ÷ 22 = 1.32. The nearest possible multiple value of 22 is 22(22 x 1). Subtract 22 from 29.04 so as to get the remainder 7.04. 22 cannot be a multiple of 7.04 and so we have kept a decimal in the quotient and now 22 has the least possible multiple value of 6.60(22 x 0.3) near to 7.04. After subtracting 6.6 from 7.04, we are now having 1.3 as quotient and 0.44as remainder. Now the possible multiple value of 22 near to 0.44 is 0.44 itself(22 x 0.02 = 0.44). Now the remainder is zero and the final quotient is 1.32.

Question 4.
144 ÷ 45
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-59.8(4)
144 ÷ 45 = 3.2
Explanation:
In the above image we can observe the division operation  144 ÷ 45= 3.2. The nearest possible multiple value of 45 is 135(45 x 3). Subtract 135 from 144 so as to get the remainder 9. 45 cannot be a multiple of 9 and so we have kept a decimal in the quotient and now the possible multiple value of 45 near to 9.0 is 9.0 itself(45 x 0.2 = 9.0). Now the remainder is zero and the final quotient is 3.2.

Question 5.
A 12-ounce bottle of shampoo costs $4.20. A 16-ounce bottle costs $6.88. Which shampoo costs less per ounce? How do you know?
Answer:
A 12-ounce bottle of shampoo costs $4.20.
$4.20 ÷ 12 = $0.35.
A 16-ounce bottle costs $6.88.
$6.88 ÷ 16 = $0.43
12- ounce bottle shampoo costs less per ounce is $0.35.
Explanation:
A 12-ounce bottle of shampoo costs $4.20. Divide $4.20 ÷ 12 = $0.35. A 16-ounce bottle costs $6.88.  Divide $6.88 ÷ 16 = $0.43. Compare these 12- ounce and 16- ounce bottle of shampoos. The 12-ounce bottle shampoo costs less per ounce is $0.35.

Set E
pages 245-248

Find 4.8 ÷ 0.6.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 59.9
48 tenths ÷ 6 tenths
6 tenths × ? = 48 tenths
? = 8
So, 4.8 ÷ 6 = 8

Remember to use estimation Dates to check the quotient for reasonableness.

Question 1.
6.4 ÷ 3.2
Answer:
6.4 ÷ 3.2
3.2 x 2 = 6.4
6.4 ÷ 3.2 = 2
The quotient is 2.
Explanation:
Multiply 3.2 with 2 then the product is 6.4. Dividing 6.4 by 3.2 then the quotient is 2.

Question 2.
6.4 ÷ 0.32
Answer:
0.32 x 20 = 6.4
6.4 ÷ 0.32 = 20
The quotient is 20.
Explanation:
Multiply 0.32 with 20 then the product is 6.4. Dividing 6.4 by 0.32 then the quotient is 20.

Question 3.
9.6 ÷ 0.8
Answer:
12 x 8 = 96
12 x 0.8 = 9.6
9.6 ÷ 0.8 = 12
The quotient is 12.
Explanation:
Multiply 0.8 with 12 then the product is 9.6. Dividing 9.6 by 0.8 then the quotient is 12.

Question 4.
0.96 ÷ 0.08
Answer:
12 x 8 = 96
12 x 0.08 = 0.96
0.96 ÷ 0.08 = 12
The quotient is 12.
Explanation:
Multiply 0.08 with 12 then the product is 0.96. Dividing 0.96 by 0.08 then the quotient is 12.

Question 5.
41.8 ÷ 2.2
Answer:
19 x 2.2 = 41.8
41.8 ÷ 2.2 = 19
The quotient is 19.
Explanation:
Multiply 2.2 with 19 then the product is 41.8. Dividing 41.8 by 2.2 then the quotient is 19.

Question 6.
4.18 ÷ 0.22
Answer:
0.22 x 19 = 4.18
4.18 ÷ 0.22 = 19
The quotient is 19.
Explanation:
Multiply 0.22 with 19 then the product is 4.18. Dividing 4.18 by 0.22 then the quotient is 19.

Question 7.
81.4 ÷ 7.4
Answer:
11 x 7.4 = 81.4
81.4 ÷ 7.4 = 11
The quotient is 11.
Explanation:
Multiply 7.4 with 11 then the product is 81.4. Dividing 81.4 by 7.4 then the quotient is 11.

Question 8.
814 ÷ 74
Answer:
814 ÷ 74 = 11
The quotient is 11.
Explanation:
By Dividing 814 by 74 then the quotient is 11.

Question 9.
9.6 ÷ 0.03
Answer:
9.6 ÷ 0.03 = 320
The quotient is 320.
Explanation:
By Dividing 9.6 by 0.03 then the quotient is 320.

Question 10.
9.6 ÷ 0.3
Answer:
9.6 ÷ 0.3 = 32
The quotient is 32.
Explanation:
By Dividing 9.6 by 0.3 then the quotient is 32.

Set F
pages 249-252

Think about these questions to help you reason abstractly and quantitatively.

Thinking Habits
• What do the numbers and symbols in the problem mean?
• How are the numbers or quantities related?
• How can I represent a word problem using pictures, numbers, or equations?
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 60.2

Zoey has a goal of saving $750 for a vacation. Her vacation will last 6 days. She wants to save the same amount each week for 12 weeks to reach her goal. How much should she save each week?
Which quantities do you need to solve the problem?
The savings goal is $750; Zoey will save for 12 weeks.

Will Zoey need to save more than or less than $80 each week? Explain your reasoning.
Less than; 12 × $80 = $960, but she only needs to save $750.
How much should she save each week? Write an equation to represent the problem.
$62.50; $750 :12 = $62.50

Remember to check the reasonableness of a solution by making sure your calculations are correct, and that you answered all of the questions that were asked.
lan uses 4 feet of ribbon to wrap each package. How many packages can he wrap with 5.6 yards of ribbon?

Remember there are 3 feet in a yard.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 69.1

Question 1.
Describe one way to solve the problem.
Answer:

Question 2.
What is the solution to the problem? Show your work.
Answer:

A bushel of apples weighs about 42 pounds. There are 4 pecks in a bushel. It takes 2 pounds of apples to make one pie. How many pies can you make with one peck of apples?

Question 3.
How are the numbers in the problem related?
Answer:

Question 4.
Describe one way to solve the problem.
Answer:

Question 5.
Solve the problem. Show your work.
Answer:

Topic 6 Assessment Practice

Question 1.
Mr. Dodd filled the gas tank on his lawn mower with 3.8 gallons of gas. He mowed his yard 10 times on the same tank of gas. He used the same amount of gas each time. How much gas did he use each time? Write an equation to show your work. Explain how the decimal point moves.
Answer:

Question 2.
Kimberly scored a total of 35.08 points in four events for her gymnastic competition. If she scored the same number of points in each event, how many points did she score in each? Write an equation to show your work.
Answer:
35.08 points ÷  4 = 8.77 points.
She scored 8.77 points in each event.
Explanation:
Kimberly scored a total of 35.08 points in four events for her gymnastic competition. If she scored the same number of points in each event. Divide 35.08 by 4 then the quotient is 8.77. She scored 8.77 points in each event.

Question 3.
Choose the correct quotient for each expression. Use number sense and estimation to help.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 70.1
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-70.1
Explanation:
Perform division operation on 21.6 ÷ 1.8 = 12. The quotient is 12. Put a tick mark below the number 12.
Perform division operation on 10.23 ÷ 0.55 = 18.6. The quotient is 18.6. Put a tick mark below the number 18.6.
Perform division operation on 78.75 ÷ 3.5 = 22.5. The quotient is 22.5. Put a tick mark below the number 22.5.
Perform division operation on 29.67 ÷ 4.6 = 18.6. The quotient is 18.6. Put a tick mark below the number 18.6.

Question 4.
What is the value of the missing exponent in the equation?
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 80.2
A. 1
B. 2
C. 3
D. 4
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-80.2
80.5 ÷ 102 = 0.805
The missing exponent in the equation is 2.

Question 5.
The chef at a restaurant bought 37 pounds of salad for $46.25. How much did she pay for each pound of salad?
A. 0.125
B. $1.25
C. $1.3
D. $12.50
Answer:

Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-80.2(1)
$46.25 ÷ 37 = $1.25
She pays $1.25 for each pound of salad.
Explanation:
The chef at a restaurant bought 37 pounds of salad for $46.25. Divide $46.25 by 37 pounds then the quotient is $1.25. She pays $1.25 for each pound of salad.

Question 6.
Kathleen spent $231 on concert tickets for herself and 11 friends. Each ticket cost the same amount.
A. Estimate the cost of each ticket. Write an equation to show your work.
B. Find the exact cost of each ticket. Compare your answer to your estimate to check for reasonableness.
Answer:
A. $231 ÷ 12 = ?
Estimate $231 ÷ 12 closes to 230 ÷ 12 = $19.16.
The estimated cost of each ticket is $19.16.
Explanation:
Kathleen spent $231 on concert tickets for herself and 11 friends. Each ticket cost the same amount. Divide 230 by 12 then the quotient is $19.16. The estimated cost of each ticket is $19.16.
B. $231 ÷ 12 = $19.25
The actual cost of each ticket is $19.25.
Explanation:
The estimated cost of each ticket is $19.16 and the actual cost of each ticket is $19.25.  Both estimated answer and actual answer are reasonable.

Question 7.
Select all of the following equations that are true when 12.5 is used. Use number sense to help.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 80.6
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-80.6
Explanation:
In the above image we can observe the equations that are true when 12.5 is used. Option 1 and option 3, option 5 is correct.
1. When 12.5 is divided by 10 then the quotient is 1.25. So option 1 is correct.
2. When 12.5 is divided by 1 then the quotient is 12.5. So option 2 is not correct.
3. When 12.5 is divided by 1 then the quotient is 12.5. So option 3 is correct.
4. When 12.5 is divided by 100 then the quotient is 0.125. So option 4 is not correct.
5. When 12.5 is divided by 100 then the quotient is 0.125. So option 5 is correct.

Question 8.
Which division problem does the model Tess made represent?
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 80.8
A. 1.35 ÷ 3 = 0.45
B. 1.35 ÷ 3 = 0.54
C. 1.62 ÷ 3 = 0.45
D. 1.62 ÷ 3 = 0.54
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-80.8
Option D 1.62 ÷ 3 = 0.54 is correct.
Explanation:
In the above image we can observe 5 tenths and 4 hundredths. By dividing 1.62 by 3 then the quotient is 0.54. The division problem answer option D represents the above image.

Question 9.
If 8 ounces of canned pumpkin has 82 calories, how many calories are in 1 ounce? Use your answer to find how many calories are in 6 ounces of pumpkin.
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-80.8(1)
10.25 calories are there in 1 ounce.
10.25 calories = 1 ounce
? calories    = 6 ounces
10.25 calories x 6 ounces = 61.5 calories
61.5 calories are in 6 ounces of pumpkin.
Explanation:
8 ounces of canned pumpkin has 82 calories. Perform division operation on 82 ÷ 8 = 10.25. There are 10.25 calories in 1 ounce. We have to find out the how many calories are there in 6 ounces. Perform multiplication operation on these two numbers 10.25 calories and 6 ounces then the product is 61.5 calories. There are 61.5 calories in 6 ounces of pumpkin.

Question 10.
Use the equation 1.6 ÷ n = 0.016.
A. What value of n makes the equation true? Write your answer using an exponent.
B. Explain how you know your answer is correct.
Answer:
A. 1.6 ÷ n = 0.016.
1.6 ÷ 0.01 = 0.016.
1.6 ÷ 10-2 = 0.016.
The value n = 0.01 makes the equation true. The exponent form of 0.01 is 10-2 .
B. We can check the answer is correct or not by performing division operation on 0.016 ÷ 1.6 = 0.01.

Question 11.
Eileen bought 8 roses for $45.50. Which is the best way to estimate the cost of one rose?
A. $45 ÷ 5 = $9.00
B. $48 ÷ 8 = $6.00
C. $45 ÷ 10 = $0.45
D. $40 ÷ 8 = $0.50
Answer:
Option B $48 ÷ 8 = $6.00 is the best way to estimate the cost of one rose.

Estimate $45.50÷ 8. Use compatible numbers.
Look for compatible numbers.
$45.50÷ 8 is closes to $48 ÷ 8 = $6.
The Estimated cost of one rose is $6.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. Eileen bought 8 roses for $45.50. In the above division problem $45.50÷ 8 is closes to 48 ÷ 8. The actual dividend $45.50 is compatible to 48. Perform division operation $48 ÷ 8 = 6. The Estimated cost of one rose is $6.

Question 12.
Toby’s faucet dripped a total of 1.92 liters of water in 24 hours. The faucet dripped the same amount each hour.
A. Estimate how many liters his faucet dripped each hour. Write an equation to model your work.
B. Find the exact amount of water that dripped each hour.
C. Compare your estimate to your answer. Is your answer reasonable? Explain.
Answer:
A. 1.92 liters ÷ 24 = ?
Estimate 1.92 liters ÷ 24 closes to 2 liters ÷ 24 = 0.083 liters.
The estimated amount of water dripped each hour is 0.083 liters.
Explanation:
Toby’s faucet dripped a total of 1.92 liters of water in 24 hours. Divide 2liters by 24 then the result is 0.083 liters. The estimated amount of water dripped each hour is 0.083 liters.
B. 1.92 liters ÷ 24 = 0.08 liters.
The exact amount of water that dripped each hour is 0.08 liters.
Explanation:
Perform division operation on 1.92 liters by 24 hours. The quotient is 0.08 liters. The exact amount of water that dripped each hour is 0.08 liters.
c. The estimated amount of water dripped each hour is 0.083 liters.
The exact amount of water that dripped each hour is 0.08 liters. The answer is reasonable.

Topic 6 Assessment Practice

Question 13.
Choose the correct quotient for each expression.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 85.1
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-85.1
Explanation:
Perform division operation on 0.78 ÷ 10 = 0.078. The quotient is 0.078. Put a tick mark below the number 0.078.
Perform division operation on 7,080 ÷ 103 = 7.08. The quotient is 7.08. Put a tick mark below the number 7.08.
Perform division operation on 70.8 ÷ 102 = 0.708. The quotient is 0.708. Put a tick mark below the number 0.708.
Perform division operation on 780 ÷ 103 = 0.78. The quotient is 0.78. Put a tick mark below the number 0.78.

Question 14.
Diego is making a large mural. He draws a hexagon with a perimeter of 10.5 meters. Each side of the hexagon is the same length.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 85.6
A. How many meters long is each side of Diego’s hexagon? Write an equation to model your work.
B. The total cost of the supplies to paint the mural is $38.70. Diego and 9 friends divide the total cost equally. How much does each person pay?
Answer:

Question 15.
Select all of the following equations that are true when 40.3 is used. Use number sense to help.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 86.1
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-86.1
Explanation:
In the above image we can observe the equations in option 2 and option 3 are true when 40.3 is used.
Perform division operation on 40.3 ÷ 102 = 0.403. The quotient is 0.403. So option 2 is correct.
Perform division operation on 40.3 ÷ 100 = 40.3. The quotient is 40.3. So option 3 is correct.

Question 16.
Lou’s Diner spent $12.80 on 8 pounds of potatoes. What was the cost of one pound of potatoes? What would be the total cost if the cost per pound remained the same and the diner bought 7 pounds? Show your work.
Answer:
$12.80 ÷ 8 pounds = $1.6
The cost of one pound of potatoes is $1.6.
? ÷ 7 pounds = $1.6
$1.6 x 7 pounds = $11.2
The total cost is $11.2. If the cost per pound remains same and the dinner bought 7 pounds.
Explanation:
Lou’s Diner spent $12.80 on 8 pounds of potatoes. Divide $12.80 ÷ 8 pounds = $1.6. The cost of one pound of potatoes is $1.6. If the cost per pound remains same and the dinner bought 7 pounds. Multiply $1.6 x 7 pounds = $11.2. The total cost is $11.2.

Question 17.
How many quarters are there in $30? Solve the equation 30 ÷ 0.25 to help you.
A. 12 quarters
B. 20 quarters
C. 120 quarters
D. 200 quarters
Answer:
30 ÷ 0.25 = 120
There are 120 quarters in $30.
Option C is correct.
Explanation:
Perform division operation on 30 ÷ 0.25 = 120 . Here the dividend is 30 and the divisor is 0.25. By dividing the dividend with divisor then the quotient is 120. There are 120 quarters in $30. So option C is correct.

Question 18.
When solving 6.1 ÷ 102, how is the decimal point moved?
A. 1 place to the right
B. 1 place to the left
C. 2 places to the right
D. 2 places to the left
Answer:
6.1 ÷ 102  = 0.061
Option D is correct .
Explanation:
Perform division operation on 6.1 ÷ 102  = 0.061 . Here the divisor is 102  which is 100. So the decimal point is moved two places to the left. The quotient is 0.061. So option D is correct.

Question 19.
A group of 5 friends bought a bag of grapes to share equally. If the bag of grapes weighs 11.25 pounds, how much is each person’s share? How many friends could share the grapes if each person’s share was 1.25 pounds? Write an equation to model your work.
Answer:
11.25 pounds  ÷ 5 = 2.25 pounds.
Each person share is 2.25 pounds.
11.25 pounds ÷ ? = 1.25 pounds.
11.25 pounds ÷ 9 = 1.25 pounds.
9 friends can share the grapes if each person’s share was 1.25 pounds.
Explanation:
A group of 5 friends bought a bag of grapes to share equally. The bag of grapes weighs 11.25 pounds. Perform division operation on 11.25 pounds  ÷ 5 = 2.25 pounds. Each person share is 2.25 pounds.
Divide 11.25 pounds ÷ 1.25 pounds = 9. Nine friends can share the grapes if each person’s share was 1.25 pounds.

Question 20.
When dividing 560.9 by 100, how should the decimal point be moved?
Answer:
560.9 ÷ 100 = 5.609
Explanation:
Dividing by 100, or 102, means moving the decimal point two places to the left. Move the dividend decimal point 560.9 two places to the left then the result is 5.609. The quotient is 5.609.

Question 21.
June says that there should be a decimal point in the quotient below after the 4. Is she correct? Use number sense to explain your answer. 43.94 ÷ 5.2 = 845
Answer:
43.94 ÷ 5.2 = 8.45
She is not correct. The decimal should be placed after 8.
Explanation:
June says that there should be a decimal point in the quotient after the 4. She is not correct because we have to place the decimal point after 8.

Question 22.
Three coworkers decided to buy fruit to share at lunchtime. Antonio spent $1.47 on bananas. Laura spent $2.88 on apples. Suzanne spent $2.85 on oranges.
A. Complete the bar diagram to find out how much they spent in all on fruit.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 87.2
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-87.2
They spent $7.2 in all on fruit.
Explanation:
Three coworkers decided to buy fruit to share at lunchtime. Antonio spent $1.47 on bananas. Laura spent $2.88 on apples. Suzanne spent $2.85 on oranges. Add all fruit costs. Add $1.47 with $2.88 and $2.85 then the sum is $7.2. They spent $7.2 in all on fruit.

B. They evenly divided the cost of the 3 types of fruit. How much did each person pay? Complete the bar diagram to help you.
Envision Math Common Core Grade 5 Answers Topic 6 Use Model Strategies to Divide Decimals 87.3
Answer:
Envision-Math-Common-Core-Grade-5-Answers-Topic-6-Use-Model-Strategies-to-Divide-Decimals-87.3
Each person has to pay $2.4 for fruits.
Explanation:
The three coworkers evenly divided the cost of the 3 types of fruit. The total cost of three fruits is $7.2. Divide $7.2 by 3 then the quotient is $2.4. Each person has to pay $2.4 for fruits.

C. If Laura bought 2.1 pounds of apples, is the price per pound of apples greater than or less than $1? How can you tell?
Answer:

Topic 6 Performance Task

Cooking Competition
Lydia is organizing a cooking competition at her school. She ordered some basic supplies to share among the teams that are competing. The teams will be bringing other ingredients as well.

Use the list at the right to answer the questions.

Question 1.
If 10 of the teams divide the olive oil equally, how much will each team receive? Write an equation to model your work.
Envision Math Common Core 5th Grade Answer Key Topic 6 Use Model Strategies to Divide Decimals 150
Answer:
5.4 liters ÷ 10 = 0.54 liters.
Each team receives 0.54 liters.
Explanation:
10 of the teams divide the olive oil equally. Here we have total 5.4 liters of olive oil. Perform division operation on 5.4 liters ÷ 10 = 0.54 liters. Each team receives 0.54 liters.

Question 2.
Eight teams agree to share the flour equally.
Part A
About how many grams of flour will each team get? Use compatible numbers to estimate. Write an equation to show how you estimated.
Answer:
738.4 grams ÷ 8  = ?.
Estimate 738.4 grams ÷ 8. Use compatible numbers.
Look for compatible numbers.
738.4 ÷ 8 is closes to 738 ÷ 8 = 92.25 grams.
The Estimated quotient is 92.25.
Each team get 92.25 grams of flour.
Explanation:
Compatible numbers are pairs of numbers that are easy to add, subtract, multiply, or divide mentally. When using estimation to approximate a calculation, replace actual numbers with compatible numbers. In the above division problem 738.4 grams ÷ 8 is closes to 738 ÷ 8. The actual dividend738.4 is compatible to 738.  Perform division operation 738 ÷ 8 = 92.25. The Estimated quotient is 92.25. Each team get 92.25 grams of flour.
Part B
Find the actual amount of flour each team will receive. Show your work.
Answer:
738.4 grams ÷ 8  = 92.3 grams.
Each team will receive 92.3 grams of flour.
Explanation:
Perform division operation on 738.4 grams ÷ 8  = 92.3 grams. Each team will receive the actual amount of flour is 92.3 grams.

Question 3.
Several teams agree to share the salt equally. Each team will be given 7.3 grams of salt. How many teams agree to share the salt? Write a division equation to model the problem. Then write an equivalent equation using whole numbers.
Answer:
87.6 grams ÷ ? = 7.3 grams.
87.6 grams ÷ 12 = 7.3 grams.
12 teams agree to share the salt.
Explanation:
Several teams agree to share the salt equally. Each team will be given 7.3 grams of salt. The division equation is 87.6 grams ÷ ? = 7.3 grams. Divide 87.6 with 7.3 then the answer is 12. 12 teams agree to share the salt.

Question 4.
Malcolm calculated how many liters of milk each team would get if 6 teams shared the milk equally. His work is shown at the right, but he forgot to place the decimal point in the quotient. Where should he place the decimal point? Explain.
Answer:

Envision Math Common Core 5th Grade Answer Key Topic 6 Use Model Strategies to Divide Decimals 151
8.25 liters ÷ 6 = 1.375 liters.
Malcolm has to place the decimal point before 3 and after 1.
Each team get 1.375 liters of milk.
Explanation:
Malcolm calculated how many liters of milk each team would get if 6 teams shared the milk equally. His work is shown above, but he forgot to place the decimal point in the quotient. He has to place the decimal point before 3 and after 1. Each team get 1.375 liters of milk.

Question 5.
Lydia decides to provide cheddar cheese for the competition. She buys 4.2 kilograms for $39.90.
Part A
She estimates the cost of 1 kilogram of cheese to be $1. Is her estimate reasonable? Explain.
Answer:
4.2 kilograms ÷ $39.90 = ?
Estimate 4.2 ÷ $40 = $0.105
The cost of 1 kilogram of cheese to be $0.105. Her Estimation is not reasonable.
Explanation:
Lydia decides to provide cheddar cheese for the competition. She buys 4.2 kilograms for $39.90. Perform division operation on 4.2 ÷ $40 = $0.105. The cost of 1 kilogram of cheese to be $0.105. Her Estimation is not reasonable.
Part B
To find the actual cost of 1 kilogram of cheese, Lydia needs to divide $39.90 by 4.2. How can she change the division problem to an equivalent problem using whole numbers? Write and solve the equivalent problem..
Part C
If 7 teams share the cheese equally, how much cheese will each team get?
Answer:
4.2 kilograms ÷  7 = 0.6 kilograms.
Each team get 0.6 kilograms of cheese equally.
Explanation:
The cheese we have is 4.2 kilograms. Seven teams takes the cheese equally. perform division operation on 4.2 kilograms ÷  7 = 0.6 kilograms. Each team get 0.6 kilograms of cheese equally.

Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities

Go through the enVision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities regularly and improve your accuracy in solving questions.

Envision Math Common Core 6th Grade Answers Key Topic 4 Represent And Solve Equations And Inequalities

?Topic Essential Question What procedures can be used to write and solve equations and inequalities?
Answer:
The three methods most commonly used to solve systems of equation are substitution, and elimination. Substitution and elimination are simple methods that can effectively solve most systems of two equations in a few straightforward steps
The steps to solve an inequality are:
a. Add the same number to both sides.
b. Subtract the same number from both sides.
c. Multiply both sides by the same positive number.
d. Divide both sides by the same positive number.
e. Multiply both sides by the same negative number and reverse the sign

3-ACT MATH

Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 1

Checking a Bag
A large plane flying across the ocean can weigh almost 1 million pounds! The heavier an airplane is, the more fuel it needs for a flight. The cost of fuel has led many airlines to add a weight restriction on luggage.
If you were to fly somewhere, what would you bring? What would you leave at home to minimize the weight of your luggage? Packing light is important, not only to avoid a fee but also to do your part to conserve fuel. Think about this during the 3-Act Mathematical Modeling lesson.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 2

Topic 4 EnVision STEM Project

Did You Know?
The design of a bridge depends on factors such as the distance the bridge will cover, the expected number of vehicles that will cross the bridge daily, and the geographic conditions.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 3

Your Task: Design a Bridge
Now that you have defined the problem, identified the criteria and constraints, and performed some data collection, it is time to focus on the solution. You and your classmates will continue to be engineers as you brainstorm solutions and develop prototypes for your bridge.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 4

Topic 4 Get Ready!

Review What You Know!

Vocabulary
Choose the best term from the box to complete each definition.

  • algebraic expression
  • coefficient equation
  • evaluate
  • variable

Question 1.
In 6x, x is a(n) _________ .
Answer:
We know that,
In 6x,
“6” is called as “Coefficient”
“x” is called as “Variable”
Hence, from the above,
We can conclude that
The best term that is suitable for the given statement is: Variable

Question 2.
x + 5 is an example of a(n) __________
Answer:
We know that,
The expressions are of 2 types. They are:
a. Numeric Expressions – The expression that contains only numbers and arithmetic symbols
Ex: 6 + 2 – 5
b. Algebraic expressions – The expression that contains variables, numbers,and arithmetic symbols
Ex: x + 2 – 5 + y
So,
x + 5 is an example of “Algebraic expression”
Hence, from the above,
We can conclude that
The best term that is suitable for the given statement is: Algebraic expression

Question 3.
__________ an expression to find its value.
Answer:
We know that,
“Evaluate” an expression to find its value
Hence, from the above,
We can conclude that
The best term that is suitable for the given statement is: Evaluate

Question 4.
The expressions on each side of the equal sign in a(n) __________ are equal.
Answer:
We know that,
The expressions on each side of the equal sign in an “Equation” are equal
Hence, from the above,
We can conclude that
The best term that is suitable for the given statement is: Equation

Equality

Tell whether the equation is true or false.
Question 5.
6 + 2 = 2 + 6
Answer:
The given equation is:
6 + 2 = 2 + 6
Now,
We know that,
According to the Commutative Property of Addition,
a + b = b + a
Hence, from the above,
We can conclude that
The given equation is: True

Question 6.
2.5 – 1 = 1 – 2.5
Answer:
The given equation is:
2.5 – 1 = 1 – 2.5
Now,
We know that,
According to the Commutative Property,
a – b ≠ b – a
Hence, from the above,
We can conclude that
The given equation is: False

Question 7.
\(\frac{1}{2}\) × 3= 3 × \(\frac{1}{2}\)
Answer:
The given equation is:
\(\frac{1}{2}\) × 3 = 3 × \(\frac{1}{2}\)
Now,
We know that,
According to the Commutative Property of Multiplication,
a × b = b × a
Hence, from the above,
We can conclude that
The given equation is: True

Question 8.
\(\frac{3}{4} \div 5=\frac{3}{4} \times \frac{1}{5}\)
Answer:
The given equation is:
\(\frac{3}{4}\) ÷ 5 = \(\frac{3}{4}\) × \(\frac{1}{5}\)
Now,
We know that,
When any number is present after the “Division” symbol, then it will turn into its reciprocal when it is converted into “Multiplication” and vice-versa
So,
÷ 5 will convert into × \(\frac{1}{5}\)
Hence, from the above,
We can conclude that
The given equation is: True

Question 9.
\(5 \div \frac{1}{3}=\frac{5}{3}\)
Answer:
The given equation is:
5 ÷ \(\frac{1}{3}\) = \(\frac{5}{3}\)
Now,
We know that,
When any number is present after the “Division” symbol, then it will turn into its reciprocal when it is converted into “Multiplication” and vice-versa
So,
÷ \(\frac{1}{3}\) will be converted into × 3
Hence, from the above,
We can conclude that
The given equation is: False

Question 10.
\(\frac{2}{3} \times 5=\frac{10}{15}\)
Answer:
The given equation is:
\(\frac{2}{3}\) × 5 = \(\frac{10}{15}\)
Now,
\(\frac{2}{3}\) × 5
= \(\frac{2 × 5}{3}\)
= \(\frac{10}{3}\)
Hence, from the above,
We can conclude that
The given equation is: False

Expressions

Evaluate each expression.
Question 11.
x – 2 for x = 8
Answer:
The given expression is: x – 2
Now,
For x = 8,
x – 2 = 8 – 2
= 6
Hence, from the above,
We can conclude that
The value of the given expression is: 6

Question 12.
2b for b = 9
Answer:
The given expression is: 2b
Now,
For b = 9,
2b = 2 × b
= 2 × 9
= 18
Hence, from the above,
We can conclude that
The value of the given expression is: 18

Question 13.
3\(\frac{3}{4}\) + y for y = \(\frac{5}{6}\)
Answer:
The given expression is: 3\(\frac{3}{4}\) + y
Now,
For y = \(\frac{5}{6}\),

Hence, from the above,
We can conclude that
The value of the given expression is: 4\(\frac{7}{12}\)

Question 14.
\(\frac{15}{x}\) for x = 3
Answer:
The given expression is: \(\frac{15}{x}\)
Now,
For x = 3,
\(\frac{15}{x}\) = \(\frac{15}{3}\)
= 5
Hence, from the above,
We can conclude that
The value of the given expression is: 5

Question 15.
5.6t for t = 0.7
Answer:
The given expression is: 5.6t
Now,
For t = 0.7,
5.6t = 5.6 × t
= 5.6 × 0.7
= 3.92
Hence, from the above,
We can conclude that
The value of the given expression is: 3.92

Question 16.
4x for x = \(\frac{1}{2}\)
Answer:
The given expression is: 4x
Now,
For x = \(\frac{1}{2}\),
4x = 4 × \(\frac{1}{2}\)
= \(\frac{4}{2}\)
= 2
Hence, from the above,
We can conclude that
The value of the given expression is: 2

Order of Operations

Question 17.
Explain the order in which you should compute the operations in the expression below. Then evaluate the expression.
[(33 ÷ 3) + 1] – 22
Answer:
The given expression is: [(33 ÷ 3) + 1] – 2²
Now,
We know that,
We will follow the order of operations by uisng the BODMAS rule
Where,
B – Brackets
O – Of
D – Division
M – Multiplication
A – Addition
S – Subtraction
So,
In the given expression,
The order of expressions we have to compute from the first to the last is:
a. 33 ÷ 3
b. [(33 ÷ 3) + 1]
c. 2²
d. [(33 ÷ 3) + 1] – 2²
So,
[(33 ÷ 3) + 1] – 2²
= [11 + 1] – 2²
= 12 – 4
= 8
Hence, from the above,
We can conclude that
The value of the given expression is: 8

Graphing in the Coordinate Plane

Question 18.
Describe how to plot point A(-6, 2) on a coordinate plane.
Answer:
The given point is: A (-6, 2)
Now,
When we observe the given point,
The x-coordinate of point A is negative and the y-coordinate of point A is positive
So,
For point A,
The x-coordinate is at the left side of the coordinate plane and the y-coordinate is at the top side of the coordinate plane
Hence,
The representation of A (-6, 2) in the coordinate plane is:

Language Development
Use the graphic organizer to help you understand new vocabulary terms.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 5
Answer:

Pick A Project

PROJECT 4A
If you were going to try a new exercise, what would it be? Why?
PROJECT: ANALYZE AN EXERCISE ROUTINE
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 6

PROJECT 4B
What is the most interesting book you have read?
PROJECT: WRITE AND ILLUSTRATE A CHILDREN’S BOOK
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 7

PROJECT 4C
If you were a carpenter what sorts of things would you build?
PROJECT: MAKE A MODEL OF A STAIRCASE
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 8

PROJECT 4D
What skills would you need if you wanted to move as slowly as a snail?
PROJECT: PLAN A RACE
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 9

Lesson 4.1 Understand Equations and Solutions

Solve & Discuss It!
Unit cubes are placed on a pan balance. There are 3 cubes on one pan and 9 cubes on the other pan. What can you do to make the pans balance?

Model with Math
A pan balance can be used to represent the relationship between two quantities. You can write an equation with a variable to show this relationship.
I can… determine if a value for a variable makes an equation true.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 10
Answer:
It is given that
Unit cubes are placed on a pan balance. There are 3 cubes on one pan and 9 cubes on the other pan.
Now,
Let the number of cubes on one pan that has to be added as to make the pan balance be: x
Let the number of cubes on other pan that has to be added as to make the pan balance be: y
So,
The number of cubes present on one pan = x + 3
The number of cubes present on other pan = y + 9
So,
To make the given pans balanced,
x + 3 = y + 9
Hence, from the above,
We can conclude that
The equation that makes the pans balances is:
x + 3 = y + 9

Focus on math practices
Use Structure Suppose that you added 10 cubes to the pan with 3 cubes and then added 4 cubes to the pan with 9 cubes. Would the pans balance? Write an equation to show this relationship.
Answer:
It is given that
you added 10 cubes to the pan with 3 cubes and then added 4 cubes to the pan with 9 cubes
So,
The number of cubes present on one pan = 10 + 3 = 13 cubes
The number of cubes present on other pan = 9 + 4 = 13 cubes
So,
The number of cubes present on both pans are the same
Hence, from the above,
We can conclude that
The pans are balanced

Essential Question
How can you determine whether a given number makes an equation true?
Answer:
We can check if the given solution to an expression is actually the solution the expression by replacing the variables in the equation with the given solution and solving the equation. If LHS = RHS with the given solution, the solution is correct. If not, it’s incorrect.

Try It!

Tracy received a $21.00 gift card for phone apps. She has used $9.00 of the value and wants to buy one more app from the list above to use up the balance. Complete the bar diagram and use the equation $21.00 = x + $9.00 to determine which app she should buy.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 11
The solution is _________, so Tracy should buy the _________ app.
Answer:
It is given that
Tracy received a $21.00 gift card for phone apps. She has used $9.00 of the value and wants to buy one more app from the list above to use up the balance
Now,
The given figure is:

Now,
Let x be the cost of the another app that Tracy wanted to buy
So,
According to the given information,
The equation that represents the used up balance is:
$9 + $x = $21
Now,
The representation of the above equation in the form of a bar diagram is:

So,
$x = $21 – $9
$x = $12
So,

Hence, from the above,
We can conclude that
Tracy should buy the “Remote Desktop” app with her balance of $12

Convince Me! What do you notice about the expression on the left side of an equation compared to the expression on the right side when a value is substituted for the variable? How do you know which value is a solution?
Answer:
When we observe the expression that is present on the left side of an equation and the expression that is present on the right side of an equation when a value is substituted for the variable,
We can say that
The left hand side of the equation = The right hand side of the equation
Now,
The solution for the equation is the value we substituted for a “Variable”

Try It!

Anthony has a total of y marbles and 4 boxes. He puts 13 marbles in each box and has none left over. Which of his friends, if any, correctly guessed how many marbles Anthony has in all? Use the equation y ÷ 4 = 13.
Substitute each guess for y and evaluate.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 12
Try y = 48: _______ ÷ 4 = _______
Try y = 60: _______ ÷ 4 = _______
Try y = 120: _______ ÷ 4 = _______

Of Anthony’s three friends, _______ correctly guessed the number of marbles he has in all.
No solution is given in the set of values.
Anthony has _______ marbles in all.
Answer:
It is given that
Anthony has a total of y marbles and 4 boxes. He puts 13 marbles in each box and has none left over.
Now,
The representation of the given situation in the form of a bar diagram is:

Now,
The given table is:

Now,
To find whether any friend of Anthony guesses correctly or not,
Substitute the values of marbles below

So,

Now,
The given equation that represents the number of marbles Anthony has is:
y ÷ 4 = 13
y = 13 × 4
y = 52 marbles
So,

Hence, from the above,
We can conclude that
The number of marbles Anthony has in all is: 52 marbles

KEY CONCEPT
A solution of an equation is a value for the variable that makes the equation true. Substitute values from a given set for the variable and evaluate. x – 4 = 12 x = 9, 16
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 13

Do You Understand?
Question 1.
Essential Question How can you determine whether a given number makes an equation true?
Answer:
We can check if the given solution to an expression is actually the solution the expression by replacing the variables in the equation with the given solution and solving the equation. If LHS = RHS with the given solution, the solution is correct. If not, it’s incorrect.

Question 2.
When is an equation true?
Answer:
To make a true equation, check your math to make sure that the values on each side of the equals sign are the same. Ensure that the numerical values on both sides of the “=” sign are the same to make a true equation

Question 3.
Reasoning Ben says that n = 5 is the solution of the equation 7n = 45. How can you check whether Ben is correct?
Answer:
It is given that
Ben says that n = 5 is the solution of the equation 7n = 45
Now,
The given equation is:
7n = 45
Now,
substitute the given value of n in the given equation
So,
For the given equation,
If  LHS = RHS, then
Ben is correct
If LHS ≠ RHS, then
Ben is not correct

Question 4.
A pan balance has 3 cubes on one pan and 11 cubes on the other pan. Lucy thinks she should add 7, 8, 9, or 10 cubes to make the pans balance. How can you use the equation 3 + C = 11 to find the number of cubes Lucy should add?
Answer:
It is given that
A pan balance has 3 cubes on one pan and 11 cubes on the other pan. Lucy thinks she should add 7, 8, 9, or 10 cubes to make the pans balance.
Now,
According to the given information,
The number of cubes on one pan = 3 cubes
The number of cubes on other pan = 11 cubes
Now,
It is given that
Lucy wants to add the extra cubes with 3 cubes
So,
The number of cubes in the second pan is constant
Now,
Let the number of extra cubes on one pan to be added so that the pan should be balanced be: C
So,
3 + C = 11
So,
C = 11 – 3
C = 9 cubes
So,
Lucy should add 9 cubes to make the pans balance
Hence, from the above,
We can conclude that
Lucy should add 9 cubes on one pan to make both the pans balance

Do You Know How?
In 5-8, substitute each given value of the variable to find which, if any, is a solution of the equation.
Question 5.
d + 9 = 35; d = 16, 22, 26, 36
Answer:
The given equation is:
d + 9 = 35
Now,
For d = 16,
16 + 9 = 35
25 ≠ 35
For d = 22,
22 + 9 = 35
31 ≠ 35
For d = 26,
26 + 9 = 35
35 = 35
For d = 36,
36 + 9 = 35
45 ≠ 35
Hence, from the above,
We can conclude that
d = 26 is a solution to the given equation

Question 6.
14n = 35; n = 2, 3, 3.5, 4
Answer:
The given equation is:
14n = 35
Now,
For n = 2,
14 (2) = 35
28 ≠ 35
For n = 3,
14 (3) = 35
42 ≠ 35
For n = 3.5,
14 (3.5) = 35
49 ≠ 35
For n = 4,
14 (4) = 35
56 ≠ 35
Hence, from the above,
We can conclude that
The given values of n are not any solutions for the given equation

Question 7.
13.4 – g = 8.1; g = 4.3, 5.3, 5.5, 6.5
Answer:
The given equation is:
13.4 – g = 8.1
Now,
For g = 4.3,
13.4 – 4.3 = 8.1
9.1 ≠ 8.1
For g = 5.3,
13.4 – 5.3 = 8.1
8.1 = 8.1
For g = 5.5,
13.4 – 5.5 = 8.1
7.9 ≠ 8.1
For g = 6.5,
13.4 – 6.5 = 8.1
6.9 ≠ 8.1
Hence, from the above,
We can conclude that
g = 5.3 is a solution to the given equation

Question 8.
4 = 36 ÷ m; m = 4, 6, 8, 9
Answer:
The given equation is:
4 = 36 ÷ m
Now,
For m = 4,
4 = 36 ÷ 4
4 ≠ 9
For m = 6,
4 = 36 ÷ 6
4 ≠ 6
For m = 8,
4 = 36 ÷ 8
4 ≠ 4.5
For m = 9,
4 = 36 ÷ 9
4 = 4
Hence, from the above,
We can conclude that
m = 9 is a solution to the given equation

In 9-12, tell whether each equation is true or false for n = 8.
Question 9.
n = 54 – 36
Answer:
The given equation is:
n = 54 – 36
Now,
n = 54 – 36
= 18
So,
8 ≠ 18
Hence, from the above,
We can conclude that
The given equation is False for n = 8

Question 10.
5n = 40
Answer:
The given equation is:
5n = 40
Now,
5n = 40
n = \(\frac{40}{5}\)
= 8
So,
8 = 8
Hence, from the above,
We can conclude that
The given equation is True for n = 8

Question 11.
152 ÷ n = 21
Answer:
The given equation is:
152 ÷ n = 21
Now,
152 ÷ n = 21
n = \(\frac{152}{21}\)
= 0.7
So,
0.7 ≠ 8
Hence, from the above,
We can conclude that
The given equation is False for n = 8

Question 12.
n + 46 = 54
Answer:
The given equation is:
n + 46 = 54
Now,
n + 46 = 54
n = 54 – 46
= 8
So,
8 = 8
Hence, from the above,
We can conclude that
The given equation is True for n = 8

Practice & Problem Solving

In 13-16, tell which given value, if any, is a solution of the equation.
Question 13.
t – 2.1 = 0           t = 2.1, 2.4, 2.6, 2.8
Answer:
The given equation is:
t – 2.1 = 0
Now,
t – 2.1 = 0
Now,
Add with 2.1 on both sides
So,
t – 2.1 + 2.1 = 0 + 2.1
t = 2.1
Hence, from the above,
We can conclude that
t = 2.1 is the solution for the given equation

Question 14.
49 = 7r            r = 3, 6, 7, 9
Answer:
The given equation is:
49 = 7r
Now,
49 = 7r
Divide by 7 on both sides
So,
\(\frac{49}{7}\) = \(\frac{7r}{7}\)
7 = r
Hence, from the above,
We can conclude that
r = 7 is the solution for the given equation

Question 15.
$4.10 = $6.25 – y           y = $2.15, $2.95, $3.05, $3.15
Answer:
The given equation is:
$4.10 = $6.25 – y
Now,
$4.10 = $6.25 – y
y = $6.25 – $4.10
y = $2.15
Hence, from the above,
We can conclude that
y = $2.15 is the solution for the given equation

Question 16.
24 ÷ h = 6         h = 1, 3, 6, 8
Answer:
The given equation is:
24 ÷ h = 6
Now,
24 ÷ h = 6
h = \(\frac{24}{6}\)
h = 4
Hence, from the above,
We can conclude that
There is not any solution from the given values for the given equation

Question 17.
In the past, Marcie’s father rode his bike 108 miles in 7.5 hours. Her mother rode the same distance in 8 hours. Marcie plans to ride her bike 108 miles at a steady rate of 18 mph for y hours. Will she match her father’s or mother’s time? Use the equation 108 ÷ y = 18 to justify your answer.
Answer:
It is given that
In the past, Marcie’s father rode his bike 108 miles in 7.5 hours. Her mother rode the same distance in 8 hours. Marcie plans to ride her bike 108 miles at a steady rate of 18 mph for y hours.
Now,
We know that,
Speed = \(\frac{Distance}{Time}\)
Time = \(\frac{Distance}{Speed}\)
So,
According to the given information,
The time took for Marcie to ride her bike at a steady rate (t) = (The distance rode by Marcie) ÷ (The speed of Marcie’s bike)
= 108 ÷ 18
= 6 hours
Now,
From the given information,
The time took for Marcie’s father to ride his bike is: 7.5 hours
The time took for Marcie’s mother to ride her bike is: 8 hours
So,
6 ≠ 7.5 ≠ 8
Hence, from the above,
We can conclude that
Marcie will not match her father’s or mother’s time

Question 18.
Write if b = 6 is a solution or is not a solution of each equation.
a. 8b = 48
b. 11 – b = 6
c. b + 3 = 9
d. 54 ÷ b = 9
Answer:
The given expression sare:
a. 8b = 48
b. 11 – b = 6
c. b + 3 = 9
d. 54 ÷ b = 9
Now,
a.
For b = 6,
8 (6) = 48
48 = 48
b.
For b = 6,
11 – 6 = 6
5 ≠ 6
c.
For b = 6,
6 + 3 = 9
9 = 9
d.
For b = 6,
54 ÷ 6 = 9
9 = 9
Hence, from the above,
We can conclude that
The equations that have a solution b = 6 are:

Question 19.
A group of 4 friends is planning a fun day trip. The equations in the table represent the number of people n who can participate in each activity for $29.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 14
Which activity should the friends choose if they want to spend exactly $29?
Answer:
It is given that
A group of 4 friends is planning a fun day trip. The equations in the table represent the number of people n who can participate in each activity for $29.
Now,
The given table is:

Now,
For the friends to choose an activity so as they spend exactly $29,
The solutions of the variables should satisfy their own equations
Now,
a. For the Raft Trip activity:
The given equation is:
6n + 5 = 29
6n = 29 – 5
6n = 24
n = \(\frac{24}{6}\)
n = 4
Verification:
6 (4) + 5 = 29
24 + 5 = 29
29 = 29
b. For the Amusement park Trip activity:
The given equation is:
14n = 29
n = \(\frac{29}{14}\)
n = 2.07
n ≅ 2
Verification:
14 (2) = 29
28 ≠ 29
c. For the Balloon Ride activity:
30n – 40 = 29
30n = 20 + 49
30n = 69
n = \(\frac{69}{30}\)
n = \(\frac{23}{10}\)
n = 2.3
n ≅ 2
Verification:
30 (2) – 40 = 29
60 – 40 = 29
20 ≠ 29
Hence, from the above,
We can conclude that
The activity the friends should choose if they want to spend exactly $29 is: Raft Trip

Question 20.
There are 27 pennies on one pan of a pan balance and 18 pennies on the other. To make the pans balance, Hillary thinks 5 pennies should be added to the higher pan. Sean thinks 8 pennies should be added, and Rachel thinks 9 pennies should be added. Use the equation 27 = 18 + p to determine who is correct.
Answer:
It is given that
There are 27 pennies on one pan of a pan balance and 18 pennies on the other. To make the pans balance, Hillary thinks 5 pennies should be added to the higher pan. Sean thinks 8 pennies should be added, and Rachel thinks 9 pennies should be added
Now,
Let the nuber of pennies added be: p
Now,
The given equation in the problem that represents the situation is:
27 = 18 + p
So,
On the basis of the given information,
According to Hillary, p = 5
According to Sean, p = 8
According to Rachel, p = 9
Now,
For p = 5,
27 = 18 + p
27 = 18 + 5
27 ≠ 23
Now,
For p = 8,
27 = 18 + p
27 = 18 + 8
27 ≠ 26
Now,
For p = 9,
27 = 18 + p
27 = 18 + 9
27 = 27
Hence, from the above,
We can conclude that
Rachel is correct

Question 21.
Construct Arguments Gerard spent $5.12 for a drink and a sandwich. His drink cost $1.30. Did he have a ham sandwich for $3.54, a tuna sandwich for $3.82, or a turkey sandwich for $3.92? Use the equation s + 1.30 = 5.12 to justify your answer.
Answer:
It is given that
Gerard spent $5.12 for a drink and a sandwich. His drink cost $1.30
Now,
Let the cost of sandwich be: $s
So,
According to the given information,
$5.12 = s + $1.30
Subtract $1.30 on both sides
So,
$5.12 – $1.30 = s + $1.30 – $1.30
s = $3.82
Now,
According to the given information,
The cost of tuna sandwich is: $3.82
Hence, from the above,
We can conclude that
Gerard will have a tuna sandwich

Question 22.
Higher Order Thinking Write an equation that has a solution of 12. Show how you know that 12 is the solution.
Answer:
Let the equation that has a solution of 12 be:
6x = 72
Now,
We know that,
To find whether the solution is correct or not, substitute the solution in the place of the variable present in that equation and if LHS = RHS, then that solution is true for the equation
So,
The equation is: 6x = 72
Now,
Substitute 12 in place of x
So,
6 (12) = 72
Hence,
72 = 72

Question 23.
Gina’s family is driving 255 miles to visit Tallahassee. After driving for a while, they pass a sign that reads “Tallahassee: 124 miles.” Substitute the values m = 111, 121, 131, and 141 in the equation 255 – m = 124 to find the number of miles the family has already driven.
Answer:
It is given that
Gina’s family is driving 255 miles to visit Tallahassee. After driving for a while, they pass a sign that reads “Tallahassee: 124 miles.”
Now,
The given equation to represent the number of miles the Gina’s family has already driven is:
255 – m = 124 with m = 111, 121, 131, and 141
Now,
For m = 111,
255 – m = 124
255 – 111 = 124
144  ≠ 124
Now,,
For m = 121,
255 – m = 124
255 – 121 = 124
134  ≠ 124
Now,
For m = 131,
255 – m = 124
255 – 131 = 124
124  = 124
Now,
For m = 141,
255 – m = 124
255 – 141 = 124
114  ≠ 124
Hence, from the above,
We can conclude that
The number of miles the Gina’s family has already driven is: 131 miles

Question 24.
Lisa is making a quilt that uses a pattern of triangles like the one shown. Write an equation that represents the missing side length if the perimeter is 19 centimeters
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 15
Answer:
It is given that
Lisa is making a quilt that uses a pattern of triangles like the one shown
Now,
The given figure is:
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 15
Now,
We know that,
The “Perimeter” of a figure is the sum of all the side lengths of a figure
So,
For the given figure,
Perimeter = 5 + (3 + 3) + m + 3
19 = 5 + 6 + m + 3
19 = 14 + m
m = 19 – 14
m = 5 cm
Hence, from the above,
We can conclude that
The missing side length is: 5 cm

Question 25.
Alisa’s family planted 7 palm trees in their yard. The park down the street has 147 palm trees. Alisa guessed that the park has either 11 or 31 times as many palm trees as her yard has. Is either of Alisa’s guesses correct? Use the equation 7n = 147 to justify your answer.
Answer:
It is given that
Alisa’s family planted 7 palm trees in their yard. The park down the street has 147 palm trees. Alisa guessed that the park has either 11 or 31 times as many palm trees as her yard has.
Now,
The equation that represents the given information that is given in the problem is:
7n = 147
So,
n = \(\frac{147}{7}\)
n = 21 palm trees
But,
According to the given information,
Alisa had guessed that the park has either 11 or 31 times as many palm trees as her yard has
Hence, from the above,
We can conclude that
Alisa’s guesses are not correct

Assessment Practice

Question 26.
Trish has $26.00 to spend at a craft store. She buys fabric that costs $18.62. She also wants to buy knitting needles for $7.32, silk flowers for $7.38, or oil paints for $8.48.
Use the equation $18.62 + c = $26.00, where c is the item cost, to find the most expensive item Trish can buy Explain how you found your answer.
Answer:
It is given that
Trish has $26.00 to spend at a craft store. She buys fabric that costs $18.62. She also wants to buy knitting needles for $7.32, silk flowers for $7.38, or oil paints for $8.48.
Now,
The equation that represents the given information and is mentioned in the problem is:
$18.62 + c = $26.00
So,
c = $26.00 – $18.62
c = $7.38
So,
Trish can buy silk flowers with her balance
Hence, from the above,
We can conclude that
The most expensive item Trish can buy with the remaining amount of money is: Silk flowers

Lesson 4.2 Apply Properties of Equality

Solve & Discuss It!
Start with the equation 4 + 8 = 12 and complete each computation listed below. Do each computation individually. Which of the computations keeps the equation true? Explain.

I can… use the properties of equality to write equivalent equations.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 16
Answer:
The given equation is:
4 + 8 = 12
Now,
We know that,
The equation will be true only when the equations’s
LHS = RHS
Now,
The completed table with the individual computations and the result as “True” and “False” is:

Hence, from the above,
We can conclude that
The computations that keep the equation true are:
a. Add 5 to both sides of the equation
b. Subtract 4 from both sides of the equation

Reasoning
How can you determine whether an equation is true?
Answer:
From above,
The completed table is:

Now,
We know that,
According to the Properties of Equality,
In an equation,
The operation we performed with the given number on the left side of the equation will be as the same as the operation we performed with the same number on the right side of the equation
So,
From the completed table,
Only 2 computations follows the “Properties of equality”
Hence, from the above,
We can conclude that
We can determine the equation by using the “Properties of equality”

Focus on math practices
Use Structure Complete the equation 7 + ☐ = 10 – ☐ by filling in the missing numbers. Describe at least two other operations with numbers that you can do to each side of the completed equation to keep it true.
Answer:
Let the missing number on the left side and right side of the given equation be: x
Now,
We know that,
According to the Properties of Equality,
In an equation,
The operation we performed with the given number on the left side of the equation will be as the same as the operation we performed with the same number on the right side of the equation
So,
7 + x = 10 – x
x + x = 10 – 7
2x = 3
x = \(\frac{3}{2}\)
x = 1.5
Hence, from the above,
We can conclude that
The completed equation is:

Essential Question
How can you use the properties of equality to write equivalent equations?
Answer:
Just as you can add or subtract the same exact quantity on both sides of an equation, you can also multiply both sides of an equation by the same quantity to write an equivalent equation.

Try It!

If 5y = 25, which property of equality was used to keep the equation 5y – 7 = 25 – 7 equal?
Answer:
The given equation is:
5y = 25
Now,
We know that,
The “Subtraction Property of equality” states that when you subtract the same amount from both sides of an equation, the two sides of the equation stay equal
So,
According to the above property,
5y = 25 changed into 5y – 7 = 25 – 7
Hence, from the above,
We can conclude that
The “Subtraction Property of Equality” was used to keep the equation 5y – 7 = 25 – 7 equal

Convince Me! What other properties of equality could you apply to keep the equation 5y = 25 equal? Give an example of each.
The given equation is:
5y = 25
Now,
We know that,
We can use any “Property of Equality” like “Addition Property of equality”, “Subtraction Property of equality” , “Multiplication Property of equality”, and “Division Property of equality” to keep the given equation true
Hence, from the above,
We can conclude that
The other properties of equality you could apply to keep the equation 5y = 25 equal are:
a. Addition Property of equality
b. Multiplication Property of equality
c. Division Property of equality

Try It!

A. A scale balances with four blue x-blocks on one side and 36 green blocks on the other side. Complete the equation to balance the scale with only one blue x-block.
4 • x = 36
(4 • x) ÷ ☐ = 36 ÷ ☐
x = 9
Answer:
It is given that
A scale balances with four blue x-blocks on one side and 36 green blocks on the other side.
Now,
According to the given information,
To balance the equation with only one blue x-block,
Divide the both sides of the given equation by 4 so that only one blue x rock will be present
So,

Hence, from the above,
We can conclude that
The number of blue x-rocks are: 9 blue x-rocks

B. If 25 + d = 36, does 25 + d – 25 = 36 – 20? Explain.
Answer:
The given equations are: 25 + d = 36 and 25 + d – 25 = 36 – 20
Now,
We know that,
The “Subtraction Property of equality” states that when you subtract the same amount from both sides of an equation, the two sides of the equation stay equal
So,
For 25+ d = 36,
According to the given second equation,
25 + d – 25 = 36 – 25
Hence, from the above,
We can conclude that
If 25 +d = 36, then 25 + d – 25 = 36 – 25

KEY CONCEPT
You can use the properties of equality to write equivalent equations.

Addition Property of Equality
7 + 3 = 10
(7 + 3) + a = 10 + a
Add the same amount to each side to keep the equation balanced.

Subtraction Property of Equality
7 + 3 = 10
(7 + 3) – a = 10 – a
Subtract the same amount from each side to keep the equation balanced.

Multiplication Property of Equality
7 + 3 = 10
(7 + 3) × a = 10 × a
Multiply each side of the equation by the same amount to keep the equation balanced.

Division Property of Equality
7+ 3 = 10
(7 + 3) ÷ a = 10 ÷ a
Divide each side of the equation by the same non-zero amount to keep the equation balanced.

Do You Understand?
Question 1.
Essential Question How can you use the properties of equality to write equivalent equations?
Answer:
Just as you can add or subtract the same exact quantity on both sides of an equation, you can also multiply both sides of an equation by the same quantity to write an equivalent equation.

Question 2.
A pan balance shows 7 + 5 = 12. If 4 units are removed from one side, what needs to be done to the other side to keep the pans balanced?
Answer:
It is given that
A pan balance shows 7 + 5 = 12. and 4 units are removed from one side
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
So,
To keeps the pans balanced, we have to remove 4 from the other side also
Hence, from the above,
We can conclude that
We have to remove 4 from other side also to keep the pans balanced

Question 3.
If one side of the equation 23 + 43 = 66 is multiplied by 3, what needs to be done to the other side of the equation to keep the sides equal?
Answer:
It is given that
One side of the equation 23 + 43 = 66 is multiplied by 3
Now,
We know that,
According to the “Multiplication Property of Equality”,
Multiply the same amount from each side to keep the equation balanced.
So,
To keeps the pans balanced, we have to multiply 3 to the other side also
Hence, from the above,
We can conclude that
We have to multiply 3 to the other side also to keep the pans balanced

Question 4.
Reasoning If one side of the equation x + 5 = 8 has 9 added to it and the other side has (4 + 5) added to it, will the equation stay equal?
Answer:
It is given that
One side of the equation x + 5 = 8 has 9 added to it and the other side has (4 + 5) added to it
Now,
We know that,
According to the “Addition Property of Equality”,
Add the same amount from each side to keep the equation balanced.
Now,
We know that,
4 + 5 = 9
So,
The equation stays equal
Hence, from the above,
We can conclude that
The equation will stay equal even we added (4 + 5) to the other side of the equation

Do You Know How?
In 5 and 6, answer yes or no and explain why or why not.
Question 5.
If 23 + 37 = 60, does 23 + 37 + 9 = 60 + 9?
Answer:
The given equations are:
23 + 37 = 60 and 23 + 37 + 9 = 60 + 9
Now,
We know that,
According to the “Addition Property of Equality”,
Add the same amount from each side to keep the equation balanced.
So,
From the above equation,
We can observe that
9 is added to both sides
Hence, from the above,
We can conclude that
The given equation is true

Question 6.
If 16 + 1 = 17, does (16 + 1) – 1 = 17 – 2?
Answer:
The given equations are:
16 + 1 = 17 and (16 + 1) – 1 = 17 – 2
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
So,
From the above equation,
We can observe that
1 is subtracted from one side and 2 is subtracted from the other side
Hence, from the above,
We can conclude that
The given equation is false

Question 7.
Apply the Multiplication Property of Equality to write an equation equivalent to 7n = 28.
Answer:
The given equation is:
7n = 28
Now,
We know that,
According to the “Multiplication Property of Equality”,
Multiply the same amount from each side to keep the equation balanced.
Now,
Let the number be multiplied on both sides of the equation be 2
So,
According the Multiplication Property of Equality,
7n × 2 = 28 × 2
Hence, from the above,
We can conclude that
According to the Multiplication Property of equation,
The equation that is equivalent to the given equation is:
7n × 2 = 28 × 2

Question 8.
Critique Reasoning Tomas says that if one side of the equation 6m = 9 is divided by 2 and the other side is divided by 3, the equation will stay equal because the result will be 3m = 3. Is Tomas correct? Explain.
Answer:
It is given that
Tomas says that one side of the equation 6m = 9 is divided by 2 and the other side is divided by 3
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount from each side to keep the equation balanced.
So,
We have to divide the both sides of the equation by either only 2 or only 2 but not with 2 on one side and with 3 on other side
Hence,f rom the above,
We can conclude that
Tomas is not correct

Practice & Problem Solving

In 9-12, tell which property of equality was used.
Question 9.
5m + 4 = 19
5m + 4 – 3 = 19 – 3
Answer:
The given equations are:
5m + 4 = 19
5m + 4 – 3 = 19 – 3
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
So,
From the given equation,
We can observe that
We subtracted 3 on both sides
Hence, from the above,
We can conclude that
“Subtraction Property of Equality” was used for the given equation

Question 10.
3t = 20
3t ÷ 2 = 20 ÷ 2
Answer:
The given equations are:
3t = 20
3t ÷ 2 = 20 ÷ 2
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount at each side to keep the equation balanced.
So,
From the given equation,
We can observe that
We divided by 2 on both sides
Hence, from the above,
We can conclude that
“Division Property of Equality” was used for the given equation

Question 11.
\(\frac{n}{6}\) = 9
\(\left(\frac{n}{6}\right)\) × 5 = 9 × 5
Answer:
The given equations are:
\(\frac{n}{6}\) = 9
\(\frac{n}{6}\) × 5 = 9 × 5
Now,
We know that,
According to the “Multiplication Property of Equality”,
Multiply the same amount at each side to keep the equation balanced.
So,
From the given equation,
We can observe that
We multiplied 5 on both sides
Hence, from the above,
We can conclude that
“Multiplication Property of Equality” was used for the given equation

Question 12.
5b – 6 = 14
(5b – 6) + 2 = 14 + 2
Answer:
The given equations are:
5b – 6 = 14
(5b – 6) + 2 = 14 + 2
Now,
We know that,
According to the “Addition Property of Equality”,
Add the same amount at each side to keep the equation balanced.
So,
From the given equation,
We can observe that
We added 2 on both sides
Hence, from the above,
We can conclude that
“Addition Property of Equality” was used for the given equation

Question 13.
If r + 9 = 42, does r + 9 – 9 = 42 + 9? Why or why not?
Answer:
The given equations are:
r + 9 = 42
r + 9 – 9 = 42 + 9
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
So,
From the given equation,
We can observe that
We subtracted 9 from one side and added 9 at the other side
Hence, from the above,
We can conclude that
r + 9 = 42 is not the equivalent of r + 9 – 9 = 42 + 9

Question 14.
If 6s = 24, does 6s ÷ 6 = 24 ÷ 6? Why or why not?
Answer:
The given equations are:
6s = 24
6s ÷ 6 = 24 ÷ 6
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount at each side to keep the equation balanced.
So,
From the given equation,
We can observe that
We divided with 6 on both sides
Hence, from the above,
We can conclude that
6s = 24 is the equivalent of 6s ÷ 6 = 24 ÷ 6

Question 15.
This scale was balanced. Find the number to add that makes the scale become balanced again. Then complete the equation to make it true.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 17
Answer:
It is given that
This scale was balanced
Now,
The given figure is:

Now,
From the given figure,
We can observe that
To make the scale balanced again,
We have to add some quantity to 12 on the left side of the pan
Now,
Let the some quantity that is added on the left side of the pan be x
So,
To make the scale balanced,
12 + x = 2 + 7+ 3 + 16
So,
12 + x = 28
Subtract with 12 on both sides
12 + x – 12 = 28 – 12
x = 28 – 12
x = 16
Hence, from the above,
We can conclude that
The completed equation so that the equation is true is:

Question 16.
This scale balanced with 3 green blocks on one side and 1 blue x-block on the other side. Find the number to multiply by that makes the scale balance. Then complete the equation to make it true.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 18
Answer:
It is given that
This scale balanced with 3 green blocks on one side and 1 blue x-block on the other side
Now,
The given figure is:

Now,
From the given information,
The equation that represents the given situation is:
1x = 3
So,
x = 3
Now,
Multiply both sides with 5
So,
5 × x = 3 × 5
5x = 15
15 = 5x
Hence, from the above,
We can conclude that
The completed equation so that the equation will be true is:

Question 17.
You start with the equation 8x = 24. Your friend changes the equation as follows.
8x = 24 ÷ 4
How can you make your friend’s equation equivalent to the original equation?
Answer:
The given equations are:
8x = 24
8x = 24 ÷ 4
Now,
From the above equation,
We can observe that
Your friend wants to change the equation by dividing the equation by 4
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount at each side to keep the equation balanced.
So,
For the given equation,
We have to divide by 4 on both sides instead of only one side like your friend
So,
8x ÷ 4 = 24 ÷ 4
Hence, from the above,
We can conclude that
The representation of your friend’s equation equivalent to the original given equation is:
8x ÷ 4 = 24 ÷ 4

Question 18.
A scale balanced with 1 blue x-block and 20 green blocks on the left side and 40 green blocks on the right side. A student bumped into the scale and knocked some blocks off so that only 1 blue x-block and 3 green blocks remained on the left side. How many blocks do you need to remove from the right side to make the scale balance?
Answer:
It is given that
A scale balanced with 1 blue x-block and 20 green blocks on the left side and 40 green blocks on the right side. A student bumped into the scale and knocked some blocks off so that only 1 blue x-block and 3 green blocks remained on the left side
So,
According to the given information,
Now,
Before a student bumped into the scale,
The representation of the equation is:
1x blue rocks + 20 green rocks = 40 green rocks
x blue rocks + 20 green rocks = 40 green rocks
Now,
After a student bumped into the scale,
x blue rocks + 20 green rocks – 0 blue rocks – 17 green rocks = 40 green rocks – x
Where,
x is the variable to make the equation balanced
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
So,
x blue rocks + 20 green rocks – 0 blue rocks – 17 green rocks = 40 green rocks – 0 blue rocks – 17 green rocks
Hence, from the above,
We can conclude that
The number of blocks you needed to remove from the right side to make the scale balance is: 17 green rocks

Question 19.
Bobbie wrote y + 6 = 15. Then she wrote (y + 6) ÷ 3 = 15. Explain why the second equation is not equivalent to the first. What can Bobbie do to make the two equations equivalent?
Answer:
It is given that
Bobbie wrote y + 6 = 15. Then she wrote (y + 6) ÷ 3 = 15
Now,
The given equations are:
y + 6 = 15
(y + 6) ÷ 3 = 15
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount at each side to keep the equation balanced.
So,
From the given equation,
We can observe that
We have to divide by 3 on both sides
But,
According to the second equation,
It has been divided only on the left side
So,
(y + 6) ÷ 3 ≠ 15
Hence, from the above,
We can conclude that
Due to the “Division Property of Equality”,
(y + 6) ÷ 3 ≠ 15

Question 20.
Construct Arguments John wrote that 5 + 5 = 10. Then he wrote that 5 + 5 + n = 10 + n. Are the equations John wrote equivalent? Explain.
Answer:
It is given that
John wrote that 5 + 5 = 10. Then he wrote that 5 + 5 + n = 10 + n
Now,
The given equations are:
5 + 5 = 10
5 + 5 + n = 10 + n
Now,
We know that,
According to the “Addition Property of Equality”,
Add the same amount at each side to keep the equation balanced.
So,
From the given equation,
We can observe that
John added n at both sides
So,
5 + 5 = 10 is equivalent to 5 + 5 + n = 10 + n
Hence, from the above,
We can conclude that
Due to the Addition Property of Equality,
5 + 5 = 10 is equivalent to 5 + 5 + n = 10 + n

Question 21.
Reasoning Scientists often use a pan balance to measure mass when doing experiments. The equation 4 + 3 – 1 = 7 – 1 represents a scientist taking away one unit of mass from each side of a pan balance. Construct an argument to explain how the scientist knows that the pans are still in balance.
Answer:
It is given that
Scientists often use a pan balance to measure mass when doing experiments. The equation 4 + 3 – 1 = 7 – 1 represents a scientist taking away one unit of mass from each side of a pan balance.
Now,
The given expression is:
4 + 3 – 1 = 7 – 1
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
So,
From the given equation,
We can observe that
1 is subtracted from both sides of the equation
So,
The pans are still in balance according to “Subtraction Property of Equality”
Hence, from the above,
We can conclude that
The pans are still in balance according to “Subtraction Property of Equality”

Question 22.
Bryce wrote the equation n – 3 = 4. Lexi used a property of equality to write an equivalent equation. Write an equation Lexi could have written. Explain how you know the equations are equivalent.
Answer:
It is given that
Bryce wrote the equation n – 3 = 4. Lexi used a property of equality to write an equivalent equation
Now,
The given equation is:
n – 3 = 4
Now,
We know that,
According to the “Addition Property of Equality”,
Add the same amount at each side to keep the equation balanced.
So,
n – 3 + 3 = 4 + 3
n = 7
So,
The equivalent equation of the given equation is: n = 7
Hence, from the above,
We can conclude that
The equation Lexi could have written is: n = 7
The equation swritten by Bryce and Lexi are equivalent by using the “Additie Property of Equality”

Question 23.
Higher Order Thinking Emil has $1 and a quarter. Jade has 5 quarters. If Emil gives Jade $1 and Jade gives Emil 4 quarters, will they each still have the same amount of money? Explain.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 19
Answer:
It is given that
Emil has $1 and a quarter. Jade has 5 quarters and Emil gives Jade $1 and Jade gives Emil 4 quarters
Now,
We know that,
1 Quarter = $0.25
Now,
The amount of money Emil contains = $1 + $0.25
= $1.25
The amount of money Jade contains = 5 × $0.25
= $1.25
Now,
If Emil gives Jade $1, then
The amount of money Jade contains = $1.25 + $1
= $2.25
The remaining amount of money Emil contains = $1.25 – $1
= $0.25
If Jade gives 4 Quarters to Emil, then
The amount of money Emil contains = $0.25 + 4 × $0.25
= $0.25 + $1
= $1.25
Hence, from the above,
We can conclude that
Emil and Jade each still have the same amount of money

Question 24.
Vocabulary If 7w = 49, which property of equality was used to find the equivalent equation 7w ÷ 7 = 49 ÷ 7?
Answer:
The given equations are:
7w = 49
7w ÷ 7 = 49 ÷ 7
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount at each side to keep the equation balanced.
So,
From the given equation,
We can observe that
7 is divided on both sides
Hence, from the above,
We can conclude that
“Division Property of Equality” was used to find the equivalent equation  of the given equation 7w ÷ 7 = 49 ÷ 7

Question 25.
You start with the equation 12b = 24. What step should you take to find the quantity that equals 4b?
Answer:
The given equation is:
12b = 24
Now,
It is given that
After using the “Equality Property”, we have to make 12b as 4b
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount at each side to keep the equation balanced.
So,
Divide the given equation by 3 on both sides
So,
\(\frac{12b}{3}\) = \(\frac{24}{3}\)
4b = 8
Hence, from the above,
We can conclude that
To find the quantity “4b”,
We have to use “Division Property of Equality” for the given equation

Assessment Practice

Question 26.
Which equation is equivalent to n + 4 = 11?.
A. (n + 4) × 2 = 11
B. (n + 4) × 2 = 11 ÷ 2
C. (n + 4) × 2 = 11 × 4
D (n + 4) × 2 = 11 × 2
Answer:
The given equation is:
n + 4 = 11
Now.
We know that,
According to the “Properties of Equality”,
The operation we are doing at the left side will be the same as the operation we are doing at the right side
Hence, from the above,
We can conclude that
The equation that is equivalent to n + 4 = 11 is:

Question 27.
Which of the equations is NOT equivalent to 8p = 12? Select all that apply.
☐ 8p ÷ 8 = 12 ÷ 8
☐ 8p ÷ 8 = 12 ÷ 12
☐ 8p + 4 = 12 + 4
☐ 8p – 2 = 12 – 2
☐ 8p × 8 = 12 × 12
Answer:
The given equation is:
8p = 12
Now.
We know that,
According to the “Properties of Equality”,
The operation we are doing at the left side will be the same as the operation we are doing at the right side
Hence, from the above,
We can conclude that
The equations that are not equivalent to 8p = 12 are:

Lesson 4.3 Write and Solve Addition and Subtraction Equations

Solve & Discuss It!
A group of students were on a school bus. How many students were on the bus before the last stop?
I can… write and solve an addition or subtraction equation.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 20

Use Appropriate Tools
You use a pan balance to help solve for the unknown.
Answer:
It is given that
A group of students were on a school bus
Now,
The given figure is:
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 20
Now,
From the given figure,
We can observe that
The total number of students arrived at school = (The total number of students present on the bus before the last stop) + (The total number of students present on the bus at the last stop)
Now,
Let the total number of students present on the bus before the last stop be x
So,
25 = x + 16
x = 25 – 16
x = 9 students
Hence, from the above,
We can conclude that
The total number of students present on the bus before the last stop is: 9 students

Focus on math practices
Reasoning How does using cubes on the pan balance demonstrate the Addition and Subtraction Properties of Equality?
Answer:
In the pan balance,
The cubes represent the variables
Remember that the pans must be in a balanced position and it is represented by “=”
Ex:
In a pan balance,
At one side, 3x cubes are present
At other side, 2x cubes are present
So,
The balanced pan will be:
3x = 2x
Ex:
In a pan balance,
At one side, 10x cubes are added
At other side, 25x cubes are added and later, 6x quantities are removed
So,
The balance pan will be:
10x = 25x – 6x

Essential Question
How can you write and solve an addition or subtraction equation?
Answer:
a.
To write a proper addition equation, you have an equals sign. One side shows you the total. The other side shows you what things are being added together. You can have a variable on either side of the equation
b.
When we write a subtraction equation, we use two symbols: – and =. The minus sign (-) means one thing is being subtracted from another

Try It!

Cabrini had some markers. After she bought 12 more markers, she had 16. How many markers did Cabrini have at the start?
Let n represent the number of markers Cabrini had at the start.
Solve the addition equation.
n + 12 = 16
n + 12 ___ = 16 ____
n = _____
Cabrini had ______ markers at the start.
Answer:
It is given that
Cabrini had some markers. After she bought 12 more markers, she had 16
Now,
Let the number of markers Cabrini had before she bought more markers be: x
So,
According to the given information,
The equation will be:
x + 12 = 16
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
So,
Subtract 12 from both sides in the given equation
So,

Hence, from the above,
We can conclude that
Cabrini had 4 markers at the start

Convince Me! Which property of equality is used to solve the equation n + 12 = 16? Could one of the other properties of equality have also been used? Explain.
The given equation is:
n + 12 = 16
Now,
To solve the above equation,
The property of equality we used is “Subtraction Property of Equality”
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
Now,
We know that,
If we observe the above equation,
We can say that,
We can use other “Properties of Equality” like “Addition Property of Equality”, “Multiplication Property of Equality”, and “Division Property of Equality”
Hence, from the above,
We can conclude that
We used “Subtraction Property of Equality” to solve the given equation n + 12 = 16
The other properties of equality can also be used to solve the given equation n + 12 = 16

Try It!

Vivian read 14 fewer pages than she was assigned to read. She read 60 pages. Write and solve an equation to find how many pages, p, Vivian was assigned to read.
Answer:
It is given that
Vivian read 14 fewer pages than she was assigned to read. She read 60 pages.
Now,
Let the number of pages Vivian was assigned to read be: x pages
Now,
According to the given information,
The equation that represents the given situation is:
x – 14 = 60
Now,
We know that,
According to the “Addition Property of Equality”,
Add the same amount at each side to keep the equation balanced.
So,
Add 14 on both sides to the given equation
So,
x – 14 + 14 = 60 + 14
x = 74 pages
Hence, from the above,
We can conclude that
The number of pages Vivian was assigned to read is: 74 pages

KEY CONCEPT
You can use inverse relationships and the properties of equality to solve equations.
Envision Math Common Core 6th Grade Answer Key Topic 4 Represent And Solve Equations And Inequalities 21

Do You Understand?
Question 1.
Essential Question How can you write and solve an addition or subtraction equation?
Answer:
a.
To write a proper addition equation, you have an equals sign. One side shows you the total. The other side shows you what things are being added together. You can have a variable on either side of the equation
b.
When we write a subtraction equation, we use two symbols: – and =. The minus sign (-) means one thing is being subtracted from another

Question 2.
Explain how you can use the inverse relationship of addition and subtraction to solve the equation n + 7 = 25.
Answer:
The given equation is:
n + 7 = 25
Now,
We know that,
Addition and subtraction are inverse operations because one operation can “undo” the other operation
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
Now,
subtract 7 from both sides
So,
n + 7 – 7 = 25 – 7
n = 18
Hence, from the above,
We can conclude that
The value of n for the given equation is: 18

Question 3.
Model with Math Clare had t seashells. After she bought 8 more seashells, she had 24 seashells. Write and solve an equation to find the number of seashells Clare started with.
Answer:
It is given that
Clare had t seashells. After she bought 8 more seashells, she had 24 seashells.
So,
The number of seashells = (The number of seashells Clare had at the start) + (The number of seashells she bought after the start)
24 = t + 8
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
Now,
subtract 8 from both sides
So,
24 – 8 = t + 8 – 8
t = 16 seashells
Hence, from the above,
We can conclude that
The number of seashells Clare had at the start is: 16 seashells

Question 4.
Model with Math The outside temperature dropped 20°F from the time Arianna ate breakfast until the time she ate dinner. When she ate dinner the temperature was 35°F. Write and solve an equation to find the outside temperature t when Arianna ate breakfast.
Answer:
It is given that
The outside temperature dropped 20°F from the time Arianna ate breakfast until the time she ate dinner. When she ate dinner the temperature was 35°F
So,
The outside temperature from the time Arianna ate breakfast until the time she ate dinner = (The outside temperature when Arianna ate breakfast) + (The outside temperature when Arianna ate dinner)
20° F = x° F + 35° F
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from each side to keep the equation balanced.
Now,
subtract 35° F from both sides
So,
20° F – 35° F = x° F + 35° F – 35° F
x° F = – 15° F
Hence, from above,
We can conclude that
The outside temperature when Arianna ate breakfast is: -15° F

Do You Know How?
In 5-10, solve each equation.
Question 5.
24 + m = 49
Answer:
The given equation is:
24 + m = 49
Now,
Subtract with 24 on both sides
So,
24 + m – 24 = 49 – 24
m = 25
Hence, from the above,
We can conclude that
The value of m is: 25

Question 6.
12 = y – 11
Answer:
The given equation is:
12 = y – 11
Now,
Add 11 on both sides
So,
12 + 11 = y – 11 + 11
y = 23
Hence, from the above,
We can conclude that
The value of y is: 23

Question 7.
22 = 13 + a
Answer:
The givene quation is:
22 = 13 + a
Now,
Subtract 13 on both sides
So,
22 – 13 = 13 + a – 13
a = 9
Hence, from the above,
We can conclude that
The value of a is: 9

Question 8.
t – 40 = 3
Answer:
The given equation is:
t – 40 = 3
Now,
Add 40 on both sides
So,
t – 40 + 40 = 3 + 40
t = 43
Hence, from the above,
We can conclude that
The value of t is: 43

Question 9.
d + 11 = 15
Answer:
The given equation is:
d + 11 = 15
Now,
Subtract 11 on both sides
So,
d + 11 – 11 = 15 – 11
d = 4
Hence, from the above,
We can conclude that
The value of d is: 4

Question 10.
32 = s – 19
Answer:
The given equation is:
32 = s – 19
Now,
Add 19 on both sides
So,
32 + 19 = s – 19 + 19
s = 51
Hence, from the above,
We can conclude that
The value of s is: 51

Practice & Problem Solving

Leveled Practice
In 11-16, solve each equation.

Question 11.
y – 12 = 89
y – 12 + _____ = 89 + 12
y = ______
Answer:
The given equation is:
y – 12 = 89
Now,
Add 12 on both sides
So,

Hence, from the above,
We can conclude that
The value of y is: 101

Question 12.
80 + r = 160
80 + r – ______ = 160 – ______
r = ______
Answer:
The given equation is:
80 + r = 160
Now,
Subtract 80 on both sides
So,

Hence, from the above,
We can conclude that
The value of r is: 80

Question 13.
60 = x – 16
60 + ______ = x – 16 + ______
______ = x
Answer:
The given equation is:
60 = x – 16
Now,
Add 16 on both sides
So,

Hence, from the above,
We can conclude that
The value of x is: 76

Question 14.
20 = y + 12
Answer:
The givene quation is:
20 = y + 12
Now,
Subtract 12 on both sides
So,
20 – 12 = y + 12 – 12
y = 8
Hence, from the above,
We can conclude that
The value of y is: 8

Question 15.
x + 2 = 19
Answer:
The given equation is:
x + 2 = 19
Now,
Subtract 2 on both sides
So,
x + 2 – 2 = 19 – 2
x = 17
Hence, from the above,
We can conclude that
The value of x is: 17

Question 16.
z – 313 = 176
Answer:
The given equation is:
z – 313 = 176
Now,
Add 313 on both sides
So,
z – 313 + 313 = 176 + 313
z = 489
Hence, from the above,
We can conclude that
The value of z is: 489

Question 17.
You have some baseball trading cards. You give 21 baseball cards to a friend and have 9 left for yourself. How many baseball cards were in your original deck? Write and solve an equation to find t, the number of baseball cards in your original deck.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 22
Answer:
It is given that
You have some baseball trading cards. You give 21 baseball cards to a friend and have 9 left for yourself
Now,
The representation of the given information in the form of a bar diagram is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 22
Now,
From the given bar diagram,
We can observe that
(The total number of baseball trading cards) – (The number of baseball cards you have given to your friend) = (The number of baseball cards you have left)
So,
t – 21 = 9
Now,
Add 21 on both sides
So,
t – 21 + 21 = 9 + 21
t = 30
Hence, from the above,
We can conclude that
The total number of baseball trading cards in your original deck is: 30 cards

Question 18.
Model with Math Joy added 26 new contacts to her phone list. She now has a total of 100 contacts. Let c represent how many contacts Joy had on her phone list before she updated it. Write an equation and solve for c.
Answer:
It is given that
Joy added 26 new contacts to her phone list. She now has a total of 100 contacts. Let c represent how many contacts Joy had on her phone list before she updated it
Now,
According to the given information,
The representation of the equation for the given information is:
c + 26 = 100
Now,
Subtract 26 on both sides
So,
c + 26 – 26 = 100 – 26
c = 84 contacts
Hence, from the above,
We can conclude that
The number of contacts Joy had on her phone list before she updated is: 84 contacts

Question 19.
Reasoning Jeremy bought a sandwich and a drink that cost him $7. His drink cost $1.75. Solve the equation 7 = s + 1.75 to find s, the cost of Jeremy’s sandwich.
Answer:
It is given that
Jeremy bought a sandwich and a drink that cost him $7. His drink cost $1.75
Now,
Let s be the cost of Jeremy’s sandwich
So,
According to the given information,
The total cost pf a sandwich and a drink that Jeremy bought = (The cost of Jeremy’s sandwich) + (The cost of Jeremy’s drink)
$7 = s + $1.75
Now,
subtract $1.75 on both sides
So,
$7 – $1.75 = s + $1.25 – $1.25
s = $5.25
Hence, from the baove,
We can conclude that
The cost of Jeremy’s sandwich is: $5.25

Question 20.
A triathlon is about 51 Kilometers. One participant completed two of the three legs of the race and traveled 42 Kilometers. Solve the equation 42 + d = 51 for the distance, d, of the third leg of the race.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 23
Answer:
It is given that
A triathlon is about 51 Kilometers. One participant completed two of the three legs of the race and traveled 42 Kilometers
Now,
The representation of the given information in the form of a bar diagram is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 23

Now,
The representation of the equation that represents the given information ad as given in the problem is:
42 + d = 51
Where,
d is the Distance of the third leg
Now,
Subtract 41 from both sides
So,
42 + d – 42 = 51 – 42
d = 9 Kilometers
Hence, from the above,
We can conclude that
The distance of the third leg of the race is: 9 Kilometers

Question 21.
What operation should be used to solve the equation 153 = 9 + 45? Solve the equation.
Answer:
The given equation is:
153 = 9 + 45
Now,
When we observe the equation,
There is “Addition” operation taking place in the given equation
Now,
We have to subtract the required number
Hence, from the above,
We can conclude that
The operation we should be used to solve the given equation 153 = 9 + 45 is: Subtraction

Question 22.
Higher Order Thinking In the equation 6 + 3y = 4y + 2 the variable y represents the same value. Is y = 2, 3, 4, or 5 the solution of this equation? Explain.
Answer:
It is given that
In the equation 6 + 3y = 4y + 2 the variable y represents the same value
Now,
The given equation is:
6 + 3y = 4y + 2
Now,
For y = 2:
6 + 3y = 4y + 2
6 + 3 (2) = 4 (2) + 2
6 + 6 = 8 + 2
12 ≠ 10
For y = 3:
6 + 3y = 4y + 2
6 + 3 (3) = 4 (3) + 2
6 + 9 = 12 + 2
15 ≠ 14
For y = 4;
6 + 3y = 4y + 2
6 + 3 (4) + 4 (4) + 2
6 + 12 = 16 + 2
18 = 18
For y = 5:
6 + 3y = 4y + 2
6 + 3 (5) = 4 (5) + 2
6 + 15 = 20 + 2
21 ≠ 22
Hence, from the above,
We can conclude that
y = 4 is the solution for the given equation

Question 23.
A traffic helicopter descends to hover 477 meters above the ground. Let h be the original height of the helicopter. What is a subtraction equation that represents the problem? What was the original height of the helicopter?
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 24
Answer:
It is given that
A traffic helicopter descends to hover 477 meters above the ground. Let h be the original height of the helicopter
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 24
Now,
From the given figure,
We can observe that
(The original height of helicopter) + 127 m = 477 m
h – 127 = 477
Now,
Add 127 on both sides
So,
h + 127 – 127 = 477 + 127
h = 604 meters
Hence, from the above,
We can conclude that
The subtraction equation that represents the given problem is:
h  – 127 = 477
The original height of the helicopter is: 604 meters

Question 24.
The drama club sold all the tickets for its annual production in three days. The club sold 143 tickets the first day and 295 tickets the second day. If the drama club sold 826 tickets, how many tickets were sold on the third day of sales? Solve the equation 438 + t = 826 for the number of tickets, t, sold on the third day of ticket sales.
Answer:
It is given that
The drama club sold all the tickets for its annual production in three days. The club sold 143 tickets the first day and 295 tickets the second day. If the drama club sold 826 tickets
So,
The total number of tickets sold by the drama club in two days = (The number of tickets sold on the first day) + (The number of tickets sold on the second day)
= 143 + 295
= 438 tickets
Now,
Let the number of tickets sold on third day be: t
So,
According to the given information,
The equation that represents the given information is:
438 + t = 826
Now,
Subtract 438 on both sides
So,
438 + t – 438 = 826 – 438
t = 388 tickets
Hence, from the above,
We can conclude that
The number of tickets sold on the third day of ticket sales is: 388 tickets

Question 25.
In a bag of mixed nuts, there are 35 almonds, 34 pecans, 32 walnuts, and p pistachios. The bag has a total of 134 nuts. Find the total number of almonds, pecans, and walnuts. Then write and solve an equation to find the number of pistachios in the bag.
Answer:
It is given that
In a bag of mixed nuts, there are 35 almonds, 34 pecans, 32 walnuts, and p pistachios. The bag has a total of 134 nuts
So,
The total number of almonds, pecans, and walnuts = 35 + 34 + 32
= 101
Now,
The total number of almonds, peacons, walnuts, and pistachios = (The total number of almond, pecans, and walnuts) + (The number of pistachios)
So,
134 = 101 + p
Now,
Subtract 101 on both sides
So,
134 – 101 = 101 + p – 101
p = 33
Hence, from the above,
We can conclude that
The number of pistachios in the bag is: 33 pistachios

Assessment Practice

Question 26.
Which equation has g = 6 as the solution?
A. g+ 2 = 10
B. 9- 1 = 10
C. 58 +9 = 60
D. 44 – g = 38
Answer:
The given equations are:
A. g+ 2 = 10
B. 9- 1 = 10
C. 58 +g = 60
D. 44 – g = 38
So,
A.
g + 2 = 10
g = 10 – 2
g = 8
B.
g – 1 = 10
g = 10 + 1
g = 11
C.
58 + g = 60
g = 60 – 58
g = 2
D.
44 – g = 38
g = 44- 38
g = 6
Hence, from the above,
We can conclude that
The equation that has g = 6 as the solution is:

Question 27.
Select all the equations that have the same solution as 36 = x + 32.
☐ 42 = 38 + x
☐ x + 15 = 19
☐ 18 = x – 2
☐ 36 = x – 32
☐ 52 – x = 46
Answer:
The given equation is:
36 = x + 32
So,
x = 36 – 32
x = 4
Now,
The given equations are:
A.
42 = 38 + x
x = 42 – 38
x = 4
B.
x + 15 = 19
x = 19 – 15
x = 4
C.
18 = x – 2
x = 18 + 2
x = 20
D.
36 = x – 32
x = 36 + 32
x = 68
E.
52 – x = 46
x = 52 – 46
x = 6
Hence, from the above,
We can conclude that
All the equations that have the same solution as 36 = x + 32 are:

Lesson 4.4 Write and Solve Multiplication and Division Equations

Solve & Discuss It!
A school group is planning a trip to New York City. There are 29 people going on the trip. They agreed to share the total cost of the trip equally. Let s equal each person’s share of the cost. What is each person’s share of the cost?

I can… write and solve a multiplication or division equation.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 25
Answer:
It is given that
A school group is planning a trip to New York City. There are 29 people going on the trip. They agreed to share the total cost of the trip equally. Let s equal each person’s share of the cost
Now,
The given table is:

Now,
From the given table,
We can observe that
The total cost is: $19,111
So,
According to the given information,
(The total number of people going to a trip) × (The share of the cost of each person) = $19,111
29 × s = $19,111
s = \(\frac{$19,111}{29}\)
s = $659
Hence, from the above,
We can conclude that
Each person’s share of the cost is: $659

Generalize
How can you use what you know about dividing lesser numbers to write equations and solve problems involving greater numbers?
Answer:
Let a smaller faction be: \(\frac{a}{b}\)
Where,
a = 1, 2, ……… n
b = 1, 2, ……… n
Now,
When we divide lesser numbers say the lesser numbers only have 2 digits, then the quotient we will also get will be a small number
Now,
When we divide larger numbers say the larger numbers have 4 digits, then the quotient we will also get will be a large number with 3 (or) 4 digits

Focus on math practices
Construct Arguments Can you use the same strategy that you used above to find each person’s share of the hotel bill? Explain.
Answer:
Yes,
We can use the same strategy that you used above to find each person’s share of the hotel bill

Essential Question
How can you write and solve a multiplication or division equation?
Answer:
The steps to solve a multiplication or division problem is:
a. Always perform the same operation to both sides of the equation.
b. When you multiply or divide, you have to multiply and divide by the entire side of the equation.
c. Try to perform addition and subtraction first to get some multiple of x by itself on one side.

Try It!

Theresia picked the same number of tomatoes each day. In 4 days she picked 52 tomatoes. How many tomatoes did Theresia pick each day? Let n represent the number of tomatoes Theresia picked each day.
4n = 52
4n ÷ 4 = 52 ______
n = _______
Theresia picked _______ tomatoes each day.
Answer:
It is given that
Theresia picked the same number of tomatoes each day. In 4 days she picked 52 tomatoes
Now,
Let n represent the number of tomatoes Theresia picked each day.
So,
4 × (The number of tomatoes Theresia picked each day) = (The number of tomatoes Theresia picked in 4 days)
4 × n = 52
Now,

Hence, from the above,
We can conclude that
Theresia picked 13 tomatoes each day

Convince Me! Which property or equality can you use to solve Theresia’s equation? Explain.
Answer:
From the above problem,
The equation is:
4n = 52
Now,
To find the value of n (or) the number of tomatoes Theresia picked each day,
We have to use “Division Property of Equality”
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount to the equation to keep the equation balanced
Hence, from the above,
We can conclude that
We used the “Division Property of equality” to solve Theresia’s equation

Try It!

Meghann is reading a 630-page book. She reads 18 pages each day. Write and solve a division equation to find the number of days, d, it will take Meghann to finish her book.
Answer:
It is given that
Meghann is reading a 630-page book. She reads 18 pages each day
Now,
Let d be the number of days it will take Meghann to finish her book
Now,
(The number of pages Meghann reads each day) × (The number of days it will take Meghann to finish her book) = (The total number of pages in a book)
18 × d = 630
d = \(\frac{630}{18}\)
d = 35 days
Hence, from the above,
We can conclude that
It will take 35 days for Meghann to finish her 630-page book

KEY CONCEPT
You can multiply or divide both sides of an equation by the same number and it will remain balanced.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 26

Do You Understand?
Question 1.
Essential Question How can you write and solve a multiplication or division equation?
Answer:
The steps to solve a multiplication or division problem is:
a. Always perform the same operation to both sides of the equation.
b. When you multiply or divide, you have to multiply and divide by the entire side of the equation.
c. Try to perform addition and subtraction first to get some multiple of x by itself on one side.

Question 2.
Which property of equality would you use to solve the equation 8n = 16?
Answer:
The given equation is:
8n = 16
Now,
Divide by 8 to find the value of n
So,
We have to use “Division Property of Equality”
Now,
We know that,
According to the “Division Property of Equality”,
Divide the same amount at each side to keep the equation balanced.
So,
\(\frac{8n}{8}\) = \(\frac{16}{8}\)
n = 2
Hence, from the above,
We can conclude that
You would use “Division Property of Equality” to solve the given equation 8n = 16

Question 3.
Which property of equality would you use to solve the equation a ÷ 9 = 2?
Answer:
The given equation is:
a ÷ 9 = 2
Now,
Multiply with 9 to find the value of ‘a’
So,
We have to use “Multiplication Property of Equality”
Now,
We know that,
According to the “Multiplication Property of Equality”,
Multiply the same amount at each side to keep the equation balanced.
So,
(a ÷ 9) × 9 = 2 × 9
a = 18
Hence, from the above,
We can conclude that
You would use “Multiplication Property of Equality” to solve the given equation a ÷ 9 = 2

Question 4.
There are 30 students in the drama club. They are carpooling in 5 vans to perform a play. They want each van to carry an equal number of students. Let s be the number of students in each van. Write and solve a multiplication equation to find the number of students in each van.
Answer:
It is given that
There are 30 students in the drama club. They are carpooling in 5 vans to perform a play. They want each van to carry an equal number of students.
Now,
Let s be the number of students in each van
So,
(The number of vans carpooling to perform a play) × (The number of students in each van) = (The total number of students in the drama club)
5 × s = 30
5s = 80
Now,
Divide by 5 on both sides
So,
\(\frac{5s}{5}\) = \(\frac{80}{5}\)
s = 16 students
Hence, from the above,
We can conclude that
The number of students in each van is: 16 students

Do You Know How?
In 5-8, explain how to solve each equation.
Question 5.
18m = 36
Answer:
The given equation is:
18m = 36
Now,
Divide the equation by 18 on both sides
So,
\(\frac{18m}{18}\) = \(\frac{36}{18}\)
m = 2
Hence, from the above,
We can conclude that
The value of m in the given equation is: 2

Question 6.
t ÷ 3 = 10
Answer:
The given equation is:
t ÷ 3 = 10
Now,
Multiply the equation with 3 on both sides
So,
(t ÷ 3) × 3 = 10 × 3
t = 30
Hence, from the above,
We can conclude that
The value of t in the given equation is: 30

Question 7.
12 = 2y
Answer:
The given equation is:
12 = 2y
Now,
Divide the equation by 2 on both sides
So,
\(\frac{12}{2}\) = \(\frac{2y}{2}\)
6 = y
y = 6
Hence, from the above,
We can conclude that
The value of y in the given equation is: 6

Question 8.
22 = a ÷ 5
Answer:
The given equation is:
22 = a ÷ 5
Now,
Multiply the equation with 5 on both sides
So,
22 × 5 = (a ÷ 5) × 5
a = 110
Hence, from the above,
We can conclude that
The value of a in the given equation is: 110

In 9-12, solve each equation.
Question 9.
23d = 2,392
Answer:
The given equation is:
23d = 2,392
Now,
Divide the given equation by 23 on both sides
So,
\(\frac{23d}{23}\) = \(\frac{2,392}{23}\)
d = 104
Hence, from the above,
We can conclude that
The value of d in the given equation is: 104

Question 10.
74f = 6,179
Answer:
The given equation is:
74f = 6,179
Now,
Divide the given equation by 74 on both sides
So,
\(\frac{74f}{74}\) = \(\frac{6,179}{74}\)
f = 83.5
Hence, from the above,
We can conclude that
The value of f in the given equation is: 83.5

Question 11.
y ÷ 11 = 987
Answer:
The given equation is:
y ÷ 11 = 987
Now,
Multiply the given equation with 11 on both sides
So,
(y ÷ 11) × 11 = 987 × 11
y = 10,857
Hence, from the above,
We can conclude that
The value of y in the given equation is: 10,857

Question 12.
r ÷ 187 = 9
Answer:
The given equation is:
r ÷ 187 = 9
Now,
Multiply the given equation with 187 on both sides
So,
(r ÷ 187) × 187 = 9 × 187
y = 1,683
Hence, from the above,
We can conclude that
The value of r in the given equation is: 1,683

Practice & Problem Solving

In 13-16, explain how to get the variable alone in each equation.
Question 13.
8y = 56
Answer:
The given equation is:
8y = 56
Now,
Divide the given equation with 8 on both sides
so,
\(\frac{8y}{8}\) = \(\frac{56}{8}\)
y = 7
Hence, from the above,
We can conclude that
The value of y for the given equation is: 7

Question 14.
t ÷ 15 = 3
Answer:
The given equation is:
t ÷ 15 = 3
Now,
Multiply the given equation with 15 on both sides
So,
(t ÷ 15) × 15 = 3 × 15
t = 45
Hence, from the above,
We can conclude that
The value of t for the given equation is: 45

Question 15.
u ÷ 8 = 12
Answer:
The given equation is:
u ÷ 8 = 12
Now,
Multiply the given equation with 8 on both sides
So,
(u ÷ 8) × 8 = 12 × 8
u = 96
Hence, from the above,
We can conclude that
The value of u for the given equation is: 96

Question 16.
31y = 310
Answer:
The given equation is:
31y = 310
Now,
Divide the given equation with 31 on both sides
so,
\(\frac{31y}{31}\) = \(\frac{310}{31}\)
y = 10
Hence, from the above,
We can conclude that
The value of y for the given equation is: 10

In 17-20, solve each equation.
Question 17.
d ÷ 2 = 108
Answer:
The given equation is:
d ÷ 2 = 108
Now,
Multiply the given equation with 2 on both sides
So,
(d ÷ 2) × 2 = 108 × 2
d = 216
Hence, from the above,
We can conclude that
The value of d for the given equation is: 216

Question 18.
7,200 = 800s
Answer:
The given equation is:
7,200 = 800s
Now,
Divide the given equation with 800 on both sides
so,
\(\frac{7,200}{800}\) = \(\frac{800s}{800}\)
9 = s
s = 9
Hence, from the above,
We can conclude that
The value of s for the given equation is: 9

Question 19.
x ÷ 3 = 294
Answer:
The given equation is:
x ÷ 3 = 294
Now,
Multiply the given equation with 3 on both sides
So,
(x ÷ 3) × 3 = 294 × 3
d = 882
Hence, from the above,
We can conclude that
The value of x for the given equation is: 882

Question 20.
99 = 3x
Answer:
The given equation is:
99 = 3x
Now,
Divide the given equation with 3 on both sides
so,
\(\frac{99}{3}\) = \(\frac{3x}{3}\)
33 = x
x = 33
Hence, from the above,
We can conclude that
The value of x for the given equation is: 33

In 21 and 22, write a division equation and a multiplication equation to represent each problem.
Question 21.
Lolo typed 1,125 words in 15 minutes. Let w represent the number of words typed each minute. If Lolo typed the same number of words each minute, how many words did she type in 1 minute?
Answer:
It is given that
Lolo typed 1,125 words in 15 minutes. Let w represent the number of words typed each minute. and Lolo typed the same number of words each minute
So,
(The number of minutes needed to type 1,125 words) × (The number of words Lolo typed each minute) = 1,125
15 ×w = 1,125
15w = 1,125
Now,
Divide by 15 on both sides
So,
\(\frac{15w}{15}\) = \(\frac{1,125}{15}\)
w = \(\frac{1,125}{15}\)
Hence, from the above,
We can conclude that
The representation of the multiplication equation and the division equation to represent the given situation is:
a. Multiplication equation: 15w = 1,125
b. Division equation: w = \(\frac{1,125}{15}\)

Question 22.
In 12 weeks Felipe earns $4,500 doing yard work. He earns the same amount each week. Let m stand for the amount earned each week. How much does Felipe make in 1 week?
Answer:
It is given that
In 12 weeks Felipe earns $4,500 doing yard work. He earns the same amount each week. Let m stand for the amount earned each week
So,
(The number of weeks needed to earn $4,500) × (The amount earned by Felipe each week) = $4,500
12 × m = $4,500
12m = $4,500
Now,
Divide by 12 on both sides
So,
\(\frac{12m}{12}\) = \(\frac{$4,500}{12}\)
m = \(\frac{$4,500}{12}\)
Hence, from the above,
We can conclude that
The representation of the multiplication equation and the division equation to represent the given situation is:
a. Multiplication equation: 12m = $4,500
b. Division equation: m = \(\frac{$4,500}{12}\)

Question 23.
Model with Math Abel has 3,330 toothpicks. He wants to use them all to make a floor mat with 18 equal rows. Use the bar diagram to write a division equation. Then solve the equation to find how many toothpicks Abel should use in each row.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 27
Answer:
It is given that
Abel has 3,330 toothpicks. He wants to use them all to make a floor mat with 18 equal rows
Now,
The representation of the gven situation in the form of a bar diagram is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 27
Now,
Let the number of toothpicks Abel shoud use in each row be: t
Now,
From the given bar diagram,
We can observe that
(The total number of toothpicks) ÷ (The number of tooth picks Abel should use in each row) = (The total number of rows)
\(\frac{3,330}{t}\) = 18
t = \(\frac{3,330}{18}\)
t = 185 toothpicks
Hence, from the above,
We can conclude that
The number of toothpicks Abel should use in each row is: 185 toothpicks

Question 24.
Model with Math Emily took an airplane trip. Her plane flew an equal number of miles each hour. Let m stand for the miles flown each hour. Write an equation to represent one way you can find how many miles Emily’s plane flew each hour.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 28
Answer:
It is given that
Emily took an airplane trip. Her plane flew an equal number of miles each hour. Let m stand for the miles flown each hour.
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 28
Now,
From the figure,
We can observe that
The total distance airplane travels is: 2,184 miles in 12 hours
So,
(The time took for airplane to reach Emily’s destination) × (The number of miles Emily’s plane flew each hour) = (The total distance an airplane travels in 12 hours)
12 × m = 2,184
12m = 2,184
Now,
Divide by 12 on both sides
So,
m = \(\frac{2,184}{12}\)
m = 182 miles
Hence, from the above,
We can conclude that
The number of miles Emily’s plane flew each hour is: 182 miles

In 25 and 26, use the triangle.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 29
Question 25.
The area of the isosceles triangle is 44 square centimeters. Use the equation \(\frac{1}{2}\)(8h) = 44 to find the height of the triangle.
Answer:
It is given that
The area of the isosceles triangle is 44 square centimeters
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 29
Now,
We know that,
The area of an Isosceles triangle (A) = \(\frac{1}{2}\) × Base × Height
So,
Accoring to the given information,
\(\frac{1}{2}\) × 8 × h = 44
\(\frac{8h}{2}\) = 44
8h = 44 × 2
8h = 88
h = \(\frac{88}{8}\)
h = 11 cm
Hence, from the above,
We can conclude that
The height of the given triangle is: 11 cm

Question 26.
If the perimeter of the triangle is 32 centimeters, what is the length of each of the two sides? Write and solve an equation.
Answer:
It is given that
The perimeter of the triangle is 32 centimeters
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 29
Now,
We know that,
In an Isosceles triangle, 2 sides lengths are the same
The “Perimeter” of any figure is the sum of all the side lengths in a given figure
Now,
Let x be the side length of the given triangle
So,
x + x + 8 = 32
2x + 8 = 32
2x = 32 – 8
2x = 24
x = \(\frac{24}{2}\)
x = 12 cm
Hence, from the above,
We can conclude that
The length of one side in the given triangle is: 12 cm
The length of the other side in the given triangle is: 12 cm

Question 27.
Kelsey and her 4 sisters spent an equal amount of time cleaning their home. Their parents added their times. They found that each of the 5 girls spent 3 hours cleaning. Let c be the total number of hours the girls spent cleaning. Write and solve a division equation to find the total number of hours the girls spent cleaning.
Answer:
It is given that
Kelsey and her 4 sisters spent an equal amount of time cleaning their home. Their parents added their times. They found that each of the 5 girls spent 3 hours cleaning. Let c be the total number of hours the girls spent cleaning.
So,
According to the given information,
(The total number of hours the girls spent cleaning) ÷ (The total number of girls) = (The time took each girl spent cleaning)
c ÷ 5 = 3
c = 3 × 5
c = 15 hours
Hence, from the above,
We can conclude that
The total number of hours the five girls spent cleaning is: 15 hours

Question 28.
Higher Order Thinking Veronica traveled 562 miles to Venice, Florida. She drove 85 miles every day. On the last day of her trip she only drove 52 miles. Write and solve an equation to find the number of days Veronica traveled. Explain each step of your problem-solving strategy.
Answer:
It is given that
Veronica traveled 562 miles to Venice, Florida. She drove 85 miles every day. On the last day of her trip she only drove 52 miles
Now,

Hence, from the above,
We can conclude that
The number of days Veronica traveled is: 7 days

Question 29.
Generalize A movie theater sells 11,550 tickets for 50 sold-out showings of the same movie. Write a division equation that you can use to find the number of people who bought tickets for each showing. Use what you know about dividing with larger numbers to solve the equation.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 30
Answer:
It is given that
A movie theater sells 11,550 tickets for 50 sold-out showings of the same movie.
Now,
Let the number of people who bought tickets for each showing be: p
So,
According to the given information,
(The total number of tickets sold by a movie theater) ÷ (The number of people who bought tickets for each showing) = (The number of showings)
11,550 ÷ p = 50
p = \(\frac{11,550}{50}\)
p = 231 people
Hence, from the above,
We can conclude that
The number of people who bought tickets for each showing is: 231 people

Assessment Practice

Question 30.
In October, Calvin’s school used 4,920 pounds of sand to protect the building against flooding during different tropical storms. One bag contains 40 pounds of sand.
Which of the following equations can be used to find how many bags of sand, b, Calvin’s school used in October?
A. 4,920b = 40
B. b ÷ 40 = 4,920
C. 40b = 4,920
D. b ÷ 4,920 = 40
Answer:
It is given that
In October, Calvin’s school used 4,920 pounds of sand to protect the building against flooding during different tropical storms. One bag contains 40 pounds of sand.
Now,
Let b be the number of bags of sand
So,
According to the given information,
(The number of bags) × (The amount of sand in each bag) = (The total amount of sand)
40b = 4,920
\(\frac{4,920}{b}\) = 40
Hence, from the above,
We can conclude that
The equation that can be used to find how many bags of sand, b, Calvin’s school used in October is:

Lesson 4.5 Write and Solve Equations with Rational Numbers

Explore It!
The cost of T-shirts for four different soccer teams are shown below.
I can… write and solve equations that involve rational numbers.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 31

A. Lorna is on Team A. Ben is on another team. They paid a total of $21.25 for both team T-shirts. Write an equation represent the cost of Ben’s shirt
Answer:
It is given that
The cost of T-shirts for four different soccer teams are shown below.
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 31
Now,
Let the cost of Ben’s shirt be: x
So,
According to the given information,
(The total cost of both T-shirts) = (The cost of Lorna’s shirt which is in Team A) + (The cost of Ben’s shirt)
$21.25 = $12.50 + x
So,
x = $21.25 – $12.50
x = $8.75
Hence, from the above,
We can conclude that
The cost of Ben’s shirt is: $8.75

B. Dario also plays soccer and he says that, based on the price of Ben’s T-shirt, Ben is on Team B. is Dario correct explain.
Answer:
It is given that
Dario said that based on the price of Ben’s T-shirt, Ben is on Team B
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 31
Now,
We know that,
From Part A,
The cost of Ben’s T-shirt is: $8.75
Now,
From the given figure,
We can observe that
The T-shirt costs $8.75 that belongs to Team C
Hence, from the above,
We can conclude that
Dario is not correct

Focus on math practices
Generalize How is solving for unknowns involving money like solving for unknowns involving whole numbers?
We know that,
The representation of money is as the same as the rational numbers
So,
Whatever operations we are performing on the whole numbers, we can perform the same operations on the unknowns involving money

Essential Question
How can you write and solve equations involving rational numbers?
Answer:
Convert the rational number to decimals, then solve it as a decimal instead, (with the optional choice of re-converting it back to rational number).

Try It!

Suppose you cut the shorter piece of fruit snack from the example above into two pieces. The longer of the two pieces is 1\(\frac{3}{8}\) feet long. Complete the bar diagram to represent the equation. Then find the length of the shorter piece.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 32
Answer:
It is given that
you cut the shorter piece of fruit snack from the example above into two pieces. The longer of the two pieces is 1\(\frac{3}{8}\) feet long.
Now,
From Example 1,
The length of the shorter piece is: 2\(\frac{1}{4}\) feet
Now,
The length of the longer piece in the given shorter piece is: 1\(\frac{3}{8}\) feet
Now,
Let the length of the shorter piece in the given shorter piece be: x
Now,
The representation of the given information in the form of a bar diagram is:

Now,
From the given diagram,
We can observe that

Hence, from the above,
We can conclude that
The shorter piece of the shorter piece is: \(\frac{7}{8}\) feet

Convince Me! How does the equation change if you know the length of the shorter piece is \(\frac{7}{8}\) foot and you want to know the length of the longer of the two pieces?
Answer:
If we know
The length of the shorter piece is: \(\frac{7}{8}\) foot
So,
The equation in the above problem will change into
\(\frac{7}{8}\) + x = 2\(\frac{1}{4}\)
Where,
x is the length of the other piece
Now,
x = 2\(\frac{1}{4}\) – \(\frac{7}{8}\)
x = 1\(\frac{3}{4}\) feet
So,
\(\frac{7}{8}\) < 1\(\frac{3}{4}\)
Hence, from the above,
We can conclude that
The length of the longer piece of the shorter piece is: 1\(\frac{3}{4}\) feet

Try It!

Solve \(\frac{5}{9}\)y = 25 for y.
Answer:
The given equation is:
\(\frac{5}{9}\)y = 25
Now,
Multiply with \(\frac{9}{5}\) on both sides
So,
\(\frac{5}{9}\) × \(\frac{9}{5}\)y = 25 × \(\frac{9}{5}\)
y = \(\frac{25 × 9}{5}\)
y = 45
Hence, from the above,
We can conclude that
The value of y for the given equation is: 45

Try It!

Molly also buys a bag of 8 apples for $3.60. Write and solve an equation to find how much Molly paid for each apple.
Answer:
It is given that
Molly also buys a bag of 8 apples for $3.60
So,
The cost of each apple = (The total cost of apples) ÷ (The total number of apples)
= \(\frac{$3.60}{8}\)
= $0.45
Hence, from the above,
We can conclude that
The cost of each apple is: $0.45

Try It!

Carmen spent $12.50 for a new notebook and a compass. The notebook cost $6.35. Write and solve an equation to find c, the cost of the compass.
Answer:
It is given that
Carmen spent $12.50 for a new notebook and a compass. The notebook cost $6.35
Now,
Let the cost of compass be c
So,
The total amount of money Carmen spent on a new notebook and a compass = (The cost of a compass) + (The cost of a new notebook)
$12.50 = c + $6.35
So,
c = $12.50 – $6.35
c = $6.15
Hence, from the above,
We can conclude that
The cost of a compass is: $6.15

KEY CONCEPT
You can solve equations using properties of equality and inverse relationships.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 33

Do You Understand?
Question 1.
Essential Question How can you write and solve equations involving rational numbers?
Answer:
Convert the rational number to decimals, then solve it as a decimal instead, (with the optional choice of re-converting it back to rational number).

Question 2.
Construct Arguments Why are inverse relationships important for solving equations?
Answer:
Mathematically, Inverse operations are opposite operations. Addition is the opposite of subtraction; division is the opposite of multiplication, and so on. Inverse operations are used to solve simple algebraic equations to more difficult equations that involve exponents, logarithms, and trigonometry

Question 3.
Critique Reasoning Johnny says that he solved the equation x – 3.5 = 7.2 by adding 3.5 to the left side of the equation. Explain whether Johnny is correct.
Answer:
It is given that
Johnny says that he solved the equation x – 3.5 = 7.2 by adding 3.5 to the left side of the equation.
Now,
The given equation is:
x – 3.5 = 7.2
Now,
We know that,
According to the “Addition Property of Equality”,
Add the same amount on both sides to make the equation balanced
So,
For the given equation,
Add 3.5 on both sides
So,
x – 3.5 + 3.5 = 7.2 – 3.5
Hence, from the above,
We can conclude that
Johnny is not correct

Question 4.
Generalize When solving an equation involving a mixed number, such as y + \(\frac{3}{4}\) = 4\(\frac{1}{2}\), what do you need to do to the mixed number?
Answer:
The given equation is:
y + \(\frac{3}{4}\) = 4\(\frac{1}{2}\)
Now,
To solve the given equation,
We have to convert the mixed number into a proper fraction
Hence, from the above,
We can conclude that
We have to convert the given mixed number into a proper fraction

Question 5.
Construct Arguments How is solving an equation with fractions like solving an equation with whole numbers? How is it different?
Answer:
Solving an equation with a fraction isn’t much different than solving an equation full of whole numbers. You group the variable terms on one side, the constants on the other, and then simplify.

Do You Know How?
In 6-14, solve each equation.
Question 6.
t – \(\frac{2}{3}\) = 25\(\frac{3}{4}\)
Answer:
The given equation is:
t – \(\frac{2}{3}\) = 25\(\frac{3}{4}\)
Now,

Hence, from the above,
We can conclude that
The value of t for the given expression is: \(\frac{317}{12}\)

Question 7.
\(\frac{f}{2}\) = \(\frac{5}{8}\)
Answer:
The given equation is:
\(\frac{f}{2}\) = \(\frac{5}{8}\)
Now,

Hence, from the above,
We can conclude that
The value of f for the given equation is: \(\frac{5}{4}\)

Question 8.
13.27 = t – 24.45
Answer:
The given equation is:
13.27 = t – 24.45
Now,

Hence, from the above,
We can conclude that
The value of t for the given equation is: \(\frac{943}{25}\)

Question 9.
r ÷ 5.5 = 18.2
Answer:
The given equation is:
r ÷ 5.5 = 18.2
Now,

Hence, from the above,
We can conclude that
The value of r for the given equation is: \(\frac{1,001}{10}\)

Question 10.
\(\frac{7}{10}=x – [latex]\frac{3}{5}\)
Answer:
The given equation is:
\(\frac{7}{10}=x-[latex]\frac{3}{5}\)
Now,

Hence, from the above,
We can conclude that
The value of x for the given equation is: \(\frac{13}{10}\)

Question 11.
1.8x = 40.14
Answer:
The given equation is:
1.8x = 40.14
Now,

Hence, from the above,
We can conclude that
The value of x for the given equation is: \(\frac{223}{10}\)

Question 12.
17.3 + v = 22.32
Answer:
The given equation is:
17.3 + v = 22.32
Now,

Hence, from the above,
We can conclude that
The value of v for the given equation is: \(\frac{251}{50}\)

Question 13.
9 = \(\frac{3}{8}\)y
Answer:
The given equation is:
9 = \(\frac{3}{8}\)y
Now,

Hence, from the above,
We can conclude that
The value of y for the given equation is: 24

Question 14.
1\(\frac{3}{4}+z=2[latex]\frac{2}{3}\)
Answer:
The given equation is:
1\(\frac{3}{4}+z=2[latex]\frac{2}{3}\)
Now,
Convert the given mixed numbers into the fraction form
So,
1\(\frac{3}{4}\) = \(\frac{7}{4}\)
2\(\frac{2}{3}\) = \(\frac{8}{3}\)
Now,

Hence, from the above,
We can conclude that
The value of y for the given equation is: \(\frac{11}{12}\)

Practice & Problem Solving

Leveled Practice
In 15-22, solve each equation.

Question 15.
w – 3.2 = 5.6
w – 3.2 + _____ = 5.6 + _____
w = _____
Answer:
The given equation is:
w – 3.2 = 5.6
Now,

Hence, from the above,
We can conclude that
The value of w for the given equation is: 8.8

Question 16.
9.6 = 1.6y
9.6 ÷ _____ = 1.6y ÷ ______
_______ = y
Answer:
The given equation is:
9.6 = 1.6y
Now,

Hence, from the above,
We can conclude that
The value of y for the given equation is: 6

Question 17.
48.55 + k = 61.77
48.55 + k – _____ = 61.77 – _____
k = _____
Answer:
The given equation is:
48.55 + k = 61.77
Now,

Hence, from the above,
We can conclude that
The value of k for the given equation is: 13.22

Question 18.
m ÷ 3.54 = 1.5
m ÷ 3.54 × _____ = 1.5 × _____
m = _____
Answer:
The given equation is:
m ÷ 3.54 = 1.5
Now,

Hence, from the above,
We can conclude that
The value of m for the given equation is: 5.31

Question 19.
\(7 \frac{1}{9}=2 \frac{4}{5}+m\)
Answer:
The given equation is:
\(7 \frac{1}{9}=2 \frac{4}{5}+m\)
Now,
Convert the given mixed numbers into fractions
So,
7\(\frac{1}{9}\) = \(\frac{64}{9}\)
2\(\frac{4}{5}\) = \(\frac{14}{5}\)
Now,

Hence, from the above,
We can conclude that
The value of m for the given equation is: \(\frac{194}{45}\)

Question 20.
\(a+3 \frac{1}{4}=5 \frac{2}{9}\)
Answer:
The given equation is:
\(a+3 \frac{1}{4}=5 \frac{2}{9}\)
Now,
Convert the given mixed numbers into the fractions
So,
3\(\frac{1}{4}\) = \(\frac{13}{4}\)
5\(\frac{2}{9}\) = \(\frac{47}{9}\)
Now,

Hence, from the above,
We can conclude that
The value of a for the given equation is: \(\frac{71}{36}\)

Question 21.
\(\frac{1}{8}\) • y=4
Answer:
The given equation is:
\(\frac{1}{8}\) • y=4
Now,

Hence, from the above,
We can conclude that
The value of y for the given equation is: 32

Question 22.
\(k-6 \frac{3}{8}=4 \frac{6}{7}\)
Answer:
The given equation is:
\(k-6 \frac{3}{8}=4 \frac{6}{7}\)
Now,
Convert the given mixed numbers into the fractions
So,
6\(\frac{3}{8}\) = \(\frac{51}{8}\)
4\(\frac{6}{7}\) = \(\frac{34}{7}\)
Now,

Hence, from the above,
We can conclude that
The value of k for the given equation is: \(\frac{629}{56}\)

Question 23.
Mr. Marlon buys these tickets for his family to visit the water park. The total cost is $210. Write and solve an equation to find the cost of each ticket.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 34
Answer:
It is given that
Mr. Marlon buys these tickets for his family to visit the water park. The total cost is $210
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 34
Now,
From the given figure,
We can observe that
The number of tickets Mr. Marlon bought is: 4
Now,
The cost of each ticket = (The total cost of tickets) ÷ (The total number of people)
= \(\frac{210}{4}\)
= $ 52.50
Hence, from the above,
We can conclude that
The cost of each ticket is: $52.50

Question 24.
Higher Order Thinking Without solving, tell which equation below has a greater solution. Explain.
\(\frac{5}{8}\)m = 2\(\frac{3}{4}\)
\(\frac{5}{9}\)m = 2\(\frac{3}{4}\)
Answer:
The given equations are:
\(\frac{5}{8}\)m = 2\(\frac{3}{4}\)
\(\frac{5}{9}\)m = 2\(\frac{3}{4}\)
Now,
We know that,
In the given fraction,
The numerators are the same and to find whether which fraction is greater,
We can compare by using the denominators
If the denominator is a small number when the numerators are the same then the other denominator, then the fraction that contains the smallest value of denominator is the greater fraction
Now,
From the given fractions,
When we compare the denominators,
8 < 9
Hence, from the above,
We can conclude that
The equation which is greater is:
\(\frac{5}{8}\)m = 2\(\frac{3}{4}\)

Question 25.
Make Sense and Persevere A high school track team’s long jump record is 21 feet 2\(\frac{1}{4}\) inches. This year, Tim’s best long jump is 20 feet 9\(\frac{1}{2}\) inches. If long jumps are measured to the nearest quarter inch, how much farther must Tim jump to break the record?
Answer:
It is given that
A high school track team’s long jump record is 21 feet 2\(\frac{1}{4}\) inches. This year, Tim’s best long jump is 20 feet 9\(\frac{1}{2}\) inches
Now,
We know that,
1 foot = 12 inches
So,
21 feet 2\(\frac{1}{4}\) inches = (21 × 12) + 2\(\frac{1}{4}\) inches
= 252 + 2\(\frac{1}{4}\) inches
= 252 + 2.25 inches
= 254.25 inches
So,
20 feet 9\(\frac{1}{2}\) inches = (20 × 12) + 9\(\frac{1}{2}\) inches
= 240 + 9\(\frac{1}{2}\) inches
= 240 + 9.5 inches
= 249.5 inches
So,
The distance Tim has to cross to break the record = 254.25 – 249.5
= 4.75 inches
Hence, from the above,
We can conclude that
The distance Tim has to cross to break the record is: 4.75 inches

Question 26.
Make Sense and Persevere About how many gallons of fuel does it take to move the space shuttle 3 miles from its hangar to the Vehicle Assembly Building?
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 35
Answer:
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 35
Now,
From the given figure,
We can observe that
1 mile = 5,280 ft
It will take 1 gallon of fuel to move space shuttle 42 feet
Now,
The distance of 3 miles traveled by the space shuttle in fuel = (The number of feet required for 1 mile) × 3
= 3 × 5,280
= 15,840 feet
Now,
The number of gallons of fuel required to move the space shuttle 3 miles = (The total distance of 3 miles in feet) ÷ (The distance covered by 1 gallon of fuel)
= \(\frac{15,840}{42}\)
= 377 gallons
Hence, from the above,
We can conclude that
It will take 377 gallons of fuel to move the space shuttle 3 miles from its hangar to the Vehicle Assembly Building

Question 27.
Is the solution of b × \(\frac{5}{6}\) = 25 greater than or less than 25? How can you tell before computing?
Answer:
The given equation is:
b × \(\frac{5}{6}\) = 25
Now,
We know that,
When a multiplication is converted into a division, then the fraction after × or ÷ symbols will have to be reciprocal and vice-versa
So,
The reciprocal of \(\frac{5}{6}\) is: \(\frac{6}{5}\)
So,
b = 25 × \(\frac{6}{5}\)
Now,
We know that,
The value of \(\frac{6}{5}\) is greater than 1
So,
The solution for the given equation will also be greater than 25
Hence, from the above,
We can conclude that
The solution of b × \(\frac{5}{6}\) = 25 is greater than 25

Question 28.
What is the width of a rectangle with a length of \(\frac{3}{7}\) ft and an area of 2 ft2? Write an equation to show your work.
Answer:
It is given that
The area of a rectangle is: 2 ft²
The length of a rectangle is: \(\frac{3}{7}\) ft
Now,
Let the width of the rectangle be x
Now,
We know that,
The area of a rectangle = Length × Width
So,
2 = \(\frac{3}{7}\) × x
Now,

Hence, from the above,
We can conclude that
The width of the given rectangle is: \(\frac{14}{3}\) ft

Question 29.
Model with Math Helen is filling the pool shown for her little brother. She can carry 1\(\frac{7}{8}\) gallons of water each trip. Write and solve an equation to find how many trips Helen needs to make.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 36
Answer:
It is given that
Helen is filling the pool shown for her little brother. She can carry 1\(\frac{7}{8}\) gallons of water each trip
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 36
So,
The number of trips Helen needs to make = (The total amount of water held in the pool) ÷ (The amount of water Helen can carry each trip)
= 10\(\frac{1}{2}\) ÷ 1\(\frac{7}{8}\)
Now,

Hence, from the above,
We can conclude that
The number of trips Helen needs to make is about 6 trips

Question 30.
After the pool was full, Helen’s little brother and his friend splashed g gallons of water out of the pool. There are 7\(\frac{7}{8}\) gallons still left in the pool. Write and solve an equation to find how much water was splashed out of the pool.
Answer:
It is given that
After the pool was full, Helen’s little brother and his friend splashed g gallons of water out of the pool. There are 7\(\frac{7}{8}\) gallons still left in the pool
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 36
Now,
Let the amount of water splashed from the pool be: g gallons
So,
(The total amount of water present in the pool) – (The amount of water splashed out of the pool) = (The amount of water still left in the pool)
10\(\frac{1}{2}\) – g = 7\(\frac{7}{8}\)
g = 10\(\frac{1}{2}\) – 7\(\frac{7}{8}\)
Now,

Hence, from the above,
We can conclude that
The amount of water that splashed out from the pool is: 2\(\frac{5}{8}\) gallons

Question 31.
Grace solved the equation 2\(\frac{1}{2}\)y = \(\frac{5}{8}\). Her steps for the solution are shown in the table but are all mixed up. Write her steps in the correct order on the right side of the table.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 37
Answer:
It is given that
Grace solved the equation 2\(\frac{1}{2}\)y = \(\frac{5}{8}\). Her steps for the solution are shown in the table but are all mixed up.
Now,
The given equation is:
2\(\frac{1}{2}\)y = \(\frac{5}{8}\)
Now,

Hence,from the above,
We can conclude that
Her steps in the correct order on the right side of the table is:

Question 32.
The scientific name for the little bumps on your tongue is fungiform papillae. Each bump can contain many taste buds. The number of taste buds a person has varies. There are three general classifications of taste: supertaster, medium taster, and non-taster. Suppose a supertaster has 8,640 taste buds. Solve the equation 4.5n = 8,640 to find the number of taste buds, n, a non-taster may have.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 38
Answer:
It is given that
The scientific name for the little bumps on your tongue is fungiform papillae. Each bump can contain many taste buds. The number of taste buds a person has varies. There are three general classifications of taste: supertaster, medium taster, and non-taster. Suppose a supertaster has 8,640 taste buds
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 38
The given equation according to the given information is:
4.5n = 8,640
Now,

Hence, from the above,
We can conclude that
The number of taste buds a non-taster may have is: 1,920 taste buds

Question 33.
Model with Math In one study, the number of women classified as supertasters was 2.25 times the number of men classified as supertasters. Suppose 72 women were classified as supertasters. Write an equation that represents the number of men, m, who were classified as supertasters. Then solve the equation. How many men were classified as supertasters?
Answer:
It is given that
In one study, the number of women classified as supertasters was 2.25 times the number of men classified as supertasters. Suppose 72 women were classified as supertasters
Now,
From the given information,
The number of women who are supertasters = 2.25 × (The numberof men who are supertasters)
72 = 2.25 × (The number of men who are supertasters)
The number of men who are supertasters = \(\frac{72}{2.25}\)
= 32
Hence, from the above,
We can conclude that
The number of men who are classified as supertasters is: 32 men

Question 34.
Use Structure A fraction, f, multiplied by 5 equals \(\frac{1}{8}\). Write an algebraic sentence to show the equation. Then solve the equation and explain how you solved it.
Answer:
It is given that
A fraction, f, multiplied by 5 equals \(\frac{1}{8}\).
Now,
The representation of the given information in the form of an equation is:
f × 5 = \(\frac{1}{8}\)
5f = \(\frac{1}{8}\)
Now,

Hence, from the above,
We can conclude that
The value of f for the given equation is: \(\frac{1}{40}\)

Question 35.
Yelena needs to swim a total of 8 miles this week. So far, she swam 5\(\frac{3}{8}\) miles. Use the equation 5\(\frac{3}{8}\) + m = 8 to find how many more miles Yelena needs to swim.
Answer:
It is given that
Yelena needs to swim a total of 8 miles this week. So far, she swam 5\(\frac{3}{8}\) miles.
Now,
The givene quation according to the given information is:
5\(\frac{3}{8}\) + m = 8
Now,
Convert the given mixed number into a fraction
So,
\(\frac{43}{8}\) + m = 8
Now,

Hence, from the above,
We can conclude that
The number of miles Yelena needs to swim is: \(\frac{21}{8}\) miles

Question 36.
Can any equation that is written using addition be written as an equivalent equation using subtraction? Explain your reasoning and give an example containing decimals that shows your reasoning.
Answer:
Yes, any equation that is written using addition can be written as an equivalent equation using subtraction
Ex:
3.35 + y = 6.88
y = 6.88 – 3.35
y = 3.53
Now,
By using Subtraction:
Subtract any number let say 5 from both sides of 3.35 + y = 6.88
Now,
3.35 + y – 5 = 6.88 – 5
y – 1.65 = 1.88
y = 3.53

Question 37.
Critique Reasoning Oscar is 12 years old and his little sister is 6. Oscar uses a to represent his age. He says that he can use the expression a ÷ 2 to always know his sister’s age. Do you agree? Explain.
Answer:
It is given that
Oscar is 12 years old and his little sister is 6. Oscar uses a to represent his age. He says that he can use the expression a ÷ 2 to always know his sister’s age
Now,
Let the age of Oscar be: 18 years
Then,
The age of his sister will be: 8 – 6 = 12 years
So,
The relationship between the ages of Oscar and his sister is:
The age of Oscar = The age of his sister + 6
Hence, from the above,
We can conclude that
We can not agree with Oscar

Assessment Practice

Question 38.
Which value for y makes the equation 0.26y = 0.676 true?
A. y = 0.17576
B. y = 0.26
C. y = 2.6
D. y = 26
Answer:
The given equation is:
0.26y = 0.676
Now,

Hence, from the above,
We can conclude that
The value of y that makes the given equation true is:

Question 39.
Which value for x makes the equation 0.435 + x = 0.92 true?
A. x = 1.355
B. x = 0.595
C. x = 0.495
D. x = 0.485
Answer:
The given equation is:
0.435 + x = 0.92
Now,
x = 0.92 – 0.435
x = 0.485
Hence, from the above,
We can conclude that
The value of x that makes the givene quation true is:

Topic 4 Mid-Topic Checkpoint

Question 1.
Vocabulary Describe the relationship between equations and the properties of equality. Lessons 4-1 and 4-2
Answer:
The property of equality states that when we do arithmetic operations on both sides of an equation by the same number, the two sides remain equal and the property of equality is pplicable only on equations

In 2-4, write an equation for the situation. Then solve the equation.
Question 2.
A fraction f multiplied by 4 equals \(\frac{1}{2}\). Lesson 4-5
Answer:
The given situation is:
A fraction f multiplied by 4 equals \(\frac{1}{2}\)
Now,
The representation of the given situation in the form of an equation is:
4f = \(\frac{1}{2}\)
Now,
Divide the equation by 4 on both sides
So,
f = \(\frac{1}{2 × 4}\)
f = \(\frac{1}{8}\)
Hence, from the above,
We can conclude that
The value of f for the given equation is: \(\frac{1}{8}\)

Question 3.
When 832 is divided by n, the result is 16. Lesson 4-4
Answer:
The given situation is:
When 832 is divided by n, the result is 16
Now,
The representation of the given situation in the form of an equation is:
\(\frac{832}{n}\) = 16
Now,
Multiply the equation with n on both sides
So,
n = \(\frac{832}{16}\)
n = 52
Hence, from the above,
We can conclude that
The value of n for the given equation is: 52

Question 4.
When 10 is subtracted from x, the result is 6. Lesson 4-3
Answer:
The given situation is:
When 10 is subtracted from x, the result is 6.
Now,
The representation of the given situation in the form of an equation is:
x – 10 = 6
Now,
Add 10 on both sides for the equation
So,
x – 10 + 10 = 6 + 10
x = 16
Hence, from the above,
We can conclude that
The value of x for the given equation is: 16

Question 5.
Select all the equations that are equivalent to n-9 = 12. Lesson 4-2
☐ n – n – 9 = 12 – n
☐ n – 9 + 12 = 12 – 9
☐ n – 9 + 9 = 12 + 9
☐ n – 9 – n = 12 – n
☐ n – 9 + 9 = 12 – 12
Answer:
The given equation is: n – 9 = 12
Now,
We know that,
According to the “Property of Equality”,
We have to do the same arithmetic operation with the same number on both sides of the equation to keep the equation balanced
Hence, from the above,
We can conclude that
The equations that are equivalent to n – 9 = 12 are:

Question 6.
Select all the values ford that make the equation 9 = 18 ÷ d true. Lesson 4-1
☐ 2
☐ 0.5
☐ \(\frac{10}{5}\)
☐ 162
☐ \(\frac{1}{4}\)
Answer:
The given equation is:
9 = 18 ÷ d
Now,
Multiply with d on both sides fro the equation
So,
d = \(\frac{18}{9}\)
d = 2
Hence,f rom the above,
We can conclude that
The values of d that make the given equation true are:

Question 7.
The area, A, of a triangle is 15.3 square cm. Its base, b, is 4.5 cm. The formula for finding the area of a triangle is A = \(\frac{1}{2}\)bh. Write and solve an equation to find the height, h, of the triangle. Lessons 4-4 and 4-5
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 39
Answer:
It is given that
The area, A, of a triangle is 15.3 square cm. Its base, b, is 4.5 cm. The formula for finding the area of a triangle is A = \(\frac{1}{2}\)bh.
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 39
Now,
According to the given formula in the given informatio,
15.3 = \(\frac{1}{2}\) × 4.5 × h
15.3 = 2.25 × h
h = \(\frac{15.3}{2.25}\)
h = 6.8 cm
Hence,f rom the above,
We can conclude that
The value of h of the given triangle is: 6.8 cm

Topic 4 Mid-Topic Performance Task

Ronald carved 3\(\frac{3}{8}\) feet of a totem pole. He says that the totem pole is \(\frac{3}{4}\) complete.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 40

PART A
If h represents the height, in feet, of the finished totem pole, then \(\frac{3}{4}\)h = 3\(\frac{3}{8}\) represents this situation. Which equations show the use of a reciprocal to write an equivalent equation that can be used to solve for h? Select all that apply.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 41
Answer:
It is given that
Ronald carved 3\(\frac{3}{8}\) feet of a totem pole. He says that the totem pole is \(\frac{3}{4}\) complete.
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 40
Now,
If h represents the height, in feet, of the finished totem pole, then
\(\frac{3}{4}\)h = 3\(\frac{3}{8}\) represents this situation
Now,
We know that,
The term “Reciprocal” is applicable only for multiplication and division
Now,
We know that,
The reciprocal of \(\frac{3}{4}\) is: \(\frac{4}{3}\)
Now,
We know that,
According to the “Property of Equality”,
The arithmetic operation we performed on the left side of th equation with a number will have to be the same to the right side of the equation also
Hence, from the above,
We can conclude that
The equations that show the use of a reciprocal to write an equivalent equation that can be used to solve for h are:

PART B
Use the equation in Part A to determine the height of the finished totem pole. Then write and solve an equation to find the height, s, of the section that has not been carved.
Answer:
From Part A,
The equation to determine the height h of the finished totem pole is:
\(\frac{3}{4}\)h = 3\(\frac{3}{8}\)
Now,
The given figure is:
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 40
Now,
From the given figure,
We can observe that
The \(\frac{1}{4}\) of the section has not been carved
Now,
h = 3\(\frac{3}{8}\) × \(\frac{4}{3}\)
h = \(\frac{27}{8}\) × \(\frac{4}{3}\)
h = \(\frac{27 × 4}{8 × 3}\)
h = \(\frac{9}{2}\) ft
Now,
The height of the section that ahs not been carved (s) = \(\frac{h}{4}\)
= h × \(\frac{1}{4}\)
= \(\frac{9}{2}\) × \(\frac{1}{4}\)
= \(\frac{9}{8}\) ft
Hence, from the above,
We can conclude that
The height of the section that has not been carved is: \(\frac{9}{8}\) ft

PART C
Ronald spent $10.50 on tools and x dollars on the wood for the totem pole. His total cost for the totem pole is $19.35. The equation $10.50 + x = $19.35 represents this situation. What is the cost of the wood Ronald used?
Answer:
It is given that
Ronald spent $10.50 on tools and x dollars on the wood for the totem pole. His total cost for the totem pole is $19.35. The equation $10.50 + x = $19.35 represents this situation
Now,
The given equation that represents the given situation is:
$10.50 + x = $19.35
x = $19.35 – $10.50
x = $8.85
Hence, from the above,
We can conclude that
The cost of Wood Ronald used is: $8.85

PART D
To make the same totem pole with wood that costs y dollars, Ronald would have to spend a total of $35.19. Explain which property of equality Ronald could use to solve the equation $10.50 + y = $35.19 and why that property can be used. Then show how to use that property to solve for y.
Answer:
It is given that
To make the same totem pole with wood that costs y dollars, Ronald would have to spend a total of $35.19.
Now,
The given equation that is used to represent the given situation is:
$10.50 + y = $35.19
Now,
We know that,
According to the “Subtraction Property of Equality”,
Subtract the same amount from both sides to make the equation balanced
Now,
Subtract $10.50 from the given equation by using the “Subtraction Property of Equality”
So,
$10.50 + y – $10.50 = $35.19 – $10.50
y = $24.69
Hence, from the above,
We can conclude that
The cost of wood that is used to make the totem pole is: $24.69

Lesson 4.6 Understand and Write Inequalities

Solve & Discuss It!
The record time for the girls’ 50-meter freestyle swimming competition is 24.49 seconds. Camilla has been training and wants to break the record. What are some possible times Camilla would have to swim to break the current record?

I can… understand and write an inequality that describes a real-world situation.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 42
Answer:
It is given that
The record time for the girls’ 50-meter freestyle swimming competition is 24.49 seconds. Camilla has been training and wants to break the record”
Now,
The given table is:

Now,
From the given table,
We can observe that
To break the record,
Camilia has to swim greater than the time it is taken for the girls’ 50-meter freestyle swimming competition
So,
The possible times Camilia would have to swim to break the current record is: 26.56 seconds, 25.14 seconds, and 25.32 seconds
Hence, from the above,
We can conclude that
The possible times Camilia would have to swim to break the current record is:
a. 26.56 seconds b. 25.14 seconds c. 25.32 seconds

Reasoning
How do Camilla’s possible times compare to 24.49 seconds?
Answer:
From the above Exercise,
We know that,
Camilia wants to break the record
So,
The possible times of Camilia must be greater than 24.49 seconds
Hence, from the above,
We can conclude that
Camilia’s possible times are greater than 24.49 seconds

Focus on math practices
Be Precise Fran won a blue ribbon for growing the heaviest pumpkin. It weighed 217 pounds. What could be the weights of other pumpkins in the contest? How could you show the weights of the other pumpkins using a mathematical statement? Explain.
Answer:
It is given that
Fran won a blue ribbon for growing the heaviest pumpkin. It weighed 217 pounds.
Now,
We know that,
The heaviest weight means there is no other weight greater than that weight
Now,
From the given information,
217 pounds is the heaviest weight
So,
Other weights other than 217 pounds are lesser
Now,
Let the weight of all the other pumpkins be x
So,
According to the given information,
The weights of all the pumpkins present in the contest have lesser weight than the heaviest pumpkin
So,
The mathematical representation of the above statement is:
x < 217 pounds
Hence, from the above,
We can conclude that
The representation of the give information in the form of a mathematical statement is:
The weights of all the pumpkins present in the contest have lesser weight than the heaviest pumpkin. i.e.,
x < 217 pounds

Essential Question
How can you write an inequality to describe a situation?
Answer:
The steps to write an inequality to describe a situation are:
a. Read through the entire problem.
b. Highlight the important information and key words that you need to solve the problem.
c. Identify your variables.
d. Write the equation or inequality.
e. Solve.
f. Write your answer in a complete sentence.
g. Check or justify your answer

Try It!

Use the number line to show some of the ages of people who do not need to be accompanied by an adult. Write an inequality to represent the ages of people, n, who do not need to be accompanied by an adult.
Envision Math Common Core 6th Grade Answers Topic 4 Represent And Solve Equations And Inequalities 43
Answer:
Let the ages of the people who do not need to be accompanied by an adult be: n
Now,
The given figure is:

Now,
From the given figure,
We can observe that
The people who are less than 8 years have to be accompanied by an adult
Now,
The representation of the people who do not need to be accompanied by an adult in the given number line is:

So,
The inequality that represents ages of people ,n, who do not need to be accompanied by an adult is:
n > 8 years
Hence, from the above,
We can conclude that
The inequality that represents ages of people ,n, who do not need to be accompanied by an adult is:
n > 8 years

Convince Me! How do you know to which group an 8-year-old belongs, those who must be accompanied by an adult or those who do not need to be accompanied by an adult? Explain.
Answer:
The given figure is:

Now,
Let the number of children who must be accompanied by an adult be: x
Let the number of children who do not need to be accompanied by an adult be: y
Now,
From the given figure,
We can observe that
The children under the age of 8 must be accompanied by an adult
So,
The representation of an inequality that represents the ages of the children who must be accompanied by an adult is:
x < 8
The representation of an inequality that represents the ages of the children who need not to be accompanied by an adult is:
y > 8
Hence, from the above,
We can conclude that
The representation of an inequality that represents the ages of the children who must be accompanied by an adult is:
x < 8
The representation of an inequality that represents the ages of the children who need not to be accompanied by an adult is:
y > 8

Try It!

Write an inequality to represent each situation.
a. Harry is taller than 60 inches.
Answer:
The given situation is:
Harry is taller than 60 inches.
Now,
Let h be the height of Harry
Hence, from the above,
We can conclude that
The representation of the inequality that represents the given situation is:
h > 60 inches

b. Sherry is not 4 years old.
Answer:
The given situation is:
Sherry is not 4 years old
Now,
Let a be the age of Sherry
Hence, from the above,
We can conclude that
The representation of the inequality that represents the given situation is:
a ≠ 4 years

c. Hank has at least $7.50.
Answer:
The given situation is:
Hank has at least $7.50
Now,
Let s be the amount of money Hank has
Hence, from the above,
We can conclude that
The representation of the inequality that represents the given situation is:
s ≥ $7.50

KEY CONCEPT
Inequality symbols can be used to describe situations that have more than one possible solution.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 44

Do You Understand?
Question 1.
Essential Question How can you write an inequality to describe a situation?
Answer:
The steps to write an inequality to describe a situation are:
a. Read through the entire problem.
b. Highlight the important information and key words that you need to solve the problem.
c. Identify your variables.
d. Write the equation or inequality.
e. Solve.
f. Write your answer in a complete sentence.
g. Check or justify your answer

Question 2.
Generalize What is the difference between an equation with a variable and an inequality with a variable?
Answer:
An equation is a mathematical statement that shows the equal value of two expressions while an inequality is a mathematical statement that shows that an expression is lesser than or more than the other. An equation shows the equality of two variables while an inequality shows the inequality of two variables.

Question 3.
Would it be more efficient to use an inequality or to list all of the quantities less than 6? Explain.
Answer:
Without using “Inequalities”,
The qualities less than 6 are: -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, and 5
By using the “Inequalities”,
The quantities less than 6 are: x < 6
Where,
x is the list of numbers that are less than 6

Question 4.
Generalize How are the symbols for greater than (>) and greater than or equal to (≥) related?
Answer:
“Greater than or equal to” and “less than or equal to” are just the applicable symbol with half an equal sign under it. For example, 4 or 3 ≥ 1 shows us a greater sign over half an equal sign, meaning that 4 or 3 are greater than or equal to 1. It works the other way, too

Do You Know How?
In 5-12, write an inequality for each situation.
Question 5.
A number, n, is greater than 22.
Answer:
The given situation is:
A number, n, is greater than 22.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
n > 22

Question 6.
The value, v, does not equal 2\(\frac{1}{2}\).
Answer:
The given situation is:
The value, v, does not equal 2\(\frac{1}{2}\).
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
v ≠ 2\(\frac{1}{2}\)

Question 7.
Sally’s age, a, is at most 15.
Answer:
The given situation is:
Sally’s age, a, is at most 15.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
a ≤ 15

Question 8.
The width of the picture, w, is shorter than 8.5 inches.
Answer:
The given situation is:
The width of the picture, w, is shorter than 8.5 inches.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
w < 8.5 inches

Question 9.
Steve’s height, h, is at least 48 inches.
Answer:
The given situation is:
Steve’s height, h, is at least 48 inches.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
h ≥ 48 inches

Question 10.
Vera’s baby brother’s age, b, is not 24 months.
Answer:
The given situation is:
Vera’s baby brother’s age, b, is not 24 months.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
b ≠ 24 months

Question 11.
The number of quarters, q, in the jar is less than 75.
Answer:
The given situation is:
The number of quarters, q, in the jar is less than 75.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
q < 75

Question 12.
The length of the fish a fisherman catches, f, must be at least 10 inches for him to keep it.
Answer:
The given situation is:
The length of the fish a fisherman catches, f, must be at least 10 inches for him to keep it
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
f ≥ 10 inches

Practice & Problem Solving

In 13-22, write an inequality for each situation.
Question 13.
Up to 12 people, p, can ride in the van.
Answer:
The given situation is:
Up to 12 people, p, can ride in the van.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
p ≤ 12 people

Question 14.
A number of days, d, of sunshine is not 28.
Answer:
The given situation is:
A number of days, d, of sunshine is not 28.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
d ≠ 28

Question 16.
The value, v, of the bracelet is less than $85.25.
Answer:
The given situation is:
The value, v, of the bracelet is less than $85.25.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
v < $85.25

Question 15.
The distance of the race, r, is farther than 6.2 miles.
Answer:
The given situation is:
The distance of the race, r, is farther than 6.2 miles.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
r > 6.2 miles

Question 17.
The number of people, p, that a restaurant can seat at one time is no more than 171.
Answer:
The given situation is:
The number of people, p, that a restaurant can seat at one time is no more than 171.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
p ≤ 171 people

Question 18.
The time, t, a customer has left on a parking meter is at least 25 minutes.
Answer:
The given situation is:
The time, t, a customer has left on a parking meter is at least 25 minutes.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
t ≥ 25 minutes

Question 19.
The bill, b, was less than $45.
Answer:
The given situation is:
The bill, b, was less than $45.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
b < $45

Question 20.
The girls live b blocks apart; they do not live 7\(\frac{1}{2}\) blocks apart.
Answer:
The given situation is:
The girls live b blocks apart; they do not live 7\(\frac{1}{2}\) blocks apart.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
b ≠ 7\(\frac{1}{2}\) blocks

Question 21.
The speed of the truck, s, must be no less than 34 miles per hour.
Answer:
The given situation is:
The speed of the truck, s, must be no less than 34 miles per hour.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
s ≤ 34 miles per hour

Question 22.
The number of baseball games, x, that Karen went to last year is more than 5.
Answer:
The given situation is:
The number of baseball games, x, that Karen went to last year is more than 5.
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
x ≤ 5 games

Question 23.
Mia is taller than Gage. If m represents Mia’s height and g represents Gage’s height, write an inequality that shows the relationship between their heights.
Answer:
It is given that
Mia is taller than Gage and m represents Mia’s height and g represents Gage’s height
Now,
According to the given information,
The representation of the inequality for the given situation is:
m > g
Hence, from the above,
We can conclude that
The representation of the inequality for the given situation is:
m > g

Question 24.
Taryn sold gift-wrapping paper for a school fund-raiser. She sold at least 15 rolls of paper. Write an inequality to represent the amount of money, d, she earned for the fund-raiser.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 45
Answer:
It is given that
Taryn sold gift-wrapping paper for a school fund-raiser. She sold at least 15 rolls of paper
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 45
Now,
Let the number of rolls of paper be: x
So,
The representation of the inequality for representing the rolls of paper is:
x ≥ 15 rolls
Now,
The amount of money, d, Taryn earned for the fundraiser = (The total number of rolls) × (The cost of each roll)
= 15 × $8
= $120
So,
The representation of the inequality for representing the amount of money Taryn earned for the fundraiser is:
d ≥ $120
Hence, from the above,
We can conclude that
The representation of the inequality for representing the amount of money Taryn earned for the fundraiser is:
d ≥ $120

Question 25.
A city in New England just experienced its greatest 1-day snowfall. Write an inequality to represent a snowfall that would beat this record.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 46
Answer:
It is given that
A city in New England just experienced its greatest 1-day snowfall
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 46
Now,
Let the snowfall that would beat the given record be: t
From the given figure,
We can observe that
The representation of the inequality to represent a snowfall that would beat the given record is:
t > 19.7 inches of snow

Question 26.
The first bookcase, a, in a library can hold 1 less book than the second bookcase. The second bookcase holds 2,492 books. Write an inequality to represent the number of books the first bookcase can hold.
Answer:
It is given that
The first bookcase, a, in a library can hold 1 less book than the second bookcase. The second bookcase holds 2,492 books
So,
The number of books the first bookcase can hold = (The number of books the second bookcase can hold) – 1
= 2,492 – 1
= 2,491 books
Now,
Let the number of books the first bookcase can hold be: x
Let the number of books the second bookcase can hold be: y
So,
From the above,
We can observe that
x < y
Hence, from the above,
We can conclude that
The number of books the first bookcase can hold < The number of books the second bookcase can hold

Question 27.
A certain airplane must carry no more than 134 passengers during a flight. Write an inequality to represent the number of passengers, p, that would NOT be allowed during this flight.
Answer:
It is given that
A certain airplane must carry no more than 134 passengers during a flight
Now,
Let p be the number of passengers during a flight
So,
The representation of the inequality to represent the number of passengers that would not be allowed during this flight is:
p > 134 passengers
Hence, from the above,
We can conclude that
The representation of the inequality to represent the number of passengers that would not be allowed during this flight is:
p > 134 passengers

Question 28.
Higher Order Thinking To ride a certain roller coaster, a rider must be at least 42 inches tall. To represent this situation, Elias wrote h > 42 and Nina wrote h > 42. Who is correct? Explain.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 47
Answer:
It is given that
To ride a certain roller coaster, a rider must be at least 42 inches tall. To represent this situation, Elias wrote h > 42 and Nina wrote h > 42.
Now,
Let the height of the rider be: h inches
So,
The representation of the inequality that represents the height of a rider to ride a certain roller coaster is:
h ≥ 42
Hence, from the above,
We can conclude that
Elias is correct

Assessment Practice

Question 29.
Miguel earns extra money working two weekends with his dad. He is saving to buy a new bike that costs $140.
Heather says that Miguel needs to earn more than $6 for each hour that he works to have enough money to buy the bike. Her work is shown below. Write an inequality to explain why she is incorrect.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 48
$140 ÷ 23 hours > $6.00 per hour
Miguel has to earn more than $6.00 per hour.
Answer:
It is given that
Miguel earns extra money working two weekends with his dad. He is saving to buy a new bike that costs $140.
Heather says that Miguel needs to earn more than $6 for each hour that he works to have enough money to buy the bike. Her work is shown below
Now,
The given figure is:

Now,
From the given figure,
We can observe that
Miguel’s work record in Weekend 1 is: 9 hours
Miguel’s work record in Weekend 2 is: 7 hours
So,
The total number of hours in 2 Weekends for Migul = 9 + 7
= 16 hours
So,
The amount of money Migul will earn per hour = (The amount of money Migul saved to buy a new bike) ÷ (The total number of hours in 2 Weekends for Migul)
= \(\frac{$140}{16}\)
= $8.75
Hence, from the above,
We can conclude that
The inequality that represents Migul’s work is:
W > $8.75 per hour

Lesson 4.7 Solve Inequalities

Solve & Discuss It!
Henry is thinking of a number that is less than 17. What number could he be thinking of?
I can… write and represent solutions of inequalities.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 49
Answer:
It is given that
Henry is thinking of a number that is less than 17
Now,
Let x be the numbers less than 17
Where,
x may be an integer, decimal number (or) a whole number that is less than 17
So,
The representation of the inequality that represents the number that is less than 17 that Henry is thinking is:
x < 17
Hence, from the above,
We can conclude that
The representation of the inequality that represents the number that is less than 17 that Henry is thinking is:
x < 17

Use Appropriate Tools
How can you use a number line to show all the numbers that are less than 17?
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 50
Answer:
We know that,
The numebrs that are 17 will be an integer, decimal number or a Whole number
Now,
The whole numbers that are less than 17 are: 0, 1, 2, 3, …….. 16
Hence, from the above,
We can conclude that
The representation of the list of all the Whole numbers that are less than 17 in the given number line is:

Focus on math practices
Reasoning Could Henry be thinking of 17? Explain.
Answer:
No, Henry should not be thinking of 17 because it is clearly mentioned that Henry is thinking of a number that is less than 17
So,
The list of the numbers that Henry may be thinking is: 0, 1, 2, 3 ….. 16

Essential Question
How can you represent the solutions of an inequality?
Answer:
The rules for Solving Inequalities are:
a. Add the same number on both sides.
b. From both sides, subtract the same number.
c. By the same positive number, multiply both sides.
d. By the same positive number, divide both sides.
e. Multiply the same negative number on both sides and reverse the sign.
A closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution

Try It!

Graph all of the solutions of x < 8.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 51
To graph x < 8, draw a(n) ________ circle at 8 on the number line.
7 and 4 are two of the many possible solutions of the inequality.
Shade the solutions to the ________ of the ________ circle you drew at 8.
Answer:
The given inequality is: x < 8
Now,
The representation of the given inequality in the given number line is:

Now,


Hence, from the above,
We can conclude that
The solutions for the given inequality in the given number line is:

Convince Me! How does the graph of the inequality change when the less than sign is changed to a greater than sign? How does it stay the same?
Answer:
We know that multiplying or dividing an inequality by a negative number changes the direction of the inequality. In other words, a greater-than symbol becomes a less-than symbol, and vice versa
Now,
When the inequality has the symbol > (or) ≥, the numbers to the right of this inequality will become the solutions
When the inequality has the symbol < (or) ≤, the numbers to the left of this inequality will become the solutions

Try It!

There are no menu items on the children’s menu at the Flamingo Restaurant that cost more than $8.50. What are all the possible costs of the items on the children’s menu?
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 52
Answer:
It is given that
There are no menu items on the children’s menu at the Flamingo Restaurant that cost more than $8.50
Now,
Let c be the cost of the menu items on the children’s menu at the Flamingo Restaurant
So,
The representation of the inequality that represents the given situation is:
c < $8.50
Hence,
The representation of all the possible costs of the items on the children’s menu on the given number line is:

Try It!

Which athletes, if any, would qualify for the finals if the length of a jump that qualifies for the finals were at least 20\(\frac{1}{2}\) feet?
Answer:
It is given that
The length of a jump that qualifies for the finals were at least 20\(\frac{1}{2}\) feet
Now,
The given table is:

Now,
Let the length of a jump be: d feet
Now,
The representation of the given situation in teh form of an inequality is:
d ≥ 20\(\frac{1}{2}\) feet
Now,
From the given table,
We can observe that
The values that are greater than 20\(\frac{1}{2}\) feet are:
20\(\frac{1}{2}\) = 20\(\frac{1}{2}\)
20\(\frac{1}{2}\) > 22\(\frac{1}{3}\)
Hence, from the above,
We can conclude that
Amir and Ryan would qualify for the finals if the length of a jump that qualifies for the finals were at least 20\(\frac{1}{2}\) feet

KEY CONCEPT
An inequality uses these symbols: <, >, ≤ , or ≥ to compare two expressions.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 53

Do You Understand?
Question 1.
Essential Question How can you represent the solutions of an inequality?
Answer:
The rules for Solving Inequalities are:
a. Add the same number on both sides.
b. From both sides, subtract the same number.
c. By the same positive number, multiply both sides.
d. By the same positive number, divide both sides.
e. Multiply the same negative number on both sides and reverse the sign.
A closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution

Question 2.
In Example 1, why is 9 a solution of x > 5?
Answer:
The given equation is: x > 5
Now,
From the given equation,
We can observe that
Since x > 5,
The solutions to the given equation are all the numbers that are greater than 5
So,
The given equation will have infinitely many solutions that are greater than 5
Hence, from the above,
We can conclude that
9 is a solution of x > 5

Question 3.
Explain why 2 is NOT a solution of x > 5.
Answer:
The given equation is: x > 5
Now,
From the given equation,
We can observe that
Since x > 5,
The solutions to the given equation are all the numbers that are greater than 5
So,
The given equation will have infinitely many solutions that are greater than 5
Hence, from the above,
We can conclude that
2 is not a solution of x > 5

Question 4.
How many solutions does the inequality x > 12 have? Explain.
Answer:
The given equation is: x > 12
Now,
From the given equation,
We can observe that
Since x > 12,
The solutions to the given equation are all the numbers that are greater than 12
So,
The given equation will have infinitely many solutions that are greater than 12
Hence, from the above,
We can conclude that
x > 12 will have infinitely many solutions that are greater than 12

Question 5.
Generalize How do the graphs of the solutions of inequalities involving greater than (>) and greater than or equal to (≥) compare?
Answer:
A closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution

Do You Know How?
In 6 and 7, write the inequality that each graph represents.
Question 6.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 54
Answer:
The given number line is:

Now,
From the given number line,
We can observe that
There is an open circle on 14.
So,
14 will not be included and the selected numbers are to the left side of 14 in the given number line
So,
The representation of the inequality for the given number line is:

Hence, from the above,
We can conclude that
The representation of the inequality for the given number line is:
z < 14

Question 7.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 55
Answer:
The given number line is:

Now,
From the given number line,
We can observe that
There is a closed circle on 18.
So,
18 will be included and the selected numbers are to the right side of 18 in the given number line
So,
The representation of the inequality for the given number line is:

Hence, from the above,
We can conclude that
The representation of the inequality for the given number line is:
d ≥ 18

In 8-11, substitute each given value of the variable to find which, if any, is a solution of the inequality.
Question 8.
w < 8         w = 4.3, 5.3, 8.3, 9
Answer:
The given inequality is: w < 8
Now,
The given list of numbers are: 4.3, 5.3, 8.3, and 9
Now,
When we observe the given list of numbers,
4.3, and 5.3 are less than 8
Hence, from the above,
We can conclude that
The solutions for the given inequality are: 4.3, 5.3

Question 9.
t > 25      t = 24, 25, 25.1, 27
Answer:
The given inequality is: t > 25
Now,
The given list of numbers are: 24, 25, 25.1, and 27
Now,
When we observe the given list of numbers,
25.1 and 27 are greater the 25
Hence, from the above,
We can conclude that
The solutions for the given inequality are: 25.1, 27

Question 10.
g ≤ 4        g = 0, 4, 5, 6
Answer:
The given inequality is: g ≤ 4
Now,
The given list of numbers are: 0, 4, 5, and 6
Now,
When we observe the given list of numbers,
0 and 4 are less than or equal to 4
Hence, from the above,
We can conclude that
The solutions for the given inequality are: 0, 4

Question 11.
y ≥ 28        y = 4, 5, 6, 7
Answer:
The given inequality is: y ≥ 8
Now,
The given list of numbers are: 4, 5, 6, and 7
Now,
When we observe the given list of numbers,
The given list of numbers are less than 28
Hence, from the above,
We can conclude that
There are no solutions for the given inequality from the given list of numbers

Practice & Problem Solving

In 12-15, write the inequality that each graph represents.
Question 12.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 56
Answer:
The given number line is:

Now,
From the given number line,
We can observe that
There is an open circle on 7.
So,
7 will not be included and the selected numbers are to the left side of 7 in the given number line
So,
The representation of the inequality for the given number line is:

Hence, from the above,
We can conclude that
The representation of the inequality for the given number line is:
y < 7

Question 13.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 57
Answer:
The given number line is:

Now,
From the given number line,
We can observe that
There is an open circle on 0.
So,
0 will not be included and the selected numbers are to the right side of 0 in the given number line
So,
The representation of the inequality for the given number line is:

Hence, from the above,
We can conclude that
The representation of the inequality for the given number line is:
b > 0

Question 14.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 58
Answer:
The given number line is:

Now,
From the given number line,
We can observe that
There is an open circle on 3.
So,
3 will not be included and the selected numbers are to the right side of 3 in the given number line
So,
The representation of the inequality for the given number line is:

Hence, from the above,
We can conclude that
The representation of the inequality for the given number line is:
x > 3

Question 15.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 59
Answer:
The given number line is:

Now,
From the given number line,
We can observe that
There is a closed circle on 5.
So,
5 will be included and the selected numbers are to the left side of 5 in the given number line
So,
The representation of the inequality for the given number line is:

Hence, from the above,
We can conclude that
The representation of the inequality for the given number line is:
t ≤ 5

In 16-19, graph each inequality on a number line.
Question 16.
h ≥ 9
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 59
Answer:
The given inequality is: h ≥ 9
Hence, from the above,
We can conclude that
The representation of the given inequality on the number line is:

Question 17.
p < 3
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 59
Answer:
The given inequality is: p < 3
Hence, from the above,
We can conclude that
The representation of the given inequality on the number line is:

Question 18.
t ≤ 6
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 59
Answer:
The given inequality is: t ≤ 6
Hence, from the above,
We can conclude that
The representation of the given inequality on the number line is:

Question 19.
s > 1
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 59
Answer:
The given inequality is: s > 1
Hence, from the above,
We can conclude that
The representation of the given inequality on the number line is:

In 20-27, name three solutions of each inequality.
Question 20.
x > 10.5
Answer:
The given inequality is: x > 10.5
Now,
We know that,
If the inequality has a “>” symbol, then the values that are greater than the given number will be the solutions for the equation
Hence, from the above,
We can conclude that
The three solutions for the given inequality are: 11, 12, and 13

Question 21.
r < 19
Answer:
The given inequality is: r < 19
Now,
We know that,
If the inequality has a “<” symbol, then the values that are lesser than the given number will be the solutions for the equation
Hence, from the above,
We can conclude that
The three solutions for the given inequality are: 15, 16, and 17

Question 22.
y ≥ 200
Answer:
The given inequality is: y ≥ 200
Now,
We know that,
If the inequality has a “≥” symbol, then the values that are greater than or equal to the given number will be the solutions for the equation
Hence, from the above,
We can conclude that
The three solutions for the given inequality are: 200, 205, and 210

Question 23.
m ≤ 82
Answer:
The given inequality is: m ≤ 82
Now,
We know that,
If the inequality has a “≤” symbol, then the values that are lesser than or equal to the given number will be the solutions for the equation
Hence, from the above,
We can conclude that
The three solutions for the given inequality are: 75, 80, and 81

Question 24.
x ≥ 12
Answer:
The given inequality is: x ≥ 12
Now,
We know that,
If the inequality has a “≥” symbol, then the values that are greater than or equal to the given number will be the solutions for the equation
Hence, from the above,
We can conclude that
The three solutions for the given inequality are: 12, 13, and 14

Question 25.
q ≤ 3.5
Answer:
The given inequality is: q ≤ 3.5
Now,
We know that,
If the inequality has a “≤” symbol, then the values that are lesster than or equal to the given number will be the solutions for the equation
Hence, from the above,
We can conclude that
The three solutions for the given inequality are: 0, 1.5, and 3.5

Question 26.
v > 35
Answer:
The given inequality is: v > 35
Now,
We know that,
If the inequality has a “>” symbol, then the values that are greater than the given number will be the solutions for the equation
Hence, from the above,
We can conclude that
The three solutions for the given inequality are: 40, 45, and 50

Question 27.
m < 2.5
Answer:
The given inequality is: m < 2.5
Now,
We know that,
If the inequality has a “<” symbol, then the values that are lesser than the given number will be the solutions for the equation
Hence, from the above,
We can conclude that
The three solutions for the given inequality are: 0, 1, and 2

Question 28.
The inequality w ≤ 1,500 describes the maximum weight in pounds, w, allowed by law in a freight elevator. Is a total weight of either 1,505 pounds or 1,600 pounds allowed in a freight elevator? Explain.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 61
Answer:
It is given that
The inequality w ≤ 1,500 describes the maximum weight in pounds, w, allowed by law in a freight elevator.
Now,
The given equation is: w ≤ 1,500
Now,
From the given inequality,
We can observe that
The solutions for the given inequality will be less than or equal to 1,500 but not greater than 1,500
So,
1,505 > 1,500 and 1,600 > 1,500
Hence, from the above,
We can conclude that
The total weight of either 1,505 pounds or 1,600 pounds will not be allowed in a freight elevator

Question 29.
Reasoning Graph the inequalities x > 2 and x < 2 on the same number line. What value, if any, is not a solution of either inequality? Explain.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 59
Answer:
The given inequalities are: x > 2 and x < 2
Now,
The representation of x > 2 on the given number line is:

The representtaion of x < 2 on the given number line is:

Now,
When we observe the number lines of x > 2 and x < 2,
We can say that
2 is not a solution for either of the number lines
Hence, from the above,
We can conclude that
2 is not a solution of either inequality

Question 30.
Model with Math Death Valley is the hottest place in the United States. The highest temperature ever recorded there was 134°F. The lowest temperature recorded there was 15°F. Write two inequalities that would describe the temperature, in degrees Fahrenheit, in Death Valley at any time since temperatures have been recorded.
Answer:
It is given that
Death Valley is the hottest place in the United States. The highest temperature ever recorded there was 134°F. The lowest temperature recorded there was 15°F
Now,
Let the highest temperature recorded in the Death Valley be: H
Let the lowest temperature recorded in the Death Valley be: L
So,
The inequality that represents the highest temperature in °F in the Death Valley is: H < 134° F
The inequality that represents the lowest temperature in °F in the Death Valley is: L > 15° F
Hence, from the above,
We can conclude that
The two inequalities that describe the temperature in the Death Vally at any time since the temperatures have been recorded is:
The inequality that represents the highest temperature in °F in the Death Valley is: H < 134° F
The inequality that represents the lowest temperature in °F in the Death Valley is: L > 15° F

Question 31.
The number line below represents the solutions of the inequality x > 7. Is 7.1 a solution? Is 7.01 a solution? Explain.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 62
Answer:
It is given that
The number line below represents the solutions of the inequality x > 7
Now,
The given number that represents the solution for the given inequality x > 7 is:
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 62
Now,
From the above number line,
We can observe that
The solutions for x > 7 will be all the numbers that are greater than 7 and will be infinite
So,
7.1 > 7 and 7.01 > 7
Hence, from the above,
We can conclude that
7.1 and 7.01 are the solutions of the given inequality x > 7

Question 32.
The temperature in a greenhouse should be 65 degrees or higher. Write an inequality to describe the allowable temperature in the greenhouse.
Answer:
It is given that
The temperature in a greenhouse should be 65 degrees or higher.
Now,
Let the temperature of the greenouse be: t
So,
The inequality that describes the allowable temperature in the greenhouse is:
t ≥ 65°
Hence, from the above,
We can conclude that
The inequality that describes the allowable temperature in the greenhouse is:
t ≥ 65°

Question 33.
Higher Order Thinking Francine received a gift card to buy cell phone apps. She says that the card’s value is enough to buy any of the apps shown at the right. Let v be the dollar value of the gift card. Write an inequality that best describes the value of the gift card.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 63
Answer:
It is given that
Francine received a gift card to buy cell phone apps. She says that the card’s value is enough to buy any of the apps shown at the right. Let v be the dollar value of the gift card.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 63
Now,
When we observe the given figure,
We can say that
The maximum vaue of the given gift card is: $12
So,
The costs of the given apps should be less than $12
So,
The representation of the inequality that describes the value of the gift card is:
v ≤ $12
Hence, from the above,
We can conclude that
The representation of the inequality that describes the value of the gift card is:
v ≤ $12

Question 34.
The maximum load on a small plane is 400 pounds. Let w represent the weight on the plane. Write an inequality to describe the allowable weight on the plane.
Answer:
It is given that
The maximum load on a small plane is 400 pounds. Let w represent the weight on the plane
Now,
Since the maximum load is 400 pounds, the remaining weights will be less than or equal to 400 pounds
So,
The representation of the inequalty that describes teh allowable weight on the plane is:
w ≤ 400 pounds
Hence, from the above,
We can conclude that
The representation of the inequalty that describes teh allowable weight on the plane is:
w ≤ 400 pounds

Question 35.
Jillian is thinking of a whole number that is greater than 21. What numbers, if any, make the inequality n > 21 true for n = 0, 1, 2, 3, 4, …?
Answer:
It is given that
Jillian is thinking of a whole number that is greater than 21
Now,
The given inequality is: n > 21
Now,
We know that,
If any inequality has “>” symbol, then the solutions for that inequality will be greater than thenumber and the solutions will be infinite
So,
The solutions for the given inequality will be: 22, 23, 24,……..
Hence, from the above,
We can conclude that
The numbers that make the inequality n > 21 true are: 22, 23, 24, …..

Assessment Practice

Question 36.
Select all the given values of y that make the inequality 3y < 25 true.
☐ 6.5
☐ 7
☐ 8
☐ 8.5
☐ 9
Answer:
The given inequality is: 3y < 25
Now,
Divide the given nequality be 3 on both sides
So,
\(\frac{3y}{3}\) < \(\frac{25}{3}\)
y < 8.3
Hence, from the above,
We can conclude that
All the values of y that make the inequality 3y < 25 true are:

Question 37.
Tania started a graph to show the inequality y < 3.7. Finish labeling the number line and draw the graph.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 64
Answer:
It is given that
Tania started a graph to show the inequality y < 3.7
Now,
The given inequality is: y < 3.7
Now,
The representation of the given number line and the solution for thegiven inequality is:

Hence, from the above,
We can conclude that
The completed number line and the solutions for y < 3.7 on the completed number line is:

3-ACT MATH

3-Act Mathematical Modeling: Checking a Bag
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 65

АСТ 1
Question 1.
After watching the video, what is the first question that comes to mind?
Answer:

Question 2.
Write the Main Question you will answer.
Answer:

Question 3.
Construct Arguments Predict an answer to this Main Question. Explain your prediction.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 66
Answer:

Question 4.
On the number line below, write a number that is too small to be the answer. Write a number that is too large.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 67
Answer:

Question 5.
Plot your prediction on the same number line.
Answer:

ACT 2
Question 6.
What information in this situation would be helpful to know? How would you use that information?
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 68
Answer:

Question 7.
Use Appropriate Tools What tools can you use to solve the problem? Explain how you would use them strategically.
Answer:

Question 8.
Model with Math Represent the situation using mathematics. Use your representation to answer the Main Question.
Answer:

Question 9.
What is your answer to the Main Question? is it higher or lower than your prediction? Explain why.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 69
Answer:

ACT 3
Question 10.
Write the answer you saw in the video.
Answer:

Question 11.
Reasoning Does your answer match the answer in the video? If not, what are some reasons that would explain the difference?
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 70
Answer:

Question 12.
Make Sense and Persevere Would you change your model now that you know the answer? Explain.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 71
Answer:

Reflect
Question 13.
Model with Math Explain how you used a mathematical model to represent the situation. How did the model help you answer the Main Question?
Answer:

Question 14.
Was an equation or an inequality more useful to answer the Main Question? Explain.
Answer:

SEQUEL
Question 15.
Be Precise A different airline has a weight limit of 40 pounds for a checked bag. Explain how the answer would change for this airline.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 72
Answer:

Lesson 4.8 Understand Dependent and Independent Variables

Explain It!
Max is shipping a present to his grandmother.
I can… identify dependent and independent variables.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 73

A. What are three factors that will affect the weight of the box? What are three factors that will not affect the weight of the box?
Answer:
It is given that
Max is shipping a present to his grandmother.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 73
Now,
From the given figure,
We can observe that
The three factors that will affect the weight of the box is:
a. Size of the box
b. The material of the box
c. Contents inside the box
The three factors that will not affect the weight of the box is:
a. The color of the box
b. The shape of the box
c. The design of the box

B. How might the size of the box and the contents of the box affect the weight of the box?
Answer:
We know that,
When we increase the size of the box, the contents of the box will also increase in the box and also the weight of the box will increase
So,
The relationship between the size of the box and the contents of the box and the weight of the box is:
Size of the box ∝ Contents of the box ∝ Weight of the box

Focus on math practices
Model with Math Describe another situation in which changing one factor results in changes to another factor.
Answer:
The example of a situation in which changing one factor results in changes to another factor is:
The distance a car travels, d, is dependent on the speed, s, at which it travels. So, speed is the independent variable and distance is the dependent variable
So,
Here,
The distance a car travels, d, is dependent on the speed, s, at which it travels. So, speed is the independent variable and distance is the dependent variable

Essential Question
What does it mean for one variable to be dependent on another variable?
Answer:
A dependent variable is a variable whose value will change depending on the value of another variable, called the independent variable. In a scientific experiment, it is the variable being tested, and therefore, it is called the dependent variable

Try It!

A baker used a certain number of cups of batter, b, to make p pancakes. Which variable, p, pancakes or b, batter is the dependent variable? Explain.
Answer:
It is given that
A baker used a certain number of cups of batter, b, to make p pancakes
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
Now,
From the given situation,
We can observe that
The independent variable is: b
The dependent variable is: p
Hence, from the above,
We can conclude that
Pancakes (p) is the dependent variable

Convince Me! If the baker doubles the number of cups of batter used, b, what would you expect to happen to the number of pancakes made, p? Explain.
Answer:
It is given that
The baker doubles the number of cups of batter used, b
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
From the given situation,
We can observe that
If the baker doubles the number of cups of batter used, b, then the number of pancakes, p, would also be double in quantity
Hence, from the above,
We can conclude that
If the baker doubles the number of cups of batter used, b, then the number of pancakes, p, would also be double in quantity

Try It!

Jenna wants to rent a mountain bike by the week. Identify the independent variables that affect the total rental cost.
Answer:
It is given that
Jenna wants to rent a mountain bike by the week
Now,
From Example 3,
We can observe that
The dependent variables and independent present in Example 3 are:

Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variables that affect the total rental cost for the given situation is:
a. Price per day (d)
b. Price per week (w)
c. Length of rental (l)
Hence, from the above,
We can conclude that
The independent variables that affect the total rental cost for the given situation is:
a. Price per day (d)
b. Price per week (w)
c. Length of rental (l)

KEY CONCEPT
A dependent variable changes in response to another variable, called an independent variable. An independent variable causes the change in a dependent variable. It is independent because its value is not affected by other variables.
The distance a car travels, d, is dependent on the speed, s, at which it travels. Speed is the independent variable, and distance is the dependent variable.

Do You Understand?
Question 1.
Essential Question What does it mean for one variable to be dependent on another variable?
Answer:
A dependent variable is a variable whose value will change depending on the value of another variable, called the independent variable. In a scientific experiment, it is the variable being tested, and therefore, it is called the dependent variable

Question 2.
Jake and Viola record the number of miles, m, they bike to help track the number of calories, s, they burn in an hour.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 74
Critique Reasoning Viola says the number of calories, c, they burn is the dependent variable. Do you agree? Explain.
Answer:
It is given that
Jake and Viola record the number of miles, m, they bike to help track the number of calories, s, they burn in an hour.
Now,
From the given situation,
We can observe that
The number of calories they burn is dependent on the number of miles
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of miles
The dependent variable for the given situation is: Number of calories they burn
Hence, from the above,
We can conclude that
We can agree with Viola

Question 3.
Reasoning in the biking problem above, identify at least one other independent variable that could affect the dependent variable.
Answer:
The given situation from Exercise 2 is:

Now,
From the given situation,
We can observe that
The number of calories they burn is dependent on the number of miles
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of miles
The dependent variable for the given situation is: Number of calories they burn
Hence, from the above,
We can conclude that
The independent variable that could affect the dependent variale for the given situation is: Number of miles

Do You Know How?
In 4-11, identify the independent variable and the dependent variable.
Question 4.
The amount of money, m, earned if t raffle tickets are sold
Answer:
The given situation is:
The amount of money, m, earned if t raffle tickets are sold
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: traffic tickets, t
The dependent variable for the given situation is: Amount of oney, m
Hence, from the above,
We can conclude that
The independent variable for the given situation is: traffic tickets, t
The dependent variable for the given situation is: Amount of money, m

Question 5.
The number of hours, h, worked and the amount of money, m, earned
Answer:
The given situation is:
The number of hours, h, worked and the amount of money, m, earned
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of hours , h
The dependent variable for the given situation is: Amount of money, m
Hence, from the above,
We can conclude that
The independent variable for the given situation is: traffic tickets, t
The dependent variable for the given situation is: Amount of money, m

Question 6.
The number of shelves, s, in a bookcase and the number of books, b, the bookcase can hold
Answer:
The given situation is:
The number of shelves, s, in a bookcase and the number of books, b, the bookcase can hold
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of shelves, s
The dependent variable for the given situation is: Number of books, b, the bookcase can hold
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of shelves, s
The dependent variable for the given situation is: Number of books, b, the bookcase can hold

Question 7.
The number of pages, p, you read in your book in h hours
Answer:
The given situation is:
The number of pages, p, you read in your book in h hours
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of pages, p
The dependent variable for the given situation is: Number of hours, h
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of pages, p
The dependent variable for the given situation is: Number of hours, h

Question 8.
The number of gallons, g, of water a garden hose produces after running for m minutes
Answer:
The given situation is:
The number of gallons, g, of water a garden hose produces after running for m minutes
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of gallons, g, of water
The dependent variable for the given situation is: Number of minutes, m
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of gallons, g, of water
The dependent variable for the given situation is: Number of minutes, m

Question 9.
The number of peaches, y, a farmer harvests in x bushels
Answer:
The given situation is:
The number of peaches, y, a farmer harvests in x bushels
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of bushels, x
The dependent variable for the given situation is: Number of peaches, y
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of bushels, x
The dependent variable for the given situation is: Number of peaches, y

Question 10.
The number of hours, h, you spend driving at a speed of r miles per hour
Answer:
The given situation is:
The number of hours, h, you spend driving at a speed of r miles per hour
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of miles per hour, r
The dependent variable for the given situation is: Number of hours, h
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of miles per hour, r
The dependent variable for the given situation is: Number of hours, h

Question 11.
Name at least two independent variables that could result in a change in a monthly electric bill.
Answer:
The two independent variables that could result in a change in a monthly electric bill is:
a. Outside temperature and humidity
b. The frequency of the electrical appliances inside the house you use

Practice & Problem Solving

In 12-15, identify the independent variable and the dependent variable.
Question 12.
The pages, p, in a book and the weight, w, of the book
Answer:
The given situation is:
The pages, p, in a book and the weight, w, of the book
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of pages, p, in a book
The dependent variable for the given situation is: Weight, w, of the book
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of pages, p, in a book
The dependent variable for the given situation is: Weight, w, of the book

Question 13.
The number of hamburgers, h, sold and the dollar amount of sales, s, taken in
Answer:
The given situation is:
The number of hamburgers, h, sold and the dollar amount of sales, s, taken in
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of hamburgers, h, sold
The dependent variable for the given situation is: The amount of sales, s, taken in
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of hamburgers, h, sold
The dependent variable for the given situation is: The amount of sales, s, taken in

Question 14.
The pounds, p, of flour you buy and the number of bread loaves, b, you want to make
Answer:
The given situation is:
The pounds, p, of flour you buy and the number of bread loaves, b, you want to make
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: Number of pounds, p, of flour you buy
The dependent variable for the given situation is: Number of bread loaves, b, you want to make
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of pounds, p, of flour you buy
The dependent variable for the given situation is: Number of bread loaves, b, you want to make

Question 15.
The temperature, t, of water and the number of minutes, m, the water is in the freezer
Answer:
The given situation is:
The temperature, t, of water and the number of minutes, m, the water is in the freezer
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
So,
The independent variable for the given situation is: The temperature, t, of water
The dependent variable for the given situation is: Number of minutes, m, the water is in the freezer
Hence, from the above,
We can conclude that
The independent variable for the given situation is: The temperature, t, of water
The dependent variable for the given situation is: Number of minutes, m, the water is in the freezer

Question 16.
Write your own situation. Identify the independent and dependent variables.
Answer:
In an experiment in Psychology, on the impact of sleep deprivation on test performance,
a. Sleep deprivation would be the independent variable.
b. The dependent variable is the variable that is measured by the experimenter

Question 17.
Name at least two independent variables that could result in a change in the price of a basket of grapefruits.
Answer:
The independent variables that could result in a change in the price of a basket of grapefruits is:
a. The weight of grapefruits
b. The size of a basket

Question 18.
Critique Reasoning You spend c dollars for p identical pairs of pants. A friend claims that because c increases if you increase p, and p increases if you increase c, either corp could be the independent variable. Is your friend right or wrong? Explain.
Answer:
It is given that
You spend c dollars for p identical pairs of pants. A friend claims that because c increases if you increase p, and p increases if you increase c, either corp could be the independent variable.
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
Now,
From the given situation,
We can observe that
The independent variable for the given situation is: Identical pairs of pants, p
The dependent variable for the given situation is: Amount of money spent, c
Hence, from the above,
We can conclude that
Your friend is wrong

Question 19.
The number of oranges in a bag and the cost of the bag of oranges are related. What is the independent variable in this relationship? Explain.
Answer:
It is given that
The number of oranges in a bag and the cost of the bag of oranges are related
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
Now,
From the given situation,
We can observe that
The independent variable for the given situation is: Number of oranges
The dependent variable for the given situation is: The cost of oranges
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Number of oranges

Question 20.
The dependent variable g represents the growth of a plant. What variables can represent independent variables in this situation?
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 75
Answer:
It is given that
The dependent variable g represents the growth of a plant
Now,
We know that,
An “Independent variable” causes the dependent variable to change
A “Dependent variable” change in response to another variable
Now,
From the given figure,
We can observe that
The independent variable for the given situation is: The number of plants
Hence, from the above,
We can conclude that
The independent variable for the given situation is: The number of plants

In 21 and 22, use the table at the right.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 76
Question 21.
The table shows distances driven by the Williams family each day of their vacation. What is an independent variable that would affect the total distance they drove each day?
Answer:
It is given that
The table shows distances driven by the Williams family each day of their vacation
Now,
The given table is:
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 76
Now,
From the given table,
We can observe that
The independent variable that would affect the total distance is: Number of days
Hence, from the above,
We can conclude that
The independent variable that would affect the total distance is: Number of days

Question 22.
Name at least two dependent variables that could affect the amount of money the Williams family spends on meals during their vacation.
Answer:
The given table is:
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 76
Now,
From the given table,
We can observe that
The independent variables that could affect the amount of money the Williams family spends on meals during their vacation is:
a. The number of items present during meals
b. The number of days
Hence, from the above,
We can conclude that
The independent variables that could affect the amount of money the Williams family spends on meals during their vacation is:
a. The number of items present during meals
b. The number of days

Question 23.
The cost of a salad at a restaurant depends on many factors. List at least two independent variables that could affect the cost of a salad.
Answer:
It is given that
The cost of a salad at a restaurant depends on many factors
So,
The independent variables that could affect the cost of a salad for the given situation is:
a. The amount of a salad
b. The type of restaurant
Hence, from the above,
We can conclude that
The independent variables that could affect the cost of a salad for the given situation is:
a. The amount of a salad
b. The type of restaurant

Question 24.
Julian drove from New York to Florida. List at least two independent variables that could affect the number of days Julian took to make the trip.
Answer:
It is given that
Julian drove from New York to Florida
So,
The independent variables that could affect the number of days Julian took to make the trip is:
a. The distance between New York and Florida
b.  The number of hours she drove each day
Hence, from the above,
We can conclude that
The independent variables that could affect the number of days Julian took to make the trip is:
a. The distance between New York and Florida
b.  The number of hours she drove each day

Question 25.
The number of incorrect answers and the score on a math test are related. What is the dependent variable in this relationship? Explain.
Answer:
It is given that
The number of incorrect answers and the score on a math test are related
Now,
From the given situation,
We can observe that
The dependent variable for the given situation is: The score on a math test
Hence, from the above,
We can conclude that
The dependent variable for the given situation is: The score on a math test

Question 26.
Higher Order Thinking Write a situation in which time, t, is an independent variable Then write a situation in which time, t, is a dependent variable.
Answer:
In the study of uniform motion, “Time” is an independent variable, denoted by t and represented on the horizontal axis, while position is a dependent variable, denoted by x and represented on the vertical axis.
“Time” is usually viewed as the independent variable for the simple reason that it doesn’t depend on anything else. Time simply ticks by at the same rate wherever you are (in non-relativistic context), independent of other variables so it doesn’t make sense to express time as a dependent variable

Assessment Practice

Question 27.
Jonas is concerned about the amount of water he uses to wash his laundry. He made a table to show the number of gallons of water used by different washing machines to complete a load of laundry.
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 77

PART A
Use variables to represent the independent and dependent quantities shown in the table.
Answer:
It is given that
Jonas is concerned about the amount of water he uses to wash his laundry. He made a table to show the number of gallons of water used by different washing machines to complete a load of laundry.
Now,
The given table is:
Envision Math Common Core Grade 6 Answer Key Topic 4 Represent And Solve Equations And Inequalities 77
Now,
From the given table,
We can observe that
The independent variable for the given situation is: Type of Washing Machine
The dependent variable for the given situation is: Gallons of Water for a Washing Machine
Hence, from the above,
We can conclude that
The independent variable for the given situation is: Type of Washing Machine
The dependent variable for the given situation is: Gallons of Water for a Washing Machine

PART B
Use variables to represent the dependent variable and the independent variable in this sentence.
Jonas records the total cost of the water he uses and the number of gallons of water he uses.
Answer:
It is given that
Jonas records the total cost of the water he uses and the number of gallons of water he uses.
Now,
From the given sentence,
We can observe that
The independent variable for the given sentence is: Gallons of water
The dependent variable for the given sentence is: The total cost of water
Hence, from the above,
We can conclude that
The independent variable for the given sentence is: Gallons of water
The dependent variable for the given sentence is: The total cost of water

Lesson 4.9 Use Patterns to Write and Solve Equations

Solve & Discuss It!
The table below shows how many candles are in different numbers of boxes. Find a pattern that explains the relationship between the values of c and b. Use words and numbers to describe the pattern. How many candles will there be in 10 boxes?

I can… use patterns to write and solve equations with variables.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 78
Answer:
It is given that
The table below shows how many candles are in different numbers of boxes.
Now,
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 78
Now,
From the given table,
We can observe that
The pattern that explains the relationship between the number of candles and the number of boxes is:
The number of boxes is one-fourth of the number of candles
Now,
The mathematical representation for the above pattern is:
The number of boxes = \(\frac{1}{4}\) × (The number of candles)
Now,
From the above relationship,
The number of candles present in 10 boxes is:
The number of boxes = \(\frac{1}{4}\) × (The number of candles)
10 = \(\frac{1}{4}\) × (The number of candles)
The number of candles = 10 × 4
The number of candles = 40
Hence, from the above,
We can conclude that
The pattern that explains the relationship between the number of candles and the number of boxes is:
The number of boxes is one-fourth of the number of candles
The number of candles present in 10 boxes is: 40 candles

Look for Relationships
How can you get from each value in the left column to its matching value in the right column?
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 79
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 78
Now,
From the above Problem,
The mathematical representation for the pattern between the left column and the right column is:
The number of boxes = \(\frac{1}{4}\) × (The number of candles)
So,
The number of candles = 4 × (The number of boxes)
Hence, from the above,
We can conclude that
The relationship between each value in the left column to its matching value in the right column is:
The number of candles = 4 × (The number of boxes)

Focus on math practices
Use Structure Write a rule that explains how you get from the values in the right column of the table above to the values in the left column.
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 78
Now,
The rule that explains the relationship between the values in the right column of the table to the values in the left column is:
The number of boxes = \(\frac{1}{4}\) × (The number of candles)

Essential Question
How can you use a pattern to write and solve an equation?
Answer:
Problems that are solved most easily by finding a pattern include those that ask students to extend a sequence of numbers or to make a prediction based on data.  Finding a Pattern is an appropriate strategy to use to solve the problem. This is a pattern that is predictable and will be continuous

Try It!

The table shows the number of yards, y, that a professional bicyclist rides in s seconds. Find a pattern that relates the variables. If the cyclist maintains this speed, how far would the cyclist ride in 8 seconds?
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 80
Answer:
It is given that
The table shows the number of yards, y, that a professional bicyclist rides in s seconds.
Now,
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 80
Now,
From the given table,
We can observe that
The relationship between the number of seconds, s, and the number of yards, y is:
12.2 × s = y
12.2s = y
Now,
The number of yards traveled by the cyclist in 8 seconds is:
12.2 × 8 = y
y = 97.6 yards
Hence, from the above,
We can conclude that
The relationship between the number of seconds, s, and the number of yards, y is:
12.2s = y
The number of yards traveled by the cyclist in 8 seconds is: 97.6 yards

Convince Me! How do you know that the equation you wrote describes the pattern in the table?
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 80
Now,
From the above Problem,
The relationship (or) pattern between the number of seconds, s, and the number of yards, y is:
12.2s = y
Now,
Substitute 2, 3, 5 in the place of s
So,
y = 12.2 (2) = 24.4 yards
y = 12.2 (3) = 36.6 yards
y = 12.2 (5) = 61 yards
Hence, from the above,
We can conclude that
The equation that you wrote describes the pattern in the given table because the ratio between the number of seconds and the number of yards is constant

Try It!

If Ethan continues to pay $5 per week, how many more weeks will he need to pay his mother after 12 weeks? Explain.
Answer:
From Example 2,
It is given that
Ethan owes his mother $75 and he repays his mother a set amount of $5 each week
Now,
From Example 2,
The pattern for the given situation is: $75 – $5n
Where,
n is the number of weeks
Now,
For 12 weeks,
The amount Eathan owed to his mother = $75 – $5 (12)
= $75 – $60
= $15
Now,
We know that,
Eathan has to pay a set amount of $5 each week
So,
The number of weeks more Eathan has to pay $5 for his mother = \(\frac{$15}{$5}\)
= 3 weeks
Hence, from the above,
We can conclude that
The number of more weeks will ethan need to pay for his mother after 12 weeks is: 3 weeks

KEY CONCEPT
You can use patterns in a table to write an equation that relates the independent and dependent variables.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 81

Do You Understand?
Question 1.
Essential Question How can you use a pattern to write and solve an equation?
Answer:
Problems that are solved most easily by finding a pattern include those that ask students to extend a sequence of numbers or to make a prediction based on data.  Finding a Pattern is an appropriate strategy to use to solve the problem. This is a pattern that is predictable and will be continuous

Question 2.
Make Sense and Persevere How do you find a pattern that relates the values in a table?
Answer:
To determine the rule for a table, simply look at one pair of input/output numbers and figure out what number has been added, subtracted, multiplied, or divided by it. Then, make sure that pattern matches the rest of the numbers. Once you know the rule for a table, you can finish filling in the rest of it

Question 3.
Reasoning In Example 2, what happens to the value of the dependent variable, a, the amount still owed, when the value of the independent variable, w, the number of weeks Ethan pays $5, is increased by 1?
Answer:
From Example 2,
It is given that
Ethan owes his mother $75 and he repays his mother a set amount of $5 each week
Now,
From Example 2,
The pattern for the given situation is: $75 – $5n
Where,
n is the number of weeks
Now,
It is given that
Ethan owes his mother $75 and he repays his mothe a set amount of $s each week for 13 weeks
Now,
For 13 weeks,
The amount Eathan owed to his mother = $75 – $5 (13)
= $75 – $65
= $10
Hence, from the baove,
We can conclude that
The amount Etan still owed to his mother after 13 weeks is: $10

Question 4.
Look for Relationships Use the pattern in the table below to write an equation.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 82
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 82
Now,
From the given table,
We can observe that
The pattern between the values of x and y is:
y = 5x + 2
Hence, from the above,
We can conclude that
The pattern in the given table to represent as an equation is:
y = 5x + 2

Do You Know How?
Question 5.
The table shows Brenda’s age, b, when Talia’s age, t, is 7, 9, and 10. Find the pattern and then write a rule and an equation that represents the pattern. Then find Brenda’s age when Talia is 12.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 83
Answer:
It is given that
The table shows Brenda’s age, b, when Talia’s age, t, is 7, 9, and 10.
Now,
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 83
Now,
From the given table,
We can observe that
The pattern between Talia’s age and Brenda’s age is:
Brenda’s age = Talia’s age – 5
b = t – 5
So,
Brenda’s age when Talia’s age is 12 is:
b = 12 – 5
b = 7 years
Hence, from the above,
We can conclude that
The pattern between Talia’s age and Brenda’s age is:
Brenda’s age = Talia’s age – 5
Brenda’s age when Talia’s age is 12 is: 7 years

In 6 and 7, use the table below.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 84
Question 6.
Use the equation y = 2x – 7 to complete the table.
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 84
Now,
The given pattern (or) equation that represents the given table is:
y = 2x – 7
Now,
For x = 7,
y = 2 (7) – 7
= 14 – 7
= 7
For x = 8,
y = 2 (8) – 7
= 16 – 7
= 9
Hence, from the above,
We can conclude that
The completed table is:

Question 7.
State the rule for the pattern in words.
Answer:
The given pattern for the given table is:
y = 2x – 7
Now,
The given pattern in terms of words is:
The value of y is equal to the value of 7 less than the 2 times the value of x
Hence, from the above,
We can conclude that
The given pattern in terms of words is:
The value of y is equal to the value of 7 less than the 2 times the value of x

Practice & Problem Solving

In 8 and 9, write a rule and an equation that represents the pattern in each table.
Question 8.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 85
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 85
Now,
From the given table,
We can observe that
The representation of the pattern for the given table in the form of an equation is:
y = x + 32
Hence, from the above,
We can conclude that
The equation that represents the pattern in the given table is:
y = x + 32

Question 9.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 86
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 86
Now,
From the given table,
We can observe that
The representation of the pattern for the given table in the form of an equation is:
n = 3m
Hence, from the above,
We can conclude that
The equation that represents the pattern in the given table is:
n = 3m

In 10 and 11, write a rule and an equation that represents the pattern in each table. Then complete the table.
Question 10.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 87
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 87
Now,
From the given table,
We can observe that
The representation of the pattern for the given table in the form of an equation is:
k = g – 15
So,
The completed table by using the above pattern is:

Hence, from the above,
We can conclude that
The equation that represents the pattern in the given table is:
k = g – 15
The completed table by using the above pattern is:

Question 11.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 88
Answer:

The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 88
Now,
From the given table,
We can observe that
The representation of the pattern for the given table in the form of an equation is:
y = \(\frac{x}{9}\)
So,
The completed table by using the above pattern is:

Hence, from the above,
We can conclude that
The equation that represents the pattern in the given table is:
y = \(\frac{x}{9}\)
The completed table by using the above pattern is:

Question 12.
To celebrate its 125th anniversary, a company produced 125 expensive teddy bears. These “125 Karat Teddy Bears” are made of gold thread and have diamonds for eyes. The table shows the approximate cost of different numbers of these bears. Write an equation that can be used to find c, the cost of n bears.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 89
Answer:
It is given that
To celebrate its 125th anniversary, a company produced 125 expensive teddy bears. These “125 Karat Teddy Bears” are made of gold thread and have diamonds for eyes. The table shows the approximate cost of different numbers of these bears.
Now,
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 89
Now,
From the given table,
We can observe that
The pattern between the number of bears and the cost of bears is:
The cost of n Teddy bears = 47,000 × (n Teddy Bears)
So,
c = 47,000n
Hence, from the above,
We can conclude that
The equation that can be used to find c, the cost of n bears is:
c = 47,000n

Question 13.
Andrea attends the county fair. The fair charges for admission and for each ride is shown below.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 90
a. Use the pattern in the table to the find the cost for Andrea to ride 5 rides or 8 rides. Then write an equation for the pattern.
Answer:
It is given that
Andrea attends the county fair. The fair charges for admission and for each ride is shown
Now,
The given table is:

Now,
From the given table,
We can observe that
The pattern between the number of rides and the cost of rides is:
The cost of r rides = 2.5 × (Tne number of rides) + 8
So,
c = 2.5r + 8
Now,
The completed table by using the above pattern is:

Hence, from the above,
We can conclude that
The pattern to find the cost for Andrea to ride 5 rides or 8rides is:
c = 2.5r + 8
The completed table by using the above pattern is:

b. Find the cost, c, for 12 rides.
Answer:
From Part (a),
The pattern to find the cost of r rides is:
c = 2.5r + 8
So,
The cost for 12 rides is:
c = 2.5 (12) + 8
c = $38
Hence, from the above,
We can conclude that
The cost for Andrea to ride 12 rides is: $38

In 14 and 15, write an equation that best describes the pattern in each table.
Question 14.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 91
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 91
Now,
From the given table,
We can observe that
The pattern between w and z is:
z = w – 2
Hence, from the above,
We can conclude that
The equation that represents the pattern in the given table is:
z = w – 2

Question 15.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 92
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 92
Now,
From the given table,
We can observe that
The pattern between x and y is:
y = 4x
Hence, from the above,
We can conclude that
The equation that represents the pattern in the given table is:
y = 4x

In 16-19, use the equation to complete each table.
Question 16.
t = 5d + 5
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 93
Answer:
The given equation is:
t = 5d + 5
Now,
The given table that is related to the given equation is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 93
Now,
For d = 3,
t = 5 (3) + 5
= 20
For d = 4,
t = 5 (4) + 5
= 25
So,
The completed table is:

Hence, from the above,
We can conclude that
The completed by using the given equation is:

Question 17.
y = \(\frac{1}{2}\)x – 1
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 94
Answer:
The given equation is:
y = \(\frac{1}{2}\)x – 1
Now,
The given table that is related to the given equation is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 94
Now,
For x = 8,
y = \(\frac{1}{2}\) (8) – 1
= 3
For x = 10,
y = \(\frac{1}{2}\) (10) – 1
= 4
So,
The completed table is:

Hence, from the above,
We can conclude that
The completed by using the given equation is:

Question 18.
y = 2x + 1
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 95
Answer:
The given equation is:
y = 2x + 1
Now,
The given table that is related to the given equation is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 95
Now,
For x = 2,
y = 2 (2) + 1
= 5
For x = 3,
y = 2 (3) + 1
= 7
So,
The completed table is:

Hence, from the above,
We can conclude that
The completed by using the given equation is:

Question 19.
b = \(\frac{a}{2}\) – 2
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 96
Answer:
The given equation is:
b = \(\frac{a}{2}\) – 2
Now,
The given table that is related to the given equation is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 96
Now,
For a = 17,
b = \(\frac{17}{2}\) – 2
= 6.5
For a = 14,
b = \(\frac{14}{2}\) – 2
= 5
For a = 11,
b = \(\frac{11}{2}\) – 2
= 3.5
For a = 8,
b = \(\frac{8}{2}\) – 2
= 2
For a = 5,
b = \(\frac{5}{2}\) – 2
= 0.5
So,
The completed table is:

Hence, from the above,
We can conclude that
The completed by using the given equation is:

Question 20.
Higher Order Thinking Maya wrote the equation h= d+ 22 to represent the relationship shown in the table. Is this equation correct? Explain.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 97
Answer:
It is given that
Maya wrote the equation h= d+ 22 to represent the relationship shown in the table.
Now,
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 97
Now,
From the given table,
We can observe that
The relationship between the values of h and d is:
d = 11h
So,
h = d + 22 and d = 11h are different relationships
Hence, from the above,
We can conclude that
h = d + 22 is not correct

Assessment Practice

Question 21.
The table below shows the total cost for the number of movie tickets purchased. Write an equation that represents the relationship between these two quantities. Use the equation to find the cost of 6 tickets.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 98
Answer:
It is given that
The table below shows the total cost for the number of movie tickets purchased
Now,
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 98
Now,
From the given table,
We can purchase that
The relationship between the number of tickets and their cost is:
Cost of n tickets (c) = 8.75 × (Number of tickets)
So,
c = 8.75n
Where,
c is teh cost of n tickets
n is the number of tickets
Now,
The cost of 6 tickets by using the above pattern is:
c = 8.75 (6)
c = $52.5
Hence, from the above,
We can conclude that
The equation that represents the relationship between the number of tickets and their cost is:
c = 8.75n
The cost of 6 tickets by using the above equation is: $52.5

Lesson 4.10 Relate Tables, Graphs, and Equations

Solve & Discuss It!
Nancy walks 4 blocks to Maria’s house. Together, they continue the walk. The walk can be described as n = m + 4, where n is the number of blocks Nancy walks and m is the number of blocks Maria walks. Describe Nancy’s house how the equation, data table, and graph reflect the walk.
I can… analyze the relationship between dependent and independent variables in tables, graphs, and equations.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 99Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 100
Answer:
It is given that
Nancy walks 4 blocks to Maria’s house. Together, they continue the walk. The walk can be described as n = m + 4, where n is the number of blocks Nancy walks and m is the number of blocks Maria walks.
Now,
The given equation that represents the given situation is:
n = m + 4
Where,
n is the number of blocks Nancy walks
m is the number of blocks Maria walks
Now,
From the given equation,
We can observe that
n is the output
m is the input
Now,
The given data table and the graph for the given situation is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 100
Now,
From the given data table,
We can observe that
m is the input
n is the output
We can take any value of input and calculate the value of output
Now,
From the given graph,
We can observe that
The graph can be drawn by taking the ordered pairs (m, n) and if we observe the graph, we can say that it is a straight line without passingthrough the origin

Look for Relationships How can you use the values in one row of the data table to describe the relationship shown in the equation, data table, and graph?
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 100
Answer:
From the above,
We know that,
The given equation that represents the given situation is:
n = m + 4
Where,
n is the number of blocks Nancy walks
m is the number of blocks Maria walks
Now,
From the given equation,
We can observe that
n is the output
m is the input
Now,
The given data table and the graph for the given situation is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 100
Now,
From the given data table,
We can observe that
m is the input
n is the output
We can take any value of input and calculate the value of output
Now,
From the given graph,
We can observe that
The graph can be drawn by taking the ordered pairs (m, n) and if we observe the graph, we can say that it is a straight line without passingthrough the origin

Focus on math practices
Model with Math Draw a line through the points on the graph. What ordered pair on the line includes m = 5? Explain what that ordered pair represents.
Answer:
The given data table is:

Now,
We know that,
The representation of the ordered pair is: (Input, Output)
Now,
From the given data table,
We can observe that
The ordered pairs are: (1, ), (2, 6), (3, 7)
So,
The representation of the ordered pairs in the coordinate plane is:

Now,
From the above,
We can observe that
The equation that represents the above situation is:
n = m + 4
Now,
For m = 5,
n = 5 + 4
= 9
So,
The ordered pair when m = 5 is: (5, 9)
The above ordered pair represents that
When Maria walks 5 blocks, Nncy walks 9 blocks
Hence, from the above,
We can conclude that
The ordered pair when m = 5 is: (5, 9)
The above ordered pair represents that
When Maria walks 5 blocks, Nancy walks 9 blocks

Essential Question
How can you analyze the relationship between dependent and independent variables using tables, graphs, and equations?
Answer:
In a graph, the X-axis runs horizontally (side to side) and the Y-axis runs vertically (up and down). Typically, the independent variable will be shown on the X axis and the dependent variable will be shown on the Y axis
In a table, the independent variable will be shown in the left side or the top of the column ans the dependent variable will be shown in the right side or the bottom of the column
In an equation, the independent variable will be shown at the right side of “=” and the dependent variable will be shown at the left side of “=”

Try It!

The booster club now raises $0.41 for each pom pom they sell. Complete the table and graph. Write and solve an equation to find how many pom poms they need to sell to raise $50.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 101
Answer:
It is given that
The booster club now raises $0.41 for each pom pom they sell.
Now,
From Example 1,
We can observe that
The representation of the equation that represents the amount of money raised to the number of pom poms sold is:
r = 0.45n
Where,
r is the amount of money raised
n is the number of pom poms
Now,
According to the given situation,
The representation of the equation that represents the amount of money raised to the number of pom poms sold is:
r = 0.41n
Now,
For n = 150,
r = 0.41 (150)
= 61.5
So,
The completed table is:

The representation of the graph in the coordinate plane according to the above table is:

Now,
For r = $50,
r = 0.41n
$50 = 0.41n
n = \(\frac{50}{0.41}\)
n = 121.95
n ≅ 122
Hence, from the above,
We can conclude that
The number of pom poms they needed to sell to raise $50 must be atleast 122 pom poms

Convince Me! How does finding three values for x and y help you represent the relationship between x and y?
Answer:
We know that,
In a graph,
The x-values represent on the horizontal axis and the y-values represent on the vertical axis
Now,
The representation of x and y values in a graph gives us the information that whether the equation is linear or not

Try It!

A company makes decorations for pens. All the supplies cost $5, and the company plans to sell the decorations for $2 apiece. Analyze the relationship between the number of decorations sold and the profit by completing the table and the graph. Use the table and the graph to write and solve an equation to find the number of decorations that must be sold for the company to make a $15 profit.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 102
Answer:
It is given that
A company makes decorations for pens. All the supplies cost $5, and the company plans to sell the decorations for $2 apiece
Now,
Let the number of decorations be x
Let the profit be y
So,
The representation of the given situation in the form of an equation is:
Profit = $2 × (Number of decorations)
y = 2x
Now,
For x = 3,
y = 2 (3)
= 6
For x = 4,
y = 2 (4)
= 8
For x = 5,
y = 2 (5)
= 10
So,
The completed table for y = 2x is:

So,
The representation of the above table in the cordinate plane is:

Now,
The number of decorations that must be sold for the company to make a $15 profit is:
y = 2x
$15 = 2 (x)
x = \(\frac{15}{2}\)
x = 7.5
x ≅ 8
Hence, from the above,
We can conclude that
The number of decorations that must be sold for the company to make a profit of $15 should be about 8 decorations

KEY CONCEPT
You can analyze the relationship between independent and dependent variables in tables and graphs. You can relate tables and graphs to an equation.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 103

Do You Understand?
Question 1.
Essential Question How can you analyze the relationship between dependent and independent variables using tables, graphs, and equations?
Answer:
In a graph, the X-axis runs horizontally (side to side) and the Y-axis runs vertically (up and down). Typically, the independent variable will be shown on the X axis and the dependent variable will be shown on the Y axis
In a table, the independent variable will be shown in the left side or the top of the column ans the dependent variable will be shown in the right side or the bottom of the column
In an equation, the independent variable will be shown at the right side of “=” and the dependent variable will be shown at the left side of “=”

Question 2.
Reasoning Using the relationship in Example 1, how many pom poms must the booster club sell to raise $75 for charity? Explain.
Answer:
From Example 1,
We know that,
The relationship between the amount of money raised and the number of pom poms sold is:
r = 0.45n
Where,
r is the amount of money raised
n is the number of pom poms sold
Now,
For r = $75,
75 = 0.45n
n = \(\frac{75}{0.45}\)
n = 166.66
n ≅ 167
Hence, from the above,
We can conclude that
The number of pom poms must booster club sell to raise $75 for charity should be at least 167 pom poms

Question 3.
Construct Arguments For every 4 bananas a grocery store sells, it sells 2 apples. Mary wrote the equation 4b × 2 = a, where b= the number of bananas sold and a = the number of apples sold. Does Mary’s equation correctly represent the relationship of bananas sold to apples sold? Explain.
Answer:
It is given that
For every 4 bananas a grocery store sells, it sells 2 apples. Mary wrote the equation 4b × 2 = a, where b= the number of bananas sold and a = the number of apples sold
Now,
According to the given information,
The representation of the given information in the form of an equation is:
4 × (The number of bananas) = 2 × (The number of apples)
So,
4b = 2a
4b × 2 = a and 4b = 2a are not the same
Hence, from the above,
We can conclude that
Mary’s equation does not correctly represent the relationship of bananas sold to apples sold

Do You Know How?
In 4-6, use the equation d = 4t.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 104
Question 4.
Complete the table.
d = distance t = time
Answer:
The given equation is: d = 4t
Now,
For t = 1,
d = 4 (1) = 4
For t = 2,
d = 4 (2) = 8
For t = 3,
d = 4 (3) = 12
So,
The completed table for the given equation is:

Hence, from the above,
We can conclude that
The completed table for d = 4t is:

Question 5.
Name four ordered pairs found on the line plotted using this equation.
Answer:
The given table is:

Now,
The representation of the given table in the coordinate plane is:

Hence, from the above,
We can conclude that
The ordered pairs found on the line plotted using the equation d = 4t are:
(1, 4), (2, 8), (3, 12)

Question 6.
Describe the relationship between the variables.
Answer:
The given equation is: d = 4t
Now,
From the given equation,
We can observe that
t is the independent variable (or) input
d is the dependent variable (or) output
Now,
From Question 5,
We can observe that
As the value of t increases, the value of d also increases
Hence, from the above,
We can conclude that
The relationship between the variables d and t in the equation d = 4t is:
As the value of t increases, the value of d also increases

In 7, complete the table and graph to show the relationship between the variables in the equation d = 5 + 5t.
Question 7.
d= distance
t = time
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 105
Answer:
The given equation is: d = 5 + 5t
Now,
For t = 0,
d = 5 + 0 = 5
For t = 2,
d = 5 + 5 (2)
= 5 + 10
= 15
For t = 4,
d = 5 + 5 (4)
= 5 + 20
= 25
So,
The completed table for the equation d = 5 + 5t is:

So,
The representation of the above table in the coordinate plane is:

Hence, from the above,
We can conclude that
The completed table and the graph to show the relationship between the variables in the equation d = 5 +5t are:

Practice & Problem Solving

In 8 and 9, complete the table and graph to show the relationship between the variables in each equation.
Question 8.
A rectangle is \(\frac{1}{2}\) inch longer than it is wide.
Let w = width.
Let l = length
Graph l = w + \(\frac{1}{2}\)
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 106
Answer:
It is given that
A rectangle is \(\frac{1}{2}\) inch longer than it is wide.
Now,
The given equation is:
l = w + \(\frac{1}{2}\)
Now,
For w = 1,
l = 1 + \(\frac{1}{2}\)
= 1 + 0.5
= 1.5
For w = 2,
l = 2 + \(\frac{1}{2}\)
= 2 + 0.5
= 2.5
For w = 3,
l = 3 + \(\frac{1}{2}\)
= 3 + 0.5
= 3.5
So,
The completed table for the equation l = w + \(\frac{1}{2}\) is:

So,
The representation of the above table in the coordinate plane is:

Hence, from the above,
We can conclude that
The completed table and the graph to show the relationship between the variables in the equation l = w + \(\frac{1}{2}\) are:

Question 9.
The sale price is $5 less than the regular price.
Let s = the sale price.
Let r = the regular price.
Graph s = r – 5.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 107
Answer:
It is given that
The sale price is $5 less than the regular price.
Now,
The given equation is:
s = r – 5
Now,
For r = 10,
s = 10 – 5 = 5
For r = 20,
s = 20 – 5 = 15
For r = 30,
s = 30 – 5 = 25
So,
The completed table for the equation s = r – 5 is:

So,
The representation of the above table in the coordinate plane is:

Hence, from the above,
We can conclude that
The completed table and the graph to show the relationship between the variables in the equation l = w + \(\frac{1}{2}\) are:

Question 10.
The points (2, 4) and (-2, -4) are plotted on the coordinate plane using the equation y = a • x. How can you use the coordinates to find the value of a?
Answer:
It is given that
The points (2, 4) and (-2, -4) are plotted on the coordinate plane using the equation y = a • x
Now,
Compare the given points with (x, y)
Now,
The given equation is:
y = a . x
Now,
For (2, 4),
4 = a . 2
a = \(\frac{4}{2}\)
a = 2
Now,
For (-2, -4),
-4 = a . (-2)
4 = a . 2
a = \(\frac{4}{2}\)
a = 2
Hence, from the above,
We can conclude that
The value of a for the equation y = a . x is: 2

Question 11.
Without using a table or graph, identify three other points that a graph of the equation in Exercise 10 will pass through.
Answer:
From Question 10,
We know that,
The equation is: y = a . x
Now,
From Question 10,
We can observe that
The points that pss through y = a . x are: (2, 4), and (-2, -4)
Now,
For x = 3,
y = 2 . 3 = 6
For x = -3,
y = 2 . -3 = -6
For x = 4,
y = 2 . 4 = 8
Hence, from the above,
We can conclude that
The other three points that a graph of the equation y = a . x will pass through are: (3, 6), (-3, -6), and (4, 8)

Question 12.
Reasoning The Jackson family is planning a weekend vacation. They plan to rent a car from the ABC Car Rental Company. Let m represent the number of miles the family will drive. Let c represent the cost for renting a car. Write an equation that shows what the cost for renting a car will be.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 108
Answer:
It is given that
The Jackson family is planning a weekend vacation. They plan to rent a car from the ABC Car Rental Company. Let m represent the number of miles the family will drive. Let c represent the cost for renting a car.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 108
Now,
According the given information,
The equation that represents the given situation is:
c = ($40 + $0.10)m
So,
c = $40.1m
Hence, from the above,
We can conclude that
The equation tht shows the cost for renting a car is:
c = $40.1m

In 13, write an equation. Complete the table and graph to solve the problem.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 109
Question 13.
A puppy weighs 1 pound. What does the puppy weigh after 4 weeks?
Answer:
It is given that
A puppy weighs 1 pound and the puppy gains \(\frac{1}{2}\) each week
Now,
Let w be the number of weeks
Let p be the weight of the puppy
Now,
The completed table for the given information is:

Now,
The representation of the above table in the coordinate plane is:

Hence, from the above,
We can conclude that
The completed table and the completed graph for the given problem is:

Question 14.

Model with Math During a movie matinee, the film projector broke. The theater manager refunded the ticket price to everyone attending. Let n represent the number of people watching the movie. Let r represent the total amount of money refunded. Write an equation to represent the amount of money refunded.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 110
Answer:
It is given that
During a movie matinee, the film projector broke. The theater manager refunded the ticket price to everyone attending. Let n represent the number of people watching the movie. Let r represent the total amount of money refunded.
Now,
The given figure is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 110
Now,
The amount of money collecting by selling the movie tickets =  $5.00
Now,
The representation of the quation for the given information is:
The total amount of money refunded = $5 (The number of people watching the movie)
So,
r = 5n
Hence, from the above,
We can conclude that
The equation to represent the amount of money refunded is:
r = 5n

Question 15.
Higher Order Thinking Write an algebraic equation that matches the values shown in the table at the right. Explain how you solved the problem.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 111
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 111
Now,
From the given table,
We can observe that
The pattern that describes the relationship between x and y is:
y = 3x + 5
Hence, from the above,
We can conclude that
The algebraic equation that matches the values shown in the table is:
y = 3x + 5

Assessment Practice

Question 16.
For every hour Sonia worked, she had made 2 seashell necklaces for her gift shop.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 112

PART A
Write an equation that describes the relationship shown in the graph on the right.
Answer:
It is given that
For every hour Sonia worked, she had made 2 seashell necklaces for her gift shop.
Now,
The given graph that describes the given situation is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 112
Now,
From the given graph,
The representation of the quation that represents the given situation is:
The number of seashell necklaces = 2 × (Time in hours)
So,
n = 2h
Hence, from the above,
We can conclude that
The equation that describes the relationship shown in the graph is:
n = 2h

PART B
Describe the relationship between the variables in the graph and the equation.
Answer:
From Part A,
The equation that describes the relationship shown in the graph is:
n = 2h
Where,
n is the number of seashell necklaces
h is the number of hours
Now,
In the graph,
The x-axis represents the number of hours, h
The y-axis represents the number of seashell necklaces, n

Topic 4 Review

Topic Essential Question
What procedures can be used to write and solve equations and inequalities?
Answer:
The three methods most commonly used to solve systems of equation are substitution, and elimination. Substitution and elimination are simple methods that can effectively solve most systems of two equations in a few straightforward steps
The steps to solve an inequality are:
a. Add the same number to both sides.
b. Subtract the same number from both sides.
c. Multiply both sides by the same positive number.
d. Divide both sides by the same positive number.
e. Multiply both sides by the same negative number and reverse the sign

Vocabulary

Review Complete each definition with a vocabulary word.
Vocabulary

  • dependent variable
  • independent variable
  • inequality
  • equation

Question 1.
In the equation y = x + 9, the variable x is the ___________
Answer:
We know that,
In the equation y = x + 9,
x is called the “Independent variable”
Hence, from the above,
We can conclude that
The best term that is suitable for the given sentence is: Independent variable

Question 2.
A(n). __________ has an infinite number of solutions.
Answer:
We know that,
An “Inequality” has infinite number of solutions
Hence, from the above,
We can conclude that
The best term that is suitable for the given sentence is: Inequality

Question 3.
In the equation y = x -9, the variable y is the _________
Answer:
We know that,
In the equation y = x – 9,
y is called the “Dependent variable”
Hence, from the above,
We can conclude that
The best term that is suitable for the given sentence is: Dependent variable

Draw a line from each equation to the property of equality it illustrates.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 113
Answer:
The equations that matched to the corresponding property of equality it illustrates is:

Use Vocabulary in Writing
Describe how to solve \(\frac{3}{7}\)n = 27. Use vocabulary words in your explanation.
Answer:
The given equation is:
\(\frac{3}{7}\)n = 27
Now,
From the given equation,
We can observe that
n is the variable
Now,
Multiply the given equation with \(\frac{7}{3}\) i.e., the reciprocal of \(\frac{3}{7}\) on both sides
So,
\(\frac{3}{7}\) × \(\frac{7}{3}\) × n = 27 × \(\frac{7}{3}\)
n = \(\frac{27 × 7}{3}\)
n = 9 × 7
n = 63
Hence, from the above,
We can conclude that
The value of n for the given equation is: 63

Concepts and Skills Review

Lesson 4.1 Understand Equations and Solutions

Quick Review
The solution of an equation makes the equation true. Substitute each of the given values into the equation for the variable to determine which value, if any, is a solution of the equation.

Example
Which value of x is a solution of the equation?
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 114

Practice
Tell which value of the variable, if any, is a solution of the equation.
Question 1.
d + 9 = 25
d = 6, 14, 16, 21
Answer:
The given equation is:
d + 9 = 25
Now,
For d = 6,
6 + 9 = 25
15 ≠ 25
For d = 14,
14 + 9 = 25
23 ≠ 25
For d = 16,
16 + 9 = 25
25 = 25
For d = 21,
21 + 9 = 25
30 ≠ 25
Hence, from the above,
We can conclude that
d = 16 is a solution of the givene quation

Question 2.
C – 8 = 25
C = 17, 28, 33, 35
Answer:
The givene quation is:
c – 8 = 25
Now,
For c = 17,
17 – 8 = 25
9 ≠ 25
For c = 28,
28 – 8 = 25
20 ≠ 25
For c = 33,
33 – 8 = 25
25 = 25
For c = 35,
35 – 8 = 25
27 ≠ 25
Hence, from the above,
We can conclude that
c = 33 is a solution of the given equation

Question 3.
2y = 30
y = 10, 12, 24, 36
Answer:
The given equation is:
2y = 30
Now,
Now,
For y = 10,
2 (10) = 30
20 ≠ 30
For y = 12,
2 (12) = 30
24 ≠30
For y = 24,
2 (24) = 30
48 ≠ 30
For y = 36,
2 (36) = 30
72 ≠ 30
Hence, from the above,
We can conclude that
The given equation does not have any solution from the given values of y

Question 4.
150 ÷ h = 50
h = 2, 3, 4, 5
Answer:
The given equation is:
150 ÷ h = 50
Now,
For h = 2,
150 ÷ 2 = 50
75 ≠ 50
For h = 3,
150 ÷ 3 = 50
50 = 50
For h = 4,
150 ÷ 4 = 50
37.5 ≠ 50
For h = 5,
150 ÷ 5 = 50
30 ≠ 50
Hence, from the above,
We can conclude that
h = 3 is a solution of the given equation

Question 5.
f – 13.2 = 28.9
f= 38.7, 42.2, 45.8, 51.4
Answer:
The given equation is:
f – 13.2 = 28.9
Now,
For f = 38.7,
38.7 – 13.2 = 28.9
25.5 ≠ 28.9
For f = 42.2,
42.2 – 13.2 = 28.9
29 ≠ 28.9
For f = 45.8,
45.8 – 13.2 = 28.9
32.6 ≠ 28.9
For f = 51.4,
51.4 – 13.2 = 28.9
38.2 ≠ 28.9
Hence, from the above,
We can conclude that
There are solutions for the given equation from the given values of f

Lesson 4.2 Apply Properties of Equality

Quick Review
The properties of equality allow you to apply the same operation with the same amount to both sides of an equation.

Example
The properties of equality are illustrated in the table.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 115

Practice
Question 1.
If 6+2 = 8, does 6 + 2 + 3 = 8+ 3? Why or why not?
Answer:
The given equations are:
6 + 2 = 8
6 + 2 + 3 = 8 + 3
Now,
According to “Addition Property of Equality”,
Add the same amount of number on both sides to make the equation balanced
So,
From the given equation,
We can observe that 3 is added on both sides
Hence, from the above,
We can conclude that
The given equations are the same by using the Addition Property of Equality

Question 2.
If 8 – 1 = 7, does 8 – 1 – 2 = 7 – 3? Why or why not?
Answer:
The given equations are:
8 – 1 = 7
8- 1 – 2 = 7 – 3
Now,
According to “Subtraction Property of Equality”,
Subtract the same amount of number from both sides to make the equation balanced
So,
From the given equation,
We can observe that
2 is subtracted from one side and 3 is subtracted from other side
Hence, from the above,
We can conclude that
The given equations are not the same by using the Subtraction Property of Equality

Question 3.
If 4 + 6 = 10, does (4 + 6) × 3 = 10 × 3? Why or why not?
Answer:
The given equations are:
4 + 6 = 10
(4 + 6) × 3 = 10 × 3
Now,
According to “Multiplication Property of Equality”,
Multiply the same amount of number on both sides to make the equation balanced
So,
From the given equation,
We can observe that 3 is multiplied on both sides
Hence, from the above,
We can conclude that
The given equations are the same by using the Multiplication Property of Equality

Question 4.
If 5 + 4 = 9, does (5 + 4) ÷ 3 = 9 ÷ 4? Why or why not?
Answer:
The given equations are:
5 + 4 = 9
(5 + 4) ÷ 3 = 9 ÷ 4
Now,
According to “Division Property of Equality”,
Divide the same amount of number on both sides to make the equation balanced
So,
From the given equation,
We can observe that
3 is divided on one side and 4 is divided on the other side
Hence, from the above,
We can conclude that
The given equations are not the same by using the Division Property of Equality

Lessons 4.3 AND 4.4 Write and Solve Addition, Subtraction, Multiplication, and Division Equations

Quick Review
Use the inverse relationship of addition and subtraction or multiplication and division to solve equations. To check, substitute your answer back into the original equation.

Example
23 + y = 57
23 + y – 23 = 57 – 23a
y = 34

a – 12 = 16
a – 12 + 12 = 16 + 12
a = 28

9z = 63
9z ÷ 9 = 63 ÷ 9
z = 7

c ÷ 4 = 24
c ÷ 4 × 4 = 24 × 4
c = 96

Practice
Solve for x.
Question 1.
8x = 64
Answer:
The given equation is:
8x = 64
Now,
Divide by 8 on both sides
So,
\(\frac{8x}{8}\) = \(\frac{64}{8}\)
x = 8
Hence, from the above,
We can conclude that
The value of x for the given equation is: 8

Question 2.
x + 2 = 11
Answer:
The given equation is:
x + 2 = 11
Now,
Subtract 2 on both sides
So,
x + 2 – 2 = 11 – 2
x = 9
Hence, from the above,
We can conclude that
The value of x for the given equation is: 9

Question 3.
x ÷ 20 = 120
Answer:
The given equation is:
x ÷ 20 = 120
Now,
Multiply with 20 on both sides
So,
(x ÷ 120) × 20 = 120 × 20
x = 2,400
Hence, from the above,
We can conclude that
The value of x for the given equation is: 2,400

Question 4.
x – 17 = 13
Answer:
The given equation is:
x – 17 = 13
Now,
Add 17 on both sides
So,
x – 17 + 17 = 13 + 17
x = 30
Hence, from the above,
We can conclude that
The value of x for the given equation is: 30

Question 5.
x ÷ 12 = 2
Answer:
The given equation is:
x ÷ 12 = 2
Now,
Multiply with 12 on both sides
So,
(x ÷ 12) × 12 = 2 × 12
x = 24
Hence, from the above,
We can conclude that
The value of x for the given equation is: 24

Question 6.
8 + x = 25
Answer:
The given equation is:
8 + x = 25
Now,
Subtract 8 on both sides
So,
8 + x – 8 = 25 – 8
x = 17
Hence, from the above,
We can conclude that
The value of x for the given equation is: 17

Question 7.
7x = 77
Answer:
The givene quation is:
7x = 77
Now,
Divide by 7 on both sides
So,
\(\frac{7x}{7}\) = \(\frac{77}{7}\)
x = 11
Hence, from the above,
We can conclude that
The value of x for the given equation is: 11

Question 8.
x – 236 = 450
Answer:
The given equation is:
x – 236 = 450
Now,
Add 236 on both sides
So,
x – 236 + 236 = 450 + 236
x = 686
Hence, from the above,
We can conclude that
The value of x for the given equation is: 686

Question 9.
26 = 13x
Answer:
The given equation is:
26 = 13x
Now,
Divide by 13 on both sides
So,
\(\frac{26}{13}\) = \(\frac{13x}{13}\)
2 = x
x = 2
Hence, from the above,
We can conclude that
The value of x for the given equation is: 2

Question 10.
x + 21.9 = 27.1
Answer:
The given equation is:
x + 21.9 = 27.1
Now,
Subtract 21.9 on both sides
So,
x + 21.9 – 21.9 = 27.1 – 21.9
x = 5.2
Hence, from the above,
We can conclude that
The value of x for the given equation is: 5.2

Question 11.
2,448 ÷ 48 = x
Answer:
The given equation is:
2,448 ÷ 48 = x
Now,
x = 2,448 ÷ 48
x = 51
Hence, from the above,
We can conclude that
The value of x for the given equation is: 51

Question 12.
x + 15 = 31
Answer:
The given equation is:
x + 15 = 31
Now,
Subtract with 15 on both sides
So,
x + 15 – 15 = 31 – 15
x = 16
Hence, from the above,
We can conclude that
The value of x for the given equation is: 16

Lesson 4.5 Write and Solve Equations with Rational Numbers

Quick Review
You can use inverse relationships and properties of equality to solve each equation.

Example
Solve w + 4\(\frac{1}{3}\) = 7.
Subtract 4\(\frac{1}{3}\) from both sides.
w + 4\(\frac{1}{3}\) – 4\(\frac{1}{3}\) = 7 – 4\(\frac{1}{3}\)
w = 2\(\frac{2}{3}\)

Solve \(\frac{3}{5}\)n = \(\frac{2}{3}\)
Multiply both sides by the reciprocal of \(\frac{3}{5}\).
\(\frac{5}{3} \times \frac{3}{5} n=\frac{5}{3} \times \frac{2}{3}\)
\(n=\frac{10}{9} \text { or } 1 \frac{1}{9}\)

Practice
In 1-8, solve for x.
Question 1.
x + 3\(\frac{5}{8}\) = 7\(\frac{1}{4}\)
Answer:
The given equation is:
x + 3\(\frac{5}{8}\) = 7\(\frac{1}{4}\)
Now,
x = 7\(\frac{1}{4}\) – 3\(\frac{5}{8}\)
So,

Hence, from the above,
We can conclude that
The value of x for the given equation is: 3\(\frac{5}{8}\)

Question 2.
x – \(\frac{4}{8}\) = 4\(\frac{1}{4}\)
Answer:
The given equation is:
x – \(\frac{4}{8}\) = 4\(\frac{1}{4}\)
Now,
x = 4\(\frac{1}{4}\) + \(\frac{4}{8}\)
So,

Hence, from the above,
We can conclude that
The value of x for the given equation is: 4\(\frac{3}{4}\)

Question 3.
x ÷ 15 = 8\(\frac{1}{3}\)
Answer:
The given equation is:
x ÷ 15 = 8\(\frac{1}{3}\)
Now,
x = 8\(\frac{1}{3}\) × 15
So,

Hence, from the above,
We can conclude that
The value of x for the given equation is: 125

Question 4.
\(\frac{4}{2}\)x = 6
Answer:
The given equation is:
\(\frac{4}{2}\)x = 6
Now,
x = 6 × \(\frac{2}{4}\)
x = \(\frac{6 × 2}{4}\)
x = \(\frac{12}{4}\)
x = 3
Hence, from the above,
We can conclude that
The value of x for the given equation is: 3

Question 5.
\(\frac{x}{3}\) = 9
Answer:
The given equation is:
\(\frac{x}{3}\) = 9
Now,
x = 9 × 3
x = 27
Hence, from the above,
We can conclude that
The value of x for the given equation is: 27

Question 6.
14x = 73.5
Answer:
The given equation is:
14x = 73.5
Now,
x = \(\frac{73.5}{14}\)
x = 5.25
Hence, from the above,
We can conclude that
The value of x for the given equation is: 5.25

Question 7.
12x = 19.2
Answer:
The given equation is:
12x = 19.2
Now,
x = \(\frac{19.2}{12}\)
x = 1.6
Hence, from the above,
We can conclude that
The value of x for the given equation is: 1.6

Question 8.
17.9 – x = 12.8
Answer:
The given equation is:
17.9 – x = 12.8
Now,
x = 17.9 – 12.8
x = 5.1
Hence, from the above,
We can conclude that
The value of x for the given equation is: 5.1

Question 9.
Tomas buys a bag of 5 peaches for $3.55. Write and solve an equation to find how much money, m, Tomas paid for each peach.
Answer:
It is given that
Tomas buys a bag of 5 peaches for $3.55
Now,
The amount of money Tomas paid for each peach = (The amount of money Tomas paid for 5 peaches) ÷ (The number of peaches)
= \(\frac{$3.55}{5}\)
= $0.71
Hence, from the above,
We can conclude that
The amount of money Tomas paid for each peach is: $0.71

Question 10.
Krys has $1.54 and spends $0.76. Write and solve an equation to find how much money, m, Krys has left.
Answer:
It is given that
Krys has $1.54 and spends $0.76.
Now,
Let the amount of money Krys has left be x
So,
x = (The amount of money Krys has) – (The amount of money Krys spent)
x = $1.54 – $0.76
x = $0.78
Hence, from the above,
We can conclude that
The amount of money Krys has left is: $0.78

Lesson 4.6 Understand and Write Inequalities

Quick Review
An inequality is a mathematical sentence that contains < (less than), > (greater than), < (less than or equal to), 2 (greater than or equal to), or = (not equal to).

Example
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 116

Practice
Write an inequality for each situation.
Question 1.
Up to 5 people, p, visited Mary today.
Answer:
The given situation is:
Up to 5 people, p, visited Mary today.
So,
The representation of the given situation in the form of an inequality is:
p ≤ 5
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
p ≤ 5

Question 2.
The value, v, of the hat is less than $9.
Answer:
The given situation is:
The value, v, of the hat is less than $9.
So,
The representation of the given situation in the form of an inequality is:
v < $9
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
v < $9

Question 3.
The number of guests, g, coming for dinner is not 8.
Answer:
The given situation is:
The number of guests, g, coming for dinner is not 8.
So,
The representation of the given situation in the form of an inequality is:
g ≠ 8
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
g ≠ 8

Question 4.
The distance of the race, d, is at least 6 miles.
Answer:
The given situation is:
The distance of the race, d, is at least 6 miles.
So,
The representation of the given situation in the form of an inequality is:
d ≥ 6 miles
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
d ≥ 6 miles

Question 5.
The time it takes to get to Grandma’s house, t, is longer than 2 hours.
Answer:
The given situation is:
The time it takes to get to Grandma’s house, t, is longer than 2 hours.
So,
The representation of the given situation in the form of an inequality is:
t > 2 hours
Hence, from the above,
We can conclude that
The representation of the given situation in the form of an inequality is:
t > 2 hours

Lesson 4.7 Solve Inequalities

Quick Review
To graph the solutions of an inequality on a number line, use an open circle for < or > and a closed circle for ≤ or ≥. If the values of the variable are less than the given number, shade to the left on the number line. If the values of the variable are greater than the given number, shade to the right on the number line.

Example
“Molly is less than 15 years old” is represented by the inequality x < 15. Write three ages that could represent Molly’s age.
To graph the inequality on a number line, draw an open circle at 15 and shade to the left of 15 because x is less than 15. Draw an arrow to show all numbers less than 15.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 117
There are many solutions. Molly could be 10, 12, 14, or any age less than 15 years.

Practice
Write the inequality that each graph represents.
Question 1.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 118
Answer:
The given number line is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 118
Now,
Let the solutions of the given number line be x
Now,
From the given number line,
We can observe that
There is an open circle on 10 and the list of numbers are on the left side of 10
So,
The representation of the given number line in the form of an inequality is:
x < 10
Hence, from the above,
We can conclude that
The representation of the given number line in the form of an inequality is:
x < 10

Question 2.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 119
Answer:
The given number line is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 119
Now,
Let the solutions of the given number line be x
Now,
From the given number line,
We can observe that
There is an open circle on 5 and the list of numbers are on the right side of 5
So,
The representation of the given number line in the form of an inequality is:
x > 5
Hence, from the above,
We can conclude that
The representation of the given number line in the form of an inequality is:
x > 5

Question 3.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 120
Answer:
The given number line is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 120
Now,
Let the solutions of the given number line be x
Now,
From the given number line,
We can observe that
There is a closed circle on 3 and the list of numbers are on the right side of 3
So,
The representation of the given number line in the form of an inequality is:
x ≥ 3
Hence, from the above,
We can conclude that
The representation of the given number line in the form of an inequality is:
x ≥ 3

Question 4.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 121
Answer:
The given number line is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 121
Now,
Let the solutions of the given number line be x
Now,
From the given number line,
We can observe that
There is a closed circle on 7 and the list of numbers are on the left side of 7
So,
The representation of the given number line in the form of an inequality is:
x ≤ 7
Hence, from the above,
We can conclude that
The representation of the given number line in the form of an inequality is:
x ≤ 7

Lesson 4.8 Understand Dependent and Independent Variables

Quick Review
Think about how the values of variables affect each other.
To identify the dependent variable, ask yourself which variable depends on the other.
To identify the independent variable, ask yourself which variable causes the change.

Example
The spirit squad is washing cars. The equation m=2c represents the money they make, m, for washing c cars. Identify the dependent variable and the independent variable.
The amount of money the spirit squad makes depends on the number of cars they wash. The dependent variable is m.
The number of cars washed changes the amount of money made. The independent variable is c.

Practice
Identify the dependent variable and the independent variable in each situation.
Question 1.
The distance traveled, d, and the speed, s
Answer:
The given situation is:
The distance traveled, d, and the speed, s
Now,
To identify the “Dependent variable” ask yourself which variable depends on the other
To identify the “Independent variable”, ask yourself which variable causes the change
So,
The independent variable for the given situation is: d
The dependent variable for the given situation is: s
Hence, from the above,
We can conclude that
The independent variable for the given situation is: d
The dependent variable for the given situation is: s

Question 2.
The calories, c, in a snack and the amount of the snack, a
Answer:
The given situation is:
The calories, c, in a snack and the amount of the snack, a
Now,
To identify the “Dependent variable” ask yourself which variable depends on the other
To identify the “Independent variable”, ask yourself which variable causes the change
So,
The independent variable for the given situation is: c
The dependent variable for the given situation is: a
Hence, from the above,
We can conclude that
The independent variable for the given situation is: c
The dependent variable for the given situation is: a

Question 3.
The amount of money you have spent, s, and how much money you have left, m
Answer:
The given situation is:
The amount of money you have spent, s, and how much money you have left, m
Now,
To identify the “Dependent variable” ask yourself which variable depends on the other
To identify the “Independent variable”, ask yourself which variable causes the change
So,
The independent variable for the given situation is: s
The dependent variable for the given situation is: m
Hence, from the above,
We can conclude that
The independent variable for the given situation is: s
The dependent variable for the given situation is: m

Question 4.
The number of apple slices remaining, r, and the number of apple slices eaten, e
Answer:
The given situation is:
The number of apple slices remaining, r, and the number of apple slices eaten, e
Now,
To identify the “Dependent variable” ask yourself which variable depends on the other
To identify the “Independent variable”, ask yourself which variable causes the change
So,
The independent variable for the given situation is: e
The dependent variable for the given situation is: r
Hence, from the above,
We can conclude that
The independent variable for the given situation is: e
The dependent variable for the given situation is: r

Lesson 4.9 Use Patterns to Write and Solve Equations

Quick Review
Look for patterns between two related variables to find rules and write equations.

Example
Write a rule and an equation that represents the pattern. Then complete the table.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 122
Find the rule and write an equation.
12 is 3 × 4
16 is 4 × 4
20 is 5 × 4
Rule: The value of y is 4 times the value of x.
Equation: y = 4x
Evaluate the equation for x = 6 and x = 7.
y = 4 × 6 = 24
y = 4 × 7 = 28

Practice
Question 1.
Find the pattern and then write a rule and an equation that represents the pattern. Then complete the table.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 123
Answer:
The given table is:
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 123
Now,
From the given table,
We can observe that
The relationship (or) pattern between x and y is:
y = \(\frac{x}{2}\)
Now,
For x = 16,
y = \(\frac{16}{2}\)
y = 8
For x = 20,
y = \(\frac{20}{2}\)
y = 10
So,
The completed table by using the above relationship is:

Hence, from the above,
We can conclude that
The completed table by using the above relationship is:

Question 2.
Use the equation to complete the table.
y = 6x + 1
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 124
Answer:
The given equation is:
y = 6x + 1
Now,
For x = 1,
y = 6 (1) + 1
= 7
For x = 2,
y = 6 (2) + 1
= 13
For x = 3,
y = 6 (3) + 1
= 19
For x = 4,
y = 6 (4) + 1
= 25
For x = 5,
y = 6 (5) + 1
= 31
So,
The completed table by uisng the above equation is:

Hence, from the above,
We can conclude that
The completed table by uisng the above equation is:

Lesson 4.10 Relate Tables, Graphs, and Equations

Quick Review
A table, equation, or graph can be used to analyze the relationship between dependent and independent variables. Ordered pairs that make an equation true can be used to graph the equation.

Example
Complete the table and graph to show the relationship between the variables in the equation t = s + 1.
A restaurant has a special that when you buy one sandwich you get a second sandwich for $1
Let s = price of one sandwich.
Let t = total price of two sandwiches.
Step 1
Make a table. Include at least three values.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 125

Step 2
Graph each ordered pair on a coordinate plane. Then draw a line through the points.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 126

Practice
Question 1.
The cross country team practices by jogging on the town’s streets. The average jogging rate is 6 miles per hour. One member jogged for 3.5 hours one weekend. How many miles did the team member jog?
a. Complete the table to relate the number of miles to the number of hours jogged.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 127
Answer:
It is given that
The cross country team practices by jogging on the town’s streets. The average jogging rate is 6 miles per hour. One member jogged for 3.5 hours one weekend.
So,
From the given situation,
We can observe that
The independent variable is: The number of hours the team member jogged
The dependent variable is: Number of miles the team member jogged
Now,
Let the dependent variable be y
Let the independent variable be y
So,
The relation between x and y from the given situation is:
y = 6x
Now,
The completed table by using the above equation is:

Hence, from the above,
We can conclude that
The completed table by using the above equation is:

b. Graph the ordered pairs on the coordinate plane.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 128
Answer:
The given table is:

Now,
From the given table,
We can observe that
The ordered pairs to draw in the coordinate plane is:
(1, 6), (2, 12), (3, 18)
Hence,
The representtaion of the given ordered pairs in the coordinate plane is:

c. Write an equation that describes the relationship. Then solve the problem.
Answer:
From part (a),
We know that,
The equation that describes the given situation is:
y = 6x
So,
The number of miles did the team member jog is:
y = 6x
= 6 (3.5)
= 21 miles
Hence, from the above,
We can conclude that
The number of miles did the team member jog is: 21 miles

Question 2.
Alex is making puppets for a show. He bought all the string needed for $125. It costs $18 for the remaining materials to make each puppet. What is the total cost to make 50 puppets?
Answer:
It is given that
Alex is making puppets for a show. He bought all the string needed for $125. It costs $18 for the remaining materials to make each puppet
So,
The total cost of the materials to make each puppet = $125 + $18
= $143
So,
The total cost to make 50 puppets = 50 × $143
= $7,150
Hence, from the above,
We can conclude that
The total cost to make 50 puppets = 50 × $143
= $7,150

Topic 4 Fluency Practice

Riddle Rearranging
Find each quotient. Then arrange the answers in order from least to greatest. The letters will spell out the answer to the riddle below.
I can… divide multi-digit numbers.
Envision Math Common Core Grade 6 Answers Topic 4 Represent And Solve Equations And Inequalities 129

enVision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100

enVision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100

Go through the enVision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 regularly and improve your accuracy in solving questions.

enVision Math Common Core 3rd Grade Answers Key Topic 5 Fluently Multiply and Divide within 100

Essential Question:
What are strategies to solve multiplication and division facts?
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 1

enVision STEM Project: Weather Information
Do Research Use the Internet or other sources to find the weather in different places on Earth. Find the weather at different times of day. Write down the temperature for each place. Also write down any conditions such as rain or snow.

Journal: Write a Report Include what you found. Also in your report:

  • Tell how many places you checked.
  • Tell how many times you checked the weather in one day.
  • Write a multiplication or division story using your information. Then find an answer for your story.

Review What You Know

Vocabulary
Choose the best term from the box. Write it on the blank.

  • dividend
  • divisor
  • product
  • quotient
  • factor

Question 1.
The answer to a division problem is the _________.
Answer:
The answer to a division problem is the ___quotient___.

Explanation:
The answer to a division problem is the quotient.

 

 

Question 2.
A ________ is the answer to a multiplication problem.
Answer:
A _product_______ is the answer to a multiplication problem.

Explanation:
A product is the answer to a multiplication problem.

 

Question 3.
The _________ is the number in a division problem that is divided into equal groups.
Answer:
The __dividend_______ is the number in a division problem that is divided into equal groups.

Explanation:
The dividend is the number in a division problem that is divided into equal groups.

 

 

Question 4.
Multiply a factor by a ___________ to solve a multiplication problem.
Answer:
Multiply a factor by a ____factor_______ to solve a multiplication problem.

Explanation:
Multiply a factor by a factor to solve a multiplication problem.

 

Multiplication
Question 5.
6 × 2 = _______
Answer:
6 × 2 = ___12____.

Explanation:
6 × 2 = 12.

 

Question 6.
5 × 1 = _________
Answer:
5 × 1 = ___5______.

Explanation:
5 × 1 = 5.

 

Question 7.
4 × 10 = ________
Answer:
4 × 10 = __40______.

Explanation:
4 × 10 = 40.

 

Question 8.
7 × 5 = _______
Answer:
7 × 5 = ___35____.

Explanation:
7 × 5 = 35.

 

Question 9.
4 × 4 = _______
Answer:
4 × 4 = __16_____.

Explanation:
4 × 4 = 16.

 

Question 10.
9 × 3 = _______
Answer:
9 × 3 = __27_____.

Explanation:
9 × 3 = 27.

 

 

Question 11.
The oranges in a store are in 7 rows and 8 columns. How many oranges are there?
Answer:
Total number of oranges  in all = 56.

Explanation:
Number of rows of oranges = 7.
Number of columns of oranges = 8.
Total number of oranges  in all = Number of rows of oranges  × Number of columns of oranges
= 7 × 8
= 56.

 

 

Division
Question 12.
60 ÷ 6 = ______
Answer:
60 ÷ 6 = _10_____.

Explanation:
60 ÷ 6 = 10.

 

Question 13.
25 ÷ 5 = _______
Answer:
25 ÷ 5 = __5_____.

Explanation:
25 ÷ 5 = 5.

 

Question 14.
12 ÷ 3 = _______
Answer:
12 ÷ 3 = ___4____.

Explanation:
12 ÷ 3 = 4.

 

Question 15.
30 ÷ 6 = _______
Answer:
30 ÷ 6 = __6_____.

Explanation:
30 ÷ 6 = 6.

 

Question 16.
14 ÷ 2 = _______
Answer:
14 ÷ 2 = ___7____.

Explanation:
14 ÷ 2 = 7.

 

Question 17.
9 ÷ 3 = _______
Answer:
9 ÷ 3 = ___3____.

Explanation:
9 ÷ 3 = 3.

 

Question 18.
If 28 stamps are arranged into an array with 4 columns, how many rows are there?
Answer:
Number of rows of stamps arranged in array = 7.

Explanation:
Total number of stamps arranged in array = 28.
Number of columns of stamps arranged in array = 4.
Number of rows of stamps arranged in array = Total number of stamps arranged in array ÷ Number of columns of stamps arranged in array
= 28 ÷ 4
= 7.

 

The Distributive Property
Question 19.
Explain how to use 2s facts to find 4 × 9.
Answer:
4 × 9 = (2 × 9) + (2 × 9) = 36.

Explanation:
4 × 9 = (2 × 9) + (2 × 9)
4 × 9 = 18 + 18
4 × 9 = 36.

 

Pick a Project

PROJECT 5A
How many books are in a library?
Project: Design a Library
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 2
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-5-Fluently-Multiply-and-Divide-within-100-Pick a Project-PROJECT 5A

Explanation:
The word “library” seems to be used in so many different aspects now, from the brick-and-mortar public library to the digital library. Public libraries—and indeed, all libraries–are changing and dynamic places where librarians help people find the best source of information whether it’s a  book,  a web site, or database entry.

 

 

 

PROJECT 5B
How would you use number cubes?
Project: Make a Multiplication Game
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 3

Answer:
Place each token on the “Start” space. Have one student roll the dice, then move his token the same number of places he rolled. Have the student multiply the number on the game space with the number shown on the dice. If the student answers the multiplication problem correctly, he earns a point. If he answers incorrectly, the next player can steal the point by answering the problem.

Explanation:
When you multiply a whole number (not a fraction) by itself, and then by itself again the result is a cube number.
For example 3 x 3 x 3 = 27.

 

 

 

PROJECT 5C
Would you rather ride a bike or a “trike”?
Project: Create a Bike Chart
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 4

Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-5-Fluently-Multiply-and-Divide-within-100-Pick a Project-PROJECT 5C

Explanation:
Cycle sport is competitive physical activity using bicycles. There are several categories of bicycle racing including road bicycle racing, cyclo-cross, mountain bike racing, track cycling, BMX, and cycle speedway.

 

 

 

3-ACT MATH PREVIEW

Math Modeling
The Cheese Sticks
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 5

Lesson 5.1 Patterns for Multiplication Facts

Solve & Share
Max found 6 × 8 = 48. He noticed that (6 × 4) + (6 × 4) also equals 48. Use the multiplication table to find two other facts whose sum is 48. Use facts that have a 6 or 8 as a factor. What pattern do you see?
I can … use structure and properties to explain patterns for multiplication facts.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 6

Look Back! How can a multiplication table help you find products that equal 48 when added together?
Answer:
Multiplication table can help in finding products that are equal 48 when added together are by finding the factors of 48 and later adding them, which is easy.

Explanation:
Multiplication table helps in easy way to find factors required for the given number.

 

Essential Question
How Can You Explain Patterns on in the Multiplication Chart?
Answer:
Factors of 48:
2 × 24 = 48.
3 × 16 = 48.
4 × 12 = 48.
6 × 8 = 48.

Explanation:
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 6
?? + ?? = 48.
Factors of 48:
2 × 24 = 48.
3 × 16 = 48.
4 × 12 = 48.
6 × 8 = 48.

 

 

Visual Learning Bridge
Yolanda noticed that 4 × 6 is double 2 × 6. How can you explain this?
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 7

4 is the double of 2.
So, 4 × 6 is double 2× 6.
You can use the Distributive Property of Multiplication to explain.
4×6= (2 × 6) + (2 × 6)
4 × 6 = 12 + 12
4 × 6= 24

Look at the highlighted rows.
The product of any number multiplied by 4 will be double the product of that number multiplied by 2.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 8

Convince Me! Look for Relationships Look at the highlighted rows of numbers multiplied by 2 or 4. What pattern do you see across the rows?
Answer:
The highlighted rows of numbers multiplied by 2 or 4 shows they are the multiples of the 2 and 4 numbers.

Explanation:
The highlighted rows of numbers multiplied by 2 or 4 shows the pattern of difference of 2 and 4 between them. They are the multiples of the 2 and 4 numbers.

 

 

Guided Practice
Do You Understand?
Question 1.
How are 3 × 7 and 6 × 7 related?
Answer:
6 × 7 is double of 3 × 7.

Explanation:
6 × 7 = (3 × 7) + (3 × 7)
6 × 7 = 21 + 21
6 × 7 = 42.

 

Question 2.
In the table on the previous page, is the pattern that Yolanda found also true for factors that are multiplied by 3 and 6? Explain.
Answer:
No, in the table on the previous page, is the pattern that Yolanda found also true for factors that are multiplied by 3 and 6.

Explanation:
No, in the table on the previous page, is the pattern that Yolanda found also true for factors that are multiplied by 3 and 6. They are the multiples of 2 and 4 not 3 and 6.

 

 

Do You Know How?
In 3 and 4, use the multiplication table shown below.
Question 3.
What pattern do you see in the columns and rows that have 0 as a factor?
Answer:
The pattern seen in the columns and rows that have 0 as a factor is crossed.

Explanation:
The pattern seen in the columns and rows that have 0 as a factor is crossed. Zero multiplied by any factor, the result is zero.

 

Question 4.
Use a property to explain why this pattern is true.
Answer:
8 × 0 = (4 × 0) + (4 × 0)
8 × 0 = 0 + 0
8 × 0 = 0.

Explanation:
Distributive property can be used.
8 × 0 = (4 × 0) + (4 × 0)
8 × 0 = 0 + 0
8 × 0 = 0.

 

Independent Practice
In 5-8, use the multiplication table shown at the right.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 9
Question 5.
Look at the shaded products. What pattern do you see?
Answer:
Shaded products shows the pattern of 8 difference from 0 to 8, 8 to 14, later 4 difference from 14 to18, later 2 difference from18 to 20, and reverse from 20 to 0.

Explanation:
Shaded products shows the pattern of 8 difference from 0 to 8, 8 to 14, later 4 difference from 14 to18, later 2 difference from18 to 20, and reverse from 20 to 0. Its not content change of pattern noticed.

 

Question 6.
Write the equation for each shaded product.
Answer:
(0 × 0) + (0 × 0) = 0 + 0 = 0.
(2 × 2) + (2 × 2) = 4 + 4 = 8.
(2 × 4) + (2 × 3) = 8 + 6 = 14.
(2 × 5) + (2 × 4) = 10 + 8 =18.
(2 × 5) + (2 × 5) = 10 + 10 = 20

Explanation:
shaded product:
(0 × 0) + (0 × 0) = 0 + 0 = 0.
(2 × 2) + (2 × 2) = 4 + 4 = 8.
(2 × 4) + (2 × 3) = 8 + 6 = 14.
(2 × 5) + (2 × 4) = 10 + 8 =18.
(2 × 5) + (2 × 5) = 10 + 10 = 20

 

Question 7.
Look at the factors you wrote. Use a property to explain why the pattern for the products is true.
Answer:
0 = (0 × 0) + (0 × 0) = 0 + 0
8 = (2 × 4) = (2 × 2) + (2 × 2) = 4 + 4.
14 = (2 × 7) = (2 × 4) + (2 × 3) = 8 + 6.
18 = (2 × 9) = (2 × 5) + (2 × 4) = 10 + 8.
20 = (2 × 10) = (2 × 5) + (2 × 5) = 10 + 10.

Explanation:
Distributive property:
0 = (0 × 0) + (0 × 0) = 0 + 0
8 = (2 × 4) = (2 × 2) + (2 × 2) = 4 + 4.
14 = (2 × 7) = (2 × 4) + (2 × 3) = 8 + 6.
18 = (2 × 9) = (2 × 5) + (2 × 4) = 10 + 8.
20 = (2 × 10) = (2 × 5) + (2 × 5) = 10 + 10.

 

 

Question 8.
Shade a line in the multiplication table to show how this pattern is true for other products.
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Pick a Project-Visual Learning Bridge-Guided Practice-Independent Practice-8

Explanation:
shaded numbers are 8,14,16,20. The numbers are shaded.
8 = 2 × 4.
14 = 2 × 7.
18 = 2 × 9.

 

 

Problem Solving
Question 9.
enVision® STEM How many arms do 9 starfish have if …
a. each starfish has 6 arms? Write a multiplication equation to solve.

Answer:
Total number of arms 9 star fishes have = Number of arms each star fish has × Number of star fishes
= 6 × 9
= 54.

Explanation:
Number of arms each star fish has = 6.
Number of star fishes = 9.
Total number of arms 9 star fishes have = Number of arms each star fish has × Number of star fishes
= 6 × 9
= 54.

 

 

b. each starfish has 7 arms? Write a multiplication equation to solve.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 10

Answer:
Total number of arms 9 star fishes have = Number of arms each star fish has × Number of star fishes
= 7 × 9
= 63.

Explanation:
Number of arms each star fish has = 7.
Number of star fishes = 9.
Total number of arms 9 star fishes have = Number of arms each star fish has × Number of star fishes
= 7 × 9
= 63.

 

 

Question 10.
Higher Order Thinking Karen found a pattern on the multiplication table. What pattern did she find? Explain why it is true.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 11

Answer:
The pattern she found is the difference of 6 in between every number highlighted on the multiplication table.

Explanation:
The pattern she found is the multiples of 6 number on the multiplication table.

 

 

Question 11.
Write the fact family for each fact: 2 × 0, 2 × 1, 2 × 2, 2 × 3, 2 × 4, 2 × 5, 2 × 6, 2 × 7, 2 × 8, 2 × 9, and 2 × 10.
Answer:
2 × 0 = 0. => 0 × 2 = 0.
2 × 1 = 2. => 1 × 2 = 2.
2 × 2 = 4. => 2 × 2 = 4.
2 × 3 = 6. => 3 × 2 = 6.
2 × 4 = 8. => 4 × 2 = 8.
2 × 5 = 10. => 5 × 2 = 10.
2 × 6 = 12. => 6 × 2 = 12.
2 × 7 = 14. => 7 × 2 = 14.
2 × 8 = 16. => 8 × 2 = 16.
2 × 9 = 18. => 9 × 2 = 18.
2 × 10 = 20. => 2 × 2 = 4.

Explanation:
Fact family:
2 × 0 = 0. => 0 × 2 = 0.
2 × 1 = 2. => 1 × 2 = 2.
2 × 2 = 4. => 2 × 2 = 4.
2 × 3 = 6. => 3 × 2 = 6.
2 × 4 = 8. => 4 × 2 = 8.
2 × 5 = 10. => 5 × 2 = 10.
2 × 6 = 12. => 6 × 2 = 12.
2 × 7 = 14. => 7 × 2 = 14.
2 × 8 = 16. => 8 × 2 = 16.
2 × 9 = 18. => 9 × 2 = 18.
2 × 10 = 20. => 2 × 2 = 4.

 

 

Question 12.
Be Precise Describe a pattern you see in the 9s row of the multiplication table.
Answer:
The pattern noticed is they are the multiples of 9 number in the 9s row of the multiplication table.

Explanation:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Pick a Project-Visual Learning Bridge-Guided Practice-Independent Practice-8

 

Assessment Practice
Question 13.
One row and 1 column are shaded in the multiplication table below.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 12
What pattern and property of operations is shown in the shaded row and column?
A. The products are all equal to the factor that is multiplied by 1; The Identity Property of Multiplication
B. The products in the shaded row are equivalent to the products in the shaded column; The Zero Property of Multiplication
C. Each product is 1 greater than the product before; The Distributive Property
D. There are no patterns or properties.

Answer:
A. The products are all equal to the factor that is multiplied by 1; The Identity Property of Multiplication is the pattern and property of operations is shown in the shaded row and column:

Explanation:
The pattern and property of operations is shown in the shaded row and column:
A. The products are all equal to the factor that is multiplied by 1; The Identity Property of Multiplication

 

Lesson 5.2 Use a Table to Multiply and Divide

Solve & Share
Find 18 ÷ 3 any way you choose.
I can … use reasoning and the relationship between multiplication and division to find basic facts.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 13
Look Back! Describe another way you can find 18 ÷ 3.
Answer:
Another way:
18 ÷ 6 = 3.
6 × 3 = 18.

Explanation:
Another way:
18 ÷ 3 = 6.
18 ÷ 6 = 3.
6 × 3 = 18.

 

Essential Question
How Can You Use a Multiplication to Table to Solve Division Problems?
Answer:
We can use a Multiplication to Table to Solve Division Problems by using the factors.
For Example:
2 × 5 = 10.
10 ÷ 2 = 5.

Explanation:
We use the multiplication tables of the smaller. Number to get the answer to a division problem quickly. For Example:
2 × 5 = 10.
10 ÷ 2 = 5.

 

Visual Learning Bridge
Write a missing factor equation and then use the multiplication table to find 15 ÷ 3.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 14
15 ÷ 3= ?
3 × ? = 15
3 times what number equals 15?

Step 1 You know one factor is 3. Find the 3 in the first column of this multiplication table.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 15
Step 2 You know the product is 15. Follow the row the 3 is in until you come to 15.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 16
Step 3 Look straight up to the top of that column of the table. The number on the top of the column is 5. The missing factor is 5.
3 × 5 = 15
15 ÷ 3 = 5
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 17

Convince Me! Reasoning Write a missing factor equation and use the multiplication table above to solve each division problem.
6 ÷ 3 = ?
12 ÷ 3 = ?
9 ÷ 3 = ?
Answer:
6 ÷ 3 = 2.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.2 Use a Table to Multiply and Divide-Visual Learning Bridge-
12 ÷ 3 = 4.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.2 Use a Table to Multiply and Divide-Visual Learning Bridge
9 ÷ 3 = 3.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.2 Use a Table to Multiply and Divide-Visual Learning Bridge..

Explanation:
6 ÷ 3 = ?
=> 6 ÷ 3 = 2.
12 ÷ 3 = ?
=> 12 ÷ 3 = 4.
9 ÷ 3 = ?
=> 9 ÷ 3 = 3.

 

 

Another Example!
How can you find the missing numbers in the table?
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 18

 

 

Guided Practice
Do You Understand?
Question 1.
Explain how to use a multiplication table to solve a missing factor equation.
Answer:
Way you can find the missing factor in a multiplication:
Equation is using a repeated addition let’s take a look at this multiplication equation four times something equals 24.
24 ÷ 4 = ??
=> 24 ÷ 4 = 6.

Explanation:
Equation is using a repeated addition let’s take a look at this multiplication equation four times something equals 24.
24 ÷ 4 = ??
=> 24 ÷ 4 = 6.

 

 

Do You Know How?
In 2-5, find the value that makes the equation correct. Use a multiplication table to help.
Question 2.
24 ÷ 6 = _______
24 = 6 × _______
Answer:
24 ÷ 6 = ___4____.
24 = 6 × ___4____.

Explanation:
24 ÷ 6 = 4.
24 = 6 × 4.

 

Question 3.
63 ÷ 9 = _______
9 × _____ = 63
Answer:
63 ÷ 9 = __7_____.
9 × _7____ = 63.

Explanation:
63 ÷ 9 = 7.
9 × 7 = 63.

 

Question 4.
25 ÷ 5 = ______
5 × ______ = 25
Answer:
25 ÷ 5 = __5____.
5 × __5____ = 25.

Explanation:
25 ÷ 5 = 5.
5 × 5 = 25.

 

Question 5.
42 ÷ 7 = _______
42 = 7 × _______
Answer:
42 ÷ 7 = ___6____.
42 = 7 × __6_____.

Explanation:
42 ÷ 7 = 6.
42 = 7 × 6.

 

 

Independent Practice
In 6 and 7, find the missing factors and products.
Question 6.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 19
Answer:
5 × ? = 25.
6 × ? = 48.
6 × ? = 42.
? × 5 = 45.

Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.2 Use a Table to Multiply and Divide-Guided Practice-Independent Practice-6

Explanation:
5 × ? = 25.
=> 5 × 5 = 25.
6 × ? = 48.
=> 6 × 8 = 48.
6 × ? = 42.
=> 6 × 7 = 42.
? × 5 = 45.
=> 9 × 5 = 45.

 

 

 

Question 7.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 20
Answer:
4 × ? = 12.
? × 9 = 54.
3 × ? = 6.
? × 9 = 72.

Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.2 Use a Table to Multiply and Divide-Guided Practice-Independent Practice-7

Explanation:
4 × ? = 12.
=> 4 × 3 = 12.
? × 9 = 54.
=> 6 × 9 = 54.
3 × ? = 6.
=> 3 × 2 = 6.
? × 9 = 72.
=> 8 × 9 = 72.

 

 

 

Problem Solving

Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 21
Question 8.
Some members of the Bird Club used a tally chart to record how many different birds they each saw one day. Fill in the blanks below to make the sentence correct. _________ saw 4 more birds than ________.
Answer:
__Miss. Simmons_______ saw 4 more birds than ___Ms. Chester_____.

Explanation:
Number of birds Ms. Chester saw = 7.
Number of birds Mr. Dobbs saw = 4.
Number of birds Miss. Simmons saw = 11.
Number of birds Mr. Molina saw = 0.
Difference:
Number of birds Miss. Simmons saw – Number of birds Ms. Chester saw
= 11 – 7
= 4.

 

 

Question 9.
Complete the chart to show that Mr. Molina saw 5 fewer birds than Mr. Dobbs and Miss Simmons combined.
Answer:
Mr. Molina saw 15 fewer birds than Mr. Dobbs and Miss Simmons combined.

Explanation:
Number of birds Ms. Chester saw = 7.
Number of birds Mr. Dobbs saw = 4.
Number of birds Miss. Simmons saw = 11.
Number of birds Mr. Molina saw = 0.
Number of birds Mr. Dobbs and Miss Simmons combined = Number of birds Miss. Simmons saw + Number of birds Mr. Dobbs saw
= 11 + 4
= 15.

 

 

Question 10.
Critique Reasoning Bill used a multiplication table to find the value of 12 = 6. His answer was 3. Do you agree? Why or why not?

Answer:
Bill is wrong because 12 = 6 when the answer is 2 not 3.
=> 12 ÷ 2 = 6.

Explanation:
12 = 6.
=> 12 ÷ 2 = 6.

 

Question 11.
Write the fact family for each fact: 5 × 0, 5 × 1, 5 × 2, 5 × 3, 5 × 4, 5 × 5, 5 × 6, 5 × 7, 5 × 8, 5 × 9, and 5 × 10.
Answer:
Fact family:
5 × 0 = 0.
= 0 × 5 = 0.
5 × 1 = 5.
=> 1 × 5 = 5.
5 × 2 = 10.
=> 2 × 5 = 10.
5 × 3 = 15.
=> 3 × 5 = 15.
5 × 4 = 20.
=> 4 × 5 = 20.
5 × 5 = 25.
=> 5 × 5 = 25.
5 × 6 = 30.
=> 6 × 5 = 30.
5 × 7 = 35.
=> 7 × 5 = 35.
5 × 8 = 40.
=> 8 × 5 = 40.
5 × 9 = 45.
=> 9 × 5 = 45.
5 × 10 = 50.
=> 10 × 5 = 50.

Explanation:
5 × 0 = 0.
= 0 × 5 = 0.
5 × 1 = 5.
=> 1 × 5 = 5.
5 × 2 = 10.
=> 2 × 5 = 10.
5 × 3 = 15.
=> 3 × 5 = 15.
5 × 4 = 20.
=> 4 × 5 = 20.
5 × 5 = 25.
=> 5 × 5 = 25.
5 × 6 = 30.
=> 6 × 5 = 30.
5 × 7 = 35.
=> 7 × 5 = 35.
5 × 8 = 40.
=> 8 × 5 = 40.
5 × 9 = 45.
=> 9 × 5 = 45.
5 × 10 = 50.
=> 10 × 5 = 50.

 

 

Question 12.
Higher Order Thinking Brit uses a multiplication table to multiply 2 different factors. She notices that the product is in the same column as the number 35. What is one of the factors in Brit’s multiplication problem? Explain your answer.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 22

Answer:
One of the factors in Brit’s multiplication problem:
7 × 5 = 35.

Explanation:
One of the factors in Brit’s multiplication problem:
7 × 5 = 35.

 

Assessment Practice
Question 13.
Use the relationship between multiplication and division to find the missing number in 21 ÷ ☐ = 7.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 23
A. 1
B. 3
C. 7
D. 9

Answer:
21 ÷ 3 = 7.
B. 3

Explanation:
21 ÷ ☐ = 7.
=> 21 ÷ ?? = 7.
=> 21 ÷ 3 = 7.

 

 

Lesson 5.3 Use Strategies to Multiply

Solve & Share
Alfredo has 6 bags of oranges. Each bag contains 7 oranges. How many oranges does Alfredo have? Show 2 ways to find this answer.
I can … use different strategies to solve multiplication problems.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 24

Look Back! How do strategies such as skip counting, using known facts, and making arrays help you solve multiplication facts?
Answer:
Strategies such as skip counting, using known facts, and making arrays helps solve multiplication facts by easy calculations and easy in finding the solution for the problem.

Explanation:
Strategies such as skip counting, using known facts, and making arrays helps solve multiplication facts by easy calculations and easy in finding the solution for the problem.

 

Essential Question
How Do You Use Strategies Question to Multiply?
Answer:
Strategies help us use what we do know  (easier multiplication facts or addition facts) to solve any problem.

Explanation:
Strategies help us use what we do know  (easier multiplication facts or addition facts) to understand the problem and solve the problem.

 

Visual Learning Bridge
A scientist on a boat is studying hammerhead sharks. The length of 6 hammerhead sharks lined up nose to tail without gaps is equal to the length of the boat. How long is the boat?
Drawings, skip counting, tools, and properties of operations are strategies you can use to multiply equal groups.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 25

One Way
Use a bar diagram to find 6 × 5.
6 × 5 means 6 groups of 5. Skip count by 5s.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 26
So, 6 × 5= 30.
The boat is 30 yards long.

Another Way
Use counters and properties to find 6 × 5.
The Distributive Property says you can break the problem into smaller parts. Use 2s facts and 4s facts to help.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 27
Then add the two products: 10 + 20 = 30.
The boat is 30 yards long.

Convince Me! Use Structure How can knowing the product of 5 × 6 help you solve 6 × 5?

Answer:
5 × 6 = 30.
6 × 5 = 30.
Both the products value is same.

Explanation:
5 × 6 = (2 × 6) + (3 × 6) = 12 + 18 =  30.
6 × 5 = (4 × 5) + ( 2 × 5) = 20 + 10 = 30.

 

 

Guided Practice
Do You Understand?
Question 1.
What two known facts can you use to find 3 × 5?
Answer:
3 × 5 = (1 × 5) + (2 × 5) = 5 + 10 = 15.

Explanation:
3 × 5 = (1 × 5) + (2 × 5)
3 × 5 = 5 + 10
3 × 5 = 15.

 

Question 2.
How could knowing 7 × 5 = 35 help you find 9 × 5?
Answer:
9 × 5 = (7 × 5) + (2 × 5) = 35 + 10 = 45.

Explanation:
7 × 5 = 35 helps to find 9 × 5.
9 × 5 = (7 × 5) + (2 × 5)
9 × 5 = 35 + 10
9 × 5 = 45.

 

 

Do You Know How?
In 3-8, multiply.
Question 3.
6 × 4 = _______
Answer:
6 × 4 = __24._____

Explanation:
6 × 4 = (3 × 4) + (3 × 4)
6 × 4 = 12 + 12
6 × 4 = 24.

 

Question 4.
______ = 4 × 5
Answer:
__20____ = 4 × 5.

Explanation:
4 × 5 = (2 × 5) + (2 × 5)
4 × 5 = 10 + 10
4 × 5 = 20.

 

Question 5.
9 × 3 = _______
Answer:
9 × 3 = __27_____.

Explanation:
9 × 3 = (6 ×3) + (3 × 3)
9 × 3 = 18 + 9
9 × 3 = 27.

 

Question 6.
3 × 2 = ________
Answer:
3 × 2 = ____6____.

Explanation:
3 × 2 = (1 × 2) + (2× 2)
3 × 2 = 2 + 4
3 × 2 = 6.

 

Question 7.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 28
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Guided Practice-7

Explanation:
1 × 4 = 4.

 

Question 8.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 29
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Guided Practice-8

Explanation:
9 × 8 = (5 × 8) + (4 × 8)
9 × 8 = 40 + 32
9 × 8 = 72.

 

 

Independent Practice
In 9-25, use strategies to find the product.
Question 9.
_____ = 5 × 5
Answer:
__25___ = 5 × 5.

Explanation:
5 × 5 = (3 × 5) + (2 × 5)
5 × 5 = 15 + 10
5 × 5 = 25.

 

Question 10.
9 × 2 = _______
Answer:
9 × 2 = ___18____.

Explanation:
9 × 2 = (7 × 2) + (2 × 2)
9 × 2 = 14 + 4
9 × 2 = 18.

 

Question 11.
______ = 5 × 9
Answer:
__45____ = 5 × 9.

Explanation:
5 × 9 = (3 × 9) + (2 × 9)
5 × 9 = 27 + 18
5 × 9 = 45.

 

Question 12.
8 × 7 = _______
Answer:
8 × 7 = __56_____.

Explanation:
8 × 7 = (4 × 7) + (4 × 7)
8 × 7 = 28 + 28
8 × 7 = 56.

 

Question 13.
_____ = 3 × 6

Answer:
__18___ = 3 × 6.

Explanation:
3 × 6 = (1 × 6) + (2 × 6)
3 × 6 = 6 + 12
3 × 6 = 18.

 

Question 14.
8 × 4 = _______
Answer:
8 × 4 = ___32____.

Explanation:
8 × 4 = (4 × 4) + (4 × 4)
8 × 4 = 16 + 16
8 × 4 = 32.

 

Question 15.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 30
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Independent Practice-15

Explanation:
10 × 4 = (5 × 4) + (5 × 4)
10 × 4 = 20 + 20
10 × 4 = 40.

 

Question 16.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 31
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Independent Practice-16

Explanation:
7 × 6 = ( 4 × 6) + ( 3 × 6)
7 × 6 = 24 + 18
7 × 6 = 42.

 

Question 17.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 32
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Independent Practice-17

Explanation:
6 × 5 = (3 × 5) + (3 × 5)
6 × 5 = 15 + 15
6 × 5 = 30.

 

Question 18.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 33
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Independent Practice-18

Explanation:
2 × 8 = (1 × 8) + (1 × 8)
2 × 8 = 8 + 8
2 × 8 = 16.

 

Question 19.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 34
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Independent Practice-19

Explanation:
9 × 0 = (5 × 0) + (4 × 0)
9 × 0 = 0 + 0
9 × 0 = 0.

 

Question 20.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 35
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Independent Practice-20

Explanation:
10 × 6 = (5 × 6) + (5 × 6)
10 × 6 = 30 + 30
10 × 6 = 60.

 

Question 21.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 36
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Independent Practice-21

Explanation:
4 × 9 = (2 × 9) + (2 × 9)
4 × 9 = 18 + 18
4 × 9 = 6.

 

Question 22.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 37
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.3 Use Strategies to Multiply-Visual Learning Bridge-Independent Practice-22

Explanation:
9 × 7 = ( 6 × 7) + ( 3 × 7)
9 × 7 = 42 + 21
9 × 7 = 63.

 

Question 23.
What is 4 × 6? _______
Answer:
4 × 6 = 24.

Explanation:
4 × 6 = (2 × 6) + (2 × 6)
4 × 6 = 12 + 12
4 × 6 = 24.

 

Question 24.
What is 5 × 8?_______.
Answer:
5 × 8 = 40.

Explanation:
5 × 8 = (3 × 8) + (2 × 8)
5 × 8 = 24 + 16
5 × 8 = 40.

 

Question 25.
What is 10 × 1? _________
Answer:
10 × 1 = 10.

Explanation:
10 × 1 = (6 × 1) + ( 4 × 1)
10 × 1 = 6 + 4
10 × 1 = 10.

 

 

Problem Solving
In 26 and 27, use the pictures below.
Question 26.
Dr. Marks is studying 3 blacktip sharks and 4 tiger sharks. What is the total length of the 7 sharks? Show your strategy.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 38

Answer:
Total length of the 7 sharks = 22 square yards long.

Explanation:
Number of blacktip sharks Dr. Marks is studying = 3.
Number of tiger sharks Dr. Marks is studying = 4.
Length of the each blacktip shark = 2 yards long.
Length of the each tiger shark = 4 yards long.
Total length of the 7 sharks = (Length of the blacktip shark × Number of blacktip sharks Dr. Marks is studying) + ( Length of the each tiger shark × Number of tiger sharks Dr. Marks is studying)
=  (2 × 3) + ( 4 × 4)
= 6 + 16
= 22 square yards long.

 

Question 27.
Critique Reasoning Kent reasons that the total length of 4 blacktip sharks can be found using addition. Is his reasoning correct? Explain.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 39

Answer:
Yes, his reasoning is correct, we can find the total length of 4 blacktip sharks can be found using addition.

Explanation:
Length of the each blacktip shark = 2 yards long.
Total length of 4 blacktip sharks = Length of the each blacktip shark + Length of the each blacktip shark  + Length of the each blacktip shark  + Length of the each blacktip shark
= 2 + 2 + 2 + 2
= 4 + 2 + 2
= 6 + 2
= 8 square yards long.

 

Question 28.
Write the fact family for each fact: 3 × 0, 3 × 1, 3 × 2, 3 × 3, 3 × 4, 3 × 5, 3 × 6, 3 × 7, 3 × 8, 3 × 9, and 3 × 10.
Answer:
Fact family:

3 × 0 = 0.
=> 0 × 3 = 0.
3 × 1 = 3.
=> 1 × 3 = 3.
3 × 2 = 6.
=> 2 × 3 = 6.
3 × 3 = 9.
=> 3 × 3 = 9.
3 × 4 = 12.
=> 3 × 4 = 12.
3 × 5 = 15.
=> 5 × 3 = 15.
3 × 6 = 18.
=> 6 × 3 = 18.
3 × 7 = 21.
=> 7 × 3 = 21.
3 × 8 = 24.
=> 8 × 3 = 24.
3 × 9 = 27.
=> 9 × 3 = 27.
3 × 10 = 30.
= 10 × 3 = 30.

Explanation:
3 × 0 = 0.
=> 0 × 3 = 0.
3 × 1 = 3.
=> 1 × 3 = 3.
3 × 2 = 6.
=> 2 × 3 = 6.
3 × 3 = 9.
=> 3 × 3 = 9.
3 × 4 = 12.
=> 3 × 4 = 12.
3 × 5 = 15.
=> 5 × 3 = 15.
3 × 6 = 18.
=> 6 × 3 = 18.
3 × 7 = 21.
=> 7 × 3 = 21.
3 × 8 = 24.
=> 8 × 3 = 24.
3 × 9 = 27.
=> 9 × 3 = 27.
3 × 10 = 30.
= 10 × 3 = 30.

 

 

Question 29.
Higher Order Thinking Show how you can use known facts to find 11 × 9. Explain how you chose the known facts.
Answer:
11 × 9 = (6 × 9) + (5 × 9) = 66 + 33 = 99.

Explanation:
11 × 9 = (6 × 9) + (5 × 9)
11 × 9 = 66 + 33
11 × 9 = 99.

 

Assessment Practice
Question 30.
Which shows one way you could use properties of operations to find 7 × 2?
A. (5 × 2) + (2 × 2)
B. (7 + 2) + (7 + 2)
C. (7 × 2) × 2
D. 7 × (2 × 2)
Answer:
A. (5 × 2) + (2 × 2) is one way you could use properties of operations to find 7 × 2.

Explanation:
7 × 2 = (5 × 2) + (2 × 2)
7 × 2 = 10 + 4
7 × 2 = 14.

 

Question 31.
Which multiplication equation could you use to help find 40 ÷ 8 = ☐?
A. 55 = 25
B. 8 × 8 = 64
C. 1 × 8 = 8
D. 8 × 5 = 40
Answer:
D. 8 × 5 = 40 multiplication equation could you use to help find 40 ÷ 8 = ☐.

Explanation:
40 ÷ 8 = ??
40 ÷ 8 = 5.
=> 8 × 5 = 40.

 

 

Lesson 5.4 Solve Word Problems: Multiplication and Division Facts

Solve & Share
At the Fall Fest parade, members of the Cat Lovers Club and the Dog Lovers Club will march in equal rows. There will be 6 members in each row. How many rows of dog lovers will march in the parade? How many total cat lovers will march in the parade? Complete the table.
I can … use strategies to solve word problems that involve multiplication and division.
Envision Math Common Core 3rd Grade Answer Key Topic 5 Fluently Multiply and Divide within 100 40

Look Back! What operations did you use to solve the problem? Explain your reasoning.
Answer:
Operations used to solve the problem are multiplication and division.
Number of rows of dog lovers in the parade = 4.
Number of members of cat lovers in the parade = 30.

Explanation:
Number of members in each row = 6.
Number of dog lovers in the parade = 24.
Number of rows of dog lovers in the parade = Number of dog lovers in the parade ÷ Number of members in each row
= 24 ÷ 6
= 4.
Number of members in each row = 6.
Number of rows of cat lovers given = 5.
Number of members of cat lovers in the parade = Number of rows of cat lovers given × Number of members in each row
= 5 × 6
= 30.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.4 Solve Word Problems- Multiplication and Division Facts

 

Essential Question
How Can You Solve Word Problems Using Multiplication and Division?
Answer:
We can solve Word Problems Using Multiplication and Division by using a repeated method of finding what is asked, by using the data given and finding the correct solution of the problem.

Explanation:
We can solve Word Problems Using Multiplication and Division by using a repeated method step-by-step of finding what is asked, by using the data given and finding the correct solution of the problem.

 

 

 

Visual Learning Bridge
Gina has 45 hats. She is packing them by putting 9 hats in each of several boxes. How many boxes will she fill?
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 41

Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 42

One Way
Think: 45 divided by what number equals 9?
45 ÷ 5 = 9
There are 5 groups of 9 in 45.
Gina can divide 45 hats into 5 boxes of 9 hats each.

Another Way
You can use a related fact.
Think: 9 times what number equals 45?
9 × 5 = 45
So, 45 ÷ 9 = 5.
Gina can divide 45 hats into 5 boxes of 9 hats each.

Convince Me! Generalize Krys has 42 hats. She puts 6 hats in each of several boxes. Can you find how many boxes she needs using the same strategies as in the example above? Explain.
Answer:
Number of boxes she needs = 7.

Explanation:
Number of hats Krys has = 42.
Number of hats in each box she puts = 6.
Number of boxes she needs = Number of hats Krys has ÷ Number of hats in each box she puts
= 42 ÷ 6
= 7.

 

 

Guided Practice
Do You Understand?
Question 1.
Why can you use division to model the problem on the previous page?
Answer:
We can use division to model the problem on the previous page because according to given data, the required solution is only found by using division method.

Explanation:
We can use division to model the problem on the previous page because according to given data, the required solution is only found by using division method.
Number of boxes she needs = Number of hats Krys has ÷ Number of hats in each box she puts

 

Question 2.
Casey gives 27 stickers to 3 friends. She writes the equation 27 ÷ 3 = 9. What does the 9 represent in this problem?
Answer:
Number of stickers she gives to each friend = 9.

Explanation:
Number of stickers Casey gives = 27.
Number of friends she gives = 3.
Number of stickers she gives to each friend = Number of stickers Casey gives ÷ Number of friends she gives
= 27 ÷ 3
= 9.

 

 

Do You Know How?
In 3, represent the problem with an equation or a bar diagram. Then solve.
Question 3.
A checkerboard has 64 squares. It has 8 rows. How many columns does it have?
Answer:
Number of columns a checkerboard has = 8.

Explanation:
Number of squares a checkerboard has = 64 .
Number of rows a checkerboard has = 8.
Number of columns a checkerboard has = Number of squares a checkerboard has ÷ Number of rows a checkerboard has
= 64 ÷ 8
= 8.

 

Independent Practice
In 4 and 5, draw a bar diagram to represent the problem. Then solve.
Question 4.
There are 5 pancakes in a stack. Elise makes 40 pancakes. How many stacks does Elise make?
Answer:
Number of stacks Elise makes = 8.

Explanation:
Number of pancakes in a stack = 5.
Number of pancakes Elise makes = 40.
Number of stacks Elise makes = Number of pancakes Elise makes ÷ Number of pancakes in a stack
= 40 ÷ 5
= 8.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.4 Solve Word Problems- Multiplication and Division Facts-Independent Practice-4

 

 

 

Question 5.
A park has 4 swing sets. Each of the sets has 7 swings. How many swings are in the park?
Answer:
Number of swings are in the park = 28.

Explanation:
Number of swing sets a park has = 4.
Number of swings in each set = 7.
Number of swings are in the park = Number of swing sets a park has × Number of swings in each set
= 4 × 7
= 28.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.4 Solve Word Problems- Multiplication and Division Facts-Independent Practice-5

 

In 6 and 7, write an equation with an unknown to represent the problem. Then solve.
Question 6.
Mrs. Jameson plants 30 tulips in rows. Each row has 6 tulips. How many rows did Mrs. Jameson plant?
Answer:
Number of rows Mrs. Jameson plants = 5.

Explanation:
Number of tulips in rows Mrs. Jameson plants = 30.
Number of tulips in each row = 6.
Number of rows Mrs. Jameson plants = Number of tulips in rows Mrs. Jameson plants ÷ Number of tulips in each row
= 30 ÷ 6
= 5.

 

Question 7.
Bonnie buys 6 paperback books every month. She buys 2 hardcover books every month. How many books does she buy in 4 months?
Answer:
Total number of books she buys in 4 months = 32.

Explanation:
Number of paperback books every month Bonnie buys = 6.
Number of hardcover books every month Bonnie buys = 2.
Total number of books she buys in 4 months = 4 ( Number of paperback books every month Bonnie buys  + Number of hardcover books every month Bonnie buys)
= 4 ( 6 + 2)
= 4 × 8
= 32.

 

 

Problem Solving
Question 8.
Jodie has 24 flowers in her garden. She wants to give an equal number of flowers to 4 families in her neighborhood. How many flowers will each family get? Complete the bar diagram and write an equation to help solve this problem.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 43
Answer:
Number of flowers each family gets = 6.

Explanation:
Number of flowers in her garden Jodie has = 24.
Number of families she want to give flowers equally = 4.
Number of flowers each family gets = Number of flowers in her garden Jodie has ÷ Number of families she want to give flowers equally
= 24 ÷ 4
= 6.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.4 Solve Word Problems-Multiplication and Division Facts-Problem Solving-8

 

Question 9.
Model with Math Casey has 2 sisters. He gave each sister 2 pages of stickers. Each page had 9 stickers on it. How many stickers did Casey give in all? Explain what math you used to solve.
Answer:
Total number of stickers Casey give in all = 18.
Math used to solve the problem is multiplication.

Explanation:
Number of stickers Model with Math Casey has = 2.
Number of pages of stickers he gave each sister = 2.
Number of stickers each page has = 9.
Total number of stickers Casey give in all = Number of pages of stickers he gave each sister × Number of stickers each page has
= 2 × 9
= 18.

 

Question 10.
Write the fact family for each fact: 6 × 0, 6 × 1, 6 × 2, 6 × 3, 6 × 4, 6 × 5, 6 × 6, 6 × 7, 6 × 8, 6 × 9, and 6 × 10.
Answer:
Fact family:
6 × 0 = 0.
=> 0 × 6 = 0.
6 × 1 = 6.
=> 1 × 6 = 6.
6 × 2 = 12.
=> 2 × 6 = 12.
6 × 3 = 18.
=> 3 × 6 = 18.
6 × 4 = 24.
=> 4 × 6 = 24.
6 × 5 = 30.
=> 5 × 6 = 30.
6 × 6 = 36.
=> 6 × 6 = 36.
6 × 7 = 42.
=> 7 × 6= 42.
6 × 8 = 48.
=> 8 × 6 = 48.
6 × 9 = 54.
=> 9 × 6 = 54.
6 × 10 = 60.
=> 10 × 6= 60.

Explanation:
6 × 0 = 0.
=> 0 × 6 = 0.
6 × 1 = 6.
=> 1 × 6 = 6.
6 × 2 = 12.
=> 2 × 6 = 12.
6 × 3 = 18.
=> 3 × 6 = 18.
6 × 4 = 24.
=> 4 × 6 = 24.
6 × 5 = 30.
=> 5 × 6 = 30.
6 × 6 = 36.
=> 6 × 6 = 36.
6 × 7 = 42.
=> 7 × 6= 42.
6 × 8 = 48.
=> 8 × 6 = 48.
6 × 9 = 54.
=> 9 × 6 = 54.
6 × 10 = 60.
=> 10 × 6= 60.

 

Question 11.
Higher Order Thinking Twenty-five students are working in groups on a science project. Each group can have either 2 or 3 students in it. What is the fewest number of groups there could be?
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 44
Answer:
Number of students in each group of 2 is the fewest number of groups than Number of students in each group of 3.

Explanation:
Number of students are working in groups on a science project = 25.
Number of students in each group = 2.
Number of groups = Number of students are working in groups on a science project × Number of students in each group
= 25 × 2
= 50.
Number of students are working in groups on a science project = 25.
Number of students in each group = 3.
Number of groups = Number of students are working in groups on a science project × Number of students in each group
= 25 × 3
= 75.

 

 

Assessment Practice
Question 12.
Eight vans are going to the zoo. There are 6 children in each van. How many children are going to the zoo?
Select numbers and an operation from the box to complete an equation that could be used to answer the problem. Then solve the equation.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 45
Answer:
Number of children going to the zoo = 48.

Explanation:
Number of vans going to the zoo = 8.
Number of children in each van = 6.
Number of children going to the zoo = Number of vans going to the zoo × Number of children in each van
= 8 × 6
= 48.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.4 Solve Word Problems-Multiplication and Division Facts-Assessment Practice-12

 

 

Question 13.
Ninety children are going to a museum. Nine children can ride in each minibus. How many minibuses are needed? Select numbers and an operation from the box to complete an equation that could be used to answer the problem. Then solve the equation.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 46
Answer:
Number of minibuses are needed = 10.

Explanation:
Number of children are going to a museum = 90.
Number of children can ride in each minibus = 9.
Number of minibuses are needed = Number of children are going to a museum ÷ Number of children can ride in each minibus
= 90 ÷ 9
= 10.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.4 Solve Word Problems-Multiplication and Division Facts-Problem Solving-13

 

 

Lesson 5.5 Write Multiplication and Division Math Stories

Solve & Share
Write a real-world division story for 28 ÷ 4. Then write another real-world story that shows a different way to think about 28 ÷ 4.
I can … write and solve math stories for multiplication and division equations.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 47

Look Back! Draw a bar diagram and write an equation to represent and solve one of your division stories.

Answer:
Number of students in each bus = Total number of students in a school ÷ Number of buses
= 28 ÷ 4
= 7.

Explanation:
Total number of students in a school = 28.
Number of buses = 4.
Number of students in each bus = Total number of students in a school ÷ Number of buses
= 28 ÷ 4
= 7.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.5 Write Multiplication and Division Math Stories

 

 

Essential Question
How Can You Describe a Multiplication Fact?
Answer:
A multiplication fact is the answer to a multiplication calculation.
For example, in the sum 3 x 3 = 9, the multiplication fact is 9

Explanation:
The repeated addition of the same number is expressed by multiplication in short. Hence, repeated addition of 2 five times is equal to 2 multiplied by 5. Thus, 3 × 6 = 18 that 3 multiplied by 6 is equal to 18, or 3 into 6 is equal to 18, or product of 3 and 6 is 18. 3 × 6 = 18 is called a multiplication fact

 

 

Visual Learning Bridge
Write a multiplication story for 3 × 6.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 48

Equal Groups
Randy has 3 packs of 6 buttons. How many buttons does he have?
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 49
3 × 6 = 18
Randy has 18 buttons.

An Array
Eliza planted 6 lilies in each of 3 rows. How many lilies did she plant?
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 50
3 × 6 = 18
Eliza planted 18 lilies.

Bar Diagram
A rabbit eats an equal amount of carrots each day for 3 days. If the rabbit eats 6 carrots each day, how many carrots does it eat in all?
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 51
3 × 6 = 18
The rabbit eats 18 carrots.

Convince Me! Reasoning Write a multiplication story for 3 × 10 = ☐.
Answer:
Number of buns he eats in all = Number of buns each day Rakesh eats × Number of buns he eats each day
= 3 × 10
= 30.

Explanation:
A Rakesh eats an equal amount of buns each day for 3 days. If the Rakesh eats 10 buns each day, how many buns does he eat in all?
Number of buns each day Rakesh eats = 3.
Number of buns he eats each day = 10.
Number of buns he eats in all = Number of buns each day Rakesh eats × Number of buns he eats each day
= 3 × 10
= 30.

 

Another Example!
Seth has 15 fluid ounces of juice. Write and solve division . You can write a division stories about Seth and his juice. Use the equation story about “How many are 15 ÷ 3 = ?.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 52
How many in each group?
Seth has 15 fluid ounces of juice. He pours an equal amount of juice into 3 containers. How many fluid ounces of juice are in each container?
15 ÷ 3 = 5 fluid ounces How many groups are there?

How many groups are there?
Seth has 15 fluid ounces of juice. He wants to pour 3 fluid ounces of juice into each container. How many containers does Seth need?
15 ÷ 3 = 5 containers

 

 

Guided Practice
Do You Understand?
Question 1.
When you write a division story, what two pieces of information do you need to include?
Answer:
For writing any division story, the two pieces of information required are total number n each part about what the problem is mandatory.

Explanation:
For writing any division story, the two pieces of information required are total number n each part about what the problem is mandatory.

 

 

Do You Know How?
In 2 and 3, write a story for the equation. Then solve.
Question 2.
3 × 5 = ________
Answer:
Mimi has 15 container of fluid ounces of juice. She wants to pour 3 fluid ounces of juice into each container. How many containers does Mimi has ?
3 × 5 = __15______.

Explanation:
Mimi has 5 container of fluid ounces of juice. She wants to pour 3 fluid ounces of juice into each container. How many containers does Mimi has ?
Number of fluid ounces of juice Mimi wants to pour into each container = 3.
Number of container Mimi has = 5.
Number of fluid ounces of juice Mimi has = Number of fluid ounces of juice Mimi wants to pour into each container ×  Number of container Mimi has
= 3 × 5
= 15.

 

Question 3.
8 ÷ 4 = ________
Answer:
Mia has 8 books. She puts books equally into 4 boxes. How many books are in each box?
8 ÷ 4 = ___2_____.

Explanation:
Mia has 8 books. She puts books equally into 4 boxes. How many books are in each box?
Number of books Mia has = 8.
Number of boxes she puts the books = 4.
Number of books are in each box = Number of books Mia has ÷ Number of boxes she puts the books
= 8 ÷ 4
= 2.

 

Independent Practice
In 4-7, write a story for each equation. Then solve.
Question 4.
7 × 3 = _______
Answer:
Mimi has 5 container of fluid ounces of oil. She wants to pour 3 fluid ounces of oil into each container. How many containers does Mimi has ?
7 × 3 = __21_____.

Explanation:
Mimi has 5 container of fluid ounces of oil. She wants to pour 3 fluid ounces of oil into each container. How many containers does Mimi has ?
Number of fluid ounces of oil Mimi wants to pour into each container = 3.
Number of container Mimi has = 7.
Number of fluid ounces of oil Mimi has = Number of fluid ounces of oil Mimi wants to pour into each container ×  Number of container Mimi has
= 3 × 7
= 21.

 

Question 5.
5 × 5 = ________
Answer:
Moni has 5 packets of chocolates. She wants to put 5 packets of chocolates into each container. How many containers does Moni has ?
5 × 5 = ___25_____.

Explanation:
Moni has 5 packets of chocolates. She wants to put 5 packets of chocolates into each container. How many containers does Moni has ?
Number of packets of chocolates Moni wants to put into each container = 5.
Number of container Mimi has = 5.
Number of packets of chocolates Moni has = Number of packets of chocolates Moni wants to put into each container ×  Number of container Moni has
= 5 × 5
= 25..

 

Question 6.
18 ÷ 3 = ________
I will write about 18 __________
I will put them in 3 equal groups.
Answer:
18 ÷ 3 = ___6_____.

Explanation:
18 ÷ 3 = ___6_____.
I will write about 18  biscuits packets.
I will put them in 3 equal groups.
Each group 6.

 

Question 7.
14 ÷ ____ = 2
I will write about 14
I will put them in groups of 2.

Answer:
14 ÷ _7___ = 2.

Explanation:
14 ÷ _7___ = 2.
I will write about 14 students.
I will put them in groups of 2.
Students each group 7.

 

Problem Solving
Question 8.
Reasoning Write a multiplication story about these pencils. Write an equation for your story.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 53

Answer:
Number of pencils kept in each group = Total number of pencils ÷ Number of groups equally they are kept
= 8 ÷ 2
= 4.

Explanation:
Total number of pencils = 8.
Number of groups equally they are kept = 2.
Number of pencils kept in each group = Total number of pencils ÷ Number of groups equally they are kept
= 8 ÷ 2
= 4.

 

Question 9.
Write the fact family for each fact: 8 × 0, 8 × 1, 8 × 2, 8 × 3, 8 × 4, 8 × 5, 8 × 6, 8 × 7, 8 × 8, 8 × 9, and 8 × 10.
Answer:
Fact family:
8 × 0 = 0.
=> 0 × 8 = 0.
8 × 1 = 8.
=> 1 × 8 = 8.
8 × 2 = 16.
=> 8 × 2 = 16.
8 × 3 = 24.
=> 3 × 8 = 24.
8 × 4 = 32.
=> 4 × 8 = 32.
8 × 5 = 40.
=> 5 × 8 = 40.
8 × 6 = 48.
=> 6 × 8 = 48.
8 × 7 = 56.
=> 7 × 8 = 56.
8 × 8 = 64.
=> 8 × 8 = 64.
8 × 9 = 72.
=> 9 × 8 = 72.
8 × 10 = 80.
=> 10 × 8= 80.

Explanation:
8 × 0 = 0.
=> 0 × 8 = 0.
8 × 1 = 8.
=> 1 × 8 = 8.
8 × 2 = 16.
=> 8 × 2 = 16.
8 × 3 = 24.
=> 3 × 8 = 24.
8 × 4 = 32.
=> 4 × 8 = 32.
8 × 5 = 40.
=> 5 × 8 = 40.
8 × 6 = 48.
=> 6 × 8 = 48.
8 × 7 = 56.
=> 7 × 8 = 56.
8 × 8 = 64.
=> 8 × 8 = 64.
8 × 9 = 72.
=> 9 × 8 = 72.
8 × 10 = 80.
=> 10 × 8= 80.

 

 

Question 10.
A soccer team traveled to a game in 4 vans. Each van held 6 players. Two of the players are goalkeepers. How many of the players are not goalkeepers?
Answer:
Number of players are not goalkeepers = 22.

Explanation:
Number of vans soccer team traveled to a game = 4.
Number of players in each van = 6.
Number of players are goalkeepers = 2.
Number of soccer team players traveled to a game = Number of vans soccer team traveled to a game × Number of players in each van
= 4 × 6
= 24.
Number of players are not goalkeepers = Number of soccer team players traveled to a game – Number of players are goalkeepers
= 24 – 2
= 2.

 

 

 

Question 11.
Higher Order Thinking A group of 9 monarch butterflies is getting ready to migrate. Write a multiplication story involving this group. Explain what fact you are using and find the product.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 54

Answer:
Number of wings and legs monarch butterfly has = 90.
Multiplication fact is used to find the product.

Explanation:
Number of bright orange wings each monarch butterfly has = 4.
Number of legs each monarch butterfly has = 6.
Total number of monarch butterfly = 9.
Number of wings and legs monarch butterfly has = Total number of monarch butterfly (Number of bright orange wings each monarch butterfly has + Number of legs each monarch butterfly has)
= 9(4 + 6)
= 9 × 10
= 90.

 

Assessment Practice
Question 12.
Mary writes the following story for 72 ÷ 9 = ?.
There are 72 marbles separated into 9 equal groups. How many marbles are in each group? Select the correct answer for Mary’s story.
A. 7 marbles
B. 8 marbles
C. 9 marbles
D. 10 marbles
Answer:
Number of marbles in each group = 8.
B. 8 marbles.

Explanation:
Total number of marbles = 72.
Number of groups = 9.
Number of marbles in each group = Total number of marbles ÷ Number of groups
= 72 ÷ 9
= 8.

 

Question 13.
Chris writes the following story for 4 × 10 = ?.
There are 4 pieces of wood set end to end to make a ramp. Each piece is 10 inches long. How long is the ramp? Select the correct answer for Chris’s story.
A. 4 inches
B. 10 inches
C. 20 inches
D. 40 inches
Answer:
Length of the ramp = 40 inches.
D. 40 inches.

Explanation:
Number of pieces of wood set end to end to make a ramp = 4.
Length of each piece = 10 inches.
Length of the ramp = Number of pieces of wood set end to end to make a ramp × Length of each piece
= 10 × 4
= 40 inches.

 

 

Lesson 5.6 Problem Solving

Look For and Use Structure
Solve & Share
Jacob has started the pattern below. Fill in the blanks to make correct equations and continue the pattern. Explain your thinking.
I can … use the structure of multiplication and division to compare expressions.
6 × 1 = 3 × 2
6 × 2 = 3 × 4
6 × 3 = 3 × ☐
6 × = 3 × ☐
☐ × ☐ = ☐ × ☐
Thinking Habits
Be a good thinker! These questions can help you.

  • What patterns can I see and describe?
  • How can I use the patterns to solve the problem?
  • Can I see expressions and objects in different ways?
    Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 55

Look Back! Use Structure Jacob starts this new pattern. Fill in the blank to make the equation true. What do you notice about this pattern compared to the pattern above?
3 × 2 = 6 × 1
3 × 4 = 6 × 2
3 × ☐ = 6 × 3
Answer:
3 × 6 = 6 × 3 = 18.
It is noticed that from from equation to other there is a difference of 6.

Explanation:
3 × 2 = 6 × 1
=> 3 × 2 = 6 × 1 = 6.
3 × 4 = 6 × 2
=> 3 × 4 = 6 × 2 = 12.
3 × ?? = 6 × 3
=> 3 × ?? = 6 × 3 = 18
=> 3 × 6 = 6 × 3 = 18.

 

Essential Question
How Can You Use the Structure of Mathematics?
Answer:
The Structure of Mathematics helps in understanding the problem in order to find the correct solution to the problem.

Explanation:
In mathematics, a structure is a  set endowed with some additional features on the set. Often, the additional features are attached or related to the set, so as to provide it with some additional meaning or significance.

 

 

Visual Learning Bridge
How can you tell without computing whether the symbol >, <, or = should be placed in each circle below?
1. 4 × 5 × 2 ○ 4 × 3 × 5
2. 6 × 7 ○ 7 × 6
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 56
What do I need to do to complete the task?
I need to compare the expressions. Instead of doing any calculations, I will look at the values of the factors in each expression.

How can I make use of structure to solve this problem?
I can

  • think about properties i know.
  • look for patterns and use them as needed.

Here’s my thinking
Some factors in the expressions are the same and some are different. I will use this to help me compare.
1. I know that I can group factors in any way, so I can rewrite one expression.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 57
2. I see the factors are the same on both sides. I know this means the products are the same.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 58

Convince Me! Use Structure Dario says, “I can find 9 × 0 < 3 × 1 without computing. I can think about properties that I know.” What could he mean?
Answer:
He could mean:
1. He know that he can group factors in any way, so he can rewrite one expression.
2. He sees the factors are the same on both sides. He knows this means the products are the same.

Explanation:
He could mean:
1. He know that he can group factors in any way, so he can rewrite one expression.
2. He sees the factors are the same on both sides. He knows this means the products are the same.
9 × 0 < 3 × 1
=> 9 × 0 = 0.
=> 3 × 1 = 3.
Hence, 9 × 0 < 3 × 1.

 

 

Guided Practice
Use Structure Hakeem and Nicole each have 48 stickers. Hakeem shared his stickers among 8 friends. Nicole shared her stickers among 6 friends. These expressions show how Hakeem and Nicole shared their stickers.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 59
48 ÷ 8 ○ 48 ÷ 6

Question 1.
Look at the expressions. Explain how you can use what you see to compare without computing.
Answer:
48 ÷ 8 ○ 48 ÷ 6
=> 48 ÷ 8 < 48 ÷ 6.
We use this expression without computing in this way.

Explanation:
Total number of stickers Hakeem and Nicole each have = 48.
Number of Hakeem shared his stickers = 8.
Number of stickers each friend of Hakeem gets = Total number of stickers Hakeem and Nicole each have  ÷ Number of Hakeem shared his stickers
= 48 ÷ 8
= 6.
Number of Nicole shared his stickers = 6.
Number of stickers each friend of Nicole gets = Total number of stickers Hakeem and Nicole each have  ÷ Number of Nicole shared his stickers
= 48 ÷ 6
= 8.

 

 

Question 2.
Whose friends each received more stickers? Write the correct symbol >, <, or = in the circle above.
Answer:
Number of stickers each friend of Hakeem gets < Number of stickers each friend of Nicole gets
=> 6 < 8.

Explanation:
Number of stickers each friend of Hakeem gets = Total number of stickers Hakeem and Nicole each have  ÷ Number of Hakeem shared his stickers
= 48 ÷ 8
= 6.
Number of stickers each friend of Nicole gets = Total number of stickers Hakeem and Nicole each have  ÷ Number of Nicole shared his stickers
= 48 ÷ 6
= 8.

 

Independent Practice Use Structure Dan has saved $10 each week for 7 weeks. Misha has saved $7 each week for 9 weeks. These expressions show how they saved. 7 × $10 ○ 9 × $7
Answer:
Total amount Dan saved > Total amount Misha saved.
7 × $10 > 9 × $7.

Explanation:
Number of money Dan has saved each week = $10.
Number of weeks he saved = 7.
Total amount Dan saved = Number of money Dan has saved each week × Number of weeks he saved
= $10 × 7
= $70.
Number of money Misha has saved each week = $7.
Number of weeks she saved = 9.
Total amount Misha saved = Number of money Misha has saved each week × Number of weeks he saved
= $7 × 9
= $63.

 

Question 3. Look at the expressions. Explain how you can use what you see to compare without computing. Answer:
We can use what is seen to compare without computing is by this way: finding the total two sides and using the required symbol.
7 × $10 > 9 × $7.

Explanation:
7 × $10 ○ 9 × $7
=> $70 > $63.

 

 

Question 4. Who saved more money? Write the correct symbol >, <, or = in the circle above.
Answer:
Total amount Dan saved is more than the total amount Misha saved.
7 × $10 > 9 × $7.

Explanation:
Total amount Dan saved = $70.
Total amount Misha saved = $63.
7 × $10 > 9 × $7.

 

Question 5.
Can you use the same symbol you wrote in Exercise 4 to compare $10 × 7 and $7 × 9? Explain.
Answer:
Yes, we can the same symbol written in Exercise 4 to compare $10 × 7 and $7 × 9.
$10 × 7 > $7 × 9.

Explanation:
$10 × 7 and $7 × 9
$10 × 7 = $70.
$7 × 9 = $63.

 

 

Problem Solving
Performance Task
Selling Necklaces Trina wants to find the least expensive way to buy 24 necklaces. She wants to buy only the same type of packages. She has $48. The table shows the number of necklaces in a package and the cost of each package.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 60

Question 6.
Model with Math Complete the table to find the number of packages Trina would need to buy.
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.6 Problem Solving-Problem Solving-Performance Task

Explanation:
Number of packages Trina want to buy = 24.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Lesson 5.6 Problem Solving-Problem Solving-Performance Task

 

Question 7.
Use Structure Trina can use 8 × $4 to find the cost of enough $4 packages. Write a similar expression that shows a way to find how much it costs Trina to buy enough $5 packages.
Answer:
Total cost needed to buy for Trina = $120.

Explanation:
Number of packages Trina want to buy = 24.
Cost of each package = $5.
Total cost needed to buy for Trina = Number of packages Trina want to buy × Cost of each package
= 24 × $5
= $120.

Write a similar expression that shows a way to find how much it costs Trina to buy enough $6 packages.

 

Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 61

Answer:
Total cost needed to buy for Trina = $144.

Explanation:
Number of packages Trina want to buy = 24.
Cost of each package = $6.
Total cost needed to buy for Trina = Number of packages Trina want to buy × Cost of each package
= 24 × $6
= $144.

 

Question 8.
Make Sense and Persevere Compare the cost of buying the $5 packages to the $6 packages. Which package type costs less if Trina wants to buy 24 necklaces? Explain how to solve without computing.
Answer:
Total cost needed to buy enough $5 packages for Trina is less than the Total cost needed to buy enough $6 packages for Trina
$120 < $144.

Explanation:
Total cost needed to buy enough $5 packages for Trina = $120.
Total cost needed to buy enough $6 packages for Trina = $144.
=> $120 < $144.

 

Question 9.
Construct Arguments Compare the costs of buying the $4 packages to the $6 packages. Which package type costs less if Trina wants to buy 24 necklaces? Explain how to solve without computing.

Answer:
Total cost needed to buy enough $4 packages for Trina is less than the Total cost needed to buy enough $6 packages for Trina
$96< $144.

Explanation:
Number of packages Trina want to buy = 24.
Cost of each package = $4.
Total cost needed to buy for Trina = Number of packages Trina want to buy × Cost of each package
= 24 × $4
= $96.
Number of packages Trina want to buy = 24.
Cost of each package = $6.
Total cost needed to buy for Trina = Number of packages Trina want to buy × Cost of each package
= 24 × $6
= $144.

 

 

Topic 5 Fluency Practice Activity

Point & Tally
Find a partner. Get paper and a pencil. Each partner chooses a different color: light blue or dark blue.

Partner 1 and Partner 2 each point to a black number at the same time. Both partners multiply those numbers.

If the answer is on your color, you get a tally mark. Partners then write the remaining facts in the fact family. Work until one partner has seven tally marks.
I can … multiply and divide within 100.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 62

Answer:
9 × 7 = 63.
5 × 4 = 20.
6 × 5 = 30.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Fluency Practice Activity-Point & Tally

Explanation:
9 × 7 = 63.
5 × 4 = 20.
6 × 5 = 30.
8 × 6 = 48.
4 × 9 = 36.
Three are correct , tally marks are three.

 

 

Topic 5 Vocabulary Review

Understand Vocabulary
For each of these terms, give an example and a non-example.

Word List

  • column
  • equation
  • even
  • fact family
  • odd
  • row

Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 63
Write always, sometimes, or never.

Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Vocabulary Review-Understand Vocabulary

Explanation:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Vocabulary Review-Understand Vocabulary

 

 

Question 5.
An even number can __________ be divided by 2 with none left over.
Answer:
An even number can ____300______ be divided by 2 with none left over.

Explanation:
An even number can be divided by 2 with none left over:
all multiples of 2 number.
Like : 4, 50, 100, 3060, so on….

 

Question 6.
A fact family _________ has odd numbers.
Answer:
A fact family ____odd_____ has odd numbers.

Explanation:
A fact family odd has odd numbers.

 

Question 7.
An array _________ has the same number of rows and columns.
Answer:
An array ___square______ has the same number of rows and columns.

Explanation:
An array square has the same number of rows and columns.

 

Question 8.
The product of an odd number times an odd number is ____________ an even number.
Answer:
The product of an odd number times an odd number is ____odd not________ an even number.

Explanation:
The product of an odd number times an odd number is odd not an even number.

 

Use Vocabulary in Writing
Question 9.
Explain the pattern in the green squares. Use at least 2 terms from the Word List in your explanation.
Envision Math Common Core 3rd Grade Answers Topic 5 Fluently Multiply and Divide within 100 64
Answer:
The pattern in the green squares:
odd × odd = odd number.

Explanation:
The pattern in the green squares:
1 × 1 = 1.
1 × 3 = 3.
1 × 5 = 5.
3 × 1 = 3.
3 × 3 = 9.
3 × 5 = 15.
1 × 5 = 5.
3 × 5 = 15
5 × 5 = 25.

 

Topic 5 Reteaching
Set A pages 169-172

You can see patterns in a multiplication table.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 65

Remember that properties can help to explain patterns.
In 1 and 2, use the multiplication table to answer the questions.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 66
Question 1.
Find the column that has products that are the sum of the green shaded numbers in each row. Shade this column.
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Reteaching-Set A pages 169-172-1

Explanation:
Column shaded in purple color has the products that are the sum of the green shaded numbers in each row.

 

Question 2.
Explain why this pattern is true.
Answer:
Yes, the pattern is true because the sum of the two green color numbers is equal to the number shaded in the same column.

Explanation:
Numbers in green color:
1 + 6 = 7.
2 + 12 = 14.

 

Set B pages 173-176

Use a multiplication table to find 20 ÷ 4.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 67
Find 4 in the first column of the table.
Follow the 4s row until you come to 20.
Then look to the top of that column to find the missing factor: 5. 20 ÷ 4 = 5.

Remember how multiplication and division are related

In 1-12, use the multiplication table to find each product or quotient.
Question 1.
2 × 7 = ______
Answer:
2 × 7 = __14____.

Explanation:
2 × 7 = 14. (product)

 

Question 2.
5 × 8 = ________
Answer:
5 × 8 = ___40_____.

Explanation:
5 × 8 = 40.(product)

 

Question 3.
2 × 10 = _______
Answer:
2 × 10 = ___20____.

Explanation:
2 × 10 = 20.(product)

 

Question 4.
5 × 4 = _______
Answer:
5 × 4 = __20_____.

Explanation:
5 × 4 = 20.(product)

 

Question 5.
3 × 5 = _____
Answer:
3 × 5 = __15___.

Explanation:
3 × 5 = 15.(product)

 

Question 6.
6 × 5 = _______
Answer:
6 × 5 = ___30____.

Explanation:
6 × 5 = 30.(product)

 

Question 7.
63 ÷ 9 = ______
Answer:
63 ÷ 9 = ___7___.(quotient)

Explanation:
63 ÷ 9 = 7.

 

Question 8.
56 ÷ 8 = _______
Answer:
56 ÷ 8 = __7_____.

Explanation:
56 ÷ 8 = 7.(quotient)

 

Question 9.
45 ÷ 9 = _______
Answer:
45 ÷ 9 = __5_____.

Explanation:
45 ÷ 9 = 5.(quotient)

 

Question 10.
40 ÷ 8 = _______
Answer:
40 ÷ 8 = ___5____.

Explanation:
40 ÷ 8 = 5.(quotient)

 

Question 11.
35 ÷ 7 = _______
Answer:
35 ÷ 7 = __5_____.

Explanation:
35 ÷ 7 = 5.(quotient)

 

Question 12.
36 ÷ 6 = ______
Answer:
36 ÷ 6 = ___6___.

Explanation:
36 ÷ 6 = 6.(quotient)

 

 

Set B, continued pages 173-176

You can use basic facts and properties to find missing numbers in a multiplication table.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 68
Use multiplication or division to find missing factors.
42 ÷ 7 = 6, so 7 × 6 = 42
Use strategies to find products.
3 × 5 = 15 4 × 5 = 20
5 × 5 = 25 6 × 5 = 30
So, 7 × 5 = 35

Remember that you can use strategies and reasoning to find missing numbers.

Use multiplication and division strategies to complete the multiplication table. Show your work.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 69
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Set B, continued pages 173-176

Explanation:
? × ? = 12.
=> 3 × 4 = 12.
3 × ? = ??.
=> 3 × 7 = 21.
?? × 6 = 24.
=> 4 × 6 = 24.
6 × ?? = 24.
=> 6 × 4 = 24.
7 × ?? = 28.
=> 7 × 4 = 28.
8 × ?? = ??
=> 8 × 7 = 56.

 

Set C pages 177-180

Find 4 × 7.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 70
You can use skip counting: 7, 14, 21, 28
You can use known facts:
2 × 7 = 14
4 × 7 = (2 × 7) + (2 × 7)
4 × 7 = 14 + 14 = 28

Remember that you can use patterns, known facts, or skip counting to find products.

In 1-8, use strategies to find the product.
Question 1.
5 × 9 = ________
Answer:
5 × 9 = ___45_____. (product)

Explanation:
5 × 9 = (3 × 9) + (2 × 9)
5 × 9 = 27 + 18
5 × 9 = 45.

 

Question 2.
8 × 10 = _______
Answer:
8 × 10 = __80_____. (product)

Explanation:
8 × 10 = (4 × 10) + (4 × 10)
8 × 10 = 40 + 40
8 × 10 = 80.

 

Question 3.
4 × 10 = ________
Answer:
4 × 10 = ___40_____.

Explanation:
4 × 10 = (3 × 10) + (1 × 10)
4 × 10 = 30 + 10
4 × 10 = 40.

 

Question 4.
9 × 8 = ________
Answer:
9 × 8 = ___72_____.

Explanation:
9 × 8 = (5 × 8) + (4 × 8)
9 × 8 = 40 + 32
9 × 8 = 72.

 

Question 5.
6 × 9 = _______
Answer:
6 × 9 = ___54____.

Explanation:
6 × 9 = (3 × 9) + (3 × 9)
6 × 9 = 27 + 27
6 × 9 = 54.

 

Question 6.
7 × 3 = _______
Answer:
7 × 3 = __21_____.

Explanation:
7 × 3 = (4 × 3) + (3 × 3)
7 × 3 = 12 + 9
7 × 3 = 21.

 

Question 7.
6 × 5 = ______
Answer:
6 × 5 = __30____.

Explanation:
6 × 5 = (3 × 5) + (3 × 5)
6 × 5 = 15 + 15
6 × 5 = 30.

 

Question 8.
4 × 9 = _______
Answer:
4 × 9 = ___36____.

Explanation:
4 × 9 = (2 × 9) + (2 × 9)
4 × 9 = 18 + 18
4 × 9 = 36.

 

 

 

Set D pages 181-184

You can solve word problems using multiplication and division.
Aaron has 49 books. His bookcase has 7 shelves. He wants to display an equal number of books on each shelf. How many books can Aaron put on each shelf?
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 71
You can use a related multiplication fact:
7 × 7 = 49
49 ÷ 7 = 7
Aaron can put 7 books on each shelf.

Remember that multiplication and division use equal groups.
Solve each problem. Show your work.
Question 1.
Oksana’s dad has 36 batteries in his desk drawer. The batteries come in packs of 4. How many packs of batteries does he have?
Answer:
Number of packs of batteries he has = 9.

Explanation:
Number of batteries in his desk drawer Oksana’s dad has = 36.
Number of packs batteries came in = 4.
Number of packs of batteries he has = Number of batteries in his desk drawer Oksana’s dad has ÷ Number of packs batteries came in
= 36 ÷ 4
= 9.

 

Question 2.
Every time Lee wins the ring toss at the carnival, he gets 3 prize tickets. Lee needs to win the ring toss 9 times to have enough prize tickets for 1 toy. How many prize tickets does Lee need for 2 toys?
Answer:
Number of prize tickets Lee needs to win for 2 toys = 27.

Explanation:
Number of prize tickets Lee gets = 3.
Number of times Lee needs to win to get ring toss to have enough prize tickets for 1 toy = 9.
Number of prize tickets Lee needs to win for 2 toys = Number of prize tickets Lee gets × Number of times Lee needs to win to get ring toss to have enough prize tickets for 1 toy
= 3 × 9
= 27.

 

Set E pages 185–188

Write a multiplication story for 4 × 7.
You can think of multiplication as equal groups.
Tim has 4 bunches of flowers. Each bunch has 7 flowers. How many flowers does Tim have?
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 72
Tim has 28 flowers.

Remember that rows and columns can also represent multiplication.
Write a multiplication story for each equation. Then solve.
Question 1.
3 × 9 = _______
Answer:
Number of nuts Mia has = Number of packets of nuts Mia has × Number of nuts in each packet
=> 3 × 9 = ___27____.

Explanation:
Mia has 3 packets of nuts. Each packet has 9 nuts. How many nuts does Mia have?
Number of packets of nuts Mia has = 3.
Number of nuts in each packet = 9.
Number of nuts Mia has = Number of packets of nuts Mia has × Number of nuts in each packet
= 3 × 9
= 27.

 

Question 2.
5 × 6 = ________
Answer:
Number of oranges John has = Number of packets of oranges John has × Number of oranges in each packet
=> 5 × 6 = ___30___.

Explanation:
John has 5 packets of oranges. Each packet has 6 oranges. How many oranges does John have?
Number of packets of oranges John has = 5.
Number of oranges in each packet = 6.
Number of oranges John has = Number of packets of oranges John has × Number of oranges in each packet
= 5 × 6
= 30.

 

 

 

Set E, continued pages 185-188

Write a division story for 20 ÷ 5.
If 20 children form 5 equal teams, how many children are on each team?
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 73
20 ÷ 5 = 4
There are 4 children on each team.

Remember that division stories can ask for the number in each group, or the number of equal groups.

Write a division story for each equation. Then solve.
Question 1.
60 ÷ 10 = _______
Answer:
Number of buses used = Number of students in the school ÷ Number of students in each bus
=> 60 ÷ 10 = 6.

Explanation:
In a school, there are 60 students. 10 Students go in each bus to picnic. How many buses are used for picnic.
Number of students in the school = 60.
Number of students in each bus = 10.
Number of buses used = Number of students in the school ÷ Number of students in each bus
= 60 ÷ 10
= 6.

 

Question 2.
32 ÷ 4 = _______
Answer:
Number of students in each bus = Number of students in the school ÷ Number of buses used
=> 32 ÷ 4 = 8.

Explanation:
In a school, there are 32 students. 4 buses are used to go the zoo.  How many Students go in each bus to zoo.
Number of students in the school = 32.
Number of buses used = 4.
Number of students in each bus = Number of students in the school ÷ Number of buses used
= 32 ÷ 4
= 8.

 

 

Set F pages 189-192

Think about these questions to help you look for and make use of structure.
Thinking Habits

  • What patterns can I see and describe?
  • How can I use the patterns to solve the problem?
  • Can I see expressions and objects in different ways?
    Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 74

Remember that properties can help you understand patterns.

Leroy earns $7 each hour that he works. He works for 8 hours. Rebecca earns $8 each hour that she works. She works for 7 hours. These expressions show the money they earned.
8 × $7 ○ 7 × $8
Question 1.
Look at the expressions. Explain how you can use what you see to compare without computing.
Answer:
Total amount earned by Leroy = $7 × 8 = $56.
Total amount earned by Rebecca = $8 × 7 = $56.
8 × $7 = 7 × $8
= $56.

Explanation:
Amount earned by Leroy for each hour = $7.
Number of hours Leroy works = 8.
Total amount earned by Leroy = Amount earned by Leroy for each hour × Number of hours Leroy works
= $7 × 8
= $56.
Amount earned by Rebecca for each hour = $8.
Number of hours Rebecca works = 7.
Total amount earned by Rebecca = Amount earned by Rebecca for each hour × Number of hours Rebecca works
= $8 × 7
= $56.

 

 

Question 2.
Who earned more money? Write the correct symbol >, <, or = in the circle above.
Answer:
Both the total amount earned by Leroy and the total amount earned by Rebecca are the same amount of $56.
=> 8 × $7 = 7 × $8
=> $56.

Explanation:
Total amount earned by Leroy = $7 × 8 = $56.
Total amount earned by Rebecca = $8 × 7 = $56.
Both Leroy and Rebecca earns the same amount $56.

 

 

Topic 5 Assessment Practice

Question 1.
Find 48 ÷ 6.
Answer:
48 ÷ 6= 8.

Explanation:
48 ÷ 6 = 8.

 

 

Question 2.
A. Fill in the missing factors and products in the multiplication table below.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 75

Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Assessment Practice-2

Explanation:
0 × 6 = 0.
0 × 7 = 0.
0 × 8 = 0.
1 × 6 = 6.
2 × 6 = 12.
2 × 7 = 14.
3 × 7 = 21.
3 × 8 = 24.
4 × 6 = 24.
4 × 8 = 32.

 

B. What pattern do you see in the first row of products in the table? Explain why this pattern is true.
Answer:
The first row of products in the table is zero because number multiplied by zero, results in zero itself.

Explanation:
The first row of products in the table is zero because number multiplied by zero, results in zero itself.
0 × 6 = 0.
0 × 7 = 0.
0 × 8 = 0.

 

Question 3.
Find 45 ÷ 5. Draw a bar diagram to represent the problem.
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Assessment Practice-3

Explanation:
45 ÷ 5 = 9.

 

Question 4.
Find the product.
5 × 7
A. 28
B. 30
C. 35
D. 42
Answer:
5 × 7 = 35.
C. 35.

Explanation:
5 × 7 = (2 × 7) + (3 × 7)
5 × 7 = 14 + 21
5 × 7 = 35. (product)

 

Question 5.
Find the product.
6 × 3 = ☐
Answer:
6 × 3 = 18.

Explanation:
6 × 3 = (3 × 3) + (3 × 3)
6 × 3 = 9 + 9
6 × 3 = 18. (product)

 

Question 6.
Which of the following strategies can help you solve 4 × 6? Select all that apply.
☐ (6 × 6) + (6 × 6)
☐ (4 × 3) + (4 × 3)
☐ (5 × 5) + (4 × 1)
☐ (5 × 4) + (1 × 4)
☐ (2 × 4) + (2 × 6)
Answer:
(4 × 3) + (4 × 3) and (5 × 4) + (1 × 4) is applied strategy helps you to solve 4 × 6.

Explanation:
4 × 6 = (2 × 6) + (2 × 6)
4 × 6 = 12 + 12
4 × 6 = 24.
or
4 × 6 = (4 × 3) + (4 × 3)
4 × 6 = 12 + 12
4 × 6 = 24.
or
4 × 6 = (5 × 4) + (1 × 4)
4 × 6 = 20+ 4
4 × 6 = 24.

 

 

Question 7.
What number is missing from this multiplication table?
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 76
A. 8
B. 9
C. 11
D. 12
Answer:

Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Assessment Practice-7
D. 12

Explanation:
2 × 6 = 12.

 

Question 8.
Select the correct product or quotient for each equation.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 77

Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Assessment Practice-8

Explanation:
54 ÷ 6 =  9.
8 × 7 = 56.
49 ÷ 7 = 7.
6 × 6 = 36.

 

 

Question 9.
Some squares are shaded orange to show a pattern in the multiplication table.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 78
A. Identify a pattern shown in the multiplication table.
Answer:
Orange colored are the multiples of 4 number and 8 number shown in the multiplication table.

Explanation:
The pattern shown in the multiplication table orange colored are the multiples of 4 number and 8 number.

 

B. Explain why this pattern is true.
Answer:
This pattern is true because they show the multiples of 4, 5, 6, 7, and 8 numbers.

Explanation:
Multiplication table shows he multiples of 4, 5, 6, 7, and 8 numbers.

 

Question 10.
Divide.
70 ÷ 7
Answer:
70 ÷ 7 = 10.

Explanation:
70 ÷ 7 = 10.

 

Question 11.
Which division equation could be used to solve 8 × ? = 32?
A. 32 ÷ 7 = ?
B. 32 ÷ 2 = ?
C. 32 ÷ 8 = ?
D. 8 ÷ ? = 32
Answer:
8 × ? = 32
=> 8 × 4 = 32.
C. 32 ÷ 8 = ? division equation could be used to solve 8 × ? = 32

Explanation:
8 × ? = 32
=> ? = 32 ÷ 8
=> ? = 4.

 

 

Question 12.
Twelve can be evenly divided by which of the following numbers? Select all that apply.
☐ 9
☐ 3
☐ 5
☐ 4
☐ 7
Answer:
Twelve can be evenly divided by the 2, 3, 4, 6 numbers:
3 and 4 numbers are applied to divide 12 number evenly.

Explanation:
Twelve can be evenly divided by the following numbers:
12 ÷ 2 = 6.
12 ÷ 3 = 4.
12 ÷ 4 = 3.
12 ÷ 6 = 2.

 

 

Question 13.
What is the product of 9 and 3? Write an equation to solve the problem.
Answer:
Equation:
9 × 3 = 27.

Explanation:
Equation:
9 × 3 = 27. (product)

 

 

Question 14.
Look at these two expressions.
40 ÷ 4       40 ÷ 8
A. Explain how you can compare the expressions without computing.
Answer:
We can compare the expressions without computing like this finding the answer.
40 ÷ 4   >   40 ÷ 8.

Explanation:
40 ÷ 4 = 10.
40 ÷ 8 = 5.

 

B. Check your answer by computing both quotients.
Answer:
40 ÷ 4 = 10. (quotient)
40 ÷ 8 = 5. (quotient)

Explanation:
40 ÷ 4 = 10. (quotient)
40 ÷ 8 = 5. (quotient)

 

 

Question 15.
Which shows a way to solve 5 × 5?
A. Skip count 5 times by numbers that end in 5: 5, 15, 25, 35, 45
B. Use the Distributive Property: (4 × 5) + (1 × 5)
C. Look at a multiplication table: Find the 5s row. Go across until you find 5. The product is the number at the top of that column, 1.
D. Use repeated addition: 5 + 5 + 5 + 5
Answer:
B. Use the Distributive Property: (4 × 5) + (1 × 5)

Explanation:
5 × 5 = (4 × 5) + (1 × 5)
5 × 5 = 20 + 5
5 × 5 = 25.

 

Question 16.
Roberta is planting flowers in her garden. She plants 9 rows of flowers. There are 7 flowers in each row. How many flowers does does she plant in all? Write an equation to solve the problem.
Answer:
Number of flowers she plants in all = Number of rows of flowers Roberta plants  × Number of flowers in each row
= 9 × 7
= 63.

Explanation:
Number of rows of flowers Roberta plants = 9.
Number of flowers in each row = 7.
Number of flowers she plants in all = Number of rows of flowers Roberta plants  × Number of flowers in each row
= 9 × 7
= 63.

 

Question 17.
Multiply.
7 × 2
Answer:
7 × 2 = 24.

Explanation:
7 × 2 = (1 × 2) + (6 × 2)
7 × 2 = 2 + 12
7 × 2 = 14.

 

Question 18.
Look at the multiplication table below.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 79
A. Shade the products in the 5s column of the table. What pattern do you see there?
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Assessment Practice-18

Explanation:
The products in the 5s column of the table are 20, 25, 30, 35.
5 × 4 = 20.
5 × 5 = 25.
5 × 6 = 30.
5 × 7 = 35.

 

B. Explain the pattern you found.
Answer:
The pattern found is difference is 5 in between the numbers and are the multiples of 5 number.

Explanation:
The pattern found is difference is 5 in between the numbers and they are multiples of 5 number.

 

Topic 5 Performance Task

Photograph Gallery Riley is setting up a display. She is hanging photographs on two walls. The photographs are hung in arrays. Riley has to decide how to arrange the photographs. She makes tables to decide which arrangement to use.

Question 1.
Use the Left Wall table to answer the questions.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 80
Part A
Which arrangement on the left wall has the most photographs?
Answer:
Left wall B arrangement has the most photographs of 27.

Explanation:
Left wall arrangement :
A = Rows × Columns
= 3 × 7
= 21.
B = Rows × Columns
= 3 × 9
= 27.
C = Rows × Columns
= 7 × 2
= 14.
D = Rows × Columns
= 8 × 3
= 24.

 

Part B
Explain how Riley could find the answer to Part A without calculating the size of each arrangement.
Answer:
Riley could find the answer to Part A without calculating the size of each arrangement by checking the highest columns  or rows size.

Explanation:
Riley could find the answer to Part A without calculating the size of each arrangement by checking the highest columns  or rows size.

 

 

Use the Right Wall table to answer Exercises 2 and 3.
Envision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 81

Question 2.
Fill in the missing columns, rows, and numbers of photographs so that Riley’s table is complete.
Answer:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Performance Task-2

Explanation:
4 × ? = 36.
=> 4 × 9 = 36.
7 × ? = 42
=> 7 × 6 = 42.
6 × ? = 42.
=> 6 × 7 = 42.
7 × ? = 63.
=> 7 × 9 = 63.
6 × ? = 30.
=> 6 × 5 = 30.
4 × ? = ??
=> 4 × 4 = 16.
=> 6 × 4 = 24.
=> 6 × 6 = 36.
=> 6 × 9 = 54.
7 × 4 = 28.
=> 7 × 5 = 35.
=> 7 × 6 = 42.
=> 7 × 7 = 49.
=> 7 × 9 = 63.
9 × 4 = 36.
=> 9 × 5 = 45.
=> 9 × 6 = 54.
=> 9 × 7 = 63.
=> 9 × 9 = 81.

 

 

Question 3.
Riley has 42 on her table twice. Is this reasonable? Explain why or why not.
Answer:
Riley has 42 on her table twice and it is reasonable because rows and columns count is not same  6 × 7 = 42 and  7 × 6 = 42.

Explanation:
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Performance Task-2
Rows × Columns
6 × 7 = 42.
7 × 6 = 42.

 

 

Use the Right Wall table to answer Exercises 4-6.
Question 4.
Some of the photographers were men, and some were women. Riley wants the number of photographs taken by men to be equal to the number of photographs taken by women. Shade the squares in the table to show the arrangements that let Riley do this. Explain what pattern you find.
Answer:
The pattern followed is doubling the numbers.
Envision-Math-Common-Core-3rd-Grade-Answers-Key-Topic-4-Use-Multiplication-to-Divide-Topic 5 Performance Task-4

Explanation:
Riley wants the number of photographs taken by men to be equal to the number of photographs taken by women:
4 × 4 = 16.
6 × 6 = 36.
7 × 7 = 49.
9 × 9 = 81.

 

Question 5.
Riley shares this table with her friend Leo. Leo is working on a different project. He is NOT hanging photographs. For what project could Leo use the table? Explain what 7 × 4 means for Leo’s project.
Answer:
7 × 4 means for Leo’s project is 28 photographs .

Explanation:
7 × 4 = (3 × 4) + (4 × 4)
7 × 4 = 12 + 16
7 × 4 = 28.

 

Question 6.
Riley also shares this table with her mother. Riley’s mother is working on a different project. She is also NOT hanging photographs. For what project could Riley’s mother use the table? Explain what 30 ÷ 6 means for Riley’s mother’s project.
Answer:
30 ÷ 6 means for Riley’s mother’s project is 5 photographs.

Explanation:
30 ÷ 6 = 5Go through the enVision Math Common Core Grade 3 Answer Key Topic 5 Fluently Multiply and Divide within 100 regularly and improve your accuracy in solving questions..

enVision Math Common Core Grade 6 Answer Key

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